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PROBLEMS ON TIME SCALES

ALBERTO CABADA

Received 24 January 2006; Revised 31 May 2006; Accepted 1 June 2006

This paper is devoted to proving the existence of the extremal solutions of aφ-Laplacian dynamic equation coupled with nonlinear boundary functional conditions that include as a particular case the Dirichlet and multipoint ones. We assume the existence of a pair of well-ordered lower and upper solutions.

Copyright © 2006 Alberto Cabada. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

1. Introduction

The method of lower and upper solutions is a very well-known tool used in the theory of ordinary and partial differential equations. It was introduced by Picard [14] and allows us to ensure the existence of at least one solution of the considered problem lying between a lower solutionαand an upper solutionβ, such thatαβ. Combining these kinds of techniques with the monotone iterative ones (see [13] and references therein), one can deduce the existence of extremal solutions lying between the lower and the upper ones.

In recent years these techniques have been applied to difference equations [7,9,15].

So, existence results of suitable boundary value problems are obtained and the differences and the similarities between the discrete and the continuous problems are pointed out.

For instance, in second-order ordinary differential equations, the existence ofαβ, a pair of well-ordered lower and upper solutions of the periodic problem, ensures the existence of at least one solution remaining in [α,β]. This result is true for the periodic discrete centered problem

Δ2uk=ft,uk+1

, k∈ {0, 1,...,N1}, u(0)=u(N), Δu(0)=Δu(N), (1.1) but it is false for the noncentered ones [4].

It is important to consider both situations under the same formulation, that is, to study equations on time scales. One can see in [2] that, provided that f is a continuous

Hindawi Publishing Corporation Advances in Dierence Equations Volume 2006, Article ID 21819, Pages1–11 DOI 10.1155/ADE/2006/21819

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function, the second-order Dirichlet problem

uΔΔ(t)= ft,uσ(t), t[a,b], u(a)=A, uσ2(b)=B, (1.2) has at least one solution lying between a pair of well-ordered lower and upper solutions.

This study has been continued in [5] fornth-order periodic boundary value problems, in [11] for antiperiodic dynamic equations, and in [1] for second-order dynamic equations with dependence of the nonlinear term on the first derivative.

This paper is devoted to the study of theφ-Laplacian problem, which arises in the theory of radial solutions for thep-Laplacian equation (φ(x)= |x|p2x) on an annular domain (see [12] and references therein) and has been studied recently for differential equations (see, e.g., [6,10]) and also for difference equations [4,8]. It can be treated in the framework of second-order equations with discontinuities on the spacial variables [10].

First we study the existence results for the following boundary value problem:

φuΔ(t)Δ= ft,uσ(t), tTκ2[a,b], (1.3) B1

u(a),u=0, (1.4)

B2u,uσ2(b)=0. (1.5)

We assume that the following conditions are fulfilled:

(H1) f :I×RRis a continuous function;

(H2)φ:RRis continuous, strictly increasing,φ(0)=0, andφ(R)=R;

(H3)B1:R×C(T)Ris a continuous function, nondecreasing in the second vari- able;B2:C(T)×RRis a continuous function, nonincreasing in the first vari- able.

Remark 1.1. Note that the assumptionφ(0)=0 is not a restriction. By redefining ¯φ(x)= φ(x)φ(0), the same problem is considered.

It is clear that, by definingB1(x,η)=xc0 andB2(ξ,y)=yc1, these functional conditions include as a particular case the Dirichlet conditions

u(a)=c0, uσ2(b)=c1. (1.6)

The multipoint boundary value conditions are given by B1(x,η)= −x+

n i=1

aiηti

, B2(ξ,y)=y m j=1

bjξsj

, (1.7)

withn,mN,ai,bj0 for alli=1,...,nandj=1,...,m,a < t1<···< tnσ2(b), and as1<···< sm< σ2(b).

Now, choosing twoΔ-measurable setsJ0,J1Tandl,rNodd, it is possible to con- sider nonlinear boundary conditions as

u(a)=

J0

ul(t)Δt, uσ2(b)=

J1

ur(t)Δt, (1.8)

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or

u(a)=max

tJ0

u(t), uσ2(b)=min

tJ1

u(t). (1.9)

InSection 2we prove the existence of at least one solution of problem (1.3)–(1.5) lying between a lower solutionαand an upper solutionβ, such thatαβ.Section 3is devoted to warrant the existence of extremal solutions of problem (1.3)-(1.4) coupled in this case with the nonfunctional boundary condition

B2u(a),uσ2(b)=0. (1.10)

The exposed results improve the ones given in [2] whenφis the identity and the Dirichlet conditions are considered. In this case the regularity of the lower and the upper solutions is weakened, here corners in the graphs are allowed. Moreover they cover the existence results given in [4] for difference equations.

Before defining the concept of lower and upper solutions, we introduce the following notations:

ut+=

slimt+u(s) iftis right-dense, u(t) iftis right-scattered, ut=

slimtu(s) iftis left-dense, uρ(t) iftis left-scattered.

(1.11)

Definition 1.2. Letn0 be given and leta=t0< t1< t2<···< tn< tn+1=σ(b) be fixed.

αC(T) is said to be a lower solution of problem (1.3)-(1.4) if the following properties hold.

(1)αΔis bounded onTκ\{t1,...,tn}.

(2) For all i∈ {1,...,n}, there are αΔ(ti ),αΔ(t+i)R satisfying the following in- equality:

αΔti < αΔti+. (1.12) (3) For alli=0, 1,...,n,φ(αΔ)C1(ti,ti+1) and it satisfies

φαΔ(t)Δft,ασ(t), t ti,ti+1

,

B1α(a),α0B2α,ασ2(b). (1.13) βC(T) is an upper solution of problem (1.3)–(1.5) if the reversed inequalities hold for suitable pointsa=s0< s1< s2<···< sn< sn+1=σ(b).

We look for solutionsuof problem (1.3)–(1.5) belonging to the set uC(T) :uC1Tκ

:φuΔC1[a,b]. (1.14) We define [α,β]= {vC(T) :α(t)v(t)β(t) for alltT}.

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2. Existence of solutions

In this section, provided that hypotheses (H1)–(H3) are satisfied, we prove the existence of at least one solution in the sector [α,β] of the problem (1.3)–(1.5). First we construct a truncated problem as follows.

Definep(t,x)=max{α(t), min{x,β(t)}}for alltTandxR. Thus, we consider the following modified problem:

φuΔ(t)Δ=ft,pσ(t),uσ(t), t[a,b], (2.1) u(a)=B1(u)=pa,u(a) +B1

u(a),u, (2.2)

uσ2(b)=B2(u)=pσ2(b),uσ2(b)B2

u,uσ2(b). (2.3) Now, we prove the following three results for problem (2.1)–(2.3).

Lemma 2.1. Ifuis a solution of (2.1)–(2.3), thenu[α,β].

Proof. We will only see thatα(t)u(t) for everytT. The caseu(t)β(t) for alltT follows in a similar way.

By definition ofB1 andB2, using (2.2) and (2.3), we have thatα(a)u(a)β(a) and α(σ2(b))u(σ2(b))β(σ2(b)).

Now, lets0(a,σ2(b)) such that αs0

us0

=max

t∈T

u)(t)>0, (2.4) (αu)(t)<u)s0

t

s02(b). (2.5)

As a consequence,

u)Δs0

0u)Δs+0

, (2.6)

which tells us that there existsi0∈ {0,...,n}such thats0(ti0,ti0+1).

In the case whens0is a right-dense point ofT, we have thatαu0 on [s0,s1] (ti0,ti0+1) for some suitables1> s0. So, for allt[s0,ρ(s1)], it is satisfied that

φuΔ(t)Δ=ft,ασ(t)≥ −

φαΔ(t)Δ, (2.7)

and, integrating on [s,t](s0,ρ(s1)], we arrive at

φuΔ(t)φαΔ(t)φuΔ(s)φαΔ(s). (2.8) So, passing to the limit ins, from the regularity ofαanduon (ti0,ti0+1), we conclude that

φuΔ(t)φαΔ(t)φuΔs+0

φαΔs+0

0, (2.9)

for allt(s0,ρ(s1)).

From this expression we arrive at (αu)Δ0 on [s0,ρ(s1)], which contradicts the definition ofs0.

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Whens0is right-scattered, we have, from (2.5), that (αu)Δs0

<0. (2.10)

If moreovers0is left-dense, the continuity of (αu)Δon (ti0,ti0+1) implies that there exists an intervalV0(ti0,s0) such that

u)(t)>u)s0

tV0, (2.11)

which contradicts the definition ofs0.

Finally, whens0is isolated, we know that (αu)Δ(ρ(s0))0>u)Δ(s0) and

φuΔρs0Δ

=fρs0s0

≥ −φαΔρs0Δ. (2.12) Thus, we get at the following contradiction:

φuΔs0

+φuΔρs0

≥ −φαΔs0

+φαΔρs0

> φuΔs0

+φuΔρs0

. (2.13)

Lemma 2.2. Ifuis a solution of problem (2.1)–(2.3), thenB1(u(a),u)=0=B2(u,u(σ2(b))).

Proof. Suppose thatu(σ2(b))B2(u,u(σ2(b)))< α(σ2(b)). By definition ofB2, we obtain u(σ2(b))=α(σ2(b)).

Thus, using the monotone properties ofB2andLemma 2.1, we conclude ασ2(b)> ασ2(b)B2

u,ασ2(b)ασ2(b)B2

α,ασ2(b)ασ2(b), (2.14) reaching a contradiction.

An analogous argument proves thatu(σ2(b)) +B2(u,u(σ2(b)))β(σ2(b)). In conse- quence, it is clear that condition (1.5) holds. In the same way we prove that (1.4) is veri-

fied.

Now we prove the existence of at least one solution of the modified problem.

Lemma 2.3. Letαandβbe a lower solution and an upper solution, respectively, for problem (1.3)–(1.5) such thatαβinT. If hypotheses (H1)–(H3) are satisfied, then problem (2.1)–

(2.3) has at least one solution.

Proof. LetT:C(T)C(T) be defined for alltTas Tu(t)=B2(u)

σ(b)

t φ1τu r

a fs,pσ(s),uσ(s)ΔsΔr, (2.15) withτuthe unique solution of the expression

σ(b)

a φ1τu r

a fs,pσ(s),uσ(s)ΔsΔr=B2(u)B1(u). (2.16)

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It is not difficult to verify thatuis a fixed point ofT if and only ifuis a solution of (2.1)–(2.3).

First, we see that operatorTis well defined.

LetuC(T) be fixed; we define the functiongu:RRas follows:

gu(x)= σ(b)

a φ1x r

a fs,pσ(s),uσ(s)ΔsΔr xR. (2.17) Sinceuis fixed,guis a continuous and strictly increasing function onR.

Note that the continuity of f and the definition of p imply that there existsM >0 independent ofuC(T) such that

ft,pσ(t),uσ(t)M tTκ. (2.18) Sinceφ1is increasing, we have, for eachxR, that

g(x)

σ(b)aφ1x

σ(b)aMgu(x)

σ(b)aφ1x+σ(b)aMg+(x). (2.19) The functionsg±are continuous, strictly increasing and, sinceφ(R)=R,g±(R)=R. So, we have thatgu(R)=Rfor alluC(T), and then for eachuC(T) there exists a uniqueτusatisfyingguu)=B2(u)B1(u) which is equivalent to the fact that (2.16) is uniquely solvable for eachuC(T).

Now callc(u)±=(g±)1(B2(u)B1(u)). From (2.19) we deduce that

c(u)+τuc(u) uC(T). (2.20) And now, sinceB2(u)B1(u) is bounded inC(T) and (g±)1 are continuous inR, there existsL >0 such that

τuL uC(T). (2.21)

Therefore (2.18) and (2.21) show that operatorTis bounded inC(T).

Now, we prove that it is continuous.

SupposeunuinC(T). Letτnbe related tounby (2.16) andτuassociated tou. Now we prove that limn→∞τn=τu.

By construction ofτnandτu, we have B2

un

B1

un

B2(u) +B1(u)

= σ(b)

a

φ1τn r

afs,pσ(s),uσn(s)Δsφ1τu r

a fs,pσ(s),uσ(s)ΔsΔr

. (2.22) Thus, from the continuity ofp,B1, andB2, we conclude that

nlim→∞

σ(b)

a φ1τn r

a fs,pσ(s),uσn(s)ΔsΔt= σ(b)

a φ1τu r

a fs,pσ(s),uσ(s)ΔsΔt.

(2.23)

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From the fact that{τn}is a bounded sequence inR, we conclude that there exists a subsequence{τnk}converging to a real numberγ=lim sup{τn}. Thus, from the continu- ity ofφ1,p, and f, we have

klim→∞φ1τnk r

a fs,pσ(s),uσnk(s)Δs=φ1γ r

a fs,pσ(s),uσ(s)Δs rT, (2.24) and then

σ(b)

a φ1τu r

a fs,pσ(s),uσ(s)ΔsΔr= σ(b)

a φ1γ r

a fs,pσ(s),uσ(s)ΔsΔr.

(2.25) Sinceφ1is a strictly increasing function, we conclude thatτu=γ.

Analogously, we verify thatτu=lim inf{τn}. Now, since

τn t

a fs,pσ(s),uσn(s)Δsτu+ t

a fs,pσ(s),uσ(s)Δs

τnτu+ σ(b)

a

fs,pσ(s),uσ(s)fs,pσ(s),uσn(s)Δs tT, (2.26) the convergence of the sequence

τn+ t

a fs,pσ(s),uσn(s)Δs (2.27) is uniform onT.

Now, by using the uniform continuity ofφ1on compact intervals, we conclude that

Tun−→Tu uniformly onT. (2.28)

Now we are going to prove thatT(C(T)) is a relatively compact set inC(T).

Using (2.18), (2.21), and (H2), we have that there existsQ >0 such that

φ1(Q)(Tu)Δ(t)φ1(Q) tTκ,uC(T). (2.29) As a consequence, the setT(C(T)) is uniformly equicontinuous:

Tu(t)Tu(s)= t

s(Tu)Δ(r)Δrmaxφ1(Q),φ1(Q)|ts|, (2.30) for alls,tT.

Now, sinceT(C(T)) is bounded, the Ascoli-Arzel´a theorem [3, Theorem IV.24] ensures that operatorT is compact. Using the Tychonoff-Schauder fixed point theorem, see [2, Theorem 6.49], we know that there is at least one fixed point ofT; hence a solution of

(2.1)–(2.3).

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Now, we are in a position to enunciate the following existence result. The proof is a direct consequence of the three previous lemmas.

Theorem 2.4. Letαandβbe a lower solution and an upper solution, respectively, for prob- lem (1.3)–(1.5) such thatαβinT. Assume that hypotheses (H1)–(H3) are satisfied. Then problem (1.3)–(1.5) has at least one solutionu[α,β].

3. Existence of extremal solutions

In this section we prove that the problem (1.3), (1.4), (1.10) has extremal solutions on [α,β], that is, the problem has a unique solution on [α,β] or there is a pair of solutions vwin [α,β] such that any other solutionuin that sector satisfiesvuw.

Theorem 3.1. Letαandβbe a lower solution and an upper solution, respectively, for prob- lem (1.3), (1.4), (1.10) (with obvious notation) such thatαβinT. Assume that hypotheses (H1)–(H3) are satisfied. Then problem (1.3), (1.4), (1.10) has extremal solutions in [α,β].

Proof. Denote

S:=

v[α,β] :vis solution of (1.3), (1.4), (1.10). (3.1) As in the proof ofLemma 2.3, we can verify that the set

SΔ:=

vΔ:vS (3.2)

is bounded in theC(Tκ)-norm.

So Sis closed, bounded, and uniformly equicontinuous. As a consequence, see [3, Theorem IV.24], we have that it is compact inC(T).

Therefore, defining, fort[a,b],

vmin(t) :=infv(t) :vS, (3.3) we have that, for eacht0T, there is a functionvSsuch that

vt0

=vmint0

(3.4) andvminis continuous inT.

Now we prove thatvminis a solution of (1.3), (1.4), (1.10), showing thatvminis a limit of some sequence of elements ofS, that is, for everyε >0, there existsvSsuch that vvminC(T)ε.

Fixε >0 arbitrarily. AsSis an equicontinuous set andvminis a continuous function, there existsμ >0 such that fort,sTwith|ts|< μwe have

v(t)v(s)< ε

2, vS vmin

. (3.5)

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Now fix 0< r < μand define{δ01,...,δm} ⊂Tsuch thatδ0=a,δm=σ2(b), and for i=1,...,m1,

δi=

σδi1

ifσδi1

> δi1+r, maxtT\

δi1

:tδi1+r otherwise. (3.6) It is clear that

δiδi2+r i=2,...,m, δi=σδi1

or 0< δiδi1r < μ i=1,...,m. (3.7) Denoteβ0(t)va(t), wherevais a function ofSthat satisfiesva(a)=vmin(a), and for i∈ {1,...,m}define

βi(t)βi1(t) ifβi1δi

=vminδi. (3.8)

Otherwise, considerviSsuch that viδi

=vmin

δi

(3.9) and define

si:=inft δi1i

T:vi(s)< βi1(s)s t,δi

T , si+1:=supt

δi2(b)T:vi(s)< βi1(s)s

δi,tT

, (3.10)

and the function

βi(t)=

βi1(t) ift a,si

si+12(b)T, vi(t) ift

si,si+1

T. (3.11)

Since functionβmis aC1function except, at most, at the set Aβ=

sim+1 i=1

ρsim+1 i=1

σsim+1

i=1, (3.12)

it is clear that, by construction,

βΔmsβΔms+ sAβ, (3.13) and coincides with a solution in (σ(si),ρ(si+1)), we have that the regularity hypotheses in Definition 1.2hold.

Now, from the definition ofβmand (H3), we have B1

βm(a),βm

=B1

va(a),βm

B1

va(a),va

=0, B2

βm(a),βm

σ2(b)=B2

βm(a),vm

σ2(b)B2

vm(a),vm

σ2(b)=0. (3.14)

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Thus, we have thatβmis an upper solution of (1.3), (1.4), (1.10). ByTheorem 2.4, there is a solutionwmof (1.3), (1.4), (1.10) such thatwm[α,βm]. So, by the construction of βm,

vmin

δi

wm δi

βm δi

=vmin

δi

i∈ {0,...,m}. (3.15) Now, lettT\{δ0,...,δm}.By construction, we know that there isi∈ {1,...,m}such that ti1i) with δiδi1r (in other case δi=σ(δi1) and so (δi1i)T is empty).

As a consequence, by (3.5),

wm(t)vmin(t)wm(t)wδi+wm δi

vmin(t)

=wm(t)wm

δi+vmin

δi

vmin(t)< ε. (3.16) Then

wmvminC(

T)< ε. (3.17)

Asεis arbitrary, by the compactness ofSonC(T), we conclude that

vminS. (3.18)

Analogous arguments show us that problem (1.3), (1.4), (1.10) has a maximal solution

vmaxS.

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& Applications 42 (2000), no. 8, 1377–1396.

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Alberto Cabada: Departamento de An´alise Matem´atica, Facultade de Matem´aticas, Universidade de Santiago de Compostela, 15782 Santiago de Compostela, Galicia, Spain

E-mail address:[email protected]

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