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LOW-CONCENTRATED AQUEOUS POLYMER SOLUTIONS

MIKHAIL V. TURBIN

Received 12 March 2005; Accepted 10 July 2005

The initial-boundary value problem for the mathematical model of low-concentrated aqueous polymer solutions is considered. For this initial-boundary value problem a con- cept of a weak solution is introduced and the existence theorem for such solutions is proved.

Copyright © 2006 Mikhail V. Turbin. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

1. Introduction

The study of fluid motion is a source of a large number of mathematical problems. Mo- tion of an incompressible fluid in a bounded domainΩRnon a time interval [0,T], (T <) is described by the following system of equations in Cauchy’s form [3]:

∂v

∂t+vi∂v

∂xi+ gradp=Divσ+f, (x,t)Ω×[0,T], divv=0, (x,t)Ω×[0,T].

(1.1) Hereinafter Einstein’s summation convention is supposed. In the given systemv(x,t) is the velocity vector of the particle at a pointxat an instantt;p=p(x,t) is the pressure of the fluid at a pointxat an instantt; f = f(x,t) is the vector of body forces acting on the fluid;σ=i j(x)) is the deviator of the stress tensor. By Divσwe denote the vector of divergences of columns of the matrixσ.

The system of (1.1) describes formally the motion of all kinds of fluids. However the number of unknowns in this system is greater than the number of equations. To complete the given system one usually uses various relations between the deviator of the stress tensorσand the strain rate tensorᏱ=(Ᏹi j),

i j=i j(v)=1 2

∂vi

∂xj+∂vj

∂xi

. (1.2)

Hindawi Publishing Corporation Abstract and Applied Analysis

Volume 2006, Article ID 12497, Pages1–27 DOI10.1155/AAA/2006/12497

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Such relations are called constitutive laws. A constitutive law is a hypothesis which should be verified for concrete fluids by experimental data.

The most known constitutive law for viscous incompressible liquid is Newton’s con- stitutive law

σ=2νᏱ. (1.3)

Hereνis the viscosity of the fluid. This model describes the motion of the majority of viscous incompressible fluids appearing in practice at moderate velocities. However this model does not describe the motion of the fluids possessing relaxational properties. These properties consist in the following. After a change of the exterior conditions the equilib- rium state in a fluid does not appear at once but after a while. This while is determined by the processes of interior reorganization. These processes may have various nature (mag- netic, thermal, etc.). The fluid may have some spectrum of relaxation times correspond- ing to these processes.

In papers [16,18] it has been noted, that the account of relaxational properties of a fluid is the account of time connections between the deviator of the stress tensorσ and the strain rate tensorᏱ. The presence of this connection expresses itself in losses of the mechanical energy of a flow, additional to the dissipative losses owing to viscosity. These additional losses of the mechanical energy of the flow are to be taken into account in the general case of motion of a fluid.

The following relation was suggested in paper [16] as a one taking into account the mentioned effects:

σ=2νᏱ+κν1ddt

, κ,ν>0. (1.4)

Hereνis the kinematic coefficient of viscosity, andκis the retardation time. Sometimes the coefficientκ is also called the time of strain relaxation. This model describes the motion of viscous non-Newtonian fluid which requires time to begin a motion after an action of a force suddenly applied.

Substitutingσfrom the constitutive law (1.4) into the system of equations of incom- pressible liquid motion in Cauchy’s form (1.1) we obtain the following system of equa- tions:

∂v

∂t νΔv+vi∂v

∂xiκ∂Δv

∂t κDiv

vkᏱ(v)

∂xk

+ gradp=f, xΩ,t[0,T], (1.5)

divv=0, xΩ,t[0,T]. (1.6)

The given system of equations differs from the Navier-Stokes system of equations by pres- ence of the additional termκDiv(dᏱ/dt). This term describes relaxational properties of a fluid. In the case of very weak relaxational properties of the fluid (forκclose to zero), and also in the case when the motion of the liquid has steady-state character (the total de- rivative of the strain rate tensor with respect to time is equal to zero) this additional term vanishes. In this case the system of (1.5), (1.6) coincides with the system of Navier-Stokes

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equations. But in the case of turbulent behavior of the fluid and on unsteady laminar behavior of the fluid this additional term is nonzero and must play a significant role. Just so low-concentrated aqueous solutions of polymers behave and it has been confirmed by experimental researches of polyethylenoxide and polyacrylamide aqueous solutions [2]

and polyacrylamide and guar gum aqueous solutions [1]. Therefore the given model has also received the title of the mathematical model of motion of low-concentrated aqueous polymer solutions.

Note also that the constitutive law (1.4) is a special case of Noll’s constitutive law [9]:

σi j=ϕI2

i j+ψI2

ikk j+ψ1

I2

∂t +vk∂Ᏹi j

∂xk ∂vi

∂xmm j+ ∂vj

∂xmim

. (1.7) Hereϕ(I2),ψ(I2),ψ1(I2) are material functions depending on the invariantI2=ikki. Noll’s model of fluid motion is a very general model for which the stress tensor at moment tis determined by nonlinear symmetrical tensor functional. This functional is defined on the set of tensor functions determining history of deformation of a medium at all times preceding the considered instantt.

In this paper we consider the system of (1.5), (1.6) in a bounded domainΩRn, n=2, 3 with locally-Lipschitz boundary on a time interval [0,T], (T <). For (1.5), (1.6) we study the initial-boundary value problem with the initial condition

v(x, 0)=a(x), xΩ, (1.8)

and the boundary condition

v|∂Ω×[0,T]=0. (1.9)

We do not know papers in which problem (1.5)–(1.9) would have been investigated.

Since this problem is very complicated for the research. In works [11,16] it was suggested the following simplification:

∂v

∂t νΔv+vi∂v

∂xiκ ∂Δv

∂t +vk∂Δv

∂xk

+ gradp= f, xΩ,t[0,T], divv=0, xΩ,t[0,T].

(1.10)

This system is obtained from (1.5), (1.6) under the condition (∂vk/∂xj)(∂/∂xk)(∂v/∂xj+ gradvj)0.

Initial-boundary value problem (1.10), (1.8), (1.9) was studied by Oskolkov in his papers [11,12]. However later he remarked in [13] that these papers contain some er- rors and the obtained results are incorrect. Under the slip boundary condition the sys- tem (1.10), has been investigated by Oskolkov in [15]. Ladyzhenskaya notes in her work [7] that the method of introduction of auxiliary viscosity used for study of the initial- boundary value problem (1.10), (1.8), (1.9) in the above mentioned papers [11,12] is erroneous and the problem of existence of solutions for the given initial-boundary value problem remains open till now.

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This work is devoted to the study of the initial-boundary value problem (1.5), (1.6), (1.8), and (1.9). Namely, the problem of existence of weak solutions for this problem is investigated.

2. Principal notations and functional spaces

Let us introduce the following functional spaces used hereinafter:

D(Ω)n is the space of smooth functions onΩwith values inRn and with compact support contained inΩ;

= {v:vD(Ω)n, divv=0}is the set of solenoidal smooth functions;

V is the completion ofᐂin the norm ofW21(Ω)n; we consider the spaceV with the following norm:

vV =

Ωv:v dx 1/2

. (2.1)

Hereu:ϕ,u=(u1,. . .,un),ϕ=1,. . .,ϕn) denotes the component-wise multiplica- tion of matrixes:

u:ϕ=∂ui

∂xj·

∂ϕi

∂xj. (2.2)

InVthis norm is equivalent to the norm induced from the spaceW21(Ω)n. Xis the completion ofᐂin the norm ofW23(Ω)n; the norm inXis defined by

vX=

Ω(Δv) :(Δv)dx1/2. (2.3)

InXthis norm is equivalent to the norm induced from the spaceW23(Ω)n.

ByXwe denote the space conjugate to the spaceX. Denote by h,vthe value of a functionalhXon a functionvX.

Denote byZthe image ofXunder the action of the operator (IκΔ), that is,Z= (IκΔ)X. Let us note thatZis a subspace ofVbut does not coincide with it.

Now we can introduce two principal functional spaces used below

E1= v:vL0,T;V,vL2(0,T;Z) (2.4) with the norm:

vE1= vL(0,T;V)+vL2(0,T;Z), (2.5) E2= v:vC[0,T],X,vL2(0,T;X) (2.6) with the norm:

vE2= vC([0,T],X)+vL2(0,T;X). (2.7)

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3. Statement of the problem and the main result

In this section an approximating problem for the investigated initial-boundary value problem (1.5), (1.6), (1.8), and (1.9) is considered. For this problem and for the original problem the concepts of weak solution is introduced. Then the main result is formulated.

3.1. Approximating problem. For study of the initial-boundary value problem (1.5), (1.6), (1.8), and (1.9) we use a modified method of introduction of auxiliary viscosity.

The original method of introduction of auxiliary viscosity for the Navier-Stokes system (see, e.g., Lions [8]) assumes introduction of the additional term (1)mεΔmv into the system. Hereε >0,mN,m(n+ 2)/4. In this work we add the termεΔ3(∂v/∂t) to (1.5). The obtained equations are called approximating equations. Increase of the order of the equation requires introduction of additional boundary conditions.

Consider the following initial-boundary value problem with small parameterε >0:

∂v

∂tεΔ3∂v

∂t

νΔv+vi∂v

∂xiκ

∂Δv

∂t κDiv

vk∂Ᏹ(v)

∂xk

+gradp=f, xΩ,t[0,T], divv=0, xΩ,t[0,T],

v(x, 0)=a(x), xΩ, v|∂Ω×[0,T]=0,

∂v

∂n

∂Ω×[0,T]=0,

2v

∂n2

∂Ω×[0,T]=0.

(3.1) Hereεis some fixed number,ε >0;nis the outer normal toΩ.

Suppose that f L2(0,T;V),aX.

Definition 3.1. A functionvE2is called a weak solution for the initial-boundary value problem (3.1) if for anyϕXand almost allt(0,T) the functionvE2satisfies the equality

Ω

∂v

∂tϕ dx

Ωvivj

∂ϕj

∂xidx+ν

Ωv:ϕ dx+ε

Ω Δ∂v

∂t

:(Δϕ)dx +κ

Ω∂v

∂t

:ϕ dxκ 2

Ωvk∂vi

∂xj

2ϕj

∂xi∂xkdx

κ 2

Ωvk

∂vj

∂xi

2ϕj

∂xi∂xkdx= f

(3.2)

and the initial condition

v(0)=a. (3.3)

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3.2. Definition of weak solution for initial-boundary value problem (1.5), (1.6), (1.8), and (1.9). Suppose that f L2(0,T;V),aV.

Definition 3.2. A functionvE1is a weak solution for the initial-boundary value prob- lem (1.5), (1.6), (1.8), and (1.9) if for anyϕXand almost allt(0,T) the functionv satisfies the equality

(IκΔ)∂v

∂t

Ωvivj

∂ϕj

∂xi dx+ν

Ωv:ϕ dx

κ 2

Ωvk∂vi

∂xj

2ϕj

∂xi∂xkdxκ 2

Ωvk∂vj

∂xi

2ϕj

∂xi∂xkdx= f

(3.4)

and the initial condition

v(0)=a. (3.5)

3.3. The main result. Our main result is the following theorem.

Theorem 3.3. For any f L2(0,T;V),aV the initial-boundary value problem (1.5), (1.6), (1.8), and (1.9) has at least one weak solutionvE1.

In order to prove this theorem we use the modified method of introduction of auxil- iary viscosity. At the first stage we introduce into (1.5) the termεΔ3(∂v/∂t). The resolv- ability of the obtained approximating problem is established by topological methods on the basis of a priori estimates of weak solutions. Then it is shown that in a sequence of weak solutions of the approximating problem it is possible to select a subsequence con- verging to a weak solution of the initial-boundary value problem (1.5), (1.6), (1.8), and (1.9) as the parameter of approximation tends to zero.

4. Operator treatment for the approximating problem (3.1)

Let us introduce operators in functional spaces using the following equalities:

A:V−→V, Av,ϕ =

Ωv:ϕ dx, v,ϕV, N:X−→X, Nv,ϕ =

Ω(Δv) :(Δϕ)dx, v,ϕX, B1:L4(Ω)n−→V, B1(v),ϕ=

Ωvivj

∂ϕj

∂xidx, vL4(Ω)n,ϕV, B2:V−→X, B2(v),ϕ=

Ωvk∂vi

∂xj

2ϕj

∂xi∂xkdx, vV,ϕX, B3:V−→X, B3(v),ϕ=

Ωvk

∂vj

∂xi

2ϕj

∂xi∂xkdx, vV,ϕX, J:X−→X, Jv,ϕ =

Ωvϕ dx, v,ϕX.

(4.1)

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Since in (3.2) the functionϕXis arbitrary, this equation is equivalent to the following operator equation:

JvB1(v) +νAv+εNvAvκ

2B2(v)κ

2B3(v)=f . (4.2) Hence the problem of existence of a weak solution for the problem (3.1) is equivalent to the problem of existence of a solutionvE2for operator equation (4.2) satisfying the initial condition (3.3).

4.1. Properties of operatorsAandN. In this subsection the properties of operatorsA andNfrom the operator equation (4.2) are investigated.

Lemma 4.1. The operatorAhas the following properties.

(i) The operatorA:VVis continuous and the following inequality holds:

AuVuV, uV. (4.3)

(ii) For anyuL2(0,T;V) one hasAuL2(0,T;V) and the operatorA:L2(0,T;V) L2(0,T;V) is continuous.

(iii) For anyuE2one hasAuL2(0,T;X) and the operatorA:E2L2(0,T;X) is compact and the following estimate holds:

AuL2(0,T;X)C0uC([0,T],V). (4.4) Proof. (i) It suffices to show boundedness of the linear operatorA. By definition we have

Au,ϕ=

Ωu:ϕ dxuVϕV. (4.5) The last inequality implies (4.3). Thus the operatorA:VVis continuous.

(ii) LetuL2(0,T;V). For almost allt(0,T) by virtue of (4.3) we have

Au(t)2Vu(t)2V. (4.6)

ThereforeAuL2(0,T;V).

Integrating the obtained estimate with respect totfrom 0 toT, we obtain

Au2L2(0,T;V)u2L2(0,T;V). (4.7)

Since the operatorAis linear and bounded, it is continuous as an operator fromL2(0,T;

V) toL2(0,T;V).

(iii) In order to prove that the operatorA:E2L2(0,T;X) is compact we use [17, Theorem 2.1, page 184]. We remind here its statement.

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Theorem 4.2. LetX0,F,X1be three Banach spaces satisfying the following condition:

X0FX1. (4.8)

Where the embeddings are continuous,X0,X1are reflexive, the embeddingX0Fis com- pact. LetT >0 be fixed finite number andα01 be two finite numbers such thatαi>1, i=0, 1.

Suppose thatY= {v:vLα0(0,T;X0); vLα1(0,T;X1)}is the space with the norm vY= vLα0(0,T;X0)+vLα1(0,T;X1). Then the embedding ofYintoLα0(0,T;F) is compact.

In our case

X0=X, F=V, X1=L2(Ω)n, α0=α1=2, Y= v:vL2(0,T;X);vL2

0,T;L2(Ω)n. (4.9)

Since the embeddingX=VW23(Ω)nV is compact, all conditions of this theorem hold and consequently the embedding ofYintoL2(0,T;V) is compact.

Note thatE2Y and this embedding is continuous. Indeed, it follows from the em- beddingsC([0,T],X)L2(0,T;X) andL2(0,T;X)L2(0,T;L2(Ω)n) which are continu- ous. From (ii) we have that the operatorA:L2(0,T;V)L2(0,T;V) is continuous.

Thus we have the following composition E2YL2(0,T;V)−−−→A L2

0,T;VL2

0,T;X. (4.10)

Here the first embedding is continuous, the second embedding is compact, and the map Aand the last embedding are continuous. This yields that the mapA:E2L2(0,T;X) is completely continuous.

The required estimate follows from (4.7) and continuity of embeddingsL2(0,T;V)

L2(0,T;X) andC([0,T],V)L2(0,T;V).

Lemma 4.3. The operatorJ+εNAhas the following properties.

(i) The operator (J+εNA) :XXis continuous, invertible and the following in- equalities hold

εuX(J+εNA)uXC1+εC2

uX. (4.11)

HereC1,C2 are some constants, which depend fromnand domainΩand do not depend onu.

(ii) For anyuL2(0,T;X) one has (J+εNA)uL2(0,T;X) and the operator (J+εNA) :L2(0,T;X)L2(0,T;X) is continuous, invertible and the following estimate holds

εuL2(0,T;X)(J+εNA)uL2(0,T;X). (4.12)

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Proof. (i) By linearity of the operatorJ+εNAfor the proof of its continuity it suffices to show its boundedness. By definition we have

(J+εNA)u,ϕ=

Ωuϕ dx+ε

Ω(Δu) :(Δϕ)dx+κ

Ωu:ϕ dx uL2(Ω)nϕL2(Ω)n+εuXϕXuVϕV

C1uXϕX+εuXϕXC2uXϕX

=

C1+εC2

uXϕX.

(4.13) We have used two following inequalities:

u2L2(Ω)nC1u2X, u2VC2u2X. (4.14) Here the constantsC1,C2depend onnand domainΩand do not depend onu.

This implies the right part of estimation (4.11). Thus the operator (J+εNA) :X Xis bounded and hence it is continuous.

In order to prove that the operator (I+εNA) :XXis invertible we use [17, Theorem 2.2, page 17]. We remind here its statement.

Theorem 4.4. LetW be a separable real Hilbert space (norm · W) and leta(u,v) be a linear continuous form onW×W, which is coercive, that is, there existsα >0, such that

a(u,u)αu2W uW. (4.15) Then for eachlfromW, the dual space ofW, there exists one and only oneuW such that

a(u,v)= l,vvW. (4.16)

To apply this theorem it suffices to show that the following continuous bilinear form is coercive.

a(u,v)=

(J+εNA)u,v=

Ωuv dx+ε

Ω(Δu) :(Δv)dx+κ

Ωu:v dx.

(4.17) In fact, for anyuXwe have

a(u,u)=

(J+εNA)u,u

=

Ωu2dx+ε

Ω(Δu) :(Δu)dx

Ωu:u dx

= u2L2(Ω)n+εu2Xu2Vεu2X, ε >0.

(4.18)

Thus we have proved that (J+εNA) :XXis an isomorphism and the left part of estimate (4.11) is valid.

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Furthermore by virtue of [4, Remark 2.3] the inverse operator (J+εNA)1:X Xis Lipschitz-continuous (in the nomenclature of [4]). That is for any f,gX:

(J+εNA)1f (J+εNA)1gXC3f gX, C3=1

ε. (4.19) (ii) LetuL2(0,T;X). Quadrating right part of estimate (4.11) at almost all tand integrating with respect totfrom 0 toT, we get

T

0

(J+εNA)u(t)2XdtC1+εC2

2

u2L2(0,T;X). (4.20) The right-hand side of this inequality is finite and therefore the left-hand side is also finite. From here it follows that (J+εNA)uL2(0,T;X) and

(J+εNA)uL2(0,T;X)C1+εC2

uL2(0,T;X). (4.21)

The operator (J+εNA) :L2(0,T;X)L2(0,T;X) is linear and bounded and therefore it is continuous.

Now, let us show that it is invertible. First we will prove that the range of the operator (J+εNA) coincides withL2(0,T;X). For this purpose it is necessary to show that for anywL2(0,T;X) the equation (J+εNA)u=whas a solutionuL2(0,T;X).

By (i) the operator (J+εNA) :XXis invertible. This implies that at almost all t(0,T) the equation (J+εNA)u=whas a solutionu(t)=(J+εNA)1w(t). It is necessary to show that the functionuL2(0,T;X). Using the left part of the estimate (4.11) we get

εu(t)X(J+εNA)u(t)X=w(t)X. (4.22) SincewL2(0,T;X) we have from this inequality thatuL2(0,T;X). Quadrating this inequality and integrating it along (0,T), we obtain the required inequality (4.12).

Therefore ker(J+εNA)= {0}. Thus the operator (J+εNA) :L2(0,T;X)

L2(0,T;X) is invertible.

4.2. Properties of operatorsB1,B2,B3. In this section we consider the properties of op- eratorsB1,B2andB3from (4.2).

Lemma 4.5. The mapB1has the following properties.

(i) The mapB1:L4(Ω)nVis continuous and the following inequality holds

B1(v)VC4v2L4(Ω)n. (4.23)

(ii) For anyvL4(0,T;L4(Ω)n) one hasB1(v)L2(0,T;V) and the mapB1:L4(0,T;

L4(Ω)n)L2(0,T;V) is continuous.

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(iii) For anyvE2one hasB1(v)L2(0,T;X), the mapB1:E2L2(0,T;X) is com- pact and the following estimate holds:

B1(v)L2(0,T;X)C5v2C([0,T],V). (4.24) Proof. (i) LetvL4(Ω)n,ϕV. Then we obtain

B1(v),ϕ=

Ωvivj

∂ϕj

∂xidx n

i,j=1

vi

L4(Ω)vj

L4(Ω)

∂ϕj

∂xi

L2(Ω)

n

i,j=1

vL4(Ω)nvL4(Ω)nϕVn2v2L4(Ω)nϕV

C4v2L4(Ω)nϕV.

(4.25)

Whence the required estimation (4.23) follows.

Let us prove that the mapB1:L4(Ω)nVis continuous. For anyvm,v0L4(Ω)nwe obtain

B1

vm B1

v0=

Ωvmi vmj ∂ϕj

∂xidx

Ωvi0v0j∂ϕj

∂xidx

n i,j=1

vimvmj v0iv0jL2(Ω)∂ϕj

∂xi

L2(Ω)

ϕV

n i,j=1

vmi vmj vi0v0jL2(Ω).

(4.26)

We obviously have n

i,j=1

vimvmj v0iv0jL2(Ω)= n i,j=1

vmi vmj vimv0j+vmi v0jvi0v0jL2(Ω)

n i,j=1

vimvmj v0jL2(Ω)+ n i,j=1

v0jvmi v0iL2(Ω)

n i,j=1

vimL4(Ω)vmj v0jL4(Ω)+ n i,j=1

v0jL4(Ω)vimvi0L4(Ω) C6vmL4(Ω)nvmv0L4(Ω)n+C6v0L4(Ω)nvmv0L4(Ω)n

=C6

vmL4(Ω)n+v0L4(Ω)n

vmv0L4(Ω)n.

(4.27) Therefore

B1

vmB1

v0VC6

vmL4(Ω)n+v0L4(Ω)n

vmv0L4(Ω)n. (4.28) Let a sequence{vm} ⊂L4(Ω)nconverge to some limit functionv0L4(Ω)n. Then the continuity of the mapB1:L4(Ω)nVfollows from inequality (4.28).

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(ii) LetvL4(0,T;L4(Ω)n). Quadrating estimate (4.23) and integrating with respect totfrom 0 toT, we get

T

0

B1(v)(t)2VdtC24 T

0

v(t)4L4(Ω)ndt=C42v4L4(0,T;L4(Ω)n). (4.29) SincevL4(0,T;L4(Ω)n), one hasB1(v)(t)V L2(0,T) and henceB1(v)L2(0,T;

V).

Let us prove that the mapB1:L4(0,T;L4(Ω)n)L2(0,T;V) is continuous.

Let a sequence{vm} ⊂L4(0,T;L4(Ω)n) converge to some limitv0L4(0,T;L4(Ω)n).

Quadrating inequality (4.28) and integrating with respect totfrom 0 toT, we get T

0

B1

vm(t)B1

v0(t)2Vdt

C26 T

0

vm(t)L4(Ω)n+v0(t)L4(Ω)n

2vm(t)v0(t)2L4(Ω)ndt

C26 T

0

vm(t)L4(Ω)n+v0(t)L4(Ω)n

4

dt

1/2T

0

vm(t)v0(t)4L4(Ω)ndt 1/2

=C26 T

0

4

i=0

Ci4vm(t)iL4(Ω)nv0(t)4L4(Ω)i ndt

1/2T

0

vm(t)v0(t)4L4(Ω)ndt 1/2

C26 4

i=0

Ci4 T

0

vm(t)4L4(Ω)ndt i/4T

0

v0(t)4L4(Ω)ndt

(4i)/41/2

× T

0

vm(t)v0(t)4L4(Ω)ndt 1/2

.

(4.30) Thus we obtain

B1

vmB1

v02L2(0,T;V)

C62 4

i=0

C4ivmi/4L4(0,T;L4(Ω)n)v0(4L4(0,T;Li)/44(Ω)n)

2

vmv02L4(0,T;L4(Ω)n).

(4.31)

HereCi4=4!/i!(4i)!. Since the right-hand side of (4.31) tends to zero asm+, the left-hand side tends to zero asm+. This completes the proof of (ii).

(iii) Let us use [17, Theorem 2.1, page 184]. We quoted its statement inLemma 4.1.

In our case

X0=X, F=L4(Ω)n, X1=L2(Ω)n, α0=4, α1=2, Y= v:vL4(0,T;X);vL2

0,T;L2(Ω)n. (4.32) By Sobolev’s embedding theorem we have compact embeddingXL4(Ω)n. All con- ditions of [17, Theorem 2.1] hold and we get that the embedding of Y into L4(0,T;

L4(Ω)n) is compact.

参照

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