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Best Constant in Weighted Sobolev Inequality with Weights Being
Powers of Distance from the Origin
TOSHIO HORIUCHI
Department
ofMathematical Science, IbarakiUniversity, Mito, Ibaraki,310,Japan
(Received16June 1996)
We studythe bestconstantin Sobolevinequalitywith weights beingpowersofdistancefrom theorigininn.Inthisvariationalproblem,the invariance of
n
bythe group of dilatations createssomepossible loss of compactness.Asaresultwewillseethat theexistenceof extremals and the value of bestconstantessentially dependsupon the relation among parametersinthe inequality.Keywords: Weighted Sobolevinequality;concentration compactness.
AMSSubjectClassification: 35J70, 35J60, 35J20.
1
INTRODUCTION
We
beginwithrecallingthe famous theorem due toGiorgioTalenti 11]"TI-I.OREM 1.1
Let
u be any real (or complex)valuedfunction
inC (n).
Moreover,
letpbe any number such that: 1 < p < n. ThenIVul
pdx > S(p,q,n) lul
qdx(1.1)
Thisresearch was partiallysupported byGrant-in-Aid forScientificResearch(No. 08640163), Ministry of Education,Scienceand Culture.
275
where:
IVul
isthelengthof
thegradientVuof
u, q np/(n p)and( - ;r(n) (1.2)
Theequalitysign holdsin
(1.1) if
uhas theform:
u(x)
[a+ blxlP/(P-1)] 1-n/p, (1.3)
where
Ix (x2
+."+ x2)
anda, barepositiveconstants.The main purpose of the present paper is to study the best constant in the imbedding theorems for the weighted Sobolev spaces with weight functionsbeingpowersof
Ix I.
Namely,we are interested inthe best constant S(p,q,, , n)
inthefollowing inequality:[VulPlxl
pdx > S(p,q,, ,
n)lulqlxl
qdx(1.4)
whereuisanyfunction inC (Rn)
and1 1 1-c
+/3
n n0<---=
</
< or, l<p<p q n q
1-c+/3
(1.5)
Fortheproofof thisinequalityand related informations, see[9;Theorem 1 in2] and [6;Theorem1 in3].
Ifot 0and/3
< 0,then the best constant isalreadyobtained in 11 and[4]. Theequality signin this case also holds ifuhas thesimilarform in Theorem 1.1. Therefore we are interested in(1.4)
whenot is apositivenumber.In
this variationalproblem,the invarianceofn
bythegroupof dilatations creates somepossibleloss ofcompactness.As
aresult we show that the existence of extremal functionsessentiallydepend uponthe parameters (p, q,or,/,
n).For
example, there is no extremals ifot
--/3
and p 2.Moreover
if we restrictourselves to the case when p 2, wecanmake clear the behavior of the best constant S(2,q,or,/3, n)
rather preciselyasa function of(q,or,/3,
n)under the condition(1.5).
It
seems tobe worth mentioning that the equality signin(1.4)
can not be achievedby anyfunction withcompact support.To
see this we assume thatthereexists anextremal uhavingthesupportin aballBr {x
E ]n..Ix
<r},
namely, the infimum is attained by u.Here
we may assume u is nonnegative.Moreover
it has to satisfythe EulerLagrange
equationin distributionsense;div(IxlPlVulp-2vu) )lxlqu q-l,
inBr
ulsr
0, u > 0 inBr. (1.6)
Here .
> 0 is aLagrange
multiplier.Then it follows from thenextlemma thatuhas to vanish almost everwhere inBr.
LEMMA
1.2(Pohozaev
identity)Let
p, q, n,ot and satisfy 1 < p, 0 <l/p- 1/q <
(1
-or+ 13)/n, (1
-or+
)p <nand13
> -n/q.Assumethat uWII (n)
satisfy the equation(1.6)
with Dirichletboundarycondition indistributionsense.Thenitholds that,k[1 -ot
+/3
n(1/p l/q)]f Ixlqu
qdx(1
1/p)] IxlP(x, v)lVul
pMS, (1.7)
Brwhere v isthe unit outernormalto O
Br
and Sis the(n
1)-dimensional Lebesguemeasure, andW (n)
isdefined
by(2.2)
and(2.3).
When 1/p- 1/q >
(1
-or+ )/n
itfollowsimmediatelyfrom(1.7)
that u 0. When1/p- 1/q(1
-or+ 13)/n,
wededucefrom(1.7)
thatOu 0on0
Br,
and thenby(1.6)
0
f_ div(IxlPlVulP-2Vu)dx ; f_ Ixl’qu
q-1dx,(1.8)
,]lYlr
thusu 0.
Proof of Lemma
1.2By a
standardargumentofregularization,we seethat u issmooth. Then the equalityis establishedbythe computation of divP and an integrationby partsforP IxI=PIVulP-Z(Vu, x)Vu. (1.9)
Fortheprecisesee[4;
Prop.
13],[5]
and[10].
2
WEIGHTED SOBOLEV SPACES AND
INEQUALITIESIn
this section weshallmodifythe classical Sobolevspacessothatwecan treat the variationalproblemsin thesubsequentsections.Tothisend we recall theweighted inequality ofSobolevtype.LEMMA
2.1 Letpsatisfy 1 < p <+cxz
and letn satisfyn >_ 2.Suppose (1-o+)p<n, O< 1/p-1/q(1-c + )/n
and-n/q <3
< o,then there is apositive numberCsuch that
for
anyuC (]n),
(L lulqlxlq
dx)l/q
< C(f [Vu[P[x[P
dx (2.1)Ou Ou Ou
Here, Vu
(-x, Ox- OXn)
andIVul (Y--1 I’ff [2)
1/2Theproofof thisis seen inmany places,forexamplein Maz’ja’s book
[9;
Theorem 1 and its corollaries in2].
Thisresult is also obtained as a corollaryto the more general imbeddingtheorem in the author’spaper [6;Theorem 1 in
3].
This lemma naturally leads us to define the following spaces:Let
1 < p <+o
and or, be real numbers >-niP. Let L(JR n)
denote thespace of Lebesguemeasurable functions, defined onRn,
for which Ilu;LP(In)II lulPlxl
tpdx <+cx.
(2.2)W; (IRn)
is definedbyWI[ff (IR n) {u tq(P)(IRn) lVu LP(IRn)}, (2.3)
where
1 1 1-cr
+/3
npor q(p)
p q(p) n n (1-ot +/3)p
(2.4)
equip
W:ff (]Rn)
with the normWe
Ilu;
wli()ll-
Ilu;L(P)(IRn)II 4-IIIVul; LP(n)II., (2.5)
We
also set1,p 1,p
R, (]R ) {u W, ()
uis a radialfunction},
1,p 1,p
Ilu;
R,(n)ll-
Ilu;W, (I)ll. (2.6)
Under these notations we prepare a compactness proposition for the imbeddingand restrictionoperators
W21 (IRn) L (B)
foranyballB.PROPOSITION2.2
Let
psatisfy 1 < p <+cx
and letnsatisfyn > 2.By B
wedenoteanarbitraryballin
N n.
(1) Assume
that(1
c+ 13)
p < n, 0 < 1/p 1/
r <(1
ot+ /
n and-n/q <
13
<or,then thefollowingrestrictionsof
the mappingarecompact;Wlot; (]n) _. Lr(B),
p <r < q(p) np/[n p(1-or+/3)]. (2.7) (2) Assume
that(1
ot+
)p < n, 0 < lip1/r
<(1
ot+ )/n
and-n/q <
,
thenthefollowing imbeddingmappingsarecompact:RI’P( n) -- L(B),
p <_r <q(p) np/[n p(1-or+/3)]. (2.8) In
the assertion(2)
of thisproposition,rmayexceed the so-called Sobolev exponent provided/3 > or, because elements inR,/(R
1,pn)
are essentially dependent uponone variable. Andtheproofiselementary bythe use of the polarcoordinate system.For
the detail see[4;Lemma
10]for instance.3
MAIN RESULTS
We
shall studythe followingvariationalproblems.Assume
that p, q,n,otand/3
satisfy1
<p<+cx,
(1-c+fl)p<n, O< 1/p-1/q(1-ot + fl)/n
n>2,
and
-n/q <
t3
<Under theseassumptionsweset
(3.2)
(P) In
thefollowingproblem
weassume insteadofthe inequality(3.2)
-n/q
</3. (3.3)
SR(p,q, or,
fl, n)
infIVulPlxl
p’dx uRo,(IRn), Ilu LII
1(Pn)
In
theproblem (PR),if we make achangeof variables definedbyIxl
r1/h,
h(1
-ot+ fl)(n
p+
pc)n-p(1 -or
+fl) (3.4)
wegetanequivalentvariationalproblem
(P)
forvC1 (]+)
SR(p,q,or,
, n)
C(p,q,k)
inf
Iv (r)lpr
n/(1-+fl)-Idr]v(r)lqr
n/(1-+)-1dr 1I,
(PR)
where
C(p,q,h)
IS n-111-p/q
hp-I+p/q(3.5)
and
sn-ll
isthe area ofn 1-dimensional unitsphere.Thisproblemwas solvedbyTalenti using the notion ofHilbertinvariant integral. Namelyit follows fromLemma
2 in 11 that the infimum is achievedbyfunctionsof the formhp
v(r)
[a+ blxlT:--
p(1---+fl)(3.6)
Then with somewhat more calculations we see
LEMMA
3.1Assume
that(3.1)
and(3.3).
Thenwehave St p q,or,fl n)
PY
(3.7)
wherey 1 ot+ ft. In
particularif
orfl,
thenwehaveSn(p’q’t’t’n) S(p’q’n)
(n- p+
pPt)
p(3.8)
Therefore weimmediately get
LEMMA
3.2(1) Assume
that1/p- 1/q1/n,
1 < p < n andn > 2. Thenwehave S(p,q,n)
< SR(p, q,or, or,n),S(p,q,
n)
> SR(p, q,or, or,n),ifot
>O
(3.9) ifot <O
(2) Assume
that(3.1)
and(3.3).
ThenwehaveS(p,
q,or,, n)
k1-p-p/qS(p,q,O,
or,n),(3.10)
where k n--p+otpn-p
From
thislemmaitseemsthat ifot < 0,S
e(p,q,or,/3, n)
isalso the best constant fortheproblem (P),and inthe subsequent argumentthisprovesto be true. Thefollowinglemmaispartiallyprovedby
TalentiandEgnell in the case thatot0,/3
< 0).
LEMMA
3.3Assume
thatp, q, or,13,
n satisfy(3.1)
and(3.2). Assume
that<t<O,
thenS p, q, or,
fl, n)
Sg(p,q, or,13, n). (3.11)
Proof of Lemma
3.3By
apolarcoordinatesystem,we rewrite(P)
toobtainI fs fo [lku12)p/2raP+n-1
inf
n--1
(lOrul2 + --7 g--
drdSo,lulqr
q+n-1drdSo, 1n-1
(P’)
where
So,
is an 1-dimensionalLebesguemeasure andA
istheLaplace Beltrami operator ontheunit sphere Sn-1.
Making a changeof variables definedbyr
pk,
k n P(3.12)
n p+otp wehave
[
inf
kl-p-p/q
,-
(lOpvl2
._[_k2IAvlZ]P/2102
!pn-1
dpdSo,u
wl;(n), ivl qp(n-p)q/p-1
dpdS 1n-1
(P’)
wherev(p
co)
k-1/qu(pkco).
Sinceot _< 0bytheassumption,we see k > 1.Therefore we seeS(p,q, or,
8, n)
> k1-p-p/q S(p,q,O, ,8
or,n),(3.13)
where we used (n p)q/p 1 q(/3 -or)+
n 1.Since/3
-ot < 0, the assertion(4.4)
inLemma4.1 and thespherically symmetric decreasing rearrangementofvleads us toS(p,q,O,
, n)
Sic(p, q,O,
or,n). (3.14)
Therefore the assertionfollows fromLemma3.2.Now
we are in apositiontostate our mainresult.THEORE 3.4
(1) Assume
thatO < ot--/3, 1/2-
1/q1/n,n
> 2. Thenitholdsthat S(2,q,or, or,n)
S(2,q,0, 0,n)
S(2,q,n). (3.15)
Moreover there exists no extremalfunction
which attains theinfimum
in(2) Assume
thatot >O,
ot >,
0 < lip- 1/q(1
-ot+ )/n,
n > 2n Then the
infimum
S(p q or,13, n)
is attainedbyan and l < p <_
+extremal
function
u inW; (an) anc
thisusatisfies
indistributionsensethe equation:-div(lxlPlVulP-2Vu)
I.Ixlqlulq-2u, (3.16)
whereI is a
Lagrange
multiplier.Remark Inthe assertion(1),the best constantS (p,q,ct,or,
n)
isnot known unless p 2. Becausetheproofin thispaper essentiallyusethelinearlity of the EulerLagrange
equation.But
atleast we seethat S(p,q, or,or,n)
<S (p,q,n)intheproofof the assertion
(1).
And the bestconstantin assertion (2)isalso unknown forthepresent.We
also note that ifwereplacetheweight functionIx
byIXn I,
we canshow a similar result.4
PROOF OF THE ASSERTION
1First weprovethe assertion 1.Let beadomainof
R n.
Foranonnegative functionf
6C()
with having acompact support, we denote byS(f)
the spherically symmetric decreasing rearrangement of
f
(the Schwarzsymmetrization of
f).
That is:S(f)(x)
sup{t/x(t)
>IS-l. Ixl },
/z(t)I{x f(x)
>}l.
(4.1)
We preparethefollowinglemmas. The first one iswell-known for theproof see 11; Lemma1]for instance).
LEMMA
4.1Let S(f)
be thesphericallysymmetricdecreasing rearrange- mentof
a nonnegativefunction f C(f2)
with a compactsupport. Let g 6C((0, cx))
be a nonnegative decreasingfunction.
Then,for
everyexponent p > 1, the followings hold:
f s(f)P
dxf fP
dx,(4.2)
f lS(f)lP
dx<- f I flp (4.3)
f S(f)Pg(lxl)dx
>_ffP
(4.4)The next one isavariantof theHardy-Sobolev inequality.
LEMMA
4.2Assume
thatf C2(f2),
u 6C(),
CR
n (n > 2). Letus set
v(x) S(If" ul)(x).
Thenitholds that[Vv[ 2dx +
- [A(f 2)- 2lVfl
dx <_IVu
dx.(4.5)
Admitting this in the present we shall establish the assertion
(1)
in Theorem3.4.Proof of
theassertion(1) By
the useof these lemmas forf Ix 1’,
f2R n,
weseethatS(2,q,n)
Ivl
qdx+
oe(o+
n2) u2lxl
2(c->dx[ IVulZlxI
2tdx.(4.6)
Here 1/2
1/ql/n,
n > 2.Hence
if there exists anextremal function u 6W (R"),
then we haveS(2,q,
n)
4-or(or4-n 2)f tZlx]
2(c-1)dx <_ S(2,q, o,c,n).
(4.7)Thisimplies
S(2,
q, oe,c,n)
>S(2,
q,n),
andobviouslythe equality sign holds in(4.7)
onlyifu 0.Therefore it suffices to see theoppositeinequality.Letusset, fory 6
I
n\ {0},
S(y) inf{
f. [Vul2lyl2
dx[ulqlYl=q
dx 1,u 6C(n)}. (4.8)
Onethencheckseasilythat if wereplaceuby
,-n/qu(.
y/F.),8 >0,q2n/(n 2)
andletetend to0,we haveS(2,
q, or, or,n)
< S(y). Onthe other hand,it holdsS(y)=inf{f. ivul2
dx.lulqdx=l}=S(2,
q,n).(4.9) So
that we seeS(2,q, or, or,2) S(2,q,n).
Proof of Lemma
4.2 Firstwehavefo
IV(f U)[
2dx[[Vul2f
2-+- U2IVf[ 2]
dx+
- VU2 v f2
dxlvul2 f
2 lf. U2[A(/2) 21Vfl 2]
dx.(4.10)
Then, from
Lemma
1 we can show the desired result.Here
we note that this proofstill works if we put eitherf(x) Ix c,
(or > 0,n >2)
orf (x) Ixnl ’,
(o >_1/2,
n >2).
5
PROOF OF THE ASSERTION
2us setforu 6
W;ff (]n)
Let
J(u) f,
lulqlxlqdx,(5.1) E(’) finn IVulPlxl
pdxHere0 < (1-or
+)/n
l/p- 1/q,ot > > -n/q, p(1-or+/3)
< n.Wealso set for 0 < ) < 1
Sz inf[E(u)
J(u)
),u 6W (IR n) (5.2)
Assume
that{uj}
CWI? (IRn)
isaminimizingsequencesuch thatlim
E(uj)
S=_ S(p,q,ot,, n) J(uj) I
(j-1,2,3).
j+
(5.3)
In
order toprovethe existence of the extremal function inW: (n),
first weshow thetightnessof thesequenceconsidered.Letusalso set pj
--IVujlPlxlCp + ]ujlqlx] q,
Qj(R) I
JBR(O)pjdx (j 1,2,3). (5.4)
For
6 1 ot n/p ande >0,wesetueeu(x/e).
Then we seeJ
(u)J
(ue)
and E(u)
E(ue). (5.5) Hence
wemayassumefrom the firstQj(1) ,
1 j 1, 2,3(5.6)
Then we see
LEMMA
5.1 Foranarbitrary e > O, thereexistssomepositive numberR suchthatwehavedx < (j 1, 2, 3
(5.7)
n\B(O)
P
Proof of Lemma
5.1 Firstwenotethat for somepositivenumberL lim fI
pjdx L >_I +
S.(5.8)
j--+cx:)
JRn
According to the argumentin [8; Theorem 1 in part 1], we just have to show that dichotomy cannot occur. Tothis end we assume thatdichotomy occurs.Then, extracting subsequencefrom
{uj
ifnecessary,we see that for anarbitrarye > 0,there existpositivenumbersA
6 (0,L), Rand asequence ofpositivenumbersRj
such that:A-- fB
(0)pjdx <’ fBj
(0)\BR(0)pjdx
<e, and j--+limRj
=cx.(5.9)
Let f
and g benonnegativesmooth functions such that 1,Ixl
< 1{
1,Ixl
> 1f
0,Ixl
> 2, go, Ixl
<1/2. (5.10)
Let
us setul(x) f(x/R)’u,
u2(x) g(x/Rj)
u.Then,foranye > 0there is apositive integer
N()
such that(5.11)
[IV f (x/R)lPlujl
p+ IVg(x/Rj)lPlujlP]lxl
pdx <et (5.12)
for j >N (e). In
fact we seeIP[x[
pdx_<lxl_<2R
)P/q
<
luj
qIx
qdx_<lxl_<2R
<
CRPe.
Ixl
1-- dx1<2R
(5.3)
And in a similarway,dx
CRPe. (5.14)
lujlPlxl
pj/2<lxl<Rj
Here
Cisapositivenumberindependentof eachRanduj.Thereforewe see(5.12).
Ontheotherhand,wemayassumethat for some numberss, 6 [0, 1]lq
Ix I/q
dx--
s,f lulqlxl
q dx --+ t,(5.15)
I1 (s + t)l
_< e.From
Sobolevinequality,there is apositivenumbercsuch thatf lvujlPlxl
pdx >c.(5.16)
When e tendsto0,we mayassumethats
s(e)
alsoconvergestosome number g 6 [0, 1].In
casethatg 0or 1, then we see S >_ c/S
efor anye > 0, and this contradictstoSobolevinequality. Therefore,g 6 (0,1).
Since
(e)
-+ 1g,
wehaveS > S --1-S1---
[P/q
--[-.(1 -)P/q]s
>S, (5.17)
and thisisa contradiction.Afterallwe seethat under the condition
(5.6)
theminimizing sequence{u}.
j=lc W,
1,p(IRn)
and{PJ}-I
aretight inL(IR n)
and a space of allbounded measures on
R
n respectively. Toseethe existence ofextremals,we needan apparentvariant of the concentration compactness lemma due to Lions in[7]and [8].For
thesakeof self-containedness we state it here. The proofis omitted.Let {uj
be aminimizing sequence satisfying(5.3).
CONCENTRATION COMPACTNESS
LEMMA
5.2 Let{uj
beaboundedsequenceinWI; (an)
convergingweaklytosome uand such that]Vuj IPINI
paconvergesweaklyto lZand
luj
qIx
q convergestightlytovwhereIxandv arebounded nonnegativemeasures onN n.
Then we have(1)
Thereexistsome at most countablesetJandtwofamilies {xj}jej of
distinctpointsinIR n, {vj}jej
in (0,cx)
such that:lulqlxl
q, + 2_., ,a,, ,
>_+ 2..,,a,,
J J
(5.18)
for
sometzj > O. Moreoveritholds thatV;/q
<lZJ.
S(5.19)
(2) If
vWI(Nn)
andIV(uj
q-v)lPlxl
p converges weakly to somemeasure-if, then -/z L
(R).
(3) If
u =_0 andlz(IRn)
<_Sv(ln) p/q,
thenJ isasingleton andwehave 113
’(Xo
S,p/q
lz,(5.20)
for
someg > 0andxo
]n.ENDOFPROOFOFTHEOREM. Fromthis lemma we mayassumethatthere is aweak limit u
WII (Nn)
of the minimizing sequence{uj}.
Thereforeit sufficesto show thatuj converges stronglyto u
7
0 identically under the condition o > >_ 0.From
the assumption wesee/x(Rn)
S andv(Rn)
1(tightness).Here
wenotethatthe lack ofcompactnesscan occur only atthe origin.Because
the weightfunction vanishesonly there.More
precisely,ifD isboundedopen subsetofR
n having apositive distanceto theorigin,thentheimbedding operatorWII (Rn) Lq(D)
iscompactunder the conditions 1/p 1/q
(1
oe+ fl)/n,
c >fl
> -n/q and1 < p <
n/(1
ot+/3). Now
ifu 0,then fromLemma
5.2andthe above+/-/z 3o But
remark we seev s
1
Qj(1) >_
1(o)lujlqlxl
qdx--
1.(5.21)
This isa contradiction.
Next
we seeuj converges stronglytou.Letus set af, lu
qIx
qdxand assume that 0 <a < 1. Then from the lemma we havevo
1 -a, lzoS13g/q, f IVulPlxl
pdx <S-lzo.(5.22)
Hence
we seelVulPlxl
pdx S lzoS(1 P/q)
<S(1 vo)
p/qSa
p/q(5.23)
Onthe otherhand,itholdslvulPlxl
pdx > Sa Sap/q. (5.24)
Sowereachacontradiction.
Appendix
In
this section wecalculatethe best constantS(2, q(ot),or,/3(o0,
n), where or,fl(ot),
q(ot)andn satisfythe relations;2or
fl
q ot n >2,q ot 2(n+ 200
n+
2t 2fl(ot)-
or.(A.1)
n
+
2or2’
n+
2orPROPOSITION
A.
1In
additiontothese assumptionswe assume that 2or isa positive integer. ThenitholdsthatS(2, q(ot),or,
fl(ot), n) Sn(2,
q(ct),or,fl(ot), n)
=S(2 2n/(n 2),
n -k-2ot)
yr-2a/(n+2O(I’((n 1-’(n/2) + 2t)/2) )
2/(n+2)(A.2)
Proof
Then
S > 2,--inf
IVu Ixl
dx"lu Ix[
dx 1Note
thatfv l7ul2lxl
2tdxZ
Cafv IVu[
2"2al 2a21 62Xn
2a"dx’
We
abbreviateS(2,
q(ot),or,fl(ot), n)
toS.Let
ussetV
[0,)n.
(A.3)
(A.4)
! Then we see where0- (0-1,0"2
o"n)
andca
S _> 2.+2 inf
ca
(6a/ Ca )2/q
(or)y
e=l,e>_0lal=[fv
2..2a-2a"dx" fvlV,lq(’)2’ -2a"dx 1].
inf
IXTva
.x ...xn(A.5)
Weneeds more notations.Z
(Z
Z2 Zn)
j (./J
.zJ ,rJ
]I?2aj+l.’1’"2’ "2aj+l
ka IS
2asZazl Szan
Va(z) v(lzll, Iz21 Iznl)
Under these notations
(A.6)
(A.7)
Here
weprepareelementary
lemmas.290 T. HORIUCHI
LEMMAA.2 Under thesamenotations, itholds that Ccr
r
8orkcr ]2/q((*)
inf
-
/C
ye=l,e>0[
1-2/q((*)
(A.8)
LEMMA
A.3Ca
Isn-ll
1r(-)
E k-- 2nlSn+2(*-I
2nrr(*r() (A.9)
Proof of Lemma
A.2Let
us setF({ea})a)=(*, be) E
)7 beE a
1(A.10)
lal--(* Irl--(*
Applyingthemethod ofa
Lagrange
multipliertoF({e}ll--(*,/z)
under therestriction
lrl--(*
8r 1,8or _>0, the infimum inLemma
is attainedwhenq(ot)
q(a)
(
2)2-q()
111.2-q()
q
(or) lcrl=(* cr /
Therefore the assertion is now obvious.
Proof ofLemma
A.3 In placeof ea, weset(A.12)
wherea (0-1,0"2ng, lal
0-1+
0"2-+- +
0"n.Thenweshown,a 1.
To
thisend let us set thatlal--(*
8cr’.’(*
l(n,a) Dn,c, Dn
a Finj--l\crjl[2crj’,
andl(n,
0)
1.(A.13)
We
shall show the assertioninductively. Sowe assume thate ’
1,(A.14)
Icr=crl-q-... +Crk=/3
forany nonnegative integers k
and/3
satisfying k < n 1and/3
< or, and weconsider thecasek n.By
thehypothesisof the induction, we seeDn,cr Dn-l,a
l(n 1,ot k)-1.
Irl=o k--0 Icrl=c-k k=0
(A.15)
Then it suffices to show that=o ()
l(n 1, k)-
l(n,)-,
namely
LEMMAA.4 Forn,ot >O, weset
e(n, or)
Z
(n1)(n
-4- 1)...(n
3+ 2(or
k))(A.16)
Then
n(n +
2)... (n+
2or2)
e(n,
ot)
(A.17)
Proof ofLemma
A.4 Againwemake use of the inductiononthe values ofot
+
n.Weassume that(A.18)
holdswhenot+
n <m.Nowweassume thatot
+
n rn+
1 First we see that forany nonnegative integersot andn P(n,ot+ 1)
2P(n,or) +
P(n 2,oe+
1).(A.18)
Then the desiredequality
(A.18)
easilyfollows from these relations.References
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