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On sufficient condition for starlikeness

1

D. O. Makinde, T. O. Opoola

Abstract

In this paper,we give a condition for starlikeness of the integral oper- ator of the formF(z) =

Z z

0 k

Y

ı=1

fı(s) s

α1

ds.

2000 Mathematics Subject Classification:30C45

Key words and phrases: Starlike, Convex, Briot-Bouquet subordination.

1 Introduction

LetA be the class of all analytic functions f(z) defined in the open unit disk U ={z∈C :|z|<1}andSthe subclass ofAconsisting of univalent functions

(1) f(z) =z+

X k=2

akzk

S={f ∈S:Re(zf0(z)

f(z) )>0, z∈U}, Mα={f ∈S : f(z)f0(z)

z 6= 0, ReJ(α, f;z)>0, z∈U}

1Received 14 February, 2009

Accepted for publication (in revised form) 17 March, 2009

35

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where J(α, f;z) = (1−α)zff(z)0(z) +α(1 + zff000(z)(z)) be the class of starlike and α−convexfunctions respectively.

Letp(z) be the class of functions that are regular in U and of the form :

(2) p(z) = 1 +

X k=1

bkzk Furthermore, let h(z) = 1+z1z.

Let T be the univalent [5] subclass of Aconsisting of functionsf(z) satisfying

|zf(z)2f0(z)2 −1|<1,(z∈U)

LetTn be the subclass ofT for which fk(0) = 0 (k= 2,3, ..., n).

Let Tn,µ be the subclass of Tn consisting of functions of the form Rz

0

Qk

ı=1(fıs(s))α1dssatisfying: |zf(z)2f0(z)2 −1|< µ,(z∈U) for someµ(0< µ≤1).

2 Preliminaries

Theorem 1 [1] LetM andN be analytic inU withM(0) =N(0) = 0.IfN(z) maps onto a many sheeted region which is starlike with respect to the origin and Re{MN00(z)(z)}>0 in U, then Re{MN(z)(z)}>0 in U.

Theorem 2 [6] Letfı ∈Tn,µı(ı= 1,2, ..., k;k∈ N) be defined by

(3) fi(z) =z+

X n=2

ainzn

for all i = 1,2, ..., k;α, β ∈ C;R{β} ≥ γ and γ = Xk i=1

1 + (1 +µi)M

|α| (M ≥ 1,0< µi <1, k∈N). If |fi(z)| ≤ M(z∈U), i= 1,2, ..., k then, the integral operator

(4) Fα,β(z) ={β

Z z 0

tβ1 Yk i=1

(fi(t) t )α1dt}β1 is univalent.

Theorem 3 [2] Let h be convex in U and Re{βh(z) +γ} >0, z ∈U.If p ∈ H(U) whereH(U) is the class of functions which are analytic in the unit disk, with p(0) =h(0)andpsatisfies the Briot-Bouquet differential subordinations:

p(z) +βp(z)+γzp0(z) ≺h(z), z∈U. Then, p(z)≺h(z), z∈U.

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3 Main Results

We now give the proof of the following results:

Theorem 4 Let Fα(z) be the function in U defined by

(5) Fα(z) =

Z z 0

Yk i=1

(fi(s)

s )α1ds, α∈C.

If fi ∈S then, F(z)∈S where fi is as in equation (3) above.

Proof. By differentiating (5), we obtain: F0(z) = Qk

i=1(fi(z)z )1α. Thus, zF0(z)

F(z) = Qk

i=1(fiz(z))α1 Rz

0

Qk

i=1(fi(s)s )α1ds. Let

(6) M =zF0(z), N(z) =F(z)

From (5) and (6) we have:

M0(z)

N0(z) = 1 + zF00(z)

F0(z) , M0(z) N0(z) = 1 +

Pk i=1 1

α(zff(z)i0(z)−1) Qk

i=1(fiz(z))α1

|M0(z)

N0(z) −1|= |Pk i=1 1

α(zff(z)i0(z)−1)|

|Qk

i=1(fiz(z))α1| ≤ Pk

i=1|α1||zff(z)i0(z)−1|

|Qk

i=1(fiz(z))α1| .

By hypothesis fi ∈ S. This means that |zff(z)i0(z)−1| <1, which implies that

|MN00(z)(z) −1|<1. Thus Re{MN00(z)(z)}>0 and by Theorem 1,Re{MN(z)(z)}>0. This implies thatRe{zFF(z)0(z)}>0. Hence F ∈S.

Remark 1 The integral in (5) is equivalent to that in (4) of section 2 with β = 1.

Let S={f :U →C} ∩S. LetF(z)∈U be defined by

(7) F(z) =

Z z 0

Yk i=1

(fi(s) s )α1ds.

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Theorem 5 Letz∈U, α∈C, Reα >0andmα=Mα∩s.IfF ∈mα, then F ∈ Sthat is mα⊂S.

Proof. From (6) above, we have F(z)Fz0(z) 6= 0 and forF ∈mα,we have (8) ReJ(α, f;z) =Re{(1−α)zF0(z)

F(z) +α(1 + zF0(z) F(z) )}

forp(z) = zFF(z)0(z), zpp(z)0(z) = 1 +zFF0”(z)(z) −p(z).This implies that

(9) 1 +zF00(z)

F0(z) = zp0(z)

p(z) +p(z) using (7) and (9) in (8), we obtain

(10) ReJ(α, f;z) =Re{(1−α)p(z) +α(zp0(z)

p(z) +p(z))}.

Simplifying (10), we obtainReJ(α, f;z) =Re{p(z) +α(zpp(z)0(z))}

p(0) + αzpp(0)0(0) = 1 and p(0) = h(0) = 1. Thus, using Theorem 3 with β = 1 andγ = 0,we havep(z)+αzpp(z)0(z) < h(z) = 1+z1z. This implies thatp(z)≺h(z).

That isRe{p(z)}>0. Thus, Re{zFF(z)0(z)}>0. Hence, F ∈S.

References

[1] S.A. Halim,On a class of Analytic Functions involing, Tamkang, Journal of Mathematics vol.23 Number 1, Spring 1992.

[2] M. Acu and S. Owa, On some subclasses of univalent function, Journal of inequalities in pure and applied mathematics, vol. 6,(3) art 70, 2005.

[3] S. Kanas and F. Ronning, Uniformly Starlike and convex functions and other related classes of univalent functions, Ann University, Marie Curie- Sklodowska Section A, 53, 1999, 95-105.

[4] S.S. Miller and P.T. Mocanu, Univalent solutions of Briot-Bouquet dif- ferential equations, Journal of Differential equations, 56, 1985, 297-309.

[5] S. Ozaki and M.Nunokawa, The Schwarzian derivative and Univalent functions,, Pro. Ameri.Math. Soc., 33, 1972, 302-394.

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[6] N. Seenivasagan, Sufficient Conditions for Univalence, Applied Mathe- matics E-Notes, 8, 2008, 30-35.

D. O. Makinde

Department of Mathematics Obafemi Awolowo University Ile Ife 220005, Nigeria

e-mail: [email protected], [email protected] Timothy O. Opoola

University of Ilorin Mathematics

Department of Mathematics, University of Ilorin, Ilorin,Nigeria e-mail: [email protected]

参照

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