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三角形の相互関係 tan θ = sin θ

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3

三角形の相互関係 ②

三角形の相互関係 tan θ = sin θ

cos θ

1 + tan

2

θ = 1 cos

2

θ cos

2

θ + sin

2

θ = 1

> 第3章 図形 計量 > 第1節 三角比 > 第2講:三角比 相互関係

 

I

例題

 

のとき,次の値を求めなさい。ただし, 

は鋭角とする。

tan

θ

= 2

θ

(1)

cos θ

(2)

sin θ

tanθ = sinθ

cosθ より,

tanθ cosθ = sinθ

cos2θ + sin2θ = 1 に代入すると,

cos2θ + (tanθ cosθ)2 = 1 cos2θ + tan2θcos2θ = 1

1 + tan2θ = 1cos2θ

参照

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