Volume 2012, Article ID 329298,14pages doi:10.1155/2012/329298
Research Article
Tripled Coincidence Point Theorems for Nonlinear Contractions in Partially Ordered Metric Spaces
Binayak S. Choudhury,
1Erdal Karapınar,
2and Amaresh Kundu
31Department of Mathematics, Bengal Engineering and Science University, Shibpur, Howrah 711103, India
2Department of Mathematics, Atilim University, ˙Incek 06836, Ankara, Turkey
3Department of Mathematics, Siliguri Institute of Technology, Darjeeling 734009, India
Correspondence should be addressed to Amaresh Kundu,[email protected] Received 12 April 2012; Accepted 19 May 2012
Academic Editor: Paolo Ricci
Copyrightq2012 Binayak S. Choudhury et al. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.
Tripled fixed points are extensions of the idea of coupled fixed points introduced in a recent paper by Berinde and Borcut, 2011. Here using a separate methodology we extend this result to a triple coincidence point theorem in partially ordered metric spaces. We have defined several concepts pertaining to our results. The main results have several corollaries and an illustrative example.
The example shows that the extension proved here is actual and also the main theorem properly contains all its corollaries.
1. Introduction and Preliminaries
In recent times coupled fixed point theory has experienced a rapid growth in partially ordered metric spaces. The speciality of this line of research is that the problems herein utilize both order theoretic and analytic methods. References1–19are some instances of these works.
Definition 1.1see14. A functiong : R → R is said to be monotone nondecreasingor increasingifx≥yimpliesgx≥gy.
Definition 1.2see14. LetX be a nonempty set. LetF : X×X → X be a mapping. An elementx, yis called a coupled fixed point ofFif
F x, y
x, F y, x
y. 1.1
Recently, Berinde and Borcut20extended the idea of coupled fixed points to tripled fixed points. The definition is as follows.
Definition 1.3see20. LetXbe a nonempty set. LetF:X×X×X → Xbe a mapping. An elementx, y, zis called a tripled fixed point ofFif
F x, y, z
x, F y, x, y
y, F z, y, x
z. 1.2 They also extended the mixed monotone property to functions with three arguments.
Definition 1.4see20. LetX,be a partially ordered set andF : X×X×X → X. The mappingFis said to have the mixed monotone property if for anyx, y, z∈X
x1, x2∈X, x1x2⇒F
x1, y, z F
x2, y, z , y1, y2∈X, y1y2 ⇒F
x, y1, z F
x, y2, z , z1, z2 ∈X, z1z2⇒F
x, y, z1
F
x, y, z2
.
1.3
Our purpose here is to establish tripled coincidence point results in metric spaces with partial ordering. For that purpose we define mixedg-monotone property in the following.
Mixed g-monotone property was already defined in the context of coupled fixed points14.
Here in the spirit ofDefinition 1.4we have made an extension of that.
Definition 1.5. LetX,be a partially ordered set. Letg :X → XandF :X×X×X → X.
The mappingFis said to have the mixedg-monotone property if for anyx, y, z∈X.
x1, x2∈X, gx1gx2⇒F
x1, y, z F
x2, y, z , y1, y2∈X, gy1gy2⇒F
x, y1, z F
x, y2, z , z1, z2∈X, gz1gz2⇒F
x, y, z1
F
x, y, z2
.
1.4
Coupled coincidence point was defined by Lakshmikantham and ´Ciri´c14. We also extend the concept of coupled coincidence point to tripled coincidence point in the following.
Definition 1.6. LetXbe any nonempty set. Letg:X → XandF :X×X×X → X. An element x, y, zis called a tripled coincidence point ofgandFif
F x, y, z
gx, F y, x, y
gy, F z, y, x
gz. 1.5 We extend the concept of commuting mappings given by Lakshmikantham and ´Ciri´c 14, in the following definition.
Definition 1.7. LetX be a nonempty set. Then one says that the mappingsg : X → Xand F:X×X×X → Xare commuting if for allx, y, z∈X
g F
x, y, z F
gx, gy, gz
. 1.6
The following is the definition of compatible mappings which is an extension of the compatibility defined by Choudhury and Kundu in8.
Definition 1.8see8. LetX, dbe a metric space. The mappingsgandF, whereg:X → X andF:X×X×X → Xare said to be compatible if
n→ ∞limd gF
xn, yn, zn
, F
gxn, gyn, gzn
0,
nlim→ ∞d gF
yn, xn, yn
, F
gyn, gxn, gyn
0,
n→ ∞limd gF
zn, yn, xn , F
gzn, gyn, gxn 0,
1.7
whenever{xn},{yn},{zn}are sequences inXsuch that
nlim→ ∞F
xn, yn, zn
gxnx,
nlim→ ∞F
yn, xn, yn
gyny,
nlim→ ∞F
zn, yn, xn
gznz.
1.8
2. Main Results
Theorem 2.1. LetX,be a partially ordered set and suppose there is a metricdonX such that X, dis a complete metric space. SupposeF:X×X×X → Xandg :X → Xare such that,gis monotone increasing,Fhas the mixedg-monotone property and
d F
x, y, z
, Fu, v, w
≤ψ max
d gx, gu
, d gy, gv
, d
gz, gw
2.1 for allx, y, z∈Xfor whichgxgu,gygvandgzgw, whereψ:0,∞ → 0,∞is such thatψtis monotone,ψt< tand limr→tψr< tfor allt >0. SupposeFX×X×X⊆gX,g is continuous, and{g, F}is a compatible pair. Suppose either
aF is continuous or
bXhas the following properties:
iif a nondecreasing sequence{αn} → α, thenαnαfor alln, iiif a nonincreasing sequence{βn} → β, thenβnβfor alln.
If there existx0, y0, z0 ∈ X such thatgx0 Fx0, y0, z0,gy0 Fy0, x0, y0, andgz0 Fz0, y0, x0, then there existx, y, z∈Xsuch that
F x, y, z
gx, F y, x, y
gy, F z, y, x
gz, 2.2
that is,gandFhave a tripled coincidence point.
Proof. By a condition of the theorem, there existx0, y0, z0 ∈X such thatgx0 Fx0, y0, z0, gy0 Fy0, x0, y0, and gz0 Fz0, y0, x0. Since FX ×X ×X ⊆ gX, we can choose x1, y1, z1∈Xsuch that
gx1F
x0, y0, z0
, gy1F
y0, x0, y0
, gz1F
z0, y0, x0
. 2.3
Continuing this process, we can construct sequences{xn},{yn}, and{zn}inXsuch that gxn1F
xn, yn, zn
, gyn1F
yn, xn, yn
, gzn1F
zn, yn, xn
. 2.4
Next we will show that, forn≥0,
gxngxn1, gyngyn1, gzn gzn1. 2.5
Since,gx0Fx0, y0, z0, gy0Fy0, x0, y0, andgz0 Fz0, y0, x0, by2.3, we get
gx0gx1, gy0gy1, gz0gz1, 2.6
that is,2.5holds forn0.
We presume that2.5holds for somen m > 0. As F has the mixed g-monotone property andgxmgxm1, gymgym1andgzmgzm1, we obtain
gxm1F
xm, ym, zm F
xm1, ym, zm
F
xm1, ym, zm1 F
xm1, ym1, zm1
gxm2,
2.7
gym1F
ym, xm, ym F
ym, xm, ym1 F
ym1, xm, ym1 F
ym1, xm1, ym1
gym2,
2.8
gzm1F
zm, ym, xm F
zm1, ym, xm F
zm1, ym1, xm
F
zm1, ym1, xm1
gzm2.
2.9
Thus,2.5holds fornm1. Then, by induction, we conclude that2.5holds forn≥1.
If for somen∈N,
gxngxn1, gyngyn1, gzn gzn1, 2.10
then, by2.4,xn, yn, znis a tripled coincidence point ofgandF. Therefore we assume, for anyn∈N,
gxn, gyn, gzn
/
gxn1, gyn1, gzn1
. 2.11
Setδnmax{dgxn, gxn1, dgyn, gyn1, dgzn, gzn1}.
Then
δn>0 ∀n≥0. 2.12
Then, by2.1,2.4and2.5, we have d
gxn, gxn1 d
F
xn−1, yn−1, zn−1 , F
xn, yn, zn
≤ψ max
d
gxn−1, gxn
, d
gyn−1, gyn
, d
gzn−1, gzn
,
d
gyn, gyn1 d
F
yn−1, xn−1, yn−1 , F
yn, xn, yn
≤ψ max
d
gyn−1, gyn , d
gxn−1, gxn , d
gyn−1, gyn , d
gzn, gzn1 d
F
zn−1, yn−1, xn−1 , F
zn, yn, xn
≤ψ max
d
gzn−1, gzn , d
gyn−1, gyn , d
gxn−1, gxn .
2.13
Thus, from2.13we obtain that δnmax
d
gxn, gxn1 , d
gyn, gyn1 , d
gzn, gzn1
≤ψ max
d
gxn−1, gxn , d
gyn−1, gyn , d
gzn−1, gzn
. 2.14
It then follows from2.12and a propertyψ, that for alln≥1,
δn≤ψδn−1< δn−1. 2.15
Thus,{δn}is a monotone decreasing sequence of nonnegative real numbers. So, there exist a δ≥0 such that
nlim→ ∞δnδ. 2.16
Supposeδ >0. Lettingn → ∞in2.14, using2.15,2.16, and a property ofψ, we get
δ≤ψδ< δ, 2.17
which is a contradiction. Thusδ0, or
n→ ∞limδn0, 2.18
or
nlim→ ∞d
gxn1, gxn 0,
nlim→ ∞d
gyn1, gyn
0,
nlim→ ∞d
gzn1, gzn
0.
2.19
Now, we will prove that{gxn}, {gyn}, and{gzn} are Cauchy sequences. Suppose, to the contrary, that at least one of {gxn},{gyn}, and{gzn}is not a Cauchy sequence. So, there exists anε >0 for which we can find subsequences{gxnk}of{gxn},{gynk}of{gyn}, and {gznk}of{gzn}withnk> mk≥ksuch that
αkmax d
gxnk, gxmk , d
gynk, gymk , d
gznk, gzmk
≥ε. 2.20
Additionally, corresponding tomk, we may choosenksuch that it is the smallest integer satisfying2.20. Then, for allk≥0,
max d
gxnk−1, gxmk , d
gynk−1, gymk , d
gznk−1, gzmk
< ε. 2.21
By using2.20and2.21we have fork≥0,
ε≤αkmax d
gxnk, gxmk , d
gynk, gymk , d
gznk, gzmk
≤ max d
gxnk, gxnk−1 d
gxnk−1, gxmk , d
gynk, gynk−1 d
gynk−1, gymk , d
gznk, gznk−1 d
gznk−1, gzmk
≤ max d
gxnk, gxnk−1 , d
gynk, gynk−1 , d
gznk, gznk−1 ε
≤δnk−1ε.
2.22
Lettingk → ∞in2.22, and using2.19, we get
klim→ ∞αk lim
k→ ∞max d
gxnk, gxmk , d
gynk, gymk , d
gznk, gzmk
ε. 2.23
Let, fork≥0,
βkmax d
gxnk1, gxmk1 , d
gynk1, gymk1 , d
gznk1, gzmk1
. 2.24
Again, for allk≥0,
αk max d
gxnk, gxmk , d
gynk, gymk , d
gznk, gzmk
≤ max d
gxnk, gxnk1 d
gxnk1, gxmk1 d
gxmk1, gxmk , gynk, gynk1
d
gynk1, gymk1 d
gymk1, gymk , d
gznk, gznk1 d
gznk1, gzmk1 d
gzmk1, gzmk
≤ max d
gxnk, gxnk1 , d
gynk, gynk1 , d
gznk, gznk1 max
d
gxnk1, gxmk1 , d
gynk1, gymk1 , d
gznk1, gzmk1 max
d
gxmk, gxmk1 , d
gymk, gymk1 , d
gzmk, gzmk1
≤δnk1βkδmk1.
2.25
Analogously we have fork≥0,
βk max d
gxnk1, gxmk1 , d
gynk, gymk1 , d
gznk1, gzmk1
≤ max d
gxnk1, gxnk d
gxnk, gxmk d
gxmk, gxmk1 , d
gynk1, gynk d
gynk, gymk d
gymk, gymk1 , d
gznk1, gznk d
gznk, gzmk d
gzmk, gzmk1
≤ max d
gxnk, gxnk1 , d
gynk, gynk1 , d
gznk, gznk1 max
d
gxnk, gxmk , d
gynk, gymk , d
gznk, gzmk max
d
gxmk, gxmk1 , d
gymk, gymk1 , d
gzmk, gzmk1
≤δnk1αkδmk1.
2.26
Lettingk → ∞in2.25and2.26, we get that
k→ ∞lim max d
gxnk1, gxmk1 , d
gynk1, gymk1 , d
gznk1, gzmk1 lim
k→ ∞βkε lim
k→ ∞αk. 2.27
Sincenk> mk, fork≥0, we have
gxnkgxmk, gynkgymk,
gznkgzmk. 2.28
Then from2.1,2.4, and2.28, we have fork≥0, d
gxnk1, gxmk1 d
F
xnk, ynk, znk , F
xmk, ymk, zmk
≤ψ max
d
gxnk, gxmk , d
gynk, gymk , d
gznk, gzmk , d
gynk1, gymk1 d
F
ynk, xnk, ynk , F
ymk, xmk, ymk
≤ψ max
d
gynk, gymk , d
gxnk, gxmk , d
gynk, gymk , d
gznk1, gzmk1 d
F
znk, ynk, xnk , F
zmk, ymk, xmk
≤ψ max
d
gznk, gzmk , d
gynk, gymk , d
gxnk, gxmk . 2.29
From2.29fork≥0, we get βk≤ψ
max d
gxnk, gxmk , d
gynk, gymk , d
gznk, gzmk
ψαk. 2.30 Lettingk → ∞in2.30, using2.20,2.27, and a property ofψ, we get
ε≤ψε< ε, 2.31
which is a contradiction. This shows that{gxn},{gyn}, and{gzn}are Cauchy sequences.
SinceXis complete, there existx, y, z∈Xsuch that
nlim→ ∞gxnx, lim
n→ ∞gyny, lim
n→ ∞gznz. 2.32
From2.4and2.32, using the continuity ofg, we have gx lim
n→ ∞g gxn1
lim
n→ ∞g F
xn, yn, zn
, 2.33
gy lim
n→ ∞g gyn1
lim
n→ ∞g F
yn, xn, yn
, 2.34
gz lim
n→ ∞g gzn1
lim
n→ ∞g F
zn, yn, xn
. 2.35
Now we will show thatgxFx, y, z, gyFy, x, y, andgzFz, y, x.
Sinceg andF are compatible, in addition with2.33,2.34, and2.35, respectively imply
nlim→ ∞d g
F
xn, yn, zn , F
gxn, g yn
, gzn
0, 2.36
nlim→ ∞d g
F
yn, xn, yn
, F g
yn
, gxn, g yn
0, 2.37
nlim→ ∞d g
F
zn, yn, xn
, F
gzn, g yn
, gxn
0. 2.38
Suppose now the assumptionaholds, that is,Fis continuous.
For alln≥0, we have d
gx, F
gxn, gyn, gzn
≤d gx, g
F
xn, yn, zn d
g F
xn, yn, zn , F
gxn, gyn, gzn . 2.39 Taking the limit as n → ∞, using 2.32, 2.33, 2.36, and the facts that g and F are continuous, we havedgx, Fx, y, z 0.
Similarly, by using2.32,2.34, and2.37and2.32,2.35, and2.38, respectively, and also the facts that g and F are continuous, we have dgy, Fy, x, y 0 and dgz, Fz, y, x 0.
Thus we have proved thatgandFhave a tripled coincidence point.
Suppose that the assumption b holds. Since{gxn}, {gzn} are nondecreasing and gxn → xwithgzn → zand also{gyn}is nonincreasing withgyn → y, by assumptionb we have for alln
gxnx, gyny, gznz. 2.40
By virtue of monotone increasing property ofgwe have
ggxngx, ggyngy, ggzngz. 2.41
Now using2.4we have d
gx, F
x, y, z
≤d gx, g
gxn1 d
g
gxn1 , F
x, y, z
≤d gx, g
gxn1 d
g F
xn, yn, zn
, F
gxn, gyn, gzn
d
F
gxn, gyn, gzn , F
x, y, z
≤d gx, g
gxn1 d
g F
xn, yn, zn
, F
gxn, gyn, gzn
ψ
max d
ggxn, gx , d
ggyn, gy , d
ggzn, gz
,
by2.1,2.41 . 2.42
Taking the limit asn → ∞in the above inequality, using2.33,2.36, and2.41we have d
gx, F
x, y, z
≤ lim
n→ ∞ψ max
d
ggxn, gx , d
ggyn, gy , d
ggzn, gz
. 2.43
By2.33,2.34,2.35, and the property ofψ, we have d
gx, F
x, y, z
≤ψ0 0, 2.44
that is
gxF x, y, z
. 2.45
In a similar manner using 2.33,2.34,2.35, and 2.36, 2.37, 2.38, respectively, we obtain
gyF y, x, y
, gzF
z, y, x
. 2.46
Thus, we proved thatgandFhave a tripled coincidence point.
This completes the proof of the theorem.
Corollary 2.2. LetX,be a partially ordered set and suppose there is a metricdonXsuch that X, dis a complete metric space. SupposeF:X×X×X → Xandg:X → Xare such thatFhas the mixedg-monotone property and
d F
x, y, z
, Fu, v, w
≤ψ max
d gx, gu
, d gy, gv
, d
gz, gw
2.47 for anyx, y, z∈Xfor whichgxgu,gy gvandgz gw, whereψ : 0,∞ → 0,∞be such thatψtis monotone,ψt< tand limr→tψr< tfor allt >0. SupposeFX×X×X⊆gX, gis continuous, andFandgare commuting. Suppose either
aFis continuous, or
bXhas the following property:
iif a nondecreasing sequence{xn} → x, thenxnxfor alln, iiif a nonincreasing sequence{yn} → y, thenynyfor alln.
If there existx0, y0, z0 ∈ X such thatgx0 Fx0, y0, z0,gy0 Fy0, x0, y0, andgz0 Fz0, y0, x0, then there existx, y, z∈Xsuch that
F x, y, z
gx, F y, x, y
gy, F z, y, x
gz, 2.48 that is,Fandghave a tripled coincidence point.
Proof. Since a commuting pair is also a compatible pair, the result of theCorollary 2.2follows fromTheorem 2.1.
Later, by an example, we will show that the Corollary 2.2 is properly contained in Theorem 2.1.
Corollary 2.3. LetX,be a partially ordered set and suppose there is a metricdonXsuch that X, dis a complete metric space. SupposeF:X×X×X → Xbe such thatFhas the mixed monotone property and
d F
x, y, z
, Fu, v, w
≤ψ max
dx, u, d y, v
, dz, w
2.49 for anyx, y, z∈X for whichxu, yvandzw, whereψ :0,∞ → 0,∞be such that ψtis monotone,ψt< tand limr→tψr< tfor allt >0. Suppose
aFis continuous, or
bXhas the following property:
iif a nondecreasing sequence{xn} → x, thenxnxfor alln, iiif a nonincreasing sequence{yn} → y, thenynyfor alln.
If there exist x0, y0, z0 ∈ X such that x0 Fx0, y0, z0, y0 Fy0, x0, y0, and z0Fz0, y0, x0, then there existx, y, z∈Xsuch that
F x, y, z
x, F y, x, y
y, F z, y, x
z, 2.50 that is,Fhas a tripled fixed point.
Proof. Takinggx xinTheorem 2.1we obtainCorollary 2.3.
Corollary 2.4. LetX,be a partially ordered set and suppose there is a metricdonXsuch that X, dis a complete metric space. SupposeF:X×X×X → Xandg:X → Xare such thatFhas the mixed monotone property and
d F
x, y, z
, Fu, v, w
≤kmax
dx, u, d y, v
, dz, w
2.51
for anyx, y, z∈Xfor whichxu, yvandzw, where 0< k <1. Suppose either aFis continuous, or
bXhas the following property:
iif a nondecreasing sequence{xn} → x, then xnxfor alln, iiif a nonincreasing sequence{yn} → y, thenynyfor alln.
If there exist x0, y0, z0 ∈ X such that x0 Fx0, y0, z0, y0 Fy0, x0, y0, and z0 Fz0, y0, x0, then there existx, y, z∈Xsuch that
F x, y, z
x, F y, x, y
y, F z, y, x
z, 2.52 that is,Fhas a tripled coincidence point.
Proof. Takingψt kt,t >0 where 0< k <1, inCorollary 2.3we obtainCorollary 2.4.
The following corollary is the result of Berinde and Borcut in20.
Corollary 2.5. LetX,be a partially ordered set and suppose there is a metricdonXsuch that X, dis a complete metric space. SupposeF:X×X×X → Xbe such thatFhas the mixed monotone property and
d F
x, y, z
, Fu, v, w
≤a1dx, u a2d y, v
a3dz, w 2.53
for anyx, y, z∈Xfor whichxu, yvandzw, wherea1a2a3<1. Suppose either
aFis continuous, or
bXhas the following property:
iif a nondecreasing sequence{xn} → x, thenxnxfor alln iiif a nonincreasing sequence{yn} → y, thenynyfor alln.
If there exist x0, y0, z0 ∈ X such that x0 Fx0, y0, z0, y0 Fy0, x0, y0, and z0Fz0, y0, x0, then there existx, y, z∈Xsuch that
F x, y, z
x, F y, x, y
y, F z, y, x
z, 2.54 that is,Fhas a tripled fixed point.
Proof. The proof follows fromCorollary 2.4, since the inequality inCorollary 2.5implies that Corollary 2.4.
Remark 2.6. The method used in the proof of Corollary 2.5 is different from that used by Berinde and Borcut20.
Next we discuss an example.
Example 2.7. LetX. ThenX,is a partially ordered set with the partial ordering defined byxyif and only if|x| ≤ |y|andx·y≥0.
Letdx, y |x−y|forx, y∈ . ThenX, dis a complete metric space.
Letg:X → Xbe defined asgx x2/10, for allx∈X. LetF:X×X×X → Xbe defined as
F x, y, z
x2−y2z2
9 , ∀x, y, z∈X. 2.55 Then F obeys the mixedg-monotone property.
Letψ:0,∞ → 0,∞be defined asψt 1/3tfor allt∈0,∞.
Let,{xn}, {yn}, and{zn}be three sequences inXsuch that
nlim→ ∞F
xn, yn, zn
lim
n→ ∞gxn a,
nlim→ ∞F
yn, xn, yn
lim
n→ ∞g yn
b,
nlim→ ∞F
zn, yn, xn lim
n→ ∞gzn c.
2.56
Then explicitly,
nlim→ ∞
xn2−y2nz2n
9 lim
n→ ∞
x2n
10, ∀x, y, z∈X, or,
10a−10b10c
9 aimply a−10b10c0.
2.57
Again,
nlim→ ∞
yn2−xn2y2n
9 lim
n→ ∞
y2n
10, ∀x, y, z∈X, or,
10b−10a10b
9 bimply 11b−10a0.
2.58
And
nlim→ ∞
z2n−y2nx2n
9 lim
n→ ∞
z2n
10, ∀x, y, z∈X, or,
10c−10b10a
9 cimplyc−10b10a0.
2.59
Then from the above relations we have,a0, b0, andc0.
Therefore,
d g
F
xn, yn, zn , F
gxn, gyn, gzn
−→0 asn−→ ∞, d
g F
yn, xn, yn
, F
gyn, gxn, gyn
−→0 asn−→ ∞, d
g F
zn, yn, xn , F
gzn, gyn, gxn
−→0 asn−→ ∞.
2.60
Hence, the pairg, Fis compatible inX.
Also,x0 0, z0 c> 0, andy0 0 are three points inX such thatgx0 g0 0< c2/9F0,0, c Fx0, y0, z0, gy0 g0 0 F0,0,0 Fy0, x0, y0, andgz0
gc c2/10< c2/9Fc,0,0 Fz0, y0, x0.
We next verify inequality2.1ofTheorem 2.1. We takex, y, z, u, v, w∈ X, such that gxgu, gzgwandgygv, that is,x2≤u2, z2≤w2, andy2≥v2.
LetAmax{dgx, gu, dgy, gv, dgz, gw}max{|x2−u2|,|y2−v2|,|z2−w2|}.
ThendFx, y, z, Fu, v, w dx2 −y2z2/9,u2 −v2w2/9 |x2−u2− y2−v2 z2−w2/3| ≤|x2−u2||y2−v2||z2−w2|/9≤3A/9 A/3ψA ψmax{dgx, gu, dgy, gv, dgz, gw}.
Thus it is verified that the functions g, F, and ψ satisfy all the conditions of Theorem 2.1. Here0,0,0is the tripled coincidence point ofgandFinX.
Remark 2.8. It is observed that in Example 2.7 the function F and g do not commute, but they are compatible. HenceCorollary 2.2cannot be applied to this example. This shows that Theorem 2.1properly containsCorollary 2.2. Alsog /I, so the results of Berinde and Borcut 20cannot be applied to this example. This shows that result in20is effectively generalised.
References
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