A two-weight inequality for the Bessel potential operator
Y. Rakotondratsimba
Abstract. Necessary conditions and sufficient conditions are derived in order that Bessel potential operator Js,λ is bounded from the weighted Lebesgue spaces Lpv = Lp(Rn, v(x)dx) intoLquwhen 1< p≤q <∞.
Keywords: weighted inequalities, Bessel potential operators, Riesz potential operators Classification: Primary 42B25
§1. Introduction
The Bessel potential operatorJs,λ is defined via the Fourier transform by (J[s,λf)(ξ) =
4π2|ξ|2+λ1s−s2
fb(ξ) whereλ >0, 0< s < n,n∈N∗ andbg(ξ) =R
y∈Rne−2iπy·ξg(y)dy. Our purpose is to characterize the weight functionsu(·) andv(·) for which there isC >0 such that
(1.1) Z
x∈Rn
(Js,λf)q(x)u(x)dx1
q
≤C Z
x∈Rn
fp(x)v(x)dx1p
for all f(·)≥0, and with 1 < p ≤ q < ∞. A weight means a nonnegative locally integrable function. This inequality implies Js,λ is bounded from the weighted Lebesgue spaceLpv =Lp(Rn, vdx) intoLqu. For the convenience (1.1) will also be denoted byJs,λ:Lpv →Lqu.
Inequality (1.1) plays a fundamental role in Analysis since it is closely connected with spectral properties of Schr¨odinger operators [Ch-Wh], [Ke-Sa] and it leads to applications in partial differential equations ([Ad-Pi], [Ma-Ve]), theory of Sobolev spaces ([Ma]), complex analysis, etc. For instance estimate like
Z
y∈Rngp(y)u(y)dy
≤c Z
y∈Rn
(−∆ +λ1s)s2gp
(y)v(y)dy for all smooth functions g(·),
which also appears in partial differential equation related to the operators (−∆ + λ1s)s2, can be derived fromJs,λ:Lpu→Lpu, since ((−∆+λ1s)s2Js,λ)g= (Js,λ(−∆+
λ1s)s2g) =g.
Compared to the Riesz potential operatorsIs, 0< s < n, defined by (Isf)(x) =
Z
y∈Rn
|x−y|s−nf(y)dy,
few works (see for instance [Ad1], [Sc]) are devoted to the study ofJs,λ:Lpv → Lqu; and people had to be content oneself on Js,λ ≤cIs so that a condition for Is :Lpv →Lqu is also right forJs,λ :Lpv →Lqu. The strongest up to date results are those of Kerman-Sawyer [Ke-Sa], and Maz’ya-Verbitsky [Ma-Ve]. Indeed a characterization of weightsu(·) for which Js,λ:Lp1→Lqu (i.e. v(·) = 1) is given in [Ke-Sa], and investigations of weightsw(·) which ensureJs,1 :Lp1→Lq
(Js,1w)p′
are presented in [Ma-Ve]. Although a necessary and sufficient condition for Is : Lpv →Lquis known ([Sa-Wh]), the analog condition characterizingJs,λ:Lpv →Lqu
is not clear in the literature. Consequently our intention is to fill this gap.
Although a result due to Sawyer and Wheeden [Sa-Wh] related toT :Lpv →Lqu, whereTis a potential operator given by a positive kernelK(x, y), could be applied directly to get Js,λ : Lpv → Lqu, the fast decrease at infinity of the kernel Ks,λ of Js,λ (see §3) leads to conditions more refined than the standard ones used forT. Therefore the boundednessJs,λ:Lpv →Lqu deserves its own study which is performed in this paper.
The main results are presented in the next section. And§3 is devoted to basic lemmas used for the results whose proofs are given in§4.
§2. The main results
In this paper we always assume:
0< s < n, λ >0, 1< p≤q <∞, p′= p
p−1, q′ = q q−1, u(·), v(·) are weight functions with σ(·) =v−p−11 (·)∈L1loc(Rn, dx).
Our first main result is
Theorem 1. The boundedness Js,λ : Lpv → Lqu holds if and only if there are C, c >0such that
(2.1) Z
Q
(Isg)q(x)u(x)dx1q
≤C Z
(3Q)
gp(x)v(x)dx1p
for each g(·)≥0whose support is3Q
and (2.2) Z
y /∈(3Q)
|xQ−y|(s−n)p′exp{−cλ21s|xQ−y|}σ(y)dyp′1
× Z
y∈Q
u(y)dy1q
≤C for all cubesQcentered atxQ and with |Q|n1 =λ−2s1 . Remind that a cubeQ(centered atxQ= (xi)∈Rn) is a product ofnintervals of the form [xi−l, xi+l] wherel >0. And forR >0,RQis the cube given by the product of [xi−Rl, xi+Rl]. The Lebesgue measureR
y∈Q dyofQis denoted by|Q|.
Next we give some remarks whose proofs are given in§4.
Remarks.
(1) A necessary condition forJs,λ :Lpv →Lqu, which is consequently assumed is 0≤ ns +1q−1p. So for 1< p < ns this boundedness has a sense forp≤q≤p∗ with p1∗ =1p −ns.
(2) Theorem 1 remains true if in conditions (2.1) and (2.2) the cubes Q are chosen such that|Q|n1 ≈λ−21s. This equivalence meansc1λ−21s ≤ |Q|1n ≤c2λ−21s for some fixed constantsc−1, c2>0.
(3) Condition (2.1) in Theorem 1 can be replaced by
(2.3) Z
Q2
(Ish)q(x)u(x)dx1q
≤C Z
Q1
hp(x)v(x)dx1p
for each functionh(·)≥0 whose support is Q1; and whereQ1 andQ2 are cubes with|Q1|n1 =|Q2|n1 = [resp. ≈]λ−2s1 andQ1∩Q26=∅.
(4) Also the condition (2.2) can be replaced by (2.4) exp(−cm)m(s−n)(λ−2s1 )(s−n) Z
y∈Q2
σ(y)dyp′1 Z
x∈Q1
u(x)dx1q
≤C for all integers m ≥ 4 and cubes Q1, Q2 with |Q1|1n = |Q2|n1 = λ−21s and dist(Q1, Q2) = inf{|x−y|;y ∈Q1, x∈Q2} ≈(mλ−2s1 )>0. So here we are in the caseQ1∩Q2=∅.
(5) The weight functionw(·) satisfies the doubling condition ifR
(2Q)w(y)dy≤ CR
Qw(y)dy for someC >0 and all cubes Q. If one ofu(·) andσ(·) =v−p−11 (·) is a doubling weight then an easy condition which ensures (2.4) is
(2.5) (λ−2s1 )(s−n) Z
y∈Qσ(y)dyp′1 Z
x∈Qu(x)dx1
q ≤C
for all cubesQwith |Q|n1 =λ−2s1 . Now we can state the following
Theorem 2. Assume that one ofu(·)andσ(·) =v−p−11 (·)is a doubling weight function. ThenJs,λ:Lpv→Lqu if and only if the condition(2.3)is satisfied.
With this theorem and the well known results on the (global) boundedness Is:Lpv→Lqu, we obtain the following more useful statement.
Proposition 3. Let u(·) and σ(·) as in Theorem 2. Then Js,λ : Lpv → Lqu whenever, for somet >1 with1< t <
1 q−1p+1
s n+1q−p1, (2.6) |Q|ns+1q−1p 1
|Q|
Z
Q
ut(y)dytq1 1
|Q|
Z
Q
σt(y)dy 1
tp′
≤A
for all cubesQwith |Q|n1 ≤λ−2s1 . Moreover for u(·) andσ(·)satisfying A∞ condition, thenJs,λ :Lpv →Lqu if and only if
(2.7) |Q|ns+1q−1p 1
|Q|
Z
Q
u(y)dy1q 1
|Q|
Z
Q
σ(y)dyp′1
≤A
for all cubesQwith |Q|n1 ≤λ−21s. Conditions (2.6) and (2.7) have nontrivial senses sincens+1q−1p ≥0 is assumed (see Remark 1). Recall thatw(·) satisfies the A∞ condition if, for some r > 1:
|Q|ns−1(|Q|1 R
Qw(y)dy)1r(|Q|1 R
Qw1−r′(y)dy)r′1 ≤cfor all cubesQ.
As an example, for each weight function w(·) then Js,1 : Lp1 → Lp
(Js,1w)p′
whenever for a t >1: |Q|ns(|Q|1 R
Q(Js,1w)tp′(y)dy)tp1 ≤ C for all cubesQ with
|Q|n1 ≤1. Such a result was proved by a different method in [Ma-Ve]. We will present below another application of Proposition 3.
Although this result yields sufficient condition for Js,λ : Lpv → Lqu, we are able to state a necessary and sufficient condition for this embedding. However, compared with (2.6), the corresponding characterizing condition is not easy to check in general.
Proposition 4. Letu(·), σ(·)as in the hypotheses of Theorem 2. Then Js,λ : Lpv →Lqu if and only if for someC >0:
(2.8) Z
(3Q)
(IsσIQ)q(y)u(y)dy1q
≤C Z
Q
σ(y)dy1p and
(2.8∗) Z
(3Q)
(IsuIQ)p′(y)σ(y)dyp′1
≤C Z
Q
u(y)dyq′1
for all dyadic cubesQwith|Q|1n ≤λ−21s.
A dyadic cubeQis a product of nintervals of the form [2k(xi−l),2k(xi+l)]
wherel >0, andIE(·) is the characteristic function of the measurable setE.
Letw(·) be a weight function, and 0< s < prn with 1< r <∞. By a result due to Adams [Ad2], there isC >0 such that
(2.9) Z
x∈Rn
(Isf)p(x)w(x)dx≤C Z
x∈Rn
fp(x) Msprwr1r (x)dx
for all f(·)≥0.
Here Mβ, 0 ≤ β < n, is the usual fractional maximal operator defined as (Mβg)(x) = sup{|Q|βn−1R
Q|g(y)|dy;Q∋ x}. Since Js,λ is pointwise majorized byIsthen inequality (2.9) remains true withIsreplaced byJs,λ, and it becomes natural to ask whether (2.9) holds withJs,λand the weight in the second member defined by a smaller operator thanMβ. Therefore we will be interested to get an inequality like
(2.10) Z
x∈Rn
(Js,λf)p(x)w(x)dx≤C Z
x∈Rn
fp(x) Mspr,λwr1
r(x)dx for all f(·)≥0, where (Mβ,λg)(x) = sup{|Q|βn−1R
Q|g(y)|dy;Q∋xand|Q|1n ≤λ−2s1}.
Unfortunately (2.10) is false in general. Indeed take n = 1, λ = 1, w(·) = I[0,1](·) and f(·) = I
[3,4](·). Clearly (Mβ,1wr)(x) = 0 for all |x| ≥ 3 and R
x∈Rnfp(x)(Mβ,1wr)1r(x)dx = 0. On the other hand (Js,λf)(·)≈(Isf)(·)≈1, on [0,1] andR
x∈Rn(Js,λf)p(x)w(x)dx≈1.
Consequently to get (2.10), some restriction on the weight function w(·) is needed. Really, by Proposition 3, we have
Corollary 5. Let r > 1, 0 < s < prn and λ > 0. Suppose that one of w(·) andσ(·)is a doubling weight function, whereσ(·) = (Mspr,λwr)1r(1−p′)(·). Then there is C >0 for which(2.10)is true. This constantC depends on n, p, sand the constant on the doubling condition.
§3. Preliminaries lemmas
As we have alluded in§1, by arguments in [Ar-Sm] the kernelKs,λ(·) of Js,λ satisfies
(3.1) Ks,λ(R)≈Rs−n if R≤λ−21s, else Ks,λ(R)≈R12(s−n+1)exp(−Rλ21s).
These equivalences lead to a better knowledge of the behaviour ofJs,λ.
Lemma 1. Let0≤s < n,λ >0. Then
(3.2) C1(Ts,c2sλf)(·)≤(Js,λf)(·)≤C2(Ts,c−2sλf)(·).
HereC1,C2,cdepend only onnands. And the operatorTs,µ(µ >0)is defined as(Ts,µf)(x) =R
y∈Rn|x−y|(s−n)exp{−µ2s1 |x−y|}f(y)dy.
Obviously (Js,λf)(·)≤C(Isf)(·).
Lemma 2. Let L >0. One can find a family(Ql)l∈I of cubes with|Ql|n1 =L and disjoint interiors such that
(3.3) Rn=[
l∈I
Ql,
and there is an integerN >1 (depending only onn)for which the following holds:
(3Ql) = [
l′∈Il
Ql′ where l′∈ Il if Ql∩Ql′ 6=∅, and card{l;l′ ∈ Il} ≤N; (3.4)
(3Ql)c={y;y /∈(3Ql)}= [∞ m=4
[(m+ 1)Ql\(m−1)Ql] = [∞ m=4
[
j∈Jm,l
Qj, (3.5)
where j ∈ Jm,l iff dist(Qj, Ql) ≈ (mL), and card{j;j ∈ Jm,l} ≤ N ×mn or card{l;j∈ Jm,l} ≤N×mn;
|x−y| ≈ |xQl−y| ≈(mL) for all x∈Ql, y∈Qj and j∈ Jm,l; (3.6)
X
l∈I
I(3Q
l)(·)≤N; (3.7)
X
l∈I
I[(m+1)Ql\(m−1)Ql](·)≤N mn for each integer m≥4.
(3.8)
Proof of Lemma 1: Using the property of the exponential like
limR→∞Rαexp{−βR} = 0, and estimates (3.1) for Ks,λ then we can find C1, C2, c > 0 depending only on s and n such that C1Rs−nexp{−cλ21sR} ≤ Ks,λ(R) ≤ C2Rs−nexp{−c−1λ2s1 R} for all R > 0. With the definition of the
operatorTs,µ, these inequalities imply (3.2).
Proof of Lemma 2: This geometrical lemma will be a consequence of the homogeneity property of the euclidean space Rn. Thus the points (3.3) to (3.6) are standard and can be easily seen.
Inequality (3.7) is a consequence of (3.4) since X
l∈I
I(3Ql)(·) =X
l∈I
X
l′∈Il
IQ
l′(·) =X
l′∈I
IQ
l′(·) X
l;l′∈Il
1≤NX
l′∈I
IQ
l′(·)≤N.
Inequality (3.8) comes from the cardinality property (3.5) since X
l∈I
I[(m+1)Ql\(m−1)Ql](·) =X
l∈I
X
j∈Jm,l
IQ
j(·) =X
j∈I
IQ
j(·) X
l;j∈Jm,l
1
≤N mnX
j∈I
IQ
j(·)≤N mn.
§4. Proofs of results
Proof of Theorem 1: We begin by the sufficient part. By Lemma 1, the proof of Js,λ : Lpv →Lqu is reduced to that ofTs,c−2sλ :Lpv → Lqu. Without a loss of generality it can be assumed that c = 1. Take a family of cubes (Ql)l∈I with common sizeL=λ−2s1 (=|Q|n1) as in Lemma 2. So forf(·)≥0 we have
Z
x∈Rn
(Ts,λf)q(x)u(x)dx=X
l∈I
Z
Ql
(Ts,λf)q(x)u(x)dx≤C{S1+S2} where
S1=X
l∈I
Z
Ql
(Ts,λfI
(3Ql))q(x)u(x)dx, S2=X
l∈I
Z
Ql
(Ts,λfI(3Q
l)c)q(x)u(x)dx,
and C > 0 is a constant which depends on n and q. The estimates for S1 are done as follows
S1≤X
l∈I
Z
Ql
(IsfI(3Q
l))q(x)u(x)dx by the definition ofTs,λ
≤CX
l∈I
Z
(3Ql)
f(x)pv(x)dxqp
by the condition (2.1)
≤C Z
x∈Rn
h X
l∈I
I(3Q
l)(x)i
f(x)pv(x)dxpq
since q p≥1
≤CNqp Z
x∈Rn
f(x)pv(x)dxqp
by (3.7).
Let H(c, Q)
= Z
y∈(3Q)c
|xQ−y|(s−n)p′exp{−cL−1|xQ−y|}σ(y)dyp′1 Z
x∈Qu(x)dx1q . Consequently
S2=X
l∈I
Z
x∈Ql
h Z
y∈(3Ql)c
|x−y|s−nexp{−L−1|x−y|}f(y)dyiq
u(x)dx by the definition ofTs,λ
≤CX
l∈I
h Z
y∈(3Ql)c
|xQl−y|s−nexp{−cL−1|xQl−y|}f(y)dyiq
×
× Z
x∈Ql
u(x)dx
by property (3.6)
≤CX
l∈I
[H(c, Ql)]q Z
y∈(3Ql)c
exp{−cL−1|xQl−y|}f(y)pv(y)dyqp by the H¨older inequality
≤CHqX
l∈I
Z
y∈(3Ql)c
exp{−cL−1|xQl−y|}f(y)pv(y)dyq
p
by the condition (2.2)
≤CHq X
l∈I
Z
y∈(3Ql)c
exp{−cL−1|xQl−y|}f(y)pv(y)dypq
since q p ≥1
=CHq X
l∈I
X∞ m=4
Z
y∈[((m+1)Ql)\((m−1)Ql)]
exp{−cL−1|xQl−y|}f(y)pv(y)dxqp
≤CHqX∞
m=4
exp{−c′m}
Z
y∈Rn
h X
l∈I
I[((m+1)Ql)\((m−1)Ql)]yi
f(y)pv(y)dxqp
≤N CHqhX∞
m=4
exp{−c′m}i Z
y∈Rn
f(y)pv(y)dxq
p by (3.8)
≤N C′Hq Z
y∈Rn
f(y)pv(y)dxqp
by the fast decreasing of the exponential function.
Conversely supposeJs,λ :Lpv →Lqu. ThenTs,c2sλ :Lpv →Lqu (by Lemma 1).
LetQbe a cube with|Q|n1 =λ−2s1, andh(·)≥0 a function whose support is 3Q.
The last boundedness implies
(4.1) Z
Q
(Ts,c2sλh)q(x)u(x)dx1
q ≤C Z
(3Q)
h(x)pv(x)dx1
p
for a constantC >0 which does not depend onh(·) andQ. Then for allx∈Q (Ts,c2sλh)(x) =
Z
y∈(3Q)
|x−y|s−nexp{−(c2sλ)2s1 |x−y|}h(y)dy
≥exp{−c′} Z
y∈(3Q)
|x−y|s−nh(y)dy since |x−y| ≤c′λ−2s1
= exp{−c′}(Ish)(x) since the support ofh(·) is (3Q).
This last inequality with (4.1) yields the point (2.1) in Theorem 1. To get (2.2) observe that, by duality,Ts,c2sλ:Lpv→Lqu is equivalent to
Z
y∈Rn
h Z
x∈Rn
|x−y|s−nexp{−(c2sλ)21s|x−y|}f(x)u(x)dxip′
(x)σ(y)dyp′1
≤C Z
x∈Rn
f(x)q′u(x)dxq′1 .
Now take a cubeQwith|Q|n1 =λ−2s1 , andf(·)≥0 equal to 1 in its supportQ.
Then Z
y∈(3Q)c
h Z
x∈Q
|x−y|s−nexp{−(c2sλ)21s|x−y|}u(x)dxip′
(x)σ(y)dyp′1
≤C Z
x∈Q
u(x)dxq′1 . Since|x−y| ≈ |xQ−y|, for allx∈Q,y∈(3Q)c, andR
Qu(x)dx <∞then Z
y∈(3Q)c
|xQ−y|(s−n)p′exp{−c′p′(c2sλ)2s1 |xQ−y|}σ(y)dy1
p′
× Z
x∈Qu(x)dx1
q ≤C
which is the condition (2.2)
Proof of Remark 1: Suppose Js,λ : Lpv → Lqu. Then Ts,c2sλ : Lpv → Lqu and Is : Lp(Q, vdx) → Lq(Q, udx) for all cubes Q with |Q|n1 ≤ λ−2s1. So
|Q|ns+1q−1p(|Q|1 R
Qσ(y)dy)p′1(|Q|1 R
Qu(y)dy)1q ≤C for a constantC >0 not de- pending onQ. By the Lebesgue differentiation theorem, this last inequality yields
0≤ns +1q−1p unlessu(·) = 0 orσ(·) = 0.
Proof of Remark 3: If Js,λ : Lpv → Lqu then Ts,c2sλ : Lpv → Lqu and the condition (2.3) is satisfied. Indeed ifQ1andQ2 are cubes with|Q1|1n =|Q2|n1 = λ−2s1 and Q1∩Q2 6=∅, then |x−y| ≤c′λ−2s1 for x∈Q1 and y ∈Q2, and the operatorTs,c2sλ can be replaced byIs. To see that (2.3) implies (2.1), letQbe a cube with|Q|n1 =λ−2s1 andh(·)≥0 supported in (3Q). By (3.4), (3Q) =S
lQl with|Ql|n1 =|Q|n1,Q=Ql6=∅, and so by (2.3) the condition (2.1) appears since
Z
Q
(Ish)q(x)u(x)dx≤CX
l
Z
Q
(IshIQ
l)q(x)u(x)dx
≤CX
l
Z
Ql
h(x)pv(x)dxq
p
≤C Z
x∈Rn
h X
l
IQ
l(x)i
h(x)pv(x)dxqp
=C Z
(3Q)
h(x)pv(x)dxqp .
Proof of Remark 4: Suppose (2.2) is true. To get (2.4) letQ1, Q2 be cubes with |Q1|1n =|Q2|n1 =λ−21s and dist(Q1, Q2)≈(mλ−21s) wherem ≥4. Since Q2⊂(3Q1)c then, takingQ=Q1 in (2.2) and using|xQ1 −y| ≈dist(Q1, Q2)≈ (mλ−2s1) for ally∈Q2, we obtain (2.4). Conversely suppose this last condition is satisfied for some constantc0>0. For a cubeQwith|Q|n1 =λ−21s andc=c0c−11 , withc1 a fixed constant depending only on n, then
Z
(3Q)c
|xQ−y|(s−n)p′exp{−(2c)λ−2s1 |xQ−y|}σ(y)dy Z
Q
u(x)dxpq′
= X∞ m=4
X
l∈J(m,Q)
Z
Ql
|xQ−y|(s−n)p′exp{−(2c)λ−21s|xQ−y|}σ(y)dy
× Z
Q
u(x)dxpq′
≤C X∞ m=4
X
l∈J(m,Q)
(mλ−2s1)s−nexp{−(2cc1)m} Z
Ql
σ(y)dy Z
Q
u(x)dxp′
q
here |xQ−y| ≈dist(Q, Q1)≈(mλ−21s)
≤C X∞ m=4
ms−nexp{−c0m} X
l∈J(m,Q)
exp{−c0m}(mλ−2s1)s−n Z
Ql
σ(y)dy
× Z
Q
u(x)dxp′
q
≤C′C X∞ m=4
ms−nexp{−c0m} X
l∈J(m,Q)
1 by the condition (2.4)
≤N C′C X∞ m=4
msexp{−c0m}=N C′CC′′ by (3.5).
Proof of Remark 5: Since the arguments are the same, we can suppose that σ(·) satisfies the doubling condition. This hypothesis implies R
(tQ)σ(y)dy ≤ C1tnρR
Qσ(y)dy for all t >1. The constantρ, C1 >0, depend on the doubling condition. Suppose (2.5) is satisfied. To get (2.4) let Q1, Q2 with |Q1|n1 =
|Q2|n1 =λ−2s1 and dist(Q1, Q2)≈(mλ−2s1 ), m≥4. SinceQ2 ⊂(c1mQ1) for a fixed constant c1 (depending only onn), thenR
Q2σ(y)dy ≤R
(c1mQ1)σ(y)dy ≤ C1mnρR
Q1σ(y)dy. With this last inequality the conclusion appears, since for all c >0
exp(−cm)m(s−n)(λ−2s1 )(s−n) Z
y∈Q2σ(y)dyp′1 Z
x∈Q1u(x)dx1
q
≤C2exp(−cm)m[s−n(1−
ρ p′)]
(λ−2s1 )(s−n) Z
Q1σ(y)dyp′1 Z
Q1u(x)dx1q
≤C0C3C2
where C0 is from the condition (2.5) and C3 a constant which exists by the property of the exponential function (limR→∞Rβexp{−γR} = 0, γ > 0) and
does not depend onm.
Proof of Theorem 2: By Theorem 1, Remarks 3 and 4 thenJs,λ:Lpv →Lquiff both (2.3) and (2.4) hold. So we have just to prove that (2.3) implies (2.4). Taking Q1 =Q2 =Q (with |Q|n1 = λ2s1 ) in (2.3) then Is : Lp(Q, vdx) → Lq(Q, udx), with a constant independent of Q. So, as in the proof of Remark 1, (2.5) is satisfied. By Remark 5, this last condition implies (2.4).
Proof of Proposition 3: By Theorem 2 and Remark 2, to getJs,λ:Lpv →Lqu it is sufficient to get (2.3), which can be written as
(4.2) Z
x∈Rn
(Isf)q(x)u(x)e dx1q
≤C Z
x∈Rn
f(x)pev(x)dx1p
for all f(·)≥0.
Here eu(·) = u(·)IQ
2(·), ev(·) = v(·)IQ
1(·) and Q1, Q2 are cubes with |Q1|n1 =
|Q2|n1 = 13λ−21s andQ1∩Q26=∅. We emphasize that C >0 is a constant which does not depend onQ1andQ2. Sawyer and Wheeden [Sa-Wh] proved that (4.2) holds if for somet >1 andS >0
(4.3) |Q|ns+1q−1p 1
|Q|
Z
Qeu(y)tdy1
tq 1
|Q|
Z
Qeσ(y)tdytp′1
≤S
for any cubeQof arbitrary size and where eσ(·) =σ(·)IQ
1(·).
Precisely they foundC =cS where c >0 depends only on s, n, p, q. Of course the constantS >0 in (4.3) must depend onu(·) ande eσ(·). Thus to get (4.2), by using this Sawyer-Wheeden’s result, we have to prove that in our context really S in (4.3) depends only onu(·) andv(·) but not on the cubes Q1 andQ2.
Call A(u,e eσ, Q) the left member of (4.3), and where Q is an arbitrary cube.
First consider the case|(3Q1)|n1 ≤ |Q|n1. Note thatR
Quet(y)dy≤R
Q2ut(y)dy≤ R
(3Q1)ut(y)dy and R
Qeσt(y)dy ≤ R
(3Q1)σt(y)dy. Using these estimates and 1< t <
1 q−1p+1
s
n+1q−p1 then
A(eu,eσ, Q)≤ A(u, σ,(3Q1))≤A.
This last inequality is true since |3Q1|n1 = 3|Q1|n1 ≤ λ−2s1, and A > 0 which depends on u(·), v(·) comes from (2.6). Next suppose |Q|n1 ≤ |3Q1|n1. Since R
Quet(y)dy≤R
Qut(y)dyandR
Qeσt(y)dy≤R
Qσt(y)dy then, again by (2.6), A(eu,eσ, Q)≤ A(u, σ, Q)≤A here |Q|n1 ≤ |3Q1|n1 ≤λ−21s.
ThereforeA(eu,eσ, Q)≤Afor any cube of arbitrary size, and withA >0 indepen- dent ofQ1,Q2. Then (4.2) is satisfied and soJs,λ:Lpv →Lqu.
If moreover bothu(·) andσ(·) satisfy the MuckenhouptA∞condition then, as above, bothu(·) ande eσ(·) satisfyA∞ with constants depending onu(·) andσ(·) but not onQ1 andQ2. It is known from [Sa-Wh] that condition (4.3), witht= 1, is a sufficient condition which ensures the embedding (4.2). Condition (4.3) with t= 1 and a constant S >0 not depending on Q1 and Q2 can be obtained from
(2.7).
Proof of Proposition 4: Choose the family of dyadic cubes (Ql)l∈I, in Lemma 2, with common size equal to 2k, where k is an integer such that 2k ≤λ−2s1 <
2k+1. Again we have to get (4.2) (where Q1 and Q2 are dyadic cubes with
|Q1|n1 =|Q2|n1 = 2k andQ1∩Q26=∅). By the Sawyer’s theorem [Sa-Wh], then (4.2) holds iff for someS >0
(4.4) Z
y∈Rn
(IsσeIQ)q(y)eu(y)dy1q
≤S Z
Qeσ(y)dy1p
and
(4.4∗) Z
y∈Rn
(IsueIQ)p′(y)eσ(y)dyp′1
≤S Z
Qeu(y)dyq′1
for each dyadic cubeQwith an arbitrary size. Therefore it remains to prove that the condition (2.8) (respectively (2.8∗)) implies (4.4) (respectively (4.4∗)) and the corresponding contactS >0 depends only onu(·), σ(·) but not onQ1 and Q2. Conditions (4.4) and (4.4∗) can be written as
(4.5) Z
Q∩Q2
(IsσIQ∩Q
1)q(y)u(y)dy1q
≤S Z
Q∩Q1
σ(y)dy1p and
(4.5∗) Z
Q∩Q2
(IsuIQ∩Q
2)p′(y)σ(y)dyp′1
≤S Z
Q∩Q2
u(y)dyq′1
The crucial fact we use is the well-known property of dyadic cubes which asserts that: for a given closed dyadic cubesQ,Q0 the only cases which can occur are:
(a)Q∩Q0=∅; (b)Q∩Q0=∂Q∩∂Q0; (c)Q⊂Q1; (d)Q1⊂Q.
First take a dyadic cubeQwith|Q|n1 ≤2k. We can assumeR
Q∩Q1σ(y)dy6= 0 (respectively R
Q∩Q2u(y)dy 6= 0) else (4.5) (respectively (4.5∗)) is trivially satis- fied. Suppose Q⊂Q1 (respectively Q⊂Q2). For Q1 6=Q2 then (4.5) (respec- tively (4.5∗)) is trivially satisfied since necessarilyR
Q∩Q2u(y)dy= 0 (respectively R
Q∩Q1σ(y)dy= 0). But forQ1=Q2thenQ∩Q1=Q(respectivelyQ∩Q2=Q) and (4.5) (respectively (4.5∗)) is reduced to
(4.6) Z
Q
(IsσIQ)q(y)u(y)dy1q
≤S Z
Q
σ(y)dy1p (respectively
(4.6∗) Z
Q
(IsuIQ)p′(y)σ(y)dy1
p′
≤S Z
Q
u(y)dy1
q′
).
Since |Q|n1 ≤2k≤λ−21s, then by (2.8) (respectively (2.8∗)) the condition (4.6) (respectively (4.6∗)) is satisfied with S =C, a constant which depends only on u(·) andσ(·).
Next consider 2k<and assumeR
Q∩Q1σ(y)dy6= 0 (respectivelyR
Q∩Q2u(y)dy 6= 0) else there is nothing to prove. IfQ1 ⊂Q(respectively Q2 ⊂Q) then (4.5) (respectively (4.5∗)) is reduced to
(4.7) Z
Q∩Q2
(IsσIQ
1)q(y)u(y)dy1q
≤S Z
Q1
σ(y)dy1p
(respectively (4.7∗) Z
Q∩Q1
(IsuIQ
2)p′(y)σ(y)dyp′1
≤S Z
Q2
u(y)dyq′1 ).
If moreoverR
Q∩Q2u(y)dy6= 0 (respectively R
Q∩Q1σ(y)dy6= 0) then necessarily Q2⊂Q(respectively Q1⊂Q) and (4.7) (respectively (4.7∗)) is the same as
(4.8) Z
Q2
(IsσIQ
1)q(y)u(y)dy1q
≤S Z
Q1
σ(y)dy1p
(respectively (4.8∗) Z
Q1
(IsuIQ
2)p′(y)σ(y)dyp′1
≤C Z
Q2
u(y)dyq′1 ).
Since |Q1|1n =|Q2|1n = 2k ≤λ−21s and Q2 ⊂(3Q1) (respectively Q1 ⊂(3Q2)) then the condition (4.8) (respectively (4.8∗)) is satisfied with S=C by (2.8) (re- spectively (2.4∗)).
Proof of Corollary 5: Letv(·) = (Mspr,λwr)1r(·). It remains to proveJs,λ: Lpv →Lpw. Since one ofw(·) and σ(·) =v−p−11 (·) is a doubling weight function, then by Proposition 3, (2.6) is a sufficient condition in order to get the above em- bedding. So we have to estimate|Q|ns(|Q|1 R
Qwr(y)dy)rp1 (|Q|1 R
Qσr(y)dy)rp′1 = Fr(Q) by a constant which does nor depend on Q with |Q|1n ≤ λ−2s1. By the definition ofMβ,λthenσr(x)≤(|Q|sprn |Q|1 R
Qwr(y)dy)1−p′ for each cubeQwith
|Q|n1 ≤λ−2s1 and for allx∈Q. ConsequentlyFr(Q)≤ |Q|sn(|Q|1 R
Qwr(y)dy)rp1 (|Q|sprn |Q|1 R
Qwr(y)dy)−rp1 = 1.
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Current address:
Institut Polytechnique St.-Louis (EPMI), 13, boulevard de l’Hautil, 95 092 Cergy-Pontoise Cedex, France
E-mail: [email protected] [email protected]
(Received May 13, 1996)