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Volume 2010, Article ID 912601,8pages doi:10.1155/2010/912601

Research Article

Hardy-Hilbert-Type Inequalities with a Homogeneous Kernel in Discrete Case

Josip Pe ˇcari´c

1

and Predrag Vukovi ´c

2

1Faculty of Textile Technology, University of Zagreb, Pierottijeva 6, 10000 Zagreb, Croatia

2Faculty of Teacher Education, University of Zagreb, Ante Starˇcevi´ca 55, 40000 ˇCakovec, Croatia

Correspondence should be addressed to Predrag Vukovi´c,[email protected] Received 4 September 2009; Accepted 16 February 2010

Academic Editor: Ondˇrej Doˇsl ´y

Copyrightq2010 J. Peˇcari´c and P. Vukovi´c. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

The main objective of this paper is a study of some new generalizations of Hilbert’s and Hardy- Hilbert’s type inequalities. We apply our general results to homogeneous functions. We shall obtain, in a similar way as Yang did in2009, that the constant factors are the best possible when the parameters satisfy appropriate conditions.

1. Introduction

Hilbert and Hardy-Hilbert type inequalitiessee1are very significant weight inequalities which play an important role in many fields of mathematics. Although classical, such inequalities have attracted the interest of numerous mathematicians and have been generalized in many different ways. Also the numerous mathematicians reproved them using various techniques. Some possibilities of generalizing such inequalities are, for example, various choices of nonnegative measures, kernels, sets of integration, extension to multidimensional case, and so forth.

Similar inequalities, in operator form, appear in harmonic analysis where one investigates properties of boundedness of such operators. This is the reason why Hilbert’s inequality is so popular and represents field of interest of numerous mathematicians: since Hilbert till nowadays.

We start with the following two discrete inequalities, which are the well-known Hilbert and Hardy-Hilbert type inequalities. More precisely, if p > 1, 1/p 1/q 1, an, bn ≥ 0,such that 0<

n0apn <∞and 0<

n0bqn <∞, then the following inequality holdsHardy et al.1:

n0

m0

ambn

mn1 < π sin

π/p

n0

apn

1/p

n0

bqn 1/q

, 1.1

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where the constant factorπ/sinπ/pis the best possible. The equivalent form of inequality 1.1issee Yang and Debnath2

n0

m0

am mn1

p

<

π sin

π/p p

n0

apn, 1.2

where the constant factorπ/sinπ/ppis still the best possible.

In this paper we refer to a recent paper of Yangsee3. In 2005, Yang3gave some extension of Hilbert’s inequality with two pairs of conjugate exponentsp, q,r, s p, r >1, and two parametersα, λ >0 αλ≤min{r, s}as

m1

n1

ambn

mαnαλ < kαλr

n1

np1−αλ/r−1apn

1/p

n1

nq1−αλ/s−1bqn

1/q

, 1.3

where the constant factorkαλr 1/αBλ/r, λ/sis the best possible.

Letφx xαp1−λ/r−1, ϕx xαq1−λ/s−1, ψx xαpλ/s−1 x∈0,∞,and lpφ {a{an}n0;ap,φ:{

n0φn|an|p}1/p<∞}.Define a Hilbert-type linear operatorT; for allalφp,one has

Tan:

m0

lnmα/nα

mαλ−nαλam. 1.4 Foralpφ, blqϕ,define the formal inner product ofTaandbas

Ta, b:

n0

m0

lnmα/nαambn

mαλ−nαλ . 1.5

Zhongsee4proved the following theorem.

Theorem 1.1. Suppose that p, q and r, s are two pairs of conjugate exponents, r > 1, p >

1, 1/2 ≤ α ≤ 1, 0 < λ ≤ 1, an, bn ≥ 0.If ap,φ > 0, bq,ϕ > 0,then one has the equivalent inequalities as

Ta, b< kλsap,φbq,ϕ, Tap,ψ < kλsap,φ,

1.6

where the constant factorkλs 1/λB1/s,1/r2is the best possible.

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Results in this paper will be based on the following general form of Hilbert’s and Hardy-Hilbert’s inequality proven in 5. All the measures are assumed to be σ-finite on some measure spaceΩ. Let 1/p1/q 1 withp > 1, Kx, y, fx, gy, ϕx, ψybe nonnegative functions. Then the following inequalities hold and are equivalent:

Ω2K x, y

fxg y

1xdμ2

y

ΩϕpxFxfpxdμ1x 1/p

ΩψqyGygqydμ2y 1/q

,

1.7

ΩG1−p y

ψ−p

y

ΩK x, y

fxdμ1x p

2

y

ΩϕpxFxfpxdμ1x, 1.8

where

Fx

Ω

K x, y ψp

y 2 y

, G

y

Ω

K x, y

ϕqx 1x. 1.9

It is of great importance to consider the case when the functions Fx and Gy, defined by1.9, are bounded. More precisely, Krni´c and Peˇcari´c in5proved the following result.

Theorem 1.2. Let 1/p1/q 1 withp > 1, Kx, y, fx, gy, ϕx, ψybe nonnegative functions andFxF1x, Gy ≤ G1y,whereFxandGyare defined by1.9. Then the following inequalities hold and are equivalent:

Ω2K x, y

fxg y

1xdμ2

y

ΩϕpxF1xfpxdμ1x 1/p

ΩψqyG1ygqydμ2y 1/q

,

ΩG1−p1 y

ψ−p

y

ΩK x, y

fxdμ1x p

2

y

ΩϕpxF1xfpxdμ1x.

1.10

In this paper a generalization of Theorem 1.1 for a general type of homogeneous kernels is obtained. Recall that for a homogeneous function Kx, y of degree −λ, λ > 0, equality Ktx, ty t−λKx, y is satisfied for every t > 0. Further, we define :

0K1, tt−αdtand suppose thatkα<∞for 1−λ < α <1.

In what follows, without further explanation, we assume that all series and integrals exist on the respective domains of their definitions.

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2. Main Results

We applyTheorem 1.2to obtain the following theorem.

Theorem 2.1. Letλ >0, 1/p1/q1 withp >1.Let{an}n1and{bn}n1be two nonnegative real sequences. IfKx, y0 is homogeneous function of degree−λstrictly decreasing in both parameters xandy, μ≥0,then the following inequalities hold and are equivalent:

m1

n1

K

mμ, nμ ambn

L

m1

1−λpA1−A2 apm

1/p

n1

1−λqA2−A1 bqn

1/q

,

2.1

n1

λ−1p−1pA1−A2

m1

Kmμ, nμam p

Lp m1

1−λpA1−A2

apm, 2.2

whereA1∈max{1−λ/q,0},1/q, A2∈max{1−λ/p,0},1/pand Lk

pA2

1/p k

2−λqA1

1/q

. 2.3

Proof. We use the inequalities1.7,1.8, andTheorem 1.2with counting measure. First, we prove the inequality2.1. Putϕmμ mμA1andψnμ nμA2in the inequality 1.7. Then, we have

m1

n1

K

mμ, nμ ambn

m1

pA1 F

apm

1/p

n1

qA2 G

bqn

1/q

,

2.4

where Fmμ

n1Kmμ, nμ/nμpA2and Gnμ

m1Kmμ, n μ/mμqA1.SinceqA1 >0 andpA2 >0,the functionsFmμandGnμare strictly decreasing, where we have

F

< F1

:

0

K

mμ, yμ pA2 dy, G

< G1

:

0

K

xμ, nμ qA1 dx.

2.5

Using homogeneity of the functionsKand the substitutionu yμ/mμwe get

F1

1−λ−pA2

0

K1, tt−pA2dt

1−λ−pA2 k

pA2

. 2.6

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In a similar manner we obtain

G1

1−λ−qA1 k

2−λqA1

. 2.7

Now, the result follows fromTheorem 1.2.

Remark 2.2. Equality in the previous theorem is possible only if

fxpK1ϕx−pq, g yq

K2ψ y−pq

, 2.8

for arbitrary constantsK1andK2see5. Condition2.8immediately gives that nontrivial case of equality in2.1and2.2leads to divergent series.

Now, we consider some special choice of the parametersA1 andA2.More precisely, let the parametersA1andA2satisfy constraint

pA2qA1 2−λ. 2.9

Then, the constantLfromTheorem 2.1becomes

Lk pA2

. 2.10

Further, the inequalities2.1and2.2take form

m1

n1

K

mμ, nμ ambn

L

m1

−1pqA1 apm

1/p

n1

−1pqA2 bnq

1/q

,

2.11

n1

p−11−pqA2

m1

K

mμ, nμ am

p

≤Lp

m1

−1pqA1

apm. 2.12

In the following theorem we show, in a similar way as Yang did in6, that if the parameters A1andA2 satisfy condition2.9, then one obtains the best possible constant. To prove this result we need the next lemmasee6.

Lemma 2.3. Iffx≥0is decreasing in0,∞and strictly decreasing in a subinterval of0,∞, andI0:

0 fxdx <∞,then

I1:

1

fxdx

n1

fn< I0. 2.13

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Theorem 2.4. Letλ, μ, A1, A2, andKx, ybe defined as inTheorem 2.1. If the parametersA1and A2satisfy conditionpA2qA12−λ,then the constantsLkpA2andLpin the inequalities 2.11and2.12are the best possible.

Proof. For this purpose, withε > 0, setam mμ−qA1−ε/p andbn nμ−pA2−ε/q.Now, let us suppose that there exists a smaller constant 0< M < Lsuch that the inequality2.11 is valid. LetJdenote the right-hand side of2.11. UsingLemma 2.3, we have

JM

1μ−1−ε

n2

1

< M

1μ−1−ε

1

−1−ε dx

M ε

1με ε

1μ1

.

2.14

Further, letIdenote the left-hand side of the inequality2.11, for above choice of sequences

amand bn.Applying, respectively,Lemma 2.3, Fubini’s theorem, and substitutiont x μ/yμ,we have

1≥

n1

1

K

xμ, nμ

−qA1−ε/p

dx

−pA2−ε/q

1

−qA1−ε/p

1

K

xμ, yμ

−pA2−ε/q dy

dx

1

−1−εxμ/1μ

0

K1, tt−qA1ε/qdt dx 1

ε 1με

1

0

K1, tt−qA1ε/qdt

1

−1−εxμ/1μ

1

K1, tt−qA1ε/qdt dx

1 ε

1με 1

0

K1, tt−qA1ε/qdt

1

K1, tt−qA1−ε/pdt .

2.15

From2.11,2.14, and2.15we get

M ε

1μ1

1

0

K1, tt−qA1ε/qdt

1

K1, tt−qA1−ε/pdt. 2.16

By lettingε → 0,we obtain

M1

0

K1, tt−qA1dt

1

K1, tt−qA1dtk qA1

. 2.17

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Using symmetry of the functionKx, y,we havekqA1 kpA2 L.Now, from2.17 we obtain a contradiction with assumptionM < LkpA2.

Finally, equivalence of the inequalities2.11and2.12means that the constantLp is the best possible in the inequality2.12. This completes the proof.

We proceed with some special homogeneous functions. Since the functionKx, y 1/xαyαλis homogeneous of degree−αλ,by usingTheorem 2.4we obtain the following.

Corollary 2.5. Let λ > 0, α > 0, μ ≥ 0.Suppose that the parameters A1, A2 satisfy condition pA2gA12−αλ.Then the following inequalities hold and are equivalent:

m1

n1

ambn α

αλ

L1

m1

−1pqA1 apm

1/p

n1

−1pqA2 bqn

1/q

,

n1

p−11−pqA2

m1

am

α

αλ

p

Lp1 m1

−1pqA1 apm,

2.18

where the constant factorsL1 1/αB1−pA2/α,1−qA1andLp1are the best possible.

Remark 2.6. If we putα1, A1A2 2−λ/pqinCorollary 2.5, then the inequalities2.18 become

m1

n1

ambn

mnλL1

m1

1−λ apm

1/p

n1

1−λ bnq

1/q

,

n1

p−1λ−1

m1

am mnλ

p

Lp1 m1

1−λ apm,

2.19

where the constant factorsL1B1/pλ−1/q,1/qλ−1/p, andLp1are the best possible.

For λ 1 we obtain nonweighted case with the best possible constant L1 B1/p,1/q.

Settingμ1/2 andλ1 in the inequalities2.19we obtain the inequalities1.1and1.2 from Introduction.

Remark 2.7. It is easy to see thatTheorem 2.4is the generalization ofTheorem 1.1. Namely, let us defineA1 1/q−λ/qr, A2 1/p−λ/ps, andKmμ, nμ lnmμ/n μ/mμλ−nμλ.Note that the parametersA1, A2satisfy conditionpA2qA12−λ.

Then, the best possible constantLfromTheorem 2.4becomeskλsfromTheorem 1.1see also4.

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Remark 2.8. Similarly as in Corollary 2.5, for the homogeneous function of degree

−1, Kx, y xλ−1yλ−1/xλyλ,nonnegative real sequencesa{am}m1, b{bm}m1, and the parametersA1A21/pq,we have

m1

n1

λ−1

λ−1 λ

λ ambnL2apbq,

n1

m1

λ−1

λ−1 λ

λ am

p

Lp2app,

2.20

where the constantsL2 π/λ1/sinπ/p 1/sinπ/qandLp2 are the best possible.

Remark 2.9. Let λ, A1, A2, and Kx, y be defined as in Theorem 2.1. Take μ 0 in the inequalities2.11and2.12. By usingTheorem 2.4we get equivalent inequalities for general homogeneous kernelKx, y:

m1

n1

Km, nambnL

m1

m−1pqA1apm

1/p

n1

n−1pqA2bnq

1/q

,

n1

np−11−pqA2

m1

Km, nam p

≤Lp

m1

m−1pqA1apm,

2.21

where the constant factorsLkpA2andLpare the best possible.

SettingA11/q−λ/qr, A2 1/p−λ/psin the inequalities2.21we obtain the result from6. Similarly, for above choice of the parametersA1, A2, andKx, y 1/xαyαλ,we obtain Yang’s result1.3from Introduction.

References

1 G. H. Hardy, J. E. Littlewood, and G. P ´olya, Inequalities, Cambridge University Press, Cambridge, UK, 2nd edition, 1967.

2 B. Yang and L. Debnath, “On a new generalization of Hardy-Hilbert’s inequality and its applications,”

Journal of Mathematical Analysis and Applications, vol. 233, no. 2, pp. 484–497, 1999.

3 B. Yang, “On best extensions of Hardy-Hilbert’s inequality with two parameters,” Journal of Inequalities in Pure and Applied Mathematics, vol. 6, no. 3, article 81, pp. 1–15, 2005.

4 W. Zhong, “A Hilbert-type linear operator with the norm and its applications,” Journal of Inequalities and Applications, vol. 2009, Article ID 494257, 18 pages, 2009.

5 M. Krni´c and J. Peˇcari´c, “General Hilbert’s and Hardy’s inequalities,” Mathematical Inequalities &

Applications, vol. 8, no. 1, pp. 29–52, 2005.

6 B. Yang, “On a Hilbert-type operator with a class of homogeneous kernels,” Journal of Inequalities and Applications, vol. 2009, Article ID 572176, 9 pages, 2009.

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