A,Bについて正しいはど
各論 : マウス ラット その他の小動物 それぞれの設問について 該当するものを選び 解答用紙の該当欄の を鉛筆で黒く塗り つぶしてください 1. CBAの毛色として正しい遺伝子型はどれか 1) A/A b/b c/c 2) a/a B/B C/C 3) A/A B/B C/C 4) a/a b/b
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問 61 すい膵臓に関する以下の記述のうち 正しいものの組み合わせはどれか すい a 胃の後下部に位置する細長い臓器で 膵液を回腸に分泌する b 分泌液は 弱アルカリ性である c 分泌液は 脂質を分解するリパーゼなどの消化酵素を含んでいる d 胆汁酸を合成する 1(a b) 2(a d) 3(b c
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1) a) b) CRP c) d) e) a,b b,c c,d d,e a,e b,d 2) CKD a) ACE ARB b) 2mg/dL ACE ARB c) 2mg/dL d) e) ACE ARB a,b b,c c,d d,e a,e b,d 3) a) 130/85mmHg b)
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(a) (b) / 1 (a) b :
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1 2. a b 3. a b c 4. a b c 5.
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-June TARGET EU TARGET EU A A A a a B b b A B B a b b a A a b A b a ECB EU TARGET ECB TARGET TARGET TARGETTrans-European
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(a) (b) (c) (d) 1: (a) (b) (c) (d) (a) (b) (c) 2: (a) (b) (c) 1(b) [1 10] 1 degree k n(k) walk path 4
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( ) f a, b n f(b) = f(a) + f (a)(b a) + + f (n 1) (a) (n 1)! (b a)n 1 + R n, R n = b a f (n) (b t)n 1 (t) (n 1)! dt. : R n = b a f (n) (b t
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, 1. x 2 1 = (x 1)(x + 1) x 3 1 = (x 1)(x 2 + x + 1). a 2 b 2 = (a b)(a + b) a 3 b 3 = (a b)(a 2 + ab + b 2 ) 2 2, 2.. x a b b 2. b {( 2 a } b )2 1 =
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(a) (b) 1: (a) ( ) (b) ( ) : ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( 2 ) 2 2
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a bc a b c a b a bc a
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x 3 a (mod p) ( ). a, b, m Z a b m a b (mod m) a b m 2.2 (Z/mZ). a = {x x a (mod m)} a Z m 0, 1... m 1 Z/mZ = {0, 1... m 1} a + b = a +
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x = a 1 f (a r, a + r) f(a) r a f f(a) 2 2. (a, b) 2 f (a, b) r f(a, b) r (a, b) f f(a, b)
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II (10 4 ) 1. p (x, y) (a, b) ε(x, y; a, b) 0 f (x, y) f (a, b) A, B (6.5) y = b f (x, b) f (a, b) x a = A + ε(x, b; a, b) x a 2 x a 0 A = f x (
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(2016 2Q H) [ ] R 2 2 P = (a, b), Q = (c, d) Q P QP = ( ) a c b d (a c, b d) P = (a, b) O P ( ) a p = b P = (a, b) p = ( ) a b R 2 {( ) } R 2 x = x, y
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() () () () PSR PSR 16 PSA a) a) a) b) b) b) PSA PSA c) PSR /173
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1 (1) (2a) (2b) (2) a. [ame ga [fur anakatta] ] b. [ [ame ga fur] anakatta] (2a) (2b) 1.1 (3) (4a) (4b) (3) (4) a. [ [ ] ] b. [ [ ] ] (4a) (4b) 3 (5)
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(2018 2Q C) [ ] R 2 2 P = (a, b), Q = (c, d) Q P QP = ( ) a c b d (a c, b d) P = (a, b) O P ( ) a p = b P = (a, b) p = ( ) a b R 2 {( ) } R 2 x = x, y
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) a + b = i + 6 b c = 6i j ) a = 0 b = c = 0 ) â = i + j 0 ˆb = 4) a b = b c = j + ) cos α = cos β = 6) a ˆb = b ĉ = 0 7) a b = 6i j b c = i + 6j + 8)
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(a) (b) 1: [16] PET [17]. ( 1).1 ( 2a) ( 2b).2 ( a) (a) (b) 2: (a) (b) : b. 2 c 2017 Information Processing Society of Japan 2
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