13
http://sites.google.com/site/hustat2017/
[email protected]
January 19th, 2018
2
. . . 3
. . . 4
. . . 5
. . . 6
. . . 8
. . . 9
. . . 10
. . . 11
. . . 12
13 . . . 14
2 / 18
■ A
□ A I 1×I
■
□ I {p1, p2, p3, . . . , pI}
□ n {np1, np2, np3, . . . , npI}
{X1, X2, X3, . . . , XI}
Table 1:
A1 A2 . . . AI
X1 X2 · · · XI n
n·p1 n·p2 · · · n·pI n
■
H0: {p1, p2, p3, . . . , pI}
■
H1:
■
X2≡ X2(p1, p2, . . . , pI) = I
∑
i=1
(Xi−n·pi)2
npi
(1)
13 – 3 / 18
0.1 ( ).
n
I
{
p
1, p
2, . . . , p
I}
X
in
·
p
iX
2(p
1, p
2, . . . , p
I) =
I
∑
i=1
(X
i−
n
·
p
i)
2np
i−→
χ
2(I
−
1)
X
2(p
1, p
2, . . . , p
I)
n
■ H0 n
I−1 1
■ H1 n
I−1 1
Figure 1:
H
0:
p
1, p
2, . . . , p
IH
1:
H
0■ C= (c,∞) α
I−1
13 – 4 / 18
■ ( ) 120 ( )
48 ( ) 36 ( ) 13
Table 2:
(1. ) (2. ) (3. ) (4. )
120 48 36 13 217
217
■
■
H0: p1= , p2= , p3= , p4=
■ 1 H0
3 (= 4−1) C= ( ,∞)
■
x2= {120−217·(9/16)}
2
217·(9/16) +
{48−217·(3/16)}2
217·(3/16) +
{36−217·(3/16)}2
217·(3/16) +
{13−217·(1/16)}2
217·(1/16) ≈
■ A B
■ A I B J
■ I×J
Table 3:
I
×
J
B
A B1 B2 · · · BJ
A1 X1,1 X1,2 · · · X1,J X1,•
A2 X2,1 X2,2 · · · X2,J X2,•
. .
. ... ... . .. ... ...
AI XI,1 XI,2 · · · XI,J XI,•
X•,1 X•,2 · · · X•,J n(=
∑I i=1
∑J
j=1Xi,j)
X•,j =∑Ii=1Xi,j Xi,•=∑jJ=1Xi,j n=∑Ii=1∑Jj=1Xi,j
Table 4:
I
×
J
B A B1 B2 · · · BJ
A1 pˆ1,1 pˆ1,2 · · · pˆ1,J pˆ1,•
A2 pˆ2,1 pˆ2,2 · · · pˆ2,J pˆ2,•
. .
. ... ... . .. ... ... AI pˆI,1 pˆI,2 · · · pˆI,J pˆI,•
ˆ
p•,1 pˆ•,2 · · · pˆ•,J 1
ˆ
p•,j =∑ I
i=1Xi,j/n pˆi,•=
∑J
j=1Xi,j/n ˆ
pi,j=Xi,j/n
5
6
Table 5:
1625 5 1630
1022 11 1033
2647 16 2663
Table 6:
YS MA NK
40 23 9 72
705 544 149 1398
215 272 96 583
960 840 254 2053
■ A i Ai
■ B j Bj
■ (i, j) Ai∩ Bj
■ A I B
■ i, j i̸=j
pi,j=pi,•×p•,j (2)
pi,j ≡Pr[Ai∩ Bj] pi,•≡Pr[Ai] =∑ J
j=1Pr[Ai∩ Bj] p•,j ≡Pr[Bj] =∑ I
i=1Pr[Ai∩ Bj]
□ 5
□ 6
13 – 7 / 18
■ n (i, j)
E[Xi,j] =n·pi,j (3)
■ 2
E[Xi,j] =n·pi,j =n·pi,•·p•,j (4)
■ Xi,j 4 (i, j)
Xi.j
{Xi,j−n·pˆi,•·pˆ•,j}2
n·pˆi,•·pˆ•,j
={Xi,j−Xi,•·X•,j/n}2
Xi,•·X•,j/n
ˆ
pi,•=
Xi,•
n =
1
n
J
∑
j=1
Xi,j, pˆ•,j =
X•,j
n =
1
n
I
∑
i=1 Xi,j
■
X2= I
∑
i=1
J
∑
j=1
{Xi,j−n·pˆi,•·pˆ•,j}2
n·pˆi,•·pˆ•,j
= I
∑
i=1
J
∑
j=1
{Xi,j−Xi,•·X•,j/n}2
Xi,•·X•,j/n
(5)
0.2 ( ).
I
×
J
n
■ 4
X
2(I
−
1)(J
−
1)
■ 4
X
2(I
−
1)(J
−
1)
(I
−
1)(J
−
1)
■
□ H0 4 □ H1 4
■ X2
□ H0 X2 (I−1)(J−1) □ H1 X2 H0
■
□ α H0 X2 (I−1)(J−1)
□ χ2
α
Pr[X2≥χ2α] =α
■
Table 7:
0.608 0.004 0.612
0.386 0.388
0.994 0.006 1.000
Table 8:
1620.2 9.8 1026.8 6.2
1. 5
□
□
0.612·0.994≈0.608, . . . , 0.388·0.006≈0.002
□
2663·0.608≈1620.2, . . . , 2663·0.00233≈6.2
□ = (2−1)·(2−1) 3.84
(3.84,∞)
□
x2= (1625−1620.2)
2
1620.2 +· · ·+
(11−6.2)2
6.2 ≈6.72
6.084865
Table 9:
YS MA NK
0.016 0.014 0.004 0.035
0.318 0.278 0.084 0.681
0.133 0.116 0.035 0.284
0.467 0.409 0.124 1.000
Table 10:
YS MA NK
33.6 29.4 8.9
653.2 571.5 172.9
272.7 238.6 72.2
2. 6
□
□
□
□ = (3−1)·(3−1) 9.49
(9.49,∞)
□
x2= (40−33.6)
2
33.6 +
(23−29.4)2
29.4 +· · ·+
(96−72.2)2
72.2 ≈37.41
■
■ p1
■ p2
■ n,m
■
{X1, X2, . . . , Xn}, {Y1, Y2, . . . , Ym}
Xi p1 1−p1 Yi p2 1−p2
■
ˆ
p1=
1
n
n
∑
i=1
Xi, pˆ2=
1
m
m
∑
i=1 Yi
■ H0: p1=p2
Z= √ pˆ1−pˆ2
¯
p(1−p¯)/n+ ¯p(1−p¯)/m, p¯=
n·pˆ1+m·pˆ2
n+m (6)
■
Table 11:
135 465 600
116 284 400
251 749 1000
Table 12: :
150.6 449.4 0.6
100.4 299.6 0.4
0.251 0.749 1.000
■ Z2 a
■
■ 29.0 22.5
600 400
■
x2=(135−150.6)
2
150.6 +
(465−449.4)2 449.4 +
(116−100.4)2 100.4 +
(284−299.6)2 299.6 ≈5.39
■ = (2−1)·(2−1) 3.84
(3.84,∞)
a
■ : Cochran rule
□
□
■
□
■ ( )
□
□ 0.5
I
∑
i=1
{|Xi−npi| −0.5}2
npi
n·max{0,|X11X22−X21X12| −n/2}2 X1,•X2,•X•,1X•,2
2 ∑
i=1 2 ∑
j=1
(Xij−Xi,•X•,j/n)2
Xi,•X•,j
=n·(X11X22−X21X12)
2 X1,•X2,•X•,1X•,2
(7)
□
■ Exact Test
□
□
1. 1630 1625 1630C1625
2. 1033 1022 1033C1022
3. 2663 (= 1630 + 1033)
2647 (= 1625 + 1022) 2663C2647
1630C1625×1033C1022 2663C2647
= 0.01106942
4.
0.01106942
■
■
5. 16 0.011
0.01884755
13 / 18
a
■
■
□
□
□ 13 14 (1) (2)
Table 13: S ppm
10 20 50 100 200 200
457 480 310 94 39 23 1403
38 11 4 1 1 0 55
495 491 314 95 40 23 1458
Table 14: S ppm
10 20 50 100 200 200
38 11 4 1 1 0 55
32 7 3 1 1 0 44
70 18 7 2 2 0 99
■ 5 b
□ 13
x2=
2 ∑
i=1 6 ∑
j=1
{xi,j−1458·pi,•·p•,j}2 1458·pi,•·p•,j
= 32.378
5
5 (= (2−1)·(6−1) ) (11.0705,∞)
□ 200ppm
14
x2=
2 ∑
i=1 5 ∑
j=1
{xi,j−99·pi,•·p•,j}2 99·pi,•·p•,j
= 0.328
5
4 (= (2−1)·(5−1) ) (9.48773,∞)
a
(1971) Vol.41, No.10
b
cont.
■ a
■
15 16
Table 15: ppm
10 20 50 100 200 200
451 475 308 91 38 23 1386
44 16 6 4 2 0 72
495 491 314 95 40 23 1458
Table 16: ppm
10 20 50 100 200 200
44 16 6 4 2 0 72
23 3 2 1 0 0 29
67 19 8 5 2 0 101
15 16
a
■ 15
19
□ 15
x2= 2 ∑
i=1 6 ∑
j=1
{xi,j−1458·pi,•·p•,j}2 1458·pi,•·p•,j
=
5
(11.0705,∞)
■ 16
19
□ 200ppm
16
x2=
2 ∑
i=1 5 ∑
j=1
{xi,j−101·pi,•·p•,j}2 101·pi,•·p•,j
=
5
(9.48773,∞)
Table 17:
1458
·
p
i,•·
p
•,j10 20 50 100 200 200
470.556 466.753 298.494 90.309 38.025 21.864 0.951
24.444 24.247 15.506 4.691 1.975 1.136 0.049
0.340 0.337 0.215 0.065 0.027 0.016
Table 18: ppm
101
·
p
i,•·
p
•,j10 20 50 100 200 200
47.762 13.545 5.703 3.564 1.426 0.713
19.238 5.455 2.297 1.436 0.574 0.287
0.663 0.188 0.079 0.050 0.020
■ (7)
■ 15
19
□ 15
x2= 2 ∑
i=1 6 ∑
j=1
{xi,j−1458·pi,•·p•,j}2 1458·pi,•·p•,j
= 26.841
5
5 (= (2−1)·(6−1) )
(11.0705,∞)
■ 16
19
□ 200ppm
16
x2= 2 ∑
i=1 5 ∑
j=1
{xi,j−101·pi,•·p•,j}2 101·pi,•·p•,j
= 3.627
5
4 (= (2−1)·(5−1) )
(9.48773,∞)
Table 19:
1458
·
p
i,•·
p
•,j10 20 50 100 200 200
470.556 466.753 298.494 90.309 38.025 21.864 0.951
24.444 24.247 15.506 4.691 1.975 1.136 0.049
0.340 0.337 0.215 0.065 0.027 0.016
Table 20: ppm
101
·
p
i,•·
p
•,j10 20 50 100 200 200
47.762 13.545 5.703 3.564 1.426 0.713
19.238 5.455 2.297 1.436 0.574 0.287
0.663 0.188 0.079 0.050 0.020
Table 21:
B1 B2 total
A1 X11 X12 n1=X1,•
A2 X21 X22 n2=X2,•
total X•,1 X•,2 n
■ Xi,•=Xi1+Xi2,X•,j =X1j+X2j,n=∑2i=1Xi,•=
∑2
j=1X•,j =∑2i=1
∑2
j=1Xij ■
(Xij−Xi,•X•,j/n)2= 1
n2 (
Xij· n ∑ s=1 2 ∑ t=1
Xst−Xi,•X•,j
)2
= 1
n2(X11X22−X12X21) 2
(Xi1−Xi,•X•,1/n)2 Xi,•X•,1/n +
(Xi2−Xi,•X•,2/n)2 Xi,•X•,2/n =
1
n
(X11X22−X12X21)2 Xi,•
(
1
X•,1 +
1
X•,2 )
= (X11X22−X12X21)
2 Xi,•X•,1X•,2
X = (X11−X1,•X•,1/n)2 X1,•X•,1 +
(X12−X1,•X•,2/n)2 X1,•X•,2 +
(X21−X2,•X•,1/n)2 X2,•X•,1 +
(X22−X2,•X•,2/n)2 X2,•X•,2
= n·(X11X22−X12X21)
2 X1,•X•,2X•,1X•,2
■ B1 A1 B2 A2
□
□ pˆ1=X11/(X11+X12) =X11/X1,•,pˆ2=X21/(X21+X22) =X21/X2,• □ (pˆ= (X11+X21)/n)
ˆ
p1−pˆ2 √
ˆ
p(1−pˆ)/n1+ ˆp(1−pˆ)/n2
ˆ
p = X11+X21
n , 1−pˆ=
X12+X22 n
ˆ
p(1−pˆ)
n1 =
X11+X21 n
X12+X22 n
1
n1 =
1
n2
X•,1X•,2 X1,•
, pˆ(1−pˆ) n2 =
1
n2
X•,1X•,2 X2,•
ˆ
p(1−pˆ)
n1
+pˆ(1−pˆ)
n2
= 1
n2
X•,1X•,2
X1,• + 1
n2
X•,1X•,2
X2,• = 1
n
X•,1X•,2
X1,•X2,•
ˆ
p1−pˆ2 = X11 X1,• −
X21 X2,•
=X11X22−X12X21
X1,•X2,•
ˆ
p1−pˆ2 √
p(1−p)
n + p(1−p)
n =
X11X22−X12X21 X1,•X2,•
√ 1
n
X•,1X•,2 X X
= √
n(X11X22−X12X21) √