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http://jipam.vu.edu.au/

Volume 7, Issue 3, Article 113, 2006

BEST GENERALIZATION OF A HILBERT TYPE INEQUALITY

BAOJU SUN

ZHEJIANGWATERCONSERVANCY& HYDROPOWERCOLLEGE

HANGZHOU, ZHEJIANG310018 PEOPLESREPUBLICOFCHINA

[email protected]

Received 05 January, 2006; accepted 10 April, 2006 Communicated by B. Yang

ABSTRACT. By introducing a parameterλ, we have given generalization of Hilbert’s type in- tegral inequality with a best possible constant factor. Also its equivalent form is considered, and the generalized formula corresponding to the double series inequalities are built.

Key words and phrases: Hilbert’s type integral inequality; Weight coefficient; Weight function; Hölder’s inequality.

2000 Mathematics Subject Classification. 26D15.

1. INTRODUCTION

Ifp > 1, 1p +1q = 1, f, g ≥0, satisfy0<R

0 fp(t)dt <∞and0<R

0 gq(t)dt <∞,then (1.1)

Z

0

Z

0

f(x)g(y)

x+y dxdy < π sin(πp)

Z

0

fp(t)dt

1pZ

0

gq(t)dt 1q

,

where the constant factor π/(sinπ/p) is the best possible. Inequality (1.1) is called Hardy- Hilbert’s inequality (see [1]) and is important in analysis and applications (cf. Mitrinovi´c et al.

[2]). Recently, Yang gave an extension of (1.1) as (see [4, 5]):

(1.2) Z

0

Z

0

f(x)g(y) (x+y)λdxdy

< B

p+λ−2

p ,q+λ−2 q

Z

0

t1−λfp(t)dt

1pZ

0

t1−λgq(t)dt 1q

, where the constant factor B

p+λ−2

p ,q+λ−2q

(λ > 2− min{p, q}) is the best possible, and B(u, v)is theβ function. Hardy et al. [1] gave an inequality similar to (1.1) as:

(1.3)

Z

0

Z

0

f(x)g(y)

max{x, y}dxdy < pq Z

0

fp(t)dt

1pZ

0

gq(t)dt 1q

,

ISSN (electronic): 1443-5756

c 2006 Victoria University. All rights reserved.

007-06

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where the constant factorpqis the best possible. The double series inequality is:

(1.4)

X

n=1

X

m=1

ambn

max{m, n} < pq

X

n=1

apn

!p1 X

m=1

bqm

!1q ,

where the constant factorpqis the best possible. In particular, ifp=q= 2, one has the Hilbert type integral inequality:

(1.5)

Z

0

Z

0

f(x)g(y)

max{x, y}dxdy <4 Z

0

f2(t)dt Z

0

g2(t)dt 12

.

Recently, Kuang gave an extension of (1.4) as (see [3]):

(1.6)

X

n=1

X

m=1

ambn max{m, n} <

X

n=1

[pq−G(p, n)]apn

!1p X

m=1

[pq−G(q, n)]bpm

!1q ,

where G(r, n) = r+1/3r−4/3

(2n+1)1/r > 0 (r = p, q). Yang and Debnath have also considered other Hilbert type integral inequalities in [6].

The main objective of this paper is to build a new inequality with a best constant factor, related to the double integral R

0

R 0

f(x)g(y)

max{xλ,yλ}dxdy, which improves inequality (1.5). The equivalent form and the corresponding double series form are considered.

2. MAINRESULTS

Theorem 2.1. If λ > 0, p > 1, 1p + 1q = 1, f, g ≥ 0such that0 < R

0 tp−1−λfp(t)dt < ∞, 0<R

0 tq−1−λgq(t)dt <∞, then one has

(2.1)

Z

0

Z

0

f(x)g(y)

max{xλ, yλ}dxdy < pq λ

Z

0

tp−1−λfp(t)dt

1p Z

0

tq−1−λgq(t)dt 1q

and (2.2)

Z

0

yλ(p−1)−1 Z

0

f(x)

max{xλ, yλ}dx p

<pq λ

pZ

0

xp−1−λfp(x)dx,

where the constant factors pqλ, pqλp

are the best possible. Inequality (2.1) is equivalent to (2.2).

In particular, for λ = 1, (2.1) and (2.2) respectively reduce to the following two equivalent inequalities:

(2.3)

Z

0

Z

0

f(x)g(y)

max{x, y}dxdy < pq Z

0

tp−2fp(t)dt

p1 Z

0

tq−2fq(t)dt 1q

and (2.4)

Z

0

yp−2 Z

0

f(x) max{x, y}dx

p

dy <(pq)p Z

0

xp−2fp(x)dx.

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Proof. By Hölder’s inequality, one has Z

0

Z

0

f(x)g(y)

max{xλ, yλ}dxdy = Z

0

Z

0

"

f(x) (max{xλ, yλ})1p

y x

pqλp1

x1qp1 (2.5)

× g(y) (max{xλ, yλ})1q

x y

pqλ1

q

y1p1q

# dxdy

≤ Z

0

Z

0

fp(x) max{xλ, yλ}

y x

λq−1

xpq−1dxdy 1p

× (Z

0

Z

0

gq(y) max{xλ, yλ}

x y

λp−1

ypq−1dxdy )1q

.

Equality holds in (2.5) if there are two constantsA,B, such thatA2+B2 6= 0and A fp(x)

max{xλ, yλ} y

x λq−1

xpq−1 =B gq(y) max{xλ, yλ}

x y

λp−1

yqp−1

a.e. in(0,∞)×(0,∞), orAxp−λfp(x) =Byq−λgq(y) =constant a.e. in(0,∞)×(0,∞), this contradicts the fact that0<R

0 tp−1−λfp(t)dt <∞. Thus the inequality (2.5) is strict.

Define the weight functionwλ(r, t)as:

wλ(r, t) = tλ−1 Z

0

1 max{tλ, uλ}

u t

λr−1

du, r=p, q;t∈(0,∞).

By computing, one has:

(2.6) wλ(p, t) = pq

λ =wλ(q, t), and we obtain

Z

0

Z

0

f(x)g(y)

max{xλ, yλ}dxdy

<

Z

0

wλ(q, t)tp−1−λfp(t)dt

1p Z

0

wλ(p, t)tq−1−λfq(t)dt 1q

= pq λ

Z

0

tp−1−λfp(t)dt

1pZ

0

tq−1−λfq(t)dt 1q

.

For 0 < ε < λ , setting f(t),e eg(t) as: t ∈ (0,1), fe(t) = eg(t) = 0; t ∈ [1,∞), fe(t) = tλ−p−εp , eg(t) = tλ−q−εq

Z

0

Z

0

f(x)e eg(y)

max{xλ, yλ}dxdy (2.7)

= Z

1

yλ−q−εq Z

1

1

max{xλ, yλ}xλ−p−εp dx

dy

= Z

1

yλ−q−εq Z y

1

1

yλxλ−p−εp dx

dy+ Z

1

yλ−q−εq Z

y

1

xλxλ−p−εp dx

dy

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= p λ−ε

1

ε + q

λ−λq−ε

+ 1

ε · p

λp−λ+ε

= 1 ε

p

λ−ε + p

λp−λ+ε

− pq

(λ−ε)(λq−λ+ε).

On the other hand, (2.8)

Z

0

tp−1−λfep(t)dt

1pZ

0

tq−1−λegq(t)dt 1q

= 1 ε.

If the constant factor pqλ in (2.1) is not the best possible, then there exists a positive number k (withk < pqλ), such that (2.1) is still valid if one replaces pqλ byk. By (2.7) and (2.8), one has:

p

λ−ε + p

λp−λ+ε − pqε

(λ−ε)(λq−λ+ε) (2.9)

=ε Z

0

Z

0

f(x)e f(y)e

max{xλ, yλ}dxdy

< εk Z

0

tp−1−λfep(t)dt

1pZ

0

tq−1−λegq(t)dt 1q

=k.

Settingε→0+, then pλ +(p−1)λp ≤kor pqλ ≤k. By this contradiction we can conclude that the constant factor pqλ in (2.1) is the best possible.

Define the weight functiong(y)as:

g(y) =yλ(p−1)−1 Z

0

f(x)

max{xλ, yλ}dx p−1

, y ∈(0,∞).

By (2.1), one has:

0<

Z

0

yq−1−λgq(y)dy p

(2.10)

= Z

0

yλ(p−1)−1 Z

0

f(x) max{xλ, yλ}

p

dy p

= Z

0

Z

0

f(x)g(y)

max{xλ, yλ}dxdy p

≤pq λ

pZ

0

xp−1−λfp(x)dx Z

0

yq−1−λgq(y)dy p−1

,

0<

Z

0

yq−1−λgq(y)dy (2.11)

= Z

0

yλ(p−1)−1 Z

0

f(x) max{xλ, yλ}dx

p

dy

≤pq λ

pZ

0

xp−1−λfp(x)dx <∞.

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Hence by using (2.1), (2.10) takes the form of strict inequality; so does (2.11). One then has (2.2). On other hand, if (2.2) holds, by Hölder’s inequality, one has

Z

0

Z

0

f(x)g(y)

max{xλ, yλ}dxdy (2.12)

= Z

0

yλ+1−qq

Z

0

f(x)

max{xλ, yλ}dx h

yq−1−λq g(y)i dy

≤ Z

0

yλ(p−1)−1 Z

0

f(x) max{xλ, yλ}

p1p Z

0

yq−1−λgq(y)dy 1q

By (2.2), we have (2.1).

If the constant factor in(2.2) is not the best possible, we may show that the constant factor in (2.1) is not the best possible by using (2.12). This is a contradiction. Hence the constant factor in (2.2) is the best possible. Inequality (2.1) is equivalent to (2.2). Thus the theorem is

proved.

Remark 2.2. Forp=q = 2, (2.3) reduces to (1.5); (2.1), (2.3) are generalizations of (1.5), but (2.1) is not a generalization of (1.3).

Theorem 2.3. If p > 1, 1/p+ 1/q = 1, 0 < λ ≤ min{p, q}, an ≥ 0, bn ≥ 0 such that 0<

P

n=1

np−1−λapn<∞,0<

P

n=1

nq−1−λaqn<∞, one has:

(2.13)

X

n=1

X

m=1

ambn

max{mλ, nλ} < pq λ

X

n=1

np−1−λapn

!1p X

n=1

nq−1−λbqn

!1q

and (2.14)

X

n=1

nλ(p−1)−1

X

m=1

am max{mλ, nλ}

!p

<pq λ

p

X

n=1

np−1−λapn,

where the constant factors pqλ, pqλp

are the best possible. Inequality (2.13) is equivalent to (2.14).

In particular, forλ= 1,(2.13)and(2.14)respectively reduce to the following two equivalent inequalities:

(2.15)

X

n=1

X

m=1

ambn

max{m, n} < pq

X

n=1

np−2apn

!1p X

n=1

nq−2bqn

!1q

and (2.16)

X

n=1

np−2

X

m=1

am max{m, n}

!p

<(pq)p

X

n=1

np−2apn.

Proof. Define the weight coefficientweλ(λ, n)as:

(2.17) weλ(r, n) =nλ−1

X

m=1

1 max{mλ, nλ}

m n

λr−1

, r=p, q; n∈N.

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Since0< λ≤min{p, q}, we have:

weλ(r, n)< nλ−1

X

m=1

Z m

m−1

1 max{uλ, nλ}

u n

λr−1 du (2.18)

=nλ−1 Z

0

1 max{uλ, nλ}

u n

λr−1

du

=wλ(r, n) = pq

λ , r =p, q

By Hölder’s inequality and (2.17), following the method of proof in Theorem 2.1, one has:

X

n=1

X

m=1

ambn

max{mλ, nλ} <

X

n=1

weλ(q, n)np−1−λapn

!1p X

m=1

weλ(p, n)nq−1−λapn

!1q

By (2.18) we have (2.13), for0 < ε < λ, setting ean = nλ−p−εp , ebn = nλ−q−εq , n ∈ N. Since 0< λ≤min{p, q}, by (2.9), we get:

X

n=1

X

m=1

eamebn

max{mλ, nλ} >

Z

1

Z

1

f(x)e eg(y)

max{xλ, yλ}dxdy

= 1 ε

p

λ−ε + p

λp−λ+ε

− pq

(λ−ε)(λq−λ+ε). On other hand,

X

n=1

np−1−λeapn

!p1 X

m=1

nq−1−λebqn

!1q

=

X

n=1

1

n1+ε <1 + 1 ε.

By using the above inequalities and the method of proof in Theorem 2.1, we may show that the constant factor in (2.13) is the best possible.

Settingbnas:

bn=nλ(p−1)−1

X

m=1

am max{mλ, nλ}

!p−1

, we obtain:

X

n=1

nq−1−λbqn=

X

n=1

nλ(p−1)−1

X

m=1

am max{mλ, nλ}

!p

=

X

m=1

X

n=1

ambn max{mλ, nλ}.

By (2.13) and using the same method of Theorem 2.1, we have (2.14). We may show that the constant factor in (2.14)is the best possible, and inequality (2.13) is equivalent to (2.14).

REFERENCES

[1] G.H. HARDY, J.E. LITTLEWOODANDG. POLYA, Inequalities, Cambridge University Press Cam- bridge, 1952.

[2] D.S. MITRINOVI ´C, J.E. PE ˘CARI ´CAND A.M. FINK, Inequalities Involving Functions and Their Integrals and Derivatives, Kluwer Academic Publishers, Boston, 1991.

[3] J. KUANG AND L. DEBNATH, On new generalizations of Hilbert’s inequality and their applica- tions, Math. Anal. Appl., 245(1) (2000), 248–265.

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[4] B. YANG, On a generalization of Hardy Hilbert’s integral inequality with a best value, Chinese Ann.

of Math., A21(4) (2000), 401–408.

[5] B. YANG, On Hardy Hilbert’s integral inequality, J. Math. Anal. Appl., 261 (2001), 295–306.

[6] B. YANGANDL. DEBNATH, On a new strengthened Hardy-Hilbert’s inequality, Internat. J. Math.

Sci., 21(1) (1998), 403–408.

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