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Vol. 9 No. 3 (1986) 429-434

INCLUSIONS OF HARDY ORLICZ SPACES

ROSHDI

KHALIL Department

of Mathematics The University of Michigan Ann Arbor, Michigan 48109 U.S.A.

(Received September 9, 1985 and in revised form February 24, 1986)

ABSTRACT. Let be a continuous positive increasing function defined on

[0,)

such

that (x y)

_< (x)

+ (y) and (0) 0. The Hardy-Orlicz space generated by

is denoted by

H().

In this paper, we

prove

that for

#

4, if

H() H()

as sets, then H() H() as topological vector spaces. Some other results are given.

KEY WORDS AND PHRASES. Modulus function, Orlicz spaces.

1980 AMS SUBJECT CLASSIFICATION CODE. 30G99.

I. INTRODUCTION.

Let

:[0,

=)

[0,=)

be a continuous increasing function such that

(x

y) (x) (y) and 4(0) 0. Let T be the unit circle, and m be the Lebesgue measure on T. A complex valued measurable function

f

defined on T is called -integrable if

fiIf(t) Idm(t)

<

.

The space of all -integrable functions on T will be denoted by L(). This space was first introduced by Orlicz,

[8].

Subsequent papers were written to study different aspects of

L().

Examples of these papers are Cater,

[4],

Gramsch,

[5]

and Pallashke

[9].

In

[6]

and

[7],

Lesniewicz introduced the so called Hardy-Orlicz spaces

H()

for

a given such function 9. The space

H()

was defined to be the space of all functions f e L() such that f is the radial limit of some function g analytic in the open unit disc and belongs to the Nevalinna class N. The relation between different H()- spaces was studied by Deeb, Khalil and Marzug

[3].

In this paper, we show that the inclusion map between two H()-spaces is always continuous. Some other results are given. It should be remarked that in the work of Lesniewicz,

[6], [7]

and many other authors, is assumed to be a Q-convex function. In this paper it is not assumed so.

2. PRELIMINARIES AND NOTATIONS.

A function

’[0,=)

-->

[0,

) is called a modulus function if (i) is continuous and increasing

(ii) (x) 0 if and only if x 0 (iii) (x +y) (x) (y).

The functions (x) x

p,

0 p and (x) in(1 x) are examples of modulus functions. Further, if

bl

and

b2

are modulus functions, then

l 2

and

bl ’}2

(2)

is a modulus function if is.

are modulus functions. Further, @-

#

Let T {z"

Izl

i}, A {z"

Izl

< i}. The space of analytic functions on &

is denoted by H(4). Let

H+(A)

{f e H(4)" li

rX+

f(reI@ exists a.e.@} We will consider H

+(4)

as a space of functions on T. For a given modulus function we define"

H i

@)

i@

H() {f (4)" sup

elf(re Id0 If(e )Ido

}.

0 <r <I

The function d" l-t(qb)

H(40 [0,),

d(f,g)

,If(e ie)

g(e

i0) Id

defines a metric on H(O), under which

H(b)

becomes a topological vector space. If one assumes that

Olul

is subharmonic for u e I-I(4), then

tt.)

turns out to be complete

[21.

For f e

H(,),

we write

llfll

T

If(e )ld@"

If

,(x)

x

p,

0 p i,

f

then

H()

Hp and for

(x)

In(l + x),

H()

N {f e N"

T in(l

Ifl)

<}, where N is the Nevalinna class.

3. I- II H() IS CONTINUOUS.

In

[2],

it was shown that H

H()

for all modulus functions The authors in

[3]

were not able to show that the inclusion map H

H()

is continuous.

In this section we prove that H

H()

is continuous. Some other related questions are discussed.

THEOREM 2.1. Let and

,

be two modulus functions such that lira

(

exists. Then" x-

(i) H() --H() if X 0 and is finite

(ii)

H()

H() if 0

(iii) H() H() if

.

PROOF. (i) Let 0 be finite. Then there exists a

l, bI, a 2, b

2

[0,)

such that

(x) _< al(X

for x

[a2,

(*)

(x)

_<

b

l(x)

for x e

[b2,)

(**).

Let f H(). Set

E(a2)

{t e T

If(t) >_a2}.

Then

*lf(e )ld0 ,]f(e io)

Ilfl[

(a2) EC(a2)

_<

a

If flI (a 2)

<-

Hence f e H() and H()

H().

Similarly we sho H()

H().

Consequently, H() H(). Case (xi) and (iii) are proved similarly and details are omitted. This ends the proof.

THEOREM 2.2. Let lira (x)

--

O. Then the inclusion map I"

H() tt()

is continuous. X-Oo

PROOF. From the proof of Theorem 2.1, there exists a,b 0 such that

IIfll

(a) b

]lfl]

for all f H().

Let

fn

0 in H(). Thus the sequence

(fn)

is bounded in the metric of H(,)

and consequently bounded in H(). If possible let there exist a subsequence (f nk

(3)

fnk fnk

0

(fnk)

has a subsequence which such that

II II

a > 0. Since

I] I1

converges pointwise to the zero function. With no loss of generality, we can assume that fn 0 a.e. Another application of the

proof

of Theorem 2.1, yields

(x)

k

(a) +

b-Ixl

for all x e

[0,).

Hence

Ifnk(t) ,(a)

b (t) The sequence of functions

gnk ,(a)

/ b

01fnk

converges a.e. to

,(a)

and

f

T

gnk

(t)dt

Consequently, by the generalized Lebesgue convergence theorem,

[10],

we have

lin 41fnk(t; Idt limnk 41 fnk

(t)

Idt

0.

This is a contradiction. Thus, the point w 0 is the only limit point of the bounded sequence

(11 fnll,)"

Consequently,

[11]

the

sequence lie

n converges to

zero. Hence I:

H(O)

H() is continuous. This ends the proof.

COROLLARY 2.3. If lira

,,-

e(O,o), then

H() H()

as topological vector spaces. X-o

PROOF. By Theorem 2.1, H(O)

H()

as sets. Theorem 2.2 implies that I:

H()

H() is an isomorphism. This ends the

proof.

A linear map A" H() H() is called metrically bounded if

for all f e H() and some X 0. Clearly every metrically bounded map is contanuous.

The converse need not be true. However, for the inclusion map, we have the following:

THEOREM 2.4. Let be any modulus function. Then there exists X 0 such that for all f e H

I,

PROOF. It is know,

[2]

(and easy to show) that H

H()

for all modulus func-

tions

.

If f e H and

If film m,

then using the argument in Theorem 2.1, we have

!1 fll,

get f H

II elI..

> 1. Then there exists 0 a such that

II af[I

1.. 1.

Since a 1, there exists a natural nber n such that a Hence n+ 1-- --n

II fll

fo an>, odu function It

llfll

and

But n

i f[l_ + K

follows that:

n+

"f",

X- and consequently

xn+ Ilfll xllfll

II,,f,,, "

This ends the proof.

TItEOREM 2.5. Let be a given modulus function such that H H(). If metric and topological bounded sets coincide in H(,), then

Ilfll xllfll

for al f e It(,),

for some X 0.

(4)

PROOF. Applying Corollary 2.3, I" H() H1 is an isomorphism of topological

__< III

f be not true on the unlt sphere of

vector spaces If possible let f

111

H()

Then, for each n there exists

fn

C

H(), llf

n

II

such that

f

Conslder the sequence

--= gn

By the assumptionf on bounded sets of H() we

have,

[12], gn

0 in

H().

But

llgn IIi ll_-lll_>

for all n This contradicts the continuity of the identity map I: H() H Hence there exists 0

such that

f < t f

II

{*)

for all f C H(), f

!1

Let f C H(), f

11

< Consider the map K"

[0

)

[0

) K(t)

]]tf 1]

It can be easily seen that K is continuous. Hence there exists a > such that we can find a such that K(a) Thus for every f E

H()

f

Iaf

Hence, from equation (*) we get"

]af Il ! ]]af ]I !

2ak

lf [

2t f This end the proof

Consequently, f

II +

4. FURTHER RESULTS

The concept of metrically bounded linear operator was introduced in Section 3.

A linear map A:

H() H()

is called metrically bounded if there exists

III

f In general a continuous linear map need not

I C (0,) such that

]IAf [1_

be metrically bounded

In

this section we prove a result which is a generalizatlon of Theorem 3.1 in

[3].

THEOREM 4.1 Let and be any two modules functlons. Then the following are equivalent

(i) lit (x) lit (x)

k+o

(x)

x-

(x) for some

c,

C (0,)

(ii) H() H(), and the identity map is metrically bounded.

PROOF. (i) (ii) From the assumption in (i) one can choose a and b in (0,) such that

(x] >-

r on

[0,a]

(X) S on (b,) (x]

for some r,s (0,oo) Theorem 3.2 implies that H() H(q) Let f H() Consider the following sets:

(5)

Then-

E(a)

={t- 0<

If(eil

<a}

E(b) ={t"

If(ei%l

> b)

E(a,b) {t"

a_< fi _<

b}

E(a,b)

E(b)

<

--I]

r f

,

E(a,b)

]f(eit) Idt

+

7 II

f

I1

on

the closed interval

[a,b],

the continuity of

(x)

(x) implies the existence of X > 0 such that

(x) _< X(x) Hence

(1 1)

Thus,

If[ _<

8

]f []$

where

m,,3

In a similar way one c show that f

]$ ! [$

for all f g H($) H()

Hence

the identity map is metrically .bounded.

Conversely, (ii) (i) Asse H($)

H()

d

" H() H()

is

metrically bounded.

en

there exists and in (0,) such that

< a

]if ]if ]]

l]

f

,

Hence

!

for all f g

H()

H() Consider the function f(z) xz for z eit x g (0,) Then

[If [[

}(x) and

[If II

(x)

Consequently

(x)

---< (x)

<a Since ,8 g (0,) (i) then follows. This end the

proof.

ACKNOWLEDGEMENT.

This work was done while the author was a visiting Professor at the University of Michigan. The author would also like to thank the Department of Mathematics for their warm hospitality.

REFERENCES

1. ALEKSANDROV, A.B. Essays On No Locally Convex Hardy Classes. Lecture Notes In Math. 864(1-90).

2. DEEB, W. and

RZUQ,

M. H()-Spaces. To

Appear

In Bull. Canad. Math. Soc.

3. DEEB, W., KHALIL, R. and btARZUQ, M. Isometric Multiplication Of Hardy-Orlicz

Spaces.

To

Appear In ull.

Aust. Math. Soc.

4. CATER, S. Continuous Linear Functionals On Certazn Topological Vector Spaces.

Pac. J. Math. 13(1963) 6S-71.

5. GRAMSCH, B. Die K1asse Der Metrischen L1nearen Raume L( Math. Ann. 171(1967) 61-78.

6. LESNIEWICZ, R. On Hardy-Orlicz

Spaces

I, Commt. Math. 15(1971) 3-56.

(6)

7. LESNIEWICZ, R. On Linear Functionals

In

Hardy-Orlicz

Spaces

I, Stud. Math.

4_6(1973)

53-77.

8. ORLICZ, W. On

Spaces

Of -integrable Functions. Proc. Intern. Syrup. On Linear

Spaces.

Hebrew Univ. Jerusalem,

(1960)

357-365.

9. PALLASHKE, D. The Compact Endomorphisms Of The Metric Linear

Spaces

L().

_tudia

Math.

XLVII(1973).

I0.

ROYDEN, H.L.,

Macmillan Company New York, 1963.

II.

WILANSKY,

A. Topology For Analysis, John Wiley, 1970.

12.

WILANSKY,

A. Modern Methods

In

Topological

Vector Spaces.

McGraw Hill. 1978.

参照

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