Vol. LXXXI, 2 (2012), pp. 171–183
COMPOSITION OPERATOR ON THE SPACE OF FUNCTIONS TRIEBEL-LIZORKIN AND BOUNDED VARIATION TYPE
M. MOUSSAI
Abstract. For a Borel-measurable functionf:R→Rsatisfyingf(0) = 0 and sup
t>0
t−1 Z
R
sup
|h|≤t
|f0(x+h)−f0(x)|pdx <+∞, (0< p <+∞), we study the composition operatorTf(g) :=f◦gon Triebel-Lizorkin spacesFp,qs (Rn) in the case 0< s <1 + (1/p).
1. Introduction and the main result
The study of the composition operator Tf: g → f ◦g associated to a Borel- measurable function f:R → R on Triebel-Lizorkin spaces Fp,qs (Rn), consists in finding a characterization of the functionsf such that
Tf(Fp,qs (Rn))⊆Fp,qs (Rn).
(1.1)
The investigation to establish (1.1) was improved by several works, for example the papers of Adams and Frazier [1, 2], Brezis and Mironescu [6], Maz’ya and Shaposnikova [9], Runst and Sickel [12] and [10]. There were obtained some necessary conditions onf; from which we recall the following results. Fors >0, 1< p <+∞and1≤q≤+∞
• if Tf takes L∞(Rn)∩Fp,qs (Rn)toFp,qs (Rn), thenf is locally Lipschitz con- tinuous.
• if Tf takes the Schwartz space S(Rn)toFp,qs (Rn), thenf belongs locally to Fp,qs (R).
The first assertion is proved in [3, Theorem 3.1]. The proof of the second assertion can be found in [12, Theorem 2, 5.3.1].
Bourdaud and Kateb [4] introduced the functions class Up1(R), the set of Lipschitz continuous functionsf such that their derivatives, in the sense of distri- butions, satisfy
Ap(f0) :=
sup
t>0
t−1 Z
R
sup
|h|≤t
|f0(x+h)−f0(x)|pdx1/p
<+∞, (1.2)
Received August 8, 2011; revised February 17, 2012.
2010Mathematics Subject Classification. Primary 46E35, 47H30.
Key words and phrases. Triebel-Lizorkin spaces; Besov spaces; functions of bounded variation;
composition operators.
and are endowed with the seminorm kfkU1
p(R):= inf(kgk∞+Ap(g)),
where the infimum is taken over all functionsg such thatf is a primitive ofg. In [4] the authors, proved the acting of the operatorTf on Besov spaceBsp,q(Rn) for 1≤p < +∞, 1 < s <1 + (1/p) andf ∈Up1(R) with f(0) = 0. In [5] the same result holds for 0< s <1 + (1/p).
In this work we will study the composition operatorTf onFp,qs (Rn) for a func- tionf which belongs to Up1(R), then we will obtain a result of type (1.1). To do this, we introduce the setVp(Rn) of the functionsg:Rn→Rsuch that
kgkVp(Rn):=
n
X
j=1
Z
Rn−1
kgx0jkpBV1
p(R)dx0j1/p
<+∞
where BVp1(R) is the Wiener space of the primitives of functions of bounded p-variation (see Subsection 2.2 below for the definition) and
gx0
j(y) :=g(x1, . . . , xj−1, y, xj+1, . . . , xn), y∈R, x∈Rn. (1.3)
We will prove the following statement.
Theorem 1.1. Let 0< p, q <+∞and 0< s <1 + (1/p). Then there exists a constantc >0such that the inequality
kf◦gkFs
p,q(Rn)≤ckfkU1 p(R)
kgkp+kgkVp(Rn)
(1.4)
holds for all functionsg∈Lp(Rn)∩ Vp(Rn)and allf ∈Up1(R)satisfyingf(0) = 0.
Moreover, for all suchf, the operator Tf takesLp(Rn)∩ Vp(Rn) toFp,qs (Rn).
Remark. (i) SinceFp,qs (Rn),→Lp(Rn), thenTf maps fromFp,qs (Rn)∩ Vp(Rn) toFp,qs (Rn) under the assumptions of Theorem 1.1.
(ii) Since the Bessel potential spacesHps(Rn) =Fp,2s (Rn), 1< p <∞, Theorem 1.1 covers the results of composition operators in caseHps(Rn) instead ofFp,qs (Rn).
The paper is organized as follows. In Section 2 we collect some properties of the needed function spacesFp,qs (Rn) andBVp1(R). Section 3 is devoted to the proof of the main result where in a first step we study the case of 1-dimensional which is the main tool when we prove Theorem 1.1. Also, our proof uses various Sobolev and Peetre embeddings, Fubini and Fatou properties, etc. In Section 4 we give some corollaries and prove the sharp estimate of (1.4).
Notation. We work with functions defined on the Euclidean space Rn. All spaces and functions are assumed to be real-valued. We denote by Cb(Rn) the Banach space of bounded continuous functions onRnendowed with the supremum.
Let D(Rn) (resp. S(Rn) and S0(Rn)) denotes the C∞-functions with compact support (resp. the Schwartz space of allC∞ rapidly decreasing functions and its topological dual). Withk · kp we denote theLp-norm. We define the differences by ∆hf := f(·+h)−f for all h ∈ Rn. If E is a Banach function space on Rn, we denote byE`oc the collection of all functionsf such thatϕf ∈E for all
ϕ∈ D(Rn). As usual, constantsc, c1, . . .are strictly positive and depend only on the fixed parametersn, s, p, q; their values may vary from line to line.
2. Function spaces 2.1. Triebel-Lizorkin spaces
Let 0< a≤ ∞. For all measurable functionsf onRn, we set Mp,qs,u,a(f) :=Z
Rn
Z a
0
t−sq1 tn
Z
|h|≤t
|∆hf(x)|udhq/udt t
p/q
dx1/p
.
Definition 2.1. Let 0< p <+∞and 0< q≤+∞. Letsbe a real satisfying 1< s <2 and s > nmax1
p−1,1 q−1
.
Then, a functionf ∈Lp(Rn) belongs toFp,qs (Rn) if kfkFs
p,q(Rn):=kfkp+
n
X
j=1
Mp,qs−1,1,∞(∂jf)<+∞.
The set Fp,qs (Rn) is a quasi Banach space for the quasi-norm defined above.
For the equivalence of the above definition with other characterizations we refer to [15, Theorem 3.5.3] from which we recall the following statement.
Proposition 2.2. Let 0 < p < +∞ and 0 < q, u ≤ +∞. Let s be a real satisfying
1< s <2 and s > nmax1 p−1
u,1 q− 1
u
. Then, a functionf ∈Lp(Rn)belongs toFp,qs (Rn)if and only if
kfkp+Mp,qs,u,∞(f)<+∞
(2.1)
and the expression (2.1) is an equivalent quasi-norm in Fp,qs (Rn). Moreover, this assertion remains true if one replacesMp,qs,u,∞ byMp,qs,u,a for any fixeda >0.
The argument of the equivalence of above quasi-norms that we can replace the integration fort∈]0,+∞[ byt≤afor a fixed positive numberais the part of the integral for whicht > acan be easily estimated by theLp-norm.
Embeddings. Triebel-Lizorkin spaces are spaces of equivalence classes w.r.t. al- most everywhere equality. However, if such an equivalence class contains a contin- uous representative, then usually we work with this representative and call also the equivalence class a continuous function. Later on we need the following continuous embeddings:
(i) The spacesFp,qs (Rn) are monotone with respect to s and q, more exactly Fp,∞s (Rn),→Fp,qt (Rn),→Fp,∞t (Rn) ift < s and 0< q≤ ∞.
(ii) With Besov spaces, we haveBsp,1(Rn),→Fp,qs (Rn),→Bp,∞s (Rn).
(iii) If eithers > n/por s=n/pand 0< p≤1, thenFp,qs (Rn),→Cb(Rn).
For various further embeddings we refer to [14, 2.3.2, 2.7.1] or [12, 2.2.2, 2.2.3].
The Fatou property. Well-known the Triebel-Lizorkin space has the Fatou prop- erty, cf. [8]. We will briefly recall it. Any f ∈Fp,qs (Rn) can be approximated (in the weak sense in S0(Rn)) by a sequence (fj)j≥0 such that any fj is an entire function of exponential type
fj ∈Fp,qs (Rn) and lim sup
j→+∞
kfjkFp,qs (Rn)≤ckfkFp,qs (Rn)
with a positive constantc independent of f. Vice versa, if for a tempered distri- butionf ∈ S0(Rn), there exists a sequence (fj)j≥0 such that
fj∈Fp,qs (Rn) and A:= lim sup
j→+∞
kfjkFp,qs (Rn)<+∞,
and limj→+∞fj=f in the sense of distributions, thenf belongs toFp,qs (Rn) and there exists a constantc >0 independent off such thatkfkFs
p,q(Rn)≤cA.
2.2. Functions of bounded variation
For a functiong:R→R, we set νp(g) := supXN
k=1
|g(bk)−g(ak)|p1/p , (2.2)
taken over all finite sets{]ak, bk[ ;k= 1, . . . , N}of pairwise disjoint open intervals.
A function g is said to be of bounded p-variation if νp(g) < +∞. Clearly, by considering a finite sequence with only two terms, we obtain|g(x)−g(y)| ≤νp(g), for allx, y∈R, henceg is a bounded function. The set of (generalized) primitives of functions of boundedp-variation is denoted by BVp1(R) and endowed with the seminorm
kfkBVp1(R):= inf νp(g),
where the infimum is taken over all functionsgwhosef is the primitive. For more details about this space we refer to [11] or [5]. However, we need to recall some embeddings
BVp1(R),→Up1(R) (2.3)
(equality in case p = 1), see [5, Theorem 5] for the proof which is given for 1< p <+∞and can be easily extended to 0< p≤1, see also [7, Theorem 9.3].
The Peetre embedding theorem
B˙1+(1/p)p,1 (R),→BVp1(R),→B˙1+(1/p)p,∞ (R), (1≤p <+∞), (2.4)
where the dotted space is thehomogeneousBesov space.
Example. Letα∈R. We putuα(x) :=|x+α| − |α|for allx∈R, and fα(x, y) :=uα(x)χ[0,1](y) +uα(y)χ[0,1](x), ∀x, y∈R,
whereχ[0,1] denotes the indicatrix function of [0,1]. Clearly thatνp(u0α) = 2 and kχ[0,1]kBV1
p(R)= 0. Then it holdsfα∈ Vp(R2) with kfαkVp(R2) = 4. TheVp(Rn) space is defined in Section 1.
3. Proof of the result Theorem 1.1 can be obtained from the following statement.
Proposition 3.1. Let 0 < p, q < +∞, 0 < u < min(p, q) and 0 < s < 1/p.
Then there exists a constantc >0 such that the inequality Mp,qs,u,∞((f◦g)0)≤ckfkU1
p(R)kgkBV1 p(R)
(3.1)
holds for allf ∈Up1(R)∩C1(R)and all real analytic functionsg in BVp1(R).
Proof. For a better readability we split our proof in two steps.
Step 1. Let us prove
Mp,qs,u,a((f◦g)0)≤c a(1/p)−skfkUp1(R)kgkBVp1(R)
(3.2)
for alla >0 and allf ∈Up1(R)∩C1(R) and all real analytic functionsginBVp1(R).
Assume firsta= 1. By the assumptions onf andgit holds (f◦g)0= (f0◦g)g0. We havek(f◦g)0k∞ ≤ kf0k∞kg0k∞ and
|∆h((f0◦g)g0)(x)| ≤ kf0k∞|∆hg0(x)| + |g0(x)| |∆h(f0◦g)(x)|.
Hence
Mp,qs,u,1((f◦g)0)≤ kf0k∞Mp,qs,u,1(g0) +V(f;g), where
V(f;g) :=Z
R
Z 1
0
t−sq1 t
Z t
−t
|∆h(f0◦g)(x)|u|g0(x)|udhq/udt t
p/q dx1/p (3.3) .
Estimate ofMp,qs,u,1(g0).By writingR1
0 · · ·=P∞ j=0
R2−j
2−j−1· · · and by an elementary computation, we have
Z 1
0
t−sq1 t
Z t
−t
|∆hg0(x)|udhq/udt t ≤c1
∞
X
j=0
Z 2−j
2−j−1
t−sq sup
|h|≤t
|∆hg0(x)|q dt t
≤c2
∞
X
j=0
2jsq sup
|h|≤2−j
|∆hg0(x)|q.
Letα:= min(1, p/q). By using the monotonicity of the`r-norms (i.e. `1,→`1/α) and by the Minkowski inequality w.r.tLp/(αq), sinceq <+∞, we obtain
Mp,qs,u,1(g0)≤c1
Z
R
X∞
j=0
2jsαq sup
|h|≤2−j
|∆hg0(x)|αqp/(αq)
dx1/p
≤c2
X∞
j=0
2jsαqZ
R
sup
|h|≤2−j
|∆hg0(x)|pdx(αq)/p1/(αq)
≤c3
X∞
j=0
2j(s−(1/p))αq1/(αq) kgkU1
p(R).
From the embedding (2.3) and the assumption ons, the desired estimate holds.
Estimate of V(f;g). In (3.3) the integral with respect to hcan be limited to the interval [0, t] denoting the corresponding expression by V+(f;g). Let us notice that the estimate with respect to [−t,0] will be completely similar.
Again, by applying the Minkowski inequality twice, it holds V+(f;g)
≤ Z
R
Z 1
0
Z 1
h
t−(s+(1/u))q|∆h(f0◦g)(x)|q|g0(x)|q dt t
u/q dh
p/u dx
1/p
≤ Z 1
0
Z
R
|∆h(f0◦g)(x)|p|g0(x)|pdx
u/p Z ∞
h
t−(s+(1/u))q dt t
u/q dh
1/u
≤c Z 1
0
h−(su+1) Z
R
|∆h(f0◦g)(x)|p|g0(x)|pdx u/p
dh 1/u
.
Case 1: Assume thatg0 does not vanish on R. By the Mean Value Theorem and by the change of variabley=g(x), we find
V+(f;g)
≤c1kg0k1−(1/p)∞ Z 1 0
h−(su+1)Z
R
sup
|v|≤hkg0k∞
|f0(v+y)−f0(y)|pdyu/p
dh1/u
≤c2kfkU1
p(R)kg0k∞Z 1 0
hu((1/p)−s)−1dh1/u
≤c3kfkU1
p(R)kgkBV1 p(R).
Case 2: Assume that the set of zeros of g0 is nonempty. Then it is a discrete set whose complement in R is the union of a family (Il)l of open disjoint intervals.
For anyh >0, we denote byIl,h0 the set ofx∈Il whose distance to the boundary ofIl is greater thanh. We set
Il,h00 :=Il\Il,h0 and gl:=g|Il.
Clearly the functionglis a diffeomorphism ofIl ontog(Il). Let us notice thatIl,h0 is an open interval, possibly empty. In case it is not empty, we have
|g(gl−1(y) +h)−y| ≤hsup
Il
|g0|, ∀y∈gl(Il,h0 ).
(3.4)
The setIl,h00 is an interval of length at most 2hor the union of two such intervals, andg0 vanishes at one of the endpoints of these or those intervals.
We writeV+(f;g)≤V1(f;g) +V2(f;g), where V1(f;g) :=
Z 1
0
h−(su+1)
X
l
Z
Il,h0
|∆h(f0◦g)(x)|p|g0(x)|pdx u/p
dh 1/u
andV2(f;g) is defined in the same way by replacingIl,h0 byIl,h00 .
Estimate ofV1(f;g). By the change of variabley=gl(x) and by (3.4), we deduce V1(f;g)≤
Z 1
0
h−(su+1)
X
l
sup
Il
|g0|p−1
× Z
g(Il,h0 )
sup
|v|≤hsupIl|g0|
|f0(v+y)−f0(y)|pdy u/p
dh 1/u
≤c1kfkU1 p(R)
X
l
sup
Il
|g0|p
1/p Z 1
0
hu((1/p)−s)−1dh 1/u
≤c2kfkUp1(R)
X
l
sup
Il
|g0|p 1/p
. Hence it suffices to show
X
l
sup
t∈Il
|g0(t)|p1/p
≤ ckgkBV1 p. (3.5)
Indeed, by the assumption ong, for any Il there existsξl∈Il such that
|g0(ξl)| = sup
t∈Il
|g0(t)|.
Furthermore, set βl the right endpoint of Il. The open intervals {]ξl, βl[}l are pairwise disjoint. Then the assertion (3.5) follows from
X
l
sup
t∈Il
|g0(t)|p=X
l
|g0(ξl)−g0(βl)|p≤νp(g0)p. (See (2.2) for the definition ofνp).
Estimate of V2(f;g). Using both the elementary inequality |∆h(f0 ◦ g)(x)| ≤ 2kf0k∞ and the properties ofIl,h00 , it holds
V2(f;g)≤c1kf0k∞
X
l
sup
Il
|g0|p
1/p Z 1
0
hu((1/p)−s)−1dh 1/u
≤c2kfkU1
p(R)kgkBV1 p(R).
Hence we obtain (3.2) witha= 1. We put gλ(x) := g(λx) for all x∈R and all λ >0. Then (3.2) can be obtained for alla >0 since kgakBV1
p(R) =akgkBV1 p(R)
and
Mp,qs,u,a((f ◦g)0) =a(1/p)−s−1Mp,qs,u,1((f◦ga)0).
Step 2: Proof of (3.1). Let a > 0. Let f and g be as in Proposition 3.1. By Proposition 2.2 it holds
Mp,qs,u,∞((f◦g)0)≤ k(f ◦g)0kFs
p,q(R)=k(f◦g)0kp+Mp,qs,u,a((f◦g)0).
Applying (3.2), we obtain
Mp,qs,u,∞((f◦g)0)≤ kf0k∞kg0kp+c1a(1/p)−skfkU1
p(R)kgkBV1 p(R)
(3.6)
with a positive constantc1 depending only ons, p andq (see the end of Step 1).
Now, by replacing g by gλ in (3.6), (gλ is defined in Step 1), and by using the equality
Mp,qs,u,∞ (f ◦gλ)0
=λs+1−(1/p)Mp,qs,u,∞((f◦g)0), we deduce
Mp,qs,u,∞((f◦g)0)
≤λ−skf0k∞kg0kp+c1a(1/p)−sλ(1/p)−skfkU1
p(R)kgkBV1 p(R)
(3.7)
for alla, λ > 0. Taking a= 1/λ. Now letting λ→ +∞ in (3.7), we obtain the
desired result.
Remark. Proposition 3.1 is also valid in then-dimensional case. The inequality (3.1) becomes
Mp,qs−1,u,∞(∂j(f ◦g))≤ckfkUp1(R)kgkVp(Rn), (j= 1, . . . , n) for allf ∈Up1(R)∩C1(R) and all real analytic functionsg inVp(Rn).
Proof of Theorem1.1. Step 1. Observe that the conditions f(0) = 0 andf0 ∈ L∞(R) imply
kf ◦gkp ≤ kf0k∞kgkp
which is sufficient for the estimateTf(g) with respect toLp(Rn)-norm.
Step 2: The case 1 < s < 1 + (1/p) and n = 1. We first consider a function f ∈ Up1(R), of class C1 and a function g real analytic in Lp(R)∩BVp1(R). By Proposition 3.1, it holds
kf◦gkFs
p,q(R)≤ckfkU1 p(R)
kgkp+kgkBV1 p(R)
. (3.8)
Now we prove (3.8) in the general case. Letg∈Lp(R)∩BVp1(R) andf ∈Up1(R).
We introduce a function ρ ∈ D(R) satisfying ρ(0) = 1, and we set ϕj(x) :=
2jnF−1ρ(2jx) for allx∈Rand allj ∈N; hereF−1ρdenotes the inverse Fourier transform ofρ. We set also
fj :=ϕj∗f−ϕj∗f(0) and gj :=ϕj∗g.
Then the functiongj is real analytic andgj→g inLp(R). We have also kgjkBV1
p(R)≤ckgkBV1
p(R), ∀j∈N. (3.9)
To prove (3.9), let{]ak, bk[, k = 1, . . . , N} be a set of pairwise disjoint intervals.
By the Minkowski inequality, it holds XN
k=1
Z
R
ϕj(y)
g0(bk−y)−g0(ak−y) dy
p1/p
≤ Z
R
|ϕj(y)|XN
k=1
g0(bk−y)−g0(ak−y)
p1/p dy.
Now, for ally∈R, the intervals ]ak−y, bk−y[ (k= 1, . . . , N) are pairwise disjoint.
Then
XN
k=1
|g0j(bk)−g0j(ak)|p1/p
≤ kF−1ρk1νp(g0), ∀j∈N. Hence we obtain (3.9).
The functionsfj areC∞ such thatfj(0) = 0 and satisfy kfjkU1
p(R)≤ckfkU1
p(R), ∀j ∈N. (3.10)
To prove (3.10), for allt >0 and all h∈[−t, t] we trivially have
|ϕj∗f0(x+h)−ϕj∗f0(x)| ≤ Z
R
|ϕj(y)|sup
|z|≤t
|f0(x−y+z)−f0(x−y)|dy.
By the Minkowski inequality, we have Z
R
sup
|h|≤t
|ϕj∗f0(x+h)−ϕj∗f0(x)|pdx
≤Z
R
|ϕj(y)|Z
R
sup
|z|≤t
|f0(x−y+z)−f0(x−y)|pdx1/p
dyp
≤tkF−1ρkp1Ap(f0)p, (see (1.2) for the definition ofAp).
Consequently,
Ap(fj0) +kfj0k∞≤ kF−1ρk1(Ap(f0) +kf0k∞) and we obtain the desired result.
On the other hand, we have
j→+∞lim kfj−fk∞= 0.
(3.11)
To prove (3.11), since limj→+∞ϕj∗f(0) =f(0) = 0, the Lipschitz continuous of f yields
|fj(x)−f(x)| ≤ kf0k∞
Z
R
|x−y||ϕj(x−y)|dy +|ϕj∗f(0)|
≤c2−jkf0k∞ +|ϕj∗f(0)|.
Then the desired result holds. By the same argument, we obtain kgj−gk∞≤c2−jkg0k∞.
(3.12)
Now we apply (3.8) tofj andgj. Then by (3.9) and (3.10), we obtain kfj◦gjkFs
p,q(R)≤ckfkU1 p(R)
kgkp+ kgkBV1 p(R)
. (3.13)
The elementary inequality
kf◦g−fj◦gjk∞≤ kf0k∞kg−gjk∞+kf−fjk∞
complemented by (3.11)–(3.12) yields the convergence of the sequence{fj◦gj}j∈N tof◦g inL∞(R). Since
|hfj◦gj−f◦g, ψi| ≤ kfj◦gj−f◦gk∞kψk1, ∀ψ∈ D(R),
thus we conclude that limj→+∞fj◦gj =f◦gin the sense of distributions. Hence, by the Fatou property ofFp,qs (R), see Subsection 2.1, we deduce (3.8).
Step 3: The case1< s <1 + (1/p)andn≥2. We use the notation (1.3). Since Triebel-Lizorkin space has the Fubini property (see [12, p. 70]), by (3.1) it holds
kf◦gkFs
p,q(Rn)≤c1 n
X
j=1
Z
Rn−1
kf◦gx0
jkpFs
p,q(R)dx0j1/p
≤c2kfkU1 p(R)
n
X
j=1
Z
Rn−1
kgx0
jkpp+kgx0
jkpBV1 p(R)
dx0j1/p
≤c3kfkU1 p(R)
kgkp+kgkVp(Rn)
.
Step 4: The case 0 < s ≤1. Due to the monotonicity of the Triebel-Lizorkin scale with respect to the smoothness parameter s, the result holds. Indeed, let 1 < t < 1 + (1/p). From Step 3, we have (1.4) with kf ◦gkFt
p,q(Rn) instead of kf ◦gkFs
p,q(Rn). Now we apply the continuous embedding Fp,qt (Rn),→ Fp,qs (Rn).
This completes the proof.
Remark. In case n= 1 and 1≤p, q <+∞the inequality (1.4) becomes kf◦gkFs
p,q(R)≤ckfkU1 p(R)
kgkFs
p,q(R)+kgkBV1 p(R)
for allg ∈Lp(R)∩BVp1(R), since Fp,qs (R)∩BVp1(R) = Lp(R)∩BVp1(R) if s <
1 + (1/p). To prove this equality, we have ˙Bp,∞1+(1/p)(R)∩Lp(R) = B1+(1/p)p,∞ (R) (see [12, 2.6.2, p. 95]). Then by (2.4) and by bothB1+(1/p)p,∞ (R) ,→Bp,1s (R) and Bp,1s (Rn),→Fp,qs (Rn), it holdsLp(R)∩BVp1(R),→Fp,qs (R).
4. Concluding remarks 4.1. Some corollaries
In this section we fix a smooth cut-off functionϕ∈ D(R) such thatϕ(x) = 1 for
|x| ≤ 1. We putϕt(x) :=ϕ t−1x
, ∀x∈Rand for all t >0. Also for brevity we introduce the spaceFp,qs (Rn) :=Fp,qs (Rn)∩L∞(Rn) endowed with the quasi-norm
kfkFs
p,q(Rn):=kfkFs
p,q(Rn)+kfk∞.
Theorem 1.1 has a consequence for the case of functionsf which are only locally inUp1(R).
Corollary 4.1. Lets, p, q be real numbers as in Theorem1.1. Then there exists a constantc >0such that the inequality
kf◦gkFs
p,q(Rn)≤ckf ϕkgk∞kU1 p(R)
kgkFs
p,q(Rn)+kgkVp(Rn)
(4.1)
holds for all functions g ∈ Fp,qs (Rn)∩ Vp(Rn) and all f ∈ Up1,`oc(R) satisfying f(0) = 0. Moreover, for all such functions f, the composition operator Tf takes Fp,qs (Rn)∩ Vp(Rn)toFp,qs (Rn).
Proof. Since f ◦g = (f ϕkgk∞)◦g and (f ϕt)(0) = 0, the result follows from
Theorem 1.1.
There is consequence of Theorem 1.1 that we can obtain the equivalence of acting condition and boundedness.
Corollary 4.2. Lets, p, q be real numbers as in Theorem1.1. Letf be a func- tion inUp1,`oc(R)satisfyingf(0) = 0. Then the following assertions are equivalent:
(i) Tf satisfies the acting conditionTf(Fp,qs (Rn)∩ Vp(Rn))⊆ Fp,qs (Rn).
(ii) Tf maps bounded sets inFp,qs (Rn)∩ Vp(Rn)into bounded sets inFp,qs (Rn).
Proof. Lett >0. By (4.1), it holds
kf◦gkFp,qs (Rn)≤c tkf ϕtkUp1(R)
(4.2)
for all g ∈ Fp,qs (Rn)∩ Vp(Rn) such that kgkFs
p,q(Rn)+kgkVp(Rn) ≤t. Now, from (4.2), we conclude thatTf maps bounded sets inFp,qs (Rn)∩ Vp(Rn) into bounded
sets inFp,qs (Rn).
Remark. Ifn/p < s <1 + (1/p), then we can replaceFp,qs (Rn) byFp,qs (Rn) in Corollaries 4.1–4.2, sinceFp,qs (Rn),→Cb(Rn).
We show that Theorem 1.1 can be extended to the case of the boundedness between Besov spaces and Triebel-Lizorkin spaces.
Corollary 4.3. Let 1≤p, q <+∞and0< s <1 + (1/p). Then there exists a constantc >0such that the inequality
kf◦gkFp,qs (Rn)≤ckfkUp1(R)kgkB1+(1/p) p,1 (Rn)
holds for all functions g ∈ Bp,11+(1/p)(Rn) and all f ∈Up1(R) satisfying f(0) = 0.
Moreover, for all such functionsf, the operatorTf takesBp,11+(1/p)(Rn)toFp,qs (Rn).
Proof. This is an easy consequence of Theorem 1.1 and the following continuous embedding
Bp,11+(1/p)(Rn),→ Vp(Rn).
(4.3)
To prove (4.3), we use the notation (1.3) and the equivalent norm in Besov space given by
kfkp +
n
X
j=1
Z 1
0
t−sqk∆2te
jfkqp dt t
1/q
, (0< s <2), where{e1, . . . , en} denotes the canonical basis ofRn, see [15, p. 96].
Letf ∈Bp,11+(1/p)(Rn). Since ˙Bp,11+(1/p)(R)∩Lp(R) =Bp,11+(1/p)(R) (in the sense of equivalent norms, see, e.g. [15]), then by (2.4), we get
kfkVp(Rn)≤c
n
X
j=1
Z
Rn−1
kfx0jkp
B1+(1/p)p,1 (R)dx0j 1/p
.
Using the Minkowski inequality with respect toLp(Rn−1), it follows Z
Rn−1
Z 1
0
t−(1+(1/p))k∆2tekfx0
jkp
dt t
p
dx0j≤ Z 1
0
t−(1+(1/p))k∆2tekfkp
dt t
p
forj, k∈ {1, . . . , n}. Then we obtain the desired result.
Remark. As in Corollary 4.1 we can see the case when the functionfassociated to the composition operatorTf belongs locally toUp1(R). Indeed, if 1≤p, q <+∞
and 0< s <1 + (1/p), it holds that kf◦gkFs
p,q(Rn)≤ckf ϕkgk∞kU1
p(R)kgkB1+(1/p) p,1 (Rn)
for allf ∈Up1,`oc(R) such thatf(0) = 0 and all g∈Bp,11+(1/p)(Rn)∩L∞(Rn).
4.2. Sharpness of estimate For simplicity we define
kgk:=kgkFs
p,q(Rn)+kgkVp(Rn).
According to Corollary 4.1, there is a substantial class ofnonlinearfunctionsf for which there exist constantscf =c(f)>0 such that
kf ◦gkFs
p,q(Rn)≤cfkgk, ∀g∈Fp,qs (Rn)∩ Vp(Rn).
In this form the inequality isoptimalif we avoid linearfunctions in the following sense.
Proposition 4.4. LetΩ : [0,+∞)→[0,+∞)be a continuous function satisfy- ing
t→+∞lim t1/pΩ(t) = 0.
(4.4)
Iff is a function such that the inequality
kf ◦gkFp,qs (Rn) ≤ Ω(kgk) (4.5)
holds for all g ∈ Fp,qs (Rn)∩ Vp(Rn), then f is an affine function (linear, if we assume thatf(0) = 0).
Proof. Let us define a smooth function ϕ∈ D(Rn) such thatϕ(x) = 1 on the cubeQ:= [−1,1]n andϕ(x) = 0 ifx /∈2Q. We put ∆2h:= ∆h◦∆hand
ga(x) :=ax1ϕ(x), (x= (x1, x0)∈R×Rn−1, a >0).
We havekgak ∼aand
∆2h(f◦ga)(x) = ∆2ah1f(ax1), (∀x∈ 2(√1n)Q, ∀h∈ 4(√1n)Q, ∀a >0).
On the other hand, for allh∈ 4(√1n)Q(i.e. |h| ≤1/4), we have k∆2h(f ◦ga)kp≥Z
x∈(1/(2√ n))Q
|∆2h(f◦ga)(x)|pdx1/p
≥c a−1/pZ a/(2√ n)
−a/(2√ n)
|∆2ah1f(y)|pdy1/p .
By the above inequality, the embeddingFp,qs (Rn),→Bp,∞s (Rn) and the assumption (4.5), we obtain
Z a/(2√ n)
−a/(2√ n)
|∆2ah1f(y)|pdy1/p
≤c1|h|sa1/pΩ(kgak)
≤c2a1/pΩ(kgak), (∀h:|h| ≤1/4).
By settingu:=ah1, we deduce that Z a/(2√
n)
−a/(2√ n)
|∆2uf(y)|pdy1/p
≤c1a1/pΩ(c2a), ∀a >0, ∀u:|u| ≤a.
By applying the assumption (4.4) on Ω and takingato +∞, we obtain Z +∞
−∞
|f(y+ 2u)−2f(y+u) +f(y)|pdy= 0, ∀u∈R. Hencef(y+ 2u)−2f(y+u) +f(y) = 0 a.e.,∀y, u∈R. Then
f0(y+ 2u)−f0(y+u) = 0, i.e.,
it impliesf0(u) =f0(0) (∀u∈R). We deduce thatf0 is a constant.
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M. Moussai, Department of Mathematics, University of M’Sila, P.O. Box 166, 28000 M’Sila, Algeria,e-mail:[email protected]