060310391
0560565
2
2016/10/3 13:00-14:45
@1 - 4
•
•
•
–
–
–
–
•
h/p://konicaminolta.jp/instruments/knowledge/color/part2/07.html
R 151
G 109
B 121
182 × 167 × 3
= 91182
pixel
256 0-255 3 256^3=16 777 216
• RGB: Red, Green, Blue
– 3
• CMY: Cyan, Magenta, Yellow
– 3
• HSV: Hue SaturaRon Value
–
• HSL: Hue SaturaRon Luminance
– 100%
100% 0%
h/p://homepage2.niUy.com/studio_AURK/ccconv/Color/hue.html
• RGB CMY
C = 255 – R
M = 255 – G
Y = 255 – B
• RGB HSV
max,min RGBV = max
S = 255 × (max – min) / max
R max
H = 60 × (B – G) / (max – min)
G max
H = 60 × (R – B) / (max – min)
B max
H = 60 × (G – R) / (max – min)
H H ← H + 360
•
50×50
50 × 50 × 3 = 7500
0
255
1
(R, G, B) = (23, 14, 22)
(R, G, B) = (200, 198, 168)
(R, G, B) = (201, 200, 173)
(R, G, B) = (200, 199, 172)
50 × 50 × 3 = 7500
7500
Principal component analysis (PCA)
•
50 × 50 × 3 = 7500
7500
•
•
2 1
u
1x
1, x
21 u
1u
1u
1u
1x
1x
2
u
1u
1= u
1u
1
x
1x
2ε
i= y
i− (α + βx
i)
( 2
SSE
= ε
i2i n
∑ = (y
i− α − βx
i)
2 in
∑
:
∂SSE
∂β =−2 i (yi−α − βxi)xi
n
∑
= 0∂SSE
∂α =−2 i (yi−α − βxi)
n
∑
= 0a = yi
i
∑
n n− b ixi∑
n n = y − bxb =
xiyi−
i
∑
n ixi∑
n iyi∑
n nxi2− xi
i
∑
n( )
2 ni
∑
n= i(xi− x )(yi− y )
∑
n(xi− x )2
i
∑
nn xi
i
∑
nxi
i
∑
n xi 2 i∑
n#
$
%
%
&
' ( ( a b
#
$ % & ' ( = iyi
∑
nxiyi
i
∑
n#
$
%
%
&
' (
-3 -2 -1 0 1 2 3 (
455055
x
y
yi ˆ
y i=
α
+β
xi xiε
i15
(a) y
(b)
1
x,y
16
2 1
u
1 Tu
1
= u
11 2+ u
12 2
= 1
1
n −1 z
1i2
i=1 n
∑
z1i
= x
i Tu1
= x (
1i x2i)
uu1112
"
# $ %
&
' = u
11x1i+ u
12x2i(u1
x 0
u
1x
i Z1i = u1 xi
Z1i
1 n−1
x1i2
i=1 n
∑
x1ix2i i=1n
∑
x1ix2i i=1
n
∑
x2i 2 i=1n
∑
$
%
&
&
&
&
'
( ) ) ) )
u11
u12
$
% & ' ( ) = λ
u11
u12
$
% & ' ( ) L(u
1,λ) =
1 n−1 (u11
x1i+ u12x2i)
2−λ(u112+ u122 −1)
i=1 n
∑
∂L
∂u11= 1
n−1i 2(u11x1i+ u12x2i)x1i− 2λu11= 0
=1 n
∑
∂L
∂u12= 1
n−1 2(u11x1i+ u12x2i)x2i− 2λu12= 0
i=1 n
∑
1 n−1u11 x1i
2 i=1
n
∑
+ u12 x1ix2i i=1n
$
∑
% & '
( ) = λu11 1
n−1 u11 x1ix2i
i=1 n
∑
+ u12 x2i 2 i=1n
$
∑
% & '
( ) = λu12
(V)
{
Vu
1= λu
1}
u
1= 0
[ ]
var(x) = 1
n−1 (xi− x
i=1 n
∑
)2cov(x, y) = 1
n−1i=1(xi− x
n
∑
)(yi− y ) 2r = cov(x, y) var(x) var(y)=
(xi− x
i=1 n
∑
)(yi− y )(xi− x
i=1 n
∑
)2 (yi− y i=1n
∑
)2-3 -2 -1 0 1 2 3
-2-10123
length
width
(xi− x )(yi− y )
x y
2 4
×(-1)
2
V
=
6.00 2.03
2.03 2.98
"
# $ %
&
' =
6 2
2 3
"
# $ %
&
'
7, 2 u1=
2 / 5 1/ 5
"
#
$ %
& ' u2=
1/ 5
−2 / 5
#
$
% & ' (
1 2.5 -0.2
2 3.4 3.4
3 1.0 1.9
4 -2.4 -0.8
5 -3.0 -2.4
6 0.1 -1.6
7 -2.5 -0.5
8 -2.9 1.2
9 1.8 0.1
10 1.6 -1.0
-3 -2 -1 0 1 2 3
-2-10123
length
width
Au = λ u
A 0 u A λ
A n×n A n λ1, λ2, …, λn
u1, u2, …, un
{u1, u2, …, un}
(A − λI)u = 0
u=0 0
0
A − λI = 0
V
=
6 2
2 3
"
# $ %
&
'
6 2
2 3
"
# $ %
&
'
u1
u2
"
# $ %
&
' = λ
u1
u2
"
# $ %
&
'
6 − λ 2
2 3 − λ
$
% & '
( )
u1
u2
$
% & '
( ) =
0
0
$
% & '
( )
6 − λ 2
2 3 − λ = 0
(6 −λ)(3 −λ) − 4 = (λ− 2)(λ− 7) = 0λ=2 2u21+ u22= 0 u212 + u222 = 1 u21 u22
"
# $ %
& ' = 1/ 5
−2 / 5
"
# $ %
& ' λ=7 u11− 2u12= 0 u112+ u122 = 1 u11
u12
"
# $ %
& ' = 2 / 5
1/ 5
"
# $ %
& '
2, 7
u1= u11 u12
"
# $ %
& ' =
2 / 5 1/ 5
"
# $ %
&
' u2=
u11 u12
"
# $ %
& ' =
1/ 5
−2 / 5
"
# $ %
& '
k 2 B
50 × 50 × 3 = 7500
7500
z1, z2, …
•
•
z
ij= u
j1x
1i++ u
jMx
Mi= x
iTu
j
j i principal component score
1.
2. -3 -2 -1 0 1 2 3
-2-10123
length
width
z11= 2.5( −0.2)2 / 5
1/ 5
#
$
% & ' ( = 2.2
z12=
(
2.5 −0.2)
1 / 5−2 / 5
⎛
⎝⎜
⎜
⎞
⎠⎟
⎟= 1.3
PC1 PC2
1 2.5 -0.2 2.2 1.3
2 3.4 3.4 4.6 -1.5
3 1.0 1.9 1.8 -1.2
4 -2.4 -0.8 -2.5 -0.3
5 -3.0 -2.4 -3.7 0.8
6 0.1 -1.6 -0.6 1.5
7 -2.5 -0.5 -2.4 -0.6
8 -2.9 1.2 -2.0 -2.3
9 1.8 0.1 1.7 0.7
10 1.6 -1.0 1.0 1.6
0
1 N − 1 zji
2 i N
∑
= 1 N − 1zj Tz
j= 1
N − 1(Xuj)
T(Xuj)
= 1
N − 1 uj
TXTXu j= uj
TVu j= λjuj
Tu j= λj
Vuj=λjuj
V eigenvalue λ1≥λ2≥ ≥λM≥ 0 ui
zj j
λ
j/ λ
ii=1 M
∑
λi
i=1 j
∑
/ λii=1 M
∑
j contribuRon cumulaRve
1 M −1X
TX= V
x 0
i λi
x
0.77 0.77
0.33 1.00
var(z
1) = 7.0
…
PC1 PC2
1 2.5 -0.2 2.2 1.3
2 3.4 3.4 4.6 -1.5
3 1.0 1.9 1.8 -1.2
4 -2.4 -0.8 -2.5 -0.3
5 -3.0 -2.4 -3.7 0.8
6 0.1 -1.6 -0.6 1.5
7 -2.5 -0.5 -2.4 -0.6
8 -2.9 1.2 -2.0 -2.3
9 1.8 0.1 1.7 0.7
10 1.6 -1.0 1.0 1.6
var(l) = 6.0
V=
6 2
2 3
"
# $ %
&
'
var(w) = 3.0
var(z
2) = 2.0
•
•
1
• 1
•
2
R =
1 r
r 1⎛
⎝⎜
⎞
⎠⎟
R − λI = 0 ⇔ (1− λ)2
− r
2= 0
∴ λ
1
= 1+ r, λ
2= 1− r
Ra1= λ
1a1y1= 1
2(x1+ x2), y2= 1
2(x1− x2)
∴a
11= a
12= 1
2
a2a11+ ra12= (1+ r)a11 ra11+ a12= (1+ r)a12
-2s.d. 平均 +2s.d. PC1
PC2
PC3
PC4
*** 24.05
*** 57.28
*** 119.71
*** 48.27 品種効果
自由度174, 875
主成分
寄与率
(43.5%)
(15.0%)
(9.3%)
(4.5%)
z
iq= x
iTu
q(z
i1,..., z
iq) = x
iT(u
1,..., u
q) z
iT= x
iTU ⇔ z
i= U
Tx
iz
i1
= x
iTu
1UTU = u1
Tu
1 u1
Tu q
uqTu
1 uq
Tu q
⎡
⎣
⎢
⎢⎢
⎢
⎤
⎦
⎥
⎥⎥
⎥
= I
U
T= U
−1⇔ UU
T= I
∴x
i= Uz
i= 2 x T 2
xi = U k λ1
0
0
⎛
⎝
⎜⎜
⎜⎜
⎞
⎠
⎟⎟
⎟⎟
2
2
eigenfaces
Murphy KP (2012) "Machine Learning: A ProbabilisRc PerspecRve" The MIT Press.
102
30
30
•
• A B …
– 100 100
A B 100/100 = 1
– 100 0
A B 0/100 = 0
– 100 65
A B 65/100 = 0.65
Principal co-ordinate analysis (PCO)
•
h/p://aoki2.si.gunma-u.ac.jp/lecture/misc/princo-ex.html
B = XX
T• q n
• n q n×q X i
j ij
b
ij= x
ikx
jkk=1
∑
q• x bij i j
d
ij2= (x
ik− x
jk)
2k=1
∑
q= x
ik2 k=1
∑
q+ x
ik 2 k=1∑
q− 2
k=1x
ikx
jk∑
q= b
ii+ b
jj− 2b
ij• i j dij
b
iji=1
∑
n=
k=1x
ikx
jk∑
q=
i=1
∑
nx
jk i=1x
ik∑
k= 0
k =1
∑
q{
• dij
2 i=1
∑
n = i=1(bii+ bjj− 2bij)∑
n = i=1bii∑
n + nbjjdij 2 j=1
∑
n = j=1(bii+ bjj− 2bij)∑
n = j=1bjj∑
n + nbii= i=1bii∑
n + nbiidij2
j=1
∑
n i=1∑
n = j=1(bii+ bjj− 2bij)∑
n i=1∑
n = n i=1bii∑
n + nn j=1bjj∑
n = 2n i=1bii∑
n•
di.2=1 n dij
2 j=1
∑
n =1 n i=1bii∑
n + biidi.2=1 n dij
2 i=1
∑
n =1 n i=1bii∑
n + bjjd.. 2= 1
n2 dij
2 j=1
∑
n i=1∑
n =2 n i=1bii∑
nbij= −1 2(dij
2− di. 2− d.j
2+ d.. 2)
X 2 2
X ,
A(u1
,..., u
q) = (u
1,..., u
q)
λ
10
0 λ
q⎡
⎣
⎢
⎢ ⎢
⎤
⎦
⎥
⎥ ⎥
Au
1= λ
1u
1Au
q= λ
qu
qAU = UΛ
u
i Tu
j
= 0
u
iT
u
i
= 1, U
T
U = I ⇔ U
T= U
−1⇔ UU
T= I
∴A = UΛU
Tu
*i= λ
iu
iA = U
*U
*T U*= (u
1*
,..., u
*q)
B = XX
T XX = UΛ
1/2Λ
1/2= diag( λ
11/2,…, λ
q1/2)
B
感覚距離 PC2
PC4 主成分得点の差 0123
0.2 0.4 0.6 0.8 1.0
012345
…
1
( )
PC1 PC2 PC3 PC4 PC5 PC6 PC7 PC8 PC9 PC10
PCO1 -1.0-0.50.00.51.0
PC1 PC2 PC3 PC4 PC5 PC6 PC7 PC8 PC9 PC10
PCO2 -1.0-0.50.00.51.0
u
2
3
4 1
x x
•
– 3 4
•
–
h/p://konicaminolta.jp/instruments/knowledge/color/part2/06.html
II. :
(m) 10 2
1
10 -2
10 -4
10 -6
10 -8
10 -10
10 -12
10 -14
FM
780
700
600
500
400
380
(nm)
780
700
600
520
440
360
(nm)
< >
< >
Brassica rapa L.
Brassica napus L.
rapa
< >
Brassica rapa L.
Brassica napus L.
: Nikon D70
: Ultra AchromaRc Takumar
•
Syafaruddin et al. (2006) Breed Sci 56:75-79
f (x)
g( x) = 0
L(x, λ ) ≡ f (x) + λ g(x)
x
(Lagrangian)
(Lagrange mulRplier)
∇L = ∇f + λ ∇g = 0
h/p://www.isigas.com/LagrangeMP.html
g(x
1, x
2) = 0
f (x
1, x
2)
∇g ∇f
g(x)=0 f(x)
∇f − λ ∇g = 0
λ
g(x
1, x
2) = x
1+ x
2−1 = 0
f (x
1, x
2) = 1− x
12− x
22L (x, λ ) = 1− x
1
2
− x
22+ λ (x
1+ x
2−1)
x
∂ L
∂ x
1= −2x
1+ λ = 0
∂ L
∂ x
2= −2x
2+ λ = 0
∂ L
∂λ = x
1+ x
2−1 = 0
x
1=
1
2 ,
x
2=
1
2 , λ = 1
3
z
1i= u
11x
1i+ + u
1mx
mi= u
1T
x
i
V (z
1) = 1
n −1 (z
1i− z
1)
2 i=1
n
∑ = s
jku
1ju
1k= u
1 TVu
1 k =1
m
∑
j =1 m
∑
sjk xj xk
u
Tu = u
112+ + u
1M2= 1
z1
L(u
1,λ) = u
1 TVu
1
− λ(u
1 Tu
1
−1)
∂L
∂u
1= 2Vu
1− 2λu
1= 0 (V − λ I)u
1= 0
V(z2) = u2TVu2
L(u
2,λ,ν ) = u
2 TVu
2
− λ(u
2 Tu
2
−1) − ν (u
2 Tu
1
)
3 ...
x
1 1
z
2i= u
21x
1i+ + u
2mx
mi= u
2T
x
i
u
2Tu
2= u
212+ + u
2M2= 1
u
2T
u
1= u
21u
11
+ + u
2Mu
1M= 0
=0 →
∂L
∂u
2= 2Vu
2− 2λu
2− νu
1= 0 u
2T
u
1
= u
1 Tu
2
= 0, u
1 Tu
1
= 1
ν = 0
(V − λI)u = 0
2