f :ブロック書込みデータ 1
135 1 Attainable order Runge-Kutta $c_{k}$ $y$ $y_{k}$ $y_{k}=y_{n}+h \sum_{j=1}^{k-1}a_{kj}f_{j}$ $f_{1}=f(t_{n} y_{n})$ $f_{i}=f(t_{n}+c_{i}h y_{i})
20
68 JAXA-RR r v m Ó e ε 0 E = - Ó/ r f f 0 f 1 f = f 0 + f 1 x k f 1 = f k e ikx Ó = Ó k e ikx Ó k 3
7
サンプリング点 f = 1/2 f = 1/2 f = 2/2 f = DC f = 3/2 f = 1/2 f = 4/2 f = DC f = 5/2 f = 1/2 A/D 出力周波数 1/ 1/2 2/2 3/2 4/2 5/2 6/2 エリアシンク 信号 ( 妨害波成分 ) A/D 入力で
12
( ) f a, b n f(b) = f(a) + f (a)(b a) + + f (n 1) (a) (n 1)! (b a)n 1 + R n, R n = b a f (n) (b t)n 1 (t) (n 1)! dt. : R n = b a f (n) (b t
12
January 16, (a) (b) 1. (a) Villani f : R R f 2 f 0 x, y R t [0, 1] f((1 t)x + ty) (1 t)f(x) + tf(y) f 2 f 0 x, y R t [0, 1] f((1 t)x + ty) (1 t
65
Chapter (dynamical system) a n+1 = 2a n ; a 0 = 1. a n = 2 n f(x) = 2x a n+1 = f(a n ) a 1 = f(a 0 ), a 2 = f(f(a 0 )) a 3 = f(f(f(a
19
2. Bilingual Pivoting Bilingual Pivoting [5] e 1 f f e 2 e 1 e 2 p(e 2 e 1 ) p(f e 1 ) p(e 2 f) p(e 2 e 1 ) = f p(e 2 f, e 1 ) p(f e 1 ) f p(e 2 f) p(
8
Fortran90/95 2. (p 74) f g h x y z f x h x = f x + g x h y = f y + g y h z = f z + g z f x f y f y f h = f + g Fortran 1 3 a b c c(1) = a(1) + b(1) c(
28
[2] ATMUKN [3] (ATMU ATMUKN)[4] ( ) X tr = f photo photo + f incoh incoh + f pair pair = E h 0 (2) h 0 E 1 f photo =1; X h 0 f incoh f pair =1;
14
1 Ricci V, V i, W f : V W f f(v ) = Imf W ( ) f : V 1 V k W 1
39
f (x) f (x) f (x) f (x) f (x) 2 f (x) f (x) f (x) f (x) 2 n f (x) n f (n) (x) dn f f (x) dx n dn dx n D n f (x) n C n C f (x) x = a 1 f (x) x = a x >
12
14 35H-3 35H-3 15 b f f b b b f f f f f f f f f f b b f f f f f b b b b b b b b b f f f f f f f f f f f f f
18
2 (2.1) Q = (O, M, s, t) (, quiver) (oriented graph), (2.1.1) O, M. (2.1.2) s : M O t : M O.. O (vertex), M (arrow). f M, s(f) f source, t(f) f target
111
0 = m 2p 1 p = 1/2 p y = 1 m = 1 2 d ( + 1)2 d ( + 1) 2 = d d ( + 1)2 = = 2( + 1) 2 g() 2 f() f() = [g()] 2 = g()g() f f () = [g()g()]
30
1520 Vol. 131 (2011) Í Ì 160 f Í f h f Íh f Ì 7,8 h h i f Í Ìh f 1 Table 1 Ì 9 f m id Ì Í Ì f k h Ì l Í i Í 実験方法 1. 試料及び試薬 Lecithin from Egg Í h Í h ä
7
B [ 0.1 ] x > 0 x 6= 1 f(x) µ 1 1 xn 1 + sin sin x 1 x 1 f(x) := lim. n x n (1) lim inf f(x) (2) lim sup f(x) x 1 0 x 1 0 (
11
9 8 7 (x-1.0)*(x-1.0) *(x-1.0) (a) f(a) (b) f(a) Figure 1: f(a) a =1.0 (1) a 1.0 f(1.0)
28
C-1 210C f f f f f f f f f f f f f f f f f f f f r f f f f f f f f f f f f f R R
18
1 ( ) I 1) f 2) a I 3) (1.1) lim x a f(x) = f(a) a (1.1) 4)5) ( lim f(x) = f(a) x a+0 lim x a 0 f(x) = f(a)). I f I I I I f I a 6) f(x
61
x = a 1 f (a r, a + r) f(a) r a f f(a) 2 2. (a, b) 2 f (a, b) r f(a, b) r (a, b) f f(a, b)
22