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A polynomial invariant of a homology 3-sphere defined by Reidemeister torsion

Teruaki Kitano

Soka Univ.

26th Jan., 2017

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Contents

Johnson theory

Reidemeister torsion Casson invariant

Polynomial defined by Reidemeister torsion Brieskorn homology sphere

1/n-surgery along the figure-eight knot SL(2;C)-Casson invariant

Witten’s topolgical field theory

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Reidemeister torsion

1930’s Reidemeister, Franz, de Rham: Classification of lens space

1961-2 Milnor:

Hauptvermutung for polyhedrons

Alexander polynomial=Reidemeister torsion 1980’s asymptotic behavior of quantum invariants 1990’s twisted Alexander polynomial=Reidemeister torsion

1996 Meng-Taubes: SW=Milnor torsion

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Casson invariant and Reidemeister torsion

1985 Casson, an integral lift of Rochlin invariant Late 1980’s D. Johnson, A geometric form of Casson’s invariant and its connection to Reidemeister torsion, unpublished lecture notes (hand written).

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A generalization of the determinant

Roughly speaking,

Reidemeister torsion= ”det”(an acyclic based chain complex).

acyclic: a linear isomorphism

based: a matrix is given under a basis

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determinant for a linear isomorphism

V: l-dimensional vector space over a field F(=C,R).

f :V →V: a linear isomorphism How to define det(f) ?

e1, . . . ,el: a basis of V

F ∈M(l;F): the matrix defined by f undere1, . . . ,el Fore1, . . . ,el, we take their image f(e1), . . . ,f(el).

det(f,(e1, . . . ,el)) = det(F)

= det (f(e1), . . . ,f(el)/e1, . . . ,el).

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Under fixing a basis ofV, e1, . . . ,el, we have an identification

lV =F.

f(e1)∧· · ·∧f(el) = det (f(e1), . . . ,f(el)/e1, . . . ,el)e1∧· · ·∧el

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determinant for a short exact sequence

0→V1 f1 V2 f2 V3 0: an exact sequence of finite dimensional vector spaces overF.

bi ⊂Vi: a basis of Vi for i = 1,2,3 f21(b3)⊂V2: a lift of b2

(f1(b1),f21(b3)): another basis of V2

τ = det(

f1(b1),f21(b3)/b2) Remark

τ does not depend on a choice of a lift f21(b3).

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Reidemeister torsion for a chain complex

F: a field

a chain complex of finite dimensional vector spaces overF C:

0−→m+1 Cm −→m Cm1 −→m−1. . .−→2 C1 −→1 C0 −→0 0 ci: a basis of Ci

Definition

A chain complexC isacyclic if

Im∂i+1 =Ker∂i (Zi(C) =Bi(C),Hi(C) ={0})

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Assumption: C is acyclic.

Fix bi for Bi(C) =Zi(C).

Exact sequence

0−→Zi(C)−→Ci −→i Bi1(C)−→0 ebi1: a lift of bi1 in Ci

(bi,ebi−1): another basis ofCi (

bi,ebi1/ci )

: the transformation matrix from ci to (bi,ebi1)

[bi,ebi−1/ci] = det (

bi,ebi−1/ci )

:

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Torsion of a based chain complex

Definition

The torsionτ(C) of a based chain complex C with c τ(C) = Πi:odd[bi,ebi1/ci]

Πi:even[bi,ebi1/ci] F\ {0}. Lemma

τ(C) does not depend on choices of lifts {bi}.

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Lemma

τ(C) does not depend on choices of {bi}. Proof.

Assumebq is another basis ofBq.

In the definition of τ(C), the difference between bq and bq is related to the followings only two parts:

[bq,bq1/cq]

= [bq,bq1/cq][

bq/bq] [bq+1,bq/cq+1] = [bq+1,bq/cq+1][

bq/bq] Since[

bq/bq]

appears in the both of the denominator and the numerator of the definition, they are cancelled.

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Reidemeister torsion for a CW-complexe

X:a finite(=compact) CW-complex X˜ →X:universal covering

π1(X) acts on ˜X (from the right), cellularly.

Ci( ˜X;Z):spanned by lifts of i-cells of X overZ.

C( ˜X;Z): a chain complex of right Z[π1(X)]-modules.

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local coefficients

ρ:π1(X)→GL(V): a finite dimensional linear representation over F

V:l-dimensional vector space over F (=C2,sl(2;C),su(2))

C(X;Vρ) =C( ˜X;Z)π1(X)Vρ Assume: C(X;Vφ) is acyclic.

Definition

τρ(X) = τ(C(X;Vρ))F\ {0}.

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well-definedness

Choices of lifts of cells Orders of cells. Choice of a basis for V Proposition

τρ(X)Fdet(ρ(π1(X))) does not depend on choices of lifts and orders of cells.

It depends on a choice of basis e1, . . . ,el. Then we fix e1 ∧ · · · ∧el l

V

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topological invariant

Under same assumption, we have the following.

Theorem (Kirby-Siebenmann, Chapman)

If X is a closed manifold, thenτρ(M)Fdet(ρ(π1(X))) is a topological invariant of M.

Remark

For any acyclic even-dimensional unimodular representation ρ:π1(X)→SL(2l;F),τρ(X)F\ {0} is well defined

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Remark

In the case of V =C2, we take e1 =

(1 0

) ,e2 =

(0 1

) .

In the case of V =su(2), under a fixed Killing form, we take an orthonormal basis.

If ρ is not acyclic, then we defineτρ(X) = 0.

Definition

We callρ an acyclic representation ifC(X;Vφ) is acyclic.

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Condition for acyclicity

If C(X;Vφ) is acyclic, then Euler number of H(X;Vφ) is 0 =∑

i

(1)idimHi(X;Vρ)

=∑

i

(1)idimCi(X;Vρ)

=∑

i

(1)idimCi(X;Z)·dimV

=lχ(X).

Hereχ(X) is Euler characteristic of X. Hence we have χ(X) = 0.

There does not exist an acyclic representation for X with χ(X)̸= 0.

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Johnson Theory

M : homology 3-sphere λ(M)∈Z : Casson invariant

R(X) =:π1X →SU(2);irreducible representation} Rˆ(X) =R(X)/SU(2)

M =A∪Σg B : Heegard decomposition Rˆ(M) = ˆR(A)∩Rˆ(B)⊂Rˆ(Σg)

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Assume:

Rˆ(M) is a finite set.

Any point of ˆR(M) isnon degenerate.

For anyρ∈ R(M), compose it with

Adj :SU(2)→Aut(su(2)), we have

Adj ◦ρ:π1(M)→Aut(su(2)).

dimRH1g;su(2)Adjρ) = 6g 6 dimRH1(A;su(2)Adjρ) = 3g 3 dimRH1(B;su(2)Adjρ) = 3g3 H1(M;su(2)Adjρ) = {0}

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volume forms

Johnson constructed volume forms volΣg onH1g;su(2)Adjρ), volA on H1(A;su(2)Adjρ), volB on H1(B;su(2)Adjρ).

By the assumption, he definedt[ρ]R\ {0} by

volΣg =t[ρ](volA ∧volB)

6g6

H1g;su(2)Adjρ).

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Geometric form of Casson invariant

Theorem (Johnson)

λ(M) =

[ρ]Rˆ(M)

sgn(t[ρ]) t[ρ] =τAdjρ(M)

Remark

Adj ◦ρ :π1M →SU(2) →Aut(su(2)) τAdjρ(M) =τ(C(M;su(2)Adjρ)) Ageometric form of Casson invariant:

[ρ]Rˆ(M)

t[ρ]

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A polynomial invariant defined by Reidemeister torsion

Johnson proposed to study

a polynomial whose zeros are {t[ρ]}:

[ρ]

(t −t[ρ]),

a polynomial for Reidemeister torsion τρ(M) for an SL(2;C)-representation.

In particular he studied ∏

[ρ]

(t −τρ) for 1/n-surgeried manifold along the trefoil knot.

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A polynomial defined by Reidemeister torsion

M : homology 3-sphere

τρ(M)C : Reidemeister torsion forM with an irreducibleSL(2;C)-representation ρ

τρ(M) = 1/τρ(M)

Assume : ˆRSL(2;C)(M) is afinite set.

By assumption, ρ(M) | τρ(M)̸= 0} is a finite set.

Definition

σM(t)C[t] is a polynomial whose roots are given by the set {

τρ(M) = τ 1

ρ(M) | τρ(M)̸= 0

} .

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Assumption : ˆRSL(2;C)(M) is an algebraic variety of dimension zero.

By using resultants, it is given as a set of algebraic numbers.

Any representation ρ in ˆRSL(2;C)(M) can be realized over an algebraic extension fieldF over Q.

τρ(M) and τρ(M) are also algebraic numbers inF. Any Galois conjugate ofρ (under the action of Gal(F/Q)) is a representation.

If the action of Gal(F/Q) gives all Galois conjugate of τρ by Gal(Q(ρ})/Q), then

σM(t)Q[t].

It is the minimal polynomial ofτρ Q(τρ).

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minimal polynomial

F Q is an extension ofQ. θ∈F

Definition

The minimal polynomial ofθ is the monic polynomial of least degree among all polynomials inQ[x] having θ as a root.

Remark

The minimal polynomial ofθ exists when θ is algebraic over Q, that is, f(θ) = 0 for some non-zero polynomial f(x)Q[x].

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Brieskorn homology 3-sphere

Σ(p,q,r) : Brieskorn homology 3-sphere {z1p+z2q+z3r = 0} ∩S5 C3 =R6 p,q,r Z : pairwise coprime positive integers We may assumeq and r are odd numbers.

Σ(p,q,r) can be given by Dehn surgery along (p,q)-torus knot

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Σ(p, q, | pqn + 1 | )

Now consider the case of r =|pqn+ 1|. Then

Σ(p,q,|pqn+ 1|) can be obtained by 1/n-surgery along T(p,q).

In this case any conjugacy class of irreducible representations can be represented by

ρ(a,b,k) :π1(Σ(p,q,|pqn+ 1|))→SL(2;C) with

1 0<a <p,0<b <q,a ≡b mod 2,

2 0<k <|pqn+ 1|,k ≡na mod 2,

3 tr(ρ(a,b,k)(x)) = 2 cosp ,

4 tr(ρ(a,b,k)(y)) = 2 cosq ,

5 tr(ρ(a,b,k)(µ)) = 2 cos|pqn+1 |.

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τ

ρ

(Σ(p , q , | pqn + 1 | ))

Johnson computed Reidemeister torsion τρ(a,b,k)(Σ(p,q,|pqn+ 1|)) as follows.

Theorem (Johnson)

1 A representation ρ(a,b,k) is acyclic if and only if a≡b 1,k ≡n mod 2.

2 For an acyclic representation ρ(a,b,k), τρ(a,b,k)(Σ(p,q,|pqn+ 1|))

= 1

2 (

1cos p ) (

1cosq ) (

1 + cos|pqn+1pqkπ| ).

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τ

ρ

(Σ(p , q , r ))

In general case, we have the following.

Proposition (Johnosn, Kitano-Tran)

τρ(a,b,c)(Σ(p,q,r)) = 1

2 (

1cosp ) (

1cosq ) (

1cosr )

= 1

16 sin2 (πa

2p

) sin2

(πb 2q

)

sin2(πc

2r

)

where(0,0,0)<(a,b,c)<(p,q,r), a≡b≡c 1mod 2.

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σ

(p,q,r)

(t )

From hereσΣ(p,q,r)(t) is simply written as σ(p,q,r)(t).

σ(p,q,r)(t) = C

(a,b,c)

(

t 16 sin2 (πa

2p )

sin2 (πb

2q )

sin2 (πc

2r ))

where the above product can be taken over the same condition (0,0,0)<(a,b,c)<(p,q,r), a ≡b ≡c 1 mod 2.

Now put

C(p,q,a,b)= 2 sin (πa

2p )

sin (πb

2q )

.

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Normalized Chebyshev polynomial of first kind

Normalized Chebyshev polynomial of the first kind:

Tn(2cosθ) =2cosnθ.

Recursive definition:

T0(x) = 2, T1(x) =x.

Tn+1(x) =xTn(x)−Tn1(x).

T0(x) = 2,T1(x) =x,T2(x) = x22,T3(x) = x33x.

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Normalized Chebyshev polynomial of second kind

Normalized Chebyshev polynomial of the second kind:

Sn(2cosθ) = sin((n+ 1)θ) sinθ . Recursive definition:

S0(x) = 1, S1(x) = x.

Sn+1(x) =xSn(x)−Sn−1(x).

S0(x) = 1,S1(x) =x,S2(x) =x21,S3(x) =x32x. A Relation:

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Polynomial of Σ(p , q , r )

Theorem (Kitano-Tran)

σ(p,q,r)(t) = ∏

(a,c)

Sq1

( t C(p,r,a,c)

)

= ∏

(a,b)

Sr1

( t C(p,q,a,b)

)

=











(b,c)

Sp1

( t C(q,r,b,c)

)

(p :odd)

(b,c)

S¯2p1

( t C(q,r,b,c)

)

(p :even) .

HereS¯2p1(x) =S2p1(x)/x .

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Examples

σ(2,3,5)(t) =4t2 6t + 1

σ(2,3,7)(t) =8t3 20t2+ 12t 1

σ(2,3,11)(t) =32t5144t4+ 224t3140t2+ 30t 1

σ(2,3,13)(t) =64t6352t5+ 720t4672t3+ 280t242t + 1 σ(2,3,17)(t) =256t81920t7+ 5824t69152t5+ 7920t4

3693t3+ 840t272t + 1

σ(2,3,19)(t) =512t94352t8+ 15360t729120t6+ 32032t5

20592t4 + 7392t31320t2+ 90t 1 They are irreducible over Q.

Remark

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Example (reducible example)

σ(2,5,9)(T) =256t8 2688t7+ 9856t615840t5 +12192t44608t3+ 820t260t + 1 This is not irreducible as

σ(2,5,9)(T)

=(4t26t+ 1)

×(64t6576t5+ 1584t41440t3+ 492t254t + 1)

(2,3,5)(T)

×(64t6576t5+ 1584t41440t3+ 492t254t + 1)

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SL(2; C )-Casson invariant

ForM = Σ(2,3,6n+ 1)(n>0),

♯RˆSL(2;C)(Σ(2,3,6n+ 1)) =λSL(2;C)(Σ(2,3,6n+ 1))

=3n (Boden−Curtis) On the other hand,

λSU(2)(Σ(2,3,6n+ 1)) =n.

λSL(2;C)(Σ(2,3,6n+ 1))SU(2)(Σ(2,3,6n+ 1)) =n What is the difference ?

♯RˆSL(2;R)(Σ(2,3,6n+ 1)) =n

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Proposition (K.-Yamaguchi)

λSL(2;C)(Σ(p,q,r)) = 2λSU(2)(Σ(p,q,r))+♯RˆSL(2;R)(Σ(p,q,r)) ρ:π1(Σ(p,q,r))→SL(2;C) induces

¯

ρ:π1orbS2(p,q,r)→PSL(2;C).

πorb1 S2(p,q,r) = x,y,z | xp =yq =zr =xyz = 1 Jenkins-Neumann:

Classification of PSL(2;R)-representations of triangle groups

AnySU(2)-representation that is conjugate to SL(2;R)-representation is an abelian representation.

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”SL(2; R )-Casson invariant”

Problem

Can we define an SL(2;R)-Casson invariant ?

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Dehn surgery along the figure-eight knot

K = 41

π1(S3\K) =⟨a,b|w1a =bw1wherew =ba1b1a.

Mn(K): 1/n-Dehn surgery along K

ρ:π1(Mn(K))→SL(2,C): irreducible representation.

µ=a∈π1(Mn(K)): meridian of K x =tr(ρ(µ))

(41)

Reidemeister torsion for M

n

(K )

Reidemeister torsion ofMn(K) for ρ is given as follows.

Theorem (K.)

τρ(Mn(K)) = 2(x1) x49x2+ 4 Here x =tr(ρ(µ)).

Remark

The explicit value x is determined by the surgery conditionRemark that any complex value x can not be realized.

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Letρ:π1(S3\K)→SL(2;C) be an irreducible representaion.

By taking a conjugation, we may assume ρ(a) =

[ s 1 0 s1

]

, ρ(b) =

[ s 0

−u s1 ]

.

Here (s,u)∈(C)2 is a solution of

ϕK(s,u) =u2(u+ 1)(s2+s23).

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Compute the image of longitude λ= (ab1a1b)1)(ba1b1a1)1,

ρ(λ) =

[ λ11 λ12 λ21 λ22

]

where

λ11= (−s21)u3+ (s2−s2)u+ (s4+s2−s21)u2+ 1, λ12=u(s +s1)(s2+s21−u),

λ21=−u2(s+s1K(s,u),

λ22= (−s21)u3+ (s4−s2+s21)u2+ (s2−s2)u+ 1.

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The conditionϕK(s,u) = 0 implies

trρ(λ) =s4+s4−s2−s22

=x45x2+ 2 wherex =s+s1.

Here this representation π1(S3\K)→SL(2;C) can be extend as ρ:π1(Mn(K))→SL(2;C) if and only if

ρ(λn) = ρ(µ1).

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By using L=trρ(λ) =x45x2+ 2, ρ(λn) =

[ λn11 λ12Sn1(L) 0 λn22

] .

Further the condition ρ(λn) = ρ(µ1) is equivalent to the following three conditions of

1 λn11=s1,

2 λn22=s,

3 λ12Sn1(L) = 1.

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By direct computation, we have

1 u2 (u+ 1)(s2+s23) = 0,

2 λn11=s1,

3 =2 (i.e. x2 ̸= 4).

Lemma

The set of s satisfying the following

1 u2 (u+ 1)(s2+s23) = 0,

2 λn11=s1

is coincided wth the set of solutions for

s +s1 =Tn(s4+s4−s2−s22).

(47)

By the formula of Reideimeister torsion τρ = 2x 2

x2(x25), we consider the resultant

Pn(t) = Resx

(Tn(x45x2+ 2)−x,tx2(x25)(2x 2)) .

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A resultant

f(x) =anxn+an1xn1 +· · ·+a1x +a0

g(x) =bmxm+bm1xm1+· · ·+b1x +b0 Definition (the resultant off(x),g(x))

Res(f(x),g(x)) =

an an1 · · · · · · a0

an an1 · · · a1 a0

an · · ·

...

an · · · a1 a0

bm bm1 · · · · · · b0

bm bm1 · · · b1 b0

bm · · ·

...

bm · · · b1 b0

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f(x,y),g(x,y):polynomials of 2-variable x,y By considering x is a variable andy is a constant, we can define the resultant Resx(f,g).

Proposition

There exist polynomials F(x,y),G(x,y)such that f(x,y)G(x,y) +g(x,y)F(x,y) = Resx(f,g).

Therefore a solution (x,y) off(x,y) =g(x,y) = 0 satisfies Res(f,g) = 0.

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Polynomial for surgeried manifold along 4

1

Mn(K) is a homology 3-sphere obtained by 1/n-surgery along K = 41.

Theorem (Kitano-Tran) σMn(K)(t) =

{

Pn(t)/(2t3) n is odd, Pn(t)/(2t+ 1) n is even.

Here

Pn(t) =Resx(

Tn(x45x2+ 2)−x,tx2(x25)(2x 2))

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Examples

σ1(t) =t312t2+ 20t 8

σ2(t) =t756t6+ 660t53384t4+ 8720t311008t2 + 5376t 128

σ3(t) =t11124t10+ 3036t931696t8+ 161024t7

364128t6 + 152640t5+ 426752t4262144t3

142336t2 + 55296t 2048

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σ4(t) =t15224t14+ 10320t13211776t12+ 2296400t11

13570900t10+ 41172200t949672100t835529500t7 +156351000t6113653000t558957800t4+ 115933000t3

50004000t2 + 5898240t32768

(53)

Open Problems

Problem

How strong is this polynomial σM(t) ?

How about for Brieskorn homology sphere ?

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σ

M

(t ) is a minimal polynomial?

Problem

How is it related with minimal poly ofτρ overQ?

Problem

If there exists an epimorphismφ:π1(M)→π1(M), then σM(t)can be divided by σM(t)?

Problem

Does σM(t) know♯RˆSL(2;C)(M) and SL(2;C)-Casson invariant?

Does τρ with the action of a Galois group know

♯RˆSL(2;C)(M) and SL(2;C)-Casson invariant?

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General case

Problem

How can we treat it in the case of ♯Rˆ(M) = ∞? Only consider the componets of dimension 0? How to take a perturbation ?

How to treat splicing manifolds ?

In the original definition of the Casson invariant, we need to take a perturbation to get a transverse intersection. The problem is that a representation after a perturbation does not give a representation of π1(M).

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Problem

Can we construct λSL(2;R)(M)for (some class of) homology 3-spheres satisfying

λSL(2;C)(Σ(p,q,r)) = 2λ(Σ(p,q,r)) +λSL(2;R)(Σ(p,q,r))?

Proposition

There exists a hyperbolic homology 3-sphere without an irreducible SL(2;R)-representation.

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SL(2; R )-representations

Mn(K): 1/n-surgeried along the figure-eight knot Proposition

λSL(2;C)(Mn(K)) = 4n1, λ(Mn(K)) = −n

λSL(2;C)(Mn(K))2|λ(Mn(K))|= 2n1 Checked by Mathematica:

Example (n=2,. . . ,6,8)

λSL(2;C)(Mn(K))2|λ(Mn(K))|> ♯RˆSL(2;R)(Mn(K))>0 Example (n= 7,9)

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TQFT

Problem

How can we construct TQFT for Johnson theory?

(59)

Witten’s theory

Description from the view point of topological quantum field theory: E. Witten, Topology-changing amplitudes in

(2 + 1)-dimensional gravity, Nuclear Phys. B 323(1989).

参照

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