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Volume 2012, Article ID 602513,17pages doi:10.1155/2012/602513

Research Article

General Iterative Methods for

Equilibrium Problems and Infinitely Many Strict Pseudocontractions in Hilbert Spaces

Peichao Duan and Aihong Wang

College of Science, Civil Aviation University of China, Tianjin 300300, China

Correspondence should be addressed to Peichao Duan,[email protected] Received 11 January 2012; Revised 24 February 2012; Accepted 25 February 2012 Academic Editor: Rudong Chen

Copyrightq2012 P. Duan and A. Wang. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

We propose an implicit iterative scheme and an explicit iterative scheme for finding a common element of the set of fixed point of infinitely many strict pseudocontractive mappings and the set of solutions of an equilibrium problem by the general iterative methods. In the setting of real Hilbert spaces, strong convergence theorems are proved. Our results improve and extend the corresponding results reported by many others.

1. Introduction

LetHbe a real Hilbert space and letCbe a nonempty closed convex subset ofH. LetFbe a bifunction fromC×CtoR, whereRis the set of real numbers.

The equilibrium problem forF:C×C → Ris to findxCsuch that F

x, y

≥0 1.1

for allyC. The set of such solutions is denoted by EPF.

A mappingSofCis said to be aκ-strict pseudocontraction if there exists a constant κ∈0,1such that

SxSy2xy2κI−Sx−I−Sy2 1.2 for allx, yC; see1. We denote the set of fixed points ofSbyFS i.e.,FS {x ∈C: Sxx}.

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Note that the class of strict pseudocontractions strictly includes the class of nonex- pansive mappings which are mappingS on Csuch that

SxSyxy 1.3 for allx, yC. That is,Sis nonexpansive if and only ifSis a 0-strict pseudocontraction.

Numerous problems in physics, optimization, and economics reduce to finding a solution of the equilibrium problem. Some methods have been proposed to solve the equilibrium problem1.1; see, for instance,2–4. In particular, Combettes and Hirstoaga5 proposed several methods for solving the equilibrium problem. On the other hand, Mann 6, Shimoji and Takahashi 7 considered iterative schemes for finding a fixed point of a nonexpansive mapping. Further, Acedo and Xu 8 projected new iterative methods for finding a fixed point of strict pseudocontractions.

In 2006, Marino and Xu3introduced the general iterative method and proved that the algorithm converged strongly. Recently, Liu 2 considered a general iterative method for equilibrium problems and strict pseudocontractions. Tian 9 proposed a new general iterative algorithm combining an L-Lipschitzian and η-strong monotone operator. Very recently, Wang10considered a general composite iterative method for infinite family strict pseudocontractions.

In this paper, motivated by the above facts, we introduce two iterative schemes and obtain strong convergence theorems for finding a common element of the set of fixed points of a infinite family of strict pseudocontractions and the set of solutions of the equilibrium problem1.1.

2. Preliminaries

Throughout this paper, we always write for weak convergence and → for strong convergence. We need some facts and tools in a real Hilbert space H which are listed as below.

Lemma 2.1. LetHbe a real Hilbert space. There hold the following identities:

ix−y2x2− y2−2x−y, y, ∀x, y∈H;

iitx 1−ty2tx2 1−ty2t1txy2, ∀t∈0,1, ∀x, y∈H.

Lemma 2.2see11. Assume that{αn}is a sequence of nonnegative real numbers such that

αn1≤ 1−γn

αnδn, 2.1

wheren}is a sequence in0,1andn}is a sequence such that i

n1γn∞;

iilimn→ ∞supδnn≤0 or

n1n|<∞.

Then, limn→ ∞αn0.

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Recall that given a nonempty closed convex subsetCof a real Hilbert spaceH, for anyxH, there exists a unique nearest point inC, denoted byPCx, such that

x−PCx ≤xy 2.2

for allyC. Such aPCis called the metric (or the nearest point) projection ofHontoC. As known, yPCxif and only if there holds the relation:

xy, yz

≥0 ∀z∈C. 2.3

Lemma 2.3see10. LetA:HHbe aL-Lipschitzian andη-strongly monotone operator on a Hilbert spaceHwithL >0,η >0, 0< μ <2η/L2, and 0< t <1. Then,S I−tμA:HHis a contraction with contractive coefficient 1tτandτ 1/2μ2η−μL2.

Lemma 2.4see1. LetS : CCbe aκ-strict pseudocontraction. DefineT : CCby Tx λx 1−λSxfor eachxC. Then, asλ ∈κ,1,T is a nonexpansive mapping such that

FT FS.

Lemma 2.5see9. LetHbe a Hilbert space andf :HHbe a contraction with coefficient 0 < α <1, andA:HHanL-Lipschitzian continuous operator andη-strongly monotone with L >0,η >0. Then for 0< γ < μη/α:

xy,

μAγf x

μAγf y

μηγαxy2, x, yH. 2.4 That is,μAγfis strongly monotone with coefficientμηγα.

Let{Sn}be a sequence ofκn-strict pseudo-contractions. DefineSn θnI 1−θnSn, θn ∈ κn,1. Then, byLemma 2.4,Snis nonexpansive. In this paper, consider the mappingWndefined by

Un,n1I,

Un,ntnSnUn,n1 1−tnI, Un,n−1tn−1Sn−1Un,n 1−tn−1I,

. . . ,

Un,itiSiUn,i1 1−tiI, . . . ,

Un,2 t2S2Un,3 1−t2I, WnUn,1t1S1Un,2 1−t1I,

2.5

wheret1, t2, . . .are real numbers such that 0tn < 1. Such a mappingWnis called aW-mapping generated byS1, S2, . . .andt1, t2, . . .. It is easy to seeWnis nonexpansive.

Lemma 2.6see7. LetCbe a nonempty closed convex subset of a strictly convex Banach space E, letS1, S2, . . .be nonexpansive mappings ofCinto itself such thati1FSi/and lett1, t2, . . .be

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real numbers such that 0< tib <1, for everyi1,2, . . .. Then, for anyxCandkN, the limit limn→ ∞Un,kxexists.

UsingLemma 2.6, one can define the mappingWofCinto itself as follows:

Wx: lim

n→ ∞Wnx lim

n→ ∞Un,1x, xC. 2.6

Lemma 2.7see7. LetCbe a nonempty closed convex subset of a strictly convex Banach spaceE.

LetS1, S2, . . .be nonexpansive mappings ofCinto itself such thati1FSi/and lett1, t2, . . .be real numbers such that 0< tib <1, for alli1. IfKis any bounded subset ofC, then

nlim→ ∞sup

x∈KWx−Wnx0. 2.7

Lemma 2.8see12. LetCbe a nonempty closed convex subset of a Hilbert spaceH, let{Si:CC}be a family of infinite nonexpansive mappings withi1FSi/∅, lett1, t2, . . .be real numbers such that 0< tib <1, for everyi1,2, . . .. ThenFWi1FSi.

For solving the equilibrium problem, assume that the bifunction F satisfies the following conditions:

A1Fx, x 0 for allxC;

A2Fis monotone, that is,Fx, y Fy, x≤0 for anyx, yC;

A3for eachx, y, zC, lim supt→0Ftz 1−tx, yFx, y;

A4Fx,·is convex and lower semicontinuous for eachxC.

Recall some lemmas which will be needed in the rest of this paper.

Lemma 2.9see13. LetCbe a nonempty closed convex subset of H, letF be bifunction from C×CtoRsatisfying (A1)–(A4), and letr >0 andxH. Then, there existszCsuch that

F z, y

1 r

yz, zx

≥0, ∀y∈C. 2.8

Lemma 2.10see5. Forr >0, x∈H, define a mappingTr :HCas follows:

Trx

zC|F z, y

1 r

yz, zx

≥0, ∀y∈C 2.9

for allxH. Then, the following statements hold:

iTr is single-valued;

iiTr is firmly nonexpansive, that is, for anyx, yH, TrxTry2

TrxTry, xy

; 2.10

iiiFTr EPF;

ivEPFis closed and convex.

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Lemma 2.11see14. Let{xn}and{zn}be bounded sequences in a Banach space and letn}be a sequence of real numbers such that 0<lim infn→ ∞βn ≤lim supn→ ∞βn <1 for alln0,1,2, . . ..

Suppose thatxn1 1−βnznβnxnfor alln0,1,2, . . .and lim supn→ ∞zn1−zn−xn1−xn0. Then limn→ ∞znxn0.

Lemma 2.12see4. LetC, H, F, andTrxbe as inLemma 2.10. Then, the following holds:

TsxTtx2st

s TsxTtx, Tsxx 2.11 for alls, t >0 andxH.

Lemma 2.13see10. LetHbe a Hilbert space and letCbe a nonempty closed convex subset ofH, andT :CCa nonexpansive mapping withFT/∅. If{xn}is a sequence inCweakly converging toxand if{I−Txn}converges strongly toy, thenI−Txy.

3. Main Result

Throughout the rest of this paper, we always assume thatf is a contraction ofHinto itself with coefficient α ∈ 0,1, and A is a L-Lipschitzian continuous operator and η-strongly monotone onHwithL >0,η >0. Assume that 0< μ <2η/L2and 0< γ < μη−μL2/2/α τ/α.

Define a mappingVnβnI 1−βnWnTrn. Since bothWnandTrn are nonexpansive, it is easy to getVnis also nonexpansive. Consider the following mappingGnonHdefined by

Gnnγfx

IαnμA

Vnx, ∀x∈H, nN, 3.1

whereαn∈0,1. By Lemmas2.3and2.10, we have GnxGnyαnγfx−f

y 1−αnτVnxVny

αnγαxy 1−αnτxy

1−αn

τγαxy.

3.2

Since 0 < 1−αnτ −γα < 1, it follows thatGn is a contraction. Therefore, by the Banach contraction principle,Gnhas a unique fixed pointedxnfHsuch that

xfnαnγf xfn

IαnμA

Vnxfn. 3.3

For simplicity, we will writexnforxfn provided no confusion occurs. Next we prove the sequences{xn} converges strongly to ax ∈ Ω ∩i1FSiEPF which solves the variational inequality:

γfμA

x, px

≤0, ∀p∈Ω. 3.4

Equivalently,xPΩI−μAγfx.

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Theorem 3.1. LetCbe a nonempty closed convex subset of a real Hilbert spaceHandFa bifunction fromC×CtoRsatisfying (A1)–(A4). LetSi :CCbe a familyκi-strict pseudocontractions for some 0κi <1. Assume the setΩ ∩i1FSiEPF/∅. Letfbe a contraction ofHinto itself with α ∈ 0,1and letA be aL-Lipschitzian continuous operator and η-strongly monotone with L >0, η >0, 0< μ <2η/L2and 0< γ < μη−μL2/2/ατ/α. For everyn∈N, letWnbe the mapping generated bySiandtias in2.5. Let{xn}and{un}be sequences generated by the following algorithm:

un Trnxn, ynβnxn

1−βn Wnun, xnαnγfxn

IμαnA yn.

3.5

Ifn}, {βn}, and{rn}satisfy the following conditions:

i{αn} ⊂0,1, limn→ ∞αn0;

ii0<lim infn→ ∞βn≤lim supn→ ∞βn<1;

iii{rn} ⊂0,∞, lim infn→ ∞rn>0.

Then,{xn}converges strongly to a pointx∈Ω, which solves the variational inequality3.4.

Proof. The proof is divided into several steps.

Step 1. Show first that{xn}is bounded.

Take anyp∈Ω, by3.5andLemma 2.3, we derive that xnn

γfxnμAp

IμαnA yn

IμαnA p

αnαγxnnγf p

μAp 1−αnτynp

≤ 1−αn

τγαxnnγf p

μAp.

3.6

It follows thatxnp ≤γfp−μAp/τγα.

Hence,{xn}is bounded, so are{un}and{yn}. It follows from the Lipschitz continuity ofAthat{Axn}and{Aun}are also bounded. From the nonexpansivity offandWn, it follows that{fxn}and{Wnxn}are also bounded.

Step 2. Show that

n→ ∞limunxn0, lim

n→ ∞unyn0. 3.7

Notice that

unyn≤ unxnxnynunxnαnγfxnμAyn. 3.8

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ByLemma 2.10, we have unp2TrnxnTrnp2

xnp, unp 1

2

unp2xnp2− xnun2 . 3.9 It follows that

unp2xnp2− xnun2. 3.10 Thus, fromLemma 2.1and3.10, we get

xnp2 αn

γfxnμAp

IμαnA yn

IμαnA p2

≤1−αnτ2ynp2n

γfxnγf p

γf p

μAp, xnp

≤1−αnτ2unp2n

γfxnγf p

γf p

μAp, xnp

≤1−αnτ2xnp2− xnun2

nγαxnp2nγf p

μApxnp

1−2αn τ−γα

αnτ2xn−p2−1−αnτ2xn−un2nγf p

−μApxn−p

xnp2 αnτ2xnp2−1−αnτ2xnun2nγf p

μApxnp. 3.11

It follows that

1−αnτ2xnun2≤αnτ2xnp2nγf p

μApxnp. 3.12 Sinceαn → 0, we have

nlim→ ∞unxn0. 3.13

From3.8, it is easy to get

nlim→ ∞unyn0. 3.14

Step 3. Show that

nlim→ ∞unWun0, 3.15

unWnununynynWnununynβnxnununWnun. 3.16

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This implies that

1−βn

unWnununynβnxnun. 3.17

From conditionii,3.13, and3.14, we have

unWnun −→0. 3.18

Notice that

unWun ≤ unWnunWnunWun. 3.19

ByLemma 2.7and3.18, we get3.15.

Since{un}is bounded, so there exists a subsequence{unj}which converges weakly to x.

Step 4. Show thatx∈Ω.

SinceCis closed and convex,Cis weakly closed. So, we havexC.

From3.15, we obtainWunj x. From Lemmas2.8,2.4, and 2.13, we havexFW i1FSii1FSi.

ByunTrnxn, for alln≥1, we have F

un, y 1

rn

yun, unxn

≥0, ∀y∈C. 3.20

It follows fromA2that 1 rn

yun, unxn

F y, un

, ∀y∈C. 3.21

Hence, we get

1 rnj

yunj, unjxnj

F y, unj

, ∀y∈C. 3.22

It follows from conditioniii,3.13, andA4that 0≥F

y, x

, ∀y∈C. 3.23

Forswith 0 < s≤ 1 andyC, letys sy 1−sx. SinceyCandxC, we obtain ysCand henceFys, x≤0. So, we have

0f ys, ys

sF ys, y

1−sF ys, x

sF ys, y

. 3.24

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Dividing bys, we get

F ys,y

≥0, ∀y∈C. 3.25

Lettings → 0 and fromA3, we get F

x, y

≥0 3.26

for allyCandx∈EPF.Hencex∈Ω.

Step 5. Show thatxnx,wherexPΩI−μAγfx: xnxαn

γfxnμAx

IμαnA yn

IμαnA

x. 3.27

Hence, we obtain xnx2αn

γfxnμAx, xnx

IμαnA yn

IμαnA

x, xnx

;

αn

γfxnμAx, xnx

1−αnτxnx2. 3.28

It follows that

xnx2≤ 1 τ

γfxnμAx, xnx

1 τ

γ

fxnfx, xnx

γfxμAx, xnx

≤ 1 τ

γαxnx2

γfxμAx, xnx .

3.29

This implies that

xnx2

γfxμAx, xnx

τγα . 3.30

In particular,

xnjx2

γfxμAx, xnjx

τγα . 3.31

Sincexnj x, it follows from3.31thatxnjxasj → ∞. Next, we show thatx solves the variational inequality3.4.

By the iterative algorithm3.5, we have xnαnγfxn

IμαnA

ynαnγfxn

IμαnA

Vnxn. 3.32

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Therefore, we have

μαnAxnαnγfxn μαnAxnxn

IμαnA

Vnxn, 3.33

that is,

μAγf

xn− 1 αn

I−VnxnμαnAxnAVnxn

. 3.34

Hence, forp∈Ω, μAγf

xn, xnp −1

αn

I−VnxnμαnAxnAVnxn, xnp

−1 αn

I−Vnxn−I−Vnp, xnp μ

AxnAVnxn, xnp

μ

AxnAVnxn, xnp .

3.35 SinceIVnis monotonei.e.,x−y,I−Vnx−I−Vny ≥0, for allx, yH. This is due to the nonexpansivity ofVn.

Now replacingnin3.35withnjand lettingj → ∞, we obtain μAγf

x, xp lim

j→ ∞

μAγf

xnj, xnjp

≤ lim

j→ ∞μ

AxnjAVnxnj, xnjp 0.

3.36 That is,x∈Ωis a solution of3.4. To show that the sequence{xn}converges strongly tox, we assume thatxnkx. By the same processing as the proof above, we derive x∈Ω.

Moreover, it follows from the inequality3.36that μAγf

x, xx

≤0. 3.37

Interchangingxandx, we get

μAγf

x,xx

≤0. 3.38

ByLemma 2.5, adding up3.37and3.38yields μηγα

xx 2

μAγf x

μAγf

x, xx

≤0. 3.39 Hencexxand, therefore,xnxasn → ∞,

IμAγf

xx, xp

≥0, ∀p∈Ω. 3.40

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This is equivalent to the fixed point equation:

PΩ

IμAγf

xx. 3.41

Theorem 3.2. LetCbe a nonempty closed convex subset of a real Hilbert spaceHandFa bifunction fromC×CtoRsatisfying (A1)–(A4). LetSi :CCbe a familyκi-strict pseudocontractions for some 0κi <1. Assume the setΩ ∩i1FSiEPF/∅. Letfbe a contraction ofHinto itself with α ∈ 0,1and letA be aL-Lipschitzian continuous operator and η-strongly monotone with L >0,η >0,0< μ <2η/L2, and 0< γ < μη−μL2/2/ατ/α. For everyn∈N, letWnbe the mapping generated bySiand 0< tib <1. Givenx1H, let{xn}and{un}be sequences generated by the following algorithm:

unTrnxn, ynβnxn

1−βn Wnun, xn1αnγfxn

IμαnA yn.

3.42

Ifn},{βn}and{rn}satisfy the following conditions:

i{αn} ⊂0,1, limn→ ∞αn0 and

n1αn ∞;

ii0<lim infn→ ∞βn≤lim supn→ ∞βn<1;

iii{rn} ⊂0,∞, lim infn→ ∞rn>0 and limn→ ∞|rn1rn|0.

Then,{xn}converges strongly tox∈Ω, which solves the variational inequality3.4.

Proof. The proof is divided into several steps.

Step 1. Show first that{xn}is bounded.

Taking anyp∈Ω, we have xn1n

γfxnμAp

IμαnA yn

IμαnA p

αnγfxnγf

pγf p

μAp 1−αnτynp

αnαγxnnγf p

μAp 1−αnτynp

1−αn

ταγxnn

ταγγf p

μAp ταγ

≤max

xnp,γf p

μAp ταγ

.

3.43

By induction, we obtainxn−p ≤max{x1−p,γfp−μAp/τ−αγ}, n≥1.Hence,{xn} is bounded, so are{un}and{yn}. It follows from the Lipschitz continuity ofAthat{Axn}and {Aun}are also bounded. From the nonexpansivity off andWn, it follows that{fxn}and {Wnxn}are also bounded.

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Step 2. Show that

xn1xn −→0. 3.44

Observe that

un1unTrn1xn1Trnxn

≤ Trn1xn1Trn1xnTrn1xnTrnxn

≤ xn1xnTrn1xnTrnxn,

3.45

and from2.5, we have

Wn1unWnunt1S1Un1,2unt1S1Un,2un

t1Un1,2unUn,2un

t1t2S2Un1,3unt2S2Un,3un

t1t2Un1,3unUn,3un

≤ · · ·

n

i1

tiUn1,n1unUn,n1un

M1

n i1

ti,

3.46

whereM1supn{Un1,n1unUn,n1un}.

Supposexn1βnxn 1−βnzn, thenzn xn1βnxn/1−βn αnγfxn I− μαnAynβnxn/1−βn.

Hence, we have zn1zn αn1γfxn1

Iμαn1A

yn1βn1xn1

1−βn1αnγfxn

IμαnA

ynβnxn

1−βn αn1

γfxn1μAyn1

1−βn1 yn1βn1xn1

1−βn1αn

γfxnμAyn

1−βnynβnxn

1−βn αn1

γfxn1μAyn1

1−βn1 βn1xn1

1−βn1

Wn1un1βn1xn1

1−βn1

αn

γfxnμAyn

1−βnβnxn 1−βn

Wnunβnxn

1−βn

αn1

γfxn1μAyn1 1−βn1αn

γfxnμAyn

1−βn Wn1un1Wnun.

3.47

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It follows from3.45,3.46, and the above result that zn1zn

αn1

1−βn1γfxn1μAyn1 αn

1−βnγfxnμAynWn1un1Wnun

αn1

1−βn1 αn

1−βn

M2Wn1un1Wn1unWn1unWnun

αn1

1−βn1 αn 1−βn

M2un1unWn1unWnun

≤ xn1xnTrn1xnTrnxn

αn1

1−βn1 αn 1−βn

M2M1

n i1

ti,

3.48

whereM2supn{γfxnμAyn}. Hence, we get zn1zn − xn1xn ≤ Trn1xnTrnxn

αn1

1−βn1 αn 1−βn

M2M1

n i1

ti. 3.49

From conditioni,iii, 0< tnb <1, andLemma 2.12, we obtain lim sup

n→ ∞ zn1zn − xn1xn≤0. 3.50

ByLemma 2.11,we have limn→ ∞znxn0. Thus,

nlim→ ∞xn1xn lim

n→ ∞

1−βn

znxn0. 3.51

ByLemma 2.12,3.45and3.44, we obtain

un1un −→0. 3.52

Step 3. Show that

xnWxn −→0. 3.53

Observe that

xnWnxn ≤ xnWnunWnunWnxn ≤ xnWnununxn, xnWnun ≤ xnxn1xn1ynynWnunxnxn1

xn1ynβnunxnxnWnun.

3.54

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From conditioniand3.5,we can obtain 1−βn

xnWnun ≤ xn−xn1xn1−ynβnun−xn

≤ xnxn1αnγfxn−μAynβnunxn. 3.55 ByLemma 2.10, we get

un−p2Trnxn−Trnp2

Trnxn−Trnp, xn−p 1

2

un−p2xnp2xnun2 . 3.56 This implies that

unp2xnp2− xnun2. 3.57 By nonexpansivity ofWn, we have

ynp2βnxnp2

1−βnunp2xnp2− 1−βn

xnun2. 3.58

It follows from3.42that xn1p2αn

γfxnp

IμαnA yn

IμαnA n

pμAp2

αnγfxnp2 1−αnτynp2αnpμAp2

αnγfxnp2 1−αnτxnp2− 1−βn

xnun2

αnpμAp2

αnγfxnp2xnp2− 1−βn

xnun2αnpμAp2.

3.59 This implies that

1−βn

xnun2αnγfxnp2pμAp2

xnp2xn1p2

αnγfxnp2pμAp2

xnpxn1pxn1xn. 3.60

From conditioni,ii, and3.44, we have

xnun −→0. 3.61

Further we havexnWnun → 0. Thus we get

xnWnxn −→0. 3.62

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On the other hand, we have

xnWxn ≤ xnWnxnWnxnWxn ≤ xnWnxnsup

xn∈CWnxnWxn. 3.63 Combining3.62, the last inequality, andLemma 2.7, we obtain3.53.

Step 4. Show that

lim sup

n→ ∞

γfμA

x, xnx

≤0, 3.64

wherexPΩI−μAγfxis a unique solution of the variational inequality3.4. Indeed, take a subsequence{xnj}of{xn}such that

lim sup

n→ ∞

γfμA

x, xnx lim

j→ ∞

γfμA

x, xnjx

. 3.65

Since{xnj} is bounded, there exists a subsequence{xnjk}of {xnj} which converges weakly to q. Without loss of generality, we can assumexnj q. From 3.53, we obtain Wxnj q.

By the same argument as in the proof of Theorem 3.1, we have q ∈ Ω. Since x PΩI−μAγfx, it follows that

lim sup

n→ ∞

γfμA

x, xnx lim

j→ ∞

γfμA

x, xnjx

γfμA

x, qx

≤0.

3.66

Step 5. Show that

xn−→x. 3.67

Since

γfμA

x, xn1x

γfμA

x, xn1xn

γfμA

x, xnx

γfμA

xxn1xn

γfμA

x, xnx

. 3.68

It follows from3.44and3.66that lim sup

n→ ∞

γfμA

x, xn1x

≤0.

xn1x2 αnγfxn

IμαnA

ynx2 IμαnA

yn

IμαnA

xαn

γfxnμAx2

(16)

IμαnA yn

IμαnA

x2n

γfxnμAx, xn1x

≤1−αnτ2ynx2n

γfxnγfx, xn1x

n

γfμA

x, xn1x

≤1−αnτ2xnx2αnαγ

xnx2xn1x2

n

γfμA

x, xn1x . 3.69

This implies that xn1x2

≤ 1−αnτ2αnαγ

1−αnαγ xnx2n

1−αnαγ

γfμA

x, xn1x

1−2αn ταγ 1−αnαγ

xnx2n

1−αnαγ

γfμA

x, xn1x

αnτ2 1−αnαγM3,

3.70 whereM3supnxnx2, n≥1. It is easily to see thatγnnτ−αγ/1−αnαγ. Hence, byLemma 2.2, the sequence{xn}converges strongly tox.

Remark 3.3. IfF≡0, thenTheorem 3.2reduces toTheorem 3.1of Wang10.

Acknowledgments

The authors would like to thank the referee for valuable suggestions to improve the manuscript NSFC Tianyuan Youth Foundation of Mathematics of Chinano. 11126136, and the Fundamental Research Funds for the Central UniversitiesGRANT: ZXH2011C002.

References

1 F. E. Browder and W. V. Petryshyn, “Construction of fixed points of nonlinear mappings in Hilbert space,” Journal of Mathematical Analysis and Applications, vol. 20, pp. 197–228, 1967.

2 Y. Liu, “A general iterative method for equilibrium problems and strict pseudo-contractions in Hilbert spaces,” Nonlinear Analysis: Theory, Methods & Applications, vol. 71, no. 10, pp. 4852–4861, 2009.

3 G. Marino and H.-K. Xu, “Weak and strong convergence theorems for strict pseudo-contractions in Hilbert spaces,” Journal of Mathematical Analysis and Applications, vol. 329, no. 1, pp. 336–346, 2007.

4 S. Takahashi and W. Takahashi, “Strong convergence theorem for a generalized equilibrium problem and a nonexpansive mapping in a Hilbert space,” Nonlinear Analysis: Theory, Methods & Applications, vol. 69, no. 3, pp. 1025–1033, 2008.

5 P. L. Combettes and S. A. Hirstoaga, “Equilibrium programming in Hilbert spaces,” Journal of Non- linear and Convex Analysis, vol. 6, no. 1, pp. 117–136, 2005.

6 W. R. Mann, “Mean value methods in iteration,” Proceedings of the American Mathematical Society, vol.

4, pp. 506–510, 1953.

7 K. Shimoji and W. Takahashi, “Strong convergence to common fixed points of infinite nonexpansive mappings and applications,” Taiwanese Journal of Mathematics, vol. 5, no. 2, pp. 387–404, 2001.

8 G. L. Acedo and H.-K. Xu, “Iterative methods for strict pseudo-contractions in Hilbert spaces,” Non- linear Analysis: Theory, Methods & Applications, vol. 67, no. 7, pp. 2258–2271, 2007.

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