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Volume 2011, Article ID 363716,14pages doi:10.1155/2011/363716

Research Article

Common Coupled Fixed Point Theorems for Contractive Mappings in Fuzzy Metric Spaces

Xin-Qi Hu

School of Mathematics and Statistics, Wuhan University, Wuhan 430072, China

Correspondence should be addressed to Xin-Qi Hu,[email protected] Received 23 November 2010; Accepted 27 January 2011

Academic Editor: Ljubomir B. Ciric

Copyrightq2011 Xin-Qi Hu. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

We prove a common fixed point theorem for mappings underφ-contractive conditions in fuzzy metric spaces. We also give an example to illustrate the theorem. The result is a genuine generalization of the corresponding result of S.Sedghi et al.2010

1. Introduction

Since Zadeh 1 introduced the concept of fuzzy sets, many authors have extensively developed the theory of fuzzy sets and applications. George and Veeramani 2, 3 gave the concept of fuzzy metric space and defined a Hausdorff topology on this fuzzy metric space which have very important applications in quantum particle physics particularly in connection with both string andE-infinity theory.

Bhaskar and Lakshmikantham 4, Lakshmikantham and ´Ciri´c 5 discussed the mixed monotone mappings and gave some coupled fixed point theorems which can be used to discuss the existence and uniqueness of solution for a periodic boundary value problem.

Sedghi et al.6gave a coupled fixed point theorem for contractions in fuzzy metric spaces, and Fang7gave some common fixed point theorems underφ-contractions for compatible and weakly compatible mappings in Menger probabilistic metric spaces. Many authors8–

23have proved fixed point theorems inintuitionisticfuzzy metric spaces or probabilistic metric spaces.

In this paper, using similar proof as in7, we give a new common fixed point theorem under weaker conditions than in6and give an example which shows that the result is a genuine generalization of the corresponding result in6.

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2. Preliminaries

First we give some definitions.

Definition 1see2. A binary operation∗ :0,1×0,1 → 0,1is continuoust-norm if∗ is satisfying the following conditions:

1∗is commutative and associative;

2∗is continuous;

3a∗1afor alla∈0,1;

4abcdwheneveracandbdfor alla, b, c, d∈0,1.

Definition 2see24. Let sup0<t<1Δt, t 1. At-normΔis said to be of H-type if the family of functions{Δmt}m1is equicontinuous att1, where

Δ1t tΔt, Δm 1t tΔΔmt, m1,2, . . . , t∈0,1. 2.1

Thet-normΔM min is an example oft-norm of H-type, but there are some other t-normsΔof H-type24.

Obviously,Δis a H-typetnorm if and only if for anyλ∈0,1, there existsδλ∈0,1 such thatΔmt>1−λfor allm, whent >1−δ.

Definition 3see2. A 3-tupleX, M,∗is said to be a fuzzy metric space ifXis an arbitrary nonempty set,∗is a continuous t-norm, andMis a fuzzy set onX2×0, ∞satisfying the following conditions, for eachx, y, zXandt, s >0:

FM-1Mx, y, t>0;

FM-2Mx, y, t 1 if and only ifxy;

FM-3Mx, y, t My, x, t;

FM-4Mx, y, tMy, z, sMx, z, t s;

FM-5Mx, y,·:0,∞ → 0,1is continuous.

LetX, M,∗be a fuzzy metric space. Fort > 0, the open ballBx, r, twith a center xXand a radius 0< r <1 is defined by

Bx, r, t

yX:M x, y, t

>1−r

. 2.2

A subsetAXis called open if, for eachxA, there existt >0 and 0< r <1 such that Bx, r, tA. Letτdenote the family of all open subsets ofX. Thenτis called the topology onXinduced by the fuzzy metricM. This topology is Hausdorffand first countable.

Example 1. LetX, dbe a metric space. Definet-normababand for allx, yXandt >0, Mx, y, t t/t dx, y. ThenX, M,∗is a fuzzy metric space. We call this fuzzy metric Minduced by the metricdthe standard fuzzy metric.

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Definition 4see2. LetX, M,∗be a fuzzy metric space, then

1a sequence{xn}inXis said to be convergent toxdenoted by limn→ ∞xnxif

nlim→ ∞Mxn, x, t 1, 2.3

for allt >0;

2a sequence{xn}inX is said to be a Cauchy sequence if for anyε >0, there exists n0, such that

Mxn, xm, t>1−ε, 2.4

for allt >0 and n, m≥n0;

3a fuzzy metric spaceX, M,∗is said to be complete if and only if every Cauchy sequence inXis convergent.

Remark 1see25. 1For allx, yX,Mx, y,·is nondecreasing.

2It is easy to prove that ifxnx,yny,tnt, then

nlim→ ∞M

xn, yn, tn M

x, y, t

. 2.5

3In a fuzzy metric spaceX, M,∗, wheneverMx, y, t> 1−rforx, yinX,t > 0, 0< r <1, we can find at0, 0< t0< tsuch thatMx, y, t0>1−r.

4For anyr1> r2, we can find anr3such thatr1r3r2and for anyr4we can find a r5such thatr5r5r4 r1, r2, r3, r4, r5∈0,1.

Definition 5see6. LetX, M,∗be a fuzzy metric space.Mis said to satisfy then-property onX2×0,∞if

nlim→ ∞

M

x, y, kntnp

1, 2.6

wheneverx, yX,k >1 andp >0.

Lemma 1. LetX, M,∗be a fuzzy metric space andMsatisfies then-property; then

tlim→ ∞M x, y, t

1, ∀x, y∈X. 2.7

Proof. If not, sinceMx, y,·is nondecreasing and 0 ≤Mx, y,·≤ 1, there existsx0, y0X such that limt→Mx0, y0, t λ < 1, then fork >1,knt → ∞whenn → ∞ast >0 and we get limn→ ∞Mx0, y0, kntnp 0, which is a contraction.

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Remark 2. Condition2.7cannot guarantee then-property. See the following example.

Example 2. LetX, dbe an ordinary metric space,ababfor all a, b ∈ 0,1, andψ be defined as following:

ψt

⎧⎪

⎪⎩ α

t, 0< t≤4, 1− 1

lnt, t >4, 2.8

whereα 1/21−1/ln 4. Thenψtis continuous and increasing in0,∞,ψt∈ 0,1 and limt→ψt 1. Let

M x, y, t

ψtdx,y

, ∀x, y∈X, t >0, 2.9 thenX, M,∗is a fuzzy metric space and

t→limM x, y, t

lim

t→ ∞

ψtdx,y

1, ∀x, y∈X. 2.10

But for anyx /y,p1,k >1,t >0,

nlim→ ∞

M

x, y, kntnp lim

n→ ∞

ψkntdx,y·np lim

n→ ∞

1− 1 lnknt

n·dx,y

e−dx,y/lnk/1.

2.11 DefineΦ {φ:RR }, whereR 0, ∞and eachφ∈Φsatisfies the following conditions:

φ-1φis nondecreasing;

φ-2φis upper semicontinuous from the right;

φ-3

n0φnt< ∞for allt >0, whereφn 1t φφnt,n. It is easy to prove that, ifφ∈Φ, thenφt< tfor allt >0.

Lemma 2see7. LetX, M,∗be a fuzzy metric space, whereis a continuoust-norm of H-type.

If there existsφ∈Φsuch that if M

x, y, φt

M x, y, t

, 2.12

for allt >0, thenxy.

Definition 6see5. An elementx, y∈X×Xis called a coupled fixed point of the mapping F:X×XXif

F x, y

x, F y, x

y. 2.13

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Definition 7see5. An elementx, y∈X×Xis called a coupled coincidence point of the mappingsF:X×XXandg:XXif

F x, y

gx, F y, x

g y

. 2.14

Definition 8see7. An elementx, y ∈X×X is called a common coupled fixed point of the mappingsF:X×XXandg:XXif

xF x, y

gx, yF y, x

g y

. 2.15

Definition 9see7. An elementxX is called a common fixed point of the mappings F:X×XXandg:XXif

xgx Fx, x. 2.16

Definition 10see7. The mappingsF:X×X → Xandg:XXare said to be compatible if

n→ ∞limM gF

xn, yn

, F

gxn, g yn

, t 1,

n→ ∞limM gF

yn, xn

, F g

yn

, gxn , t

1,

2.17

for allt >0 whenever{xn}and{yn}are sequences inX, such that

n→ ∞limF xn, yn

lim

n→ ∞gxn x, lim

n→ ∞F yn, xn

lim

n→ ∞g yn

y, 2.18

for allx, yXare satisfied.

Definition 11see7. The mappingsF:X×XXandg:XXare called commutative if

g F

x, y F

gx, gy

, 2.19

for allx, yX.

Remark 3. It is easy to prove that, ifFandgare commutative, then they are compatible.

3. Main Results

For convenience, we denote M

x, y,tn

Mx, y, tMx, y, t ∗ · · · ∗Mx, y, t

n

, 3.1

for alln.

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Theorem 1. Let X, M,∗ be a complete FM-space, whereis a continuous t-norm of H-type satisfying2.7. LetF : X×XX andg : XX be two mappings and there existsφ ∈ Φ such that

M F

x, y

, Fu, v, φt

M

gx, gu, t

M g

y

, gv, t

, 3.2

for allx, y, u, vX,t >0.

Suppose thatFX×XgX, andgis continuous,Fandgare compatible. Then there exist x, yXsuch thatxgx Fx, x, that is,Fandghave a unique common fixed point inX.

Proof. Letx0, y0X be two arbitrary points in X. SinceFXgX, we can choose x1, y1Xsuch thatgx1 Fx0, y0andgy1 Fy0, x0. Continuing in this way we can construct two sequences{xn}and{yn}inXsuch that

gxn 1 F xn, yn

, g yn 1

F yn, xn

, ∀n≥0. 3.3

The proof is divided into 4 steps.

Step 1. Prove that{gxn}and{gyn}are Cauchy sequences.

Since∗is at-norm of H-type, for anyλ >0, there exists aμ >0 such that 1−μ∗1−μ∗ · · · ∗1−μ

k

≥1−λ,

3.4

for allk.

SinceMx, y,·is continuous and limt→ ∞Mx, y, t 1 for allx, yX, there exists t0>0 such that

M

gx0, gx1, t0

≥1−μ, M

gy0, gy1, t0

≥1−μ. 3.5

On the other hand, sinceφ∈Φ, by conditionφ-3we have

n1φnt0<∞. Then for anyt >0, there existsn0 such that

t >

kn0

φkt0. 3.6

From condition3.2, we have M

gx1, gx2, φt0 M

F x0, y0

, F x1, y1

, φt0

M

gx0, gx1, t0

M

gy0, gy1, t0

,

M

gy1, gy2, φt0 M

F y0, x0

, F y1, x1

, φt0

M

gy0, gy1, t0

M

gx0, gx1, t0 .

3.7

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Similarly, we can also get

M

gx2, gx3, φ2t0 M

F x1, y1

, F x2, y2

, φ2t0

M

gx1, gx2, φt0

M

gy1, gy2, φt0

M

gx0, gx1, t02

M

gy0, gy1, t02 ,

M

gy2, gy3, φ2t0 M

F y1, x1

, F y2, x2

, φ2t0

M

gy0, gy1, t0

2M

gx0, gx1, t0

2

.

3.8

Continuing in the same way we can get M

gxn, gxn 1, φnt0

M

gx0, gx1, t02n−1

M

gy0, gy1, t02n−1 , M

gyn, gyn 1, φnt0

M

gy0, gy1, t02n−1

M

gx0, gx1, t02n−1 .

3.9

So, from3.5and3.6, form > nn0, we have M

gxn, gxm, t

M

gxn, gxm, kn0

φkt0

M

gxn, gxm,

m−1

kn

φkt0

M

gxn, gxn 1, φnt0

M

gxn 1, gxn 2, φn 1t0

∗ · · · ∗M

gxm−1, gxm, φm−1t0

M

gy0, gy1, t0

2n−1

M

gx0, gx1, t0

2n−1

M

gy0, gy1, t0

2n

M

gx0, gx1, t02n

∗ · · · ∗ M

gy0, gy1, t02m−2

M

gx0, gx1, t02m−2

M

gy0, gy1, t02m−nm n−3

M

gx0, gx1, t02m−nm n−3

≥1−μ∗1−μ∗ · · · ∗1−μ

22m−nm n−3

≥1−λ,

3.10

which implies that

M

gxn, gxm, t

>1−λ, 3.11

for allm, nwithm > nn0andt >0. So{gxn}is a Cauchy sequence.

Similarly, we can get that{gyn}is also a Cauchy sequence.

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Step 2. Prove thatgandFhave a coupled coincidence point.

SinceXcomplete, there existx, yXsuch that

nlim→ ∞F xn, yn

lim

n→ ∞gxn x, lim

n→ ∞F yn, xn

lim

n→ ∞g yn

y. 3.12

SinceFandgare compatible, we have by3.12,

n→ ∞limM gF

xn, yn

, F

gxn, g yn

, t 1,

n→ ∞limM gF

yn, xn

, F g

yn

, gxn , t

1.

3.13

for allt >0. Next we prove thatgx Fx, yandgy Fy, x.

For allt >0, by condition3.2, we have M

gx, F x, y

, φt

M

ggxn 1, F x, y

, φk1t

M

gx, ggxn 1, φtφk1t M

gF xn, yn

, F x, y

, φk1t

M

gx, ggxn 1, φtφk1t

M gF

xn, yn

, F

gxn, gyn

, φk1tφk2t

M F

gxn, gyn

, F x, y

, φk2t

M

gx, ggxn 1, φtφk1t

M gF

xn, yn , F

gxn, gyn

, φk1tφk2t

M

ggxn, gx, k2t

M

ggyn, gy, k2t

M

gx, ggxn 1, φtφk1t ,

3.14

for all 0< k2< k1<1. Letn → ∞, sincegandFare compatible, with the continuity ofg, we get

M gx, F

x, y , φt

≥1, 3.15

which implies thatgxFx, y. Similarly, we can getgyFy, x.

Step 3. Prove thatgxyandgyx.

Since∗is at-norm of H-type, for anyλ >0, there exists anμ >0 such that 1−μ∗1−μ∗ · · · ∗1−μ

k

≥1−λ,

3.16

for allk.

SinceMx, y,·is continuous and limt→ Mx, y, t 1 for allx, yX, there exists t0>0 such thatMgx, y, t0≥1−μandMgy, x, t0≥1−μ.

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On the other hand, sinceφ∈Φ, by conditionφ-3we have

n1φnt0<∞. Then for anyt >0, there existsn0 such thatt >

kn0φkt0. Since M

gx, gyn 1, φt0 M

F x, y

, F yn, xn

, φt0

M

gx, gyn, t0

M

gy, gxn, t0

,

3.17

lettingn → ∞, we get M

gx, y, φt0

M

gx, y, t0

M

gy, x, t0

. 3.18

Similarly, we can get M

gy, x, φt0

M

gx, y, t0

M

gy, x, t0

. 3.19

From3.18and3.19we have M

gx, y, φt0

M

gy, x, φt0

M

gx, y, t0

2

M

gy, x, t0

2

. 3.20

By this way, we can get for alln,

M

gx, y, φnt0

M

gy, x, φnt0

M

gx, y, φn−1t02

M

gy, x, φn−1t02

M

gx, y, t0

2n

M

gy, x, t0

2n .

3.21

Then, we have

M

gx, y, t

M

gy, x, t

M

gx, y, kn0

φkt0

M

gy, x, kn0

φkt0

M

gx, y, φn0t0

M

gy, x, φn0t0

M

gx, y, t0

2n0

M

gy, x, t0

2n0

≥1−μ∗1−μ∗ · · · ∗1−μ

22n0

≥1−λ.

3.22

So for anyλ >0 we have

M

gx, y, t

M

gy, x, t

≥1−λ, 3.23

for allt >0. We can get thatgxyandgyx.

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Step 4. Prove thatxy.

Since∗is at-norm of H-type, for anyλ >0, there exists anμ >0 such that 1−μ∗1−μ∗ · · · ∗1−μ

k

≥1−λ,

3.24

for allk.

SinceMx, y,·is continuous and limt→Mx, y, t 1, there existst0 >0 such that Mx, y, t0≥1−μ.

On the other hand, sinceφ∈Φ, by conditionφ-3we have

n1φnt0<∞. Then for anyt >0, there existsn0 such thatt >

kn0φkt0. Since fort0>0,

M

gxn 1, gyn 1, φt0 M

F xn, yn

, F yn, xn

, φt0

M

gxn, gyn, t0

M

gyn, gxn, t0 .

3.25

Lettingn → ∞yields M

x, y, φt0

M x, y, t0

M y, x, t0

. 3.26

Thus we have

M x, y, t

M

x, y, kn0

φkt0

M

x, y, φn0t0

M

x, y, t02n0M

y, x, t02n0

≥1 −μ∗1−μ∗ · · · ∗1−μ

22n0

≥1−λ,

3.27

which implies thatxy.

Thus we have proved thatFandghave a unique common fixed point inX.

This completes the proof of theTheorem 1.

TakinggIthe identity mappinginTheorem 1, we get the following consequence.

Corollary 1. Let X, M,∗ be a complete FM-space, whereis a continuous t-norm of H-type satisfying2.7. LetF:X×XXand there existsφ∈Φsuch that

M F

x, y

, Fu, v, φt

Mx, u, tM y, v, t

, 3.28

for allx, y, u, vX,t >0.

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Then there existxXsuch thatxFx, x, that is,Fadmits a unique fixed point inX.

Letφt kt, where 0< k <1, the following byLemma 1, we get the following.

Corollary 2see6. Letababfor alla, b∈0,1andX, M,∗be a complete fuzzy metric space such thatMhasn-property. LetF:X×XXandg:XXbe two functions such that

M F

x, y

, Fu, v, kt

M

gx, gu, t

M

gy, gv, t

, 3.29

for allx, y, u, vX, where 0< k <1,FX×XgXandgis continuous and commutes withF.

Then there exists a uniquexXsuch thatxgx Fx, x.

Next we give an example to demonstrateTheorem 1.

Example 3. LetX −2,2,ababfor alla, b∈0,1.ψis defined as2.8. Let M

x, y, t

ψt|x−y|

, 3.30

for allx, y∈0,1. ThenX, M,∗is a complete FM-space.

Letφt t/2,gx xandF:X×XXbe defined as

F x, y

x2 8

y2

8 −2, ∀x, y∈X. 3.31

ThenFsatisfies all the condition ofTheorem 1, and there exists a pointx2−2√

3 which is the unique common fixed point ofgandF.

In fact, it is easy to see thatFX×X −2,−1, M

F x, y

, Fu, v, φt

ψφt|x2−u2 y2−v2|/8

, 3.32

For allt >0 andx, y∈−2,2.3.28is equivalent to

ψ t

2

|x2−u2 y2−v2|/8

ψt|x−u|

·

ψt|y−v|

. 3.33

Sinceψt∈0,1, we can get

ψ t

2

|x2−u2 y2−v2|/8

ψ t

2

|x−u|/2

·

ψ t

2

|y−v|/2

. 3.34

From3.33, we only need to verify the following:

ψ

t 2

|x−u|/2

ψt|x−u|

, 3.35

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that is,

ψ t

2

ψt2

, ∀t >0. 3.36

We consider the following cases.

Case 10< t≤4. Then3.36is equivalent to

α t

2 ≥ α

t2

, 3.37

it is easy to verified.

Case 2t≥8. Then3.36is equivalent to

1− 1 lnt/2

1− 1

lnt 2

, 3.38

which is

2 lnt·ln t

2 ≥ln2t ln t

2, 3.39

since

ln2t ln2t

2−2 lnt·ln t 2 lnt

2 −ln2t

2 ≤0, 3.40

that is

ln22 ln t 2−ln2t

2 ≤0, 3.41

holds for allt≥8. So3.36holds fort≥8.

Case 34< t <8. Then3.36is equivalent to

α t

2 ≥

1− 1 lnt

2

. 3.42

Lettex, we only need to verify

α 2ex/2

1− 1

x 2

≥0, 3.43

for allxthat 2 ln 2< x <3 ln 2. We can verify it holds.

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Thus it is verified that the functions F,g,φ satisfy all the conditions of Theorem 1;

x2−2√

3 is the common fixed point ofFandginX.

Acknowledgment

The author is grateful to the referees for their valuable comments and suggestions.

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