Volume 2012, Article ID 816529,26pages doi:10.1155/2012/816529
Research Article
Viscosity Approximation Method for System of Variational Inclusions Problems and Fixed-Point Problems of a Countable Family of
Nonexpansive Mappings
Chaichana Jaiboon
1and Poom Kumam
21Department of Mathematics, Faculty of Liberal Arts, Rajamangala University of Technology Rattanakosin (RMUTR), Bangkok 10100, Thailand
2Department of Mathematics, Faculty of Science, King Mongkut’s University of Technology Thonburi (KMUTT), Bangkok 10140, Thailand
Correspondence should be addressed to Chaichana Jaiboon,chaichana.j@rmutr.ac.thand Poom Kumam,poom.kum@kmutt.ac.th
Received 22 January 2012; Accepted 2 March 2012 Academic Editor: Yonghong Yao
Copyrightq2012 C. Jaiboon and P. Kumam. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.
We propose new iterative schemes for finding the common element of the set of common fixed points of countable family of nonexpansive mappings, the set of solutions of the variational inequality problem for relaxed cocoercive and Lipschitz continuous, the set of solutions of system of variational inclusions problem, and the set of solutions of equilibrium problems in a real Hilbert space by using the viscosity approximation method. We prove strong convergence theorem under some parameters. The results in this paper unify and generalize some well-known results in the literature.
1. Introduction
LetCbe a nonempty closed convex subset of a real Hilbert spaceH. A mappingSofCinto itself is called nonexpansive ifSx−Sy ≤ x−yfor allx, y ∈ C. We denote byFSthe set of fixed points ofS; that is, FS {x ∈ C : Sx x}. If C ⊂ H is nonempty, closed and convex and letS :C → Cbe a nonexpansive mapping, thenFSis closed and convex andFS/∅, whenCis bounded; see, for example,1,2. The metric projection,PC, onto a given nonempty, closed and convex subsetC, satisfies the nonexpansive withFPC C. A mappingB:C → Cis called monotone ifBx−By, x−y ≥0 for allx, y∈C. A mapping B : C → Cis calledβ-inverse-strongly monotone if there exists a constantβ > 0 such that
Bx−By, x−y ≥ βx−y2, for all x, y ∈ C. A mapping B : C → Cis called relaxed φ, ω-cocoercive if there existsφ, ω >0 such that
Bx−By, x−y
≥
−φBx−By2ωx−y2, ∀x, y∈C. 1.1 A mappingB :C → Cis said to beξ-Lipschitz continuous if there existsξ ≥ 0 such that
Bx−By≤ξx−y, ∀x, y∈C. 1.2 Let B : H → H be a single-valued nonlinear mapping and M : H → 2H a multivalued mapping. The variational inclusion problem is to findx∈Hsuch that
θ∈Bx Mx, 1.3
whereθis the zero vector inH. The set of solutions of problem1.3is denoted byIB, M.
IfM∂ψC, whereCis a nonempty closed convex subset ofHand∂ψC :H → 0,∞is the indicator function ofC; that is,
ψCx
0, x∈C,
∞, x /∈C, 1.4 then, the variational inclusion problem 1.3 is equivalent to the variational inequality problems denoted by VIC, Bwhich is to findx∈Csuch that
Bx, y−x
≥0, ∀y∈C. 1.5
In 2003, Takahashi and Toyoda3to findx∗∈FS∩VIC, Bintroduced the following iterative scheme:
x0∈C chosen arbitrary,
xn1αnxn 1−αn SPCxn−ξnBxn, ∀n≥0, 1.6 whereBis aβ-inverse-strongly monotone mapping,{αn}is a sequence in0, 1, and{ξn}is a sequence in0,2β. They showed that ifFS∩VIC, Bis nonempty, then the sequence{xn} generated by1.6converges weakly to somex∗∈FS∩VIC, B.
In 2008, Zhang et al.4to findx∗ ∈ FS∩IM, B. They introduced the following new iterative scheme:
x0∈C chosen arbitrary, ynJM,λxn−λBxn, xn1αnx 1−αnSyn, ∀n≥0,
1.7
whereJM,λ IλM−1is the resolvent operator associated withMand a positive number λ,{αn}is a sequence in the interval0,1.
LetFbe a bifunction ofC×CintoR, whereRis the set of real numbers. The equilibrium problem forF:C×C → Ris to findx∈Csuch that
F x,y
≥0, ∀y∈C. 1.8
The set of solutions of1.8is denoted by EPF. Many problems in applied sciences, such as monotone inclusion problems, variational inequality problems, saddle point problems, Nash equilibria in noncooperative games, as well as certain fixed-point problems reduce to finding some element to EPFin Hilbert and Banach spacessee5–14.
Given anyr >0. The operatorTr:H → Cdefined by
Trx z∈C:F z, y
1 r
y−z, z−x
≥0, ∀y∈C
, 1.9
is called the resolvent ofFsee5,6.
It is shown in 6 that, under suitable hypotheses on F to be stated precisely in Section 2,Tr:H → Cis single valued and firmly nonexpansive and satisfies
FTr EPF, ∀r >0. 1.10 Using this result, for finding an element of FS∩VIC, B∩EPF, Su et al. 15 introduced the following iterative scheme by the viscosity approximation method in Hilbert spaces:
x0∈Cchosen arbitrary,
xn1 αnfxn 1−αnSPCI−ξnBTrnxn, ∀n≥0, 1.11 wheref : C → Cis a contractioni.e.,fx−fy ≤ ψx−y,for allx, y ∈ Cand 0 ≤ ψ < 1and{αn} ⊂ 0,1,ξn ⊂ 0,2β, andrn ⊂ 0,∞satisfy some appropriate conditions.
Furthermore, they prove{xn}converges strongly to the same point x∗ ∈ FS∩VIC, B∩ EPF, wherex∗PFS∩VIC,B∩EPFfx∗.
In this paper, motivated and inspired by the above facts, we introduce a new iterative scheme for finding a common element of the set of solutions of the variational inequalities for μ-Lipschitz continuous and relaxedφ, ω-cocoercive mapping, the set of solutions to the variational inclusion for family of α-inverse strongly monotone mappings, the set of fixed points of a countable family of nonexpansive mappings, and the set of solutions of an equilibrium problem in a real Hilbert space by using the viscosity approximation method.
Strong convergence results are derived under suitable conditions in a real Hilbert space.
2. Preliminaries
In this section, we will recall some basic notations and collect some conclusions that will be used in the next section.
Let H be a real Hilbert space whose inner product and norm are denoted by ·,· and · , respectively. We denote strong convergence of{xn} to x ∈ H byxn → xand
weak convergence by xn x. Let C be nonempty closed convex subset of H. Recall that for all x ∈ H there exists a unique nearest point in C to x denoted PCx; that is, x−PCx ≤ x−y, for ally∈C. The mappingPC is nonexpansive; that is,PCx−PCy ≤ x−y, for allx, y ∈ H. The mappingPC is firmly nonexpansive; that is,PCx−PCy2 ≤ PCx−PCy, x−y , for allx, y∈H. It is well known that
x∈VIC, B⇔xPCx−λBx, ∀λ >0. 2.1 A set-valued mappingM : H → 2H is called monotone if, for allx, y ∈ H,f ∈ Mxand g ∈Myimplyx−y, f−g ≥ 0. A monotone mappingM:H → 2His called maximal, if its graph of any GraphM:{x, f∈H×H |f ∈Mx}ofMis not properly contained in the graph of any other monotone mapping. It is well known that a monotone mappingM is maximal if and only if for allx, f∈H×H,x−y, f−g ≥0, for ally, g∈GraphM the graph of mappingMimplies thatf∈Mx.
Definition 2.1. Let M : H → 2H be a multivalued maximal monotone mapping; then the set-valued mappingJM,λ:H → Hdefined by
JM,λx I λM−1x, ∀x∈H, 2.2 is called the resolvent operator associated withM, whereλis any positive number andIis the identity mapping.
Lemma 2.2see16. LetM:H → 2Hbe a maximal monotone mapping and letB :H → H be a Lipschitz continuous mapping. Then the mappingMB : H → 2H is a maximal monotone mapping.
Lemma 2.3see16,17.
1The resolvent operator JM,λis single valued and nonexpansive for allλ >0; that is, JM,λx−JM,λ
y ≤x−y, ∀x, y∈H, ∀λ >0. 2.3
2The resolvent operatorJM,λis 1-inverse-strongly monotone; that is, JM,λx−JM,λ
y2≤
x−y, JM,λx−JM,λ y
, ∀x, y∈H. 2.4 Lemma 2.4see17.
1Letx∈His a solution of problem1.3if and only ifxJM,λI−λBfor allλ >0; that is,
IB, M FJM,λI−λB, ∀λ >0. 2.5
2Ifλ∈0,2β, thenIB, Mis a closed convex subset inH.
Lemma 2.5see18. Each Hilbert spaceH satisfies Opial’s condition; that is, for any sequence {xn} ⊂Hwithxn x, the inequality
lim inf
n→ ∞ xn−x<lim inf
n→ ∞ xn−y 2.6
holds for eachy∈Hwithy /x.
Lemma 2.6see19. Let{xn}and{zn}be bounded sequences in a Banach spaceE, and let{βn}be a sequence in0,1with 0<lim infn→ ∞βn≤lim supn→ ∞βn<1. Supposexn1 1−βnznβnxn for all integersn≥1 and lim supn→ ∞zn1−zn − xn1−xn≤0. Then, limn→ ∞zn−xn0.
Lemma 2.7see20. Assume{an}is a sequence of nonnegative real numbers such that
an1 ≤1−bnanδn, n≥0, 2.7 where{bn}is a sequence in0,1and{δn}is a sequence inRsuch that
1∞
n1bn∞,
2lim supn→ ∞δn/bn≤0 or∞
n1|δn|<∞.
Then limn→ ∞an0.
Lemma 2.8. LetHbe a real Hilbert space. Then hold the following identities:
itx 1−ty2tx2 1−ty2−t1−tx−y2, ∀t∈0,1, ∀x, y∈H, iixy2≤ x22y, xy , ∀x, y∈H.
Lemma 2.9 see21. LetC be a nonempty closed subset of a Banach space, and let{Sn} be a sequence of mappings ofCinto itself. Suppose that∞
n1sup{Sn1z−Snz:z ∈C} <∞. Then, for eachy∈C,{Sny}converges strongly to some point ofC. Moreover, letSbe a mapping ofCinto itself defined by
Sy lim
n→ ∞Sny, ∀y∈C. 2.8
Then limn→ ∞sup{Sz−Snz:z∈C}0.
For solving the equilibrium problem for a bifunctionF :C×C → R, let us assume thatFsatisfies the following conditions:
A1Fx, x 0 for allx∈C;
A2Fis monotone, that is,Fx, y Fy, x≤0, ∀ x, y∈C;
A3for eachx, y, z∈C, limt↓0Ftz 1−tx, y≤Fx, y;
A4for eachx∈C, y→Fx, yis convex and lower semicontinuous.
Lemma 2.10see5. LetCbe a nonempty closed convex subset ofH, and letFbe a bifunction of C×CintoRsatisfying (A1)–(A4). Letr >0 andx∈H. Then, there existsz∈Csuch that
F z, y
1 r
y−z, z−x
≥0, ∀y∈C. 2.9
Lemma 2.11see6. Assume thatF :C×C → Rsatisfies (A1)–(A4). Forr > 0 andx ∈H, define a mappingTr :H → Cas follows:
Trx z∈C:F z, y
1 r
y−z, z−x
≥0, ∀y∈C
, 2.10
for allx∈H. Then, the following hold:
iTr is single valued;
iiTr is firmly nonexpansive; that is, for anyx, y∈HTrx−Try2≤ Trx−Try, x−y ; iiiFTr EPF;
ivEPFis closed and convex.
Lemma 2.12 see22. LetH be a Hilbert space andM a maximal monotone onH. Then, the following holds:
JM,rx−JM,sx2≤ r−s
r JM,rx−JM,sx, JM,rx−x , ∀s,r >0, x∈H, 2.11 whereJM,r IrM−1andJM,s IsM−1.
3. Main Results
In this section, we will use the viscosity approximation method to prove a strong convergence theorem for finding a common element of the set of fixed points of a countable family of nonexpansive mappings, the set of solutions of the variational inequality problem for relaxed cocoercive and Lipschitz continuous mappings, the set of solutions of system of variational inclusions, and the set of solutions of equilibrium problem in a real Hilbert space.
Theorem 3.1. LetCbe a nonempty closed convex subset of a real Hilbert spaceH, and letB:C → Hbe relaxedφ, ω-cocoercive andμ-Lipschitz continuous withω > φμ2, for someφ, ω, μ >0. Let G{Gk:k1,2,3, . . . , N}be a finite family ofβ-inverse strongly monotone mappings fromCinto H, and letFbe a bifunction fromC×C → Rsatisfying (A1)–(A4). Letf :C → Cbe a contraction with coefficientψ 0 ≤ψ <1, and let{Sn}be a sequence of nonexpansive mappings ofCinto itself such that
Ω: ∞ n1
FSn∩ N
k1
IGk, Mk
∩VIC, B∩EPF/∅. 3.1
Let the sequences{xn}and{yn}be generated by x1x∈Cchosen arbitrarily,
ynJMN,λN,nI−λN,nGn. . . JM2,λ2,nI−λ2,nG2JM1,λ1,nI−λ1,nG1Trnxn, xn1αnfxn βnxnγnSnPC
yn−ξnByn
, ∀n≥1,
3.2
where{αn},{βn},{γn} ⊂0,1and{ξn},{rn} ⊂0,∞satisfy the following conditions:
C1αnβnγn1, C2limn→ ∞αn0, ∞
n1αn∞,
C30<lim infn→ ∞βn≤lim supn→ ∞βn<1,
C4{ξn} ⊂a, bfor somea,bwith 0≤a≤b≤2ω−φμ2/μ2and limn→ ∞|ξn1−ξn|0, C5{λk,n}Nk1⊂c, d⊂0,2βand limn→ ∞|λk,n1−λk,n|0, for eachk∈ {1,2, . . . , N}, C6lim infn→ ∞rn>0 and limn→ ∞|rn1−rn|0.
Suppose that∞
n1sup{Sn1z−Snz : z ∈ K} < ∞for any bounded subset K ofC. LetS be a mapping ofCinto itself defined by Sy limn→ ∞Snyfor ally ∈ C and suppose thatFS ∞
n1FSn. Then, the sequences{xn}and{yn}converge strongly to the same pointx∗ ∈Ω, where x∗PΩfx∗.
Proof. First, we prove that the mappingPΩf :H → Chas a unique fixed point.
In fact, sincef :C → Cis a contraction withψ ∈0,1andPΩf : H → Ωis also a contraction, we obtain
PΩfx−PΩf
y≤fx−f
y≤ψx−y, ∀x, y∈C. 3.3 Therefore, there exists a unique elementx∗∈Csuch thatx∗PΩfx∗, where
Ω: ∞ n1
FSn∩ N
k1
IGk, Mk
∩VIC, B∩EPF. 3.4
Now, we prove thatI−ξnBis nonexpansive.
Indeed, for anyx, y ∈ C, sinceB : C → H is aμ-Lipschitz continuous and relaxed φ, ω-cocoercive mappings withω > φμ2andξn≤2ω−φμ2/μ2, we obtain
I−ξnBx−I−ξnBy2x−y
−ξn
Bx−By2 x−y2−2ξn
x−y, Bx−By
ξn2Bx−By2
≤x−y2−2ξn
−φBx−By2ωx−y2
ξ2nBx−By2
≤x−y22ξnφμ2x−y2−2ξnωx−y2ξ2nμ2x−y2
12ξnφμ2−2ξnωξ2nμ2x−y2
1−ξnμ2
2
ω−φμ2 μ2 −ξn
x−y2
≤
1−ξnμ2 2
ω−φμ2 μ2 −b
x−y2.
3.5 Setting
ζ μ2 2
2
ω−φμ2 μ2 −b
>0, 3.6
thus,
I−ξnBx−I−ξnBy2≤1−2ξnζx−y2≤1−ξnζ2x−y2, 3.7
which implies that
I−ξnBx−I−ξnBy≤1−ξnζx−y≤x−y. 3.8
HenceI−ξnBis nonexpansive.
We divide the proof ofTheorem 3.1into five steps.
Step 1. We show that the sequence{xn}is bounded.
Now, letx∈Ωand if{Trn}is a sequence of mappings defined as inLemma 2.11, then
xPC x−λn Bx Trnx, and let un Trnxn. So, we have
un−x Trnxn−Trnx ≤ x n−x. 3.9
Fork∈ {1,2, . . . , N}and for any positive integer numbern, we define the operatorΥkn:C → Has follows:
Υ0nxx,
ΥknxJMk,λk,nI−λk,nGk. . . JM2,λ2,nI−λ2,nG2JM1,λ1,nI−λ1,nG1x , 3.10
for all n, we getyn ΥNnun. On the other hand, since Gk : C → H isβ-inverse strongly monotone andλk,n ⊂ c, d ⊂ 0,2β, then JMk,λk,nI −λk,nGkis nonexpansive. Thus Υkn is nonexpansive. FromLemma 2.41, we havex ΥNnx. It follows that
yn−xΥnNun−ΥNnx≤ un−x ≤ x n−x. 3.11
SettingvnPCyn−ξnBynandI−ξnBis a nonexpansive mapping, we obtain
vn−x PC
yn−ξnByn
−PCx−ξnBx
≤yn−ξnByn
−x−ξnBx I−ξnByn−I−ξnBx
≤yn−x≤ xn−x.
3.12
From3.2and3.12, we deduce that
xn1−x αnfxn βnxnγnSnvn−x
≤αnfxn−xβnxn−x γnvn−x
≤αnfxn−fx αnfx−xβnxn−x γnxn−x
≤αnψxn−x αnfx −x 1−αnxn−x
≤ 1−αn
1−ψ
xn−x αnfx −x
1−αn 1−ψ
xn−x αn
1−ψfx −x 1−ψ
≤max
xn−x, fx−x 1−ψ
.
3.13
It follows from induction that
xn−x ≤ max
x1−x, fx −x 1−ψ
, ∀n≥1. 3.14
Therefore,{xn}is bounded and hence so are{vn},{yn},{un},{Byn}, and{Snvn}.
Step 2. We claim that limn→ ∞xn1−xn0.
By the definition ofTr,unTrnxnandun1Trn1xn1, we get
F un, y
1 rn
y−un, un−xn
≥0, ∀y∈H, 3.15
F un1, y
1 rn1
y−un1, un1−xn1
≥0, ∀y∈H. 3.16
Takingyun1in3.15andyunin3.16, we have
Fun, un1 1
rnun1−un, un−xn ≥0, 3.17 and hence
Fun1, un 1
rn1un−un1, un1−xn1 ≥0. 3.18 So, fromA2we have
un1−un,un−xn
rn −un1−xn1 rn1
≥0, 3.19
and hence
un1−un, un−un1un1−xn− rn
rn1un1−xn1
≥0. 3.20
Without loss of generality, let us assume that there exists a real numbercsuch thatrn> c >0 for alln∈N. Then, we have
un1−un2≤
un1−un, xn1−xn
1− rn
rn1
un1−xn1
≤ un1−un xn1−xn 1− rn
rn1
un1−xn1
,
3.21
and hence
un1−un ≤ xn1−xn 1
rn1|rn1−rn|un1−xn1
≤ xn1−xnM1
c |rn1−rn|,
3.22
whereM1sup{un−xn:n∈N}.
Notice fromLemma 2.12that yn1−ynΥNn1un1−ΥNnun
≤
un1−λk,n1GkΥkn1un1
−
un−λk,nGkΥknun JMk, λk,n1
un−λk,nGkΥknun
−JMk, λk,n
un−λk,nGkΥknun
≤ un1−un|λk,n1−λk,n|GkΥknun |λk,n1−λk,n|
λk,n1
JMk, λk,n1
un−λk,nGkΥnkun
−
un−λk,nGkΥknun
≤ un1−un2M2|λk,n1−λk,n|
≤ xn1−xnM1
c |rn1−rn|2M2|λk,n1−λk,n|,
3.23
whereM2is an appropriate constant such that
M2max
sup
n≥1
GkΥnkun , sup
n≥1
JMk, λk,n1
un−λk,nGkΥknun
−
un−λk,nGkΥnkun JMk, λk,n1
. 3.24
SinceI−ξnBis nonexpansive mappings, we have the following estimates:
vn1−vn ≤PC
yn1−ξn1Byn1
−PC
yn−ξnByn
≤yn1−ξn1Byn1
−
yn−ξnByn yn1−ξn1Byn1
−
yn−ξn1Byn
ξn−ξn1Byn
≤yn1−ξn1Byn1
−
yn−ξn1Byn|ξn−ξn1|Byn I−ξn1Byn1−I−ξn1Byn|ξn−ξn1|Byn
≤yn1−yn|ξn−ξn1|Byn.
3.25
Substituting3.23into3.25, we obtain vn1−vn ≤ xn1−xnM1
c |rn1−rn|2M2|λk,n1−λk,n| |ξn−ξn1|Byn.
3.26
Indeed, definexn1 1−βnznβnxnfor alln∈N. It follows that zn xn1−βnxn
1−βn αnfxn γnSnvn
1−βn . 3.27
Thus, we have
zn1−zn
αn1fxn1 γn1Sn1vn1
1−βn1 −αnfxn γnSnvn
1−βn
αn1 1−βn1
fxn1−fxn
γn1
1−βn1Sn1vn1−Snvn
αn1
1−βn1 − αn 1−βn
fxn
γn1
1−βn1 − γn 1−βn
Snvn
≤ αn1
1−βn1fxn1−fxn γn1
1−βn1Sn1vn1−Snvn
αn1
1−βn1 − αn
1−βn
fxn−Snvn
≤ ψαn1
1−βn1xn1−xn γn1
1−βn1Sn1vn1−Snvn
αn1
1−βn1 − αn 1−βn
fxn−Snvn.
3.28
Now, compute
Sn1vn1−Snvn ≤ Sn1vn1−Sn1vnSn1vn−Snvn
≤ vn1−vnSn1vn−Snvn
≤ xn1−xn M1
c |rn1−rn||ξn−ξn1|Byn 2M2|λk,n1−λk,n|Sn1vn−Snvn.
3.29
Combining3.28and3.29, we have
zn1−zn ≤ ψαn1
1−βn1xn1−xn γn1
1−βn1 xn1−xnM1
c |rn1−rn||ξn−ξn1|Byn 2M2|λk,n1−λk,n|Sn1vn−Snvn
αn1
1−βn1 − αn 1−βn
fxn−Snvn
≤ xn1−xn γn1 1−βn1
M1
c |rn1−rn||ξn−ξn1|Byn 2M2|λk,n1−λk,n|
γn1
1−βn1Sn1vn−Snvn
αn1
1−βn1 − αn
1−βn
fxn−Snvn.
3.30
It follows that
zn1−zn − xn1−xn
≤ γn1 1−βn1
M1
c |rn1−rn||ξn−ξn1|Byn2M2|λk,n1−λk,n| γn1
1−βn1Sn1vn−Snvn αn1
1−βn1 − αn
1−βn
fxn−Snvn
≤ γn1 1−βn1
M1
c |rn1−rn||ξn−ξn1|Byn2M2|λk,n1−λk,n| γn1
1−βn1sup{Sn1z−Snz:z∈ {vn}}
αn1
1−βn1 − αn 1−βn
fxn−Snvn. 3.31
This together with conditions C1–C6and limn→ ∞sup{Sn1z−Snz : z ∈ {vn}} 0 implies that
lim sup
n→ ∞ zn1−zn − xn1−xn≤0. 3.32
Hence, byLemma 2.6, we obtainzn−xn → 0 asn → ∞. It then follows that
nlim→ ∞xn1−xn lim
n→ ∞
1−βn
zn−xn0. 3.33
By3.26, we also have
nlim→ ∞vn1−vn0. 3.34
Step 3. We claim that limn→ ∞Svn−vn0.
Since{Gk:k1,2,3, . . . , N}isβ-inverse strongly monotone mappings, by the choice of{λk,n}for givenx∈Ωandk∈ {0,1,2, . . . , N−1}, we also have
Υk1n un−x2
JMk1,λk1,nI−λk1,nGk1Υknun−JMk1,λk1,nI−λk1,nGk1x2
≤I−λk1,nGk1Υknun−I−λk1,nGk1x2
Υknun−λk1,nGk1Υknun
−x−λk1,nGk1x 2
Υknun−x
−λk1,n
Gk1Υnkun−Gk1x2 Υknun−x2−2λk1,n
Υknun−x, G k1Υknun−Gk1x
λ2k1,nGk1Υknun−Gk1x2
≤Υknun−x2−2λk1,nβGk1Υknun−Gk1xλ2k1,nGk1Υnkun−Gk1x2
≤ un−x 2−2λk1,nβGk1Υknun−Gk1xλ2k1,nGk1Υknun−Gk1x2
≤ xn−x 2λk1,n
λk1,n−2βGk1Υknun−Gk1x2.
3.35
Form3.13, we have
xn1−x 2 ≤αnfxn−x2βnxn−x 2γnvn−x 2
≤αnfxn−x2βnxn−x 2γnyn−x2 αnfxn−x2βnxn−x 2γnΥNnun−x2
≤αnfxn−x2βnxn−x 2γnΥk1n un−x2
≤αnfxn−x2βnxn−x 2 γn xn−x 2λk1,n
λk1,n−2βGk1Υknun−Gk1x2
≤αnfxn−x2xn−x 2γnλk1,n
λk1,n−2βGk1Υknun−Gk1x2. 3.36
It follows that
γnλk1,n
2β−λk1,nGk1Υknun−Gk1x2
≤γnc
2β−dGk1Υknun−Gk1x2
≤ xn−xn1xn−x xn1−x αnfxn−x2.
3.37
By conditionC2,3.33, and lim infn→ ∞γn>0, we obtain
nlim→ ∞
Gk1Υknun−Gk1x0. 3.38
FromLemma 2.32and asI−λk1,nGk1is nonexpansive, we have Υk1n un−x2
JMk1,λk1,nI−λk1,nGk1Υknun−JMk1,λk1,nI−λk1,nGk1x2
≤
I−λk1,nGk1Υknun−I−λk1,nGk1x, Υk1n un−x 1
2 I−λk1,nGk1Υknun−I−λk1,nGk1x2Υk1n un−x2
−I−λk1,nGk1Υnkun−I−λk1,nGk1x−
Υk1n un−x2
≤ 1
2 Υknun−x2Υk1n un−x2−
Υknun−Υk1n un
−λk1,n
Gk1Υknun−Gk1x2
≤ 1
2 Υknun−x2Υk1n un−x2−Υknun−Υk1n un2
−λ2k1,nGk1Υknun−Gk1x22λk1,n
Υknun−Υk1n un, Gk1Υknun−Gk1x ,
3.39 which yields that
Υk1n un−x2
≤Υnkun−x2−Υknun−Υk1n un22λk1,nΥknun−Υk1n unGk1Υnkun−Gk1x
≤ un−x 2−Υknun−Υk1n un22λk1,nΥknun−Υk1n unGk1Υknun−Gk1x
≤ xn−x 2−Υknun−Υk1n un22λk1,nΥknun−Υk1n unGk1Υknun−Gk1x.
3.40
Substituting3.40into3.36, we obtain
xn1−x 2≤αnfxn−x2βnxn−x 2γnΥk1n un−x2
≤αnfxn−x2βnxn−x 2γn xn−x 2−Υknun−Υk1n un2
2λk1,nΥknun−Υk1n unGk1Υknun−Gk1x
≤αnfxn−x2xn−x 2−γnΥknun−Υk1n un2 2λk1,nγnΥknun−Υk1n unGk1Υknun−Gk1x.
3.41