Meagre
Subsets
of
${}^{\omega}[0,1]$and
$\mathcal{B}(l^{2})$Tristan
Bice
March 7,
2010
We generalize Talagrand’s characterization of meagre subsetsof $\mathcal{P}(\omega)$tocertainmeagresubsets
of $\omega X$, where $X$ is
a
topological space like the real unit interval $[0,1]$, and to certain meagresubsets of $\mathcal{B}(l^{2})_{1}$, the collection of bounded linear operators of norm at most 1
on
the Hilbertspace $l^{2}= \{f\in\omega \mathbb{F} : \sum|f(n)|^{2}<\infty\}$ (where $\mathbb{F}=\mathbb{R}$
or
$\mathbb{C}$), with the weak operator topology.We obtain
a
fairly complete characterization of meagre subsets of$\omega X$ thatare
closed under finite(initial segment) changes and, for metric spaces $X$, meagre subsets of $\omega X$ that
are
closed underlimit $0$ changes. To a lesser extent,
we
generalize this to characterize meagre subsets of $\mathcal{B}(l^{2})_{1}$(and the following subsets of $\mathcal{B}(l^{2})_{1}$ –the
norm
$\leq 1$ self-adjoint operators, non-negative operatorsand orthogonal projections) that
are
closed under finite rank and compact operator changes.1
Introduction
Given an interval partition $(I_{n})\subseteq\omega$ and a real $A\subseteq\omega$,
$\mathcal{M}_{A,(I_{r\iota})}$ $=$ $\{B\subseteq\omega:\forall^{\infty}n\in\omega(A\cap I_{n}\neq B\cap I_{n})\}$
$=$
$\bigcup_{m\in\omega}\bigcap_{n\geq m}\{B\subseteq\omega:A\cap I_{n}\neq B\cap I_{n}\}$
is
a
countable union ofclosed nowhere dense sets, and hence meagre, when identifying $\mathcal{P}(\omega)$ with $\omega 2$ with the usual product topology. Conversely, every meagre subset of $\mathcal{P}(\omega)$ is contained ina
set of this form ([1] 5.2). In particular if, for arbitrary $(I_{n})$,
we
let $\mathcal{M}_{(I_{n})}=\mathcal{M}_{\omega,(I_{n})}$ , then $\mathcal{M}_{(I_{n})}$will be
meagre
and closed under taking almost subsets. Conversely,every
meagre subset of $\mathcal{P}(\omega)$closed under taking almost subsets (or
even
just subsets) will be contained in $\mathcal{M}_{(I_{7L})}$, forsome
interval partition $(I_{n})([1]6.27)$. We want to generalize this result in
some
way to functions from$\omega$ to the real unit interval $[0,1]$ and, in turn, to (orthogonal) projections
on
the Hilbert space $l^{2}$(i.e. (linear) operators $P$
on
$H$ thatare
idempotent $(P^{2}=P)$ and self-adjoint $(P^{*}=P)$) withthe weak operator topology (or the strong operator topology,
as
they agree when restricted to justthe projections).
To
see
the motivation for this, letus
first makesome
definitions. Let $H$ bea
fixed infinitedimensional separable Hilbert space (i.e.
a
Hilbert space isometrically isomorphic to $l^{2}$) withsome
fixed orthonormal basis $(e_{n})$. For
any
subspace $V$ of$H$ let $P_{V}$ be the unique orthogonal projectiononto $V$ $(i.e. \mathcal{R}(P_{V})=V)$. For any $A\subseteq\omega$, let $P_{A}=P_{A,(e_{r\iota})}=P_{b}pan\{e_{7L}:n\in A\}$. For
any
$\mathcal{A}\subseteq \mathcal{P}(\omega)$let $P_{A}=\{P_{A} : A\in \mathcal{A}\}$. For any transitive relation $R$
on a
set $S$ and any subset $T$ of $S$ letcl$R(T)=\{s\in S:\exists t\in T(sRt)\}$, the R-closure of$T$. Define transitive relations, for $A,$$B\subseteq\omega$ and
$P,$$Q\in \mathcal{P}(\mathcal{B}(H))$($=$ the projections
on
$H$),as
follows,$A\subseteq*B$ $\Leftrightarrow$ $|A\backslash B|<\infty$.
$A=^{*}B$ $\Leftrightarrow$ $A\subseteq*B\wedge B\subseteq*A$.
$P\leq*Q$ $\Leftrightarrow$ $PQ-P\in \mathcal{K}(H)$($=$ the compact operators
on
$H$).$P=*Q$ $\Leftrightarrow$ $P\leq*Q\wedge Q\leq*P\Leftrightarrow P-Q\in \mathcal{K}(H)$.
We would like to prove the following.
Conjecture 1.1 For any $\mathcal{A}\subseteq y()$ . $c_{\subseteq}\cdot(\mathcal{A})$ is $7’ l$eagre $\dot{\iota}far|d$ only
if
cl$\leq\cdot(P_{\mathcal{A}})$ is meagre.This, in turn, is motivated
bv
wanting to provean
inequality between certain cardinalinvari-ants. In my presentation at RIMS 2009 I discussed
a
number of cardinal invariants defined from$\mathcal{P}(\mathcal{B}(H))/\mathcal{K}(H)$ in analogv with the classical cardinal invariants defined from $\mathcal{P}(\omega)/Fin$. In
par-ticular, I showed how these
new
cardinal invariants could often be related to analogous cardinalinvariants involving interval partitions on $\omega$, essentially due to the fact that projections onto block
subspaces
are
$\leq*$-dense in $\mathcal{P}(\mathcal{B}(H))$. We need 11 to prove sucha
relation between the analogiesof the groupwise density number $\mathfrak{g}$.
Specifically, recall that the (classical) groupwise density number $\mathfrak{g}$ is the minimum cardinality of
a
collection $\mathcal{A}$ of$\subseteq*$-closednon-meagre
subsets of $\mathcal{P}(\omega)$ whose intersection is empty. Equivalently,this is the minimum cardinality of
a
collection $\mathcal{A}\subseteq \mathcal{P}(\mathcal{P}(\omega))$ such that, for all $\mathcal{A}\in \mathcal{A},$ $c1_{\subseteq}*(\mathcal{A})$is non-meagre and, for all $B\subseteq\omega$, there exists $\mathcal{A}\in \mathcal{A}$ such that, for all $A\in \mathcal{A},$ $Bg*A$
.
Let
us
definea
new
cardinal invariant $\mathfrak{g}^{IP}$ to be the minimum cardinality ofa
collection$\mathcal{A}\subseteq \mathcal{P}(\omega)$ such that, for all $\mathcal{A}\in \mathcal{A}$, cl$\subseteq*(\mathcal{A})$ is non-meagre and, for all interval partitions $(I_{n})$ of
$\omega$, there exists $\mathcal{A}\in \mathcal{A}$ such that, for all $A\in \mathcal{A},$ $I_{n}$ and $A$
are
disjoint for infinitely many $n\in\omega$.The first defining property of$\mathcal{A}$ in the definition of $\mathfrak{g}^{IP}$ is the
same
as
that in the definition$\mathfrak{g}$, but
the second defining property is stronger and hence $\mathfrak{g}\leq \mathfrak{g}^{IP}$. It
can
also be proved that $\mathfrak{g}^{IP}\geq b$.Thus
we can
in fact have $\mathfrak{g}\neq \mathfrak{g}^{IP}$, for example in the Hechler model where $b=c=\aleph_{2}$ and $\mathfrak{g}=\aleph_{1}$.Moreover, the proof that $\mathfrak{g}\leq \mathfrak{d}$ given in $[$1]
6.27
in fact shows that $\mathfrak{g}^{IP}\leq \mathfrak{d}$,so
$\mathfrak{g}$IP is, at least, not
always equal to $c$.
Let
us
define yet another cardinal invariant $\mathfrak{g}^{\perp}$as
the minimum cardinality ofa
collection$\mathcal{P}\subseteq \mathcal{P}(\mathcal{P}(\mathcal{B}(H)))$ such that, for all $\mathcal{P}\in \mathcal{P}$, cl$\leq^{r}(\mathcal{P})$ is
non-meagre
and, for all $Q\in \mathcal{P}(\mathcal{B}(H))$,there exists $\mathcal{P}\in \mathcal{P}$ such that, for all $P\in \mathcal{P},$ $Q$ and $P^{\perp}(=1-P=P_{\mathcal{R}(P)^{\perp}})$ have
a
non-trivial(i.e. infinite rank projection) lower bound (w.r.$t$. $\leq*$ which, in particular, implies that $Q\not\leq*P$).
For any infinite rank $Q\in \mathcal{P}(\mathcal{B}(H))$ there exists
a
projection $Q’\leq*Q$ such that $\mathcal{R}(Q’)$ isa
infinitedimensional block subspace, ie. there exists
a
partition $(I_{n})$ of$\omega$ andan
orthonormal basis $(f_{n})$of$\mathcal{R}(Q’)$ such that $f_{n}\in$ span$\{e_{k}\cdot k\in I_{n}\}$ for all $n\in\omega$. If $\mathcal{A}\subseteq \mathcal{P}(\omega)$ is such that, for any $A\in \mathcal{A}$,
there
are
infinitely many $n\in\omega$ such that $I_{n}$ is disjoint from $A$ then there exists infinitely many $n\in\omega$ such that $f_{n}\in \mathcal{R}(P_{A})^{\perp}=\mathcal{R}(P_{A}^{\perp})$ andso
the projection onto the closed linear span of allthese $f_{n}$ will be a non-trivial lower bound of $P_{A}^{\perp}$ and $Q’$, and hence $Q$. Thus if
we
could prove 1.1,in particular if
we
could show that if$\mathcal{A}\subseteq \mathcal{P}(\omega)$ is such that cl$\subseteq\cdot(\mathcal{A})$ is non-meagre then cl$\leq\cdot(P_{A})$is also non-meagre, then it would follow that $\mathfrak{g}^{\perp}\leq \mathfrak{g}^{IP}$.
At first sight it might
seem
silly to be always taking $\subseteq*$ and $\leq*$ closures. Instead,one
mightsiniply deal only with $\mathcal{A}$ that
are
already $\subseteq*$-closed. Indeed, if $A\subseteq*B$ then $P_{A}\leq*P_{B}$so
1.1 isequivalent to saying that, for
any
$\subseteq*$-closed $\mathcal{A}\subseteq \mathcal{P}(\omega),$ $\mathcal{A}$ ismeagre
if and only if cl$\leq*(P_{A})$ ismeagre.
However,we
stillcan
not replace cl$\leq*(P_{A})$ with $P_{\mathcal{A}}$or even
cl$=\cdot(P_{\mathcal{A}})$ because, forany
infinite $A\subseteq\omega$, there will be many projections $P\leq*P_{A}$ that
are
not of the form $P_{B}$ forsome
$B\subseteq*A$ or even $=*$-equivalent to a projection of this form. Indeed, the conjecture will false if wedo that replacement, as cl$=\cdot(P_{9(\omega)})$ is meagre. In fact, cl$=*(P_{9(\omega)})$ is good meagre, as defined
by Zamora-Aviles in [2] (and
even
very good meagre,as
I show in 3.26).Before reviewing and extending the Zamora-Aviles theory of good meagre sets, let
us
lookat nowhere dense and meagre subsets of countable products of topological spaces (like $[0,1]$)
as
these
are
interesting in their own right and provide a good basis for studying operatorson
Hilbertspaces. Furthermore,
as we
will see,we
can
obtaina more
complete understanding in thecase
ofcountable products of topological spaces – unfortunately,
some
of the results in thiscase
to notseem to easily generalize to the
case
of operatorson
Hilbert spaces.2
Countable Products of Topological Spaces
For the rest of this section $X$ is
a
topologicalspace
and $\omega X$ is given the standard product topology,i.e. the sets $O_{0}\cross$ . . $\cross O_{n-1}\cross\omega\backslash nX=\{f\in\omega X\cdot\forall k\in n(f(k)\in O_{k})\}$, for $n\in\omega$ and open
subsets $O_{0}$, , $O_{n-1}$ of $X$, form
a
basis for the topology of $WX$. For $\mathcal{F}\subseteq\omega X$ and $A\subseteq\omega$we
Definition 2.1 A subset $Y$
of
$X$ is nowhere dense in $X$if
$X\backslash \overline{Y}$ is dense in X. Equivalently, $Y$ isnowhere dense if,
for
euery non-ernpty open subset $O$of
$X$, there exists a non-ernpty open subset$O’$
of
$O$ disjointfrom
Y. A subset $Y$of
$X$ is meagre in $X$if
it is a countable unionof
nowheredense sets.
Proposition 2.2 For any $\mathcal{F}\subseteq\omega X_{f}$ the following are equivalent.
(z) For all $n\in\omega,$ $\mathcal{F}|\omega\backslash n$ is
not
dense in $\omega\backslash nX$.(ii) For all $n\in\omega,$ $\mathcal{F}r\omega\backslash n$ is nowhere dense in $\omega\backslash nX$.
(iii) For all $n\in\omega$ there exists $m\geq n$ and non-empty open $O_{n},$
$\ldots,$$O_{m-1}\subseteq X$ such that $\{f\in\omega_{X} : \forall k\in m\backslash n(f(k)\in O_{k})\}$
$xs$ disjoint
from
$\mathcal{F}$.Proof:
$(iii)\Rightarrow$(ii) Assume (iii), fix $n\in\omega$ and take any basic open set $B=\{f\in\omega\backslash nX:\forall k\in j\backslash n(f(k)\in O_{k})\}$
of $\omega\backslash nX$, where
$j\in\omega\backslash n$ and $O_{n},$
$\ldots,$$O_{j-1}$
are
non-empty open subsets of $X$. Take $m\geq j$and
open
$O_{j},$$\ldots,$$O_{m-1}$ such that $\{f\in\omega X : \forall k\in m\backslash j(f(k)\in O_{k})\}$ is disjoint from
$\mathcal{F}$.
Then $\{f\in\omega X : \forall k\in m\backslash n(f(k)\in O_{k})\}$ is also disjoint from $\mathcal{F}$ which is equivalent to saying
$\{f\in\omega\backslash nX : \forall k\in m\backslash n(f(k)\in O_{k})\}\subseteq B$ is disjoint from $\mathcal{F}r\omega\backslash n$.
$(ii)\Rightarrow(i)$ Immediate.
$(i)\Rightarrow(iii)$ Immediate. $\square$
Definition 2.3 Any$\mathcal{F}\subseteq\omega X$ satisfying any
of
the equivalent conditions in the proposition aboveis said to be good nowhere dense. A countable union
of
good nowhere dense sets $\iota s$ said to be goodmeagre.
Proposition 2.4 Good nowhere dense sets
are
closedunder subsets,finite
unions and topologicalclosures.
Proof: Follows from characterization (ii) aboveand thecorresponding closures for nowhere dense
sets as $\mathcal{F}\subseteq \mathcal{G}\Rightarrow \mathcal{F}r\omega\backslash n\subseteq \mathcal{G}|\omega\backslash n,$$\mathcal{F}\cup \mathcal{G}r\omega\backslash n=\mathcal{F}r\omega\backslash n\cup \mathcal{G}r\omega\backslash n$ and $\overline{\mathcal{F}}|\omega\backslash n\subseteq\overline{\mathcal{F}r\omega\backslash n}$
for all $\mathcal{F},$$\mathcal{G}\subseteq\omega X$ and $n\in\omega$. $\square$
Lemma 2.5 Any $\mathcal{F}\subseteq\omega\backslash nX$ will be nowhere dense in$\omega\backslash nX$
if
and onlyif
$\{f\in\omega X$ : $f[\omega\backslash n\in \mathcal{F}\}$is nowhere dense in $\omega X$.
Proposition 2.6
If
$X\iota s$ anyfinite
set with the discrete topology then any nowhere dense subset $\mathcal{N}$of
$\omega X$ is good nowhere dense.Proof: If$\mathcal{N}$is not good nowhere densethen there exists $n\in\omega$ such that$\mathcal{N}r\omega\backslash n$ is not nowhere
dense. Wlog
assume
$X=|X|=\{0, \ldots, |X|-1\}$ and, for each $t\in X^{n}$, define $f+t\in\omega X$ by$(f+t)(k)=f(k)+t(k)mod X$
for $k\in n$ and$(f+t)(k)=f(k)$
for $k\in\omega\backslash n$. For each $t\in X^{n}$, themap $f\mapsto f+t$ is
a
homeomorphismso
if$\mathcal{N}$ is nowhere dense thenso
is $\mathcal{N}+t=\{f+t:f\in \mathcal{N}\}$.Then $\{f\in\omega X : f\lceil\omega\backslash n\in \mathcal{N}r\omega\backslash n\}=\bigcup_{t\in X}$
..
$\mathcal{N}+t$ is also nowhere dense which, by the abovelemma,
means
$\mathcal{N}r\omega\backslash n$ is nowhere dense,a
contradiction. $\square$The problem is, of course, that when $X$ is not finite there will be other nowhere dense sets.
Indeed,
as
longas
$X$ contains $\{x\}$ that is closed and not open (i.e. not isolated) thenwe see
that$\{f\in\omega X : f(O)=x\}$ is nowhere dense but not good nowhere dense. This gave
me
the idea thatperhaps these
are
the only other kinds of nowhere dense sets. However,as
the counterexampleProposition 2.7 For each $n\in\omega$, let $\mathcal{N}_{n}=\{f\in\omega[0,1]\cdot f(n)=nf(0)\}$. Then $\mathcal{N}=\cup \mathcal{N}_{n}$ is
closed nowhere dense in $\omega[0,1]$ but not good nowhere dense
nor
contained in $N\cross\omega\backslash nX$for
any $n\in\omega$ and nowhere dense subset $N$of
$n[0,1]$ .Proof: If $f\in\omega[0,1]\backslash \mathcal{N}$ then $f(O)\neq 0$,
as
$\mathcal{N}_{0}=\{0\}\cross\omega\backslash \{0\}[0,1]$,so we
may let$m= \max\{n\in\omega. nf(0)\leq 2\}$ and $\epsilon=\min\{|f(n)-nf(0)|/(2n) : n\in m\backslash \{0\}\}$.
Then $\{g\in\omega[0,1] : |f(0)-g(O)|<\epsilon\wedge\forall n\in m|f(n)-g(n)|<|f(n)-nf(0)|/2\}\ni f$ is
a
basicopen
set disjoint from $\mathcal{N}$ which,as
$f$was
arbitrary, shows that $\mathcal{N}$ is closed. Furthermore, for anybasic open set $B=\{f\in\omega[0,1] : \forall k\in n(f(k)\in O_{k})\}$ , for non-empty open subsets $O_{0},$
$\ldots,$$O_{n-1}$ of
$[0,1]$,
we
may pick $f\in\omega[0,1]$ such that $f(0)\in O_{0}\backslash \{0\}$ and $f(k)\in O_{k}\backslash \{kf(0)\}$, for all $k\in n\backslash \{0\}$,and hence $f\in B\backslash \mathcal{N}$, i.e. $\mathcal{N}$ is closed nowhere dense. However,
we
have $\mathcal{N}_{0}r\omega\backslash \{0\}=^{\omega\backslash \{0\}}[0,1]$so
$\mathcal{N}$ is not good nowhere dense. Lastly, take any $n\in\omega$ and nowhere dense $N\subseteq n[0,1]$. Thenthere exists open $O_{0},$
$\ldots,$$O_{n-1}$ such that $O_{0}\cross\ldots\cross O_{n-1}$ is disjoint from $N$ and $\sup O_{n}\leq 1n$
.
Picking any $f\in\omega[0,1]$ such that $f(k)\in O_{k}$ for all $k\in n$ and $f(n)=nf(0) \leq n\sup O_{0}\leq 1$,
we
see
that $f\in \mathcal{N}\backslash N\cross\omega\backslash n[0,1]$. $\square$Note, however, that, for
every
$n\in\omega,$ $\mathcal{N}_{n}$ is indeeda
subset of $N_{n}\cross\omega\backslash n[0,1]$ fora
nowheredense $N_{n}\subseteq[0.1]^{n}$. This begs the following question.
Question 2.8 For $X=[0,1]$
or some
non-trivial classof
topological spaces $X$, is every nowheredense $\mathcal{M}\subseteq\omega X$ either good nowhere dense
or
a subsetof
some
$\mathcal{N}=\cup N_{n}\cross\omega\backslash nX$ where $N_{n}\iota s$nowhere dense in $nX$
for
each $n\in\omega$? Whatif
we
further
require$\mathcal{N}$ to be nowhere dense? Is everymeagre $\mathcal{M}\subseteq\omega X$ a subset
of
$some\cup \mathcal{N}_{n}\cup N_{n}\cross\omega\backslash nX$ where $N_{n}$ is nowhere dense in $nX$ and$\mathcal{N}_{n}$is good nowhere dense
for
each $n\in\omega$?If the
answer
to the first question isyes
thenso
is theanswer
to the last, but unfortunatelyI do not know
more
than that for general nowhere dense and meagre subsets of $\omega X$. However, Ican
obtainsome
relations between good meagre sets and meagre sets thatare
closed under thefollowing relations.
Definition 2.9 For any set $X$ and any $f,$ $g\in\omega X$
define
$f=_{\dot{X}}g\Leftrightarrow\forall^{\infty}n\in\omega(f(n)=g(n))$.
If
$X$ is a $met\tau\eta c$ space thendefine
$f=_{X}*g\Leftrightarrow d(f(n), g(n))arrow 0$.
We drop the $X$ subscript when it is clear
from
the context.First
we
finda
nice collection ofsets whichare
cofinal in the ideal ofgood nowhere dense sets. Lemma 2.10 For any $g\in\omega X$, interval partition $(I_{n})$of
$\omega$ and $m\in\omega$,$\{f\in\omega X\cdot\exists n\in\omega\backslash m(f|I_{n}=g(I_{n})\}$
$\iota s$ dense in $\omega X$.
Proposition 2.11 For any sequence
of
non-empty open subsets $(O_{n})$of
$X$, any interval partition$(I_{n})$
of
$\omega$ and $m\in\omega$,$\mathcal{N}_{(O_{r1}),(I_{tl})_{7}n}=\{f\in\omega X : \forall n\in\omega\backslash m\exists k\in I_{n}(f(k)\not\in O_{k})\}$
is closed good nowhere dense. Furthermore, anygood nowhe$7^{\cdot}e$ dense$\mathcal{N}\subseteq\omega X$ is contained in such
Proof: We have $\mathcal{N}_{(O,1),(I_{(\iota}),\tau n}=\bigcap_{\iota\in\omega\backslash m}\bigcup_{k\in I_{\iota}},\{f\in\omega X f(k)\in X\backslash O_{k}\}$, which is closed. Good
nowhere density is immediate from 2.2(iii).
On
the other hand, givena
good nowhere dense$\mathcal{N}\subseteq\omega X$ recursively choose an interval partition $(I_{r\iota})$ and open subsets $(O_{n})$ of $X$ such that
$\min(I_{n})=\max(I_{n-1})+1(=0 if n=0)$ and $\{f\in\omega X \forall k\in I_{n}(f(k)\in O_{k})\}$ is disjoint from $\mathcal{N}$.
Then $\mathcal{N}\subseteq \mathcal{N}_{(O_{\gamma 1}),(I_{lI}),0}$ . $\square$
Likewise,
we
have nice collection of sets whichare
cofinal in the $\sigma$-ideal of goodmeagre
sets.Proposition 2.12 For any sequence
of
non-empty open subsets $(O_{n})$of
$X$ and any intervalpar-tition $(I_{n})$
of
$\omega$,$\mathcal{M}_{(O_{\iota}),(I_{n})}=\bigcup_{m}\mathcal{N}_{(O_{r\iota}),(I_{\iota}),m}=\{f\in\omega X:\forall^{\infty}n\in\omega\exists k\in I_{n}(f(k)\not\in O_{k})\}$
$is=$ -closed good meagre $F_{\sigma}$. Furthermore, any good meagre $\mathcal{M}\subseteq\omega X\iota s$ contained in such
a
set.Proof: The first part is immediate.
On
the other hand, givena
sequence $(\mathcal{N}_{n})$ of nowheredense subsets of$X$, recursively choose
an
interval partition $(I_{n})$ and open subsets $(O_{n})$ of $X$ suchthat $\min(I_{n})=\max(I_{n-1})+1(=0 if n=0)$ and $\{f\in\omega X : \forall k\in I_{n}(f(k)\in O_{k})\}$ is disjoint
from $\bigcup_{k\in 7l}\mathcal{N}_{k}$, which is possible because
a
finite union of good nowhere dense sets is again goodnowhere dense. Then the meagre set $\mathcal{M}=\cup \mathcal{N}_{n}$ is
a
subset of $\mathcal{M}_{(O_{r\iota}),(I_{r\iota})}$. Alternatively,one
may first find $(O_{rn}^{n})$, and (I;) such that $\mathcal{N}_{m}\subseteq \mathcal{N}_{(O_{n}^{rn}),(I_{r\iota^{J\iota}}^{r}),0}$, for all $m\in\omega$, and then recursively
define $(I_{n})$ and $(n_{j,k})_{j\in\omega,k\in j+1}$, such that for each $j\in\omega,$ $(I_{n_{j}}^{k}k)_{k\in j+1}$
are
disjoint subsets of $I_{j}$$($and $\min(I_{j})=\max(I_{j-1})+1(=0$ if$j=0))$ and for all $j\in\omega,$ $k\in j+1$ and $l\in I_{n_{g,k}}^{k},$ $O_{l}=O_{n_{g,k}}^{k}$.
Then letting $O_{n}=X$ for those $n \in\omega\backslash \bigcup_{j\in\omega,k\in j+1}I_{n,k}^{k}$ (i.e. those $n\in\omega$ for which $O_{n}$ has not yet
been defined)
we see
that $\mathcal{M}=\cup \mathcal{N}_{n}\subseteq \mathcal{M}_{(O_{r\iota}),(I_{\iota})}$. $\square$The
more
interesting result is thatwe can
obtaina
converse
of this for suitable $X$.Theorem 2.13
If
$X$ is compact and $\mathcal{F}\subseteq\omega X$ $is=$ -closed $F_{\sigma}$ then,for
any $f\in\omega X\backslash \mathcal{F}$ thereexists an interval partition $(I_{n})$
of
$\omega$ together with $(O_{n})$ such that $O_{n}$ is an open subsetof
$X$containing $f(n)$,
for
each $n\in\omega$, and $\mathcal{F}\subseteq \mathcal{M}_{(O_{r\iota}),(I_{JL})}$Proof: Let $\mathcal{F}=\cup \mathcal{N}_{n}$ for closed subsets $(\mathcal{N}_{n})$ of$X$. Define $(O_{n})$ and $(I_{n})$ recursively
as
follows.Let $\min(I_{n})=\max(I_{n-1})+1(=0 if n=0)$ and, for all$t \in\min(I_{r\iota})X$ set $f_{t}(k)=t(k)$ for $k \in\min(I_{n})$
and $f_{t}(k)=f(k)$ for $k \in\omega\backslash \min(l_{n})$. As $\mathcal{F}$ is $=$ -closed, $f_{t}\not\in \mathcal{F}$ and
we can
find $n_{t} \in\omega\backslash \min(I_{n})$and open $O_{k}^{t}\ni f_{t}(k)$, for all $k\in n_{t}$, such that $O_{0}^{t}\cross\ldots\cross O_{n_{t}-1}^{t}\cross\omega\backslash n{}^{t}X$ is disjoint from the
closed set $\bigcup_{k\in n}\mathcal{N}_{k}(\subseteq \mathcal{F})$ . As $\min(I_{7L})X$ is compact, there exists $m_{n}\in\omega$ and $t_{0},$
$\ldots,$$t_{m_{\mathfrak{n}}-1}$ with $\min(I_{\iota})X\subseteq\bigcup_{j\in m_{7l}}\prod_{k\in\min(I_{1\iota})}O_{k}^{t_{)}}$. Let $\max(I_{n})=\max\{n_{t_{k}} : k\in m_{n}\}$ and, for all $k\in I_{n+1}$, let $O_{k}= \bigcap_{j\in m_{7L}}O_{k}^{t_{j}}\ni f_{t},$ $(k)=f(k)$ (for $k\geq n_{t_{j}}$ set $O_{k}^{t_{j}}=X$ in this intersection). This completes
the recursion and
now
note that if $n\in\omega$ then $g| \min(I_{n})\in\prod_{k\in\min(I_{n})}O_{k}^{t_{j}}$, forsome
$j\in m_{n}$,so
if $g(k)\in O_{k}\subseteq O_{k}^{t_{j}}$ for all $k\in I_{n}$ then $g \not\in\bigcup_{k\in n}\mathcal{N}_{k}$. Thus if there
are
infinitely many $n\in\omega$ suchthat $g(k)\in O_{k}\subseteq O_{k}^{t}$’ for all $k\in I_{n}$ then $g\not\in \mathcal{F}$, i.e. $\mathcal{F}\subseteq \mathcal{M}_{(O_{7L}),(I_{n})}$. $\square$
Note that this theorem holds, with exactly the
same
proof, ifwe
replace $\omega X$ witha
closedsubset $\mathcal{X}$ of $\omega X$.
Corollary 2.14
If
$X$ is compact and $\mathcal{F}\subseteq\omega X$ $is=$ -closed meagre $F_{\sigma}$ then $\mathcal{F}$ is good meagre.Proof: As $X$ is compact, $\omega X$ is also compact, by Tychonoff’s Theorem, and hence a Baire space,
by the Baire Category Theorem. So there exists $f\in\omega X\backslash \mathcal{F}$and the result
now
follows from2.13
Corollary 2.15
If
$Xl_{\iota}5$ compact then $\mathcal{F}\subseteq\omega XlS$ good meagreif
and only $\dot{\iota}f\mathcal{F}$ is contained in a $=$ -closed $\mathcal{T}’\iota eagreF_{\sigma}$.Proof: Follows from 2.14 and (the second part of) 2.12. $\square$
Question 2.16 For cornpact $X$, is every $=$ -closed
meagre
$\mathcal{M}\subseteq\omega X$ contained in $a=$ -closedmeagre $F_{\sigma}$
subset?
Can
every $=$ -closedrneagre
$\mathcal{M}\subseteq\omega X$ be writtenas
$\mathcal{M}=\cup \mathcal{N}_{n}$ where,for
all $n\in\omega,$ $\mathcal{N}_{n}\iota s$ nowhere dense and cl$=\cdot(W_{n})\iota s$ meagre?Note that a positive
answer
to the second question would implya
positiveanswer
to the first.For then
we
could find nowhere dense $(\mathcal{N}_{t})_{t\in\omega}<\omega$ such that $c1_{=}\cdot(\overline{\mathcal{N}_{n_{0},\ldots,n_{k}}})=\bigcup_{m}\mathcal{N}_{n_{0},\ldots,n_{k},m}$ forall $k,$$n_{0}$, . . ,$n_{k}\in\omega$ and $\mathcal{F}=\cup \mathcal{N}_{n}\subseteq\bigcup_{t\in\omega}<\omega\pi_{t}$, where this last set is $=$ -closed meagre $F_{\sigma}$. Also
note the
answer
to the second question would be negative if the last ‘meagre’were
to be replacedby ‘nowhere dense’, indeed, every non-empty $=$ -closed set is dense and hence not nowhere dense.
However, the
answer
to the first question above is positive if $X$ isa
metric space and the first(and even the second) $=$ is replaced by $=*$, as shown below in 2.21.
For the rest of this section, $X$ is not just
a
topological space but a metric space.Definition
2.17
A subset $\mathcal{F}\subseteq\omega X$ isvery
good nowhere denseif
there exists $\epsilon>0$ such that,for
all $n\in\omega$, there exists $m\geq n$ and $t\in m\backslash nX$ such that$\{f\in\omega X\cdot\forall k\in m\backslash n|f(k)-t(k)|<\epsilon\}$
is disjoint
from
$\mathcal{F}.$ A countable unionof
very good nowhere dense sets $\iota s$ very good meagre.Proposition 2.18 The very good nowhere dense sets
are
closed under subsets,finite
unions andtopological closures.
Like before,
we
havea
nice collection ofsets whichare
cofinal in the ideal ofvery good meagresets,
Proposition 2.19 For any $\epsilon>0,$ $g\in\omega X$, interval partition $(I_{n})$
of
$\omega$ and $m\in\omega$, $\mathcal{N}_{\epsilon,g,(I_{ll}),m}=\{f\in\omega X : \forall n\in\omega\backslash m\exists k\in I_{n}|f(k)-g(k)|\geq\epsilon\}$is closed very good nowhere dense. Furthermore, any very good nowhere dense $\mathcal{N}\subseteq\omega X$ is
con-tained in such a set, with $m=0$ in
fact.
Proof: Proved analogously to 2.11. $\square$
Likewise, we have nice collection of sets which
are
cofinal in the $\sigma$-ideal of very good meagresets.
Proposition 2.20 For any $g\in\omega X$ and any interval partition $(I_{n})$
of
$\omega$,$\mathcal{M}_{g,(l_{r\iota})}=\bigcup_{\tau n}\mathcal{N}_{1/\tau n,g,(I_{\iota}),\gamma n}=\{f\in\omega X:\lim\inf_{nk\in}\max_{I_{tl}}|f(k)-g(k)|>0\}$
$is=*- cl_{0_{t}9}ed$ nery good meagre $F_{\sigma}$. Furthermore, any very good meagre $\mathcal{M}\subseteq\omega X$ is contained in
such a set.
Proof: Proved analogously to 2.12. $\square$
We again have
a
converse
of this for suitable $X$.Theorem 2.21
If
$X$ is compact and$\mathcal{F}\subseteq\omega X$ $is=*$-closed meagre then there exists $g\in\omega X$ andProof: Let $\mathcal{F}=\cup \mathcal{N}_{n}$ for nowhere dense $(\mathcal{N}_{r\iota})$. Recursively define a sequence $(n_{m})\subseteq\omega$,
an
interval partition $(I_{m})$ of $\omega$, open subsets $(O_{m,k}\subseteq I_{7\prime\iota X)_{m\in\omega,k\in n_{n}}}$, and, for each $m\in\omega$, open
subsets $(B_{t} \subseteq\min(I_{\iota},)X)_{t\in n_{0}\cross\ldots\cross n,,-1}|$
as
follows. First set $B_{0}=0$, take arbitrary $I_{0}$ and open$O_{0,0}\subseteq I_{0}X$ of diameter $<1$ in each coordinate.
Once
$n_{m-1}$, if $m>0,$ $(B_{t})_{t\in n_{0}\cross\ldots\cross n_{m-1}},$ $I_{m}$ and $O_{m,0}$ have been defined take $n_{rr\iota}$ and open $(O_{rn,k})_{k\in n_{1}\backslash \{0\}}$ of $I_{rr\iota X}$, each of diameter $<1/(m+1)$in each coordinate, such that $\bigcup_{k\in n_{I}},,O_{m,k}=I_{rr\iota}X$. Let $(t_{k})_{k\in n_{O}n_{1}..n}$,. enumerate $t\in n_{0}\cross\ldots\cross n_{m}$.
Recursively define ($B_{t}\subseteq nlin(I_{r;\iota+1})_{X)_{t\in n_{(}\cross}}$
$\cross n_{1\iota}$ and
$(Y_{t} \subseteq\omega\backslash \min(I_{\tau n+1})_{X)_{t\in n_{0}\cross}}$
$\cross n_{/\iota}$ by letting
$B_{t},$ $\cross Y_{t_{j}}$ be
a
non-empty open subset disjoint from $\bigcup_{k<m+1}\mathcal{N}_{k}$ such that$\overline{B_{t_{j}}\cross Y_{t},}\subseteq B_{t_{j}(m}\cross O_{m,t_{j}(m)}\cross Y_{t_{j}-1}$ (with $Y_{t_{-1}}= \omega\backslash \min(I_{m+1})X$ by convention).
Then take $\max(I_{m+1})+1=\min(I_{m+2})$ large enough that
we can
find $O_{m+1,0}\subseteq I_{m+1}X$, ofdiameter less than $1/(m+2)$ in each coordinate, such that $O_{m+1,0} \cross\omega\backslash \min(I_{m+2})X\subseteq Y_{t_{n_{O}r\iota_{1}\ldots n_{m}}}$ .
This completes the recursion.
Let $g\in\omega X$ be such that $g|I_{7n}\in O_{m,0}$ for all $m\in\omega$. Take any $f\in\omega X\backslash \mathcal{M}_{g,(I_{r\iota})}$ and
let $A\in[\omega]^{\omega}$ be such that $\lim_{narrow\infty}\max_{k\in I_{(x_{r\iota}}}|f(k)-g(k)|=0$, where $(a_{n})$ is the increasing
enumeration
of
$A$.For
each $m\in A$, let $h(m)=0$ and,for
each $m\in\omega\backslash A$, let $h(m)\in n_{m}$ besuch
that $f\lceil I_{m}\in O_{m,h(m)}$. Choose $f’ \in\bigcap_{k}B_{hrk}\cross\omega\backslash \min(I_{k})X=\bigcap_{k}\overline{B_{hrk}}\cross\omega\backslash \min(I_{k})_{X}$ , noting that
this last expression is non-empty because it is
an
intersection of non-empty decreasing compactsets. For each $m\in A$
we
have$f’ \in B_{hrm}\cross O_{rr\iota,0}\cross^{\omega\backslash \min(I_{rn+1})}X\subseteq B_{hrm}\cross Y_{hrm}\subseteq\omega x\backslash \bigcup_{k<m}\mathcal{N}_{k}$
which,
as
$A$ is infinite, implies $f’\not\in\cup \mathcal{N}_{k}$. Furthermore, byour
choice of $h,$ $|f(n)-f’(n)|arrow 0$and hence $f\not\in\cup \mathcal{N}_{k}$,
as
$\mathcal{F}$ is $=*$-closed. As $f$was
arbitrarywe
have $\mathcal{F}\subseteq \mathcal{M}_{g,(I_{n})}$. $\square$Corollary 2.22
If
$X$ is compact and $\mathcal{F}$ $is=*$-closed meagre then $\mathcal{F}\iota s$ very good meagre.Corollary 2.23
If
$X$ is compact then $\mathcal{F}$ is very good meagreif
and onlyif
$\mathcal{F}\iota s$ contained ina
$=*$-closed meagre set.
3
Operators
on a
Hilbert Space
In this section
we
will be dealing with the collection of bounded linear operators $\mathcal{B}(H)$on
a
separable infinite dimensional Hilbert space $H$ (i.e.
a
Hilbert space $H$ isometrically isomorphic to$l^{2})$ with the weak operator topology, i.e. the weakest topology in which, for each $x,$ $y\in H$, the
functions $T\mapsto\langle Tx,$$y\rangle$
are
continuous. Ifwe
are
dealing witha
uniformly bounded subcollection $\mathcal{B}$ofsuch operators and
we
fixa
basis $(e_{n})$ of$H$ then sets of the form $\{T\in \mathcal{B} : ||P_{n}(S-T)P_{n}||<\epsilon\}$,for $\epsilon>0,$ $n\in\omega$ and $S\in \mathcal{B}$, form a basis for this topology. We will also have occasion to mention
the strong operator topology, i.e. the weakest topology in which, for each $x\in H$, the functions
$7”\mapsto Tx$
are
continuous. Again, ifwe are
dealing with a uniformly bounded subcollection $\mathcal{B}$ ofsuch operators and
we
fixa
basis $(e_{n})$ of $H$ then sets of the form $\{T\in \mathcal{B} : 1 (S-T)P_{n}||<\epsilon\}$, for$\epsilon>0,$ $n\in\omega$ and $S\in \mathcal{B}$, form
a
basis for this topology. It follows that both of these topologiesare
second countable when restricted toa
uniformly bounded subcollection and hence, being(completely) regular (as, indeed,
are
all Hausdorff topological vector spaces) also metrizable, byUrysohn’s metrization theorem, which, in particular, implies that all closed subsets
are
$G_{\delta}$. Alsonote that both the weak and strong operator topologies
are coarser
than thenorm
topology.Definition 3.1 Let $\mathcal{B}(H)^{+/-},$ $\mathcal{B}(H)^{+}$ and $\mathcal{P}(\mathcal{B}(H))$ be the collection
of
$self- ad_{J}oint$ operators,$oper\cdot ator6irl\mathcal{B}$
of
norm at most $/^{\tau}$.$\mathcal{B}(H)^{+/-}$ $=$ $\{T\in \mathcal{B}(H) T=T^{*}\}$.
$\mathcal{B}(H)^{+}$ $=$ $\{T\in \mathcal{B}(H) \forall x\in H(\langle Tx, x\cdot\rangle\geq 0)\}=\{T^{*}T T\in \mathcal{B}(H)\}$ . $\mathcal{P}(\mathcal{B}(H))$ $=$ $\{T\in \mathcal{B}(H)\cdot T^{2}=T\wedge T=T^{*}\}$.
$\mathcal{B}_{7}$. $=$ $\{T\in \mathcal{B} ||T||\leq r\}$.
For what follows
we
needa
couple of technical lemmas about projections.Definition 3.2 Let $P_{L}$ and $P_{R}$ be the projections $H\oplus Harrow H$ onto the
first
and second coordinaterespectively and let $I_{L}$ and $I_{R}$ be the in$J^{}$ $Harrow H\oplus H$ into the
first
and second coordinaterespectively. Let $P_{L}’=I_{L}P_{L}$ and $P_{R}’=I_{R}P_{R}$
Proposition 3.3 ([2] 3.1.8.) For any $T\in \mathcal{B}(H)_{1}^{+}$ there exists a proJection $P$
on
$H\oplus H$ suchthat $T=P_{L}PI_{L}$. (Equivalently,
for
any $T\in \mathcal{B}(H\oplus H)_{1}^{+}$ such that $P_{L}’TP_{L}’=T$ there exists aprojection $P$
on
$H\oplus H$ such that $T=P_{L}’PP_{L}’.$)Proof:
As
$T$ is non-negative and ofnorm
at most 1, $T-T^{2}$ is also non-negative andhence
has
a
non-negative square root $\sqrt{T-T^{2}}$. Thuswe
may let $P$ be the operator whose matrixrepresentation is
$P=[_{\sqrt{T-T^{2}}}T$ $\neg_{1-T}^{T-T^{2}}$
.
i.e. $P=(TP_{L}+\sqrt{T-T^{2}}P_{R})\oplus(\sqrt{T-T^{2}}P_{L}+(1-7\urcorner)P_{R})$, which is immediately verified to satisfy
$P^{2}=P$ and $P^{*}=P$. $\square$
For the next lemma, note that if $(’I_{n}),$$(S_{n})\subseteq \mathcal{B}(H)$
are
such that $(T_{n})$ is uniformly bounded, $T_{r\iota}arrow sT$ and $S_{n}arrow 6S$ then $T_{n}S_{n}arrow 6TS$. Also note that, for any $S\in \mathcal{B}(H)^{+}$ and $x\in H$,$||\sqrt{S}x\cdot||^{2}=\langle Sx,$$x\rangle\leq||Sx||||x||$ so if $S_{n}arrow s0$ then $\sqrt{S_{n}}arrow s0$.
Lemma 3.4 For any $Q\in \mathcal{P}(\mathcal{B}(H)),$ $n\in\omega$ and $\epsilon>0$, there exists $m\in\omega\backslash n$ and $P\in \mathcal{P}(\mathcal{B}(H))$
such that $P_{2\tau n}PP_{2n\iota}=P,$ $P_{7n}PP_{7’ 1}=P_{7n}QP_{rn}$ and $||(P-Q)P_{n}||<\epsilon$.
Proof: We have $P_{\tau n}QP_{\tau n}arrow 6Q$ which,
as
$Q^{2}=Q$, gives $\sqrt{P_{7n}QP_{7n}-(P_{m}QP_{m})^{2}}arrow s0$. Let$m\geq n$ be large enough that $||\sqrt{P_{m}QP_{rr\iota}-(P_{rn}QP_{m})^{2}}P_{n}||<\epsilon/2$ and
I
$(1 -P_{m})QP_{n}$II
$<\epsilon/2$ andlet $P$ be the projection such that $P_{2m}PP_{2m}=P$ and $P_{m}PP_{m}=P_{m}QP_{m}=T$ defined in
3.3. So
$PP_{m}=T+s_{m}\sqrt{T-T^{2}}$, where $S_{m}$ is the operator that shifts any $x\in Hm$ places to the right ($ie$. such that $S_{m}e_{k}=e_{k+m}$ for all $k\in\omega$) and then
$PP_{7\downarrow}=PP_{\tau n}P_{n}=TP_{n}+S_{\gamma n}\sqrt{T-T^{2}}P_{n}=P_{m}QP_{n}+S_{m}\sqrt{P_{m}QP_{m}-(P_{7n}QP_{m})^{2}}P_{n}$
and hence $||(P-Q)P_{n}||\leq||(P_{\tau r\iota}-1)QP_{n}||+||\sqrt{P_{rr\iota}QP_{\gamma n}-(P_{m}QP_{m})^{2}}P_{n}||<\epsilon$ . $\square$
Proposition 3.5 A bounded linear operator $T$ on $H$ is a projection
if
and onlyif
$T^{*}T=T$.Proof: If$T^{*}T=T$ then $\tau*=(T^{*}T)^{*}=T^{*}T^{**}=T^{*}T=T$, i.e. $T$ is self-adjoint, and hence also
$T^{2}=T^{*}T=T$, ie. $T$ is idempotent. On the other hand if $T$ is
a
projection then $T^{*}T=T^{2}=T$. $\square$In fact,
we
can
doeven
better and noteven assume
$T$ is bounded.Proposition 3.6 A linear operator $T$ on $H$ is a projection
if
and onlyif
$\langle Tx,$$Ty\rangle=\langle Tx,$$y\rangle$for
Proof: If$T$ is
a
projection then $\langle Tx,$$\prime l\urcorner y\rangle=\langle T^{*}Tx$,$y\rangle=\langle Tx,$ $y\rangle$, for all $x,$$y\in H$.On
the otherhand, if $\langle Tx,$$Ty\rangle=\langle Tx,$ $y\}$ for all $x,$ $y\in H$ theri
$\langle Tx,$ $y\rangle=\langle Tx,$$Ty\rangle=\overline{\langle^{\Gamma}l\urcorner y,Tx\}}=\overline{\langle Ty,x\}}=\langle x,$ $Ty\rangle$,
for all $x,$ $y\in H$ and hence $\langle Tx,$$y\rangle=\langle Tx,$ $Ty\rangle=\langle T^{2}x,$ $y\rangle$ for all $x,$ $y\in H$. So $T$ is self-adjoint
(which, being defined everywhere, implies it is bounded, by the Hellinger-Toeplitz theorem) and idempotent. $\square$
Proposition 3.7
If
scalarsare
complex $(i.e. if \mathbb{F}=\mathbb{C})$ then a linear operator $T$on
$H\iota s$ aprojection
if
and onlyif
$\langle Tx,$$T^{\perp}x\}=0$for
all $x\in H$.Proof: If $T$ is
a
projection then $\langle Tx,$$T^{\perp}x\rangle=\langle T^{1*}Tx,$$x\rangle=0$,for
all $x\in H$,as we
have
$\tau^{\perp}*\tau=T-T^{*}T=0$.
On
the other hand if $\langle Tx,$$Tx\}=\langle Tx,$$x\}$for
all $x\in H$ then,for
all$x,$ $y\in H$,
$\langle T(x+y),$$T(x+y)\rangle$ $=$ $\langle T(x+y),$$x+y\rangle$
$\langle Tx,$$Tx\rangle+\langle Tx,$$Ty\rangle+\langle Ty,$ $Tx\rangle+\langle Ty,$$Ty\rangle$ $=$ $\langle Tx,$ $x\rangle+\langle Tx,$ $y\rangle+\langle Ty,$ $x\rangle+\langle Ty,$ $y\rangle$
$\langle Tx,$$Ty\}+\langle Ty,$$Tx\rangle$ $=$ $\langle Tx,$ $y\rangle+\langle Ty,$$x\}$.
But also
$\langle T(x-iy),$$T(x-iy)\}$ $=$ $\langle T(x-iy)$,
x–iy}
$\langle Tx,$$Tx\rangle+i\langle Tx,$ $Ty\rangle-i\langle Ty,$$Tx\rangle+\langle Ty,$$Ty\rangle$ $=$ $\langle Tx,$$x\rangle+i\langle Tx,$$y\}-i\langle Ty,$ $x\rangle+\langle Ty,$$y\rangle$
$\langle Tx,$ $Ty\}-\langle Ty,$ $Tx\}$ $=$ $\langle Tx,$$y\}-\langle Ty,$$x\}$.
Adding these two equations together and dividing by 2 gives $\langle Tx,$$Ty\rangle=\langle Tx,$$y\rangle$ for all $x,$$y\in H$. $\square$
Proposition 3.8
If
scalars are real $(i.e. if \mathbb{F}=\mathbb{R})$ then $T$ is a projectionif
and onlyif
$T$ isself-adjoint and $\langle Tx,$$T^{\perp}x\rangle=0$
for
all $x\in H$.Proof: For all $x,$ $y\in H$
we
have $\langle Tx,$$Tx\}=\langle Tx,$$x\}$ and $\langle Ty,$ $Ty\rangle=\langle Ty,$$y\rangle$ and hence$\langle T(x+y),$$T(x+y)\rangle$ $=$ $\langle T(x+y),$$x+y\}$
$\langle Tx,$$Tx\}+\langle Tx,$$Ty\rangle+\langle Ty,$$Tx\}+\langle Ty,$ $Ty\}$ $=$ $\langle Tx,$$x\rangle+\langle Tx,$ $y\}+\langle Ty,$$x\rangle+\langle Ty,$$y\}$ $\langle Tx,$$Ty\}+\langle Ty,$ $Tx\}$ $=$ $\langle Tx,$$y\rangle+\langle Ty,$$x\}$.
$\langle Tx,$$Ty\rangle+\langle Tx,$ $Ty\}$ $=$ $\langle Tx,$$y\}+\langle x,$$Ty\}$.
$\langle Tx,$$T^{1}y\}+\langle Tx,$ $Ty\rangle$ $=$ $\langle Tx,$$y\rangle+\langle Tx,$$y\rangle$.
$\langle Tx,$$Ty\rangle$ $=$ $\langle Tx,$ $y\rangle$. $\square$
Proposition 3.9 For any $r\in \mathbb{R},$ $B_{r}=\{x\in H : ||x||\leq r\}\iota s$ closed $w.r.t$. the weak topology.
Proof: If $||y||>r$ then the weakly open set $\{x\in H\cdot\langle x, y\rangle>r||y||\}$ contains $y$ and is disjoint
from $B_{r}$ (because if $||x||\leq r$ then $\langle x,$$y\}\leq||x||||y||\leq r||y||$). As $y$
was
arbitrary, $B_{r}$ is closed. $\square$Proof: Density follows from
3.3.
Next note that, forany
$x\in H$ ,$|| \Gamma 1’ x-\frac{1}{2}x||^{2}=\{7_{X}^{1\Gamma}l^{}x\rangle-\frac{1}{2}\langle Tx, x\cdot\rangle-\frac{1}{2}\langle.\iota\cdot, 7^{1}x\}+\frac{1}{4}||x||^{2}$
so
$\langle Tx,$ $T^{\perp}x\}=0\Leftrightarrow\langle x,$$Tx\rangle=\langle Tx,$$Tx\}=\langle Tx,$$x \rangle\Leftrightarrow||Tx-\frac{1}{2}x||=\frac{1}{2}||x||$.
Hence, defining $f_{x}(T)=Tx- \frac{1}{2}x$, which is a continuous map from $\mathcal{B}(H)_{1}$ with the weak operator
topology to $H$ with the weak topology,
we
have$\{T\in \mathcal{B}(H)_{1}:\langle Tx, T^{\perp}x\}=0\}=f_{x}^{-1}(B_{1,\tilde{2}} I |x||)\cap\bigcap_{n}(\mathcal{B}(H)_{1}\backslash f_{x}^{-1}(B_{\frac{1}{2}||x||-\frac{1}{\prime 1}}))$
which is the intersection of
a
closed and hence $G_{\delta}$ set with another $G_{\delta}$ set and thus itselfa
$G_{\delta}$set. If $D$ is
a
countable dense subset of $H$ then$\{T\in \mathcal{B}(H)_{1}:\forall x\in H\langle Tx, T^{\perp}x\rangle=0\}=\bigcap_{x\in D}\{T\in \mathcal{B}(H)_{1}:\langle Tx, T^{\perp}x\rangle=0\}$
isalso
a
$G_{\delta}$ set. Ifwe are
dealing with complex scalars then this is already preciselythecollection ofprojections, while if
we are
dealing with real scalars thenwe
must intersect this with the collectionof self-adjoint operators $\{T\in \mathcal{B}(H)_{1} : \forall x, y\in H\langle Tx, y\}=\langle x,$$Ty\rangle\}$, which is closed and hence $G_{\delta}$,
to get the collection of projections, which again shows it is
a
$G_{\delta}$ set. $\square$Proposition 3.11
If
$Y$ is a comeagre subsetof
a Baire space $X$ and $Z\subseteq X\backslash Y$ then,for
any$A\subseteq Y,$ $A$ is comeagre in $Y$
if
and onlyif
$A\cup Z\iota s$ comeagre in $X$.Proof: Let $Y\supseteq\cap O_{n}^{Y}$ for
open
dense $(O_{n}^{Y})$ in $X$. If $A\cup(X\backslash Y)\supseteq A\cup Z\supseteq\cap O_{n}$, foropen
dense $(O_{n})$ in $X$, then $O_{n} \cap\bigcap_{k}O_{k}^{Y}$ iscomeagre
and hencedense
in $X$ and hence in $Y$,for
each $n\in\omega$.
Therefore $A \supseteq\bigcap_{n}(O_{n}\cap\bigcap_{k}O_{k}^{Y})$ is comeagre in $Y$.
On the other hand, if $A$ is comeagre in $Y$ then $A\supseteq\cap O_{n}$ for open dense $(O_{n})$ in $Y$. But then
there
are
open $(O_{n}’)$ in $X$ such that, for all $n\in\omega,$ $O_{n}=O_{n}’\cap Y$. As $O_{n}$ is dense in $Y$ and $Y$ isdense in $X,$ $O_{\iota}’\supseteq O_{n}$ is also dense in $X$, for all $n\in\omega$. Thus $A\cup Z\supseteq A\supseteq\cap O_{n}’\cap O_{n}^{Y}$ is comeagre
in X. $\square$
Corollary 3.12
If
$Y$ isa
comeagre subsetof
a Baire space $X$ and$Z\subseteq X\backslash Y$ then,for
any$A\subseteq Y$, $A$ is meagre in $Y$if
and onlyif
$A\cup Z$ is meagre in $X$.Proof:
$A$ nteagre in $Y\Leftrightarrow Y\backslash A$ coineagre in $Y\Leftrightarrow(Y\backslash A)\cup(X\backslash Y)\backslash Z$ comeagre in $X\Leftrightarrow A\cup Z$ meagre in $X.\square$
Corollary 3.13
If
$\mathcal{Z}\subseteq \mathcal{B}(H)_{1}^{+}\backslash \mathcal{P}(\mathcal{B}(H))$ then,for
any $\mathcal{F}\subseteq \mathcal{P}(\mathcal{B}(H)),$ $\mathcal{F}$ is meagre in $\mathcal{P}(\mathcal{B}(H))$$w.’\cdot.t$. the weak operator topology $\iota f$ and only
if
$\mathcal{F}\cup \mathcal{Z}$ is meagre in $\mathcal{B}(H)_{1}^{+}w.r.t$. the weak operatortopology.
From now until3.27let $\mathcal{B}$ consistently be $\mathcal{B}(H)_{1},$ $\mathcal{B}(H)_{1}^{+\prime-},$ $\mathcal{B}(H)_{1}^{+}$ or $\mathcal{P}(\mathcal{B}(H))$
.
Proposition 3.14 For any $\mathcal{F}\subseteq \mathcal{B}$, the following are equivalent
(i) For all $n\in\omega,$ $P_{\omega\backslash n}\mathcal{F}P_{\omega\backslash n}$ is not dense in $P_{\omega\backslash n}\mathcal{B}P_{\omega\backslash n}w.r.t$. to the weak operator topology.
(ii) $Fo7^{\cdot}$ all $’\iota\in\omega,$ $P_{\omega\backslash n}\mathcal{F}P_{\omega\backslash n}$ is nowhere dense in $P_{\omega\backslash n}\mathcal{B}P_{\omega\backslash n}$ w.r.t. to the weak operator
topology.
$(i\dot{\iota}l)$ For all $n\in\omega$ there exists $m\geq n,$ $\epsilon>0$ and $S\in \mathcal{B}$ such that $P_{m\backslash n}SP_{m\backslash n}=S$ and $\{7^{T}\in \mathcal{B} ||S-P_{rn\backslash n}TP_{\tau r\iota\backslash n}||<\epsilon\}$ is disjoint
from
$\mathcal{F}$Proof:
$(iii)\Rightarrow(ii)$ Assume (iii), fix $n\in\omega$ and take any basic open set $\mathcal{O}$ of
$P_{\omega\backslash n}\mathcal{B}P_{\omega\backslash n}$ of the form $\mathcal{O}=\{T\in P_{\omega\backslash n}\mathcal{B}P_{\omega\backslash n}. ||P_{m}(S-T)P_{m}||<\epsilon\}$
for
some
$S\in P_{\omega\backslash n}\mathcal{B}P_{\omega\backslash r\iota},$ $\epsilon>0$ and $m\geq n$. Take $\delta>0,1\geq m$ and $R\in \mathcal{B}$ such that $P_{l\backslash m}RP_{l\backslash m}=R$ and$\mathcal{L}=\{T\in \mathcal{B}:||R-P_{l\backslash rn}TP_{l\backslash m}||<\delta\}$
is disjoint from $\mathcal{F}$. If
$T=P_{\omega\backslash n}LP_{\omega\backslash r\iota}=P_{\omega\backslash n}FP_{\omega\backslash n}$ for
some
$L\in \mathcal{L}$ and $F\in \mathcal{F}$ then $||R-P_{l\backslash m}FP_{l\backslash m}||=||R-P_{l\backslash m}TP_{l\backslash m}||=||R-P_{l\backslash m}LP_{l\backslash m}||<\delta,$ $i.e$.$P_{\omega\backslash n}\mathcal{L}P_{\omega\backslash n}\cap P_{\omega\backslash n}\mathcal{F}P_{\omega\backslash n}$ $=$ $P_{\omega\backslash n}\{F\in \mathcal{F} : ||R-P_{l\backslash m}FP_{l\backslash m}||<\delta\}P_{\omega\backslash n}$
$=$ $P_{\omega\backslash n}(\mathcal{L}\cap \mathcal{F})P_{\omega\backslash n}$,
so
$P_{\omega\backslash n}\mathcal{L}P_{\omega\backslash n}$ is disjoint from $P_{\omega\backslash n}\mathcal{F}P_{\omega\backslash n}$ too. Let $\mathcal{K}$ $=$$\{T\in P_{\omega\backslash n}\mathcal{B}P_{\omega\backslash n} : ||R+P_{m}SP_{m}-P_{l}TP_{l}||<\min(\epsilon, \delta)\}$
$\subseteq$ $\{T\in P_{\omega\backslash n}\mathcal{B}P_{\omega\backslash n} : ||R-P_{l\backslash m}TP_{l\backslash m}||<\delta\}\cap\{T\in P_{\omega\backslash n}\mathcal{B}P_{\omega\backslash n} : ||P_{m}(S-T)P_{m}||<\epsilon\}$
$=$ $P_{\omega\backslash n}\{T\in \mathcal{B}:||R-P_{l\backslash m}TP_{l\backslash m}||<\delta\}P_{\omega\backslash n}\cap \mathcal{O}$
$=$ $P_{\omega\backslash n}\mathcal{L}P_{\omega\backslash n}\cap \mathcal{O}$.
Note that $\mathcal{K}$ is non-empty
as
it contains$R+P_{m}SP_{m}$, if $\mathcal{B}$ is not $\mathcal{P}(\mathcal{B}(H))$
, while it contains
$P_{\omega\backslash n}PP_{\omega\backslash n}$ for
any
$P\in \mathcal{P}(\mathcal{B}(H))$ such that $P_{l}PP_{l}=R+P_{m}SP_{m}$, which exists by3.3.
Thus $\mathcal{K}$ is a non-empty open subset of $\mathcal{O}$ disjoint from
$P_{\omega\backslash n}\mathcal{F}P_{\omega\backslash n}$ which, as $n$ and $\mathcal{O}$ were
arbitrary, shows that (ii) holds.
$(ii)\Rightarrow(i)$ Immediate.
$(i)\Rightarrow(iii)$ Assume that (i) holds so, for any $n\in\omega$, there exists
a
basic open set $\mathcal{O}$ of$P_{\omega\backslash n}\mathcal{B}P_{\omega\backslash n}$
disjoint from $P_{\omega\backslash n}\mathcal{F}P_{\omega\backslash n}$ of the form
$\mathcal{O}=\{T\in P_{\omega\backslash n}\mathcal{B}P_{\omega\backslash n} : ||P_{m}(R-T)P_{m}||<\epsilon\}$
for
some
$R\in P_{\omega\backslash n}\mathcal{B}P_{\omega\backslash n},$ $\epsilon>0$ and $m\geq n$. Setting $S=P_{m}RP_{m}$ gives $P_{m\backslash n}SP_{m\backslash n}=S$and
$\mathcal{O}=\{T\in P_{\omega\backslash n}\mathcal{B}P_{\omega\backslash n} : ||S-P_{m}TP_{m}||<\epsilon\}=P_{\omega\backslash n}\{T\in \mathcal{B} : ||S-P_{m\backslash n}TP_{m\backslash n}||<\epsilon\}P_{\omega\backslash n}$
which implies $\{T\in \mathcal{B} : ||S-P_{m\backslash n}TP_{m\backslash n} II <\epsilon\}$ is disjoint from $\mathcal{F}$. $\square$
Definition 3.15 ([2] 3.1.4) Any$\mathcal{F}\subseteq \mathcal{B}$ satisfying any
of
the equivalent conditions in thepropo-sition above $\iota s$ said to be good nowhere dense ($w.r.t$. the basis $(e_{n})$)$.$ A countable union
of
goodnowhere dense sets is said to be good meagre ($w.r.t$. the basis $(e_{n})$).
Proposition 3.16 Good nowhere dense sets are closed undersubsets,
finite
unions and topologicalclosures,
Proof: Follows from
characterization
(ii) above and the corresponding closures for nowhere densesets. $\square$
Lemma
3.17
For any $S\in \mathcal{B},$ $n\in\omega$ and $\epsilon>0$, there exists $m\in\omega\backslash n$ and $T\in \mathcal{B}$ such thatProof: If $\mathcal{B}$ is $\mathcal{P}(\mathcal{B}(ff))$ then this follows from
3.
1.Otherwise
simply let $m\geq n$ be large enoughthat $||(1-P_{r’ l})SP_{n}||<\epsilon$ , let $T=P_{r\iota},SP_{7\Omega}$ and note that then $P_{r’\iota}TP_{rn}=T,$ $||(S-T)P_{n}||<\epsilon$ and
$||T||\leq||S||$ and if $S$ is self-adjoint
or
non-negative then thesame
applies to T. $\square$Proposition 3.18 ([2] 3.1.5.) Take a partition $(I_{n})$
of
$\omega$ anda
sequence $(T_{n})\subseteq \mathcal{B}$ such that$P_{I_{1}},T_{n}P_{I\prime 1}=T_{n}$,
for
all $n\in\omega$. Then,for
all $m\in\omega$,$\mathcal{D}_{m}=\{T\in \mathcal{B} : \exists n\geq m(T_{n}=P_{I_{r\iota}}TP_{I_{r\iota}})\}$
is dense in $\mathcal{B}w.r.t$. the strong operator topolgy.
Proof: Take
any
basicopen
set $\mathcal{O}=\{T\in \mathcal{B} : ||(S-T)P_{k}||<\epsilon\}$,for
some
$k\in\omega,$ $S\in \mathcal{B}$ and$\epsilon>0$. Let $T$ and $m$ be
as
in the above lemma (with $n$ replaced by $k$), let $n$ be large enough that$m \leq\min(I_{n})$ and note that then $T+T_{n}\in \mathcal{O}\cap \mathcal{D}_{m}$. $\square$
Proposition 3.19 Take
a
partition $(I_{n})$of
$\omega$ and sequences $(T_{n})\subseteq \mathcal{B}$ and $(\epsilon_{n})\subseteq \mathbb{R}$ such that$P_{I_{n}}T_{n}P_{I_{71}}=T_{n}$ and $\epsilon_{n}>0$
for
all $n\in\omega$. Then,for
all $m\in\omega$,$\mathcal{N}_{(\epsilon_{r\iota}),(T_{r\iota}),(I_{r}),m}=\{T\in \mathcal{B}:\forall n\geq m(||T_{n}-P_{I_{\mathfrak{n}}}TP_{I_{\mathcal{T}1}}||\geq\epsilon_{n})\}=\bigcap_{n\geq m}\{T\in \mathcal{B}:||T_{n}-P_{I_{7l}}TP_{I_{n}}||\geq\epsilon_{n}\}$
is a closed nowhere dense subset
of
$\mathcal{B}w.r.t$. both the weak and strong operator topology.Further-more
euery
good nowhere dense $\mathcal{N}\subseteq \mathcal{B}$ is contained in such a set, with $m=0$ infact.
Definition 3.20
$T=(e,,$$\cdot$ $S\Leftrightarrow\exists n\in\omega(P_{\omega\backslash n}TP_{\omega\backslash n}= P.\backslash nSP_{\omega\backslash n})$.
Proposition 3.21 ([2] 3.1.5.) Take a partition $(I_{n})$
of
$\omega$ and sequences $(T_{n})\subseteq \mathcal{B}$ and $(\epsilon_{n})\subseteq \mathbb{R}$such that $P_{I_{r\iota}}T_{n}P_{I_{1}},=T_{n}$ and $\epsilon_{n}>0$
for
all $n\in\omega$. Then$\mathcal{M}_{(\epsilon_{ll}),(T_{t1}),(I_{r\iota})}=\bigcup_{7n}\mathcal{N}_{(\epsilon_{1}),(T_{l1}),(I_{r\iota}),m}=\{T\in \mathcal{B}:\forall^{\infty}n(||T_{n}-P_{I_{71}}TP_{I_{r\iota}}||\geq\epsilon_{n})\}$
is $a=_{(e_{t1})}$-closed meagre $F_{\sigma}$ subset
of
$\mathcal{B}w.r.t$. both the weak and strong operator topology.Fur-thermore every good meagre $\mathcal{M}\subseteq \mathcal{B}$ is contained in such a set.
Definition
3.22 A subset$\mathcal{F}\subseteq \mathcal{B}$ is very good nowhere dense ($w.r.t$. the basis $(e_{n})$)if
there exists $\epsilon>0$ such that,for
all $n\in\omega$, there exists $m\geq n$ and $S\in \mathcal{B}$ such that $P_{\tau n\backslash n}SP_{7n\backslash n}=S$$\{T\in \mathcal{B}\cdot||S-P_{m\backslash n}TP_{m\backslash n}||<\epsilon\}$
is disjoint
from
$\mathcal{F}.$ A countable unionof
very good nowhere dense sets is sadi to be very goodmeagre $(u’.r.t$. the $bas$is $(e_{n}))$.
Proposition 3.23 The very good nowhere dense sets are closed under subsets,
finite
unions andtopological closures.
Proposition 3.24 Take $\epsilon>0$, a partition $(I_{n})$
of
$\omega$ and $(T_{n})\subseteq \mathcal{B}$ such that $P_{I_{\iota}},T_{n}P_{I_{r\iota}}=T_{n}$for
all $n\in\omega$. Then, $fo\tau$. all $m\in\omega$,
$\mathcal{N}_{\epsilon,(l_{l1}^{\tau})(I_{tI})rn}’=\{T\in \mathcal{B} \forall n\geq m(||T_{n}-P_{I_{1}},TP_{l_{\iota}},||\geq\epsilon)\}=\bigcap_{n\geq m}\{T\in \mathcal{B}:||T_{n}-P_{I_{r\iota}}TP_{I,\iota}||\geq\epsilon\}$
$\iota s$ a closed nowhere dense subset
of
$\mathcal{B}w.\gamma\cdot.t$. both the weak and strong operator topology.Further-more $e\{)ery\iota)ery$ good $nowher\cdot e$ dense $\mathcal{N}\subseteq \mathcal{B}$ is contained in such a set, with $m=0$ in
Proposition 3.25 Take a partition $(I_{n})$
of
$\omega$ and $(T_{n})\subseteq \mathcal{B}$ such that $P_{I_{r\iota}}T_{n}P_{I_{\tau\iota}}=T_{n}$for
all$n\in\omega$. Then
$\mathcal{M}_{(T_{r\iota}),(I_{l\iota})}=\bigcup_{m}\mathcal{N}_{1’ m,(T_{lt}),(I_{7\iota}),m}=\{T\in \mathcal{B}:\lim\inf_{n}||T_{n}-P_{I_{r\iota}}TP_{I_{t1}}||>0\}$
is $a=*$-closed meagre $F_{\sigma}$ subset
of
$\mathcal{B}w.r.t$. both the weak and strong operator topology.Further-more
$e\{)ery$ uery good meagre $\mathcal{M}\subseteq \mathcal{B}$ is contained in such a set.Proposition 3.26 $c1_{=}*(P_{9(\omega)})$ is very good meagre.
Proof: Foreach $n\in\omega$ let $I_{n}=\{2n,$ $2n+1\}$ and let $P_{n}$ be the projectiononto the
one
dimensionalsubspace span$\{e_{2n}+e_{2n+1}\}$. For any $A\in\omega$,
we
have $||P_{n}-P_{I_{n}}P_{A}P_{I_{n}}||\geq 1/\sqrt{}$ and hence$\lim$$inf||P_{n}-P_{I_{7t}}PP_{I_{r\iota}}||\geq 1/\sqrt{}$ for all $P=*P_{A}$. Thus $c1_{=}*(P_{9(\omega)})\subseteq \mathcal{M}_{(P_{r\iota}),(I_{n})}$. $\square$
Next
we
prove the analog of2.13.
Note however that,w.r.
$t$. the weak operator topology,$\mathcal{B}(H)_{1},$ $\mathcal{B}(H)_{1}^{+/-}$ and $\mathcal{B}(H)_{1}^{+}$
are
closed subsets of $\mathcal{B}(H)$, however $\mathcal{P}(\mathcal{B}(H))$ is not and hence theproof of 3.27 below does not work in this
case.
Indeed, it follows from3.3
that $\mathcal{P}(\mathcal{B}(H))$ is densein $\mathcal{B}(H)_{1}^{+}$.
For the
rest
of thissection
let $\mathcal{B}$ consistently be $\mathcal{B}(H)_{1},$ $\mathcal{B}(H)_{1}^{+/-}$or
$\mathcal{B}(H)_{1}^{+}$ (butnot
$\mathcal{P}(\mathcal{B}(H)))$.
Theorem 3.27
If
$\mathcal{F}\subseteq \mathcal{B}$$is=(e_{r\iota})$-closed $F_{\sigma}w.r.t$. the weak operator topology and$T\in \mathcal{B}\backslash \mathcal{F}$ then
there exists an interval partition $(I_{n})$
of
$\omega$ and $(\epsilon_{n})>0$ such that $\mathcal{F}\subseteq \mathcal{M}_{(\epsilon_{\iota}),(P_{I_{r\iota}}TP_{I_{L}}},$),$(I_{n})$Proof: Let $\mathcal{F}=\cup \mathcal{N}_{n}$ for closed subsets $(\mathcal{N}_{n})$ of$X$. Define $(\epsilon_{r\iota})$ and $(I_{n})$ recursively
as
follows.Let $\min(l_{n})=\max(I_{n-1})+1(=0 if n=0)$ and, for all $S\in \mathcal{B}(H)_{3}$ such that
$P_{\omega\backslash \min(I_{r\iota})}(S-T)P_{\omega\backslash \min(I_{7\iota})}=0$
and hence $S\not\in \mathcal{F}$ (and quite possibly $S\not\in \mathcal{B}$),
as
$\mathcal{F}$ is$=_{(e_{r\iota})}$-closed, there exists $n_{S} \in\omega\backslash \min(I_{n})$
and $\epsilon_{S}>0$ such that the set
$\mathcal{R}_{S,n}=\mathcal{R}_{S}=\{R\in \mathcal{B}(H) : \forall j, k\in n_{S}(\langle(R-S)e_{j}, e_{k}\rangle<\epsilon_{S})\}$
is disjoint from the closed set $\bigcup_{k\in n}\mathcal{N}_{k}(\subseteq \mathcal{F})$. As
$S$ $=$ $\{S\in \mathcal{B}(H)_{3}:P_{\omega\backslash \min(I_{r\iota})}(S-T)P_{\omega\backslash \min(I_{n})}=0\}$
$=$ $\{S\in \mathcal{B}(H)_{3} : \forall j, k\in\omega\backslash \min(I_{n})(\langle Se_{j}, e_{k}\rangle=\langle Te_{j}, e_{k}\})\}$
is closed and hence compact there exist $S_{0},$
$\ldots,$$S_{m_{r\iota}-1}$ such that $\mathcal{R}_{S_{0}},$ $\ldots,$$\mathcal{R}_{S_{\tau n_{\mathfrak{n}}-1}}$
cover
$S$. Let$\max(I_{n+1})=\max\{n_{S_{k}} : k\in m_{n}\}$ and $\epsilon_{n}=\min\{\epsilon_{S_{k}} : k\in m_{n}\}$. This completes the recursion.
Now note that if$n\in\omega,$ $R\in \mathcal{B}$ and $||P_{I_{r\iota}}(R-T)P_{I_{r\iota}}$
lI
$<\epsilon_{n}$ then$R’=R+P_{\omega\backslash \min(I_{r\iota})}(T-R)P_{\omega\backslash \min(I_{n})}$
has
norm
at most3
and $P_{\omega\backslash \min(I_{lL})}(R’-T)P_{\omega\backslash \min(I_{n})}=0$so
$R’\in \mathcal{R}_{S_{\tau n},n}$ forsome
$m\in m_{n}$.For $j,$ $k \in n_{S_{rr1}}\backslash \min(I_{n})\subseteq I_{n}$
we
have $\langle(R-S_{m})e_{j},$$e_{k}\}=\langle(R-T)e_{j},$$e_{k}\}<\epsilon_{n}\leq\epsilon_{S_{m}}$, while for $j,$ $k\in n_{S_{r’ 1}}$ with either $j$or
$k$ less than $\min(I_{n})$we
have $\langle(R-S_{m})e_{j},$$e_{k}\}=\langle(R’-S_{m})e_{j},$$e_{k}\rangle<\epsilon s_{m}$.So
we
in fact have $R\in \mathcal{R}_{S_{rt1},n}$ too and hence $R \not\in\bigcup_{k\in n}\mathcal{N}_{k}$. Thus if $||P_{I_{r\iota}}(R-T)P_{I_{r\iota}}||<\epsilon_{n}$ forinfinitely many $n\in\omega$ then $R\not\in \mathcal{F}$, i.e. $\mathcal{F}\subseteq \mathcal{M}_{(\epsilon_{\iota}),(P_{I_{7L}}TP_{I_{n}}),(I_{n})}$. $\square$
Corollary 3.28
If
$\mathcal{F}\subseteq \mathcal{B}$$is=_{(e_{n})}$-closed meagre $F_{\sigma}w.r.t$. the weak operator topology then
$\mathcal{F}$ is
Proof: As $\mathcal{B}$ is compact it is a Baire space, by the Baire Category Theorein,
so
there exists$T\in \mathcal{B}\backslash \mathcal{F}$ and the result
now
follows from327
and (the first part of) 3.21. $\square$Corollary 3.29 A subset $\mathcal{F}$
of
$\mathcal{B}\iota s$ good meagre $w.r.t$. $(e_{n})$if
and onlyif
$\mathcal{F}$ is contained in a $=cl_{0_{s}},ed(e_{t1})^{-}$ meagre $F_{\sigma}w.r\cdot.t$. the weak operator topology.Proof: Follows from
3.28
aiid (the second part of) 3.21 口I should point out that in [2]
page 47
(after 3.1.4)Zamora-Aviles
makes the comment that if$\mathcal{F}$ is closed under finite-rank changes
$($and $\mathcal{B}=\mathcal{B}(H)_{1}^{+})$ then good meagreness does not depend
on
the basis. While this does indeed follow from the above corollary if $\mathcal{F}$ is meagre $F_{\sigma}$ (becauseif $\mathcal{F}$ is closed under finite rank changes then it will be
$=_{(e_{r\iota})}$-closed for any basis $(e_{n}))$ and might
indeed be true
even
without the $F_{\sigma}$ assumption, I do notsee
how it follows directly from what iswritten in $[$2$]$.
Unfortunately, the proof of 2.21, where
we
get rid of the $F_{\sigma}$ assumption, does not,as
far
as
Ican
tell, generalize to $\mathcal{B}$, essentially because it does not generalize to closed subsets of $\omega X$ (unlikethe proofof 2.13). The best I
can
do is the following.Theorem 3.30
If
$\mathcal{F}\subseteq \mathcal{B}$ $is=*$-closed $F_{\sigma}w.r.t$. the weak operator topology and $T\in \mathcal{B}\backslash \mathcal{F}$, thereexists and interval partition $(I_{n})$
of
$\omega$ such that $\mathcal{F}\subseteq \mathcal{M}_{(P_{I_{r\iota}}TP_{I_{\iota}},),(I_{r\iota})}$.Proof: By
3.27
there exists and interval partition $(I_{n})$ of $\omega$ together with $(\epsilon_{n})>0$ such that$\mathcal{F}\subseteq \mathcal{M}_{(\epsilon_{1}),(P_{I_{\Gamma 1}}TP_{I_{\gamma 1}}),(I_{\tau\iota})}.Weclaimthat,infact,$
$\mathcal{F}\subseteq S\in \mathcal{F}\backslash \mathcal{M}_{(P_{I_{r1}}TP_{I_{1}},),(I_{1},)}whichmeanswehaveA\in[\omega]^{\omega}sucht^{r\iota}hat||P_{I_{r\iota_{1}}},\cdot(S-T)P_{I_{t\lambda}n}||\mathcal{M}_{(TP_{I_{7}}),(I_{\gamma})}p_{I}Ifnotthen$
there exists
$arrow 0$ where
$(a_{n})$ is the increasing enumeration of $A$. So if
we
let $K= \sum_{a\in}{}_{A}P_{I_{O}}(S-T)P_{I_{1}}\in \mathcal{K}(H)$ then$S-K\in \mathcal{F}$ but $P_{I_{f1}}(S-K)P_{I_{\lambda}}=P_{I_{\alpha}}TP_{I_{(1}}$ for all $a\in A$ and hence $S-K\not\in \mathcal{M}_{(\epsilon_{n}),(P_{I_{r\iota}}TP_{I_{\gamma\iota}}),(I_{r\iota})}$,
a
contradiction. $\square$Corollary 3.31
If
$\mathcal{F}\subseteq \mathcal{B}$ $is=*$-closed meagre $F_{\sigma}$ w.r.t. the weak operator topology then $\mathcal{F}$ isvery good meagre.
Corollary 3.32 A subset $\mathcal{F}$
of
$\mathcal{B}$ is very goodmeagre
if
and onlyif
$\mathcal{F}$ is contained in $a=*$-closedmeagre $F_{\sigma}w.r.t$. the weak operator topology.
Proposition 3.33
If
$(I_{n})$ isan
interval partitionof
$\omega$ and $(T_{n})\in \mathcal{B}(H)^{+}\iota s$ such thatwe
have$P_{n}T_{n}P_{n}=T_{n}$,
for
all $n\in\omega$, then there exists an interval partition $(J_{n})$of
$\omega$ and $(P_{n})\subseteq \mathcal{P}(\mathcal{B}(H))$such that $P_{J_{r\iota}}P_{n}P_{J_{r1}}=P_{n}$,
for
all $n\in\omega$, and$\mathcal{M}_{(P_{r\iota}),(J_{7t})}\subseteq \mathcal{M}_{(P_{I_{r\iota}}TP_{I_{r\iota}}),(I_{t1})}$ (where these $\mathcal{M}$ ’s aredefined
within $\mathcal{B}(H)_{1}^{+}$or
$\mathcal{P}(\mathcal{B}(H))$,or even
$\mathcal{B}(H)_{1})$.Proof: Let $(J_{n})$ be such that, for each $n\in\omega,$ $J_{n}$ contains
some
$I_{m_{1}}$, and is at least twice the sizeof $I_{m_{r\iota}}$. By 3.3
we can
find $(P_{n})\subseteq \mathcal{P}(\mathcal{B}(H))$ such that $P_{J_{n}}P_{n}P_{J_{r1}}=P_{n}$ and $P_{I_{r_{t}}},,P_{n}P_{I_{rr\iota_{\iota}}},=T_{m_{r\iota}}$,for all $n\in\omega$, from which $\mathcal{M}_{(T_{n}),(I_{r\iota})}\subseteq \mathcal{M}_{(P_{n}),(J_{7L})}$ follows. $\square$
Finally let us summarize
we
whatwe
can now
say about meagre subsets and their closures.Definition 3.34 For any $f,$$g\in\omega[0,1]$
define
$f\leq^{*}[0,1]g\Leftrightarrow$ lim$sup(f(n)-g(n))\leq 0$.
Definition 3.35 For any $A\subseteq\omega$ let $1_{A}:\omegaarrow 2$ be its charactenstic function, $i.e$. $1_{A}(n)=1$
if
$n\in A$ and $1_{A}(n)=0$ otherwise.
If
$\mathcal{A}\subseteq \mathcal{P}(\omega)$ then let $1_{A}=\{1_{A}:A\in \mathcal{A}\}$.(i) There exists
an
interval partition $(I_{n})$of
$\omega$ such that $\forall A\in \mathcal{A}\forall^{\infty}n\exists m\in I_{n}\backslash A$.(ii) cl$\leq 2*(1_{\mathcal{A}})=$ cl$\leq_{2}\cdot(1_{\mathcal{A}})=1_{c1*(\mathcal{A})}\subseteq\iota s$ meagre.
(iii) cl$\leq_{|011}(1_{\mathcal{A}})$ is meagre.
Furthermore, they imply (iv) cl$\leq*(P_{\mathcal{A}})$ zs meagre.
Proof:
$(i)=\succ(ii),(iii),(iv)$ Simply note that (i) implies that
$c1_{\leq}2*(1_{A})$ $\subseteq$ $\mathcal{M}_{1_{\omega},(I_{n})}(\subseteq\omega 2)$,
cl$\leq_{[0,1]}^{*}(1_{A})$ $\subseteq$ $\mathcal{M}_{1_{\omega},(I_{n})}(\subseteq\omega[0,1])$ and
$c1_{\leq}*(P_{A})$ $\subseteq$ $\mathcal{M}_{P_{I_{n}},(I_{n})}(\subseteq \mathcal{P}(\mathcal{B}(H)))$
(iii)$\Rightarrow(i)$ Take arbitrary $g\in\omega[0,1]$ and
an
interval partition $(I_{n})$of
$\omega$. If (i)fails
then there exists$C\in \mathcal{A}$ and $A\in[\omega]^{\omega}$ such that $I_{a}\subseteq C$ for all $a\in A$. If
we
let $C’= \bigcup_{a\in\omega\backslash A}I_{a}$ and$f=g|C’\cup 1_{C}r\omega\backslash C’$ then $f\leq 1_{C}$ (everywhere) and $frI_{a}=grI_{a}$ for all $a\in A$ and
hence $f\in$ cl$\leq_{|0,1)}^{*}(1_{A})\not\leqq \mathcal{M}_{g,(I_{\gamma\iota})}$. Thus,
as
$g$ and $(I_{n})$were
arbitrary, cl$\leq_{[01]}^{*}(1_{\mathcal{A}})$ is not verygood meagre, by 2.20. But cl$\leq_{r01|}^{*}(1_{A})$ is $=*$-closed meagre and hence very good meagre by
2.21,
a
contradiction.(ii)$\Rightarrow(i)$ Just like $(iii)\Rightarrow(i)$, instead taking arbitrary $g\in\omega 2$. 口
What
we
wanted, of course,was
to prove that (iv) implies (ii), which would follow ifwe
couldprove 3.31 without the $F_{\sigma}$ assumption because then
we
could also prove it for $\mathcal{P}(\mathcal{B}(H))$ –givenany $=*$-closed meagre subset $\mathcal{F}$ of $\mathcal{P}(\mathcal{B}(H))$, the $=*$-closure of$\mathcal{F}$ in $\mathcal{B}(H)_{1}^{+}$ would be meagre by
3.13, hence
very
goodmeagre
in $\mathcal{B}(H)_{1}^{+}$ (by3.31
without the $F_{\sigma}$ assumption) and thus $\mathcal{F}$ wouldbe very good meagre in $\mathcal{P}(\mathcal{B}(H))$ by 3.33. Then the proof of $(iv)\Rightarrow(i)$ would go like the proof of
(iii)$\Rightarrow(i)$ above.
References
[1] Andreas Blass,
Combinatorial
Cardinal Characteristicsof
the Continuum, Handbook ofSet
Theory November 24,
2003
preprint.[2] Beatriz Zamora-Aviles, The