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Sets of determination for parabolic functions on a half-space

Jarmila Ranoˇsov´a

Abstract. We characterize all subsetsM ofRn×R+such that sup

XRn×R+

u(X) = sup

X∈M

u(X)

for every bounded parabolic function u on Rn×R+. The closely related problem of representing functions as sums of Weierstrass kernels corresponding to points ofMis also considered. The results provide a parabolic counterpart to results for classical harmonic functions in a ball, see References. As a by-product the question of representability of probability continuous distributions as sums of multiples of normal distributions is investigated.

Keywords: heat equation, parabolic function, Weierstrass kernel, set of determination, decomposition ofL1(Rn), normal distribution

Classification: 35K05, 35K15, 31B10, 60Exx

1. Preliminaries

In this paper the following notation is used: Small letters, such as x, y, will denote points in Rn; capital letters, such as X, points in Rn+1, and t denotes

“time”. (We will writeX = (x, t) for x∈Rn and t ∈R.) The setRn× {0} is identified withRn, and, when there is no danger of confusion, the point

(y,0)∈Rn× {0} is denoted byy. The Lebesgue measure inRn will be denoted byλ.

Further notation is either standard or introduced when it is used.

Definition. A real function u on an open set G ⊂ Rn+1 having continuous partial derivatives ∂u∂t and ∂x2u2

i

fori= 1, ..., n, and satisfying the heat equation

∂u

∂t = Xn i=1

2u

∂x2i

onGis called parabolic on G.

We will be interested in parabolic functions onRn×R+.

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The Weierstrass kernel forRn×R+with the pole in y inRnis given by p(X, y) = (4πt)n/2exp(−kx−yk2

4t ), whereX = (x, t)∈Rn×R+.

A parabolic function which is the limit of an increasing sequence of bounded positive parabolic functions will be called quasi-bounded. The class of all functions uwhich can be expressed as a difference of two positive quasi-bounded parabolic functions will be denoted byP1.

Moreover, a parabolic functionuwill be called simple if there exists a λ-measurable subset A of Rn× {0} such that u(X) = R

A

p(X, y)dy for any X ∈Rn×R+.

The class of all simple parabolic functions will be denoted by Ps. Of course, Ps⊂ P1.

Theorem A. A function u on Rn×R+ is a difference of two positive quasi- bounded parabolic functions if and only if there is a λ-measurable function fu onRn for which Z

Rn

exp(−kyk2

4t )|fu(y)|dy <∞ for allt >0and

u(X) = Z

Rn

p(X, y)fu(y)dy, X∈Rn×R+;

uis positive, if and only iffuis positiveλ-almost everywhere.

It is clear that the functionfuis uniquely determinedλ-almost everywhere. In what follows, for anyu∈ P1,fu will denote this function.

Proof: See [5, p. 291].

Definition. A pointY = (y,0) is called a parabolic limit (resp. a1-parabolic limit)of a sequence{Xk},Xk= (xk, tk), of points inRn×R+, if{Xk}converges toY andlim infk→∞tkkxk−yk2>0 (that is, allXkbelong to some paraboloid of revolution with vertexY and opening upward)

(resp.lim infk→∞tkkxk−yk2≥1).

Let M ⊂Rn×R+. A point Y ∈ Rn× {0} is called a parabolic limit point (resp. a1-parabolic limit point)of the setM if there exists a sequence{Xk}such that everyXk∈M andY is a parabolic limit(resp. a1-parabolic limit)of{Xk}. A functionf onRn×R+ is said to have a parabolic limit qat Y if {f(Xk)} converges toqwheneverY is a parabolic limit of{Xk}.

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Theorem B (The Fatou limit theorem). Letu be a parabolic function in P1. Then for λ-almost all y ∈ Rn the function u has the parabolic limit fu(y) at Y = (y,0).

Proof: See [5, p. 292].

Lemma 1. A parabolic functionuonRn×R+is bounded if and only if there is a functionfu∈L(Rn)such that

u(X) = Z

Rn

p(X, y)fu(y)dy, X∈Rn×R+.

If it is the case, then sup

X∈Rn×R+

u(X) = ess sup

y∈Rn fu(y) and sup

X∈Rn×R+|u(X)| = kfukL(Rn).

Proof: Since uis a bounded parabolic function, it belongs to P1. From Theo- rem A it follows that there is aλ-measurable functionfu such that

u(X) = Z

Rn

p(X, y)fu(y)dy, X∈Rn×R+.

As for the constant function u = c we have fu = c (λ-almost everywhere), by Theorem A it follows thatc−u≥0 if and only ifc−fu≥0λ-almost everywhere.

Consequently, sup

X∈Rn×R+

u(X) = ess sup

y∈Rn

fu(y). The rest is trivial.

The class of all bounded parabolic functions onRn×R+will be denoted byPb. Of course,Ps⊂ Pb ⊂ P1.

Lemma 2. LetM ⊂Rn×R+. Then the set of all parabolic limit points ofM isλ-measurable.

Proof: The pointY = (y,0) is a parabolic limit point ofM if and only if lim sup

t00+ sup

{x;(x,t0)M}

t0

kx−yk2 >0.

It follows from the definition of parabolic limits points. Remark that sup∅=−∞, as usual.

LetM0 be a countable dense subset of M. The point Y is a parabolic limit point ofM if and only ifY is a parabolic limit point ofM0. That is why we can assume thatM is a countable set.

Fort∈R+,x∈Rn andy∈Rn, define g(t, x, y) = t

kx−yk2, ifx6=y,

=∞, ifx=y.

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It is easy to see that the functiongis a continuous function fromR+×Rn×Rn into (0,∞]. Fixxand t. The function g(t, x, .) is measurable (even continuous) fromRninto (0,∞].

For fixedt, let us put

gt(y) = sup

{x;(x,t)M}

t kx−yk2.

Let us recall that M is countable. Then gt, being a supremum of a countable system of measurable functions, is measurable.

BecauseM is countable, only for countably manyt the functiongtis strictly positive. Let us denote this set oftbyT.

So,Y is a parabolic limit point ofM if and only if lim sup

t0,tT gt(y)>0.

But theng, being a limes superior of a countable system of measurable func- tions, is measurable.

Thus the set of all parabolic limit points, which is{g >0}, is measurable.

2. Sets of determination Theorem 1. LetM ⊂Rn×R+.

If

sup

X∈Rn×R+

u(X) = sup

XM

u(X)

for all bounded positive parabolic functions, thenλ-almost every point y∈Rn× {0}is a parabolic limit point ofM.

Proof: Suppose it is not true.

The set of all parabolic limit points of M will be denoted by Mp. We know from the preceding lemma that the setMp is measurable. Then its complement Mp is also measurable and by our assumptionλ(Mp)>0.

Fork∈Nandy∈Rn× {0}, Γky will denote the set {(x, t)∈Rn×R+; 1/k > t >kx−yk2}.

Then, for everyy∈Mp, there isky ∈Nsuch that Γkyy∩M is empty. Denote by Dk the set ofy∈Mp for which Γky∩M is empty.

We will prove now that, for anyk, the setDkis a measurable subset ofRn×{0}. By definition

Dk=Mp∩ {y∈Rn× {0}; M∩Γky =∅}. We know thatMp is measurable. Thus it remains to prove that {y∈Rn× {0}; M∩Γky =∅}is measurable.

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ButM∩Γky=∅ if and only if for anyt∈(0,1/k):

sup

{x; (x,t)M}

t

kx−yk2 ≤1.

LetM0 be a countable dense subset of M. The point Y is a parabolic limit point ofM if and only ifY is a parabolic limit point ofM0. That is why we can assume thatM is a countable set. Let us fixt. Then

y7−→ sup

{x; (x,t)M}

t kx−yk2

is a measurable function and

{y∈Rn; sup

{x; (x,t)M}

t

kx−yk2 ≤1} is a measurable set.

This set can be different fromRn only fortsuch that there isX = (x, t)∈M. Let us denote this set byT. So, the intersection

\

0<t<1/k

{y∈Rn; sup

{x; (x,t)M}

t

kx−yk2 ≤1} is equal to

\

0<t<1/k tT

{y∈Rn; sup

{x; (x,t)M}

t

kx−yk2 ≤1},

and, as an intersection of countable system of measurable sets, it is measurable.

It means thatDkis measurable.

As S

k=1Dk = Mp, the Lebesgue measure of at least one of the sets Dk is strictly positive. Let it be the set Da where a ∈ N. Then there is a bounded subset ofDawhich has strictly positive Lebesgue measure. Denote this set byD.

For a pointX = (x, t) ofRn×R+ we define

AX ={(y,0)∈Rn× {0}; kx−yk2< t}. (AX is the ball inRn× {0}with the center (x,0) and radiust1/2.) DenoteD= (Rn× {0})\D.

LetX= (x, t)∈M∩(Rn×(0,1/a)) and lety∈AX. Then 1/a > t >kx−yk2, so thatX ∈Γay. Consequently,y /∈Da, and soy /∈D. We conclude thatAX ⊂D, wheneverX∈M ∩(Rn×(0,1/a)).

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For any measurable setA⊂Rn× {0}we define uA(X) =

Z

A

p(X, y)dy, X∈Rn×R+.

It means uA ∈ Ps, thus uA ∈ Pb and −uA ∈ Pb. By Lemma 1 we get uA is positive, and ifλ(A)>0, then sup

Rn×R+

uA(X) = 1.

Denote the Lebesgue measure of the unit ball in Rn by αn. Then for any X ∈Rn×R+:

uAX(X) = Z

AX

p(X, y)dy= (4πt)n/2 Z

AX

exp(−kx−yk2 4t )dy

≥(4πt)n/2 Z

AX

exp(−t

4t)dy= (4πt)n/2λ(AX) exp(−1/4)

= (4π)n/2αnexp(−1/4).

We see that

c= inf

X∈Rn×R+uAX(X)>0.

The setDhas a positive measure, hence the functionuD is positive, parabolic, bounded and

sup

X∈Rn×R+

uD(X) = 1.

SinceuD+uD= 1, we get for everyN ⊂Rn×R+ the equality sup

XN

uD(X) = 1− inf

XNuD(X).

ButAX is a subset ofD for everyX ∈M ∩(Rn×(0,1/a)).

It follows that

uD(X)≥uAX(X)≥c for everyX ∈M∩(Rn×(0,1/a)).

Then

sup

XM(Rn×(0,1/a))

uD(X)≤1−c.

Now sup

XM(Rn×[1/a,))

uD(X) will be estimated. AsD is bounded, there is

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d∈R+such thatD⊂[−d, d]n and so we have for any (x, t)∈Rn×[1/a,∞) uD(x, t) = (4πt)n/2

Z

D

exp(−kx−yk2 4t )dy

≤(4πt)n/2 Z

[d,d]n

exp(−kx−yk2

4t )dy≤(4πt)n/2 Z

[d,d]n

exp(−kx−yk2 4t )dy

≤(4πt)n/2 Z

[d,d]n

exp(−kyk2

4t )dy=πn/2

Z

[d/(2 t),d/(2

t)]n

exp(−kyk2)dy

≤πn/2

Z

[da/2,da/2]n

exp(−kyk2)dy <1.

Thus

sup

XM(Rn×[1/a,))

uD(X)<1.

Consequently, sup

XM

uD(X)≤max (1−c, sup

XM(Rn×[1/a,))

uD(X))<1,

contradicting our assumption.

In fact, we proved a bit more than the assertion of Theorem 1. Namely we proved

Theorem 1’. LetM ⊂Rn×R+. If

sup

X∈Rn×R+

u(X) = sup

XM

u(X)

for all simple parabolic functions, then λ-almost every point y ∈ Rn× {0} is a1-parabolic limit point ofM.

Theorem 2. LetM be a subset ofRn×R+and letλ-almost every point (y,0)∈Rn× {0} be a parabolic limit point ofM. Then

sup

XRn×R+|u(X)|= sup

XM|u(X)| for every bounded parabolic functionuonRn×R+.

Proof: Letube a bounded parabolic function onRn×R+. By Lemma 1, there existsf ∈L(Rn) such that

u(X) = Z

Rn

p(X, y)f(y)dy, X∈Rn×R+

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and

sup

X∈Rn×R+|u(X)|=kfkL. It is clear that

sup

XM|u(X)| ≤ sup

X∈Rn×R+|u(X)|=kfkL.

By the hypothesis, λ-almost every point of Rn× {0} is a parabolic limit point ofM. From the Fatou limit theorem, forλ-almost everyy∈Rn,

limu(Xk) =f(y), wheneveryis a parabolic limit of {Xk}. Thus

sup

XM|u(X)| ≥ kfkL, so that

sup

X∈Rn×R+|u(X)|= sup

XM|u(X)|.

3. A decomposition theorem forL1(Rn)

Let us introduce the following notation: The closure ofM ⊂Rn×R+ in the setRn×R+ (which is the setM∩(Rn×R+)) will be denoted byMf.

The support of a measureνonRn×R+with respect toRn×R+(it means the complement inRn×R+of the largest open setG⊂Rn×R+such thatν(G) = 0) will be denoted bys(ν).

Theorem 3. Let M be a subset of Rn×R+ and ν be a σ-finite measure on Rn×R+ such thats(ν) =Mf. Let

sup

X∈Rn×R+|u(X)|= sup

XM|u(X)| for every bounded parabolic functionuonRn×R+.

Then, for anyf inL1(Rn), there existsΦinL1(ν)such that

(1) f =

Z

Rn×R+

Φ(X)p(X, .)dν(X)

λ-almost everywhere and

kfkL1(Rn)= inf {kΦkL1); (1)holds for someΦ∈L1(ν)}.

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Further, there exists a sequence{Xk},Xk∈M and{λk} ∈l1 such that

(2) f =

X k=1

λkp(Xk, .)

λ-almost everywhere and kfkL1(Rn)= inf {X

k|; (2)holds for some{Xk}inM}.

The second part is an easy consequence of the first one. Just take a dense countable subset ofM, denote it{Xk}, and takeν the counting measure on it.

We will need the following version of the closed range theorem (see [7, p. 97]).

LetX andY be Banach spaces,T a bounded linear mapping ofX intoY. If there exists a constant c >0 such that kTyk ≥ckyk for all y∈ Y thenTX =Y. In our situation,X =L1(ν),Y=L1(Rn) and for Φ∈L1(ν) we define

TνΦ = Z

Rn×R+

p(X, .)Φ(X)dν(X).

Lemma 3. The mappingTν is a bounded linear mapping ofL1(ν)intoL1(Rn), kTνk= 1;Tν is the parabolic extension mappingL(Rn)intoL(ν).

Proof: Using the Fubini theorem we arrive at kTνΦkL1(Rn)=

Z

Rn

|TνΦ|dλ= Z

Rn

| Z

Rn×R+

p(X, y)Φ(X)dν(X)|dλ(y)

≤ Z

Rn

( Z

Rn×R+

p(X, y)|Φ(X)|dν(X))dλ(y)

= Z

Rn×R+

( Z

Rn

p(X, y)|Φ(X)|dλ(y))dν(X)

= Z

Rn×R+

|Φ(X)|( Z

Rn

p(X, y)dλ(y))dν(X)

= Z

Rn×R+

|Φ(X)|dν(X) =kΦkL1(ν). So, the first part of Lemma is proved.

Letg∈L(Rn) and Φ∈L1(ν). Using again the Fubini theorem we have [Φ, Tνg] = [TνΦ, g] =

Z

Rn

gTνΦdλ= Z

Rn

g(y)(

Z

Rn×R+

Φ(X)p(X, y)dν(X))dλ(y) = Z

Rn×R+

Φ(X)(

Z

Rn

g(y)p(X, y)dλ(y))dν(X) = [Φ, Z

Rn

p(X, y)g(y)dλ(y)].

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Proof of Theorem 3. We shall prove the existence of a constantc >0 such that kTνgkL(ν)≥ckgkL(Rn) for allg∈L(Rn) and the first part of the theorem will be proved.

The functionTνgis bounded and parabolic onRn×R+. Then, by hypothesis, Lemma 3 and Lemma 1,

sup

XM|(Tνg)(X)|= sup

X∈Rn×R+|(Tνg)(X)|=kgkL(Rn). SinceTνgis a continuous function onRn×R+ ands(ν) =Mf,

kTνgkL(ν)= sup

XM|(Tνg)(X)|. Consequently,

kTνgkL(ν)=kgkL(Rn).

So, we can takec= 1. The first part of Theorem 3 is proved.

To prove the other part, define the space Z =L1(ν)/kerTν. Forz∈ Zand Φ∈zput Sz=TνΦ.

ThenS is an invertible bounded linear mapping ofZ into L1(Rn) and so its adjointS is an invertible bounded linear mapping ofL(Rn) intoZ

(see [7, p. 94]).

Letz∈ Z, Φ∈zandg∈L(Rn). Then we have (Sg)(z) = [Sz, g] = [TνΦ, g] = [Φ, Tνg].

Ifε >0, there exists Φ0 ∈L1(ν) withkΦ0kL1(ν)= 1 and

|[Φ0, Tνg]|>kTνgkL(ν)−ε.

Letz0 denote the coset of Φ0 inZ. Then

|(Sg)(z0)|>kTνgkL(ν)−ε, and

kz0kZ ≤ kΦ0kL1(ν)= 1.

Therefore, the norm of the functionalSgsatisfies

kSgkZ>kTνgkL(ν)−ε=kgkL(Rn)−ε.

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Sinceεwas arbitrary, we proved that

kSgkZ≥ kgkL(Rn)

for any g ∈ L(Rn), and so, using the fact that the norm of any operator is the same as the norm of its adjoint (see [7, p. 93]) and the obvious fact that (S)1= (S1), we have

kS1k=k(S)1k ≤1.

Fixf ∈L1(Rn) and putz=S1f. Then kzkZ≤ kfkL1(Rn), that is

inf {kΦkL1(ν);TνΦ =f} ≤ kfkL1(Rn). By Lemma 3 we have

kfkL1(Rn)=kTνΦkL1(Rn)≤ kTνk.kΦkL1(ν)=kΦkL1(ν).

So, the opposite inequality holds as well.

Theorem 4. Letν be aσ-finite measure onRn×R+ and s(ν) =Mf. Assume that for every functionf ∈L1(Rn)there exists ΦinL1(Rn)such that

(1) f =

Z

Rn×R+

Φ(X)p(X, .)dν(X)

λ-almost everywhere and

kfkL1(Rn)= inf{kΦkL1(ν); (1)holds for someΦinL1(ν)}. Then

sup

X∈Rn×R+

u(X) = sup

XM

u(X)

for any quasi-bounded positive parabolic functionuonRn×R+. Proof: Put c = sup

XM

u(X). If c =∞, sup

XRn×R+

u(X) = ∞. So, suppose that c <∞.

Letε >0. If we fix X0 ∈Rn×R+, then p(X0, .)∈L1(Rn) and

kp(X0, .)kL1(Rn)= 1. By assumptions there is a function Φ∈L1(ν) such that p(X0, .) =

Z

Rn×R+

Φ(X)p(X, .)dν(X)≤ Z

Rn×R+

|Φ(X)|p(X, .)dν(X)

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and

kΦkL1(ν)<1 +ε.

Asuis a quasi-bounded positive parabolic function,u∈ Pand we can integrate the first inequality with respect tofudλ. Using the Fubini theorem and the fact thatu≤cons(ν), we have

u(X0) = Z

Rn

p(X0, y)fu(y)dy≤ Z

Rn

( Z

Rn×R+

|Φ(X)|p(X, y)dν(X))fu(y)dy= Z

Rn×R+

|Φ(X)|( Z

Rn

p(X, y)fu(y)dy)dν(X) = Z

Rn×R+

|Φ(X)|u(X)dν(X)≤ Z

Rn×R+

c.|Φ(X)|dν(X) =ckΦkL1(ν)≤c(1 +ε).

SinceX0 andεwere arbitrary, we have sup

X∈Rn×R+

u(X) =c.

Of course, the following special form of Theorem 4 holds:

Theorem 4’. Let M be a subset ofRn×R+. Assume that for every function f ∈L1(Rn)there exist {λk}k=1 in l1 and a sequence {Xk}k=1 of points in M such that

(2) f =

X k=1

λkp(Xk, .) λ−almost everywhere and

kfkL1(Rn)= inf { X k=1

k|; (2)holds for some{Xk}in M}. Then

sup

XRn×R+

u(X) = sup

XM

u(X) for any quasi-bounded positive parabolic functionu.

4. The main results

Theorem 5. LetM ⊂Rn×R+. Then the following statements are equivalent:

(i)

sup

X∈Rn×R+

u(X) = sup

XMu(X) for all simple parabolic functionsu;

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(ii)

sup

X∈Rn×R+

u(X) = sup

XM

u(X) for all bounded positive parabolic functionsu;

(iii)

sup

X∈Rn×R+

u(X) = sup

XM

u(X) for all bounded parabolic functionsu;

(iv)

sup

X∈Rn×R+

u(X) = sup

XM

u(X) for all quasi-bounded positive parabolic functionsu;

(v)

sup

X∈Rn×R+|u(X)|= sup

XM|u(X)| for all bounded parabolic functionsu;

(vi)forλ-almost every pointY ∈Rn× {0} there is a sequence of points ofM for whichY is a parabolic limit;

(vii)forλ-almost every pointY ∈Rn× {0}there is a sequence of points ofM for whichY is a1-parabolic limit;

(viii)ifνis aσ-finite Borel measure withs(ν) =Mf, then for everyf ∈L1(Rn) there existsΦ∈L1(ν)such that

(1) f =

Z

Rn×R+

Φ(X)p(X, .)dν(X)

λ-almost everywhere and

kfkL1(Rn)= inf {kΦkL1); (1)holds for someΦ∈L1(ν)};

(ix)for every f ∈L1(Rn), there is a sequence {Xk},Xk ∈M and {λk} ∈l1 such that

(2) f =

X k=1

λkp(Xk, .)

λ-almost everywhere and kfkL1(Rn)= inf {X

k|; (2)holds for some{Xk}inM}.

Proof: (i)⇒(vii) by Theorem 1’; (vii)⇒(vi) is clear; (vi)⇒(v) by Theorem 2;

(v)⇒(viii) by Theorem 3; (viii) ⇒(ix) is easy; (ix) ⇒(iv) by Theorem 4’;

(iv)⇒(ii) is clear; (ii)⇒(iii) is easy; (iii)⇒(i) is clear.

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Theorem 6. Let ν be a σ-finite Borel measure on Rn×R+. Then for every f ∈L1(Rn)there existsΦ∈L1(ν)such that

(1) f =

Z

Rn×R+

Φ(X)p(X, .)dν(X)

and

kfkL1(Rn)= inf {kΦkL1(ν); (1)holds for someΦ∈L1(ν)},

if and only ifλ-almost every pointY ∈Rn×{0}is a parabolic limit point ofs(ν).

Proof: The result is obtained by combining Theorem 4, Theorem 1, Theorem 2

and Theorem 3.

5. Application

Definition. Normal distribution N(µ, σ2) on R with parameters µ and σ2 is a continuous probability distribution onRwith a density

φ(y;µ, σ2) = 1 σ√

2πexp(−(y−µ)22 );

normal distribution Nn(µ,Σ) on Rn with parameters µ and Σ, where µ ∈ Rn and Σ = (σk,j) is a positive definite matrix n×n, is a continuous probability distribution with density

φ(y;µ,Σ) =φ(y1, y2, ..yn;µ,Σ) =

(2π)n/2|Σ|n/2exp(−1 2

Xn j=1

Xn k=1

(yj−µj)(yk−µkj,k), where|Σ|is the determinant ofΣand(σj,k) = Σ1.

If Σ is a σ2-multiple of the unit matrix U we have |Σ| =σ2n, Σ12U and

φ(y;µ,Σ) =φ(y;µ, σ2) = (2π)n/2σnexp(−ky−µk22 ).

Such normal distribution will be denoted byNn(µ, σ2) and the class of all such normal distributions will be denoted bySU. Let us remark that, if n= 1, then SU is a class of all normal distributions.

(We recall that a continuous probability distribution on Rn is a probability measure onRnwhich is absolutely continuous with respect toλ.)

Definition. A setN is called non-tangentially dense inRn×R+ if forλ-almost every point(y,0) ofRn× {0}there is a sequence {(µk, σk)} of points of N such that(y,0)is a limit of this sequence andlim infk→∞σk1k−yk>0. (It means that there is a coneCy ⊂Rn×R+ with vertex in (y,0) and open upward such thatM is a limit point of M∩Cy.)

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Theorem 7. LetS ⊂ SU. Then the setN ={(µ, σ)∈Rn×R+; Nn(µ, σ2)∈ S}

is non-tangentially dense if and only if for any continuous probability distribution P there is a sequence{Nnk, σ2k)} of normal distributions onRn ofS and {λk} ∈l1 such thatP can be expressed in the form

(3) P =

X k=1

λkNnk, σ2k), and

(4) inf {

X k=1

k|; (3)holds for someNnk, σk2)inS}= 1.

Proof: A functionf is a density of some continuous distribution if and only if f ≥0,f ∈L1(Rn) andkfkL1(Rn)= 1.

Let us introduce substitutiont=σ2/2,µ=x. Then φ(y, µ, σ2) =p((x, t), y).

DenoteM ={(x, t)∈Rn×R+; (µ, σ)∈N}.

The setN is non-tangentially dense if and only if for almost every (y,0) there is a sequence (µk, σk)∈N, the sequence converges to (y,0) and

lim infk→∞σkk−yk1 >0, it means lim infk→∞σ2k/2kµk−yk2 >0.Using the above substitution we have that it is equivalent to the existence of the sequence (xk, tk) of elements ofM which converges to (y,0) and

lim infk→∞tkkxk−yk2>0.It meansN is non-tangentially dense if and only ifλ-almost every point ofRn× {0}is a parabolic limit point ofM.

Then, by Theorem 5, for any densityf there is a sequence (xk, tk) of elements ofM (it means (µk, σk)∈N) and{λk} ∈l1

(5) f =

X k=1

λkp(Xk, .) λ-almost everywhere and

(6) 1 =kfkL1(Rn)= inf { X k=1

k|; (5) holds for some {xk, tk}in M} and so

f = X k=1

φ(., µk, σ2k) (7)

1 = inf { X k=1

k|; (7) holds for someNnk, σk2) inS}. (8)

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Integrating (7) with respect to λ over any λ-measurable set A and using the Lebesgue Convergence Theorem (can be used thanks to (8)) we have (3) and (4).

Let us suppose that any continuous distribution can be expressed in (3) and that (4) is true. LetP be a continuous distribution andf its density. Then (3) can be written in the form for anyλ-measurable setA

Z

A

f dλ= X k=1

λk Z

A

φ(., µk, σ2k)dλ.

Then, using the Lebesgue Convergence Theorem again (thanks to (4)), we have Z

A

f dλ= Z

A

X k=1

λkφ(., µk, σk2)dλ.

ChoosingA be a ball with the centery and radiusr, dividing the equality by the λ-measure of the ball and letting r → 0, we have (7) and (8) and thus (5) and (6).

Let us remark that for anyf ∈L1(Rn) there are real numbersa1,a2and func- tionsf1,f2 which are densities of some distributions such thatf =a1f1−a2 f2 andkfkL1(Rn) =a1 kf1kL1(Rn)+a2 kf2kL1(Rn). (Really, puta1 =kf+kL1(Rn)

and a2 =kfkL1(Rn). If a1 6= 0, put f1 = a11f+, else f1n/2exp(−k.k2), and ifa26= 0, then putf2= a1

2f, else f2n/2exp(−k.k2).)

Then (5) and (6) are true for anyf ∈L1(Rn) (of course, without 1) and, by Theorem 5,λ-almost every point ofRn× {0}is a parabolic limit point ofM, and

then, as we know,N is non-tangentially dense.

6. Remark

Similar problems as in Sections 1–4 have been recently investigated for classical harmonic functions on a ball in [2], [3], [4], [6] and for more general domains in [1].

The proofs in Section 2 were inspired by [6]; those in Section 3 by [4]. Sufficiency of the non-tangential density of the set N in Theorem 7 can be obtained as a special case of Theorem 2.9 in [8]. (From this, using substitution σ = √

2t, x=µ, Theorem 5 (vi) ⇒(viii) follows.)

References

[1] Aikawa H.,Sets of determination for harmonic function in an NTA domains, preprint, 1992.

[2] Bonsall F.F.,Decomposition of functions as sums of elementary functions, Quart J. Math.

Oxford (2)37(1986), 129–136.

[3] ,Domination of the supremum of a bounded harmonic function by its supremum over a countable subset, Proc. Edinburgh Math. Soc.30(1987), 441–477.

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[4] ,Some dual aspects of the Poisson kernel, Proc. Edinburgh Math. Soc.33(1990), 207–232.

[5] Doob J.L.,Classical Potential Theory and Its Probabilistic Counterpart, Springer-Verlag, New York, 1984.

[6] Gardiner S.J.,Sets of determination for harmonic function, Trans. Amer. Math. Soc.338 (1993), 233–243.

[7] Rudin W.,Functional Analysis, McGraw-Hill Book Company, 1973.

[8] Dudley Ward N.F.,Atomic Decompositions of Integrable or Continuous Functions, D. Phil Thesis, University of York, 1991.

Mathematical Institute, Faculty of Mathematics and Physics, Charles University, Sokolovsk´a 83, 186 00 Praha 8, Czech Republic

(Received September 15, 1993)

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