volume 5, issue 3, article 52, 2004.
Received 23 September, 2003;
accepted 29 November, 2003.
Communicated by:D. Bainov
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Journal of Inequalities in Pure and Applied Mathematics
THE ULAM STABILITY PROBLEM IN APPROXIMATION OF APPROXIMATELY QUADRATIC MAPPINGS BY
QUADRATIC MAPPINGS
JOHN MICHAEL RASSIAS
Pedagogical Department, E. E.,
National and Capodistrian University of Athens, Section of Mathematics and Informatics, 4, Agamemnonos Str., Aghia Paraskevi, Athens 15342, Greece.
EMail:jrassias@primedu.uoa.gr URL:http://www.primedu.uoa.gr/ jrassias/
c
2000Victoria University ISSN (electronic): 1443-5756 165-03
The Ulam Stability Problem In Approximation Of Approximately Quadratic
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Abstract
S.M. Ulam, 1940, proposed the well-known Ulam stability problem and in 1941, the problem for linear mappings was solved by D.H. Hyers. D.G. Bourgin, 1951, also investigated the Ulam problem for additive mappings. P.M. Gru- ber, claimed, in 1978, that this kind of stability problem is of particular interest in probability theory and in the case of functional equations of different types.
F. Skof, in 1981, was the first author to solve the Ulam problem for quadratic mappings. During the years 1982-1998, the author established the Hyers-Ulam stability for the Ulam problem for different mappings. In this paper we solve the Ulam stability problem by establishing an approximation of approximately quadratic mappings by quadratic mappings. Today there are applications in actuarial and financial mathematics, sociology and psychology, as well as in algebra and geometry.
2000 Mathematics Subject Classification:39B
Key words: Ulam problem, Ulam type problem, General Ulam problem, Quadratic mapping, Approximately quadratic mapping, Square of the quadratic weighted mean.
Contents
1 Introduction. . . 3 2 Quadratic Functional Stability. . . 9
References
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1. Introduction
S.M. Ulam [24] proposed the general Ulam stability problem: "When is it true that by slightly changing the hypotheses of a theorem one can still assert that the thesis of the theorem remains true or approximately true?" D.H. Hyers [13]
solved this problem for linear mappings. D.G. Bourgin [3] also investigated the Ulam problem for additive mappings. P.M. Gruber [12] claimed that this kind of stability problem is of particular interest in probability theory and in the case of functional equations of different types. Th.M. Rassias [20] employed Hyers’ ideas to new additive mappings, and later I. Fenyö ([7], [8]) established the stability of the Ulam problem for quadratic and other mappings. Z. Gajda and R. Ger [10] showed that one can obtain analogous stability results for sub- additive multifunctions. Other interesting stability results have been achieved also by the following authors: J. Aczél [1], C. Borelli and G.L. Forti ([2], [9]), P.W. Cholewa [4], St. Czerwik [5], H. Drljevic [6] and L. Paganoni [14]. F.
Skof ([21] – [23]) was the first author to solve the Ulam problem for quadratic mappings. We ([15] – [19]) solved the above Ulam problem for different map- pings. P. Gˇavru¸tˇa [11] answered a question of ours [17] concerning the stability of the Cauchy equation. Today there are applications in actuarial and financial mathematics, sociology and psychology, as well as in algebra and geometry.
In this paper we introduce the following quadratic functional equation (∗) Q(a1x1+a2x2) +Q(a2x1−a1x2) = a21+a22
[Q(x1) +Q(x2)]
with quadratic mappings Q : X → Y such that X and Y are real linear spaces.
Denote
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J. Ineq. Pure and Appl. Math. 5(3) Art. 52, 2004
Kr =Kr(kx1k,kx2k)
=
2r−1(kx1kr+kx2kr)−(kx1+x2kr+kx1−x2kr)
=
( 2r−1(kx1kr+kx2kr)−(kx1+x2kr+kx1−x2kr), ifr >2 kx1+x2kr+kx1−x2kr−2r−1(kx1kr+kx2kr), if1< r <2, for every(x1, x2) ∈ X2, whereX is a normed linear space. Note thatKr ≥ 0 for any fixed realr : 1< r6= 2.Note also that
Kr =Kr(kxk,kxk) = 0, Kr(|a1| kxk,|a2| kxk) =β1kxkr, Kr m−1|a1| kxk, m−1|a2| kxk
=β1m−rkxkr, Kr(kxk,0) =β2kxkr and Kr m−1kxk,0
=β3kxkr, where
β1 =Kr(|a1|,|a2|)
=
2r−1(|a1|r+|a2|r)−(|a1+a2|r+|a1 −a2|r)
=
( 2r−1(|a1|r+|a2|r)−(|a1+a2|r+|a1−a2|r), ifr >2
|a1+a2|r+|a1−a2|r−2r−1(|a1|r+|a2|r), if1< r <2, β2 =Kr(1,0) =
2r−1−2 =
( 2r−1−2, ifr >2 2−2r−1, if1< r <2,
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β3 =Kr m−1,0
=β2m−r, Note thata1 6=a2, and16=m=a21+a22 >0.
IfX andY are normed linear spaces andY complete, then we establish an approximation of approximately quadratic mappingsf : X → Y by quadratic mappings Q : X → Y, such that the corresponding approximately quadratic functional inequality
(∗∗)
f(a1x1+a2x2) +f(a2x1−a1x2)− a21+a22
[f(x1) +f(x2)]
≤cKr(kx1k,kx2k) holds with a constant c ≥ 0 (independent ofx1,x2 ∈ X), and any fixed pair a = (a1, a2)∈R2− {(0,0)}and any fixed realr >1 :
I1 ={(r, m)∈R2 : 1< r <2, m >1 and r >2,0< m <1},or I2 ={(r, m)∈R2 : 1< r <2,0< m <1 and r >2, m >1},
hold, where1 6=m =a21 +a22 =|a|2 >0anda1 6= a2. Note thatmr−2 <1if (r, m)∈I1, andm2−r <1if(r, m)∈I2.
It is useful for the following, to observe that, from (∗) withx1 =x2 = 0, and 0< m6= 1we get
2(m−1)Q(0) = 0, or
(1.1) Q(0) = 0.
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Definition 1.1. Let XandY be real linear spaces. Let a = (a1, a2) ∈ R2 − {(0,0)} : 0 < m=a21 +a22 6= 1anda1 6=a2. Then a mappingQ :X →Y is called quadratic with respect toa, if (∗) holds for every vector(x1, x2)∈X2. Definition 1.2. Let XandY be real linear spaces. Let a = (a1, a2) ∈ R2 − {(0,0)} : 0 < m = a21 +a22 6= 1anda1 6= a2. Then a mapping Q¯ : X → Y is called the square of the quadratic weighted mean of Q with respect toa = (a1, a2), if
(1.2) Q(x)¯
=
Q(a1x)+Q(a2x)
a21+a22 , if (r, m=a21+a22)∈I1
(a21+a22)h Q
a1
a21+a22x +Q
a2
a21+a22xi
, if (r, m=a21+a22)∈I2 for allx∈X.
For everyx∈RsetQ(x) = x2. Then the mappingQ¯ :R→Ris quadratic, such thatQ¯(x) =x2. Denoting by
q
x2w the quadratic weighted mean, we note that the above-mentioned mappingQis an analogous case to the square of the quadratic weighted mean employed in mathematical statistics: x2w = a21xa212+a22x22
1+a22
with weightsw1 =a21 andw2 = a22, datax1 =x2 = x, andQ(aix) = (aix)2, (i= 1,2).
Now, claim that forn ∈N0 ={0,1,2, . . .}that
(1.3) Q(x) =
( m−2nQ(mnx), if (r, m)∈I1 m2nQ(m−nx), if (r, m)∈I2,
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for allx∈Xandn ∈N0.
Forn = 0, it is trivial. From (1.1), (1.2) and (∗), withxi =aix (i = 1,2), we obtain
Q(mx) = m[Q(a1x) +Q(a2x)], or
(1.4) Q(x) =¯ m−2Q(mx),
ifI1holds. Besides from (1.1), (1.2) and (∗), withx1 =x,x2 = 0, we get Q(a1x) +Q(a2x) =mQ(x),
or
(1.5) Q(x) =¯ Q(x),
ifI1holds. Therefore from (1.4) and (1.5) we have
(1.6) Q(x) =m−2Q(mx),
which is (1.3) forn = 1, ifI1 holds. Similarly, from (1.1), (1.2) and (∗), with xi = amix (i= 1,2), we obtain
(1.7) Q(x) = ¯Q(x)
ifI2holds. Besides from (1.1), (1.2) and (∗), withx1 = mx,x2 = 0,we get Qa1
mx
+Qa2
mx
=mQ(m−1x),
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or
(1.8) Q(x) =¯ m2Q(m−1x)
ifI2holds. Therefore from (1.7) and (1.8) we have
(1.9) Q(x) = m2Q(m−1x),
which is (1.3) forn = 1, ifI2 holds.
Assume (1.3) is true and from (1.6), withmnxin place ofx, we get:
(1.10) Q mn+1x
=m2Q(mnx) =m2(mn)2Q(x) = mn+12
Q(x).
Similarly, withm−nxin place ofx, we get:
Q m−(n+1)x
=m−2Q(m−nx) (1.11)
=m−2(m−n)2Q(x) = m−(n+1)2
Q(x).
These formulas (1.10) and (1.11) by induction, prove formula (1.3).
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2. Quadratic Functional Stability
Theorem 2.1. Let X and Y be normed linear spaces. Assume thatY is com- plete. Assume in addition that mapping f : X → Y satisfies the functional inequality (∗∗). Define I1 = {(r, m) ∈ R2 : 1 < r < 2, m > 1, or r > 2, 0 < m < 1}, and I2 = {(r, m) ∈ R2 : 1 < r < 2, 0 < m < 1, orr >2, m >1}for any fixed paira = (a1, a2)of realsai 6= 0 (i= 1,2)and any fixed realr >1 : 16=m=a21+a22 =|a|2 >0,a1 6=a2. Besides define
0< β1 =Kr(|a1|,|a2|)
=
2r−1(|a1|r+|a2|r)−(|a1+a2|r+|a1−a2|r)
=
( 2r−1(|a1|r+|a2|r)−(|a1+a2|r+|a1−a2|r), ifr >2
|a1+a2|r+|a1−a2|r−2r−1(|a1|r+|a2|r), if1< r <2, β2 =Kr(1,0) = |2r−1−2|, andσ =β1+mβ2 >0. Also define
fn(x) =
( m−2nf(mnx), if(r, m)∈I1
m2nf(m−nx), if(r, m)∈I2 for allx∈X andn∈N0 ={0,1,2, . . .}.
Then the limit
(2.1) Q(x) = lim
n→∞fn(x)
exists for all x ∈ X and Q : X → Y is the unique quadratic mapping with
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respect toa = (a1, a2), such that kf(x)−Q(x)k ≤ σc
|m2−mr|kxkr (2.2)
=kxkr
( σc/(m2−mr), if(r, m)∈I1
σc/(mr−m2), if(r, m)∈I2
holds for allx∈X andn ∈N0andc≥0(constant independent ofx∈X).
Existence.
Proof. It is useful for the following, to observe that, from (∗∗) withx1 =x2 = 0 and0< m6= 1, we get
2|m−1| kf(0)k ≤0, or
(2.3) f(0) = 0.
Now claim that forn ∈N0 kf(x)−fn(x)k (2.4)
≤ σc
|m2−mr| 1−mn|r−2|
kxkr
=kxkr
σc
m2−mr 1−mn(r−2)
, if (r, m)∈I1 :mr−2 <1
σc
mr−m2 1−mn(2−r)
, if (r, m)∈I2 :m2−r <1.
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Forn= 0,it is trivial.
Definef¯: X → Y, the square of the quadratic weighted mean of f with respect to a = (a1, a2) by replacingQ, Q¯ of (1.2) with f, f, respectively, as¯ follows:
(2.5) f(x)¯
=
f(a1x)+f(a2x)
a21+a22 , if(r, m=a21+a22 =|a|2)∈I1 (a21+a22)h
f
a1
a21+a22x +f
a2
a21+a22xi
, if(r, m=a21+a22 =|a|2)∈I2 for allx∈X.
From (2.3), (2.5) and (∗∗), withxi =aix(i= 1,2), we obtain kf(mx)−m[f(a1x)+f(a2x)]k ≤σckxkr, or
(2.6)
m−2f(mx)−f(x)¯
≤ β1c m2 kxkr,
ifI1holds. Besides from (2.3), (2.5) and (∗∗), withx1 =x,x2 = 0, we get kf(a1x)+f(a2x)−mf(x)k ≤cKr(kxk,0) =β2ckxkr, or
(2.7)
f(x)−f¯ (x)
≤ β2c m kxkr,
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ifI1holds. Therefore from (2.6) and (2.7) we have
(2.8)
f(x)−m−2f(mx) ≤ σc
m2 kxkr = σc
m2−mr 1−mr−2 kxkr, which is (2.4) forn = 1, ifI1 holds.
Similarly, from (2.3), (2.5) and (∗∗), withxi = amix(i= 1,2), we obtain
(2.9)
f(x)−f¯(x)
≤ β1c mr kxkr,
ifI2holds. Besides from (2.3), (2.5) and (∗∗), withx1 = mx,x2 = 0, we get
fa1
mx
+fa2 mx
−mf(m−1x)
≤cKr m−1kxk,0
=β3ckxkr, or
(2.10)
f¯(x)−m2f(m−1x)
≤mβ3ckxkr = mβ2c mr kxkr, ifI2holds. Therefore from (2.9) and (2.10) we have
(2.11)
f(x)−m2f(m−1x) ≤ σc
mr kxkr = σc
mr−m2 1−m2−r kxkr, which is (2.4) forn = 1, ifI2 holds.
Assume (2.4) is true if(r, m)∈I1. From (2.8), withmnxin place ofx, and
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the triangle inequality, we have kf(x)−fn+1(x)k (2.12)
=
f(x)−m−2(n+1)f mn+1x
≤
f(x)−m−2nf(mnx) +
m−2nf(mnx)−m−2(n+1)f mn+1x
≤ σc m2−mr
1−mn(r−2)
+m−2n 1−mr−2 mnr
kxkr
= σc
m2−mr 1−m(n+1)(r−2) kxkr, ifI1holds.
Similarly assume (2.4) is true if (r, m) ∈ I2. From (2.11), with m−nx in place ofx, and the triangle inequality, we have
kf(x)−fn+1(x)k (2.13)
=
f(x)−m2(n+1)f m−(n+1)x
≤
f(x)−m2nf m−nx +
m2nf(m−nx)−m2(n+1)f m−(n+1)x
≤ σc mr−m2
(1−mn(2−r))+m2n(1−m2−r)m−nr kxkr
= σc
mr−m2 1−m(n+1)(2−r) kxkr, ifI2holds.
Therefore inequalities (2.12) and (2.13) prove inequality (2.4) for anyn ∈ N0.
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Claim now that the sequence {fn(x)} converges. To do this it suffices to prove that it is a Cauchy sequence. Inequality (2.4) is involved if(r, m) ∈ I1. In fact , ifi > j >0, andh1 =mjx, we have:
kfi(x)−fj(x)k=
m−2if(mix)−m−2jf(mjx) (2.14)
=m−2j
m−2(i−j)f mi−jh1
−f(h1)
≤m−2j σc
m2−mr 1−m(i−j)(r−2) kxkr
< σc
m2−mrm−2jkxkr −−−→
j→∞ 0, ifI1holds: mr−2 <1.
Similarly, ifh2 =m−jxinI2, we have:
kfi(x)−fj(x)k=
m2if(m−ix)−m2jf(m−jx) (2.15)
=m2j
m2(i−j)f m−(i−j)h2
−f(h2)
≤m2j σc
mr−m2 1−m(i−j)(2−r) kxkr
< σc
mr−m2m2jkxkr −−−→
j→∞ 0,
ifI2holds: m2−r <1.
Then inequalities (2.14) and (2.15) define a mappingQ: X →Y, given by (2.1).
Claim that from (∗∗) and (2.1) we can get (∗), or equivalently that the afore- mentioned well-defined mappingQ:X →Y is quadratic.
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In fact, it is clear from the functional inequality (∗∗) and the limit (2.1) for (r, m)∈I1 that the following functional inequality
m−2nkf(a1mnx1+a2mnx2) +f(a2mnx1−a1mnx2)
−(a21+a22) [f(mnx1) +f(mnx2)]
≤m−2ncKr(mnkx1k, mnkx2k), holds for all vectors(x1, x2)∈X2, and alln ∈Nwithfn(x) =m−2nf(mnx) : I1 holds. Therefore
lim
n→∞fn(a1x1+a2x2) + lim
n→∞fn(a2x1−a1x2)
−(a21+a22)h
n→∞lim fn(x1) + lim
n→∞fn(x2)i
≤
n→∞lim mn(r−2)
cKr(kx1k,kx2k) = 0, becausemr−2 <1or
(2.16)
Q(a1x1+a2x2)+Q(a2x1−a1x2)− a21+a22
[Q(x1)+Q(x2)]
= 0, or mappingQsatisfies the quadratic equation (∗).
Similarly, from (∗∗) and (2.1) for(r, m)∈I2we get that m2n
f(a1m−nx1+a2m−nx2)+f(a2m−nx1−a1m−nx2)
−(a21+a22)
f(m−nx1)+f(m−nx2)
≤m2ncKr m−nkx1k, m−nkx2k ,
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holds for all vectors(x1, x2)∈X2, and alln ∈Nwithfn(x) =m2nf(m−nx) : I2 holds. Thus
lim
n→∞fn(a1x1+a2x2)+ lim
n→∞fn(a2x1−a1x2)
−(a21+a22) h
n→∞lim fn(x1)+ lim
n→∞fn(x2)i
≤
n→∞lim mn(2−r)
cKr(kx1k,kx2k) = 0, becausem2−r <1, or (2.16) holds or mappingQsatisfies (∗).
Therefore (2.16) holds ifIj (j = 1,2)hold or mappingQsatisfies (∗), com- pleting the proof thatQis a quadratic mapping inX.
It is now clear from (2.4) with n → ∞, as well as formula (2.1) that (2.2) holds inX. This completes the existence proof of the above Theorem2.1.
Uniqueness
LetQ0 :X →Y be a quadratic mapping satisfying (2.2), as well asQ. Then Q0 =Q.
Proof. Remember both Q and Q0 satisfy (1.3) for (r, m) ∈ I1, too. Then for everyx∈Xandn∈N,
kQ(x)−Q0(x)k (2.17)
=
m−2nQ(mnx)−m−2nQ0(mnx)
≤m−2n{kQ(mnx)−f(mnx)k+kQ0(mnx)−f(mnx)k}
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≤m−2n 2σc
m2−mr kmnxkr
=mn(r−2) 2σc
m2−mr kxkr→0, asn→ ∞, ifI1holds: mr−2 <1.
Similarly for(r, m)∈I2, we establish kQ(x)−Q0(x)k
(2.18)
=
m2nQ(m−nx)−m2nQ0(m−nx)
≤m2n
Q(m−nx)−f(m−nx) +
Q0(m−nx)−f(m−nx)
≤m2n 2σc mr−m2
m−nx
r
=mn(2−r) 2σc
mr−m2kxkr →0, asn→ ∞, ifI2holds: m2−r <1.
Thus from (2.17), and (2.18) we findQ(x) = Q0(x)for allx∈X.
This completes the proof of the uniqueness and stability of equation (∗).
Open Problem. What is the situation in the above Theorem2.1in caser= 2?
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References
[1] J. ACZÉL, Lectures on Functional Equations and Their Applications, Academic Press, New York and London, 1966.
[2] C. BORELLIANDG.L. FORTI, On a general Hyers-Ulam stability result, Internat. J. Math. Math. Sci., 18 (1995), 229–236.
[3] D.G. BOURGIN, Classes of transformations and bordering transforma- tions, Bull. Amer. Math. Soc., 57 (1951),223-237 .
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