• 検索結果がありません。

WORDS AND

N/A
N/A
Protected

Academic year: 2022

シェア "WORDS AND"

Copied!
3
0
0

読み込み中.... (全文を見る)

全文

(1)

Internat. J. Math. & Math. Scl.

VOL. 16 NO. 2 (1993) 297-300

297

DIVERGENT

SEQUENCES

SATISFYING THE LINEAR FRACTIONAL TRANSFORMATONS

A.McD.MERCER

Department

ofMathematics and Statistics University ofGuelph

Ontario, N1G 2W1, Canada

(Received August

26, 1991 andinrevisedform March31

1992)

ABSTRACT. A

real sequence

{z,}

which satisfies therecurrence

z, + cx.

+d,+ inwhichallof a,b,e,d arereal will, forcertainvalues ofthese constants, bedivergent.

It

isthe purpose of this note toexaminethelimit

Lira f(Zn):

f

6_C(-oo, o)

n=l

in these cases.

Except

for certain exceptional values ofa,b,c,dthis valueis found for almost all

z

KEY WORDS AND PHRASES.

Divergent series, linear fractional transformations, ergodic theory,

Cesaro

means.

1991

AMS SUBJECT CLASSIFICATION CODE.

40A50.

Consider thelinear fractionaltransformation:

T(z)=az+b

cz+d (ad-bc= l:c#O)

whichis tohavethe propertyof mapping theextendedrealaxisRone-oneonto itself. Itiseasily seenthat anecessaryand sufficient condition for thisis that all ofa,b,c,dbereal.

(Note

thatwe

must allow R tocontain the ideal "point at infinity" whichwetake as o. This will allowthe point -e

d-

tohaveanimage. ThusR=[-oo,

+

).)

This transformation will have one or two fixed points.

In

the former case if

,

is the fixed point, it will be real andany sequenceof real numbers satisfying

Zn +

T(zn) (n 1,2, will

converge to

,.

Iftherearetwo fixed points theneither:

(a)

theywillbothbereal

or

(b)

theywillformacomplexconjugate pair.

In

case

(a),

any sequencegeneratedas above willconvergetooneofthe fixed points

(call

this

one

,)

whilstincase

(b)

there will not beconvergenceat all.

The behavior of the twoconvergent cases abovecan beexpressed

(more weakly)

by asserting that

(2)

298 A.M. MERCER N

forany

!

EC( oo,oo).

Our purpose here is to enquire about the existence and value of this limit in the non- convergent case

(b)

above. Weshall show that, exceptfor certainexceptional values ofa,b,e,d, and for almost allz1, weshall have

N

f +

oo Kl(z)

-oocz

2+(d-a)z-b

whenever/is such that the right handside exists asa Lebesgue integral.

(The

constant K isa

normalizingconstantwhosevalueissuchastomake therighthandsideunity when I(z)

1.)

If and arethetwofixed pointsin case

(b)

then thetransformation

canbewritten as

y T(z) c+daz+b

19

this0< <2since,cbeingnon-zero, the identity transformationisexcluded.

DefineS:l-[0, 2=)asfollows:

S(x)

arg(Zz--),

withthe principal value ofarglyingin Define

H/:[0,2r)--,[0,2r)

by

HB($)=

+$(rood 2t)

Clearly both S and

H/

areone-one and onto. It is also well-known that, whenever

B

isnot a

rationalmultiple of

,

H

E

isergodicwithrespect toordinaryLebesgue probability measuremon [0,2) andpreserves thismeasure.

Whenzandy arereal

(2)

isequivalentto

That is, S(v)

tl#S(z)

or v S

1H/S(z)

So,

sincev T(z)=_azcz

+ +

d’b we see nowthatT 5’

1HBS.

To deal with this situation we shall next provea lemma

(stated

in somewhat more general

termsthanisrequiredforthe present application).

LEMMA.

Let

Ml(Xl,t,m 1)

and

M2(X2,,m2)

be two measure spaces with probability measures m andm2. Let

S:Xl-.X

2and

H:X2-.X2,

both of these transformationsbeingone-one and onto.

Suppose

that ECX is

ml-measurable

ifand onlyif S(E)CX2is

m2-measurable

and

that

ml(E m2(S(E)).

Finally, supposethat//is

m2-measure

preserving andergodicwith respect tothis measure. Then thetransformation T $-1H$is

ml-measure

preserving andergodicwith respect tom 1.

PROOF.

Since allour transformationsare invertible, we may deal with the transformations themselves rather thantheir inverses.

(3)

DIVERGENT SEQUENCES 299

(a) Let

EcX be

rnl-measurable.

Then

ml(E) rn2(S(E)) m2(//$(E)) nl(S- I//S(E)) rnl(T(E))

This shows that 7"is

ml-measure

preserving.

(b)

Let A be a subset of

X!

which is invariant under T and whose m measure satisfies

0<

ml(A

<1.

Let

B S(A). Then B is an invariant set under H because

H(B) H$(A) ST(A) S(A) B. Also

ml(A m2(S(A)) m2(B)

sothat0<

m2(B

<1.

But,

since

H isergodic, this isimpossible.

Hence

there cannotexist anyset Asatisfyingboth T(A)=A and 0<

ml(A)

<1. This shows that T isergodic withrespectto the m measure and theproofof the

lemmaiscomplete.

Wenow return tothe particular applicationinhand. AswehavealreaAy remarked,when

B

is not arational multiple of

=

thetransformation

HB

of[0,2=)onto itselfisergodic withrespect to Lebesgue probability measure m and preserves this measure.

To

apply the

Lemma

we let

Xl_--l,X2--[0,2r),m2=m (Lebesgue

probability

measure), H=_H[3

and S--the $ of the

application. Itremainstofindm sothat

ml(E

m(S(E)) whenever EC Write _=$(z) ar sothat i

z--6

By

differentiationwefindthat

d -"6 (z-o)(z-"6)dz sothat ifECII_=[-,) then

Since and"6 arethezerosof

cz2+

(d-a)z-bthislatterintegralcanbere-written inanobvious wayandso wefindthat therequired

ml-measure

isgivenby

K dz

ml(E)=

Ef3[-x,oo)

cz2+(d_a)z_b with Kchosen to make thisaprobabilitymeasure.

Applying the Lemma we see that the transformation Tpreserves this measureand is ergodic withrespectto it.

Finally, knowing this, we can apply the Individual Ergodic Theorem

[1]

to conclude the following:

THEOREM.

Let T(z)=az

+

b(ad-bc 1:c 0) map theextendedrealaxisItonto itself and let cz+d

it have a pair ofcomplex conjugatefixed points. Ifa,b,c,d are such as to make

B

in

(2)

not a

rationalmultiple of then,for almost allz

(in

them sense

*),

thesequencedefinedby ,+b (.= 1,2,...) (d-b,= 1,0)

Zn +

czn

+

d willhave thepropertystatedin

(1)

above.

NOTE: *By

referring to the definition ofm measureabove, "almost allinthem

sense"

canbe seentobe equivalent to "almost allinthesenseofLebesguemeasure on

REFERENCES

1.

PARRY,

W.,TopicsinErgodic Theory, CambridgeUniv.

Press,

1981.

参照

関連したドキュメント

Now let y be an arbitrary point in TK n. Then for arbitrary &gt; 0 there exists a point y’ in KF.. Now suppose that T and have a second common fixed pcint w&#34;. This completes

[6] Diamandescu, A.: Ψ - bounded solutions for linear differential systems with Lebesgue Ψ-integrable functions on R as right-hand sides, Electronic Journal of Differential

Let us suppose that the first batch of P m has top-right yearn, and that the first and second batches of P m correspond to cells of M that share a row.. Now consider where batch 2

On the other hand, suppose that X is a 1–dimensional, stable random variable and let Y (1) be the infinitely divisible vector whose L´evy measure is the L´evy measure of X truncated