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Research Article

Fixed points for non-self operators in gauge spaces

Tania Laz˘ara, Gabriela Petru¸selb,∗

aDepartment of Mathematics, Technical University of Cluj-Napoca, Memorandumului Street no. 28, 400114, Cluj-Napoca, Romania.

bDepartment of Business, Babe¸s-Bolyai University, Horia Street no. 7, 400174 Cluj-Napoca, Romania.

Dedicated to the memory of Professor Viorel Radu Communicated by Professor Dorel Mihet¸

Abstract

The purpose of this article is to present some local fixed point results for generalized contractions on (ordered) complete gauge space. As a consequence, a continuation theorem is also given. Our theorems generalize and extend some recent results in the literature.

Keywords: gauge space, generalized contraction, fixed point, ordered gauge space, continuation theorem.

2010 MSC: Primary 47H10, Secondary 54H25.

1. Introduction

Throughout this paper E will denote a nonempty set E endowed with a separating gauge structure D= {dα}α∈Λ, where Λ is a directed set (see [5] for definitions). LetN :={0,1,2,· · · } and N := N\ {0}.

We also denote byR the set of all real numbers and byR+:= [0,+∞).

A sequence (xn) of elements in Eis said to be Cauchy if for every ε >0 and α∈Λ, there is an N with dα(xn, xn+p)≤εfor alln≥N andp∈N. The sequence (xn) is called convergent if there exists an x0 ∈E such that for everyε >0 andα∈Λ, there is anN ∈N withdα(x0, xn)≤ε, for all n≥N.

A gauge space E is called complete if any Cauchy sequence is convergent. A subset of X is said to be closed if it contains the limit of any convergent sequence of its elements. See also J. Dugundji [5] for other definitions and details.

If f : E → E is an operator, then x ∈ E is called fixed point for f if and only if x = f(x). The set Ff :={x∈E|x=f(x)} denotes the fixed point set off.

On the other hand, Ran and Reurings [19] proved the following Banach-Caccioppoli type principle in ordered metric spaces.

Corresponding author

Email addresses: [email protected](Tania Laz˘ar),[email protected](Gabriela Petru¸sel) Received 2012-9-12

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Theorem 1.1 (Ran and Reurings [19]) Let X be a partially ordered set such that every pair x, y ∈X has a lower and an upper bound. Letdbe a metric on X such that the metric space(X, d) is complete. Let f :X →X be a continuous and monotone (i.e., either decreasing or increasing) operator. Suppose that the following two assertions hold:

1) there existsa∈]0,1[such that d(f(x), f(y))≤a·d(x, y), for each x, y∈X withx≥y 2) there existsx0∈X such thatx0≤f(x0) or x0≥f(x0).

Thenf has an unique fixed pointx∈X, i. e. f(x) =x, and for eachx∈X the sequence (fn(x))n∈N

of successive approximations off starting from x converges to x ∈X.

Since then, several authors considered the problem of existence (and uniqueness) of a fixed point for contraction-type operators on partially ordered sets.

In 2005, J.J. Nieto and R. Rodr´ıguez-L´opez in [12] proved a modified variant of Theorem 1.1, by removing the continuity of f. The case of decreasing operators is treated in J.J. Nieto and R. Rodr´ıguez- L´opez [14]. It is also worth mentioning that A. Petru¸sel, I.A. Rus in [16] and J.J. Nieto, R.L. Pouso, R.

Rodr´ıguez-L´opez, improved part of the above mentioned results working in the setting of abstractL-spaces in the sense of Fr´echet. D. O’Regan and A. Petru¸sel in [15] extended these theoretical results to the case of nonlinear contractions and gave some interesting applications to integral equations. Moreover, since then a lot of different generalizations and extensions of these results are proved in the literature (see [1], [2], [9], [10], [11], [22], etc.).

The aim of this paper is to present some local fixed point theorems for generalized contractions on ordered complete gauge space. As a consequence, a continuation theorem is also given. Our theorems generalize some of the above mentioned theorems, as well as, some other ones in the recent literature.

2. Preliminaries

LetX be a nonempty set and f :X →X be an operator. Then, f0:= 1X, f1 :=f, . . . , fn+1 =f◦fn, n∈N

denote the iterate operators off. Let Xbe a nonempty set and lets(X) :={(xn)n∈N|xn∈X, n∈N}. Let c(X)⊂s(X) a subset ofs(X) and Lim:c(X)→X an operator. By definition the triple (X, c(X), Lim) is called an L-space (Fr´echet [6]; see also [21]) if the following conditions are satisfied:

(i) Ifxn=x, for all n∈N, then (xn)n∈N ∈c(X) and Lim(xn)n∈N =x.

(ii) If (xn)n∈N ∈ c(X) and Lim(xn)n∈N = x, then for all subsequences, (xni)i∈N, of (xn)n∈N we have that (xni)i∈N ∈c(X) andLim(xni)i∈N =x.

By definition, an element ofc(X) is a convergent sequence,x:=Lim(xn)n∈N is the limit of this sequence and we also writexn→xas n→+∞.

In what follow we denote an L-space by (X,→).

In this setting, ifU ⊂X×X, then an operatorf :X→X is called orbitallyU-continuous (see [13]) if:

[x∈X and fn(i)(x)→a∈X, asi→+∞and (fn(i)(x), a)∈U for anyi∈N] imply [fn(i)+1(x)→f(a), as i→+∞]. In particular, if U =X×X, then f is called orbitally continuous.

Let (X,≤) be a partially ordered set, i.e., X is a nonempty set and ≤ is a reflexive, transitive and anti-symmetric relation onX. Denote

X:={(x, y)∈X×X|x≤y ory≤x}.

In the same setting, considerf :X→X. Then,

(LF)f :={x∈X|x≤f(x)}

is the lower fixed point set of f, while

(U F)f :={x∈X|x≥f(x)}

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is the upper fixed point set of f.

Iff :X →X andg:Y →Y, then the cartesian product off andg is denoted byf×gand it is defined in the following way:

f×g:X×Y →X×Y,(f×g)(x, y) := (f(x), g(y)).

Definition 2.1 LetX be a nonempty set. By definition (X,→,≤) is an ordered L-space if and only if:

(i) (X,→) is an L-space;

(ii) (X,≤) is a partially ordered set;

(iii) (xn)n∈N→x, (yn)n∈N→y andxn≤yn, for each n∈N ⇒x≤y.

If E := (E,D) is a gauge space, then the convergence structure is given by the family of gauges D = {dα}α∈Λ. Hence, (E,D,≤) is an ordered L-space and it will be called an ordered gauge space, see also [17], [18], [4].

If E := (E,D) is a gauge structure, then for r := {rα}α∈A ∈ (0,∞)A and x0 ∈ E, we will denote by Bd(x0, r) the closure of Bd(x0, r) in (E,D), where

Bd(x0, r) :={x∈E :dα(x0, x)< rα, for all α∈A}.

Recall that ϕ : R+ → R+ is said to be a comparison function if it is increasing and ϕk(t) → 0, as k→+∞. As a consequence, we also have ϕ(t)< t, for eacht >0,ϕ(0) = 0 andϕis right continuous at 0.

For example,ϕ(t) =at(wherea∈[0,1[),ϕ(t) = 1+tt andϕ(t) = ln(1 +t),t∈R+ are comparison functions.

3. Fixed point results

Our first main result is the following existence, uniqueness and approximation fixed point theorem.

Theorem 3.3 Let (E,D,≤) be an ordered complete gauge space, x0 ∈E and r :={rα}α∈A∈(0,∞)A. Let f :B :=Bd(x0, r)→E be an operator. Suppose that:

(i) B ∈I(f×f);

(ii) (x, y)∈B and (y, z)∈B imply (x, z)∈B; (iii) (x0, f(x0))∈B;

(iv) f is orbitally continuous;

(v) there exists a comparison function ϕ:R+ →R+ such that, for eachα∈Λ we have dα(f(x), f(y))≤ϕ(dα(x, y)), for each (x, y)∈B.

Then, f has at least one fixed point x ∈B and, for each x∈B, the sequence (fn(x))n∈N converges to x. Moreover, the fixed point is unique in B.

Proof. Let x0 ∈E be such that (x0, f(x0))∈B. Suppose first thatx0 6=f(x0). From (i) we obtain (f(x0), f2(x0)),(f2(x0), f3(x0)),· · · ,(fn(x0), fn+1(x0)),· · · ∈B.

From (v), by induction, we get, for eachα∈Λ, that

dα(fn(x0), fn+1(x0))≤ϕn(dα(x0, f(x0)), for each n∈N.

Since ϕn(dα(x0, f(x0)) → 0 as n → +∞, for an arbitrary ε > 0 we can choose N ∈ N such that dα(fn(x0), fn+1(x0)) < ε−ϕ(ε), for each n ≥ N. Since (fn(x0), fn+1(x0)) ∈ B for all n ∈ N, we have that:

dα(fn(x0), fn+2(x0))≤dα(fn(x0), fn+1(x0)) +dα(fn+1(x0), fn+2(x0))

< ε−ϕ(ε) +ϕ(dα(fn(x0), fn+1(x0))≤ε, for all n≥N.

Now since (fn(x0), fn+2(x0))∈B (see (iii)) we have for any n≥N that dα(fn(x0), fn+3(x0))≤dα(fn(x0), fn+1(x0)) +dα(fn+1(x0), fn+3(x0))

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< ε−ϕ(ε) +ϕ(dα(fn(x0), fn+2(x0))≤ε.

By induction, for each α∈Λ, we have

dα(fn(x0), fn+k(x0))< ε, for any k∈N and n≥N.

Hence (fn(x0))n∈N is a Cauchy sequence in (B,D). From the completeness of the gauge space (E,D) we have (fn(x0))n∈N→x ∈B asn→+∞.

Let x ∈ E be such that (x, x0) ∈ B then (fn(x), fn(x0)) ∈ B and thus, for each α ∈ Λ, we have dα(fn(x), fn(x0))≤ϕn(dα(x, x0)), for each n∈N. Letting n→ +∞ we obtain that (fn(x))n∈N→ x. By the orbital continuity of f we get that x ∈Ff. Thusx =f(x).

If f(x0) =x0, thenx0 plays the role of x.

Remark 3.4Equivalent representation of condition (iii) are:

(iv)’ There exists x0 ∈E such that x0 ≤f(x0) or x0 ≥f(x0) (iv)” (LF)fS

(U F)f 6=∅.

Remark 3.5Condition (i) is implied by each of the following assertions:

(ii)’ f : (B,≤)→(E,≤) is increasing (ii)” f : (B,≤)→(E,≤) is decreasing.

In a similar way to Theorem 3.3, we can prove the following result, which is useful for applications (see [17]).

Theorem 3.6 Let (E,D,≤) be an ordered complete gauge space, x0 ∈E and r :={rα}α∈A∈(0,∞)A. Let f :B :=Bd(x0, r)→E be an operator. We suppose that:

(i) f : (B,≤)→(E,≤) is increasing;

(ii) x0≤f(x0);

(iii)A f is orbitally continuous or

(iii)B if an increasing sequence (xn)n∈N converges to x in B, then xn≤x for all n∈N; (iv) there exists a comparison function ϕ:R+ →R+ such that

dα(f(x), f(y))≤ϕ(dα(x, y)), for each (x, y)∈B with x≤y and for all α∈Λ;

(v) dα(x0, f(x0))< r−ϕ(r), for each α∈Λ;

Thenf has at least one fixed point in B. Moreover, the fixed point is unique in the set B of comparable elements from B.

Proof. Since f : (B,≤) → (E,≤) is increasing and x0 ≤ f(x0) we immediately have x0 ≤ f(x0) ≤ f2(x0)≤ · · ·fn(x0)≤ · · ·. Notice that, by (v), we have thatf(x0)∈B. Thus, by (v) and (iv) we get that, for each α ∈ Λ, we have dα(f2(x0), f(x0)) ≤ ϕ(dα(f(x0), x0)) < ϕ(r). Hence, for each α ∈ Λ, we obtain dα(f2(x0), x0) ≤ dα(f2(x0), f(x0)) +dα(f(x0), x0) < ϕ(r) +r−ϕ(r) = r, proving that f2(x0) ∈ B. By induction, we get thatfn(x0)∈B, for each n∈ {1,2,· · · }.

Now using (iv), we obtain dα(fn(x0), fn+1(x0)) ≤ ϕn(dα(x0, f(x0)), for each n ∈ N. By a similar approach as in the proof of Theorem 3.3 we obtain:

dα(fn(x0), fn+k(x0))< ε, for any k∈N and n≥N.

Hence (fn(x0))n∈N is a Cauchy sequence in E. From the completeness of the gauge space we have that (fn(x0))n∈N→x ∈B asn→+∞.

By the orbital continuity of the operator f we get that x ∈ Ff. If (iii)B takes place, then, since (fn(x0))n∈N→x, given any >0 there existsN∈Nsuch that for eachn≥Nwe havedα(fn(x0), x)< . On the other hand, for eachn≥N, sincefn(x0)≤x, we have, for eachα∈Λ, that:

dα(x, f(x)) ≤ dα(x, fn+1(x0)) +dα(f(fn(x0)), f(x)) ≤ dα(x, fn+1(x0)) +ϕ(dα(fn(x0), x)) < 2.

Thusx∈Ff.

The uniqueness of the fixed point follows by contradiction. Suppose there exists y ∈Ff, withx 6=y and (x, y) ∈B. Then we have 0 < dα(y, x) =dα(fn(y), fn(x))≤ ϕn(dα(y, x)) →0 as n →+∞, which is a contradiction. Hencex=y.

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Remark 3.7A kind of dual result also holds, with the following modified assumptions:

(ii)’ x0 ≥f(x0);

(iii)0B if a decreasing sequence (xn)n∈N converges tox in B, then xn≥x for alln∈N.

Remark 3.8 It is worth to mention that could be of interest to extend the above technique for other metrical fixed point theorems, see [3], [8], etc. It is also an open problem to present a fixed point theory (in the sense of [20]) for contractions and generalized contractions in ordered complete gauge spaces.

As a consequence of the above results a continuation result can be given now. For a nice survey on this topic see Frigon [7].

Theorem 3.9Let (E,D)be a complete gauge space, where D:={dα}α∈Λ is a gauge structure onE. Let U be an open subset ofE andG:U×[0,1]→Ebe an operator. Assume that the following assumptions are satisfied:

(i) x6=G(x, t), for each x∈∂U (the boundary ofU) and each t∈[0,1];

(ii) there exists a:={aα}α∈A∈]0,+∞[Λ such thataα<1 and

dα(G(x,·), G(y,·))≤aα·dα(x, y), for each x, y∈U and for each α∈Λ.

(iii) there exists a continuous function φ: [0,1]→R such that

dα(G(x, t), G(x, s))≤ |φ(t)−φ(s)|, for allt, s∈[0,1] and eachx∈U; (iv) G:U× [0,1]→E is continuous;

(v) G(·, t) :U →E is increasing.

ThenG(·,0) has a fixed point if and only if G(·,1)has a fixed point.

Proof. Suppose that z∈FG(·,0). From (i) we have that z∈U. Consider the set S :={(t, x)∈[0,1]×U :x=G(x, t)}.

Since (0, z)∈S, we have thatS 6=∅. We introduce a partial order defined on S by the formula:

(t, x)≤(s, y) if and only if t≤sand dα(x, y)≤ 2 1−aα

[φ(s)−φ(t)].

LetM be a totally ordered subset ofS,t:= sup{t : (t, x)∈M}and let (tn, xn)n∈N ⊂M be a sequence such that (tn, xn)≤(tn+1, xn+1) for each n∈N and let tn→t asn→ ∞. Then

dα(xm, xn)≤ 2

1−aα[φ(tm)−φ(tn)], for each m, n∈N, m > n.

Lettingm, n→+∞we obtain thatdα(xm, xn)→0, proving that (xn)n∈N is Cauchy. Denote byx ∈E its limit. Sincexn =G(xn, tn),n∈N and using the fact that G is continuous, we get thatx =G(x, t).

From (i) we note thatx∈U. Thus (t, x)∈S.

From the fact that M is totally ordered we have that (t, x)≤(t, x), for each (t, x)∈M. Thus (t, x) is an upper bound ofM. We can apply Zorn’s Lemma, soS admits a maximal element (t0, x0)∈S. Notice here that G(x0, t)≤G(x0, t0) =x0, for each t∈[0,1]. We now prove that t0 = 1.

Suppose that t0 < 1. Let r = {rα}α∈A ∈ (0,∞)A and t ∈]t0,1] be such that Bd(x0, rα) ⊂ U and rα := 1−a2

α[φ(t)−φ(t0)] for every α∈A. Then for each α∈A we have:

dα(x0, G(x0, t)) ≤ dα(x0, G(x0, t0)) +dα(G(x0, t0), G(x0, t))

≤ φ(t)−φ(t0) = rα(1−aα)

2 <(1−aα)rα.

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Since Bd(x0, rα)⊂U, the operator G(·, t) :Bd(x0, r) →Esatisfies, for all t∈[0,1], the assumptions of the dual variant of Theorem 3.6 (withϕα(t) :=aαt, for eacht∈[0,1]). Hence there existsx∈Bd(x0, rα) such thatx=G(x, t). Thus (t, x)∈S. Since we have that

dα(x0, x)≤rα= 2 1−aα

[φ(t)−φ(t0)], thus we have that

(t0, x0)<(t, x),

which contradicts the maximality of (t0, x0). Thust0 = 1 and the proof is complete.

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