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Econometrics I: Solutions of the homework

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Econometrics I: Solutions of the homework

#14

LU ANG July 21, 2020

Contents

1 Question 1

1.1 (1)

When X and u are correlated that is to say E(X

0

u) 6= 0, Thus the OLSE can be written as:

β ˆ = ( 1

n X

0

X)

−1

1

n X

0

u −→ β + M

xx−1

M

xu

6= 0 where:

1

n X

0

X −→ M

xx

, 1

n X

0

u −→ M

xu

Which imply that ˆ β 6= β. In such case OLSE is inconsistent

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1

(2)

[Econometrics] Lu Ang

1.2 (2)

the matrix Z is not correlated with X and u which satisfies the orthogonal condition 1

n Z

0

u −→ M

zu

= 0. Multiplying Z

0

on both sides of the regression model y = Xβ + u, we obtain:

Z

0

y = Z

0

Xβ + Z

0

u

Dividing n on both sides of the above equation and take plim on both sides.

Then we obtain the following:

plim( 1

n Z

0

y) = plim( 1

n Z

0

X)β + plim( 1

n Z

0

u) = plim( 1

n Z

0

X)β

Accordingly, we obtain:

β = (plim( 1

n Z

0

X))

−1

plim( 1 n Z

0

y)

Therefore:

β

IV

= (Z

0

X)

−1

Z

0

y

1.3 (3)

Assume the followings:

1

n Z

0

X −→ M

zx

, 1

n Z

0

Z −→ M

zz

, 1

n Z

0

u −→ 0 Asymptotic Distribution of β

IV

:

β

IV

= (Z

0

X)

−1

Z

0

y = (Z

0

X)

−1

Z

0

(Xβ + u) = β + (Z

0

X)

−1

Z

0

u

2

(3)

[Econometrics] Lu Ang

which is rewritten as:

√ n(β

IV

− β) = ( 1

n Z

0

X)

−1

( 1

√ n Z

0

u)

Applying the Central Limit Theorem to

1n

Z

0

u, we have the following result:

√ 1

n Z

0

u → N (0, σ

2

M

zz

) Therefore:

√ n(β

IV

− β) = ( 1

n Z

0

X)

−1

( 1

√ n Z

0

u) → N (0, σ

2

M

zx−1

M

zz

M

0−1zx

)

3

参照

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