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Volume 2012, Article ID 329298,14pages doi:10.1155/2012/329298

Research Article

Tripled Coincidence Point Theorems for Nonlinear Contractions in Partially Ordered Metric Spaces

Binayak S. Choudhury,

1

Erdal Karapınar,

2

and Amaresh Kundu

3

1Department of Mathematics, Bengal Engineering and Science University, Shibpur, Howrah 711103, India

2Department of Mathematics, Atilim University, ˙Incek 06836, Ankara, Turkey

3Department of Mathematics, Siliguri Institute of Technology, Darjeeling 734009, India

Correspondence should be addressed to Amaresh Kundu,[email protected] Received 12 April 2012; Accepted 19 May 2012

Academic Editor: Paolo Ricci

Copyrightq2012 Binayak S. Choudhury et al. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

Tripled fixed points are extensions of the idea of coupled fixed points introduced in a recent paper by Berinde and Borcut, 2011. Here using a separate methodology we extend this result to a triple coincidence point theorem in partially ordered metric spaces. We have defined several concepts pertaining to our results. The main results have several corollaries and an illustrative example.

The example shows that the extension proved here is actual and also the main theorem properly contains all its corollaries.

1. Introduction and Preliminaries

In recent times coupled fixed point theory has experienced a rapid growth in partially ordered metric spaces. The speciality of this line of research is that the problems herein utilize both order theoretic and analytic methods. References1–19are some instances of these works.

Definition 1.1see14. A functiong : RR is said to be monotone nondecreasingor increasingifxyimpliesgxgy.

Definition 1.2see14. LetX be a nonempty set. LetF : X×XX be a mapping. An elementx, yis called a coupled fixed point ofFif

F x, y

x, F y, x

y. 1.1

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Recently, Berinde and Borcut20extended the idea of coupled fixed points to tripled fixed points. The definition is as follows.

Definition 1.3see20. LetXbe a nonempty set. LetF:X×X×XXbe a mapping. An elementx, y, zis called a tripled fixed point ofFif

F x, y, z

x, F y, x, y

y, F z, y, x

z. 1.2 They also extended the mixed monotone property to functions with three arguments.

Definition 1.4see20. LetX,be a partially ordered set andF : X×X×XX. The mappingFis said to have the mixed monotone property if for anyx, y, zX

x1, x2X, x1x2F

x1, y, z F

x2, y, z , y1, y2X, y1y2F

x, y1, z F

x, y2, z , z1, z2X, z1z2F

x, y, z1

F

x, y, z2

.

1.3

Our purpose here is to establish tripled coincidence point results in metric spaces with partial ordering. For that purpose we define mixedg-monotone property in the following.

Mixed g-monotone property was already defined in the context of coupled fixed points14.

Here in the spirit ofDefinition 1.4we have made an extension of that.

Definition 1.5. LetX,be a partially ordered set. Letg :XXandF :X×X×XX.

The mappingFis said to have the mixedg-monotone property if for anyx, y, zX.

x1, x2X, gx1gx2F

x1, y, z F

x2, y, z , y1, y2X, gy1gy2F

x, y1, z F

x, y2, z , z1, z2X, gz1gz2F

x, y, z1

F

x, y, z2

.

1.4

Coupled coincidence point was defined by Lakshmikantham and ´Ciri´c14. We also extend the concept of coupled coincidence point to tripled coincidence point in the following.

Definition 1.6. LetXbe any nonempty set. Letg:XXandF :X×X×X → X. An element x, y, zis called a tripled coincidence point ofgandFif

F x, y, z

gx, F y, x, y

gy, F z, y, x

gz. 1.5 We extend the concept of commuting mappings given by Lakshmikantham and ´Ciri´c 14, in the following definition.

Definition 1.7. LetX be a nonempty set. Then one says that the mappingsg : XXand F:X×X×XXare commuting if for allx, y, zX

g F

x, y, z F

gx, gy, gz

. 1.6

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The following is the definition of compatible mappings which is an extension of the compatibility defined by Choudhury and Kundu in8.

Definition 1.8see8. LetX, dbe a metric space. The mappingsgandF, whereg:XX andF:X×X×XXare said to be compatible if

n→ ∞limd gF

xn, yn, zn

, F

gxn, gyn, gzn

0,

nlim→ ∞d gF

yn, xn, yn

, F

gyn, gxn, gyn

0,

n→ ∞limd gF

zn, yn, xn , F

gzn, gyn, gxn 0,

1.7

whenever{xn},{yn},{zn}are sequences inXsuch that

nlim→ ∞F

xn, yn, zn

gxnx,

nlim→ ∞F

yn, xn, yn

gyny,

nlim→ ∞F

zn, yn, xn

gznz.

1.8

2. Main Results

Theorem 2.1. LetX,be a partially ordered set and suppose there is a metricdonX such that X, dis a complete metric space. SupposeF:X×X×XXandg :XXare such that,gis monotone increasing,Fhas the mixedg-monotone property and

d F

x, y, z

, Fu, v, w

ψ max

d gx, gu

, d gy, gv

, d

gz, gw

2.1 for allx, y, zXfor whichgxgu,gygvandgzgw, whereψ:0,∞ → 0,∞is such thatψtis monotone,ψt< tand limr→tψr< tfor allt >0. SupposeFX×X×XgX,g is continuous, and{g, F}is a compatible pair. Suppose either

aF is continuous or

bXhas the following properties:

iif a nondecreasing sequencen} → α, thenαnαfor alln, iiif a nonincreasing sequencen} → β, thenβnβfor alln.

If there existx0, y0, z0X such thatgx0 Fx0, y0, z0,gy0 Fy0, x0, y0, andgz0 Fz0, y0, x0, then there existx, y, zXsuch that

F x, y, z

gx, F y, x, y

gy, F z, y, x

gz, 2.2

that is,gandFhave a tripled coincidence point.

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Proof. By a condition of the theorem, there existx0, y0, z0X such thatgx0 Fx0, y0, z0, gy0 Fy0, x0, y0, and gz0 Fz0, y0, x0. Since FX ×X ×XgX, we can choose x1, y1, z1Xsuch that

gx1F

x0, y0, z0

, gy1F

y0, x0, y0

, gz1F

z0, y0, x0

. 2.3

Continuing this process, we can construct sequences{xn},{yn}, and{zn}inXsuch that gxn1F

xn, yn, zn

, gyn1F

yn, xn, yn

, gzn1F

zn, yn, xn

. 2.4

Next we will show that, forn≥0,

gxngxn1, gyngyn1, gzn gzn1. 2.5

Since,gx0Fx0, y0, z0, gy0Fy0, x0, y0, andgz0 Fz0, y0, x0, by2.3, we get

gx0gx1, gy0gy1, gz0gz1, 2.6

that is,2.5holds forn0.

We presume that2.5holds for somen m > 0. As F has the mixed g-monotone property andgxmgxm1, gymgym1andgzmgzm1, we obtain

gxm1F

xm, ym, zm F

xm1, ym, zm

F

xm1, ym, zm1 F

xm1, ym1, zm1

gxm2,

2.7

gym1F

ym, xm, ym F

ym, xm, ym1 F

ym1, xm, ym1 F

ym1, xm1, ym1

gym2,

2.8

gzm1F

zm, ym, xm F

zm1, ym, xm F

zm1, ym1, xm

F

zm1, ym1, xm1

gzm2.

2.9

Thus,2.5holds fornm1. Then, by induction, we conclude that2.5holds forn≥1.

If for somen∈N,

gxngxn1, gyngyn1, gzn gzn1, 2.10

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then, by2.4,xn, yn, znis a tripled coincidence point ofgandF. Therefore we assume, for anyn∈N,

gxn, gyn, gzn

/

gxn1, gyn1, gzn1

. 2.11

Setδnmax{dgxn, gxn1, dgyn, gyn1, dgzn, gzn1}.

Then

δn>0 ∀n≥0. 2.12

Then, by2.1,2.4and2.5, we have d

gxn, gxn1 d

F

xn−1, yn−1, zn−1 , F

xn, yn, zn

ψ max

d

gxn−1, gxn

, d

gyn−1, gyn

, d

gzn−1, gzn

,

d

gyn, gyn1 d

F

yn−1, xn−1, yn−1 , F

yn, xn, yn

ψ max

d

gyn−1, gyn , d

gxn−1, gxn , d

gyn−1, gyn , d

gzn, gzn1 d

F

zn−1, yn−1, xn−1 , F

zn, yn, xn

ψ max

d

gzn−1, gzn , d

gyn−1, gyn , d

gxn−1, gxn .

2.13

Thus, from2.13we obtain that δnmax

d

gxn, gxn1 , d

gyn, gyn1 , d

gzn, gzn1

ψ max

d

gxn−1, gxn , d

gyn−1, gyn , d

gzn−1, gzn

. 2.14

It then follows from2.12and a propertyψ, that for alln≥1,

δnψδn−1< δn−1. 2.15

Thus,{δn}is a monotone decreasing sequence of nonnegative real numbers. So, there exist a δ≥0 such that

nlim→ ∞δnδ. 2.16

Supposeδ >0. Lettingn → ∞in2.14, using2.15,2.16, and a property ofψ, we get

δψδ< δ, 2.17

which is a contradiction. Thusδ0, or

n→ ∞limδn0, 2.18

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or

nlim→ ∞d

gxn1, gxn 0,

nlim→ ∞d

gyn1, gyn

0,

nlim→ ∞d

gzn1, gzn

0.

2.19

Now, we will prove that{gxn}, {gyn}, and{gzn} are Cauchy sequences. Suppose, to the contrary, that at least one of {gxn},{gyn}, and{gzn}is not a Cauchy sequence. So, there exists anε >0 for which we can find subsequences{gxnk}of{gxn},{gynk}of{gyn}, and {gznk}of{gzn}withnk> mkksuch that

αkmax d

gxnk, gxmk , d

gynk, gymk , d

gznk, gzmk

ε. 2.20

Additionally, corresponding tomk, we may choosenksuch that it is the smallest integer satisfying2.20. Then, for allk≥0,

max d

gxnk−1, gxmk , d

gynk−1, gymk , d

gznk−1, gzmk

< ε. 2.21

By using2.20and2.21we have fork≥0,

εαkmax d

gxnk, gxmk , d

gynk, gymk , d

gznk, gzmk

≤ max d

gxnk, gxnk−1 d

gxnk−1, gxmk , d

gynk, gynk−1 d

gynk−1, gymk , d

gznk, gznk−1 d

gznk−1, gzmk

≤ max d

gxnk, gxnk−1 , d

gynk, gynk−1 , d

gznk, gznk−1 ε

δnk−1ε.

2.22

Lettingk → ∞in2.22, and using2.19, we get

klim→ ∞αk lim

k→ ∞max d

gxnk, gxmk , d

gynk, gymk , d

gznk, gzmk

ε. 2.23

Let, fork≥0,

βkmax d

gxnk1, gxmk1 , d

gynk1, gymk1 , d

gznk1, gzmk1

. 2.24

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Again, for allk≥0,

αk max d

gxnk, gxmk , d

gynk, gymk , d

gznk, gzmk

≤ max d

gxnk, gxnk1 d

gxnk1, gxmk1 d

gxmk1, gxmk , gynk, gynk1

d

gynk1, gymk1 d

gymk1, gymk , d

gznk, gznk1 d

gznk1, gzmk1 d

gzmk1, gzmk

≤ max d

gxnk, gxnk1 , d

gynk, gynk1 , d

gznk, gznk1 max

d

gxnk1, gxmk1 , d

gynk1, gymk1 , d

gznk1, gzmk1 max

d

gxmk, gxmk1 , d

gymk, gymk1 , d

gzmk, gzmk1

δnk1βkδmk1.

2.25

Analogously we have fork≥0,

βk max d

gxnk1, gxmk1 , d

gynk, gymk1 , d

gznk1, gzmk1

≤ max d

gxnk1, gxnk d

gxnk, gxmk d

gxmk, gxmk1 , d

gynk1, gynk d

gynk, gymk d

gymk, gymk1 , d

gznk1, gznk d

gznk, gzmk d

gzmk, gzmk1

≤ max d

gxnk, gxnk1 , d

gynk, gynk1 , d

gznk, gznk1 max

d

gxnk, gxmk , d

gynk, gymk , d

gznk, gzmk max

d

gxmk, gxmk1 , d

gymk, gymk1 , d

gzmk, gzmk1

δnk1αkδmk1.

2.26

Lettingk → ∞in2.25and2.26, we get that

k→ ∞lim max d

gxnk1, gxmk1 , d

gynk1, gymk1 , d

gznk1, gzmk1 lim

k→ ∞βkε lim

k→ ∞αk. 2.27

Sincenk> mk, fork≥0, we have

gxnkgxmk, gynkgymk,

gznkgzmk. 2.28

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Then from2.1,2.4, and2.28, we have fork≥0, d

gxnk1, gxmk1 d

F

xnk, ynk, znk , F

xmk, ymk, zmk

ψ max

d

gxnk, gxmk , d

gynk, gymk , d

gznk, gzmk , d

gynk1, gymk1 d

F

ynk, xnk, ynk , F

ymk, xmk, ymk

ψ max

d

gynk, gymk , d

gxnk, gxmk , d

gynk, gymk , d

gznk1, gzmk1 d

F

znk, ynk, xnk , F

zmk, ymk, xmk

ψ max

d

gznk, gzmk , d

gynk, gymk , d

gxnk, gxmk . 2.29

From2.29fork≥0, we get βkψ

max d

gxnk, gxmk , d

gynk, gymk , d

gznk, gzmk

ψαk. 2.30 Lettingk → ∞in2.30, using2.20,2.27, and a property ofψ, we get

εψε< ε, 2.31

which is a contradiction. This shows that{gxn},{gyn}, and{gzn}are Cauchy sequences.

SinceXis complete, there existx, y, zXsuch that

nlim→ ∞gxnx, lim

n→ ∞gyny, lim

n→ ∞gznz. 2.32

From2.4and2.32, using the continuity ofg, we have gx lim

n→ ∞g gxn1

lim

n→ ∞g F

xn, yn, zn

, 2.33

gy lim

n→ ∞g gyn1

lim

n→ ∞g F

yn, xn, yn

, 2.34

gz lim

n→ ∞g gzn1

lim

n→ ∞g F

zn, yn, xn

. 2.35

Now we will show thatgxFx, y, z, gyFy, x, y, andgzFz, y, x.

Sinceg andF are compatible, in addition with2.33,2.34, and2.35, respectively imply

nlim→ ∞d g

F

xn, yn, zn , F

gxn, g yn

, gzn

0, 2.36

nlim→ ∞d g

F

yn, xn, yn

, F g

yn

, gxn, g yn

0, 2.37

nlim→ ∞d g

F

zn, yn, xn

, F

gzn, g yn

, gxn

0. 2.38

Suppose now the assumptionaholds, that is,Fis continuous.

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For alln≥0, we have d

gx, F

gxn, gyn, gzn

d gx, g

F

xn, yn, zn d

g F

xn, yn, zn , F

gxn, gyn, gzn . 2.39 Taking the limit as n → ∞, using 2.32, 2.33, 2.36, and the facts that g and F are continuous, we havedgx, Fx, y, z 0.

Similarly, by using2.32,2.34, and2.37and2.32,2.35, and2.38, respectively, and also the facts that g and F are continuous, we have dgy, Fy, x, y 0 and dgz, Fz, y, x 0.

Thus we have proved thatgandFhave a tripled coincidence point.

Suppose that the assumption b holds. Since{gxn}, {gzn} are nondecreasing and gxnxwithgznzand also{gyn}is nonincreasing withgyny, by assumptionb we have for alln

gxnx, gyny, gznz. 2.40

By virtue of monotone increasing property ofgwe have

ggxngx, ggyngy, ggzngz. 2.41

Now using2.4we have d

gx, F

x, y, z

d gx, g

gxn1 d

g

gxn1 , F

x, y, z

d gx, g

gxn1 d

g F

xn, yn, zn

, F

gxn, gyn, gzn

d

F

gxn, gyn, gzn , F

x, y, z

d gx, g

gxn1 d

g F

xn, yn, zn

, F

gxn, gyn, gzn

ψ

max d

ggxn, gx , d

ggyn, gy , d

ggzn, gz

,

by2.1,2.41 . 2.42

Taking the limit asn → ∞in the above inequality, using2.33,2.36, and2.41we have d

gx, F

x, y, z

≤ lim

n→ ∞ψ max

d

ggxn, gx , d

ggyn, gy , d

ggzn, gz

. 2.43

By2.33,2.34,2.35, and the property ofψ, we have d

gx, F

x, y, z

ψ0 0, 2.44

that is

gxF x, y, z

. 2.45

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In a similar manner using 2.33,2.34,2.35, and 2.36, 2.37, 2.38, respectively, we obtain

gyF y, x, y

, gzF

z, y, x

. 2.46

Thus, we proved thatgandFhave a tripled coincidence point.

This completes the proof of the theorem.

Corollary 2.2. LetX,be a partially ordered set and suppose there is a metricdonXsuch that X, dis a complete metric space. SupposeF:X×X×XXandg:XXare such thatFhas the mixedg-monotone property and

d F

x, y, z

, Fu, v, w

ψ max

d gx, gu

, d gy, gv

, d

gz, gw

2.47 for anyx, y, zXfor whichgxgu,gy gvandgz gw, whereψ : 0,∞ → 0,∞be such thatψtis monotone,ψt< tand limrtψr< tfor allt >0. SupposeFX×X×X⊆gX, gis continuous, andFandgare commuting. Suppose either

aFis continuous, or

bXhas the following property:

iif a nondecreasing sequence{xn} → x, thenxnxfor alln, iiif a nonincreasing sequence{yn} → y, thenynyfor alln.

If there existx0, y0, z0X such thatgx0 Fx0, y0, z0,gy0 Fy0, x0, y0, andgz0 Fz0, y0, x0, then there existx, y, zXsuch that

F x, y, z

gx, F y, x, y

gy, F z, y, x

gz, 2.48 that is,Fandghave a tripled coincidence point.

Proof. Since a commuting pair is also a compatible pair, the result of theCorollary 2.2follows fromTheorem 2.1.

Later, by an example, we will show that the Corollary 2.2 is properly contained in Theorem 2.1.

Corollary 2.3. LetX,be a partially ordered set and suppose there is a metricdonXsuch that X, dis a complete metric space. SupposeF:X×X×X → Xbe such thatFhas the mixed monotone property and

d F

x, y, z

, Fu, v, w

ψ max

dx, u, d y, v

, dz, w

2.49 for anyx, y, zX for whichxu, yvandzw, whereψ :0,∞ → 0,∞be such that ψtis monotone,ψt< tand limrtψr< tfor allt >0. Suppose

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aFis continuous, or

bXhas the following property:

iif a nondecreasing sequence{xn} → x, thenxnxfor alln, iiif a nonincreasing sequence{yn} → y, thenynyfor alln.

If there exist x0, y0, z0X such that x0 Fx0, y0, z0, y0 Fy0, x0, y0, and z0Fz0, y0, x0, then there existx, y, zXsuch that

F x, y, z

x, F y, x, y

y, F z, y, x

z, 2.50 that is,Fhas a tripled fixed point.

Proof. Takinggx xinTheorem 2.1we obtainCorollary 2.3.

Corollary 2.4. LetX,be a partially ordered set and suppose there is a metricdonXsuch that X, dis a complete metric space. SupposeF:X×X×XXandg:XXare such thatFhas the mixed monotone property and

d F

x, y, z

, Fu, v, w

kmax

dx, u, d y, v

, dz, w

2.51

for anyx, y, zXfor whichxu, yvandzw, where 0< k <1. Suppose either aFis continuous, or

bXhas the following property:

iif a nondecreasing sequence{xn} → x, then xnxfor alln, iiif a nonincreasing sequence{yn} → y, thenynyfor alln.

If there exist x0, y0, z0X such that x0 Fx0, y0, z0, y0 Fy0, x0, y0, and z0 Fz0, y0, x0, then there existx, y, zXsuch that

F x, y, z

x, F y, x, y

y, F z, y, x

z, 2.52 that is,Fhas a tripled coincidence point.

Proof. Takingψt kt,t >0 where 0< k <1, inCorollary 2.3we obtainCorollary 2.4.

The following corollary is the result of Berinde and Borcut in20.

Corollary 2.5. LetX,be a partially ordered set and suppose there is a metricdonXsuch that X, dis a complete metric space. SupposeF:X×X×X → Xbe such thatFhas the mixed monotone property and

d F

x, y, z

, Fu, v, w

a1dx, u a2d y, v

a3dz, w 2.53

for anyx, y, zXfor whichxu, yvandzw, wherea1a2a3<1. Suppose either

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aFis continuous, or

bXhas the following property:

iif a nondecreasing sequence{xn} → x, thenxnxfor alln iiif a nonincreasing sequence{yn} → y, thenynyfor alln.

If there exist x0, y0, z0X such that x0 Fx0, y0, z0, y0 Fy0, x0, y0, and z0Fz0, y0, x0, then there existx, y, zXsuch that

F x, y, z

x, F y, x, y

y, F z, y, x

z, 2.54 that is,Fhas a tripled fixed point.

Proof. The proof follows fromCorollary 2.4, since the inequality inCorollary 2.5implies that Corollary 2.4.

Remark 2.6. The method used in the proof of Corollary 2.5 is different from that used by Berinde and Borcut20.

Next we discuss an example.

Example 2.7. LetX. ThenX,is a partially ordered set with the partial ordering defined byxyif and only if|x| ≤ |y|andx·y≥0.

Letdx, y |x−y|forx, y∈ . ThenX, dis a complete metric space.

Letg:XXbe defined asgx x2/10, for allxX. LetF:X×X×XXbe defined as

F x, y, z

x2y2z2

9 , ∀x, y, z∈X. 2.55 Then F obeys the mixedg-monotone property.

Letψ:0,∞ → 0,∞be defined asψt 1/3tfor allt∈0,∞.

Let,{xn}, {yn}, and{zn}be three sequences inXsuch that

nlim→ ∞F

xn, yn, zn

lim

n→ ∞gxn a,

nlim→ ∞F

yn, xn, yn

lim

n→ ∞g yn

b,

nlim→ ∞F

zn, yn, xn lim

n→ ∞gzn c.

2.56

Then explicitly,

nlim→ ∞

xn2y2nz2n

9 lim

n→ ∞

x2n

10, ∀x, y, z∈X, or,

10a−10b10c

9 aimply a−10b10c0.

2.57

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Again,

nlim→ ∞

yn2xn2y2n

9 lim

n→ ∞

y2n

10, ∀x, y, z∈X, or,

10b−10a10b

9 bimply 11b−10a0.

2.58

And

nlim→ ∞

z2ny2nx2n

9 lim

n→ ∞

z2n

10, ∀x, y, z∈X, or,

10c−10b10a

9 cimplyc−10b10a0.

2.59

Then from the above relations we have,a0, b0, andc0.

Therefore,

d g

F

xn, yn, zn , F

gxn, gyn, gzn

−→0 asn−→ ∞, d

g F

yn, xn, yn

, F

gyn, gxn, gyn

−→0 asn−→ ∞, d

g F

zn, yn, xn , F

gzn, gyn, gxn

−→0 asn−→ ∞.

2.60

Hence, the pairg, Fis compatible inX.

Also,x0 0, z0 c> 0, andy0 0 are three points inX such thatgx0 g0 0< c2/9F0,0, c Fx0, y0, z0, gy0 g0 0 F0,0,0 Fy0, x0, y0, andgz0

gc c2/10< c2/9Fc,0,0 Fz0, y0, x0.

We next verify inequality2.1ofTheorem 2.1. We takex, y, z, u, v, wX, such that gxgu, gzgwandgygv, that is,x2u2, z2w2, andy2v2.

LetAmax{dgx, gu, dgy, gv, dgz, gw}max{|x2−u2|,|y2v2|,|z2−w2|}.

ThendFx, y, z, Fu, v, w dx2y2z2/9,u2v2w2/9 |x2u2− y2v2 z2w2/3| ≤|x2u2||y2v2||z2w2|/9≤3A/9 A/3ψA ψmax{dgx, gu, dgy, gv, dgz, gw}.

Thus it is verified that the functions g, F, and ψ satisfy all the conditions of Theorem 2.1. Here0,0,0is the tripled coincidence point ofgandFinX.

Remark 2.8. It is observed that in Example 2.7 the function F and g do not commute, but they are compatible. HenceCorollary 2.2cannot be applied to this example. This shows that Theorem 2.1properly containsCorollary 2.2. Alsog /I, so the results of Berinde and Borcut 20cannot be applied to this example. This shows that result in20is effectively generalised.

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