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0, (1.1) where r ∈H, the nonlinearityg : [0, π]×R→ Ris Caratheodory’s function and f ∈L1(0, π)

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Electronic Journal of Differential Equations, Vol. 2007(2007), No. 81, pp. 1–3.

ISSN: 1072-6691. URL: http://ejde.math.txstate.edu or http://ejde.math.unt.edu ftp ejde.math.txstate.edu (login: ftp)

REMARK ON DUFFING EQUATION WITH DIRICHLET BOUNDARY CONDITION

PETR TOMICZEK

Abstract. In this note, we prove the existence of a solution to the semilinear second order ordinary differential equation

u00(x) +r(x)u0+g(x, u) =f(x), x(0) =x(π) = 0, using a variational method and critical point theory.

1. Introduction

We denoteHthe Sobolev space of absolutely continuous functionsu: (0, π)→R such thatu0∈L2(0, π) andu(0) =u(π) = 0. Let us consider the nonlinear problem

u00(x) +r(x)u0+g(x, u) =f(x), x∈[0, π],

u(0) =u(π) = 0, (1.1)

where r ∈H, the nonlinearityg : [0, π]×R→ Ris Caratheodory’s function and f ∈L1(0, π).

A physical example of this equation is the forced pendulum equation. In articles [1, 2] the authors assume that the friction coefficient r is nondecreasing and the nonlinearityg satisfies the condition

g(x, u)−g(x, v)

u−v ≤k <1.

They prove the uniqueness of the solution. In this work, we prove the existence of a solution to the problem (1.1) under more general condition

G(x, s)≤ 1

2 1−ε+1 4r2+1

2r0

s2+c , x∈[0, π], s∈R, whereG(x, s) =Rs

0 g(x, t)dt,c >0, andε∈(0,1).

2000Mathematics Subject Classification. 34G20, 35A15, 34K10.

Key words and phrases. Second order ODE; Dirichlet problem; variational method;

critical point.

c

2007 Texas State University - San Marcos.

Submitted April 24, 2007. Published May 29, 2007.

Supported by Research Plan MSM 4977751301.

1

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2 P. TOMICZEK EJDE-2007/81

2. Preliminaries

Notation: We shall use the classical spaceCk(0, π) of functions whosek-th deriva- tive is continuous and the spaceLp(0, π) of measurable real-valued functions whose p-th power of the absolute value is Lebesgue integrable. We use the symbolsk · k, andk · kp to denote the norm inH and inLp(0, π), respectively.

By a solution to (1.1) we mean a functionu∈C1(0, π) such thatu0 is absolutely continuous, usatisfies the boundary conditions and the equation (1.1) is satisfied a.e. in (0, π).

For simplicity’s sake we denote R(x) = eR0x12r(ξ) and multiply (1.1) by the functionR(x). We putw(x) =R(x)u(x) and obtain for wan equivalent Dirichlet problem

w00(x)− 1

4r2(x) +1 2r0(x)

w(x) +R(x)g(x, w

R(x)) =R(x)f(x), w(0) =w(π) = 0.

(2.1)

We study (2.1) by using variational methods. More precisely, we investigate the functionalJ :H →R, which is defined by

J(w) = 1 2

Z π

0

(w0)2+ 1 4r2+1

2r0 w2

dx− Z π

0

R2G(x,w

R)−Rf w

dx , (2.2) where

G(x, s) = Z s

0

g(x, t)dt . We say thatwis a critical point ofJ, if

hJ0(w), vi= 0 for allv∈H .

We see that every critical pointw∈H of the functionalJ satisfies Z π

0

w0v0+ 1 4r2+1

2r0 wv

dx− Z π

0

Rg(x,w

R)v−Rf v dx= 0

for allv∈H, andwis a weak solution to (2.1), and vice versa. The usual regularity argument for ODE proves immediately (see Fuˇc´ık [3]) that any weak solution to (2.1) is also a solution in the sense mentioned above.

We suppose that there arec >0 andε∈(0,1) such that G(x, s)≤ 1

2 1−ε+1

4r2(x) +1 2r0(x)

s2+c x∈[0, π], s∈R. (2.3) Remark 2.1. The condition (2.3) is satisfied for example ifg(x, s) = (1−ε)sand

1

4r2+12r0 ≥0. It is easy to find a function r which is not nondecreasing on [0, π]

and which satisfies 14r2+12r0 ≥0. For exampler(x) =−x+π+√ 2.

3. Main result

Theorem 3.1. Under the assumption(2.3), Problem (2.1) has at least one solution inH.

Proof. First we prove thatJ is a weakly coercive functional; i. e., lim

kwk→∞J(w) =∞ for allw∈H.

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EJDE-2007/81 REMARK ON DUFFING EQUATION 3

Because of the compact imbedding of H into C(0, π) , (kwkC(0,π) ≤c1kwk), and the assumption (2.3) we obtain

J(w) =1 2

Z π

0

(w0)2+ 1 4r2+1

2r0 w2

dx− Z π

0

R2G(x,w

R)−Rf w dx

≥1

2kwk2−1

2(1−ε)kwk22− kR2k1c− kRfk1c1kwk.

(3.1)

Because of Poincare’s inequalitykwk2≤ kwk and (3.1) we have J(w)≥ ε

2kwk2−ckR2k1−c1kRfk1. (3.2) Then (3.2) implies limkwk→∞J(w) =∞.

Next we prove thatJ is a weakly sequentially lower semi-continuous functional onH. Consider an arbitraryw0∈H and a sequence{wn} ⊂H such thatwn* w0

inH. Due to compact imbeddingH intoC(0, π) we havewn →w0inC(0, π). This and the continuityg(x, t) in the variablet imply

1 2

Z π

0

1 4r2+1

2r0

w2ndx− Z π

0

R2G(x,wn

R )−Rf wn

dx→ 1

2 Z π

0

1 4r2+1

2r0

w20dx− Z π

0

R2G(x,w0(x)

R )−Rf w0 dx .

(3.3)

Due to the weak sequential lower semi-continuity of the Hilbert norm k · k(i.e.

lim infn→∞kwnk ≥ kw0k) and (3.3), we have lim inf

n→∞ J(wn)≥J(w0).

The weak sequential lower semi-continuity and the weak coercivity of the functional J imply (see Struwe [4]) the existence of a critical point of the functionalJ; i.e., a weak solution to the equation (2.1) and, consequently, to equation (1.1).

References

[1] P. Amster: Nonlinearities in a second order ODE, Electron. J. Diff. Eqns., Conf. 06, 2001, pp. 13-21.

[2] P. Amster, M. C. Mariani: A second order ODE with a nonlinear final condition, Electron. J.

Diff. Eqns., Vol.2001(2001), No. 75, pp. 1-9.

[3] S. Fuˇc´ık: Solvability of Nonlinear Equations and Boundary Value Problems, D. Reidel Publ.

Company, Holland 1980.

[4] M. Struwe:Variational Methods, Springer, Berlin, (1996).

Petr Tomiczek

Department of Mathematics, University of West Bohemia, Univerzitn´ı 22, 306 14 Plzeˇn, Czech Republic

E-mail address:[email protected]

参照

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