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INFINITE FAMILIES OF NONEXPANSIVE MAPPINGS IN GENERAL BANACH SPACES

TOMONARI SUZUKI Received 2 June 2004

In 1979, Ishikawa proved a strong convergence theorem for finite families of nonexpan- sive mappings in general Banach spaces. Motivated by Ishikawa’s result, we prove strong convergence theorems for infinite families of nonexpansive mappings.

1. Introduction

Throughout this paper, we denote byNthe set of positive integers and byRthe set of real numbers. For an arbitrary setA, we also denote byAthe cardinal number ofA.

LetCbe a closed convex subset of a Banach spaceE. LetTbe a nonexpansive mapping onC, that is,

TxT yxy (1.1)

for allx,yC. We denote byF(T) the set of fixed points ofT. We knowF(T)=∅in the case thatEis uniformly convex andCis bounded; see Browder [2], G¨ohde [9], and Kirk [13]. Common fixed point theorems for families of nonexpansive mappings are proved in [2,4,5], and other references.

Many convergence theorems for nonexpansive mappings and families of nonexpansive mappings have been studied; see [1,3,6,7,10,11,12,14,15,17,18,19,20,21] and others.

For example, in 1979, Ishikawa proved the following theorem.

Theorem1.1 [12]. LetCbe a compact convex subset of a Banach spaceE. Let{T1,T2,...,Tk} be a finite family of commuting nonexpansive mappings onC. Let{βi}ki=1be a finite sequence in(0, 1)and putSix=βiTix+ (1βi)xforxCandi=1, 2,...,k. Letx1Cand define a sequence{xn}inCby

xn+1= n

nk1=1

Sk

nk1

nk2=1

Sk1···

S3

n2

n1=1

S2

n1

n0=1

S1

···

x1 (1.2) fornN. Then{xn}converges strongly to a common fixed point of{T1,T2,...,Tk}.

Copyright©2005 Hindawi Publishing Corporation Fixed Point Theory and Applications 2005:1 (2005) 103–123 DOI:10.1155/FPTA.2005.103

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The author thinks this theorem is one of the most interesting convergence theorems for families of nonexpansive mappings. In the case ofk=4, this iteration scheme is as follows:

x2=S4S3S2S1x1,

x3=S4S3S2S1S1S2S1S3S2S1x2,

x4=S4S3S2S1S1S1S2S1S1S2S1S3S2S1S1S2S1S3S2S1x3, x5=S4S3S2S1S1S1S1S2S1S1S1S2S1S1S2S1S3S2S1S1

S1S2S1S1S2S1S3S2S1S1S2S1S3S2S1x4, x6=S4S3S2S1S1S1S1S1S2S1S1S1S1S2S1S1S1S2S1S1

S2S1S3S2S1S1S1S1S2S1S1S1S2S1S1S2S1S3S2S1

S1S1S2S1S1S2S1S3S2S1S1S2S1S3S2S1x5, x7=S4S3S2S1S1S1S1S1S1S2S1S1S1S1S1S2S1S1S1S1

S2S1S1S1S2S1S1S2S1S3S2S1S1S1S1S1S2S1S1S1

S1S2S1S1S1S2S1S1S2S1S3S2S1S1S1S1S2S1S1S1

S2S1S1S2S1S3S2S1S1S1S2S1S1S2S1S3S2S1S1S2

S1S3S2S1x6.

(1.3)

We remark thatSiSj=SjSidoes not hold in general.

Very recently, in 2002, the following theorem was proved in [19].

Theorem1.2 [19]. LetCbe a compact convex subset of a Banach spaceEand letSandT be nonexpansive mappings onCwithST=TS. Letx1Cand define a sequence{xn}inC by

xn+1=αn

n2 n i=1

n j=1

SiTjxn+1αnxn (1.4) for nN, where {αn} is a sequence in[0, 1]such that0<lim infnαnlim supnαn<1.

Then{xn}converges strongly to a common fixed pointz0ofSandT.

This theorem is simpler thanTheorem 1.1. However, this is not a convergence theorem for infinite families of nonexpansive mappings.

Under the assumption of the strict convexity of the Banach space, convergence theo- rems for infinite families of nonexpansive mappings were proved. In 1972, Linhart [15]

proved the following; see also [20].

Theorem1.3 [15]. LetCbe a compact convex subset of a strictly convex Banach spaceE.

Let{Tn:nN}be an infinite family of commuting nonexpansive mappings onC. Let{βn} be a sequence in(0, 1). PutSix=βiTix+ (1βi)xforiNandxC. Let f be a mapping onNsatisfying(f1(i))= ∞for alliN. Define a sequence{xn}inCbyx1Cand

xn+1=Sf(n)Sf(n1)◦ ··· ◦Sf(1)x1 (1.5) fornN. Then{xn}converges strongly to a common fixed point of{Tn:nN}.

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The following mapping f onNsatisfies the assumption inTheorem 1.3: ifnNsat- isfies

k1 j=1

j < nk

j=1

j (1.6)

for somekN, then put

f(n)=n

k1 j=1

j. (1.7)

That is, f(1)=1,

f(2)=1, f(3)=2,

f(4)=1, f(5)=2, f(6)=3,

f(7)=1, f(8)=2, f(9)=3, f(10)=4,

f(11)=1, f(12)=2, f(13)=3, f(14)=4, f(15)=5, f(16)=1, f(17)=2, ....

(1.8)

It is a natural problem whether or not there exists an iteration to find a common fixed point for infinite families of commuting nonexpansive mappings without assuming the strict convexity of the Banach space. This problem has not been solved for twenty-five years. In this paper, we give such iteration. That is, our answer of this problem is positive.

2. Lemmas

In this section, we prove some lemmas. The following lemma is connected with Kras- nosel’ski˘ı and Mann’s type sequences [14,16]. This is a generalization of [19, Lemma 1].

See also [8,20].

Lemma2.1. Let{zn}and{wn}be sequences in a Banach spaceEand let{αn}be a sequence in[0, 1]withlim supnαn<1. Put

d=lim sup

n→∞

wnzn or d=lim inf

n→∞ wnzn. (2.1) Suppose thatzn+1=αnwn+ (1αn)znfor allnN,

lim sup

n→∞

wn+1wnzn+1zn0, (2.2)

andd <. Then lim inf

n→∞ wn+kzn

1 +αn+αn+1+···+αn+k1

d=0 (2.3)

hold for allkN.

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Proof. Since

wn+1zn+1wnzn

wn+1wn+wnzn+1wnzn

=wn+1wnzn+1zn,

(2.4)

we have

lim sup

n→∞

wn+jzn+jwnzn

=lim sup

n→∞

j1

i=0

wn+i+1zn+i+1wn+izn+i

lim sup

n→∞

j1

i=0

wn+i+1wn+izn+i+1zn+i

j1

i=0

lim sup

n→∞

wn+i+1wn+izn+i+1zn+i

0

(2.5)

for jN. Put a=(1lim supnαn)/2. We note that 0< a <1. Fixk,N andε >0.

Then there existsmsuch thata1αn,wn+1wnzn+1znε, andwn+j zn+jwnznε/2 for allnmandj=1, 2,...,k. In the case ofd=lim supnwn zn, we choosemmsatisfying

wm+kzm+kdε

2 (2.6)

andwnznd+εfor allnm. We note that

wm+jzm+jwm+kzm+kε

2dε (2.7)

forj=0, 1,...,k1. In the case ofd=lim infnwnzn, we choosemmsatisfying wmzmd+ε

2 (2.8)

andwnzndεfor allnm. We note that wm+jzm+jwmzm+ ε

2d+ε (2.9)

forj=1, 2,...,k. In both cases, suchmsatisfies thatm,a1αn1,wn+1wn zn+1znεfor allnm, and

dεwm+jzm+jd+ε (2.10) forj=0, 1,...,k. We next show

wm+kzm+j

1 +αm+j+αm+j+1+···+αm+k1

d(kj)(2k+ 1)

akj ε (2.11)

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forj=0, 1,...,k1. Since dεwm+kzm+k

=wm+kαm+k1wm+k1

1αm+k1

zm+k1

αm+k1wm+kwm+k1+1αm+k1wm+kzm+k1

αm+k1zm+kzm+k1+ε+1αm+k1wm+kzm+k1

=α2m+k1wm+k1zm+k1+ε+1αm+k1wm+kzm+k1

α2m+k1d+ 2ε+1αm+k1wm+kzm+k1,

(2.12)

we obtain

wm+kzm+k1

1α2m+k1d3ε 1αm+k1

1 +αm+k1

d2k+ 1 a ε.

(2.13)

Hence (2.11) holds for j=k1. We assume (2.11) holds for some j∈ {1, 2,...,k1}. Then since

1 +

k1 i=j

αm+i

d(kj)(2k+ 1) akj ε

wm+kzm+j

=wm+kαm+j1wm+j1

1αm+j1 zm+j1

αm+j1wm+kwm+j1+1αm+j1wm+kzm+j1

αm+j1 k1 i=j1

wm+i+1wm+i+1αm+j1wm+kzm+j1

αm+j1 k1 i=j1

zm+i+1zm+i+ε+1αm+j1wm+kzm+j1

αm+j1 k1 i=j1

zm+i+1zm+i++1αm+j1wm+kzm+j1

=αm+j1 k1 i=j1

αm+iwm+izm+i++1αm+j1wm+kzm+j1

αm+j1 k1 i=j1

αm+i(d+ε) +kε+1αm+j1wm+kzm+j1

αm+j1 k1 i=j1

αm+id+ 2kε+1αm+j1wm+kzm+j1,

(2.14)

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we obtain

wm+kzm+j11 +ki=j1αm+iαm+j1k1 i=j1αm+i

1αm+j1 d(kj)(2k+ 1)/akj+ 2k 1αm+j1 ε

1 +

k1 i=j1

αm+i

d(kj+ 1)(2k+ 1) akj+1 ε.

(2.15) Hence (2.11) holds for j:=j1. Therefore (2.11) holds for all j=0, 1,...,k1. Spe- cially, we have

wm+kzm

1 +αm+αm+1+···+αm+k1

dk(2k+ 1)

ak ε. (2.16) On the other hand, we have

wm+kzmwm+kzm+k+

k1 i=0

zm+i+1zm+i

=wm+kzm+k+

k1 i=0

αm+iwm+izm+i

d+ε+

k1 i=0

αm+i(d+ε)

d+

k1 i=0

αm+id+ (k+ 1)ε.

(2.17)

From (2.16) and (2.17), we obtain wm+kzm

1 +αm+αm+1+···+αm+k1

dk(2k+ 1)

ak ε. (2.18) SinceNandε >0 are arbitrary, we obtain the desired result.

By usingLemma 2.1, we obtain the following useful lemma, which is a generalization of [19, Lemma 2] and [20, Lemma 6].

Lemma2.2. Let{zn}and{wn}be bounded sequences in a Banach spaceEand let{αn}be a sequence in[0, 1]with0<lim infnαnlim supnαn<1. Suppose thatzn+1=αnwn+ (1 αn)znfor allnNand

lim sup

n→∞

wn+1wnzn+1zn0. (2.19)

Thenlimnwnzn =0.

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Proof. We put a=lim infnαn >0, M =2 sup{zn+wn:nN}<, and d= lim supnwnzn<. We assumed >0. Then fixkNwith (1 +ka)d > M. ByLemma 2.1, we have

lim inf

n→∞ wn+kzn

1 +αn+αn+1+···+αn+k1

d=0. (2.20)

Thus, there exists a subsequence{ni}of a sequence{n}inNsuch that

ilim→∞wni+kzni

1 +αni+αni+1+···+αni+k1

d=0, (2.21)

the limit of{wni+kzni}exists, and the limits of{αni+j}exist for allj∈ {0, 1,...,k1}. Putβj=limiαni+j for j∈ {0, 1,···,k1}. It is obvious thatβjafor all j∈ {0, 1,..., k1}. We have

M <(1 +ka)d

1 +β0+β1+···+βk1

d

=lim

i→∞

1 +αni+αni+1+···+αni+k1

d

=lim

i→∞wni+kzni

lim sup

n→∞

wn+kzn

M.

(2.22)

This is a contradiction. Therefored=0.

We prove the following lemmas, which are connected with real numbers.

Lemma2.3. Let{αn}be a real sequence withlimnn+1αn)=0. Then everytRwith lim infnαn< t <lim supnαnis a cluster point of{αn}.

Proof. We assume that there existst(lim infnαn, lim supnαn) such thattis not a cluster point of{αn}. Then there existε >0 andn1Nsuch that

lim inf

n→∞ αn< tε < t < t+ε <lim sup

n→∞ αn,

αn(−∞,tε][t+ε,), (2.23) for allnn1. We choosen2n1such that|αn+1αn|< εfor allnn2. Then there exist n3,n4Nsuch thatn4n3n2,

αn3(−∞,tε], αn4[t+ε,). (2.24)

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We put

n5=maxn:n < n4,αntεn3. (2.25) Then we have

αn5tε < t+εαn5+1 (2.26) and hence

εαn5+1αn5=αn5+1αn5< ε. (2.27) This is a contradiction. Therefore we obtain the desired result.

Lemma2.4. Forα,β(0, 1/2)andnN,

αnβn≤ |αβ|,

k=1

αkβk4|αβ| (2.28)

hold.

Proof. We assume thatn2 because the conclusion is obvious in the case ofn=1. Since αnβn=β)

n1 k=0

αn1kβk, (2.29)

we have

αnβn= |αβ|n

1

k=0

αn1kβk

≤ |αβ|

n1 k=0

1 2n1

= |αβ| n 2n1

≤ |αβ|.

(2.30)

We also have

k=1

αkβk=

k=1

αkβk

= α

1α β 1β

=

αβ (1α)(1β)

4|αβ|.

(2.31)

This completes the proof.

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We know the following.

Lemma2.5. LetCbe a subset of a Banach spaceEand let{Vn}be a sequence of nonex- pansive mappings onCwith a common fixed pointwC. Letx1Cand define a sequence {xn}inCbyxn+1=VnxnfornN. Then{xnw}is a nonincreasing sequence inR. Proof. We havexn+1w = VnxnVnwxnwfor allnN. 3. Three nonexpansive mappings

In this section, we prove a convergence theorem for three nonexpansive mappings. The purpose for this is that we give the idea of our results.

Lemma3.1. LetCbe a closed convex subset of a Banach spaceE. LetT1andT2be nonex- pansive mappings onCwithT1T2=T2T1. Let{tn}be a sequence in(0, 1)converging to 0and let{zn}be a sequence inCsuch that{zn}converges strongly to somewCand

nlim→∞

1tnT1zn+tnT2znzn

tn =0. (3.1)

Thenwis a common fixed point ofT1andT2. Proof. It is obvious that

sup

m,n∈N

T1zmT1zn sup

m,n∈N

zmzn. (3.2)

So{T1zn}is bounded because{zn}is bounded. Similarly, we have that{T2zn}is also bounded. Since

nlim→∞1tn

T1zn+tnT2znzn=0, (3.3) we have

T1wwlim sup

n→∞

T1wT1zn+T1zn

1tnT1zntnT2zn +1tnT1zn+tnT2znzn+znw

lim sup

n→∞

2wzn+tnT1znT2zn+1tnT1zn+tnT2znzn

=0

(3.4) and hencewis a fixed point ofT1. We note that

T1T2w=T2T1w=T2w. (3.5)

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We assume thatwis not a fixed point ofT2. Put ε=T2ww

3 >0. (3.6)

Then there existsmNsuch that

zmw< ε, 1tm

T1zm+tmT2zmzm

tm < ε. (3.7)

Since

=T2ww

T2wzm+zmw

<T2wzm+ε,

(3.8)

we have

2ε <T2wzm. (3.9)

So, we obtain

T2wzmT2w

1tmT1zmtmT2zm +1tm

T1zm+tmT2zmzm

1tmT2wT1zm+tmT2wT2zm +1tmT1zm+tmT2zmzm

=

1tmT1T2wT1zm+tmT2wT2zm +1tmT1zm+tmT2zmzm

1tmT2wzm+tmwzm +1tm

T1zm+tmT2zmzm

<1tmT2wzm+ 2tmε

<1tmT2wzm+tmT2wzm

=T2wzm.

(3.10)

This is a contradiction. Hence,wis a common fixed point ofT1andT2.

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