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MALAYSIANMATHEMATICAL

SCIENCESSOCIETY http://math.usm.my/bulletin

Submersion of Semi-Invariant Submanifolds of Trans-Sasakian Manifold

1MOHAMMADHASANSHAHID,2FALLEHR. AL-SOLAMY,3JAE-BOKJUN AND4MOBINAHMAD

1Department of Mathematics, Jamia Millia Islamia, New Delhi-110025, India

2Department of Mathematics, Faculty of Science, University of Tabuk, P.O. Box-80015, Jeddah 21589, Saudi Arabia

3Department of Mathematics, College of Natural Science, Kookmin University, Seoul 136-702, Korea

4Department of Mathematics, Integral University, Kursi Road, Lucknow, 226026, India

1hasan [email protected],2[email protected],3[email protected],4[email protected]

Abstract. In this paper, we discuss submersion of semi-invariant submanifolds of trans- Sasakian manifold and derive some results on their differential geometry. We also discuss cohomology of semi-invariant submanifold of trans-Sasakian manifold under the submer- sion.

2010 Mathematics Subject Classification: 53C40

Keywords and phrases: Semi-invariant submanifolds,α-Sasakian manifold,β-Kenmotsu manifold, trans-Sasakian manifold, de Rham cohomology.

1. Introduction

The study of Riemannian submersions was initiated by O’Neill [15]. Semi-Riemannian submersions were introduced by O’Neill in [16]. It is well known that semi-Riemannian submersions are of interest in physics, owing to their applications in the Yang-Mills the- ory, Kaluza-Klein theory, supergravity and superstring theory [9, 11, 19, 20]. In [12], S.

Kobayashi studied submersion ofCR-submanifolds and obtained interesting results. In this paper we study submersion of semi-invariant submanifold of trans-Sasakian manifold.

Let ¯Mbe ann-dimensional almost contact metric manifold with almost contact metric structure(φ,ξ,η,g). Then they satisfy

(1.1) φ2=−1+η⊗ξ, φ◦ξ=0, η◦φ=0, η(ξ) =1, (1.2) g(φX,φY) =g(X,Y)−η(X)η(Y)

for any vector fieldsX,Y on ¯M.

Communicated byYoung Jin Suh.

Received:November 2, 2010;Revised:February 22, 2011.

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In 1985, Oubina introduced a new class of almost contact Riemannian manifold known as trans-Sasakian manifold [17]. An almost contact metric structure(φ,ξ,η,g)on ¯M is calledtrans-Sasakianif it satisfies

(1.3) (∇¯Xφ)Y =α[g(X,Y)ξ−η(Y)X] +β[g(φX,Y)ξ−η(Y)φX],

whereαandβ are non-zero constants on ¯M, ¯∇is a Riemannian connection ofgand we say that the trans-Sasakian structure is of type(α,β). A trans-Sasakian manifold is a general- ization of bothα-Sasakian andβ-Kenmotsu manifold.

LetMbe ann-dimensional isometrically immersed submanifold of ¯Mand tangent toξ. Letgbe the metric tensor field on ¯Mas well as the induced metric onM.

Definition 1.1. An m-dimensional Riemannian submanifold M of a trans-Sasakian manifold M is called a semi-invariant submanifold if¯ ξ is tangent to M and it is endowed with a pair of orthogonal differentiable distributions (D,D)which satisfies

(i) T M=D⊕D⊕ {ξ},where⊕denotes the orthogonal direct sum,

(ii) the distribution Dx :x−→D⊂TxM is invariant underφ i.e. φDx⊂Dxfor each x∈M,

(iii) the orthogonal complementary distribution D:x−→D⊂TxM of the distribution D on M is totally real i.e., φD⊂TxM where TxM,TxM are the tangent space and the normal space of M at x respectively.

Let the dimension ofD(resp.D) be 2p(resp.q) where 2p+q=m−1. If p=0 (resp.

q=0) the submanifoldMbecomesanti-invariant(resp.invariant) submanifold. Ageneric submanifoldMsatisfies dimD=dimTxM. A submanifold is calledproperif it is neither invariant nor anti-invariant. It is easy to see that any hypersurface to which the vector field ξ is tangent is a typical example of semi-invariant submanifold.

Definition 1.2. Let M be a semi-invariant submanifold of a trans-Sasakian manifoldM¯ and M0 be an almost contact metric manifold with the almost contact metric structure (φ000,g0).Assume that there is a submersionπ:M−→M0such that

(i) D=kerπ,whereπ:T M−→T M0is the tangent mapping toπ,

(ii) π:Dp⊕ {ξ} −→Tπ(p)M0is an isometry for each p∈M which satisfiesπ◦φ= φ0◦π; η=η0◦π; πp) =ξπ(0 p),where Tπ(p)M0 denotes the tangent space of M0atπ(p).

Papaghuic studied submersion of semi-invariant submanifolds of a Sasakian manifold [18]. For trans-Sasakian manifold we prove

Theorem 1.1. Letπ:M−→M0be a submersion of semi-invariant submanifold of a trans- Sasakian manifoldM onto an almost contact metric manifold M¯ 0. Then M0is also a trans- Sasakian manifold.

In particular, we obtain results on Sasakian manifold, Kenmotsu manifold, cosymplectic manifold, α-Sasakian manifold and β-Kenmotsu manifold through submersion of semi- invariant submanifolds. We also derive expressions relating curvatures of ¯M andM0 via submersions.

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2. Preliminaries and some results

LetMbe ann-dimensional isometrically immersed submanifold of trans-Sasakian manifold M¯ and tangent toξ and suppose ¯∇(resp.∇) be the covariant differentiation with respect to the Levi-Civita connection on ¯M(resp.M). The Gauss and Weingarten formulae forMare respectively given by

(2.1) ∇¯XY =∇XY+h(X,Y)

and

(2.2) ∇¯XN=−ANX+∇XN

forX,Y∈T M,N∈TM,whereh(resp.A) is the second fundamental form (resp. tensor) ofMin ¯Mand∇denotes the operator of the normal connection. Moreover we have

(2.3) g(h(X,Y),N) =g(ANX,Y).

The projection of T M toDandD are denoted byh andvrespectively i.e., for any X∈T Mwe have

(2.4) X=hX+vX+η(X)ξ.

The normal bundle toMhas the decomposition

(2.5) TM=φD⊕n1,

whereg(φD,n1) ={0}. For anyU∈TM, we put

(2.6) U=nU+mU,

wherenU∈φD, mU∈n1. Making use of the above equation, we may write (2.7) φU=φnU+φmU, U∈TM, φnU∈D, φmU∈n1.

A vector fieldX onMis said to bebasicifX∈Dp⊕ {ξ}andXisπ-related to a vector field onM0 i.e., there exists a vector fieldX∈T M0 such that π(Xp) =X∗π(p) for each p∈M.Note that, by condition (ii) of the above definition 1.2, we have that the structural vector fieldξ is a basic vector field.

Lemma 2.1. [18]Let X,Y be basic vector fields on M.Then (i) g(X,Y) =g0(X,Y)◦π,

(ii) the component h([X,Y]) +η([X,Y])ξ of[X,Y]is a basic vector field and corre- sponds to[X,Y],i.e.,π(h([X,Y]) +η([X,Y])ξ) = [X,Y],

(iii) [U,X]∈Dfor any U∈D,

(iv) h(∇XY) +η(∇XY)ξ is a basic vector field corresponding to∇XY, where∇de- notes the Levi-Civita connection on M0.

For basic vector fields onM, we define the operator ˜∇corresponding to∇by setting

∇˜XY =h(∇XY) +η(∇XY)ξ forX,Y ∈(D⊕ {ξ}).By (iv) of lemma 2.1, ˜∇XY is a basic vector field and we have

(2.8) π(∇˜XY) =∇XY. Define the tensor fieldCby

(2.9) ∇XY=∇˜XY+C(X,Y), X,Y∈(D⊕ {ξ}),

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whereC(X,Y)is the vertical part of∇XY.It is known thatCis skew-symmetric and satisfies

(2.10) C(X,Y) =1

2v[X,Y], X,Y ∈(D⊕ {ξ}).

The curvature tensorsR,Rof the connection∇,∇onM andM0respectively are related by [18]

R(X,Y,Z,W) =R(X,Y,Z,W)−g(C(Y,Z),C(X,W)) +g(C(X,Z),C(Y,W)) +2g(C(X,Y),C(Z,W)) X,Y,Z,W∈(D⊕ {ξ}),

(2.11)

whereπX=XY =YZ=ZandπW=W∈χ(M0).

First we prove the following.

Proposition 2.1. Let π:M−→M0 be a submersion of semi-invariant submanifold of a trans-Sasakian manifoldM onto an almost contact metric manifold M¯ 0.Then we have (2.12) (∇˜Xφ)Y =α[g(X,Y)ξ−η(Y)X] +β[g(φX,Y)ξ−η(Y)φX],

C(X,φY) =φnh(X,Y), (2.13)

φC(X,Y) =nh(X,φY), (2.14)

φmh(X,Y) =mh(X,φY) (2.15)

for any X,Y ∈(D⊕ {ξ}).

Proof. For anyX,Y∈(D⊕ {ξ})and by using Gauss formula (2.1), decomposition equation (2.6) and (2.9) we obtain

∇¯XY =∇XY+h(X,Y) =∇XY+nh(X,Y) +mh(X,Y)

=∇˜XY+C(X,Y) +nh(X,Y) +mh(X,Y).

(2.16) Hence

(2.17) φ∇¯XY =φ∇˜XY+φC(X,Y) +φnh(X,Y) +φmh(X,Y).

PuttingY =φY in (2.16), it follows

(2.18) ∇¯XφY =∇˜XφY+C(X,φY) +nh(X,φY) +mh(X,φY).

On the other hand, using the definition of trans-Sasakian manifold we find

(2.19) (∇¯Xφ)Y =∇¯XφY−φ∇¯XY=α[g(X,Y)ξ−η(Y)X] +β[g(φX,Y)ξ−η(Y)φX].

Substituting (2.17) and (2.18) in (2.19) we get

∇˜XφY+C(X,φY) +nh(X,φY) +mh(X,φY)−φ∇˜XY−φC(X,Y)

−φnh(X,Y)−φmh(X,Y) =α[g(X,Y)ξ−η(Y)X] +β[g(φX,Y)ξ−η(Y)φX]. Comparing components of(D⊕ {ξ}),D,φDandn1respectively on both sides in the above equation, we get the required results.

Corollary 2.1. Letπ:M−→M0be a submersion of semi-invariant submanifold of (a)β- Kenmotsu (b)α-Sasakian (c) Kenmotsu (d) Sasakian (e) cosymplectic manifoldM respec-¯ tively onto an almost contact metric manifold M0. Then we have

(i) (a0) (∇˜Xφ)Y=β[g(φX,Y)ξ−η(Y)φX],

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(b0) (∇˜Xφ)Y=α[g(X,Y)ξ−η(Y)X], (c0) (∇˜Xφ)Y= [g(φX,Y)ξ−η(Y)φX], (d0) (∇˜Xφ)Y= [g(X,Y)ξ−η(Y)X], (e0) (∇˜Xφ)Y=0,

(ii) C(X,φY) =φnh(X,Y), (iii) φC(X,Y) =nh(X,φY), (iv) φmh(X,Y) =mh(X,φY) for any X,Y ∈(D⊕ {ξ}).

Now we prove

Theorem 2.1. Letπ:M−→M0be a submersion of semi-invariant submanifold of a trans- Sasakian manifoldM onto an almost contact metric manifold M¯ 0. Then M0is also a trans- Sasakian manifold.

Proof. Using (2.12) of the Proposition 2.1, we write

(∇˜Xφ)Y =α[g(X,Y)ξ−η(Y)X] +β[g(φX,Y)ξ−η(Y)φX].

Applyingπto the above equation and using Lemma 2.1, (2.8) and definition of submersion, we derive

(∇˜Xφ0)Y

g0(X,Y0−η0(Y)X

g00X,Y0−η0(Y0X . The above equation shows thatM0is a trans-Sasakian manifold.

Corollary 2.2. Letπ :M−→M0 be a submersion of semi-invariant submanifold of (a) β-Kenmotsu (b)α-Sasakian (c) Kenmotsu (d) Sasakian (e) cosymplectic manifoldM re-¯ spectively onto an almost contact metric manifold M0.Then M0is also (a0)β-Kenmotsu (b0) α-Sasakian (c0) Kenmotsu (d0) Sasakian (e0) cosymplectic manifold.

Proposition 2.2. Let π:M−→M0 be a submersion of semi-invariant submanifold of a trans-Sasakian manifoldM onto an almost contact metric manifold M¯ 0. Then

(i) nh(φX,φY) +nh(φX,Y) =0, (ii) nh(φX,φY) =nh(X,Y), (iii) mh(φX,φY) =−mh(X,Y),

(iv) C(φX,φY) =C(X,Y) for any X,Y ∈(D⊕ {ξ}).

Proof.

(i) InterchangingXandY in (2.14) gives

φC(Y,X) =nh(Y,φX) =nh(φX,Y).

Then

nh(X,φY) +nh(φX,Y) =φC(X,Y) +φC(Y,X) =φC(X,Y)−φC(X,Y) =0.

(ii) PuttingX=φX in (2.14), we get

nh(φX,φY) =φC(φX,Y) =−φC(Y,φX).

Using (2.13) in the above equation, we deduce

nh(φX,φY) =−φC(Y,φX) =−φ(φnh(Y,X)) =−φ2nh(Y,X)

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=nh(Y,X)−η(h(X,Y))ξ =nh(Y,X).

(iii) PuttingX=φX in (2.15) and using again the same equation, we find mh(φX,φY) =φmh(φX,Y) =φmh(Y,φX) =φ2mh(Y,X) =−mh(X,Y).

(iv) PuttingX=φX in (2.13) and then using (2.14) yields

C(φX,φY) =φnh(φX,Y) =φnh(Y,φX) =φ2C(Y,X)

=−C(Y,X) +η(C(Y,X))ξ =C(X,Y).

3. Curvature relations

Proposition 3.1. Let π :M −→M0 be a submersion of semi-invariant submanifold of a trans-Sasakian manifold M onto an almost contact metric manifold M¯ 0. Then the φ- bisectional curvature ofM and M¯ 0are related by

B(X¯ ,Y) =B0(X,Y)−2knh(X,Y)k2−2knh(X,φY)k2

−2g(nh(X,X),nh(Y,Y)) +2kmh(X,Y)k2, where X,Y ∈(D⊕ {ξ}).

Proof. We know

B(X,Y¯ ) =R(X,¯ φX,φY,Y).

PutY=φX,Z=φY,W =Y in Gauss equation

R(X,¯ Y,Z,W) =R(X,Y,Z,W)−g(h(X,W),h(Y,Z)) +g(h(X,Z),h(Y,W)), we get

R(X,¯ φX,φY,Y) =R(X,φX,φY,Y)−g(h(X,Y),h(φX,φY)) +g(h(X,φY),h(φX,Y)).

Substitutingh=nh+mh,in the above equation, we arrive at

R(X,¯ φX,φY,Y) =R(X,φX,φY,Y)−g(nh(X,Y) +mh(X,Y),nh(φX,φY) +mh(φX,φY)) +g(nh(X,φY) +mh(X,φY),nh(φX,Y) +mh(φX,Y))

=R(X,φX,φY,Y)−g(nh(X,Y),nh(φX,φY))−g(nh(X,Y),mh(φX,φY))

−g(mh(X,Y),nh(φX,φY))−g(mh(X,Y),mh(φX,φY)) +g(nh(X,φY),nh(φX,Y)) +g(nh(X,φY),mh(φX,Y)) +g(mh(X,φY),nh(φX,Y)) +g(mh(X,φY),mh(φX,Y))

=R(X,φX,φY,Y)−g(nh(X,Y),nh(φX,φY))−g(mh(X,Y),mh(φX,φY)) +g(nh(X,φY),nh(φX,Y)) +g(mh(X,φY),mh(φX,Y))

=R(X,φX,φY,Y)−g(nh(X,Y),nh(X,Y)) +g(mh(X,Y),mh(X,Y))

−g(nh(X,φY),nh(X,φY)) +g(φmh(X,Y),φmh(X,Y))

=R(X,φX,φY,Y)− knh(X,Y)k2+2kmh(X,Y)k2− knh(X,φY)k2. (3.1)

Now by puttingY =φX,Z=φY,W=Yin (2.11) it follows

R(X,φX,φY,Y) =R(X0X0Y,Y)−g(C(φX,φY),C(X,Y)) +g(C(X,φY),C(φX,Y)) +2g(C(X,φX),C(φY,Y))

=R(X0X0Y,Y)−g(C(φX,φY),C(X,Y))

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−g(C(X,φY),C(Y,φX))−2g(C(X,φX),C(Y,φY)).

(3.2)

Applyingφto equationφC(X,Y) =nh(X,φY), we getφ2C(X,Y) =φnh(X,φY). This gives

−C(X,Y) +η(C(X,Y))ξ =φnh(X,φY) or

C(X,Y) =−φnh(X,φY).

Using the above relation in (3.2), we conclude

R(X,φX,φY,Y) =R(X0X0Y,Y)− knh(X,Y)k2

− knh(X,φY)k2−2g(nh(X,X),nh(Y,Y)).

(3.3)

Put this value ofR(X,φX,φY,Y)in (3.1) we obtain

R(X,¯ φX,φY,Y) =R(X0X0Y,Y)− knh(X,Y)k2− knh(X,φY)k2

−2g(nh(X,X),nh(Y,Y))− knh(X,Y)k2+2kmh(X,Y)k2− knh(X,φY)k2, which implies that

B(X¯ ,Y) =B0(X,Y)−2knh(X,Y)k2−2knh(X,φY)k2

−2g(nh(X,X),nh(Y,Y)) +2kmh(X,Y)k2.

Corollary 3.1. Letπ:M−→M0be a submersion of semi-invariant submanifold of a trans- Sasakian manifoldM onto an almost contact metric manifold. Then the¯ φ-sectional curva- ture ofM and M¯ 0are related by

H(X¯ ) =H0(X)−4knh(X,X)k2+2kmh(X,X)k2, where X∈(D⊕ {ξ}).

Proof. PuttingX=Y in the above expression of ¯B(X,Y)allow us to obtain B(X¯ ,X) =H(X¯ ) =H0(X)−2knh(X,X)k2−2knh(X,φX)k2

−2g(nh(X,X),nh(X,X)) +2kmh(X,X)k2

=H0(X)−4knh(X,X)k2−2knh(X,φX)k2+2kmh(X,X)k2. PuttingY =Xin (2.14) of Proposition 2.1

nh(X,φX) =φC(X,X) =0.

Thus we get

H(X¯ ) =H0(X)−4knh(X,X)k2+2kmh(X,X)k2.

4. Cohomology of submersion of semi-invariant submanifolds of trans-Sasakian ma- nifolds

In this section, we discuss how the submersionπ:M−→M0of a semi-invariant subman- ifoldM with minimal horizontal distribution(D⊕ {ξ})effects the topology ofM.LetM be a semi-invariant submanifold of a trans-Sasakian manifold ¯Mwith almost contact metric structure(φ,ξ,η,g).Assume that dim(D⊕ {ξ}) =2p+1 and dimM=m.We choose a lo- cal orthonormal frame{e1,e2, ...,ep,φe1,φe2, ....,φep,e2p+1=ξ,e2p+2, ...,em}onMsuch that{e1,e2, ...,ep,φe1,φe2, ....,φep,e2p+1=ξ}is a local orthonormal frame of(D⊕ {ξ}) and{e2p+2,e2p+3, ...,em} is that of D. Let{ω12, ....,ω2p+12p+2, ...,ωm} be the

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dual frame of 1-forms to the above local orthonormal frame. Define a 2p+1-formΩonM by

(4.1) Ω=ω1∧ω2∧....∧ω2p+1,

which is globally defined onM.

Definition 4.1. Let S be a q-dimensional distribution on a Riemannian manifold M. If

qi=1eiei∈S, then the distribution S is said to be minimal, where ∇is the Riemannian connection on M and{e1,e2, ...,eq}is a local orthonormal frame of S.

Theorem 4.1. LetM be a trans-Sasakian manifold and M be a closed semi-invarinat sub-¯ manifold ofM with minimal¯ (D⊕ {ξ}).Let M0be a almost contact metric manifold and π:M−→M0a submersion. Then the2p+1-formΩis closed which defines a canonical de Rham cohomology class[Ω]∈H2p+1(M,R),where2p+1=dim(D⊕ {ξ}).Moreover the cohomology group H2p+1(M,R)is non-trivial if Dis minimal.

Proof. From definition (4.1) ofΩ,we have dΩ=

2p+1 i=1

(−1)i−1ω1∧...∧dωi∧...∧ω2p+1.

From the above equation it follows thatdΩ=0 if and only if [8]

(4.2) dΩ(Z,W,E1, ....,E2p) =0 and dΩ(Z,E1, ...,E2p+1) =0

for Z,W ∈Dand E1, ...,E2p+1∈(D⊕ {ξ}). Choosing the vectors E1, ...,E2p+1∈ (D⊕ {ξ}) as a local orthonormal frame {e1,e2, ..., ep,φe1,φe2, ....,φep,e2p+1=ξ} of (D⊕ {ξ}) to which {ω12, ....,ω2p+1} works as dual frame of 1-forms, we get by a straightforward computation that the first equation in (4.2) holds if and only ifD is in- tegrable; and the second equation in (4.2) holds if and only if(D⊕ {ξ})is minimal. How- ever, from the definition of submersion it follows thatDis integrable. The hypothesis of theorem gives that(D⊕ {ξ})is minimal. Hence the formΩis closed, and it defines a de Rham cohomology class[Ω]∈H2p+1(M,R).

Now suppose thatDis minimal and we proceed to show that in this case H2p+1(M,R)6=0.

To accomplish this we show that the formΩis harmonic which would then make the coho- mology class[Ω]non-trivial. Define a(m−2p−1)-formΩonMby setting

2p+2∧....∧ωm,

where{ω2p+2, ....,ωm}is the dual frame to the local orthonormal frame{e2p+1, ...,em}of D.Then with the similar argument forΩ,it follows thatdΩ=0 if(D⊕{ξ})is integrable andDis minimal. It should be noted that minimality of(D⊕ {ξ})implies its integrability.

Since both conditions are met, we havedΩ=0.This proves that the 2p+1-formΩis co- closed, that isδΩ=0. SincedΩ=δΩ=0 andMis closed submanifold, we get thatΩis harmonic 2p+1-form; and this completes the proof.

Acknowledgement.The authors would like to express their thanks to the referee for several valuable suggestions. This work is partially supported by Kookmin University 2011.

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