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A Weighted Isoperimetric Inequality and Applications to Symmetrization
M.F. BETTA
a,,, .
BROCKb,
A. MERCALDOcandM.R. POSTERAROcaDipartimentodi Matematica,SecondeUniversita diNapoli,PiazzaDuamo, 81100Caserte,Italy;bFakultt forMathematik undInformatik,
UniversittLeipzig, Augustusplatz 10,D04109 Leipzig,Germany;
cDipartimentodi MatematicaeAppficazioni"R.Caccioppoli", Universita diNapoli, ComplessoMonte S.Angelo,ViaCintia, 80126 Napoli, Italy
(Received20October 1998; Revised 15January 1999)
Weproveaninequality ofthe form
fen
a(lxl)7,- (dx)_>fen
a(lxl)T,_ (dx),whereQis abounded domaininR"withsmoothboundary, Bis aball centeredinthe origin having the samemeasureasf.Fromthiswederive inequalities comparingaweighted$obolevnormof agiven functionwiththe norm ofits symmetric decreasing rearrangement.Furthermore,we usethe inequalitytoobtaincomparison results for ellipticboundary value problems.
Keywords: Weighted isoperimetric inequality; Weighted Sobolev norm;
Symmetric decreasing rearrangement; Comparison theorem AMS SubjectClassification: 26D10, 35B05, 35J25
1
INTRODUCTION
Consideraboundary integralof thetype
pa(Q)
"=f0f a(x) 7-[n_l(dx), (1)
whereais agivennonnegativefunctionon
R"
andf isasmooth openset.Itcan beseen as aweightedperimeterof
.
The classicalisoperimetric* Corresponding author.
215
theoremin Euclideanspace saysthat,ifa 1,then
_<
where isthe ball centered atthe originhaving the same Lebesgue measureof fl
(see [27]). By
employing the so-called methodof
levelsetsone can infer a lot of further functional inequalities from the isoperimetric theorem, thus comparing underlying problems with simpler one-dimensional ones.The literature for this themeislarge.
As
an orientation we referto the monographies[5,15,23]
and to the articles[1,12,26].
Recently Rakotoson and Simon
[24,25]
studied the problem of minimizingPa(fl)
overthe class of opensetswith given,fixed
measure.Weareinterested in the question, for whichgeneraltype of weightsa
(2)
might hold. InSection2weprove inequality(2)
forradialweights a=a([x[)
satisfying some further conditions.In
Section 3 using the method of level sets, we show integral inequalities comparing some weighted Sobolev norm ofafunction withacorrespondingnormof its symmetricdecreasingrearrangement.InSection4anextensionofoneof these inequalitiestoBV-spaces
leadsto ageneralversionofourweighted isoperimetric inequality for Caccioppoli sets. We also include a discussion of the equality case in the inequality. We mention that weightednorminequalitieswhich aresimilartoours,areknown for the so-calledstarlikerearrangements(see [6,7,16,18,19])
and for theSteiner symmetrization(see [9]). As
anapplicationoftheweighted isoperimetric inequalitiy(2),
in Section 5 we derive acomparison result forelliptic PDE. Tobemorespecific,letusconsidertheproblemLu
-(aijuxy)xi f
inFt,
u=0 on
O, (3)
where
(i)
fis anopen boundedsubset ofRn,
(ii) agjarereal valued measurable functionsonf which satisfy
aij(x)ij >_ (Ixl)l l =
Rn,
fora.e. x E f, with(Ixl)
0onf,(iii) fand ,-
in suitableLebesgue spaceswhichguaranteethe existence ofaweaksolution.Assuming that the weighted isoperimetric inequality
(2)
holds witha
v/ (Ixl),
weprovethatu<
v, where visthe solution ofaproblem whose data are radially symmetric.Here
u denotes the Schwarz symmetrizationofu(see
Section 3fordefinition).
Results in this order of ideasare contained, forexample, in[17,28]
when the operator Lis uniformly elliptic andin[2].
Such result allowsustoestimateanyOrlicz normofuby simplyevaluating thenormofv.2
THE SMOOTH CASE
For
anymeasurablesetEwith finiteLebesguemeasureletE denotethe ballBR
withcenteratthe origin andm(E)= m(BR). Here
and inwhat followsm(E)
denotes theLebesguemeasure ofE.Throughout the paper we will assume that a:
[0, +o[ [0, +o[
satisfies
a(t), (t > 0),
isnondecreasingand(4) (a(z l/n) --a(O))z
1-(l/n)(z >_ 0),
is convex.(5)
Frequentlywewill write
al
(t)
:=a(t) a(O), (t > 0).
Remark 2.1 Notethat
(5)
issatisfied,for instance, in thecasesa(t) , (t >_ O),
forp_>l,or,moregenerally,if
a(t) (t > 0),
is nondecreasing andconvex.For n
>
2 we shall use n-dimensional polar coordinates(r,
01,..., 0n_1),
torepresentanypointx(Xl,..., xn)
ER
n(compare[16]):
X[ r,
X1 rCOS01,
xk rsin
01
sin02...
sin0k-1
cos0k x
rsin01
sin02...
sin0,_,for k 2,...,n- 1,
(6)
where r
> O,
0<_ Ok <
7r fork 1,...,n 2, and -Tr<_ 0n- <_
zr. Let 0denote the vector of the angularcoordinates
(01,...
,0n_1)
and Tthe(n
1)-dimensional hypercube[0, 7r]
n-2x[-7r, zr].
Therearefunctionsh,
hm
EC(T)
satisfyingh(O) >
0,hm(O) >
0 a.e.inT(m=l,...,n-1),
such that, if E is any smooth
(n-
1)-dimensional hypersurface with representation" { (r, O)"
rp(O),
0ETo},
where
To
isanopensubsetofTwithLipschitz boundary andp C(70),
then
a(Ixl) 7"n-1 (dx) a(p) +
0-2m=lZ -m hm pn-l
h dO.(7)
Notethat
7-/n-1
(nl) nun fT h(O)
dO,(8)
where
wn /2[F(n/2 + 1)]-
isthemeasure ofthe n-dimensionalunit ball.THEOREM 2.1 Let f be a bounded openset with Lipschitzboundary.
Then
a(lxl)
7-t._(dx)>_ fosq a(lxl)7-t._ (dx)
nwln/na((w;lm(f)) 1/n) (m(f)),-,/n (9)
Proof
To showinequality in(9),
wedividetheproofintothreesteps.Step
1 Letn>
2 andsupposethat 0f ispiecewise affinand{(r, 0):
r> 0}
910f is adiscreteset forevery 0 T.(10)
Let
us observethat, to show(9),
it is sufficientto provethe following inequality:I> I
I, (11)
where
I
fOa
al(Ixl) ’n-1 (dx),
/ti
:=f0fl" al(Ixl) ’n-1 (dx).
Indeed,
(11)
and theisoperimetricinequality(Appendix2)
yielda(Ixl) 7"ln-1 (dx) I+ a(0) fo
7-/n-1(dx)
>
I+ a(0)foa
7"/n-1(dx)
Z, a(Ixl) ’n-1 (dx).
Inviewof the assumption
(10),
wehave thefollowing representations:OFt { (r, O)"
rrij(O),
0 Ti, j 1, 2ki,1,...,1}, a {(/, 0)"
/’i,2t-1(0)
rri,2(O),
0i, (12)
wherethesets
Ti
(i1,...,/),
areopen, pairwise disjoint subsetsofT withLipschitzboundary,leij
cl(f’i), (j 1,...,2ki),
ri,
l(O)
<...< ri,2ki(O),
for 0 Ti,=0 ifO
Ft
ri’l >0
if0Vt, (i=1,...,l).
(13)
Using
(7)
and(12),
wecompute2ki
fTi
n-1Orij
2I i=1 j=l
Z
al(rij) + (rij)-2
m=lm hm
(rij)n-lh
dO.(14)
By
settingZiJ:--
(?,/j)n,
(j 1,...,2ki,1,...,l), (15)
weobtainfrom
(13)
and(14)
2ki
fTi
I>
i Z al((Zij)(1/n))(zij)l-(1/n)hdO
"= j=l
>- ’: Ji
al((2i,2ki)(1/n))(Zi,2ki)l-(1/n)h
dOI1. (16)
Let9t
BR, (R > 0). By
using(18), (15)
and(12),
weseethat2ki
fTi
m(B)
6OnRn (1 In) Z Z
Zij(- 1)Jh
dO,i=1 j=l
andhence, by
(13),
R
(na;n)
-1Z Z 2ij(-1)Jh
dOi=1 j=l
<_ (nWn)
-1zi,2kh
dO =:R1. (17)
Furthermore,wehaveby
(4)
and(17)
I nwnal
(R)R
n-1<_
nwnal(R1)R
-1(18)
Now,
in viewof theassumption(5),
wemay applyJensen’s
inequality(see
Appendix1)
toobtain from(16)
and(17)
x
(nWn)
-1zi,2kih
dOnwnal
(R1)R
-1Together with
(16)
and(18),
this proves(11)
in the case under consideration.Step2 Letn andsupposethat
t
kJ(X2n_l,X2n)
where Xl <’’"<
X2k.(19)
n=l
As
in the previous case,weprovethatI>
I.
Thenwecompute2k
I=
Z
al(Ixel) (20)
i=1
and
I
2al Xi(--1)i
i=1
By (19)
wehave that(21)
2k-1
X2k Xl
Z Xi(--1)i-1
O.i=2
In
viewof(20), (21)
and(5)
thismeansthat I>_
al(Ix2kl) +
al(IXl I)
> 2al(1/2 ([X2k[ + Ixl)) I.
Step
3 Let 09t be Lipschitz.We
can find a sequence of sets{fk}
satisfying
(19)
ifn 1,respectively(10)
ifn>
2,andsuchthat limm((fk\f)t3 (f\fk))
0,ko
By
previous steps, the inequality(9)
holds forfk.
Sincea(Ixl)
iscontinuous,this meansthat
lim
a(ll)
’/n-1(dx)
ko
> k--,olim k)a(Ixl)7-/n-1 (dx)= 3f a(Ixl)
"]’/n-1(dx).
Remark 2.2 Theproofof Theorem 2.1 muchsimplifiesif2 is starlike withrespecttothe origin. Weleaveit tothe readertoconfirmthatthe assumption
(4)
issuperfluousin thiscase.3
WEIGHTED SOBOLEV
INEQUALITIESWerecallsomedefinitionsand basic properties
(see [15,26]).
Letu"Rn Rbeameasurablefunctionwhichdecaysatinfinity,i.e.
m(x: lu(x)l > t}
isfinitefor everypositivet.Themap#u(t) m(x: lu(x)l > t), (t 0),
is called the distribution
function
of u; it is a decreasing and right- continuous in[0, +o).
The functionu*definedby
u*(s) inf(t >
O:#u(t) < s), (s > O),
iscalledthe decreasingrearrangementofu;it is adecreasing andright- continuousfunctionon
[0, +o).
Furthermore it satisfies the followingproperties:
#u(U* () <_ w >_ o,
#u(U* (s)-) >_
sVs [0, m(supp u)],
b-a
m{x R": u*(a) >_ [u(x)[ > u*(b)} (22)
if 0
_<
a<
b< m(supp u);
inotherwords,u* isaninversefunction of#u.The functionu defined by
u(x) -u*(lxln), (x
ERn),
iscalledthe Schwarzsymmetrizationofu.Itisnonnegative,radialand radially decreasing;moreover uandu areequidistributed,i.e.
m{x: lu(x)l > t} m{x: un(x) > t}
Vt>
0.(23)
The mapping u---,u is a contraction in
LP(R)
for_<p <
(compare
[15]),
i.e.if u,v E
LP(R"),
then[[u v[lz(,) < [[u- v[lz(l,
).(24)
Nowweprovethefollowingtheorem:
THnOIM 3.1 Let
G’[0, +oe[ [0, +oe[
be nondecreasing andconvex withG(O)=
0and letu RnR
be Lipschitzcontinuousand decaysat infinity,i.e.re{x: [u(x)[ > t} <
oefor
every>
O. Then.. (a(Ixl)lW(x)l) ax . (a(lxl)lVu"(x)l) ax, (2)
provided the
left
integralin(25)
converges.Proof
Theproofis divided in threesteps.Step
IWe
claim thatforevew
s(0,
m(suppu)),
fx (a(Ixl) IVu(x)I) x
ds I,()1>,*()}
(dx a(Ixl)lVu(x)ldx ) (26)
where suppu denotes the support of the function u. Let 0<s
<
s
+
h<
m(suppu).
ThenJensen’sinequality(Appendix1))
givesh u*(s/h)>lu(x)l>u*(s)}
G(a(Ixl)lVu(x)l)
dxu*(s+h)lu(x)l>u*(s))
Sending h--*0,andbytakinginto account
(22),
weobtain(26).
Step2 Weclaimthat foreverys E
(0,
m(suppu)),
ix
du*dds
a(Ixl)lVu(x)l
dx> --nwl, lnsl-llna(wllns ll") ds"
lu(x)l>u*(s))
(27)
Let0
<
s<
s+
h<
m(suppu).
Thenwehave! f a(Ixl)lVu(x)l
dxh u*(s)>_lu(x)l>u*(s/h))
hau*(s+h)dt lu(x)l=t}
a(Ixl) ’n-1 (dx)
(bythecoarea formula(Appendix
3))
f
u*(s)nwln/ntu(t)l-1/na(wl/n#u(t)l/n)dt
>-
-
(by Theorem2.1)
> - (u* (s)
u*(s + h))nWn/n
tE[u*(s+h),u*(s)]inflZu( t) l-1/na(wl/n#u t) 1/n).
Passingtothe limith 0,this yields
(27).
Step
3We
have thatG(a(Ixl)lVu(x)l)
dxds
O(a(Ixl) lX7u(x) l)
(bythe coarea
formula)
>
dsGlu(x)l>u*(s)}
a(Ixl)lVu(x)l
(by(26))
f0 (-
>
dsGnwln/nsl-(1/n)a(w;1/ns1/n)du*
dsJ"
(by(27))
Butsinceu* is radially decreasing, this lastexpressionisequalto
G(a(Ixl)lVu(x)l)
dx.By
specializingG(t)=
pinTheorem3.1,weget thefollowing COROLLARY 3.1 Letu Ewl’V(Rn)for
somep [1,+o).
ThenaP(Ixl)lVu(x)l
pdx>_ f. aP(Ixl)lVu(x)l
pdx,(28)
provided the
left
integralin(28)
converges.Proof
Ifu is Lipschitzcontinuous and decays at infinity, then(28)
follows from Theorem3.1.Inthegeneralcase wechooseasequence
{Uk }
CC (Rn)
such thatUk ---* u in
WI’p(In).
By (24)
wehave that(Uk)
U inLP(Rn), (29)
Since
IIXT(uk)nll./ ) <_ IIXT(uk) ll / /,
the functions (ug) are equi- bounded inWI’p(Rn).
Together with(29)
this implies that for a subsequence{(ue) },
(Uk,)
u weaklyinWI’p(Rn).
Inviewof the weak lower semi-continuity of the integral in
(28)
we obtainaP(lxl)lVu(x)l
p dx< liinf f aP(lxl)lV(u,)(x)l
pdxk
J
<
limf aP(lxl)lVuk(x)lPdx
, aP(lxl)lVu(x)l
pdx.Remark 3.1 Wedid not useassumption
(4)
in theproofof Theorem 3.1.Inviewof Remark 2.2, the results of this sectionremain true, ifa satisfies(5)
butnot(4),
andifthe levelsetsofuarestarlike with respect tothe origin, i.e.Ve(t)
:=u(te), (t 0),
is nonincreasingfor everye Rn. (30)
4
THE GENERAL CASE
Ouraim is togeneralizeTheorem 2.1toCaccioppolisets.Thetheoryof these sets is imbedded in the framework of spaces B
V(f),-where
fis anopen set ofR
n.
Recall that any measurable set Ec
f satisfyingIIDllv) < +,
iscalledaCaccioppoliset,and the quantityiscalled theperimeterofE
(in
thesenseofDe Giorgi).As
anextension of thisdefinition,foranyfunctionu EBV(R
n)
wesetfa(U)’=sup{f.u(x)div(a([x[)qo(x))dx,
qoE
Cg (R n, Rn), I1 _<
1},
and for anyCaccioppolisetEwecall thequantity
pa(E)
:--fa(XE)
the weighted perimeter
of
E (with weighta) (see
also[3,24,25]).
Note thatfa
is a nonnegative, convex and weakly lower semi-continuous functionalonBV(Rn),
and,sincefa(U) < sup{a(lx])"
xc suppu}llOul[s(i.) Vu c BV(R"),
fa(U)
isatleast finite ifsuppuisbounded. Furthermore, if uCWI’I(R n)
andfa(u) < +,
thenfa(u) [" a(Ixl)lVu(x)l
dx.(3) LEMMA
4.1If
Eisaboundedopenset withLipschitzboundary,thenpa(E)-- f0 a(lxl)
7"/n-1(dx). (32)
Proof
Itiswell-knownthatp(EfqU)
7"[n-I(O(E
fqU))
for everyopensetU
(see [14]).
Sincea(lx])
is continuous,thisyields(32).
LEMMA
4.2 Let{Uk}
CWI’I(Rn),
uEBV(R"),
Uk U in
Ll(R n)
and
lim
IlOull ( =/. (33)
k---cx3
Then
lim
f a(Ixl)lVu(x)l
dx=fa(u). (34)
Proof (33)
implieslim
IlVUkl[Ll(U --IlDull(v/
for every open setU,
k--*o
(compare
[14]).
Sincea(Ixl)
is continuous,thisyields(34).
THF.OP,F.M4.1 Letu E
BV(R n)
andfa(U ) < +oc.
Thenfa(U) >_fa(). (35)
Proof
Wechooseasequence{uk}
CWI’I(Rn),
suchthat(33)
issatisfied.From
(24)
we seethat(uk)
u inL(Rn). (36)
Since
117(u)nll.,// 117ull,(/, (k= ,2,...),
the functions
(u)
are equiboundedinWI’(Rn).
Itfollows that fora subsequence{(u,) },
(uk,)
u weaklyinBV(Rn).
Sincethe functional
fa
isweaklylower semi-continuous, this impliesfa(U ) <
liminffa((U/e)). (37)
But by
(31)
andCorollary3.1wehave thatfa((U) n) IlalV(u)nlll,( IlalVulll.,( fa(U).
Togetherwith
(36)
and(37)
thisconcludes theproof ofthe Theorem.By
choosing u=x.E in(35),
we obtain a generalized form of Theorem 2.1.THEOrtEM4.2 (Weighted isoperimetricinequality) Let EbeaCacciop- polisetin
II n.
Thenpa(E) >_ pa(E )
ncoln/na((w-lm(E))l/n)(m(E))
1-(1/n)(38)
Next we analyze thecase ofequalityin
(38). We
needtwo auxiliary lemmata.LEMMA4.3 Then
Let
A,
Bbe Caccioppolisetswithpa(A)<
cx2andpa(B)<
cx2.pa(A
f’)B) + pa(A
UB) <_ pa(A) -+" pa(B). (39) Proof
IfA and B are bounded, open sets with Lipschitz boundary, then(39)
follows by Lemma4.1.Inthegeneralcase wefindsequences
{Ak}
and{Bk}
ofbounded, open sets withLipschitz boundary,and such thatlim
m((A\A)
tA(A\A)) O,
k--*o
and
lim
m((Bk\B)
U(B\Bk)) O,
kc
lim 7-/,-1
(OAk) p(A)
k.--o
lim
’ln-1 (OBk) p(B),
k---oo
(compare
[14]).
Sincea(lxl)
iscontinuous, thisyields limpa(hk)
limf a(Ixl) 7n-1 (dx) pa(A)
k--o k----odOAk
and
lim
pa(Bk)
limf a([x])
7-/,,_1(dx) p,,(B).
ko koJOB
By
the weak lower semi-continuityofpweinferthatpa(A) + pa(B)
kclim(pa(ak) + pa(Bk))
>
lim infpa(Ak
NBk) +
liminfpa(Ak
t2Bk)
ko kc
>_ pa(A
fqB) + pa(A
t_JB).
LEMMA
4.4 Let g’[0,+cxz[ [0, +o[
beaconvexfunction.
Theng(c s) + g(/3 + s) > g(tx) + g(/3)
for 0<
s<
c</3. (40) Proof
Firstsupposethatgis differentiable.Wesetqo(t)
:=g(c t) + g(/3 + t) g(tx) g(/3), (0 < < c).
Then
4(0)=
0and, by convexity,qo’(t) -g’(a t) + g’(/3 + t) >_
0 for 0< <
a.Thisyields
(40).
Inthegeneralcase wecanarguebyapproximation.
THEOREM 4.3 Let
a(t) >
Ofor >
0and,for
someCaccioppolisetE, pa(E) --pa(E).
ThenEisequivalenttoaball.Furthermore,
if
either(i)
n anda(t)
isstrictly convex, or(ii)
n>
2 anda(t)
isstrictlyincreasing(t > 0),
thenE &equivalenttoE
(41)
(42) (43)
Proof
Theproofisdivided intofivesteps.Step
1Suppose
that forsome6>
0,m(E
NB26) m(B26),
orm(E
fqB2)
0.(44)
By
settingfi(t) {
0a(t) -a(6)
if0<t<6 if6<t, weobtainby(41)
and(44),
a(6)p(E) + p(E) pa(E) pa(E ) a(6)p(E ) + p(E). (45)
Furthermore,since satisfies
(4)
and(5),
wehavethatp() <_ p().
This implies, together with
(45)
and the isoperimetric inequality (Appendix2),
thatp() p().
By
oncemoreapplyingtheisoperimetric theorem,we infer thatEmust be equivalentto aball.Step
2 Next supposethata(0) >
0.We
havethata(O)p(E) +
Pal(E) pa(E) pa(E I) a(O)p(E ) +
Pal(E),
and since al satisfies
(5),
we may argue as in step toinferthatEis equivalentto aball.Step
3 Now supposethata(0)=
0,and that(44)
is notsatisfied. Then 0< m(E
f’lB) < m(B)
V6>
O.We choose e
>
0 such thatEtA B
is not equivalent to a ball. Thefunction
g(z) a(z/n)z /n-, (z > 0),
is convexby
(5).
InviewofLemma
4.4 this yieldsg(m(E)) + g(m(Be)) < g(m(EfqBe)) + g(m(EU Be)).
Onthe otherhand,wehave that
nWn/ (g(m(E B,)) + g(m(E B)))
=pa((ENBe) ) +pa((EUBe) )
< pa(E n Be) + pa(E
IdBe)
(by Theorem4.2)
< pa(E) +pa(Be)
(by Lemma4.3)
pa(E ) + pa(Be)
(by(41))
na)ln/n(g(m(E)) + g(m(Be))).
Hence
we musthavepa((E
C1Be))
-1-pa((EtA Be)l) pa(E
NBe) + pa(EtA Be),
which meansthat
pa((EI.A Be) ) --pa(EtA Be),
byTheorem 4.2.
In
viewofstep weinfer thatEtA B
is equivalenttoa ball,acontradiction.ThuswehaveprovedthatEis equivalentto aball.
Step
4 Now suppose(42).
Since thesetsEandE areequivalenttointervals
(-R +
s,+R
/s)
and
(-R, +R),
respectively(R >
0,s ER),
wecomputea(l-R + s[) + a(lR + s[) pa(E) pa(E ) 2a(R).
Onthe otherhand,if
Isl >
0,(42)
yieldsa(l-R + s[)
/a(lR
/s[) a(R + Isl)
/a(-R + Isl) > 2a(R).
Hence
s 0,i.e.EisequivalenttoEStep
5 Finally assume(43).
ThesetsEandE areequivalenttoballs
BR(xo)
andBR,
respectively(R >
0,x0ER’).
Wefixacoordinate system x(x1, x/) (x
R’-1),
suchthat Xo
(s,
0,...,0),
sIx01.
Thenwecomputes,(xo)
a(lxl)7-tn-1 (dx)
=l<n(a({’x"9+(s-v/R2-lx"2)2}1/2)
{ + I’l(g I’1)-)
/’. (46)
Assume
thatsIx01 >
R.Then theterm[...
in(46)
increasesstrictly as s increases.In
view of Theorem 2.1 this means thatpa(Bg)>pa(BR), acontradiction.Hencewe musthaveIx01 _< R,
thatisBg(xo)is starlike with respecttothe origin.Followingstep of theproof ofTheorem 2.1wecompute
I
/ a (Ixl)
n-1(dx) (47)
JoB(xo)
al
(7") +
7.-2m=lZ -m hm rn-lh
dO,(48)
where
- (0), (0
6T),
is arepresentationforOB(xo),
andI
:=[ a ([xl)-l(dx)
nnal(R)Rn-1. (49)
dOB
Notethat
(43)
meansthata(t) >
0for>
0.Since
nwnR
n h dO,weobtain, using
(47), (49), (5)
andJensen’s
inequality, I[a2()-h
dOnwna (R)R
n- I,
where the firstinequality is strict when
Ix0[ #
0.ThisagainmeansthatEis equivalenttoE The theorem isproved.
5
COMPARISON RESULTS FOR PDE
Letusconsiderthe following Dirichletproblem:Lu
-(aijux) f
inft,(50)
u=O on09t,
where
(i) 9t is anopenbounded subset of
R ,
(ii)
ae
arereal valuedmeasurablefunctionsonft whichsatisfyaij(x)ij >_ (Ixl)l l = R",
fora.e. x Ea,
where u is a nonnegative measurable function on f such that uE
Ll(f), u-
ELt(f)
for some>
1 if n>_
2 andu-
LI(,-)
ifn=l,
(iii) fE Lq(f]),
with q such that 1/q1/2 1/(20 + 1/n
if n>
2 andfE Ll(f)
ifn 1.A
solution ofthe problem(50)
is a functionuW’2(u, fl)
whichverifiesthefollowingcondition:
aijuxsqox,
d.x,=fqodx Vqo C(fl). (51)
The assumptions (i)-(iii) guarantee theexistence of such a solution
(see [21,29]).
FromTheorem 4.2wederivethefollowing comparisonresult:
THEOREM 5.1 Let u be the solution
of (50).
Furthermore let wWlo’2 (u, f#
be thesolutionof
thefollowingproblem:-(u(lxl)wxi)xi =/#
infl#,
w 0 onOf
#, (52)
If X/), (t >_ 0), verifies
theassumptions(4)
and(5)
thenwehave:u#(x) < w(x) for
a.e. xa #. (53) Furthermore,for
every q]0, 2],
itresults:u(Ixl)qllvulq
dx< j u(Ixl)qllXTwlq
dx.(54) Proof
Let[0,
esssuplul[
andh>
0.Wechoose astestfunctionin(51)
signu qoh u
--. sign
uh 0
if
lul > +
h,if
< lul
t+h,otherwise.
Thenweget
h lul<_t+h
aijUx,
Uxs
dxf
signudx+
- f(u
signu)
dx.Jlul>t+h lul<t+h
Wedenote by
Wo’P(v,
9t), _<p <othe weighted Sobolev space, thatisthe closure ofC
(ft)under the normf .
v(x)lVu(x)lpdx)1/p.Using
(ii),
Hardy’s inequality and letting h go to zero, we have(see
also[2]):
d
/,u
(Ixl)lVul 2dx <
--
I>tdt I>t
ai(X)UxUx
dx--i[>tf(x)dx<-f"(Of*(a)d’o (55)
Moreover,
bytheCauchy-Schwarzinequality,wehaved/u V(IxI)IVul
dxdt I>t
(
d12 ,(Ixl)lXZul
2dx)1/2 (-#’u(t))
1/2(56)
Onthe otherhand,fromcoareaformula
(see
Appendix3)
weobtain d/u X/’u(Ixl)[Vul
dx/ V/u(Ixl)-i (dx).
dt ]>t I--t
(57)
NowTheorem 4.2gives
v/(Ixl)’?n-1 (dx) _< fu V/(IxI)/n-1 (dx),
that is,
(,#u_(t)I/nnwln/n#u(t
1-1InSi
ul=tx/,,’(Ixl)
7"/n-1(dx). (58)
On combining
(55)-(58),
weobtain(,,_mi".’n.oinz,(t)2_2i,<f"’(t)f,(r)d"
flu(t)
vt wln In )
,0(59)
Let us consider problem
(52).
Obviously, sincew(x)= w#(x),
the argumentsleadingto(59)
proceedin thesamewayexcept thatequalities nowreplaceinequalities in the details.Thus,inplaceof(59),
we obtain the equalitya,w(t) , n/n jn n ]’l’w(t)
2-2/n ,0(or)
dtr,(60)
where#wisthe distribution function ofw.Setting
F() fof* (r)
dru(
)d/n/wln/n)n2wZnAZ-Z/n
(59)
and(60)
give:#u(t)F(#u(t)) < lZw(t)F(#w(t)). (61) Let/be
aprimitive ofF. Then, integrating(61)
between 0 andt, wegetIf
f0,
thendF/d) F(A)>
0 for all A>0. Hence F is strictly increasingand"Uu(t) <_ Uw(t).
Thisyields
(53).
Furthermore,wehavebyH61der’sinequality:d
fl. u(Ixl)q/lulqdx
dt
I>
(fu
d(Ixl)lX7ul
dx(-#tu(t))
l-q/2-<
-
Using
(55),
wederivefromthis:fl
u(/#u(t)f,
d
u(lxl)q/21vulq
dx< (s)
ds(-]tu(t))l-q/2
dt I>t J0
Integrating this between 0and
+o
yields:)
9/2foo
+fUu(t)f*(s)ds (-d#(t))
u(lxl)q/2[Vulq
dx<
"#’(t)
sofrom which we obtain,by
(59)"
(lxl)q/2lu[
qdx+o
f, (r)
dr ds,nqafln/noO sl-1/ng/,.(s1/n/coln/n
and
(54)
follows.Remark 5.1 Alvino and Trombetti
[2]
obtained anothercomparison result for the solution ofproblem(50).
They provedthe inequalityu#
<
v,(62)
wherev isthe solution of the Dirichletproblem
-((Ixl)v,), =f#
v=O
in
f#,
onOf
#, (63)
and
(Ixl)
isafunctiondefined on[0,I l],
such thatu"(t) 1
flu
1(s)
ds(x)
dxi>
for a.e. C
[0,
ess suplull,
AccordingtoLemma2.1 in
[2],
the function1/
is aweaklimitofasequence offunctionshaving the same rearrangementas
Iv.
Let usobserve that, since depends on u, in
(62)
u#is compared with the solutionofaproblemwhichdependson u.InTheorem 5.1 theproblem(51)
doesnotdependon ubut furtherassumptionsonvarerequested.Remark 5.2 Theorem 5.1 canbe extended to nonlinear ellipticpro- blems of the type:
-div(A(x,
u,Vu)) f
in fl,u 0 on0f,
(64)
where
(i) A"f x
R
xRn
RnisaCaratheodoryfunctionsuch that(Ixl)l l
pwhere
uELS(f), s>
and1/u
ELt(f),
t> 1,l<p<(n(t- 1))/
(t-n).
(ii)
fE La(Vt),
with q such that1/q ((p- 1)/p)(1 l/t)+ (l/n).
Let us denote by uE
W’P(u,f)
a solution of(64)
and by zWlo
’p(u, fl#)
thesolutionof thefollowing problem:-div((Ixl)lVzlp-2Vz)
-f#
inf#,
z 0 on Of
#.
If
(u(t))
1/p(t > 0),
verifiesthe assumptions(4)
and(5),
wehaveu#(x) < z(x)
for a.e. x Ef#.
ArguingasinTheorem 3.1 in
[8],
wecanprovethatproblem(52)
isthe uniqueproblemsuchthat equality holds in(53).
More preciselywehave THEOREM 5.2 Let uandw thesolutionsof (50)
and(52)
respectively.If
u# w a.e. in 9t, then ff# +
Xo,f--f#(. +Xo)
andaij(x + Xo)Xj
u(lxl)xifor
some XoR".
APPENDIX
Werecallsomewell known theorems.
(1) Jensen’s
inequality(see
e.g.[20])
Let EC
R
nbe measurable with finite measure, letf,
h be integrableonE,
h>
0,and letG"R[0, +o[
be convex. Thenf
eO(f(x) )h(x)
dxfF h(x)
dx\ fFh(x)
dx]" (65)
(2)
Isoperimetric theoreminR
n(see
e.g.[27])
IfECRnismeasurable with finite measure, then7-[.n-1
(OE) > nwlnln(m(E)) 1-(1In). (66)
Furthermore,if
(66)
isvalidwithequalitysign,thenEisequivalent to aball.(3) Coareaformula (see
e.g.[13])
Ifu isLipschitzcontinuous
andfis
integrable, thenf(x)lVu(x)l
dx dtf(x)
7-[,n-1(dx).
11":lu(x)l-t)
(67)
Acknowledgment
The second authorwants tothankthe University ofNaplesforavisiting appointment.
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