New York Journal of Mathematics
New York J. Math. 22(2016) 1271–1282.
Weighted Bergman projections on the Hartogs triangle: exponential decay
Liwei Chen and Yunus E. Zeytuncu
Abstract. We study weighted Bergman projections on the Hartogs triangle inC2. We show that projections corresponding to exponentially vanishing weights have degenerateLpmapping properties.
Contents
1. Introduction 1271
2. Proof of Theorem 1.1 1275
3. Proof of Theorem 1.2 1279
4. Proof of Theorem 1.3 1281
References 1281
1. Introduction
Let Ω⊂Cn be a bounded domain andµbe a nonnegative function on Ω.
We sayµis an admissible weight if L2a(Ω, µ), the space of square integrable holomorphic functions, is a closed subspace ofL2(Ω, µ), the space of square integrable functions with respect to µ(z)dV(z) where dV(z) stands for the Lebesgue measure. The weighted Bergman projectionBµΩ is the orthogonal projection operator from L2(Ω, µ) ontoL2a(Ω, µ). It is an integral operator of the form
BµΩf(z) = Z
Ω
BΩµ(z, w)f(w)µ(w)dV(w)
forf ∈L2(Ω, µ). We refer to [Kra01] and [PW90] for basic definitions and properties. The analytic properties of the operatorBµΩ and kernelBµΩ(z, w) depend on the geometry of the domain Ω and the function theoretic prop- erties of the weightµ.
One particular investigation is relating theLp mapping properties of BµΩ and the order of vanishing of the weight µ on the boundary of Ω. One
Received February 17, 2016.
2010Mathematics Subject Classification. Primary 32A25; secondary 32A07, 32A36.
Key words and phrases. Weighted Bergman projection, exponential weights, Hartogs triangle.
The work of the second author was partially supported by a grant from the Simons Foundation (#353525).
ISSN 1076-9803/2016
1271
LIWEI CHEN AND YUNUS E. ZEYTUNCU
way of defining weights that vanish on the boundary is to take different compositions of a distance to the boundary function. In particular, let δ be a distance to the boundary function and ν(x) : [0,∞) → [0,∞) be a continuous function that only vanishes atx= 0. Then the compositionν(δ) is an admissible weight on Ω and one can study the Lp regularity of Bν(δ)Ω and relate it to the order of vanishing ofν(x) at 0. Below we go over some known results using this notation.
We start with the unit disc D inCand choose δ(z) = 1− |z|2. Then we list the following results.
• Ifν ≡1 orν(x) =xk for some k >0, then the weighted projection operatorBν(δ)
D is bounded fromLp(D, ν(δ)) to itself for allp∈(1,∞).
See [Zhu91,FR75].
• On the other hand, ifν(x) = exp −1x
then the weighted projection operatorBν(δ)
D is bounded from Lp(D, ν(δ)) to itself only for p= 2.
See [Dos04,Zey13].
This change inLp mapping properties between the polynomial vanishing and the exponential vanishing has been detected on some Reinhardt domains too. In particular, let Ω be a smooth bounded complete Reinhardt domain of finite type inC2 and let ρ be a smooth multi-radial defining function for Ω. We choose δ=−ρ. Then we recall the following results.
• If ν ≡ 1 or ν(x) = xt for some rational number t > 0, then the weighted projection operator Bν(δ)Ω is bounded from Lp(Ω, ν(δ)) to itself for allp∈(1,∞). See [McN94,CDM14,CDM15].
• On the other hand, ifν(x) = exp −1x
then the weighted projection operatorBν(δ)Ω is bounded from Lp(Ω, ν(δ)) to itself only forp= 2.
See [CZ16b].ˇ
In addition to these contrasting results, there are more results in the polynomial decay case where theLp boundedness on the full interval (1,∞) is observed. See for example [BG95] and [CL97]. Therefore, the degenerate Lp regularity for exponential weights on other domains arises as a natural question. More specifically, we pose the following question.
Question. Let Ω be a bounded domain with some additional geometric properties (e.g., finite type, convex, etc.) andδ be a distance to the bound- ary function. For ν(x) = exp −x1
, is the weighted projection operator Bν(δ)Ω bounded onLp(Ω, ν(δ)) for anyp6= 2?
In this note, we investigate this question on the Hartogs triangle. In C2, the Hartogs triangle His given by
H=
(z1, z2)∈C2 : |z2|<|z1|<1 .
The source of many counterexamples onHis the singular point at the origin.
Hence, the natural choice of a distance function here is the distance to the
singular point, that is, we set
δ(z) =|z1|.
For this choice ofδ, the polynomial decay case is already studied in [Che13, Che17, CZ16a]. Although the Lp boundedness does not hold for all p ∈ (1,∞), there is always a nondegenerate interval around p = 2 where the weighted projection operator isLp bounded.
Theorem ([Che17]). Let δ(z) =|z1| and ν(x) = xt where t ∈(0,∞) with the unique decompositiont=s+ 2ksuch thatk∈Zands∈(0,2]. Then the weighted Bergman projection Bν(δ)
H is bounded on Lp(H, ν(δ))if and only if p∈
t+4
s+k+1,k+1t+4 .
Note that for any t >0, there is an interval around 2 where the weighted Bergman projection is Lp bounded. Moreover, this interval gets smaller as t gets bigger. In other words, higher order vanishing of ν(x) indicates smaller Lp boundedness range. In the light of this observation we answer the question above as follows.
Theorem 1.1. Let ν(x) = exp −1x
, δ(z) =|z1|, and define the exponen- tially decaying weight
µ(z) =ν(δ(z)) = exp
− 1
|z1|
. Then the weighted Bergman projection Bµ
H is bounded on Lp(H, µ) if and only ifp= 2.
Although we state the result for a single choice of ν(x), it will be clear in the proof that the statement holds for more general choices of the form ν(x) = xsexp −1x
for s ∈ R. Moreover, further generalizations can be formulated on domains that are variants of the Hartogs triangle, see [Che13]
and [EM16a].
In addition to the change in Lp regularity of the weighted Bergman pro- jection, another related change takes place in the boundary behavior of the weighted Bergman kernel with exponentially decaying weights. For poly- nomially decaying weights on the Hartogs triangle, the weighted Bergman kernel on the diagonal does not grow faster than a power of the distance function. The following result can be derived from [Che17, Lemma 3.1], where the author presents a detailed study of polynomial weights on the Hartogs triangle.
Theorem ([Che17]). Let δ(z) =|z1| and ν(x) = xt where t ∈(0,∞) with the unique decomposition t= s+ 2k such that k ∈Z and s ∈(0,2]. Then there exist real numbers τ and C such that
δ(z)τBν(δ)
H (z, z)≤C
LIWEI CHEN AND YUNUS E. ZEYTUNCU
as z approaches the origin inside any cone
Vγ ={(z1, z2)∈C2 : γ|z2|<|z1|}, where γ >1.
However, the weighted Bergman kernel with respect to exponential weights grows faster than any power of the distance to the boundary function. We state the following result.
Theorem 1.2. Let ν(x) = exp −1x
, δ(z) =|z1|, and define the exponen- tially decaying weight
µ(z) =ν(δ(z)) = exp
− 1
|z1|
. Then for any τ >0,
δ(z)τBν(δ)
H (z, z)
is unbounded as z approaches the origin inside any cone Vγ ={(z1, z2)∈C2 : γ|z2|<|z1|}, where γ >1.
Furthermore, if we insert a factor of µ(z) into the product then we get boundedness. See the remark after the proof of Theorem1.2.
Finally, we demonstrate another change from polynomial decay to expo- nential decay in the setting of generalized Hartogs triangles. Recently, in a series of papers [EM16a,Edh16],Lpboundedness of the Bergman projection operator is studied on the following variants of the Hartogs triangle. Let k be a positive number and define
Hk={(z1, z2)∈C2 : |z2|<|z1|k<1}.1
It is shown that when k is a positive integer, the (unweighted) Bergman projection is bounded on Lp(Hk) for some values ofp.
Theorem ([EM16a,EM16b]). For positive integerk, the Bergman projec- tion BHk is bounded on Lp(Hk) if and only if p∈
2k+2 k+2,2k+2k
.
On the other hand, the domain Hk will become pieces of boundaries as k tends to ∞. In order to study the degenerate Lp boundedness, we define the following exponential version as the limiting domain inC2
H∞=
(z1, z2)∈C2 : |z2|<exp
− 1
|z1|
, 0<|z1|<1
. Then we prove the following result.
Theorem 1.3. The Bergman projectionBH∞ is bounded onLp(H∞) if and only ifp= 2.
1In [EM16a,Edh16], authors denote this domain byH1k.
Recently, Edholm and McNeal [EM16b] obtained similar degenerate Lp regularity on domainsHγ where γ is an irrational number. These examples are particularly interesting since the degeneracy is not due to the exponential decay but to nonrationality of the singularity.
In the following sections, we present proofs for the three statements above.
We start with Theorem 1.1, where the proof is based on some asymptotic computations. Then we continue with Theorem1.2 and we present a proof by obtaining an (almost) explicit closed form for the weighted Bergman kernel on the diagonal. Finally, the proof of Theorem 1.3 is based on the weighted theory on the punctured disc.
We highlight again that the irregular behavior in Theorems 1.1 and 1.2 are due to the exponential decay of the weight and similar results may hold on other domains. We plan to study these analogous questions on more general domains in future.
Throughout the paper, we write x≈ y to mean that there exists C > 0 such that C1x≤y≤Cx.
2. Proof of Theorem 1.1
We prove Theorem1.1by studying weighted Bergman projections on the punctured unit disc D∗. Let Bλ be the weighted Bergman projection from L2(D∗, λ) onto L2a(D∗, λ), where λ(z) = exp
−|z|1
, z ∈ D∗. Given any sufficiently large j ∈Z+, we pick p > 2 +2j. We study the behavior of the sequence
z−jkzk k∈
Z+ under the projection Bλ. First, forα ∈R, we define
I(α) = Z 1
0
rαe−1rdr.
Since λis radial on D∗ and exponential decaying at the origin, all {zn}n∈Z are orthogonal and in L2a(D∗, λ). So the weighted Bergman kernel has the form
Bλ(z, ζ) =
∞
X
n=−∞
cn(zζ)n, wherecn=
R
D∗|z|2nexp −|z|1
dA(z)−1
. Then by using the orthogonality of monomials and the labelling above, we get
kBλ(z−jkzk)kpλ kz−jkzkkpλ (1)
= R
D∗
R
D∗Bλ(z, ζ)·ζ−jkζk·exp
− |ζ|1 dA(ζ)
p
exp
−|z|1 dA(z) R
D∗|z−jkzk|pexp
−|z|1 dA(z)
LIWEI CHEN AND YUNUS E. ZEYTUNCU
= R
D∗
R
D∗
P∞
n=−∞cn(zζ)n·ζ−jkζk·exp
−|ζ|1 dA(ζ)
p
exp
−|z|1 dA(z) R
D∗|z|−(j−1)pkexp
−|z|1 dA(z)
= R
D∗|ζ|−2jk ·exp
−|ζ|1 dA(ζ)
pR
D∗|z|−(j+1)pkexp
− |z|1 dA(z)
R
D∗|z|−2(j+1)kexp
− |z|1 dA(z)
pR
D∗|z|−(j−1)pkexp
−|z|1 dA(z)
= [I(−2jk+ 1)]p·I(−(j+ 1)pk+ 1) [I(−2(j+ 1)k+ 1)]p·I(−(j−1)pk+ 1).
Our goal is to show that the fraction in the last line blows up. We accomplish this by studying the asymptotic behavior of the integralI(α).
Lemma 2.1. We have the following estimates on I(α) as α→ ±∞.
α→+∞lim (α+ 1)I(α) =e−1, (2)
α→+∞lim
I(−α) Γ(α−1) = 1.
(3)
Proof. To show (2), we first apply the Monotone Convergent Theorem and conclude
α→+∞lim I(α) = 0.
By integration by parts, we see that I(α) =
Z 1 0
rαe−1r dr
= 1
α+ 1rα+1e−1r
1
0
− Z 1
0
1
α+ 1rα−1e−1r dr
= e−1
α+ 1−I(α−1) α+ 1 .
By clearing the denominators, and letting α→+∞, we arrive at (2).
To show (3), we make change of variables in the definition of I(α) by x= 1r. We see that
I(−α) = Z ∞
1
xα−2e−xdx
= Γ(α−1)− Z 1
0
xα−2e−xdx,
where Γ is the Gamma function. Again by the Monotone Convergent The- orem
α→+∞lim Z 1
0
xα−2e−xdx= 0, and the fact that
α→+∞lim Γ(α−1) = +∞,
we obtain (3).
Now we combinte the asymptotic estimate in (3) and the Stirling’s formula Γ(x+ 1)≈√
2πx x
e x
asx→ ∞, to get
k→+∞lim
kBλ(z−jkzk)kpλ kz−jkzkkpλ
= lim
k→+∞
[Γ(2jk−2)]p·Γ((j+ 1)pk−2) [Γ(2(j+ 1)k−2)]p·Γ((j−1)pk−2)
= lim
k→+∞
s j
j+ 1 p
j+ 1 j−1
· (2jk−3)(2jk−3)p[(j+ 1)pk−3][(j+1)pk−3]
[2(j+ 1)k−3][2(j+1)k−3]p[(j−1)pk−3][(j−1)pk−3]
≈ lim
k→+∞
2jk−3 2(j+ 1)k−3
(2jk−3)p
·
(j+ 1)pk−3 (j−1)pk−3
(j−1)pk−3
·
(j+ 1)pk−3 2(j+ 1)k−3
2pk
.
A straightforward limit computation indicates
k→+∞lim
2jk−3 2(j+ 1)k−3
(2jk−3)p
·
j+ 1 j
(2jk−3)p
= lim
k→+∞
1− 3
2j(j+ 1)k−3j
(2jk−3)p
= exp
− 3p j+ 1
.
Similarly, we also get
k→+∞lim
(j+ 1)pk−3 (j−1)pk−3
(j−1)pk−3
·
j−1 j+ 1
(j−1)pk−3
= lim
k→+∞
1 + 6
(j+ 1)(j−1)pk−3(j+ 1)
(j−1)pk−3
= exp 6
j+ 1
and
k→+∞lim
(j+ 1)pk−3 2(j+ 1)k−3
2pk
· 2
p 2pk
= lim
k→+∞
1 + 3p−6 2(j+ 1)pk−3p
2pk
LIWEI CHEN AND YUNUS E. ZEYTUNCU
= exp
3p−6 j+ 1
.
Therefore, since j+1j−1 ≥
j+1 j
2
, we obtain
k→+∞lim
kBλ(z−jkzk)kpλ
kz−jkzkkpλ ≈ lim
k→+∞
j j+ 1
(2jk−3)p j+ 1 j−1
(j−1)pk−3
p 2
2pk
≥ lim
k→+∞
j+ 1 j
2(j−1)pk−6−(2jk−3)p
p 2
2pk
= lim
k→+∞
j+ 1 j
3p−6−2pk
p 2
2pk
≥ lim
k→+∞
1 +1
j −2pk
p 2
2pk
=∞.
This shows that for any p > 2, the weighted Bergman projection Bλ is unbounded onLp(D∗, λ).
Now, we deduce the unboundedness of Bµ
H from unboundedness of the weighted Bergman projections as follows. LetBλ˜ be the weighted Bergman projection onL2a(D∗,λ), where ˜˜ λ(z) =|z|2exp
−|z|1
,z∈D∗. Then by the inflation principle (see [Zey13, Che17]), if Bµ
H is bounded on Lp(H, µ) then Bλ˜ is bounded onLp(D∗,λ).˜
Note that the behavior of the sequence
z−jkzk k∈
Z+ under the projec- tion Bλ˜ can be obtained from the behavior of the same sequence under the projection Bλ by shifting the indices of the integral I(α) by 2. More precisely, we have
kB˜λ(z−jkzk)kp˜
λ
kz−jkzkkp˜
λ
= [I(−2jk+ 3)]p·I(−(j+ 1)pk+ 3) [I(−2(j+ 1)k+ 3)]p·I(−(j−1)pk+ 3) and
k→+∞lim
kBλ˜(z−jkzk)kp˜
λ
kz−jkzkkp˜
λ
· j
j+ 1 2p
j+ 1 j−1
2
= lim
k→+∞
kBλ(z−jkzk)kpλ kz−jkzkkpλ .
Hence, for anyp >2 the weighted Bergman projection B˜λ is unbounded on Lp(D∗,λ) and we conclude that˜ Bµ
H is bounded on Lp(H, µ) if and only ifp= 2.
3. Proof of Theorem 1.2
In this proof, we again study the weighted Bergman space L2a(D∗, λ), where λ(z) = exp
−|z|1
. Note that, if we denote the weighted Bergman kernel associated toL2a(D∗, λ) byBλ(z, ζ), then we have
Bλ(z, ζ) =
+∞
X
k=−∞
1
I(2k+ 1)zkζk. By (2) and (3), we see that
Bλ(z, z) =
−1
X
k=−∞
+
+∞
X
k=0
1
I(2k+ 1)|z|2k
≈ |z|−2 I(−1)+
+∞
X
k=2
|z|−2k Γ(2k−2)+
+∞
X
k=0
(k+ 1)|z|2k
≈ |z|−3sinh|z|−1+ 1 (1− |z|2)2. Let Bµ
H(z, ζ) be the Bergman kernel on H with respect to the weight µ(z1, z2) = exp
−|z1
1|
, and letBµ0
H(z, ζ) be the Bergman kernel on Hwith respect to the weight µ0(z1, z2) = |z1|t, where t ∈ R. By looking at the biholomorphism
Φ :H→D∗×D, where Φ(z1, z2) =
z1,z2 z1
and by the biholomorphic equivalence of kernels, see [Che17, Corollary 2.4 and Lemma 3.1], we conclude that
Bµ0
H(z, ζ)
= detJCΦ(z)detJCΦ(ζ)Bµ0◦Φ−1
D∗×D (Φ(z),Φ(ζ))
= 1 z1
· 1
ζ1 ·Bµ0◦Φ−1
D∗ (z1, ζ1)·BD z2
z1
,ζ2 ζ1
= s
2 · 1
(z1ζ1)k+2 + 1−s
2
· 1 (z1ζ1)k+1
· 1
(1−z1ζ1)2 · 1
1− zz2
1 ·ζ2
ζ1
2
wheret=s+ 2k,k∈Zand s∈(0,2], and that Bµ
H(z, ζ) = detJCΦ(z)detJCΦ(ζ)Bµ◦Φ−1
D∗×D(Φ(z),Φ(ζ))
= 1 z1 · 1
ζ1 ·Bµ◦Φ−1
D∗ (z1, ζ1)·BD z2
z1,ζ2 ζ1
LIWEI CHEN AND YUNUS E. ZEYTUNCU
=Bλ(z1, ζ1)· 1 z1 · 1
ζ1 · 1
1−zz2
1 ·ζ2
ζ1
2.
Therefore, on the diagonal line, we have Bµ0
H(z, z) = s
2 · 1
|z1|2k+4 + 1−s
2
· 1
|z1|2k+2
· 1
(1− |z1|2)2 · 1
1−|z|z2|2
1|2
2
and Bµ
H(z, z)≈
|z1|−3sinh|z1|−1+ 1 (1− |z1|2)2
· 1
|z1|2 · 1
1−|z|z2|2
1|2
2.
Recall that δ(z) =|z1|, hence Bµ0
H(z, z)·δ(z)τ
= s
2 · 1
|z1|2k+4 +
1− s 2
· 1
|z1|2k+2
· 1
(1− |z1|2)2 · 1
1−|z|z2|2
1|2
2 · |z1|τ
≤ |z1|τ−(2k+4)· 1
(1− |z1|2)2 · 1
1−|z|z2|2
1|2
2
≤C
for someτ ∈Rasz→0 inside any coneVγ ={(z1, z2)∈C2: γ|z2|<|z1|}, whereγ >1. Whereas, for the exponential weightµon H,
Bµ
H(z, z)·δ(z)τ
≈
|z1|−3sinh|z1|−1+ 1 (1− |z1|2)2
· 1
|z1|2 · 1
1−|z|z2|2
1|2
2 · |z1|τ
≈ |z1|τ−5exp 1
|z1|
· 1
1− |z|z2|2
1|2
2
is unbounded for all τ ∈Rasz→0 inside any coneVγ, whereγ >1.
Remark. If we correct the distance δ(z) by a factor of the weight µ(z), then we get
Bµ
H(z, z)·µ(z)·δ(z)τ ≈ |z1|τ−5·
1−|z2|2
|z1|2 −2
≤C forτ ≥5 as z→0 inside any cone Vγ, where γ >1.
4. Proof of Theorem 1.3
In view of the Forelli-Rudin inflation principle, see for example [Zey13, Proposition 4.4], unboundedness of BH∞ can be deduced from unbounded- ness of the corresponding weighted Bergman projection on the punctured disc D∗. Note that, in [Zey13], the smooth radial weights vanish at infinite order at the boundary of the unit disc. Hence, integration by parts plays a crucial role in obtaining asymptotics of the moment function of these weights. Whereas, here the radial weight λ(z) = exp
−|z|1
is vanishing of any order only at the origin, the nonsmooth boundary of the punctured discD∗. Since we do not have vanishing conditions on the smooth boundary of the punctured disc, we do not base our argument on successive integra- tion by parts. Instead we use the asymptotic information from the second section.
Proof of Theorem 1.3. By [Zey13, Proposition 4.4], for p ∈ (1,∞) if the weighted Bergman projection Bλ is unbounded on the weighted space Lp(D∗, λ), then the Bergman projectionBH∞associated toH∞is unbounded onLp(H∞). In Section 2, we have already showed thatBλ is unbounded on Lp(D∗, λ) forp >2, therefore we conclude thatBH∞ is bounded onLp(H∞)
if and only if p= 2.
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(Liwei Chen) The Ohio State University, Department of Mathematics, Colum- bus, OH 43210
(Yunus E. Zeytuncu)University of Michigan - Dearborn, Department of Math- ematics and Statistics, Dearborn, MI 48128
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