Volume 2008, Article ID 649162,9pages doi:10.1155/2008/649162
Research Article
Strong Convergence of a Modified Halpern’s Iteration for Nonexpansive Mappings
Liang-Gen Hu
Department of Mathematics, Ningbo University, Ningbo 315211, China
Correspondence should be addressed to Liang-Gen Hu,[email protected] Received 12 September 2008; Accepted 9 December 2008
Recommended by Jerzy Jezierski
The purpose of this paper is to consider that a modified Halpern’s iterative sequence {xn} converges strongly to a fixed point of nonexpansive mappings in Banach spaces which have a uniformly Gˆateaux differentiable norm. Our result is an extension of the corresponding results.
Copyrightq2008 Liang-Gen Hu. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.
1. Introduction
LetEbe a real Banach space andCa nonempty closed convex subset ofE. We denote byJ the normalized duality map from E to 2E∗E∗is the dual spaces ofEdefined by
Jx
f ∈E∗:x, fx2f2,∀x∈E
. 1.1
A mappingT : C → C is said to be nonexpansive ifTx−Ty ≤ x−y, for all x, y ∈ C. We denote by FixT {x ∈ C : Tx x}the set of fixed points ofT. In the last ten years, many papers have been written on the approximation of fixed point for nonlinear mappings by using some iterative processessee, e.g.,1–18.
An explicit iterative process was initially introduced, in 1967, by Halpern3in the framework of Hilbert spaces, that is, Halpern’s iteration. For anyu, x0 ∈C, the sequence{xn}is defined by
xn1αnu 1−αn
Txn, ∀n≥0, 1.2
where{αn} ⊂0,1. He proved that the sequence{xn}converges weakly to a fixed point ofT, whereαnn−a,a∈0,1. In 1977, Lions8further proved that the sequence{xn}converges
strongly to a fixed point ofTin a Hilbert space, where{αn}satisfies the following conditions:
C1 lim
n→ ∞αn0, C2 ∞
n0
αn ∞, C3 lim
n→ ∞
αn1−αn α2n1 0.
1.3
But, in3,8, the real sequence{αn}excluded the canonical choiceαn 1/n1. In 1992, Wittmann16proved, still in Hilbert spaces, the strong convergence of the sequence1.2to a fixed point ofT, where{αn}satisfies the following conditions:
C1 lim
n→ ∞αn0, C2 ∞
n0
αn ∞,
C4 ∞
n1
αn1−αn<∞.
1.4
The strong convergence of Halpern’s iteration to a fixed point of T has also been proved in Banach spacessee, e.g.,2,6,10–12,14,15,17,18. Reich10,11has showed the strong convergence of the sequence1.2, where{αn}satisfies the conditionsC1,C2, and C5.{αn}is decreasingnoting that the conditionC5is a special case of conditionC4.
In 1997, Shioji and Takahashi12extended Wittmann’s result to Banach spaces. In 2002, Xu 17obtained a strong convergence theorem, where{αn}satisfies the following conditions:
C1,C2, and C6. limn→ ∞|αn1−αn|/αn1 0. In particular, the canonical choice of αn1/n1satisfies the conditionsC1,C2, andC6.
However, is a real sequence {αn} satisfying the conditions (C1) and (C2) sufficient to guarantee the strong convergence of the Halpern’s iteration 1.2 for nonexpansive mappings? It remains an open question.
Some mathematician considered the open question. A partial answer to this question was given independently by C. E. Chidume and C. O. Chidume2and Suzuki14. They defined the sequence{xn}by
xn1αnu
1−αn
1−δxnδTxn
, 1.5
whereδ∈0,1, Iis the identity, and obtained the strong convergence of the iteration1.5, where {αn} satisfies the conditions C1and C2. Recently, Xu18 gave another partial answer to this question. He obtained the strong convergence of the iterative sequence
xn1 αn
1−δuδxn
1−αn
Txn, 1.6
whereδ∈0,1and{αn}satisfies the conditionsC1andC2.
Inspired and motivated by the above researches, we introduce a modified Halpern’s iteration. For anyu, x0∈C, the sequence{xn}is defined by
xn1αnuβnxnγnTxn, n≥0, I where{αn}, {βn},and{γn}are three real sequences in0,1, satisfyingαnβnγn 1. Clearly, the iterative sequenceIis a natural generalization of the well-known iterations.
iIf, for alln, we takeβn≡0 inI, then the sequenceIreduces to Halpern’s iteration 1.2.
iiIf, for alln, we takeαn≡0 inI, then the sequenceIreduces to Mann iteration.
The purpose of this paper is to present a significant answer to the above open question. we will show that the sequence {αn} satisfying the conditionsC1 and C2 is sufficient to guarantee the strong convergence of the modified Halpern’s iterative sequence for nonexpansive mappings. As we will see, our theorem extends the corresponding results in three aspects.1The real sequence{αn}satisfies only the conditionsC1andC2.2 In contrast with the results2,14, we replace the sequence{1−αn1−δ}in1.5by an arbitrary sequence{βn}in0,1.3In contrast with the result18, we replace the sequence {αnδ}in1.6by an arbitrary sequence{βn}in0,1.
2. Preliminaries
A Banach spaceEis said to have a Gˆateaux differentiable norm if the limit limt→0
xty − x
t 2.1
exists for eachx, y ∈U, whereU {x ∈E :x 1}.Eis called a uniformly Gˆateaux dif- ferentiable norm if for eachy∈U, the limit is attained uniformly forx∈U. It is well known that if the norm ofEis uniformly Gˆateaux differentiable norm, then the duality mapping is single-valued and norm-to-weak∗uniformly continuous on each bounded subset ofE.
Lemma 2.1see9,10. LetCbe a nonempty closed convex subset of a Banach spaceEwhich has uniformly Gˆateaux differentiable norm andT :C → Ca nonexpansive mapping with FixT/∅.
Assume that every nonempty closed convex bounded subset of C has the fixed points property for nonexpansive mappings. Then there exists a continuous path:t → zt, t ∈ 0,1 satisfyingzt tu 1−tTzt, for anyu∈C, which converges to a fixed point ofT.
Lemma 2.2see13. Let{xn}and{yn}be two bounded sequences in a Banach spaceEsuch that xn1βnxn
1−βn
yn, n≥0, 2.2
where{βn}is a sequence in0,1such that 0<lim infn→ ∞βn≤lim supn→ ∞βn<1. Assume lim sup
n→ ∞
yn1−yn−xn1−xn≤0. 2.3 Then limn→ ∞yn−xn0.
Lemma 2.3. LetEbe a real Banach space. Then the following inequality holds:
xy2≤ x22 y, jxy
, ∀x, y∈E, ∀jxy∈Jxy. 2.4 Lemma 2.4 see 17. Let {an} be a sequence of nonnegative real numbers such that an1 ≤ 1 −δnan δnξn, ∀n ≥ 0, where {δn} is a sequence in 0,1 and {ξn} is a sequence inRsatisfying the following conditions:
i∞
n1δn ∞;
iilim supn→ ∞ξn≤0 or∞
n1δn|ξn|<∞;
Then limn→ ∞an 0.
3. Main results
Theorem 3.1. Let C be a nonempty closed convex subset of a real Banach space E which has a uniformly Gˆateaux differentiable norm. LetT :C → Cbe a nonexpansive mapping with FixT/∅.
Assume that{zt}converges strongly to a fixed pointzofTast → 0, whereztis the unique element of Cwhich satisfieszttu 1−tTztfor anyu∈C. Let{αn}, {βn},and{γn}be three real sequences in0,1which satisfy the following conditions:C1limn→ ∞αn 0 andC2∞
n0αn ∞. For anyx0 ∈C, the sequence{xn}is defined by the iteration inI. Then the sequence{xn}converges strongly to a fixed point ofT.
Proof. Take anyp∈FixT. FromI, it implies that xn1−pαnu−p βn
xn−p γn
Txn−p
≤αnu−p
1−αnxn−p. 3.1
Adopting mathematical induction, we obtain, for alln≥0, xn−p≤maxx0−p,u−p
. 3.2
Therefore, we conclude that the sequence{xn}is bounded. Next, we separate the proof into two cases.
Case 10<lim infn→ ∞βn≤lim supn→ ∞βn<1. Rewrite the iterative processIas follows:
xn1αnuβnxnγnTxn
βnxn
1−βnαnuγnTxn
1−βn
βnxn 1−βn
yn,
3.3
where
yn αn
1−βnu γn
1−βnTxn, ∀n≥0. 3.4
SinceT is a nonexpansive mapping and{xn}is bounded, we get that{yn} and{Txn}are bounded. Manipulating3.4yields
yn1−yn αn1
1−βn1 − αn 1−βn
u
1− αn1 1−βn1
Txn1−Txn
αn
1−βn − αn1
1−βn1
Txn.
3.5
Consequently, we have
yn1−yn−xn1−xn≤ αn1
1−βn1 − αn
1−βn
u
1− αn1
1−βn1
xn1−xn
αn
1−βn − αn1
1−βn1
Txn−xn1−xn.
3.6
From the fact that{xn}and{Txn}are bounded and limn→ ∞αn 0, it follows that lim sup
n→ ∞
yn1−yn−xn1−xn≤0. 3.7
Hence, byLemma 2.2, we get
nlim→ ∞yn−xn0. 3.8
Using limn→ ∞αn0 and3.8, we obtain xn1−βnxnγnTxn
1−αn
≤αn
u−βnxnγnTxn 1−αn
−→0, n−→ ∞, xn1−xn≤
1−βnyn−xn−→0, n−→ ∞.
3.9
Clearly,
xn−βnxnγnTxn 1−αn γn
1−αn
xn−Txn
. 3.10
Since limn→ ∞αn 0 and lim supn→ ∞βn < 1, we get that lim infn→ ∞γn >0. Therefore, from 3.9, and3.10, we find
xn−Txn 1−αn
γn
xn− βnxnγnTxn
1−αn
−→0, n−→ ∞. 3.11
From limn→ ∞xn−Txn 0, it follows that there exists a positive numberNsuch thattn max{
xn−Txn,1/n}, n > N. Obviously, we find
n→ ∞lim
xn−Txn
tn 0. 3.12
Sinceztis a unique solution of the equationzttu 1−tTzt, we can write ztn−xn
1−tn
Tztn−xn tn
u−xn
. 3.13
UsingLemma 2.3, we get ztn−xn2≤
1−tn2Tztn−xn22tn u−xn, j
ztn−xn
≤
1−tn2Tztn−TxnTxn−xn22tn u−xn, j
ztn−xn
≤
1t2nztn−xn2
1−2tnt2nxn−Txn2ztn −xnxn−Txn 2tn u−ztn, j
ztn−xn .
3.14
Thus,
u−ztn, j
xn−ztn
≤ tn
2ztn−xn2
1t2nxn−Txn 2tn
2ztn−xnxn−Txn. 3.15
From the fact that{xn}, {ztn},and{Txn}are bounded and3.12, it implies that lim sup
n→ ∞ u−ztn, j xn−ztn
≤0. 3.16
We know that u−z, j
xn−z
u−z, j xn−z
−j
xn−ztn
u−ztn, j
xn−ztn ztn−z, j
xn−ztn
. 3.17
Noting the hypothesis thatztn → z∈FixT,n → ∞, and the fact that{xn}is bounded and the duality mappingjis norm-to-weak∗uniformly continuous on bounded subset ofE, we have
z−ztn, j
xn−ztn
−→0, n−→ ∞, u−z, j
xn−ztn
−j
xn−z
−→0, n−→ ∞. 3.18
Consequently, from3.16,3.17, and the two results mentioned above, we obtain lim sup
n→ ∞ u−z, j
xn−z
≤0. 3.19
EstimatingIyields
xn1−z2≤βn xn−z
γn
Txn−z22αn u−z, j
xn1−z
≤
1−αnxn−z22αn u−z, j
xn1−z
. 3.20
Therefore, combiningLemma 2.4with3.19and3.20, we get that limn→ ∞xn−z0.
Case 2limn→ ∞βn1. Assume thatTnxβn/1−αnxγn/1−αnTx, for alln≥0, then it is easy to see that for eachn∈N,Tnxxif and only ifTxx, that is,Tnhas the same set of fixed points ofT. Rewrite the iterative processIas follows:
xn1αnu 1−αn
Tnxn. 3.21
Since limn→ ∞αn0 and limn→ ∞βn1, and{Tnxn}is bounded, we have
xn1−xn≤αnuγnTnxn−→0, n−→ ∞. 3.22 Consequently, we get that
xn1−βnxnγnTxn
1−αn
≤αn
u−βnxnγnTxn
1−αn
−→0, n−→ ∞. 3.23
Combining3.22and3.23yields
xn−Tnxn≤xn−xn1xn1−Tnxn−→0, n−→ ∞. 3.24
Adopting the same proof as Case1, we can easily conclude that limn→ ∞xn−z0.
If lim supn→ ∞βn1, then we take arbitrarily the two subsequences{βni}and{βnj}in {βn}such that limi→ ∞βni 1 and lim supj→ ∞βnj <1, and we obtain the strong convergence of the sequence{xn}by employing the above-mentioned proof method.
Remark 3.2. If limn→ ∞βn0 and lim infn→ ∞βn0, then, from Xu’s results18and proof of Theorem 3.1, we obtain the strong convergence theorem.
As direct consequences ofTheorem 3.1, we obtain the two following corollaries.
Corollary 3.3see2, Theorem 3.1. LetE,C,andT be asTheorem 3.1. For a fixedδ ∈ 0,1, defineS:C → CbySx: 1−δxδTx, ∀x∈C. Assume that{zt}converges strongly to a fixed pointzofTast → 0, whereztis the unique element ofCwhich satisfieszttu 1−tTzt, for any
u∈C. Let{αn}be a real sequence in0,1satisfying the conditionsC1andC2. For anyx0∈C, the sequence{xn}is defined by
xn1αnu 1−αn
Sxn. 3.25
Then the sequence{xn}converges strongly to a fixed point ofT.
Proof. If, in proof ofTheorem 3.1, we takeβn 1−αn1−δ, limn→ ∞βn 1−δ, then we get the desired conclusion.
Corollary 3.4see18, Theorem 3.1. LetEbe a uniformly smooth Banach space,Ca closed convex subset ofE, andT :C → Ca nonexpansive mapping such that FixT/∅. For any sequence{αn} in0,1satisfying the conditionsC1andC2, numberδ ∈0,1,and vectorsu, x0 ∈C, define a sequence{xn}by the iterative algorithm
xn1αn
δu 1−δxn
1−αn
Txn, n≥0. 3.26
Then the sequence{xn}converges strongly to a fixed point ofT.
Remark 3.5. For any real sequence{βn} ⊂ 0,1, the real sequence {αn}satisfying the two conditionsC1andC2is sufficient for the strong convergence of the iterative sequenceII for nonexpansive mappings. Therefore, our results give a significant partial answer to the open question.
Acknowledgments
The authors are grateful to anonymous referees for careful reading of the manuscript and helpful suggestions. This work was supported partly by National Science Foundation of China 60872095, the Natural Science Foundation of Zhejiang Province Y606093, K.
C. Wong Magna Fund in Ningbo University, and Ningbo Natural Science Foundation 2008A610018.
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