F,A,Bは”1”と”0”の値しかとらない論理変数
9 8 7 (x-1.0)*(x-1.0) *(x-1.0) (a) f(a) (b) f(a) Figure 1: f(a) a =1.0 (1) a 1.0 f(1.0)
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( ) f a, b n f(b) = f(a) + f (a)(b a) + + f (n 1) (a) (n 1)! (b a)n 1 + R n, R n = b a f (n) (b t)n 1 (t) (n 1)! dt. : R n = b a f (n) (b t
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Donaldson Seiberg-Witten [GNY] f U U C 1 f(z)dz = Res f(a) 2πi C a U U α = f(z)dz dα = 0 U f U U P 1 α 0 a P 1 Res a α = 0. P 1 Donaldson Seib
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January 16, (a) (b) 1. (a) Villani f : R R f 2 f 0 x, y R t [0, 1] f((1 t)x + ty) (1 t)f(x) + tf(y) f 2 f 0 x, y R t [0, 1] f((1 t)x + ty) (1 t
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or a 3-1a (0 b ) : max: a b a > b result a result b ( ) result Python : def max(a, b): if a > b: result = a else: result = b ret
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( 3) b 1 b : b b f : a b 1 b f = f (2.7) g : b c g 1 b = g (2.8) 1 b b (identity arrow) id b f a b g f 1 b b c g (2.9) 3 C C C a, b a b Hom C (a, b) h
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105 $\cdot$, $c_{0},$ $c_{1},$ $c_{2}$, $a_{0},$ $a_{1}$, $\cdot$ $a_{2}$,,,,,, $f(z)=a_{0}+a_{1}z+a_{2}z^{2}+\cdots$ (16) $z=\emptyset(w)=b_{1}w+b_{2
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x = a 1 f (a r, a + r) f(a) r a f f(a) 2 2. (a, b) 2 f (a, b) r f(a, b) r (a, b) f f(a, b)
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l x a b l = ax + b l x x l a b l = ax + b 5 cm cm 1 x l l = 0.5x 5cm cm 1 x l l = 0.25x 1.25 値 x 値 値 x
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1 filename=mathformula tex 1 ax 2 + bx + c = 0, x = b ± b 2 4ac, (1.1) 2a x 1 + x 2 = b a, x 1x 2 = c a, (1.2) ax 2 + 2b x + c = 0, x = b ± b 2
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(a) (i) (a) (b) (c) (d) (e) (f) (g) (h) ( ) (i) (a),, 1, ,,, 1, HP,, 1, 3 /, (f)
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2.2 微分関数をexpressionで定義しDを使うとその導関数が得られる ただし関数形だけで関数値は求まらないしグラフも描けない 関数 f1とその導関数 f2を求めるには f 1 <- deriv(~*****,"x",func=t) f 2 <-function(x) attr( f1(x),
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II (10 4 ) 1. p (x, y) (a, b) ε(x, y; a, b) 0 f (x, y) f (a, b) A, B (6.5) y = b f (x, b) f (a, b) x a = A + ε(x, b; a, b) x a 2 x a 0 A = f x (
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8.1 Fubini 8.2 Fubini 9 (0%) 10 (50%) Carathéodory 10.3 Fubini 1 Introduction 1 (1) (2) {f n (x)} n=1 [a, b] K > 0 n, x f n (x) K < ( ) x [a
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1 cavity QED (a) circuit QED (b) : (a). (b). 3 :,.,. (a), (c), (b), (d)., (a), (b), (c), (d) (1).,. 1., (d). :, Wigner 8). (a) [(c)] g = 0,, 0 [Fock 1
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1 8, : 8.1 1, 2 z = ax + by + c ax by + z c = a b +1 x y z c = 0, (0, 0, c), n = ( a, b, 1). f = n i=1 a ii x 2 i + i<j 2a ij x i x j = ( x, A x), f =
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Fortran90/95 2. (p 74) f g h x y z f x h x = f x + g x h y = f y + g y h z = f z + g z f x f y f y f h = f + g Fortran 1 3 a b c c(1) = a(1) + b(1) c(
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b7240391 f798 4221 bfa6 96f9a27a14ba
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x の値などから決める 本節の最後に, 後の計算で使用する二つの積分について, その一般解を示しておく f x 2 =- x + C... (2.8) f (a - x)(b - x) = b - a[f a - x - f b - x] = b - a( ln a - x - ln b - x)
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1 1 (metamathematics) ( ) ( ) ( ) a b = c d = e f a b = c d = e f = pa + qc pb + qd = pa + qc + re pb + qd + rf a b = c d = e f = k ( 0) a = bk c = dk
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