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Internat. J. Math. & Math. Sci.

Vol. 9 No. 4

(1986)

825-827

825

ON A GENERALIZATION OF HAUSDORFF SPACE

TAPAS DUTTA A/31

C.I.T. Buildings

Singhee-Bagan Calcutta -700007, India

(Received December 4, 1985 and in revised form May 17, 1986)

ABSTRACT. Here, a new separation axiom as a generalization of that of Hausdorff is introduced. Its simple consequences and relations with some other known separation axioms are studied. That a non-indiscrete topological group satisfies this axiom is shown.

KEY

WORDS

AND

PHRASES.

Separation Axiom, Hausdoff spac,

e.

1980 AMS SUBJECT

CLASSIFICATION CODES.

54A05.

I.

INTRODUCTION. Five well known separation axioms are introduced and these signifi- cances are studies in literature

[1,2,3,4].

In addition to this, other separation axioms are formulated and their consequences with interrelations were discussed by sev- eral investigators. In this connection the papers of C. E. Aull

[5]

and A. Wilansky

[6]

are informative and of much interest.

Here a new separation axiom, which may be taken as a generalization of the Hausdorff axiom is stated and then its relations with T

O TI, T

2 separation axioms and also with other separation axioms KC, US

[6].

After that simple consequences of the aboveaxioms are studied. Finally non-indiscrete topological groups always imply as H-separatlon axiom.

DEFINITION. Let

(X,T)

be a topological space. In a non singletone space, for

every.

x X there is a y X such that x G, y H and Gn H for some G,H Then the space is called H-space and also every singletone space is H-space.

REMARK I.

It is clear that every Hausdorff space is

H-space.

But converse is not necessarily true by the following example.

EXAMPLE

i. Consider X

{1,2,3,4}

and

T {, X,{1,2},{3,4}}

there

(X,)

is a

H-space

but

(X,I)

is not a Hausdorff space. The spac9 is also non-T

O space.

REMARK 2. Example and the following example show that a H-space and T-space are independent of each other.

EXAMPLE

2. Consider X

{1,2,3,4}

and

{, X,{I},{1,2},{1,2,3}},

then

(X,)

is

T0-space

but it is not a

H-space.

REMARK 3. The following example shows that in the property of being

H-space

is non- hereditary property.

(2)

826 T. DUTTA

EXAMPLE 3. Consider X

{1,2,3,4,5}

and

T {, X,{1,2,3},{4,5}}

then

(X,I)

is H-space. Now consider the sub-space

{1,2,3}

which is not a H-space.

REMARK 4. A

T0-space

which is also H-space is not necessarily a

T1-space

(by the

following example).

EXAMPLE 4. Consider X

{1,2,3,4}

and

{, X,{I},{1,2},{3},{3,4},{1,3},{1,3,4}, {1,2,3}

Now it is clearly a

T0-space

and also a H-space. But

(X,I)

is not a

Tl-space.

REMARK 5. Example and the following example shows that a

H-space

and a

T1-space

are

independent of each other.

EXAMPLE 5. Consider R is the set of all real numbers with cofinite topology. It is clear that the space is T but it is not

H-space.

REMARK 6. A

Tl-space

which is also

H-space

is not necessarily a

T2-space (by

the fol-

lowing

example).

EXAMPLE 6. Let us consider X

{1,2,3,4

and the topology is cofintite topo- logy. Now let

X* {0,1,2,3

and

T* {G,

G u

{}

G T}.

Then clearly

(X*,T*)

is a topological space and it is clear that the space is

T1-space

as well as

H-space.

But the space is not a

T2-space.

DEFINITION

[6].

A topological space is called KC-space if every compact set is closed.

REMARK

7. Example and the following example shows that a H-space and a KC-space are independent of each other.

EXAMPLE 7. Let us consider R

+

be the set of all positive real numbers with co- countable topology. It is clear that the space is

KC-space.

But it is not a

H-space.

REMARK 8. A KC-space which is also H-space is not necessarily a

T2-space

(by the fol-

lowing

example).

EXAMPLE 8. Consider R

+

be the set of all positive real numbers with co-countable topology

I.

Now let be the set of all non-negative real numbers and

T {G,

G

u {0}:

G e

}.

Then clearly

(R,)

is a topological space and it is clear that the space is KC-space as well as

H-space.

But the space is not a

T2-space.

DEFINITION

[6].

A topological space is called a US-space if every convergent sequence has exactly one limit to which it converges.

REMARK 9. (a) Remark 5 and Remark 7 shows that US-space and

H-space

are independent of each other. Since T

2 => KC => US => T (forom

[6]).

(b)

From the above example 8 it is clear that a

US-space

which is also

H-space

is not necessarily a

T2-space.

RESULT i. Let

(X,TI)

and

(Y,T2)

be two topological spaces. If a non-constant function f: X Y is continuous and Y is

T2-space.

Then X is a

H-space.

PROOF. Since f: X Y is a non-constant function, so for every x e X there is a ye X such that f(x)

# f(y).

Since f(x),

f(y)

Y and Y is

T2-space

Hence

there are U,V

T2

such that f(x) U,

f(y)

V and U

OV .

Then

f-l(u)

and f-i(V) are mutually disjoint non-empty open in X [since f is continuous].

(3)

GENERALIZATION OF HAUSDORFF SPACE 827

x e

f-l(u)

and y e

f-l(v)

and

f-l(u)

n

f-l(u) .

Hence X is

H-space.

RESULT 2. Let

(X,T I)

and

(Y,T2)

be two topological spaces. If

(X,T I)

is a

H-space.

Then the product space

y

is also a

H-space.

PROOF. Let

(x,y)

be any point in XY. Since X is a H-space, then there is a x X such that x e VI, x V2 and V n V

2 for some VI, V 2

T

I.

And if y U

T

2, then

(x,y)

c

VIU. (xl,Y) V2U

and

(VIU)

o

(VU)

(since

V V

2

=).

Hence XY is a

H-space.

RESULT 3. Let

(X,T)

be a non-indiscrete topological group. Then

(X,I)

is

H-space.

PROOF. Let x e X and V be a non-empty proper open set in X. Case I: Let x e since V be a non-empty proper open set in X, so there is a y e X such that y e

-Iv.

Let A x Then A is a open neighborhood of e(identity). Let B A A Then B is a open neighborhood of e and B B

-I.

Let U yB. Then U is a open neighborhood of y. We claim that x U. For suppose x U. Then x c yB so

-i -i -i -i -I

B-ly-I

x yb for some b e B. Then x b y But b e

B-

B. So x

-I By-1 x-lvy-1

By 1.

Now B A, then x e

Ay -I

Then e e Vy

-1.

So y V a contradiction. So x U. Hence we get, for every x X, there is ye X such that x V, ye U and x U, y V for some V,U

eT.

Let

V’

be the complement of V, so

V’

is closed and xe

V’,

y e

V’.

Since every topological group is regular, so there are

UI,V

c

T

such that x e VI,

V’

U and V o U

.

Then x V and

ye U such that V U for some

VI,U T.

Hence

(X,)

is H-space.

Case II: If

xV

then

x V’ (complement

of

V).

Since V is open in X so

V’

is closed in X. Since V is non-empty so there is a ye V, so ye

V’.

Since every topological group is regular space. So there are

VI,V

2 e such that y V and

V’

V

2 such that V n V

2

.

Hence xe V2,

y

V and V V2

.

Hence it

is

H-space.

REFERENCES

I. KELLEY,

J. L., General

Topology,

D. Van Nostrand Co. Inc., 1955.

2. ALEKSANOROV, P. S., Combinatorial

Topology,

Graylock Press, Rochester, N. Y., 1956.

3. PONTRJAGIN, L. S., Topologische Gruppen, B. G. Teubner Verlagsesellschaft, Leipzig, 1957.

4. DUTTA, M.. DEBNATH, L., and MUKHERJEE, T. K. Elements of General Topology, World Press, 1964.

5. AULL, C. E., qeDaraton of

B-comac

set, Math.

Ann., 158____(1965),

197-202.

6. WILANSKY, A., Between

T

and

Ti,

Amer. Math. Monthly,

74(1967),

261-264.

参照

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