Volume 2011, Article ID 173430,15pages doi:10.1155/2011/173430
Research Article
An Application of Hybrid Steepest Descent Methods for Equilibrium Problems and Strict Pseudocontractions in Hilbert Spaces
Ming Tian
College of Science, Civil Aviation University of China, Tianjin 300300, China
Correspondence should be addressed to Ming Tian,[email protected] Received 9 December 2010; Accepted 13 February 2011
Academic Editor: Shusen Ding
Copyrightq2011 Ming Tian. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.
We use the hybrid steepest descent methods for finding a common element of the set of solutions of an equilibrium problem and the set of fixed points of a strict pseudocontraction mapping in the setting of real Hilbert spaces. We proved strong convergence theorems of the sequence generated by our proposed schemes.
1. Introduction
LetHbe a real Hilbert space andCa closed convex subset ofH, and letφbe a bifunction of C×CintoR, whereRis the set of real numbers. The equilibrium problem forφ:C×C → R is to findx∈Csuch that
EP :φ x, y
≥0 ∀y∈C 1.1
denoted the set of solution by EPφ. Given a mappingT :C → H, letφx, y Tx, y−x for allx, y ∈C, thenz ∈ EPφif and only ifTz, y−z ≥ 0 for all y ∈ C, that is, z is a solution of the variational inequality. Numerous problems in physics, optimizations, and economics reduce to find a solution of1.1. Some methods have been proposed to solve the equilibrium problem, see, for instance,1,2.
A mappingTofCinto itself is nonexpansive ifTx−Ty ≤ x−y, for allx, y∈C. The set of fixed points ofTis denoted byFT. In 2007, Plubtieng and Punpaeng3, S. Takahashi and W. Takahashi4, and Tada and W. Takahashi5considered iterative methods for finding an element of EPφ∩FT.
Recall that an operatorAis strongly positive if there exists a constantγ >0 with the property
Ax, x ≥γx2, ∀x∈H. 1.2
In 2006, Marino and Xu6introduced the general iterative method and proved that for a givenx0 ∈H, the sequence{xn}is generated by the algorithm
xn1αnγfxn I−αnATxn, n≥0, 1.3 whereTis a self-nonexpansive mapping onH,fis a contraction ofHinto itself withβ∈0,1 and {αn} ⊂ 0,1 satisfies certain conditions, andA is a strongly positive bounded linear operator onHand converges strongly to a fixed-pointx∗ofT which is the unique solution to the following variational inequality:
γf−Ax∗, x−x∗ ≤ 0, forx ∈FT, and is also the optimality condition for some minimization problem. A mappingS : C → H is said to bek-strictly pseudocontractive if there exists a constantk∈0,1such that
Sx−Sy2 ≤x−y2kI−Sx−I−Sy2, ∀x, y∈C. 1.4 Note that the class ofk-strict pseudo-contraction strictly includes the class of nonex- pansive mapping, that is,Sis nonexpansive if and only ifSis 0-srictly pseudocontractive; it is also said to be pseudocontractive ifk1. Clearly, the class ofk-strict pseudo-contractions falls into the one between classes of nonexpansive mappings and pseudo-contractions.
The set of fixed points ofS is denoted by FS. Very recently, by using the general approximation method, Qin et al.7obtained a strong convergence theorem for finding an element ofFS. On the other hand, Ceng et al.8proposed an iterative scheme for finding an element of EPφ∩FSand then obtained some weak and strong convergence theorems.
Based on the above work, Y. Liu9introduced two iteration schemes by the general iterative method for finding an element of EPφ∩FS.
In 2001, Yamada10introduced the following hybrid iterative method for solving the variational inequality:
xn1Txn−μλnFTxn, n≥0, 1.5 whereFisk-Lipschitzian andη-strongly monotone operator withk >0,η >0, 0< μ <2η/k2, then he proved that if {λn} satisfyies appropriate conditions, the {xn} generated by 1.5 converges strongly to the unique solution of variational inequality
Fx, x −x ≥ 0, ∀x∈FixT, x∈FixT. 1.6 Motivated and inspired by these facts, in this paper, we introduced two iteration methods by the hybrid iterative method for finding an element of EPφ∩FS, whereS : C → H is ak-strictly pseudocontractive non-self mapping, and then obtained two strong convergence theorems.
2. Preliminaries
Throughout this paper, we always assume thatCis a nonempty closed convex subset of a Hilbert spaceH. We writexn xto indicate that the sequence{xn}converges weakly to x.xn → ximplies that{xn}converges strongly tox. For anyx∈ H, there exists a unique nearest point inC, denoted byPCx, such that
x−PCx ≤x−y, ∀y∈C. 2.1 Such aPCxis called the metric projection ofHontoC. It is known thatPCis nonexpansive.
Furthermore, forx∈Handu∈C,upcx,⇔ x−u, u−y ≥0, for ally∈C.
It is widely known thatH satisfies Opial’s condition11, that is, for any sequence {xn}withxn x, the inequality
lim inf
n→ ∞ xn−x<lim inf
n→ ∞ xn−y, 2.2
holds for everyy∈Hwithy /x. In order to solve the equilibrium problem for a bifunction φ:C×C → R, let us assume thatφsatisfies the following conditions:
A1φx, x 0, for allx∈C,
A2φis monotone, that is,φx, y φy, x≤0, for allx, y∈C, A3For allx, y, z∈C.
limt↓0φ
tz 1−tx, y
≤φ x, y
; 2.3
A4For each fixedx∈C, the functiony→φx, yis convex and lower semicontinuous.
Let us recall the following lemmas which will be useful for our paper.
Lemma 2.1see12. Letφbe a bifunction fromC×CintoRsatisfying (A1), (A2),(A3) and (A4) then, for anyr >0 andx∈H, there existsz∈Csuch that
φ z, y
1
ry−z, z−x ≥0, ∀y∈C. 2.4 Further, ifTrx{z∈C:φz, y 1/ry−z, z−x ≥0,∀y∈C}, then the following hold:
1Tr is single-valued,
2Tr is firmly nonexpansive, that is, Trx−Try2 ≤
Trx−Try, x−y
, ∀x, y∈H; 2.5
3FTr EPφ,
4EPφis nonempty, closed and convex.
Lemma 2.2see13. IfS:C → His ak-strict pseudo-contraction, then the fixed-point setFS is closed convex, so that the projectionPFSis well difened.
Lemma 2.3see14. LetS : C → H be ak-strict pseudo-contraction. DefineT :C → Hby Tx λx 1−λSx for eachx ∈ C, then, asλ ∈ k,1, T is nonexpansive mapping such that FT FS.
Lemma 2.4see15. In a Hilbert spaceH, there holds the inequality xy2 ≤ x22
y, xy
, ∀x, y∈H. 2.6
Lemma 2.5see16. Assume that{an}is a sequence of nonnegative real numbers such that
an1≤ 1−γn
anγnδn, n≥0, 2.7
where{γn}is a sequence in (0,1) and{δn}is a sequence inÊ, such that i∞
n1γn∞,
iilim supn→ ∞δn≤0 or∞
n1|δnγn|<∞.
Then limn→ ∞an0.
3. Main Results
Throughout the rest of this paper, we always assume thatFis aL-lipschitzian continuous and η-strongly monotone operator withL, η >0 and assume that 0< μ <2η/L2.τ μη−μL2/2.
Let {Tλn} be mappings defined asLemma 2.1. Define a mappingSn : C → H bySnx βnx 1−βnSx, for allx∈C, whereβn∈k,1, then, byLemma 2.3,Snis nonexpansive. We consider the mappingGnonHdefined by
Gnx
I−αnμF
SnTλnx, x∈H, n∈N, 3.1
whereαn∈0,1. By Lemmas2.1and 2.3, we have
Gnx−Gny≤1−αnτTλnx−Tλny
≤1−αnτx−y. 3.2 It is easy to see thatGnis a contraction. Therefore, by the Banach contraction principle, Gnhas a unique fixed-pointxFn ∈Hsuch that
xFn
I−αnμF
SnTλnxFn. 3.3
For simplicity, we will writexnforxFn provided no confusion occurs. Next, we prove that the sequence{xn}converges strongly to aq∈FS∩EPφwhich solves the variational inequality
Fq, p−q
≥0, ∀p∈FS∩EP φ
. 3.4
Equivalently,qPFS∩EPφI−μFq.
Theorem 3.1. Let C be a nonempty closed convex subset of a real Hilbert space H and φ a bifunction from C×C into R satisfying (A1), (A2), (A3), and (A4). Let S : C → H be a k- strictly pseudocontractive nonself mapping such thatFS∩EPφ/φ. LetF : H → H be an L-Lipschitzian continuous andη-strongly monotone operator onHwithL, η >0 and 0< μ <2η/L2, τ μη−μL2/2. Let{xn}be asequence generated by
φ un, y
1
λny−un, un−xn ≥0, ∀y∈C, ynβnun
1−βn Sun, xn
I−αnμF
yn, ∀n∈N,
3.5
whereun Tλnxn,yn Snun, and{λn} ⊂ 0,∞satisfy lim infn→ ∞λn > 0 if{αn} and{βn} satisfy the following conditions:
i{αn} ⊂0,1, limn→ ∞αn0,
ii0≤k≤βn≤λ <1 and limn→ ∞βnλ,
then{xn} converges strongly to a pointq ∈ FS∩EPφwhich solves the variational inequality 3.4.
Proof. First, takep ∈FS∩EPφ. Sinceun Tλnxnandp Tλnp, fromLemma 2.1, for any n∈N, we have
un−pTλnxn−Tλnp≤xn−p. 3.6
Then, sinceSnpp, we obtain that
yn−pSnun−Snp≤un−p≤xn−p. 3.7
Further, we have
xn−p−αnμFp
I−μαnF yn−
I−μαnF p
≤αn−μF
p 1−αnτyn−p. 3.8 It follows thatxn−p ≤ μFp/τ.
Hence,{xn}is bounded, and we also obtain that{un}and{yn}are bounded. Notice that
un−yn≤ un−xnxn−yn
un−xnαn−μFyn. 3.9 ByLemma 2.1, we have
un−p2Tλnxn−Tλnp2≤
xn−p, un−p 1
2 xn−p2un−p2− un−xn2
. 3.10
It follows that
un−p2 ≤xn−p2− xn−un2. 3.11 Thus, fromLemma 2.4,3.7, and3.11, we obtain that
xn−p2αn
−μFp
I−μαnF yn−
I−μαnF p2
≤1−αnτ2yn−p22αn
−μFp, xn−p
≤1−αnτ2un−p22αn
−μFp, xn−p
≤1−αnτ2 xn−p2− xn−un2
2αn−μFpxn−p 1−2αnτ αnτ2xn−p2
−1−αnτ2xn−un22αn −μFpxn−p
≤xn−p2 αnτ2xn−p2−1−αnτ2xn−un22αn−μFpxn−p. 3.12
It follows that
1−αnτ2xn−un2 ≤αnτ2xn−p22αnμFpxn−p. 3.13 Sinceαn → 0, therefore
nlim→ ∞xn−un0. 3.14
From3.9, we derive that
nlim→ ∞un−yn0. 3.15
DefineT :C → HbyTx λx 1−λSx, thenT is nonexpansive withFT FS byLemma 2.3. We note that
Tun−un ≤Tun−ynyn−un≤λ−βnun−Sunyn−un. 3.16
So by3.15andβn → λ, we obtain that
nlim→ ∞Tun−un0. 3.17
Since{un}is bounded, so there exists a subsequence{uni}which converges weakly to q. Next, we show thatq∈FS∩EPφ. SinceCis closed and convex,Cis weakly closed. So we haveq∈C. Let us show thatq∈FS. Assume thatq∈FT, Sinceuni qandq /Tq, it follows from the Opial’s condition that
lim inf
n→ ∞ uni−q<lim inf
n→ ∞ uni−Tq
≤lim inf
n→ ∞
uni−TuniTuni−Tq
≤lim inf
n→ ∞ uni−q.
3.18
This is a contradiction. So, we getq∈FTandq∈FS.
Next, we show thatq∈EPφ. SinceunTλnxn, for anyy∈C, we obtain φ
un, y 1
λn
y−un, un−xn
≥0. 3.19
FromA2, we have
1 λn
y−un, un−xn
≥φ y, un
. 3.20
Replacingnbyni, we have
y−uni,uni−xni
λni
≥φ y, uni
. 3.21
Sinceuni −xni/λni → 0 anduni q, it follows fromA4that 0 ≥ φy, q, for all y ∈ C. Letzt ty 1−tqfor all t ∈ 0,1andy ∈ C, then we havezt ∈ Cand hence φzt, q≤0. Thus, fromA1andA4, we have
0φzt, zt≤tφ zt, y
1−tφ zt, q
≤tφ zt, y
, 3.22
and hence 0 ≤ φzt, y. FromA3, we have 0 ≤ φq, yfor ally ∈ Cand henceq ∈EPφ.
Therefore,q∈FS∩EPφ. On the other hand, we note that xn−q−αnμFq
I−μαnF yn−
I−μαnF
q. 3.23
Hence, we obtain xn−q2
−αnμFq, xn−q
I−μαnF yn−
I−μαnF
q, xn−q
≤αn
−μFq, xn−q
1−αnτxn−q2. 3.24
It follows that
xn−q2≤ 1 τ
−μFq, xn−q
. 3.25
This implies that
xn−q2≤
−μFq, xn−q
τ . 3.26
In particular,
xni−q2≤
−μFq, xni −q
τ . 3.27
Sincexni q, it follows from3.27thatxni → qasi → ∞. Next, we show thatq solves the variational inequality3.4.
As a matter of fact, we have xn
I−αnμF yn
I−αnμF
SnTλnxn, 3.28
and we have
μFxn− 1 αn
I−SnTλnxn−μαnFxn−FSnTλnxn
. 3.29
Hence, forp∈FS∩EPφ, μF
xn, xn−p − 1
αn
I−SnTλnxn−μαnFxn−FSnTλnxn
, xn−p
− 1 αn
I−SnTλnxn−I−SnTλnp, xn−p μ
Fxn−FSnTλnxn, xn−p . 3.30
SinceI−SnTλn is monotonei.e.,x−y,I−SnTλnx−I−SnTλny ≥0, for allx, y∈H. This is due to the nonexpansivity ofSnTλn.
Now replacingnin3.30withniand lettingi → ∞, we obtain μF
q, q−p lim
i→ ∞
μFxni, xni−p
≤ lim
i→ ∞μ
Fxni −FSnTλnxni, xni−p
0. 3.31
That is,q∈FS∩EPφis a solution of3.4. To show that the sequence{xn}converges strongly toq, we assume thatxnk → x. Similiary to the proof above, we derive x ∈FS∩ EPφ. Moreover, it follows from the inequality3.31that
μF
q, q−x
≤0. 3.32
Interchangeqandxto obtain μF
x,x−q
≤0. 3.33
Adding up3.32and3.33yields μηq−x2≤
q−x, μF
q− μF
x
≤0. 3.34
Hence,qx, and therefore xn → qasn → ∞, I−μF
q−q, q−p
≥0,∀p∈FS∩EP φ
. 3.35
This is equivalent to the fixed-point equation PFS∩EPφ
I−μF
qq. 3.36
Theorem 3.2. LetCbe a nonempty closed convex subset of a real Hilbert spaceHandφa bifunction from C × C into R satisfying (A1), (A2), (A3) and (A4). Let S : C → H be a k-strictly pseudocontractive nonself mapping such thatFS∩EPφ/φ. LetF:H → Hbe anL-Lipschitzian continuous andη-strongly monotone operator onH withL, η > 0. Suppose that 0 < μ < 2η/L2, τ μη−μL2/2. Let{xn}and{un}be sequences generated byx1∈Hand
φ un, y
1 λn
y−un, un−xn
≥0, ∀y∈C, ynβnun
1−βn Sun, xn1
I−αnμF
yn, ∀n∈N,
3.37
whereunTλnxn,ynSnunif{αn},{βn}, and{λn}satisfy the following conditions:
i{αn} ⊂0,1, limn→ ∞αn0,∞
n1αn∞,∞
n1|αn1−αn|<∞, ii0≤k≤βn≤λ <1 and limn→ ∞βnλ,∞
n1|βn1−βn|<∞, iii{λn} ∈0,∞, limn→ ∞λn>0 and∞
n1|λn1−λn|<∞,
then{xn}and{un}converge strongly to a pointq∈FS∩EPφwhich solves the variational inequality3.4.
Proof. We first show that{xn}is bounded. Indeed, pick anyp∈FS∩EPφto derive that xn1−p−αnμFp
I−μαnF yn−
I−μαnF p
≤αn−μF
p 1−αnτxn−p
≤1−αnτxn−pαn−μF p.
3.38
By induction, we have
xn−p ≤max
x1−p,1
τ −μF p
, ∀n∈N, 3.39
and hence {xn} is bounded. From3.6 and 3.7, we also derive that {un} and {yn} are bounded. Next, we show thatxn1−xn → 0. We have
xn1−xnI−αnμF yn−
I−αn−1μF yn−1 I−αnμF
yn−
I−αnμF
yn−1
I−αnμF
yn−1−
I−αn−1μF yn−1
≤1−αnτyn−yn−1|αn−αn−1|μFyn−1
≤1−αnτyn−yn−1K|αn−αn−1|,
3.40
where
KsupμFyn:n∈N
<∞. 3.41
On the other hand, we have
yn−yn−1Snun−Sn−1un−1
≤ Snun−Snun−1Snun−1−Sn−1un−1
≤ un−un−1Snun−1−Sn−1un−1.
3.42
Fromun1Tλn1xn1andun Tλnxn, we note that φ
un1, y 1
λn1
y−un1, un1−xn1
≥0, ∀y∈C, 3.43 φ
un, y 1
λn
y−un, un−xn
≥0, ∀y∈C. 3.44
Puttingyunin3.43andyun1in3.44, we have φun1, un 1
λn1un−un1, un1−xn1 ≥0, φun, un1 1
λnun1−un, un−xn ≥0. 3.45 So, fromA2, we have
un1−un,un−xn
λn −un1−xn1
λn1
≥0 , 3.46
and hence
un1−un, un−un1un1−xn− λn
λn1un1−xn1
≥0. 3.47
Since limn→ ∞λn > 0, without loss of generality, let us assume that there exists a real number a such thatλn> a >0 for alln∈N. Thus, we have
un1−un2≤
un1−un, xn1−xn
1− λn λn1
un1−xn1
≤ un1−un
xn1−xn 1− λn
λn1
un1−xn1
un1−un ≤ xn1−xn 1
a|λn1−λn|M0,
3.48
whereM0sup{un−xn:n∈N}. Next, we estimateSnun−1−Sn−1un−1. Notice that Snun−1−Sn−1un−1βnun−1
1−βn Sun−1
−
βn−1un−1
1−βn−1
Sun−1
≤βn−βn−1un−1−Sun−1. 3.49 From3.48,3.49, and3.42, we obtain that
yn−yn−1≤ xn−xn−1M0
a |λn−λn−1|βn−βn−1un−1−Sun−1
≤ xn−xn−1|λn−λn−1|M1βn−βn−1M1,
3.50
whereM1is an appropriate constant such that M1≥ M0
a un−1−Sun−1, ∀n∈N. 3.51 From3.41and3.50, we obtain
xn1−xn ≤K|αn−αn−1| 1−αnτ
xn−xn−1|λn−λn−1|M1βn−βn−1M1
≤1−αnτxn−xn−1M
|αn−αn−1||λn−λn−1|βn−βn−1, 3.52
whereMmaxK, M1. Hence, few byLemma 2.5, we have
nlim→ ∞xn1−xn0. 3.53
From3.48and3.50,|λn−λn−1| → 0 and|βn−βn−1| → 0, we have
nlim→ ∞un1−un0, lim
n→ ∞yn1−yn0. 3.54
Since
xn1
I−αnμF
yn, 3.55
it follows that
xn−yn≤ xn−xn1xn1−yn
xn−xn1αn−μFyn. 3.56
Fromαn → 0 and3.53, we have
nlim→ ∞xn−yn0. 3.57
Forp∈FS∩EPφ, we have
un−p2Tλnxn−Tλnp2≤
xn−p, un−p 1
2 xn−p2un−p2− un−xn2
. 3.58
This implies that
un−p2≤xn−p2− un−xn2. 3.59
Then, from3.7and3.59, we derive that xn1−p2−μαnFp
I−μαnF yn−
I−μαnF p2
≤1−αnτ2yn−p2α2n−μFp22αn−μFpyn−p
≤un−p2α2n−μFp22αn−μFpyn−p
≤xn−p2− xn−un2α2n−μFp22αn−μFpyn−p.
3.60
Sinceαn → 0,xn−xn1 → 0, we have
nlim→ ∞xn−un0. 3.61
From3.57and3.61, we obtain that
un−yn ≤ un−xnxn−yn → 0, asn → ∞. 3.62
DefineT :C → HbyTx λx 1−λSx, thenT is nonexpansive withFT FS byLemma 2.3. Notice that
Tun−un ≤Tun−ynyn−un
≤λ−βnun−Sunyn−un. 3.63
By3.62andβn → λ, we obtain that
nlim→ ∞Tun−un0. 3.64
Next, we show that lim supn→ ∞μFq, q−xn ≤0, whereq PFS∩EPφI−μFqis a unique solution of the variational inequality3.4. Indeed, take a subsequence{xni}of{xn} such that
ilim→ ∞
μFq, q−xni
lim sup
n→ ∞
μFq, q−xn
. 3.65
Since{xni} is bounded, there exists a subsequence {xnij} of {uni} which converges weakly tow.
Without loss of generality, we can assume thatuni w. From3.61and3.64, we obtainxni wandTuni w. By the same argument as in the proof ofTheorem 3.1, we have w∈FS∩EPφ. SinceqPFS∩EPφI−μFq, it follows that
lim sup
n→ ∞
μFq, q−xn
μFq, q−w
≤0. 3.66
Fromxn1−q−αnμFq I−μαnFyn−I−μαnFq, we have xn1−q2 ≤I−μαnF
yn−
I−μαnF
q22αn
−μFq, xn1−q
≤1−αnτ2xn−q22αn
−μFq, xn1−q .
3.67
This implies that xn1−q2≤
1−2αnτ αnτ2xn−q22αn
−μFq, xn1−q 1−2αnτxn−q2 αnτ2xn−q22αn
−μFq, xn1−q
1−2αnτxn−q22αnτ αnτ2
2τ M∗1 τ
−μFq, xn1−q
1−γnxn−q2γnδn,
3.68
whereM∗sup{xn−q2:n∈N},γn2αnτ, andδn αnτ2/2τM∗1/τ−μFq, xn1−q.
It is easy to see thatγn → 0,∞
n1γn∞, and lim supn→ ∞δn ≤0 by3.66. Hence by Lemma 2.5, the sequence{xn}converges strongly toq.
Acknowledgments
M. Tian was supported in part by the Science Research Foundation of Civil Aviation University of Chinano. 2010kys02. He was also Supported in part by The Fundamental Research Funds for the Central UniversitiesGrant no. ZXH2009D021.
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