Fixed Point Theory and Applications Volume 2011, Article ID 945051,24pages doi:10.1155/2011/945051
Research Article
A Viscosity of Ces `aro Mean Approximation Methods for a Mixed Equilibrium, Variational Inequalities, and Fixed Point Problems
Thanyarat Jitpeera, Phayap Katchang, and Poom Kumam
Department of Mathematics, Faculty of Science, King Mongkut’s University of Technology Thonburi (KMUTT), Bangmod, Bangkok 10140, Thailand
Correspondence should be addressed to Poom Kumam,poom.kum@kmutt.ac.th Received 6 September 2010; Accepted 15 October 2010
Academic Editor: Qamrul Hasan Ansari
Copyrightq2011 Thanyarat Jitpeera et al. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.
We introduce a new iterative method for finding a common element of the set of solutions for mixed equilibrium problem, the set of solutions of the variational inequality for a β-inverse- strongly monotone mapping, and the set of fixed points of a family of finitely nonexpansive mappings in a real Hilbert space by using the viscosity and Ces`aro mean approximation method.
We prove that the sequence converges strongly to a common element of the above three sets under some mind conditions. Our results improve and extend the corresponding results of Kumam and Katchang2009, Peng and Yao2009, Shimizu and Takahashi1997, and some authors.
1. Introduction
Throughout this paper, we assume thatHis a real Hilbert space with inner product and norm are denoted by·,·and · , respectively and letCbe a nonempty closed convex subset of H. A mappingT :C → Cis callednonexpansiveifTx−Ty ≤ x−y, for allx, y ∈C.
We useFTto denote the set of fixed points ofT, that is,FT {x ∈ C : Tx x}. It is assumed throughout the paper thatT is a nonexpansive mapping such thatFT/∅. Recall that a self-mappingf :C → Cis acontractiononCif there exists a constantα∈0,1and x, y∈Csuch thatfx−fy ≤αx−y.
Letϕ:C → R∪{∞}be a proper extended real-valued function andφbe a bifunction ofC×CintoR, whereRis the set of real numbers. Ceng and Yao1considered the following mixed equilibrium problemfor findingx∈Csuch that
φ x, y
ϕ y
≥ϕx, ∀y∈C. 1.1
The set of solutions of1.1is denoted by MEPφ, ϕ. We see that x is a solution of problem 1.1implies thatx ∈ domϕ {x ∈ C| ϕx < ∞}. If ϕ 0, then the mixed equilibrium problem1.1becomes the following equilibrium problem is to findx∈Csuch that
φ x, y
≥0, ∀y∈C. 1.2
The set of solutions of 1.2 is denoted by EPφ. The mixed equilibrium problems include fixed point problems, variational inequality problems, optimization problems, Nash equilibrium problems, and the equilibrium problem as special cases. Numerous problems in physics, optimization, and economics reduce to find a solution of1.2. Some methods have been proposed to solve the equilibrium problemsee2–14.
Let B : C → H be a mapping. The variational inequality problem, denoted by VIC, B, is to findx∈Csuch that
Bx, y−x
≥0, 1.3
for ally∈C.The variational inequality problem has been extensively studied in the literature.
See, for example, 15, 16 and the references therein. A mapping B of C into H is called monotone if
Bx−By, x−y
≥0, 1.4
for allx, y∈C. B is calledβ-inverse-strongly monotoneif there exists a positive real number β >0 such that for allx, y∈C
Bx−By, x−y
≥βBx−By2. 1.5 LetAbe a strongly positive linear bounded operator onH: that is, there is a constantγ >0 with property
Ax, x ≥γx2, ∀x∈H. 1.6 A typical problem is to minimize a quadratic function over the set of the fixed points of a nonexpansive mapping on a real Hilbert spaceH:
x∈FTmin 1
2Ax, x −hx, 1.7
whereAis strongly positive linear bounded operator andhis a potential function forγfi.e., hx γfxforx∈H. Moreover, it is shown in17that the sequence{xn}defined by the scheme
xn1nγfxn l−nATxn, 1.8 converges strongly tozPFTI−Aγfz.
In 1997, Shimizu and Takahashi18originally studied the convergence of an iteration process{xn}for a family of nonexpansive mappings in the framework of a real Hilbert space.
They restate the sequence{xn}as follows:
xn1αnx 1−αn 1 n1
n j0
Tjxn, forn0,1,2, . . . , 1.9
wherex0andxare all elements ofCandαnis an appropriate in0,1.They proved that{xn} converges strongly to an element of fixed point ofTwhich is the nearest tox.
In 2007, Plubtieng and Punpaeng19proposed the following iterative algorithm:
φ un, y
1 rn
y−un, un−xn
≥0, ∀y∈H, xn1nγfxn I−nATun.
1.10
They proved that if the sequence{n}and{rn}of parameters satisfy appropriate condition, then the sequences{xn}and{un}both converge to the unique solutionzof the variational inequality
A−γf
z, x−z
≥0, ∀x∈FT∩EP φ
, 1.11
which is the optimality condition for the minimization problem
x∈FT∩EPφmin 1
2Ax, x −hx, 1.12 wherehis a potential function forγfi.e.,hx γfxforx∈H.
In 2008, Peng and Yao20introduced an iterative algorithm based on extragradient method which solves the problem of finding a common element of the set of solutions of a mixed equilibrium problem, the set of fixed points of a family of finitely nonexpansive mappings and the set of the variational inequality for a monotone, Lipschitz continuous mapping in a real Hilbert space. The sequences generated byv∈C,
x1x∈C, φ
un, y ϕ
y
−ϕun
1 rn
y−un, un−xn
≥0, ∀y∈C,
ynPC
un−γnBun
, xn1αnvβnxn
1−αn−βn WnPC
un−λnByn ,
1.13
for alln≥1, whereWnis W-mapping. They proved the strong convergence theorems under some mind conditions.
In this paper, motivated by the above results and the iterative schemes considered in 9,18–20, we introduce a new iterative process below based on viscosity and Ces`aro mean
approximation method for finding a common element of the set of fixed points of a family of finitely nonexpansive mappings, the set of solutions of the variational inequality problem for aβ-inverse-strongly monotone mapping and the set of solutions of a mixed equilibrium problem in a real Hilbert space. Then, we prove strong convergence theorems which are connected with5,21–24. We extend and improve the corresponding results of Kumam and Katchang9, Peng and Yao20, Shimizu and Takahashi18and some authors.
2. Preliminaries
LetHbe a real Hilbert space with inner product·,·and norm · and letCbe a nonempty closed convex subset ofH. Then
x−y2x2−y2−2
x−y, y
, 2.1
λx 1−λy2λx2 1−λy2−λ1−λx−y2, 2.2 for allx, y∈Handλ∈0,1. For every pointx∈H, there exists a uniquenearest pointin C, denoted byPCx, such that
x−PCx ≤ x−y, ∀y∈C. 2.3
PC is called the metric projection ofH ontoC. It is well known that PC is a nonexpansive mapping ofHontoCand satisfies
x−y, PCx−PCy
≥PCx−PCy2, 2.4 for everyx, y∈H.Moreover,PCxis characterized by the following properties:PCx∈Cand
x−PCx, y−PCx
≤0, 2.5
x−y2≥ x−PCx2y−PCx2, 2.6 for allx∈H, y∈C. LetBbe a monotone mapping of C into H. In the context of the variational inequality problem the characterization of projection2.5implies the following:
u∈VIC, B⇐⇒uPCu−λBu, λ >0. 2.7 It is also known that H satisfies the Opial condition25, that is, for any sequence{xn} ⊂H withxn x, the inequality
lim inf
n→ ∞ xn−x<lim inf
n→ ∞ xn−y, 2.8
holds for everyy∈Hwithx /y.
A set-valued mappingU:H → 2His calledmonotoneif for allx, y∈H,f∈Uxand g∈Uyimplyx−y, f−g ≥0. A monotone mappingU:H → 2Hismaximalif the graph of GUofUis not properly contained in the graph of any other monotone mapping. It is known that a monotone mappingUis maximal if and only if forx, f∈H×H,x−y, f−g ≥0 for everyy, g∈GUimpliesf∈Ux. LetBbe a monotone mapping ofCintoHand letNCy be thenormal conetoCaty∈C, that is,NCy{w∈H:u−y, w ≤0,∀u∈C}and define
Uy
⎧⎨
⎩
ByNCy, y∈C,
∅, y /∈C. 2.9
ThenUis the maximal monotone and 0∈Uyif and only ify∈VIC, B; see26.
For solving the mixed equilibrium problem, let us give the following assumptions for a bifunctionφ:C×C → Rand a proper extended real-valued functionϕ:C → R∪ {∞}
satisfies the following conditions:
A1φx, x 0 for allx∈C;
A2φis monotone, that is,φx, y φy, x≤0 for allx, y∈C;
A3for eachx, y, z∈C, limt→0φtz 1−tx, y≤φx, y;
A4for eachx∈C,y→φx, yis convex and lower semicontinuous;
A5for eachy∈C,x→φx, yis weakly upper semicontinuous;
B1for eachx∈Handr >0, there exist a bounded subsetDx⊆Candyx∈Csuch that for anyz∈C\Dx,
φ z, yx
ϕ yx
1 r
yx−z, z−x
< ϕz; 2.10
B2C is a bounded set.
We need the following lemmas for proving our main results.
Lemma 2.1Peng and Yao20. LetCbe a nonempty closed convex subset of H. Letφ:C×C → R be a bifunction satisfies (A1)–(A5) and letϕ:C → R∪ {∞}be a proper lower semicontinuous and convex function. Assume that either (B1) or (B2) holds. For r > 0 andx ∈ H, define a mapping Tr :H → Cas follows:
Trx
z∈C:φ z, y
ϕ y
1 r
y−z, z−x
≥ϕz, ∀y∈C
, 2.11
for allx∈H. Then, the following hold.
1For eachx∈H, Trx/∅;
2Tr is single-valued;
3Tr is firmly nonexpansive, that is, for anyx, y∈H,Trx−Try2 ≤ Trx−Try, x−y;
4FTr MEPφ, ϕ;
5MEPφ, ϕis closed and convex.
Lemma 2.2Xu27. Assume{an}is a sequence of nonnegative real numbers such that
an1≤1−αnanδn, n≥0, 2.12
where{αn}is a sequence in0,1and{δn}is a sequence inRsuch that 1∞
n1αn∞,
2lim supn→ ∞δn/αn≤0 or∞
n1|δn|<∞.
Then limn→ ∞an0.
Lemma 2.3 Osilike and Igbokwe 28. LetC,·,· be an inner product space. Then for all x, y, z∈Candα, β, γ∈0,1withαβγ 1,we have
αxβyγz2 αx2βy2γz2−αβx−y2−αγx−z2−βγy−z2. 2.13
Lemma 2.4 Suzuki 29. Let {xn} and {yn} be bounded sequences in a Banach space X and let{βn} be a sequence in0,1 with 0 < lim infn→ ∞βn ≤ lim supn→ ∞βn < 1.Supposexn1 1−βnynβnxnfor all integersn ≥ 0 and lim supn→ ∞yn1−yn − xn1−xn≤ 0.Then, limn→ ∞yn−xn0.
Lemma 2.5Marino and Xu17. AssumeAis a strongly positive linear bounded operator on a Hilbert spaceHwith coefficientγ >0 and 0< ρ≤ A−1. ThenI−ρA ≤1−ργ.
Lemma 2.6Bruck30. LetCbe a nonempty bounded closed convex subset of a uniformly convex Banach spaceEandT : C → Ca nonexpansive mapping. For eachx ∈ Cand the Ces`aro means Tnx 1/n1n
i0Tix,then lim supn→ ∞Tnx−TTnx0.
3. Main Results
In this section, we show a strong convergence theorem for finding a common element of the set of fixed points of a family of finitely nonexpansive mappings, the set of solutions of mixed equilibrium problem and the set of solutions of a variational inequality problem for a β-inverse-strongly monotone mapping in a real Hilbert space by using the viscosity of Ces`aro mean approximation method.
Theorem 3.1. Let C be a nonempty closed convex subset of a real Hilbert space H. Let φ be a bifunction of C×Cinto real numbersRsatisfying (A1)–(A5) and let ϕ : C → R∪ {∞} be a proper lower semicontinuos and convex function. LetTi:C → Cbe a nonexpansive mappings for all i1,2,3, . . . , n, such thatΘ:n
i1FTi∩VIC, B∩MEPφ, ϕ/∅. Letfbe a contraction ofC
into itself with coefficientα∈0,1and letBbe aβ-inverse-strongly monotone mapping ofCintoH.
LetAbe a strongly positive bounded linear self-adjoint onHwith coefficientγ >0 and 0< γ < γ/α.
Assume that eitherB1orB2holds. Let{xn},{yn}and{un}be sequences generated byx0∈C,un∈C and
φ un, y
ϕ y
−ϕun
1 rn
y−un, un−xn
≥0, ∀y∈C, ynδnun 1−δnPCun−λnBun,
xn1 αnγfxn βnxn 1−βn
I−αnA 1 n1
n i0
Tiyn, ∀n≥0,
3.1
where{αn},{βn}andδn⊂0,1,{λn} ⊂0,2βand{rn} ⊂0,∞satisfy the following conditions:
i∞
n0αn∞and limn→ ∞αn0, iilimn→ ∞δn 0,
iii0<lim infn→ ∞βn≤lim supn→ ∞βn<1,
iv{λn} ⊂a, b,∃a, b∈0,2βand limn→ ∞|λn1−λn|0, vlim infn→ ∞rn>0 and limn→ ∞|rn1−rn|0.
Then,{xn}converges strongly toz∈Θ,wherezPΘI−Aγfz, which is the unique solution of the variational inequality
A−γf
z, x−z
≥0, ∀x∈Θ. 3.2
Proof. Now, we have1−βnI−αnA ≤1−βn−αnγ see9, page 479. Sinceλn ∈0,2β andBis aβ-inverse-strongly monotone mapping. For anyx, y∈C, we have
I−λnBx−I−λnBy2x−y−λnBx−By2 x−y2−2λn
x−y, Bx−By
λ2nBx−By2
≤x−y2−2λnβBx−By2λ2nBx−By2 x−y2λn
λn−2βBx−By2
≤x−y2.
3.3
It follows thatI−λnBx−I−λnBy ≤ x−y, henceI−λnBis nonexpansive.
Letx∗∈Θ, Trn be a sequence of mapping defined as inLemma 2.1andunTrnxn, for alln≥0,we have
un−x∗Trnxn−Trnx∗ ≤ xn−x∗. 3.4
By the fact thatPCandI−λnBare nonexpansive andx∗PCx∗−λnBx∗, we get
yn−x∗δnun 1−δnPCun−λnBun−x∗
≤δnun−x∗ 1−δnPCun−λnBun−PCx∗−λnBx∗
≤δnun−x∗ 1−δnI−λnBun−I−λnBx∗
≤δnun−x∗ 1−δnun−x∗ un−x∗
≤ xn−x∗.
3.5
LetTn 1/n1n
i0Ti; it follows that
Tnx−Tny
1 n1
n i0
Tix− 1 n1
n i0
Tiy
≤ 1 n1
n i0
Tix−Tiy
≤ 1 n1
n i0
x−y
n1 n1x−y x−y,
3.6
which implies thatTnis nonexpansive. Sincex∗∈Θ,we haveTnx∗ 1/n1n
i0Tix∗ 1/n1n
i0x∗x∗, for allx, y∈C.By3.5and3.6, we have xn1−x∗αn
γfxn−Ax∗
βnxn−x∗ 1−βn
I−αnA
Tnyn−x∗
≤αnγfxn−Ax∗βnxn−x∗
1−βn−αnγ
yn−x∗
≤αnγfxn−Ax∗βnxn−x∗
1−βn−αnγ
xn−x∗
≤αnγfxn−fx∗αnγfx∗−Ax∗
1−αnγ
xn−x∗
≤αnγαxn−x∗αnγfx∗−Ax∗
1−αnγ
xn−x∗
1−αn
γ−γα
xn−x∗αn
γ−γαγfx∗−Ax∗ γ−γα
≤max
x0−x∗,γfx∗−Ax∗ γ−γα
.
3.7
Hence{xn}is bounded and also{un},{yn}and{Tnyn}are bounded.
Next, we show that limn→ ∞xn1−xn 0.Observing thatun Trnxn ∈domϕand un1Trn1xn1∈domϕ, we get
φ un, y
ϕ y
−ϕun
1 rn
y−un, un−xn
≥0, ∀y∈C, 3.8
φ un1, y
ϕ y
−ϕun1 1 rn1
y−un1, un1−xn1
≥0, ∀y∈C. 3.9
Takeyun1in3.8andyunin3.9, by using conditionA2; it follows that
un1−un,un−xn
rn −un1−xn1 rn1
≥0. 3.10
Thusun1−un, un−un1xn1−xn1−rn/rn1un1−xn1 ≥0. Without loss of generality, let us assume that there exists a nonnegative real numbercsuch thatrn > c, for alln ≥ 1.
Then, we have
un1−un2≤ un1−un
xn1−xn 1− rn
rn1
un1−xn1
3.11
and hence
un1−un ≤ xn1−xn 1
rn1|rn1−rn|un1−xn1
≤ xn1−xn1
c|rn1−rn|M1,
3.12
whereM1 sup{un−xn :n∈N}. On the other hand, letvn PCun−λnBun; it follows from the definition of{yn}that
yn1−yn{δn1un1 1−δn1PCun1−λn1Bun1}
− {δnun 1−δnPCun−λnBun}
δn1un1−un δn1−δnun 1−δn1PCun1−λn1Bun1
−1−δn1PCun−λnBun 1−δn1PCun−λnBun
−1−δnPCun−λnBun δn1un1−un δn1−δnun
1−δn1{PCun1−λn1Bun1−PCun−λnBun} δn−δn1PCun−λnBun
≤δn1un1−un|δn1−δn|unvn 1−δn1un1−λn1Bun1−un−λnBun δn1un1−un|δn1−δn|unvn
1−δn1un1−λn1Bun1−un−λn1Bun un−λn1Bun−un−λnBun
≤δn1un1−un|δn1−δn|unvn 1−δn1{un1−un|λn1−λn|Bun}
|δn1−δn|unvn un1−un 1−δn1|λn1−λn|Bun
≤ |δn1−δn|unvn un1−un|λn1−λn|Bun
≤ |δn1−δn|unvn xn1−xn 1
c|rn1−rn|M1
|λn1−λn|Bun.
3.13
We compute that
Tn1yn1−Tnyn ≤ Tn1yn1−Tn1ynTn1yn−Tnyn
≤ yn1−yn
1 n2
n1
i0
Tiyn− 1 n1
n i0
Tiyn
yn1−yn
1 n2
n i0
Tiyn 1
n2Tn1yn− 1 n1
n i0
Tiyn
yn1−yn
− 1 n1n2
n i0
Tiyn 1
n2Tn1yn
≤ yn1−yn 1 n1n2
n i0
Tiyn 1
n2Tn1yn
≤ yn1−yn 1 n1n2
n i0
Tiyn−Tix∗x∗
1 n2
Tn1yn−Tn1x∗x∗
≤ yn1−yn 1 n1n2
n i0
yn−x∗x∗
1 n2
yn−x∗x∗
≤ yn1−yn n1 n1n2
yn−x∗x∗
1
n2yn−x∗ 1 n2x∗ yn1−yn 2
n2yn−x∗ 2 n2x∗
≤ |δn1−δn|unvn xn1−xn1
c|rn1−rn|M1
|λn1−λn|Bun 2
n2yn−x∗ 2 n2x∗.
3.14
Letxn1 1−βnznβnxn; it follows that
zn xn1−βnxn 1−βn αnγfxn
1−βn
I−αnA Tnyn
1−βn ,
3.15
and hence
zn1−zn
αn1γfxn1
1−βn1
I−αn1A
Tn1yn1 1−βn1
− αnγfxn
1−βn
I−αnA Tnyn 1−βn
αn1γfxn1 1−βn1
1−βn1
Tn1yn1 1−βn1
−αn1ATn1yn1
1−βn1 −αnγfxn 1−βn
−
1−βn Tnyn
1−βn αnATnyn
1−βn
αn1 1−βn1
γfxn1−ATn1yn1 αn
1−βn
ATnyn−γfxn
Tn1yn1−Tnyn
≤ αn1
1−βn1γfxn1−ATn1yn1 αn
1−βnATnyn−γfxnTn1yn1−Tnyn
≤ αn1
1−βn1γfxn1−ATn1yn1 αn
1−βnATnyn−γfxn |δn1−δn|unvn xn1−xn 1
c|rn1−rn|M1
|λn1−λn|Bun 2
n2yn−x∗ 2 n2x∗.
3.16
Therefore,
zn1−zn − xn1−xn ≤ αn1
1−βn1γfxn1−ATn1yn1 αn
1−βnATnyn−γfxn |δn1−δn|unvn
1
crn1−rnM1
|λn1−λn|Bun 2
n2yn−x∗ 2 n2x∗.
3.17
It follows fromn → ∞and the conditionsi–v, that
lim sup
n→ ∞ zn1−zn − xn1−xn≤0. 3.18
FromLemma 2.4and3.18, we obtain limn→ ∞zn−xn0 and also
nlim→ ∞xn1−xn lim
n→ ∞
1−βn
zn−xn0. 3.19
Next, we show thatxn−un → 0 asn → ∞.Forx∗∈Θ,we obtain un−x∗2Trnxn−Trnx∗2
≤ Trnxn−Trnx∗, xn−x∗ un−x∗, xn−x∗ 1
2
un−x∗2xn−x∗2− un−x∗−xnx∗2
1 2
un−x∗2xn−x∗2− un−xn2 ,
3.20
and hence
un−x∗2≤ xn−x∗2− un−xn2. 3.21
Sinceyn−x∗ ≤ un−x∗and fromLemma 2.3and3.21, we obtain xn1−x∗2αnγfxn βnxn
1−βn
I−αnA
Tnyn−x∗2 αn
γfxn−Ax∗
βnxn−x∗ 1−βn
I−αnA
Tnyn−x∗2
≤αnγfxn−Ax∗2βnxn−x∗2
1−βn−αnγyn−x∗2
≤αnγfxn−Ax∗2βnxn−x∗2
1−βn−αnγ
un−x∗2
≤αnγfxn−Ax∗2βnxn−x∗2
1−βn−αnγ
xn−x∗2− xn−un2
≤αnγfxn−Ax∗2xn−x∗2−
1−βn−αnγ
xn−un2.
3.22
Then, we have 1−βn−αnγ
xn−un2≤αnγfxn−Ax∗2xn−x∗2− xn1−x∗2
αnγfxn−Ax∗2xn−xn1xn−x∗xn1−x∗. 3.23
By limn→ ∞xn1−xn0,iandiv, imply that
nlim→ ∞un−xn0. 3.24
Since lim infn→ ∞rn>0,we obtain
nlim→ ∞
xn−un rn
lim
n→ ∞
1
rnxn−un0. 3.25
Next, we show that limn→ ∞Tnyn−xn0.Indeed, observe that
xn−Tnyn ≤ xn−xn1xn1−Tnyn
xn−xn1αnγfxn βnxn 1−βn
I−αnA
Tnyn−Tnyn
xn−xn1αnγfxn−αnATnynαnATnynβnxn−βnTnynβnTnyn
1−βn
I−αnA
Tnyn−Tnyn
≤ xn−xn1αnγfxn−ATnynβnxn−Tnyn
3.26
and then
xn−Tnyn ≤ 1
1−βnxn−xn1 αn
1−βnγfxn−ATnyn. 3.27
Since limn→ ∞xn1−xn0,iandiv, we get limn→ ∞xn−Tnyn0.
Next, we show that limn→ ∞yn−vn0,wherevnPCun−λnBun.FromLemma 2.3 and3.3, we obtain
xn1−x∗2≤αnγfxn−Ax∗2βnxn−x∗2 1−βn
I−αnATnyn−x∗2
≤αnγfxn−Ax∗2βnxn−x∗2
1−βn−αnγyn−x∗2 αnγfxn−Ax∗2βnxn−x∗2
1−βn−αnγ
δnun−x∗ 1−δn{PCun−λnBun−PCx∗−λnBx∗}2
≤αnγfxn−Ax∗2βnxn−x∗2
1−βn−αnγ
δnun−x∗2
1−βn−αnγ
1−δnun−λnBun−x∗−λnBx∗2 αnγfxn−Ax∗2βnxn−x∗2
1−βn−αnγ
δnun−x∗2
1−βn−αnγ
1−δnun−x∗−λnBun−Bx∗2
≤αnγfxn−Ax∗2βnxn−x∗2
1−βn−αnγ
δnun−x∗2
1−βn−αnγ
1−δn
xn−x∗2λn
λn−2β
Bun−Bx∗2
≤αnγfxn−Ax∗2
1−αnγ
xn−x∗2
1−βn−αnγ
1−δnλn
λn−2β
Bun−Bx∗2
≤αnγfxn−Ax∗2xn−x∗2
1−βn−αnγ
1−δna b−2β
Bun−Bx∗2.
3.28
It follows that 0≤
1−βn−αnγ
1−δna 2β−b
Bun−Bx∗2
≤αnγfxn−Ax∗2xn−x∗2− xn1−x∗2
≤αnγfxn−Ax∗2xn1−xnxn−x∗xn1−x∗.
3.29
Sinceαn → 0 andxn1−xn → 0,asn → ∞,we obtainBun−Bx∗ → 0 asn → ∞.Using 2.1, we have
vn−x∗2PCun−λnBun−PCx∗−λnBx∗2
≤ un−λnBun−x∗−λnBx∗, vn−x∗ 1
2
un−λnBun−x∗−λnBx∗2vn−x∗2
−1 2
un−λnBun−x∗−λnBx∗−vn−x∗2
1 2
un−x∗2vn−x∗2− un−vn−λnBun−Bx∗2
1 2
un−x∗2vn−x∗2
−
un−vn2λ2nBun−Bx∗2−2λnun−vn, Bun−Bx∗
≤ 1 2
un−x∗2vn−x∗2− un−vn2−λ2nBun−Bx∗2
2λnun−vn, Bun−Bx∗ ,
3.30
so, we obtain
vn−x∗2≤ un−x∗2− un−vn2−λ2nBun−Bx∗22λnun−vn, Bun−Bx∗, 3.31