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2016/11/29 13:00-14:30

• 

• 

• 

QTL

7 8

• 

• 

• 

• 

• 

• 

• 

• 

• 

• 

• 

vs.

• 

–  DNA

• 

– 

•  2

– 

(2)

DNA

12 24

1

1

46

h8p://wkp.fresheye.com/wikipedia/ DNA

Kurata and Omura (1982) Jpn J Breed 32:253

A B C

B C

8

0 2 4 6 8

0.000.050.100.150.200.250.30

k

P(X=k)

3 7

8

4

P(X = 4) = 8

4

"

# $ %

&

' × 0.3

4

× 0.7

4

p 1-p

n k

n

k

"

# $ %

&

' = n!

k!(n − k)!

P(X = k) = n

k

"

# $ %

&

' p

k

(1 − p)

n−k

p=0.3, n=8

(3)

p

8

4

P(X = 4 | p) = 8

4

"

# $ %

&

' p

4

(1 − p)

4

p

p

L( p | X = 4) ∝ P(X = 4 | p) = 8

4

#

$ % &

' ( p

4

(1 − p)

4

•  L(p) ln L(p)

ln L(p)

ln L( p) = 4 ln p + 4 ln(1 − p) + const

0.0 0.2 0.4 0.6 0.8 1.0

-18-14-10-6

p

4 ln(p) + 4 ln(1-p)

p=0.5

d ln L( p)

dp = 4

(1− 2 p)

p(1− p) = 0

0.0 0.2 0.4 0.6 0.8 1.0

-4-3-2-10

p

log(p)

3 5 2

9

3

P(X

1

= 3, X

2

= 3, X

3

= 3) =

9!

3!3!3! × 0.3

3

× 0.5

3

× 0.2

3

i i=1,2,…,k p

i

n i x

i

P(X

1

= x

1

,..., X

k

= x

k

) = n!

x

1

! x

2

! p

1

x1

p

kxk

= n!

x

1

! x

2

! p

i

xi

i k

1 1 1 2 2

2 2 2 3 3

ln L( p

1

, p

2

) = 3ln p

1

+ 3ln p

2

+ 3ln(1 − p

1

− p

2

) + const

p

1

=1/3, p

2

=1/3, p

3

=1/3

ln L( p1, p2)

p1 = 3 1 p1

1 1− p1− p2

$

% & '

( ) = (1− 2 p1− p2) p1(1− p1− p2)= 0

ln L( p1, p2)

p2

= 3 1 p2

1

1− p1− p2

$

% & '

( ) = (1− p1− 2 p2) p2(1− p1− p2)

= 0

p

1

,p

2

,p

3

9

3

p1,p2,p3

(4)

F 2

1 F1

1 P1

×

2 P2

1

A B

A B

A B

a b

a b a b

A B 0.5(1-r)

a b

0.5(1-r) r:

2

F2

a B A

b

0.5r 0.5r

F 2

AB 0.5(1-r)

Ab 0.5r

aB 0.5r

ab 0.5(1-r) AB

0.5(1-r) AABB (1-r)2 AABb r(1-r) AaBB r(1-r) AaBb (1-r)2 Ab

0.5r AABb r(1-r) AAbb r2 AaBb r2 Aabb r(1-r) aB

0.5r AaBB r(1-r) AaBb r2 aaBB r2 aaBb r(1-r) ab

0.5(1-r) AaBb (1-r)2 Aabb r(1-r) aaBb r(1-r) aabb (1-r)2

1/4

AA

Aa aa

BB (1-r)2 2r(1-r)

r

2

Bb 2r(1-r) 2{r2+(1-r)2} 2r(1-r)

bb r2 2r(1-r)

(1-r)

2

1/4

30

7

2

5

57

6

1

8

29

9 145

ln L (r) = 30ln(1− r)

2

+ 7ln2r(1− r) +  + 29ln(1− r)

2

+ const

= 144 ln(1− r) + 32ln r + 57ln(1− 2r + 2r

2

) + const

(5)

ln L(r) = 144 ln(1− r) + 32ln r + 57ln(1− 2r + 2r

2

) + const

0.0 0.1 0.2 0.3 0.4 0.5

-170-150-130-110

r

ln L(r) - const

d ln L(r)

dr = −

144

1− r +

32

r +

57(4r − 2)

1− 2r + 2r

2

0.0 0.1 0.2 0.3 0.4 0.5

-20002006001000

r

LOD odds

L(0.5)

L( ˆ r ) /L(0.5)

r = 0.117 ˆ

LOD

LOD = log10 L( ˆ r ) L(0.5)

"

# $ %

&

' = log10L(ˆ r ) − log10L(0.5) = 26.8

(bisec]on method)

∂ ln L(r)

∂r = − 144 1− r+

32 r +

57(4r − 2) 1− 2r + 2r2

0.0 0.1 0.2 0.3 0.4 0.5

-20002006001000

r

0 r

r Newton-Raphson

f(x)=0 x

1.  f(a) f(b) a

b

2.  a b m

3.  f(m) f(a) a m

f(b) b m

4.  2-3 m f(x)=0

a b

1

2

b b b

3

4

a a

a

m m m

• 

–  AC AB BC

( )

• 

–  2

x 2

x M

(cM)

–  Haldane Kosambi

Haldane

Kosambi

x= −1

2ln(1− 2r) x=1

4ln 1+ 2r 1− 2r

#

$ % & ' (

0.0 0.2 0.4 0.6 0.8 1.0 1.2

0.00.10.20.30.40.5

x (M)

r

Kosambi

Haldane

r = x

. 05

% 2

(6)

1.

2. 

3.  LOD

4.  LOD

(linkage groups)

5. 

6.

7. 

8.

• 

1.  LOD

2.  LOD

3.  1 2

• 

•  L1-L2-L3-L4-L5-L6

•  1

• 

L1

L2

L3

L4

L5

L6

14.5 0.0

5.2 8.3

17.1

20.3

• 

–  Maximum Likelihood

–  Minimum sum of adjacent recombina]on

frac]on SARF

=

+ +

+ +

+

+

=

1

1

1 , 1

, 1

, 1 , 1

,

[ log ( 1 ) log( 1 )]

)

(

l

i

i i i

i i

i i i i

n

i

R

L θ θ θ θ

ni,i+1

θi,i+1 .

=

=

+ 1

1 1 , l

i i

SARF θ

i

(7)

L1

L2

L3

L4

L1

L2

L3

L4

L1-L3-L2-L4

L1

L2 L3

L4

¡ 

l 

10 … 1,804,400

l 

100 … 4.7 x 10

158

l 

1000 … 2.0 x 10

2567

MAPMAKER

c

t k

q p

5

5

5!/2

= 60

a c

t k

q p

r v

(global op]mal solu]on, local op]mal solu]on)

Traveling salesman problem (TSP)

•  combinatorial op]miza]on problem

13,509 500

h8p://www.crpc.rice.edu/newsArchive/tsp.html

1

(8)

(ant colony op]miza]on: ACO)

• 

• 

• 

ACO

1.  2. 

3.  2

4. 

5.  1 4

A

B

C E

F

•  t k i j

] .

[

)]

(

[

]

[

)]

(

) [

(

ik

N

l il il

ij k ij

ij

j N

d

t

d

t t

p

k i

= ∀

β α

β α

τ

τ

d ij

)

ij

(t

τ

⎩ ⎨

= ∈

Δ

)

(

)

,

(

if

0

)

(

)

,

(

if

)

) (

( i j T t

t

T

j

i

t

L

t Q

k k k

k

τ

ij

=

Δ

+

=

+

ij mk ijk

ij

( t 1 ) ρτ ( t )

1

τ ( t )

τ

k

ρ 1

(9)

AntMap

•  AntMap

• 

•  AntMap

•  OS Windows, Mac, Linux, Solaris

Java h8p://lbm.ab.a.u-tokyo.ac.jp/~iwata/antmap/

bootstrap

•  RGP Web h8p://rgp.dna.affrc.go.jp/

AntMap

① / DHLs 169

② /Kasalath// BILs 245

③ /IR24 RILs 375

(10)

• 

–  ① 2.5 –  ② 3 –  ③ 7

CPU Intel Mobile Pen]um 1.6GH

•  100

–  ③ 38

•  ① ②

③ 5, 2, 5

•  1,200

•  10

2.5

(Swarm intelligence)

• 

• 

(par]cle swarm op]mizer: PSO)

• 

• 

• 

• 

(11)

PSO

A

B

C

A c1r1(xp− x)

c2r2(xg− x)

xg

xp

x wvt−1

vt

x

t

← x

t−1

+ v

t

v

t

← wv

t−1

+ c

1

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1

(x

p

− x) + c

2

r

2

(x

g

− x)

$ %

&

f (x)

w, c1, c2 1 (w < 1)

r1, r2 [0, 1]

PSO

f (x) = 10n + x

i

2

−10 cos2 π x

i

( )

i=1 n

Global minimum (

x = 0 f (x) = 0

Rastrigin

n = 2

R code

# load required packages require(rgl)

require(pso)

# set x and y arrays x <- (-50:50)/10 y <- x

# set a objective function (surface) z <- matrix(NA, length(x), length(y)) for(i in 1:length(x)) {

for(j in 1:length(y)) {

# Rastrigin function

z[i,j] <- 20 + (x[i]^2 - 10 * cos(2 * pi * x[i]))

+ (y[j]^2 - 10 * cos(2 * pi * y[j])) }

}

# show the objective surface open3d()

persp3d(x, y, z, col = "green")

# optimization

o1 <- psoptim(rep(NA,2),function(x) 20+sum(x^2-10*cos(2*pi*x)), lower=-5,upper=5,control=list(abstol=1e-8)) show(o1)

•  QTL

• 

• 

参照

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