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COEFFICIENT INEQUALITIES FOR CERTAIN ANALYTIC FUNCTIONS
JUNICHI NISHIWAKI and SHIGEYOSHI OWA Received 1 March 2001
For realα (α >1), we introduce subclassesM(α)andN(α)of analytic functionsf (z)with f (0)=0 andf(0)=1 inU. The object of the present paper is to consider the coefficient inequalities for functionsf (z)to be in the classesM(α)andN(α). Further, the bounds ofαfor functionsf (z)to be starlike inUare considered.
2000 Mathematics Subject Classification: 30C45.
1. Introduction. LetAdenote the class of functionsf (z)of the form f (z)=z+
∞ n=2
anzn (1.1)
which are analytic in the open unit diskU= {z∈C:|z|<1}. LetM(α)be the subclass ofAconsisting of functionsf (z)which satisfy
Re
zf(z) f (z)
< α (z∈U) (1.2)
for someα (α >1). And letN(α)be the subclass ofAconsisting of functionsf (z) which satisfy
Re
1+zf(z) f(z)
< α (z∈U) (1.3)
for someα (α >1). Then, we see thatf (z)∈N(α)if and only ifzf(z)∈M(α). We give examples of functionsf (z)in the classesM(α)andN(α).
Remark 1.1. For 1< α≤4/3, the classes M(α)and N(α) were introduced by Uralegaddi et al. [2].
Example1.2. (i)f (z)=z(1−z)2(α−1)∈M(α).
(ii) g(z)=(1/(2α−1)){1−(1−z)2α−1} ∈N(α).
Proof. Sincef (z)∈M(α)if and only if Re
zf(z) f (z)
< α, (1.4)
we can write
α−zf(z)/f (z) α−1 =1+z
1−z, (1.5)
which is equivalent to
f(z) f (z)−1
z=2(α−1)
1−z . (1.6)
Integrating both sides of the above equality, we have
f (z)=z(1−z)2(α−1)∈M(α). (1.7) Next, sinceg(z)∈N(α)if and only ifzg(z)∈M(α),
zg(z)=z(1−z)2(α−1). (1.8) For functiong(z)∈N(α), it follows that
g(z)= − 1
2α−1(1−z)2α−1+ 1
2α−1= 1 2α−1
1−(1−z)2α−1
∈N(α). (1.9)
2. Coefficient inequalities for the classesM(α)andN(α). We try to derive suffi- cient conditions forf (z)which are given by using coefficient inequalities.
Theorem2.1. Iff (z)∈Asatisfies ∞
n=2
(n−1)+|n−2α+1|an≤2(α−1) (2.1)
for someα (α >1), thenf (z)∈M(α).
Proof. Suppose that ∞ n=2
(n−1)+|n−2α+1|an≤2(α−1) (2.2)
forf (z)∈A.
It suffices to show that
zf(z)/f (z)−1 zf(z)/f (z)−(2α−1)
<1 (z∈U). (2.3)
We have
zf(z)/f (z)−1 zf(z)/f (z)−(2α−1)
≤
∞
n=2(n−1)an|z|n−1 2(α−1)−∞
n=2|n−2α+1|an|z|n−1
<
∞
n=2(n−1)an 2(α−1)−∞
n=2|n−2α+1|an.
(2.4)
The last expression is bounded above by 1 if ∞
n=2
(n−1)an≤2(α−1)− ∞ n=2
|n−2α+1|an (2.5) which is equivalent to condition (2.1). This completes the proof of the theorem.
By usingTheorem 2.1, we have the following corollary.
Corollary2.2. Iff (z)∈Asatisfies ∞
n=2
n
(n−1)+|n−2α+1|an≤2(α−1) (2.6) for someα (α >1), thenf (z)∈N(α).
Proof. Fromf (z)∈N(α)if and only ifzf(z)∈M(α), replacinganbynanin Theorem 2.1we have the corollary.
In view ofTheorem 2.1andCorollary 2.2, if 1< α≤3/2, thenn−2α+1≥0 for all n≥2. Thus we have the following corollary.
Corollary2.3. (i) Iff (z)∈Asatisfies ∞
n=2
(n−α)an≤α−1 (2.7)
for someα (1< α≤3/2), thenf (z)∈M(α).
(ii) Iff (z)∈Asatisfies ∞ n=2
n(n−α)an≤α−1 (2.8)
for someα (1< α≤3/2), thenf (z)∈N(α).
3. Starlikeness for functions inM(α)andN(α). By Silverman [1], we know that if f (z)∈Asatisfies
∞ n=2
nan≤1, (3.1)
thenf (z)∈S∗, whereS∗ denotes the subclass ofAconsisting of all univalent and starlike functionsf (z)inU. Thus we have the following theorem.
Theorem3.1. Iff (z)∈Asatisfies ∞ n=2
(n−α)an≤α−1 (3.2)
for some α (1< α≤4/3), then f (z)∈S∗∩M(α), therefore, f (z)is starlike inU.
Further, iff (z)∈Asatisfies ∞ n=2
n(n−α)an≤α−1 (3.3)
for someα (1< α≤3/2), thenf (z)∈S∗∩N(α), therefore,f (z)is starlike inU.
Proof. Considerαsuch that ∞ n=2
nan≤ ∞ n=2
n−α
α−1an≤1. (3.4)
Then we havef (z)∈S∗∩M(α)by means ofTheorem 2.1. This inequality holds true if n≤n−α
α−1 (n=2,3,4,...). (3.5)
Therefore, we have
1< α≤2− 2
n+1 (n=2,3,4,...), (3.6) which shows that 1< α≤4/3. Next, consideringαsuch that
∞ n=2
nan≤ ∞ n=2
n(n−α)
α−1 an≤1, (3.7)
we have
n≤n(n−α)
α−1 (n=2,3,4,...), (3.8)
which is equivalent to
1< α≤n+1
2 (n=2,3,4,...). (3.9)
This implies that 1< α≤3/2.
Finally, by virtue of the result for convex functions by Silverman [1], we have, if f (z)∈Asatisfies
∞ n=2
n2an≤1, (3.10)
then f (z)∈K, where K denotes the subclass ofA consisting of all univalent and convex functionsf (z)inU. Using the same method as in the proof ofTheorem 3.1, we derive the following theorem.
Theorem3.2. Iff (z)∈Asatisfies ∞ n=2
n(n−α)an≤α−1 (3.11)
for someα (1< α≤4/3), thenf (z)∈K∩N(α), therefore,f (z)is convex inU.
4. Bounds ofαfor starlikeness. Note that the sufficient condition forf (z)to be in the classM(α)is given by
∞ n=2
(n−1)+|n−2α+1|an≤2(α−1). (4.1)
Since, iff (z)∈Asatisfies
∞ n=2
nan≤1, (4.2)
thenf (z)∈S∗(cf. [1]). It is interesting to find the bounds ofαfor starlikeness of f (z)∈M(α). To do this, we have to consider the following inequality:
∞ n=2
nan≤ 1 2(α−1)
∞ n=2
(n−1)+|n−2α+1|an≤1 (4.3)
which is equivalent to ∞ n=2
|n−2α+1|+(3−2α)nan≥0. (4.4)
We define
F(n)= |n−2α+1|+(3−2α)n (n≥2). (4.5) Then, ifF(n)satisfies
∞ n=2
F(n)an≥0, (4.6)
thenf (z)belongs toS∗.
Theorem4.1. Letf (z)∈Asatisfy ∞
n=2
(n−1)+|n−2α+1|an≤2(α−1) (4.7)
for someα >1. Further, letδkbe defined by δk=
∞ n=k
F(n)an. (4.8)
Then,
(i) if1< α≤3/2, thenf (z)∈S∗,
(ii) if3/2≤α≤min(13/8,(3+δ3)/2), thenf (z)∈S∗, (iii) if8/3≤α≤min(17/10,(12−δ4+
δ24+48δ4+48)/12), thenf (z)∈S∗. Proof. For 1< α≤3/2, we know that
n−2α+1≥3−2α≥0 (n≥2), (4.9) that is,F(n)≥0(n≥2). Therefore, we have
∞ n=2
F(n)an≥0. (4.10)
If 3/2≤α≤13/8, thenF(2)=3−2α≤0 and
F(n)=2n(2−α)+1−2α≥13−8α≥0 (4.11)
forn≥3. Further, we know that
an≤ 2(α−1)
(n−1)+|n−2α+1| (n≥2), (4.12) then|a2| ≤1. Therefore, we obtain that
∞ n=2
F(n)an=F(2)a2+ ∞ n=3
F(n)an≥3−2α+δ3≥0 (4.13) for
3
2≤α≤min 13 8 ,3+δ3
2
. (4.14)
Furthermore, if 13/8≤α≤17/10, then F(2)=3−2α≤0,
F(3)= |4−2α|+3(3−2α)=13−8α≤0,
F(n)= |n−2α+1|+(3−2α)n=4n+1−2(n+1)α≥3(n−4)
5 ≥0
(4.15)
forn≥4. Noting that|a2| ≤1 and|a3| ≤(α−1)/(3−α), we conclude that ∞
n=2
F(n)an=F(2)a2+F(3)a3+ ∞ n=4
F(n)an
≥(3−2α)+(13−8α)α−1
3−α+δ4≥0,
(4.16)
forαthat satisfies
6α2− 12−δ4
α+4−3δ4≤0. (4.17)
This shows that 8
3≤α≤min
17
10,12−δ4+
δ24+48δ4+48 12
. (4.18)
This completes the proof ofTheorem 4.1.
Finally, by virtue ofTheorem 4.1, we may suppose that iff (z)∈Asatisfies ∞
n=2
(n−1)+|n−2α+1|an≤2(α−1) (4.19)
for some 1< α <2, thenf (z)∈S∗.
References
[1] H. Silverman,Univalent functions with negative coefficients, Proc. Amer. Math. Soc.51 (1975), 109–116.
[2] B. A. Uralegaddi, M. D. Ganigi, and S. M. Sarangi,Univalent functions with positive coeffi- cients, Tamkang J. Math.25(1994), no. 3, 225–230.
Junichi Nishiwaki and Shigeyoshi Owa: Department of Mathematics, Kinki Univer- sity, Higashi-Osaka, Osaka577-8502, Japan
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