Volume 2011, Article ID 859032,15pages doi:10.1155/2011/859032
Research Article
Strong Convergence Theorems for an Infinite Family of Equilibrium Problems and Fixed Point Problems for an Infinite Family of Asymptotically Strict Pseudocontractions
Shenghua Wang,
1Shin Min Kang,
2and Young Chel Kwun
31School of Applied Mathematics and Physics, North China Electric Power University, Baoding 071003, China
2Department of Mathematics and RINS, Gyeongsang National University, Jinju 660-701, Republic of Korea
3Department of Mathematics, Dong-A University, Pusan 614-714, Republic of Korea
Correspondence should be addressed to Young Chel Kwun,[email protected] Received 12 October 2010; Accepted 29 January 2011
Academic Editor: Jong Kim
Copyrightq2011 Shenghua Wang et al. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.
We prove a strong convergence theorem for an infinite family of asymptotically strict pseudo- contractions and an infinite family of equilibrium problems in a Hilbert space. Our proof is simple and different from those of others, and the main results extend and improve those of many others.
1. Introduction
LetCbe a closed convex subset of a Hilbert spaceH. LetS :C → Hbe a mapping and if there exists an elementx∈ Csuch thatx Sx, thenxis called a fixed point ofS. The set of fixed points ofSis denoted byFS. Recall that
1Sis called nonexpansive if
Sx−Sy≤x−y, ∀x, y∈C, 1.1 2S is called asymptotically nonexpansive1if there exists a sequence {kn} ⊂ 1,∞
withkn → 1 such that
Snx−Sny≤knx−y, ∀x, y∈C, n≥1, 1.2
3S is called to be a κ-strict pseudo-contraction 2if there exists a constant κwith 0≤κ <1 such that
Sx−Sy2≤x−y2κx−y
−
Sx−Sy2, ∀x, y∈C, 1.3
4Sis called an asymptoticallyκ-strict pseudo-contraction3,4if there exists a constant κwith 0≤κ <1 and a sequence{γn} ⊂0,∞with limn→ ∞γn0 such that
Snx−Sny2≤
1γnx−y2κx−y
−
Snx−Sny2, ∀x, y∈C, n≥1. 1.4 It is clear that every asymptotically nonexpansive mapping is an asymptotically 0- strict pseudo-contraction and everyκ-strict pseudo-contraction is an asymptoticallyκ-strict pseudo-contraction with γn 0 for all n ≥ 1. Moreover, every asymptotically κ-strict pseudo-contraction with sequence {γn} is uniformly L-Lispchitzian, where L sup{κ 1γn1−κ/1−κ : n ≥ 1}and the fixed point set of asymptoticallyκ-strict pseudo- contraction is closed and convex; see3, Proposition 2.6.
Let Φ be a bifunction from C×C to Ê, where Ê is the set of real numbers. The equilibrium problem for Φ : C×C → Ê is to find x ∈ C such thatΦx, y ≥ 0 for all y∈C. The set of such solutions is denoted by EPΦ.
In 2007, S. Takahashi and W. Takahashi 5first introduced an iterative scheme by the viscosity approximation method for finding a common element of the set of solutions of the equilibrium problem and the set of fixed points of a nonexpansive mapping in a Hilbert spaceHand proved a strong convergence theorem which is connected with Combettes and Hirstoaga’s result6 and Wittmann’s result 7. More precisely, they gave the following theorem.
Theorem 1.1see5. LetCbe a nonempty closed convex subset ofH. LetΦbe a bifunction from C×CtoÊsatisfying the following assumptions:
A1 Φx, x 0 for allx∈C;
A2 Φis monotone, that is,Φx, y Φy, x≤0 for allx, y∈C;
A3for allx, y, z∈C,
limt↓0 Φ
tz 1−tx, y
≤Φ x, y
; 1.5
A4for allx∈C,y→Φx, yis convex and lower semicontinuous.
LetS :C → Hbe a nonexpansive mapping such thatFS∩EPΦ/∅,f :H → Hbe a contraction and{xn},{un}be the sequences generated by
x1 ∈H, Φ
un, y 1
rny−un, un−xn ≥0, ∀y∈C, xn1αnfxn 1−αnSun, ∀n≥1,
1.6
where{αn} ⊂0,1and{rn} ⊂0,∞satisfy the following conditions:
nlim→ ∞αn0, ∞
n1
αn ∞, ∞
n1
|αn1−αn|<∞,
lim inf
n→ ∞ rn>0, ∞
n1
|rn1−rn|<∞.
1.7
Then, the sequences {xn} and {un} converge strongly to z ∈ FS ∩ EPΦ, where z PFS∩EPΦfz.
In8, Tada and Takahashi proposed a hybrid algorithm to find a common element of the set of fixed points of a nonexpansive mapping and the set of solutions of an equilibrium problem and proved the following strong convergence theorem.
Theorem 1.2see8. LetCbe a nonempty closed convex subset of a Hilbert spaceH. LetΦbe a bifunction fromC×C → ÊsatisfyingA1–A4and letSbe a nonexpansive mapping ofCintoH such thatFS∩EPΦ/∅. Let{xn}and{un}be sequences generated byx1x∈Hand
un∈C such thatΦ un, y
1 rn
y−un, un−xn
≥0, ∀y∈C, wn 1−αnxnαnSun,
Cn{z∈H:wn−z ≤ xn−z}, Dn{z∈H:xn−z, x−xn ≥0},
xn1PCn∩Dnx, ∀n≥1,
1.8
where{αn} ⊂a,1for somea∈ 0,1and{rn} ⊂ 0,∞satisfies lim infn→ ∞rn > 0. Then{xn} converges strongly toPFS∩EPΦx.
Many methods have been proposed to solve the equilibrium problems and fixed point problems; see9–13.
Recently, Kim and Xu 3 proposed a hybrid algorithm for finding a fixed point of an asymptoticallyκ-strict pseudo-contraction and proved a strong convergence theorem in a Hilbert space.
Theorem 1.3see3. LetCbe a closed convex subset of a Hilbert spaceH. LetT :C → Cbe an asymptoticallyκ-strict pseudo-contraction for some 0 ≤ κ <1. Assume thatFTis nonempty and bounded. Let{xn}be the sequence generated by the following algorithm:
x0∈C chosen arbitrarily, ynαnxn 1−αnTnxn,
Cn z∈H:yn−z≤ xn−z2 κ−αn1−αnxn−Tnxn2θn , Dn{z∈H:xn−z, x0−xn ≥0},
xn1PCn∩Dnx0, ∀n≥1,
1.9
where
θn Δ2n1−αnγn−→0 n−→ ∞, Δnsup{xn−z:z∈FT}<∞. 1.10 Assume that the control sequence {αn} is chosen such that lim supn→ ∞αn < 1−κ. Then {xn} converges strongly toPFTx0.
In this paper, motivated by3,8, we propose a new algorithm for finding a common element of the set of fixed points of an infinite family of asymptotically strict pseudo- contractions and the set of solutions of an infinite family of equilibrium problems and prove a strong convergence theorem. Our proof is simple and different from those of others, and the main results extend and improve those Kim and Xu3, Tada and Takahashi8, and many others.
2. Preliminaries
LetHbe a Hilbert space, and letCbe a nonempty closed convex subset ofH. It is well known that, for allx, y∈Candt∈0,1,
tx 1−ty2tx2 1−ty2−t1−tx−y, 2.1 and hence
tx 1−ty2≤tx2 1−ty2, 2.2 which implies that
n i1
tixi
2
≤n
i1
tixi2 2.3
for all{xi} ⊂Hand{ti} ⊂0,1withn
i1ti 1.
For anyx∈H, there exists a unique nearest point inC, denoted byPCx, such that zPCx⇐⇒
x−z, z−y
≥0, ∀y∈C. 2.4
LetIdenote the identity operator ofH, and let{xn}be a sequence in a Hilbert space Handx ∈H. Throughout the rest of the paper,xn → xdenotes the strong convergence of {xn}tox.
We need the following lemmas for our main results in this paper.
Lemma 2.1see14. Let C be a nonempty closed convex subset of a Hilbert spaceH. LetΦbe a bifunction fromC×CtoÊsatisfyingA1–A4. Letr >0 andx∈H. Then there existsz∈Csuch that
Φ z, y
1 r
y−z, z−x
≥0, ∀y∈C. 2.5
Lemma 2.2see6. Let C be a nonempty closed convex subset of a Hilbert spaceH. Let Φbe a bifunction fromC×CtoÊ satisfying A1–A4. For anyr > 0 and x ∈ H, define a mapping Tr :H → Cas follows:
Trx
z∈C:Φ z, y
1 r
y−z, z−x
≥0, ∀y∈C
, ∀x∈H. 2.6
Then the following hold:
1Tr is single-valued,
2Tr is firmly nonexpansive, that is, for anyx, y∈H, Trx−Try2≤
Trx−Try, x−y
, 2.7
3FTr EPΦ, and 4EPΦis closed and convex.
3. Main Results
Now, we are ready to give our main results.
Lemma 3.1. LetCbe a nonempty closed convex subset of a Hilbert spaceH. LetT :C → Cbe an asymptoticallyκ-strict pseudo-contraction with sequence{γn} ⊂0,∞such thatFT/∅. Assume that{βn} ⊂κ,1and define a mappingSn βnI 1−βnTnfor eachn≥ 1. Then the following hold:
Snx−Sny2≤
1γnx−y2, ∀x, y∈C,
Snx−x2 ≤γnx−x∗22x−Snx, x−x∗, ∀x∈C, x∗ ∈FT. 3.1
Proof. For allx, y∈C, we have Snx−Sny2βn
x−y
1−βn
Tnx−Tny 2 βnx−y2
1−βn
Tnx−Tny2−βn 1−βn
I−Tnx−I−Tny2
≤βnx−y2
1−βn 1γn
x−y2κI−Tnx−I−Tny2
−βn 1−βn
I−Tnx−I−Tny2 βnx−y2
1−βn 1γn
x−y2
1−βn κ−βn
I−Tnx−I−Tny2
≤βnx−y2
1−βn 1γn
x−y2
≤ 1γn
x−y2.
3.2 By this result, for allx∈Candx∗∈FT, we have
1γn
x−x∗2≥ Snx−Snx∗2Snx−xx−x∗2
Snx−x2x−x∗22Snx−x, x−x∗, 3.3 and hence
Snx−x2≤γnx−x∗22x−Snx, x−x∗. 3.4 This completes the proof.
Lemma 3.2. Let C be a nonempty closed subset of a Hilbert space H. Let T : C → C be an asymptotically κ-strict pseudo-contraction with sequence {γn} ⊂ 0,∞ satisfying γn → 0 as n → ∞. Let {zn} be a sequence in C such that zn −zn1 → 0 and zn −Tnzn → 0 as n → ∞. Thenzn−Tzn → 0 asn → ∞.
Proof. The proof method of this lemma is mainly from 15, Lemma 2.7. Since T is an asymptoticallyκ-strict pseudo-contraction, we obtain from3, Proposition 2.6that
Tn1zn−Tn1zn1≤Lzn−zn1, 3.5 whereLsup{κ
1γn1−κ/1−κ:n≥1}. Note thatzn−zn1 → 0, which implies thatTn1zn−Tn1zn1 → 0, and observe that
zn−Tzn ≤ zn−zn1zn1−Tn1zn1Tn1zn1−Tn1znTn1zn−Tzn
≤1Lzn−zn1zn1−Tn1zn1Tn1zn−Tzn. 3.6
SinceT is uniformly Lipschitzian,Tis uniformly continuous. So we have
Tn1zn−Tzn−→0 asn−→ ∞. 3.7
It follows fromzn−zn1 → 0 andzn−Tnzn → 0 asn → ∞that limn→ ∞zn−Tzn0.
This completes the proof.
LetHbe a Hilbert space, and, letCbe a nonempty closed and convex subset ofH. Let {Φn}be a countable family of bifunctions fromC×CtoÊsatisfyingA1–A4and let{rn} be a real number sequence inr,∞withr >0. Define
Trix
z∈C:Φi z, y
1 ri
y−z, z−x
≥0, ∀y∈C
, ∀x∈H. 3.8
Lemma 2.2 shows that every Tri i ≥ 1 is a firmly nonexpansive mapping and hence nonexpansive andFTri EPΦi.
Theorem 3.3. LetCbe a nonempty closed convex subset of a Hilbert spaceH. Let{Ti} :C → C be an infinite family of asymptoticallyκi-strict pseudocontractions with the sequence{γi,n} ⊂0,∞ satisfying γi,n → 0 as n → ∞for each i ≥ 1 andγ1,n ≥ γi,n for each i ≥ 1 andn ≥ 1. Let {Φn}be a countable family of bifunctions fromC×CtoÊsatisfyingA1–A4. Assume thatΩ ∞
i1FTi∩EPΦiis nonempty and bounded. Setα01 andθ01. Assume that{αi}is a strictly decreasing sequence in0, afor some 0< a <1,{θn}is a strictly decreasing sequence in0,1,{βi,n} is a sequence inκi, κwith 0< κi < κ <1 for eachi≥1, and{rn}is a sequence inr,∞withr >0.
The sequence{xn}is generated byx1x∈Cand
znθnxnn
i1
θi−1−θiTrixn,
wnαnxnn
i1
αi−1−αi
βi,nI
1−βi,n Tin
zn,
Cn{v∈C:wn−v ≤ xn−vλn}, Dnn
j1
Cj,
xn1 PDnx, ∀n≥1,
3.9
where{Tri}is defined by3.8and
λn 1−αnγ1,nΔn−→0 n−→ ∞, Δnsup{xn−v:v∈Ω}. 3.10
Then{xn}converges strongly toPΩx.
Proof. We show first that the sequence{xn}is well defined. Obviously,Cn is closed for all n≥1. Since
wn−v ≤ xn−vλn 3.11
is equivalent to
wn−xn22wn−xn, xn−z ≤λn, 3.12 Cnis convex for alln≥1. SoDnn
j1Cjis also closed and convex for alln≥1.
For eachn≥1 andi≥1, putSi,nβi,nI 1−βi,nTin. Letp∈Ω. Note thatθ01,{θn} is strictly decreasing and eachTriis firmly nonexpansive. Hence we have
zn−p≤θnxn−pn
i1
θi−1−θiTrixn−p
≤θnxn−pn
i1
θi−1−θixn−p
≤θnxn−p 1−θnxn−p xn−p, ∀n≥1.
3.13
Sinceα01 and{αn}is strictly decreasing, by3.13and Lemma3.1, we have wn−p≤αnxn−pn
i1
αi−1−αiSi,nzn−p
≤αnxn−pn
i1
αi−1−αi
1γi,nzn−p
≤αnxn−pn
i1
αi−1−αi
1γ1,nxn−p
≤xn−pλn.
3.14
So we havep ∈Cnand hencep∈Dn n
j1Cj for alln≥ 1. This shows thatΩ ⊂Dnfor all n≥1. This implies that the sequence{xn}is well defined.
SinceΩis a nonempty closed convex subset ofH, there exists a uniquez∗ ∈Ωsuch that
z∗PΩx. 3.15
Fromxn1PDnx, we have
xn1−x ≤ z−x, ∀z∈Dn. 3.16
Sincez∗∈Ω⊂Dn, we have
xn1−x ≤ z∗−x, ∀n≥1. 3.17
Therefore,{xn}is bounded. From3.13and3.14,{zn}and{wn}are also bounded.
Fromxn1PDnxandDn1⊂Dn, one sees thatxn2PDn1x∈Dn1⊂Dnfor alln≥1.
It follows that
xn1−x ≤ xn2−x, ∀n≥1. 3.18
Since{xn}is bounded, the sequence{x−xn}is bounded and nondecreasing. So there exists c∈Êsuch that
c lim
n→ ∞x−xn. 3.19
Sincexn1 PDnx∈Dn,xn2PDn1x∈Dn1⊂Dnandxn1xn2/2∈Dn, we have x−xn12≤x− xn1xn2
2 2
1
2x−xn1 1
2x−xn2 2 1
2x−xn121
2x−xn22− 1
4xn1−xn22.
3.20
So we get
1
4xn1−xn22≤ 1
2x−xn22−1
2x−xn12. 3.21
Since limn→ ∞x−xn1limn→ ∞x−xn2c, we obtain
nlim→ ∞xn1−xn20, 3.22
that is,
nlim→ ∞xn−xn10. 3.23
Now, for eachl≥1, from3.23we get
xnl−xn ≤ xnl−xnl−1· · ·xn1−xn
−→0 asn−→ ∞. 3.24
This implies that there exists an elementx∈Csuch thatxn → xasn → ∞.
Next we show thatx∈∞
i1FTiandx∈∞
i1EPΦi. Fromxn1∈Cn, we have
xn−wn ≤ xn−xn1xn1−wn
≤2xn−xn1λn. 3.25
By3.10and3.23, we obtain
nlim→ ∞xn−wn0. 3.26
Forp∈Ω, we have, from Lemma2.2,
Trixn−p2Trixn−Trip2
≤
Trixn−Trip, xn−p
Trixn−p, xn−p 1
2
Trixn−p2xn−p2− xn−Trixn2 ,
3.27
and hence
Trixn−p2≤xn−p2− xn−Trixn2, ∀i≥1. 3.28
Therefore
zn−p2≤θnxn−p2n
i1
θi−1−θiTrixn−p2
≤θnxn−p2n
i1
θi−1−θixn−p2− xn−Trixn2 xn−p2−n
i1
θi−1−θixn−Trixn2.
3.29
By3.29and Lemma3.1, we have wn−p2≤αnxn−p2n
i1
αi−1−αiSi,nzn−p2
≤αnxn−p2n
i1
αi−1−αi
1γ1,n2zn−p2 αnxn−p2 1−αn
1γ1,n2zn−p2
≤αnxn−p2 1−αn
1γ1,n2
xn−p2−n
i1
θi−1−θixn−Trixn2
xn−p2 1−αn
2γ1,nγ1,n2 xn−p2
−1−αn
1γ1,n2n
i1
θi−1−θixn−Trixn2,
3.30
and hence
1−αn
1γ1,n2n i1
θi−1−θixn−Trixn2
≤xn−p2−wn−p2 1−αn
2γ1,nγ1,n2 xn−p2
≤ xn−wnxn−pwn−p 1−αn
2γ1,nγ1,n2 xn−p2.
3.31
This shows that
1−αn
1γ1,n2θi−1−θixn−Trixn2
≤ xn−wnxn−pwn−p 1−αn
2γ1,nγ1,n2 xn−p2, ∀i≥1.
3.32
Since{αn} ⊂0, awith 0< a <1,γ1,n → 0,{θn}is strictly decreasing andxn−wn → 0, we get
nlim→ ∞xn−Trixn0, ∀i≥1. 3.33
LetMn supi≥1{xn−Trixn}for eachn≥1. ThenMn → 0 asn → ∞. Hence, from3.33, one has
xn−zn ≤n
i1
θi−1−θiTrixn−xn
≤n
i1
θi−1−θiMn 1−θnMn
−→0.
3.34
From3.26and3.34, we obtain
zn−wn ≤ zn−xnxn−wn −→0. 3.35
Noting that
n i1
αi−1−αizn−Si,nzn αnxn 1−αnzn−wn
αnxn−wn 1−αnzn−wn,
3.36
we have
n i1
αi−1−αi
zn−Si,nzn, zn−p αn
xn−wn, zn−p
1−αn
zn−wn, zn−p .
3.37
By Lemma3.1, we have
zn−Si,nzn2≤γi,nzn−p22
zn−Si,nzn, zn−p
≤γ1,nzn−p22
zn−Si,nzn, zn−p
. 3.38
Therefore, combining this inequality with3.37, we get n
i1
αi−1−αizn−Si,nzn2
≤γ1,n1−αnzn−p22αn
xn−wn, zn−p 21−αn
zn−wn, zn−p ,
3.39
and hencenoting thatαi−1> αifor eachi≥1 zn−Si,nzn2≤ γ1,n1−αn
αi−1−αi zn−p2 2αn
αi−1−αi
xn−wn, zn−p
21−αn αi−1−αi
zn−wn, zn−p .
3.40
From3.26,3.35and limn→ ∞γ1,n0,we have
nlim→ ∞zn−Si,nzn0, ∀i≥1. 3.41
From the definition ofSi,nand3.41, we havenoting that{βi,n} ⊂κi, κ⊂0,1 zn−Tinzn≤ 1
1−βi,nzn−Si,nzn −→0, ∀i≥1. 3.42 We next show3.42implies that
nlim→ ∞zn−Tizn0, ∀i≥1. 3.43
As a matter of fact, from3.23and3.34we have
zn−zn1 ≤ zn−xnxn−xn1xn1−zn1
−→0. 3.44
Now,3.42,3.44, and Lemma3.2imply3.43.
Since eachTiis uniformly continuous andzn → xasn → ∞, one getx ∈FTifor eachi≥1 and hencex∈∞
i1FTi. Now we showx∈∞
i1EPΦi.
Since everyTriis nonexpansive, from3.33andxn → x, we have x∈FTriand hence
x∈∞
i1FTri. Lemma2.2shows thatx∈∞
i1EPΦi.
Finally, we prove thatxPΩx. Fromxn1 PDnx, one sees
xn1−z, x−xn1 ≥0, ∀z∈Dn. 3.45 SinceΩ⊂Dnfor alln≥1, one arrives at
xn1−z, x−xn1 ≥0, ∀z∈Ω. 3.46
Taking the limit for above inequality, we get
x−z, x−x ≥ 0, ∀z∈Ω. 3.47 HencexPΩx. This completes the proof.
As direct consequences of Theorem3.3, we can obtain the following corollaries.
Corollary 3.4. Let C be a nonempty closed convex subset of a Hilbert space H. Let {Φn} be a countable family of bifunctions from:C×CtoÊsatisfyingA1–A4. Assume thatΩ ∞
i1EPΦi is nonempty and bounded. Let{rn}be a sequence inr,∞withr >0. Setθ01. The sequence{xn} is generated byx1 x∈Cand
znθnxnn
i1
θi−1−θiTrixn,
Cn{v∈C:zn−v ≤ xn−v}, Dnn
j1
Cj,
xn1 PDnx, ∀n≥1,
3.48
where{Tri}is defined by3.8and{θn}is a strictly decreasing sequence in0,1. Then{xn}converges strongly toPΩx.
Proof. Putting Ti I for all i ≥ 1 and αn 0 for all n ≥ 1 in Theorem 3.3, we obtain Corollary3.4.
Corollary 3.5. LetCbe a nonempty closed subset of a Hilbert spaceH. LetT be an asymptotically κ-strict pseudo-contraction with sequence{γn} ⊂0,∞satisfyingγn → 0 asn → ∞andFT/∅.
Let{xn}and{un}be sequences generated byx1x∈Hand znθnxn 1−θnPCxn, wnαnxn 1−αn
βnI 1−βn
Tn zn, Cn{v∈C:wn−v ≤ xn−v},
Dnn
j1
Cj,
xn1PDnx, ∀n≥1,
3.49
where{θn} ⊂0,1,{αn} ⊂ 0, awith 0 < a <1, and{βn} ⊂ κ, κwithκ < κ <1. Then{xn} converges strongly toPFTx.
Proof. Put Φix, y 0 for all x, y ∈ C and set rn 1 for all n ≥ 1 in Theorem 3.3.
By Lemma2.2, we have Trixn PCxn for each i ≥ 1. Hence, by Theorem3.3, we obtain Corollary3.5.
Remark 3.6. Our algorithms are of interest because the sequence{xn}in Theorem3.3is very different from the known manner. The proof is simple and different from those of others. The main results extend and improve those of Kim and Xu3, Tada and Takahashi8, and many others.
Remark 3.7. Putα01,θ01,κ3/4,r1,γi,n1/4in,κi 1/41/3i,αn 1/1n, θn1/41/8n,βi,n1/41/3i 1/8nfor alli≥1 and alln≥1,r01, andrn11/n.
Then these control sequences satisfy all the conditions of Theorem3.3.
Acknowledgments
The authors thank the referees for useful comments and suggestions. This study was supported by research funds from Dong-A University.
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