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正規直交化法 問題1 解答 - 熊本大学

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(1)

正規直交化法 問題 1 解答

・ 正規直交化法 用 , 次 基底 正規直交基底 作 .

(1) a1 =

 1 0 0

, a2 =

 1 2

1

, a3 =



1 1 2



[解]: 与 基底 直交基底 .

b1 =a1 =

 1 0 0

,

b2 =a2 (a2, b1) (b1, b1)b1 =

 1 2

1



 1 0 0

=

 0 2

1

,

b3 =a3 (a3, b1)

(b1, b1)b1 (a3, b2) (b2, b2)b2 =



1 1 2





1 0 0



 0 0 0

=

 0 1 2

.

直交基底 b1, b2, b3 正規化 行 正規直交基底 求 . ,求 正規直交基底c1, c2, c3 ,

c1 = 1

 1 0 0

=

 1 0 0

, c2 =

5 5

 0 2

1

=

 0

2 5

555

, c3 =

5 5

 0 1 2

=



0

5 5 2

5 5

.

(2) a1 =

 0 1 1

, a2 =

 1 0 1

, a3 =

 1 1 0



[解]: 与 基底 直交基底 .

b1 =a1 =

 0 1 1

,

b2 =a2(a2, b1) (b1, b1)b1 =

 1 0 1



 0

1 2 1 2

=

 1

12

1 2

,

b3 =a3(a3, b1)

(b1, b1)b1 (a3, b2) (b2, b2)b2 =

 1 1 0



 0

1 2 1 2





1

316

1 6

=



2 3 2

323

.

直交基底 b1, b2, b3 正規化 行 正規直交基底 求 . ,求 正規直交基底c1, c2, c3 ,

c1 =

2 2

 0 1 1

=



0

2

2 2 2

, c2 =

6 3

 1

12

1 2

=



6 3

66

6 6

, c3 =

3 2



2 3 2

323

=



3

3 3

333

.

(2)

(3) a1 =

 1 1 1

, a2 =

 2 0 1

, a3 =

 1

2

1



[解]: 与 基底 直交基底 .

b1 =a1 =

 1 1 1

,

b2 =a2(a2, b1) (b1, b1)b1 =

 2 0 1



 1 1 1

=

 1

1 0

,

b3 =a3(a3, b1)

(b1, b1)b1 (a3, b2) (b2, b2)b2 =

 1

2

1





23

23

23





3

232

0

=



1 6 1

613

.

直交基底 b1, b2, b3 正規化 行 正規直交基底 求 . ,求 正規直交基底c1, c2, c3 ,

c1 =

3 3

 1 1 1

=



3

3 3

3 3 3

, c2 =

2 2

 1

1 0

=



2 2

22 0

, c3 = 6



1 6 1

613

=



6

6 6 6

36

.

(4) a1 =



1 2 2

, a2 =

 0 1 2

, a3 =

 1 1 1



[解]: 与 基底 直交基底 .

b1 =a1 =



1 2 2

,

b2 =a2(a2, b1) (b1, b1)b1 =

 0 1 2





23

4 3 4 3

=



2

313

2 3

,

b3 =a3(a3, b1)

(b1, b1)b1 (a3, b2) (b2, b2)b2 =

 1 1 1





13

2 3 2 3





2

313

2 3

=



2 3 2

313

.

直交基底 b1, b2, b3 正規化 行 正規直交基底 求 . ,求 正規直交基底c1, c2, c3 ,

c1 = 1 3



1 2 2

=



13

2 3 2 3

, c2 = 1



2

313

2 3

=



2

313

2 3

, c3 = 1



2 3 2

313

=



2 3 2

313

.

1

2

3

(3)

[解]: 与 基底 直交基底 .

b1 =a1 =

 1 2 3

,

b2 =a2 (a2, b1) (b1, b1)b1 =

 2 3 4





10 7 20

7 30

7

=



4 7 1

727

,

b3 =a3 (a3, b1)

(b1, b1)b1(a3, b2) (b2, b2)b2 =

 3 4 1



 1 2 3





8 3 2

343

=



23

4

323

.

直交基底 b1, b2, b3 正規化 行 正規直交基底 求 . ,求 正規直交基底c1, c2, c3 ,

c1 =

14 14

 1 2 3

=



14

14 14 7 3 14 14

, c2 =

21 3



4 7 1

727

=



4 21

21 21 21

22121

, c3 =

6 4



23

4

323

=



66

6 3

66

.

(6) a1 =



 1

1 1

1



, a2 =



 1 1 0 0



, a3 =



 0 0 1 1



, a4 =



 0 1 1 0





[解]: 与 基底 直交基底 .

b1 =a1 =



 1

1 1

1



,

b2 =a2 (a2, b1) (b1, b1)b1 =



 1 1 0 0







 0 0 0 0



=



 1 1 0 0



,

b3 =a3 (a3, b1)

(b1, b1)b1 (a3, b2) (b2, b2)b2 =



 0 0 1 1







 0 0 0 0







 0 0 0 0



=



 0 0 1 1



,

b4 =a4 (a4, b1)

(b1, b1)b1 (a4, b2)

(b2, b2)b2 (a4, b3) (b3, b3)b3 =



 0 1 1 0







 0 0 0 0









1 2 1 2

0 0







 0 0

1 2 1 2



=





12

1 2 1

212



.

直交基底 b1, b2, b3, b4 正規化 行 正規直交基底 求 . , 求

(4)

正規直交基底 c1, c2, c3, c4 ,

c1 = 1 2



 1

1 1

1



=





1

212

1

212



, c2 =

2 2



 1 1 0 0



=





2

2 2 2

0 0



,

c3 =

2 2



 0 0 1 1



=



 0

0

2

2 2 2



, c4 = 1





12

1 2 1

212



=





12

1 2 1

212



.

(7) a1 =



 1 3 0 0



, a2 =





1 1 0 0



, a3 =



 0 0 1 1



, a4 =



 0 0 3 4





[解]: 与 基底 直交基底 .

b1 =a1 =



 1 3 0 0



,

b2 =a2 (a2, b1) (b1, b1)b1 =





1 1 0 0









1 5 3 5

0 0



=





65

2 5

0 0



,

b3 =a3 (a3, b1)

(b1, b1)b1 (a3, b2) (b2, b2)b2 =



 0 0 1 1







 0 0 0 0







 0 0 0 0



=



 0 0 1 1



,

b4 =a4 (a4, b1)

(b1, b1)b1 (a4, b2)

(b2, b2)b2 (a4, b3) (b3, b3)b3 =



 0 0 3 4







 0 0 0 0







 0 0 0 0







 0 0

7 2 7 2



=



 0 0

12

1 2



.

直交基底 b1, b2, b3, b4 正規化 行 正規直交基底 求 . , 求 正規直交基底 c1, c2, c3, c4 ,

c1 =

10 10



 1 3 0 0



=





10 10 3

10 10

0 0



, c2 =

10 4





65

2 5

0 0



=





31010

10 10

0 0



,

c3 =

2



 0 0



=



 0

0



, c4 = 2



 0 0



=



 0 0



.

(5)

(8) a1 =



 1 1 1 1



, a2 =



 2 1 2 1



, a3 =



 0

2 1

1



, a4 =



 1

3 1

1





[解]: 与 基底 直交基底 .

b1 =a1 =



 1 1 1 1



,

b2 =a2 (a2, b1) (b1, b1)b1 =



 2 1 2 1









3 2 3 2 3 2 3 2



=





1

212

1

212



,

b3 =a3 (a3, b1)

(b1, b1)b1 (a3, b2) (b2, b2)b2 =



 0

2 1

1









12

12

12

12







 1

1 1

1



=





12

12

1 2 1 2



,

b4 =a4 (a4, b1)

(b1, b1)b1 (a4, b2)

(b2, b2)b2 (a4, b3) (b3, b3)b3 =



 1

3 1

1









12

12

12

12









3

232

3

232









12

12

1 2 1 2



=





1

212

12

1 2



.

直交基底 b1, b2, b3, b4 正規化 行 正規直交基底 求 . , 求 正規直交基底 c1, c2, c3, c4 ,

c1 = 1 2



 1 1 1 1



=





1 2 1 2 1 2 1 2



, c2 = 1





1

212

1

212



=





1

212

1

212



,

c3 = 1





12

12

1 2 1 2



=





12

12

1 2 1 2



, c4 = 1





1

212

12

1 2



=





1

212

12

1 2



.

(9) a1 =



 1 1

1

1



, a2 =



 1 1 1

1



, a3 =



 1

1 1 1



, a4 =



 1 1 1 1





(6)

[解]: 与 基底 直交基底 .

b1 =a1 =



 1 1

1

1



,

b2 =a2 (a2, b1) (b1, b1)b1 =



 1 1 1

1









1 2 1

212

12



=





1 2 1 2 3

212



,

b3 =a3 (a3, b1)

(b1, b1)b1 (a3, b2) (b2, b2)b2 =



 1

1 1 1









12

12

1 2 1 2









1 6 1 6 1

216



=





4

323

0

2 3



,

b4 =a4 (a4, b1)

(b1, b1)b1 (a4, b2)

(b2, b2)b2 (a4, b3) (b3, b3)b3 =



 1 1 1 1







 0 0 0 0









1 3 1 3

1

13









2

313

0

1 3



=



 0 1 0 1



.

直交基底 b1, b2, b3, b4 正規化 行 正規直交基底 求 . , 求 正規直交基底 c1, c2, c3, c4 ,

c1 = 1 2



 1 1

1

1



=





1 2 1

212

12



, c2 =

3 3





1 2 1 2 3

212



=





3

6 3

6 3 2

63



,

c3 =

6 4





4

323

0

2 3



=





6 3

66

0

6 6



, c4 =

2 2



 0 1 0 1



=





0

2 2

0

2 2



.

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[r]

[r]

凹レンズの焦点 F’ の内側 ( レンズに近い側 ) に物体を置いたときにできる虚像を図示したものであり,凹レンズの. 場合,物体を焦点