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Identification of Elastic Modulus using Extended Kalman Filter Finite Element Method

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Identification of Elastic Modulus using Extended Kalman Filter Finite Element Method

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Yusuke KATO

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1. [ ˆP0|−1] = [Px0] , x0|−1}=x0} 2. xk+1|k}= [Fk]{ˆxk|k}

3. [Kk] = [ ˆPk|k−1][Hk]T([Rvk] + [Hk][ ˆPk|k−1][Hk]T)−1 4. [ ˆPk|k] = ([I][Kk][Hk])[ ˆPk|k−1]

5. xk|k}=xk|k−1}+ [Kk]({yk} −[Hk]{ˆxk|k−1}) 6. [ ˆPk+1|k] = [Fk][ ˆPk|k][Fk]T+ [Gk][Qwk][Gk]T

=h, õ>?Fk, Hk _? Vï^3 4{, Fk =∂fk

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(2)

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2.4 $%&'()

1). [Γ0] = [v0],{ˆ¨u−1}={uˆ¨0} 2). u˙n un by eq.(4), eq.(5)

3). [Kn] = [Γn][Hn]T([Rn] + [Hn][Γk][Hn]T)−1 4). [Pn] = ([I]−[Kn][Hn])[Γn]

5). [Γn+1] = [I][Pn]

6). {En}={En−1 }+ [Kn]({yn−[Hn]{¨un−1}) 7). {En+1 }={En}

If {xk+1} − {xk}< ǫ, go to next time cycle.

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0 20 40 60 80 100 120 140 160 180 200 Accerelation [m/sec2]

Cycle number

observation data with noise

32;P oint1 BÓ \xJV?1ü

-6 -5 -4 -3 -2 -1 0 1 2 3 4 5

0 20 40 60 80 100 120 140 160 180 200 Accerelation [m/sec2]

Cycle number

observation data with noise

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0 20 40 60 80 100 120 140 160 180 200 Accerelation [m/sec2]

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observation data with noise

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(3)

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Case2 1,2 2

Case3 1,2,3 3

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400000 500000 600000 700000 800000 900000 1e+06 1.1e+06 1.2e+06 1.3e+06 1.4e+06

0 500 1000 1500 2000 2500 3000 3500 Elastic modulus [N/m2]

Cycle number Layer1 Layer2 Layer3 Layer4

36; Case1 BÓ \—˜™š?í!

400000 500000 600000 700000 800000 900000 1e+06 1.1e+06 1.2e+06 1.3e+06 1.4e+06

0 500 1000 1500 2000 2500 3000 3500 4000 Elastic modulus [N/m2]

Cycle number Layer1 Layer2 Layer3 Layer4

37; Case2 BÓ \—˜™š?í!

200000 400000 600000 800000 1e+06 1.2e+06 1.4e+06

0 1000 2000 3000 4000 5000 6000 7000 Elastic modulus [N/m2]

Cycle number Layer1 Layer2 Layer3 Layer4

38; Case3 BÓ \—˜™š?í!

0 200000 400000 600000 800000 1e+06 1.2e+06 1.4e+06

0 1000 2000 3000 4000 5000 6000 7000 Elastic modulus [N/m2]

Cycle number Layer1 Layer2 Layer3 Layer4

39; Case4 BÓ \—˜™š?í!

(4)

2;2m(BÓ \—˜™š? â[%]

Layer1 Layer2 Layer3 Layer4

Case1 96 92 95 0

Case2 98 97 99 0

Case3 99 99 98 42

Case4 99 99 99 99

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Case2 97 97 99 0

Case3 99 99 98 0

500000 600000 700000 800000 900000 1e+06 1.1e+06 1.2e+06 1.3e+06 1.4e+06

0 200 400 600 800 1000

Elastic modulus [N/m2]

Cycle number

105 106 107

10; Case1Case3

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1 R.E.Kalman, A New Approach to Linear Filtering and Prediction Problems, Trans.ASME,J. Basic Eng., vol182D, no.1,34-45,(1960)

3 A.Murakami and T.Hasegawa, Back Analysis by Kalman Filter Finite Elements and a Determina- tion of Optimal Observed Points Location. Jour- nals of the Japan Society of Civil Engineers Vol.388,227- 235,(1987)

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参照

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