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Volume 2007, Article ID 27626,14pages doi:10.1155/2007/27626

Research Article

On Relative Homotopy Groups of Modules

C. Joanna Su

Received 10 May 2007; Accepted 16 August 2007 Recommended by M ´onica Clapp

In his book “Homotopy Theory and Duality,” Peter Hilton described the concepts of relative homotopy theory in module theory. We study in this paper the possibility of parallel concepts of fibration and cofibration in module theory, analogous to the exist- ing theorems in algebraic topology. First, we discover that one can study relative homo- topy groups, of modules, from a viewpoint which is closer to that of (absolute) homo- topy groups. Then, through the study of various cases, we learn that the classic fibra- tion/cofibration relation does not come automatically. Nonetheless, the ability to see the relative homotopy groups as absolute homotopy groups, in a stronger sense, promises to justify our ultimate search.

Copyright © 2007 C. Joanna Su. This is an open access article distributed under the Cre- ative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

1. Introduction

In [1], Peter Hilton developed homotopy theory in module theory, parallel to the existing homotopy theory in topology. However, unlike homotopy theory in topology, there are two types of homotopy theory in module theory, the injective theory and the projective theory. They are dual but not isomorphic. In this paper, we emphasize the injective rela- tive homotopy groups (of modules) and approach the proofs in a way that does not refer to elements of sets, so one can proceed with the dual, in projective relative homotopy theory, without further arguments.

During the search for the analogy between the relative homotopy groups in module theory and those in topology, we realize that the (injective) relative homotopy group, πn(A,β),n1, for a mapβ:B1B2 has a structure which is fairly similar to an (in- jective) absolute homotopy group, namely,πn(A, coker{ι,β}), whereι:B1CB1is the

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inclusion ofB1into an injective containerCB1that induces a short exact sequence:

B1 {ι,β}

CB1B2 coker{ι,β}. (1.1)

Thereafter, we analyze the phenomena related πn(A,β) and πn(A, coker{ι,β}) through cases. As expected, the two are not always isomorphic; nevertheless, the fact that all rela- tive homotopy groups are isomorphic to certain “strong (absolute) homotopy groups” gives rise to the possibility of developing parallel concepts of fibration and cofibration in pro- jective and injective homotopy theories, respectively, in module theory, corresponding to the existing fibration/cofibration relation in algebraic topology.

2. Relative homotopy groups—from a different viewpoint

In the injective relative homotopy theory of modules, for a givenΛ-module homomor- phism β:B1B2 and a givenΛ-moduleA, one computes thenth relative homotopy group,πn(A,β),n1, through the diagram

0 Σn1A ιn1

ρ

n1A n

σ

ΣnA

kerβ B1

β B2 cokerβ

(2.1)

whereι0 is the inclusion map which embedsAinto an injective containerCA, and1

is the quotient map to ΣA, called the suspension of A, as the quotient. We say that the map (ρ,σ) :ιn1βisi-nullhomotopic, denoted (ρ,σ)i0, if it can be extended to an injective container ofιn1, and thatπn(A,β)=Hom(ιn1,β)/Hom0n1,β), where Hom(ιn1,β) is the abelian group of maps ofιn1toβ, and Hom0n1,β) the subgroup consisting ofi-nullhomotopic maps.

The computation of such diagrams, as (2.1), is rather challenging at times, especially during the search for suitable definitions of fibration and cofibration in module theory, analogous to those in topology. Therefore we examine the diagram, of relative homotopy groups, from another viewpoint: First assuming that the mapβ:B1B2is monomor- phic so (2.1) is essentially

Σn1A ιn1

ρ

n1A n

σ

ΣnA

σ

B1

β B2 κ cokerβ.

(2.2)

In (2.2), each pair of maps (ρ,σ) :ιn1βinduces a map σnAcokerβ. We de- fine RHomΛnA, cokerβ) to be the subgroup of HomΛnA, cokerβ) consisting of such induced maps; it gives the relative homotopy groupπn(A,β) an alternative aspect.

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Theorem 2.1. Suppose given a monomorphismβ:B1B2. For eachA, consider the dia- gram

Σn1A ιn1

ρ

n1A n

σ

ΣnA

σ ιn

nA B1

β B2 κ cokerβ

(2.3)

whereι0:ACAis the inclusion ofAinto an injective containerCA,1the quotient map withΣA, called the suspension ofA, as the quotient, andκthe expected quotient map. Then,

πn(A,β)=RHomΛ

ΣnA, cokerβκιnHomΛ

nA,B2

, (2.4)

where

RHomΛΣnA, cokerβ

=

σHomΛΣnA, cokerβ|σ is the induced map of a commutative square Σn1A ιn1

ρ

n1A

σ

B1

β B2

. (2.5)

To prepare for the proof ofTheorem 2.1, we first state a couple of existing propositions.

Proposition 2.2 ([2]). In Hom(ιn1,β), whenβis monomorphic, (ρ,σ)i0 if and only if σ=βθ+χιnnfor someθ:n1AB1andχ:nAB2;

Σn1A ιn1

ρ

n1A

θ

n

σ

ΣnAσ ιn nA

χ

B1

β B2 κ cokerβ

(2.6)

Proposition 2.3 [1]. In the commutative diagram of short exact sequences:

A μ

α

B

ξ

C

γ

A μ B C

(2.7)

αfactors throughμif and only ifγfactors through. Proof ofTheorem 2.1. We define

φ:πn(A,β)RHomΛΣnA, cokerβκιnHomΛnA,B2

(2.8)

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byφ([(ρ,σ)])=] and show thatφis an isomorphism; first, suppose given a [(ρ,σ)] πn(A,β) and assume that (ρ,σ)i0. By Proposition 2.2, σ =βθ+χιnn for some θ: n1AB1 and χ:nAB2. Thus, σn=κσ=κ(βθ+χιnn)=κβθ+κχιnn= κχιnn, soσ=κχιn, due to the fact thatnis surjective. Hence,σκιnHomΛ(nA,B2) andφis well defined.

To prove φ monomorphic, suppose given a [(ρ,σ)]πn(A,β) and assume that φ([(ρ,σ)])=[σ]=0RHomΛnA, cokerβ)ιnHomΛ(nA,B2). That is,σ=κχιn

for someχ:nAB2, which means thatσfactors through the map κ. Then, by an immediate corollary ofProposition 2.3, namely,γ=0 if and only ifξfactors throughμ, there exists anη:n1AB1such thatσχιnn=βη;

Σn1A ιn1

ρ

n1A n

σχιnn

η

ΣnA

0

B1

β B2 κ

cokerβ

(2.9)

Hence, (ρ,σ)i0 byProposition 2.2, and thusφis monomorphic.

Finally, the definition of RHomΛnA, cokerβ) yields that eachσis induced from a commutative square

Σn1A ιn1 n1A B1

β B2

(2.10)

Thus,φis epimorphic.

We remark that one can interpret RHomΛnA, cokerβ) as the “reversible” subgroup of HomΛnA, cokerβ); suppose given a mapσHomΛnA, cokerβ), we say thatσis reversible if it can pull back and produce a commutative diagram (2.2). Furthermore, it reveals a connection between the relative homotopy groupπn(A,β) and the (absolute) homotopy groupπn(A, cokerβ).

Next, for the general case thatβ:B1B2is arbitrary, we exploit the mapping cylinder ofβandTheorem 2.5follows immediately afterProposition 2.4.

Proposition 2.4 [2]. Suppose given mapsβ:B1B2 andι:B1CB1, whereCB1is an injective container ofB1so that{ι,β}:B1CB1B2is a monomorphism, then, for arbi- traryA,πn(A,{ι,β})=πn(A,β) canonically,n1.

Theorem 2.5. Suppose givenβ:B1B2. For eachA, consider the diagram Σn1A ιn1

ρ

n1A n

σ

ΣnA ιn

σ

nA B1

{ι,β}

CB1B2 κ coker{ι,β}

(2.11)

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whereι0:ACAis the inclusion ofAinto an injective containerCA,1is the quotient map withΣA, called the suspension ofA, as the quotient,ι:B1CB1is the inclusion ofB1into an injective containerCB1, andκis the expected quotient map. Then,

πn(A,β)=RHomΛ

ΣnA, coker{ι,β}

κιnHomΛ

nA,CB1B2

, (2.12)

where

RHomΛΣnA, coker{ι,β}

=

σHomΛΣnA, coker{ι,β}

|σis the induced map of a commutative square Σn1A ιn1

ρ

n1A

σ

B1 {ι,β}

CB1B2

. (2.13)

As we mentioned earlier, our argument does not involve references to elements of sets, so one can proceed with the dual, in projective relative homotopy theory, automatically.

As an illustration, for a given Λ-module homomorphismα:A1A2 and a given Λ- moduleB, one alternatively views the projective relative homotopy groupπn(α,B),n1, as follows.

Theorem 2.6. Suppose givenα:A1A2. For eachB, consider the diagram kerα,η ι

ρ|

A1PA2 α,η ρ

A2 σ

nB ηn ΩnB μn n1B ηn1 Ωn1B

(2.14)

whereη0:PBBis the projection of a projective ancestorPBontoB,μ1 is the inclusion map withΩB, called the loop space ofB, as the kernel,η:PA2A2is the projection of a projective ancestorPA2ontoA2, andιis the expected inclusion map. Then,

πn(α,B)=RHomΛ

kerα,ηnBιηnHomΛ

A1PA2,PΩnB, (2.15) where

RHomΛkerα,ηnB

=

ρHomΛkerα,ηnB|ρ is the restriction of a commutative square A1PA2

α,η ρ

A2 σ

n1B ηn1 Ωn1B

. (2.16)

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3. Various cases forβ:B1B2

Here, we haveTheorem 2.5, which does not only give us an alternative way of computing relative homotopy groups for a mapβ:B1B2, but also shows a close connection be- tween the (injective) relative homotopy groupsπn(A,β) and the (injective) homotopy groups πn(A, coker{ι,β}). The latter indicates the possibility of developing analogous concepts of fibration and cofibration in module theory to those existing ones in algebraic topology. Before further commenting on this matter, we demonstrate a few calculations through analyzing these phenomena on RHomΛnA, coker{ι,β}).

First, we examine the case that the mapβ:B1B2is the zero map. The homotopy exact sequence of a mapβ:B1B2(see [1, Theorem 13.15]), thus,

··· πn A,B1

β

πn A,B2

J

πn(A,β) πn1

A,B1

β

···

π1

A,B1

β π1

A,B2

J

π1(A,β) πA,B1

β

πA,B2

, (3.1) yields a short exact sequence

πn A,B2

J

πn(A,β) πn1

A,B1

(3.2)

asβ=0. In addition, the special feature of the zero map suggests that (3.2) actually splits, thus, the relative homotopy groupπn(A,β) is the direct sum of the other two.

Theorem 3.1. Assume thatβ:B1B2is the zero map. Then, for eachA, πn(A,β)=πn1

A,B1

πn A,B2

, canonically, n1. (3.3) Before proceeding with its proof, we note that the theorem can also be derived using the conventional method, namely, computeπn(A,β) through the commutative square

Σn1A ιn1 n1A B1

β=0

B2

(3.4)

Proof. In diagram (2.11), thus, Σn1A ιn1

ρ

n1A n

σ

ΣnA ιn

σ

nA B1

{ι,β}

CB1B2 κ

coker{ι,β}

(3.5)

we first note that coker{ι,β} =coker{ι, 0} =ΣB1B2 and that κ= {κ1, 0,0, 1B2}, whereι:B1CB1is the inclusion ofB1into an injective containerCB1,κ1is the quotient

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map toΣB1, called the suspension ofB1, and 1B2 is the identity map onB2. So (2.11) is essentially

Σn1A ιn1

ρ

n1A n

σ={σ1,σ2}

ΣnA ιn

σ={σ12}

nA B1

{ι,0}

CB1B2 κ ΣB1B2

(3.6)

Moreover, it is the natural combination of the two commutative diagrams Σn1A ιn1

ρ

n1A n

σ1

ΣnA ιn

σ1

nA B1 ι CB1 κ1

ΣB1

(3.7)

Σn1A ιn1

ρ

n1A n

σ2

ΣnA ιn

σ2

nA B1

β=0

B2 1B2

B2

(3.8)

Thus we define

φ: RHomΛΣnA, coker{ι,β}

κιnHomΛnA,CB1B2

−→πn1

A,B1

πn A,B2

(3.9) byφ([{σ1,σ2}])=([ρ], [σ2]) and show that φis an isomorphism. First, suppose given [{σ12}]RHomΛnA, coker{ι,β})/κιnHomΛ(CΣnA,CB1B2) and assume that {σ1,σ2}∈κιnHomΛ(nA,CB1B2). Then there exists{χ1,χ2}:nACB1B2such that{σ1,σ2} =κ◦ {χ12} ◦ιn. Equivalently, one hasσ1=κ1χ1ιnin (3.7) andσ2=1B2 χ2ιn=χ2ιnin (3.8). The former says that the mapσ1factors throughκ1; therefore, by Proposition 2.3,ρ=θιn1for someθ:n1AB1. Hence [ρ]=0 inπn1(A,B1). The latter says that [σ2]=0 inπn(A,B2). Soφis well defined.

To show thatφis monomorphic, suppose given [{σ12}]RHomΛΣnA, coker{ι,β}

κιnHomΛnA,CB1B2

(3.10)

and assume thatφ([{σ1,σ2}])=([ρ], [σ2])=(0, 0)πn1(A,B1)πn(A,B2). That is,ρ= γιn1for someγ:n1AB1andσ2=ηιnfor someη:nAB2, respectively. The former says that the mapρ factors throughιn1in (3.7); therefore, byProposition 2.3, σ1=κ1τfor someτnACB1. Moreover,τ=νιnfor someν:nACB1, due to the facts thatCB1 is injective and thatιnis monomorphic. Therefore,σ1=κ1νιnand hence {σ1,σ2} = {κ1νιnιn} = {κ1νιn, 1B2ηιn} =κ◦ {ν,η} ◦ιnκιnHomΛ (nA,CB1B2).

Finally, suppose given ([ρ], [σ2])πn1(A,B1)πn(A,B2). We use the mapρto com- plete a diagram (3.7)—sinceCB1is injective andιn1is monomorphic, there exists a map

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σ1:n1ACB1such thatιρ=σ1ιn1andσ1is then the induced map:

Σn1A ιn1

ρ

n1A n

σ1

ΣnA

σ1

B1 ι CB1

κ1

ΣB1

(3.11)

Similarly, the mapσ2completes diagram (3.8), precisely,

Σn1A ιn1

ρ

n1A n

σ2n

ΣnA

σ2

B1

0 B2

1B2

B2

(3.12)

Nowφis epimorphic because of the existence of the commutative diagram

Σn1A ιn1

ρ

n1A n

{σ1,σ2n}

ΣnA

{σ12}

B1 {ι,0}

CB1B2 κ ΣB1B2

(3.13)

Theorem 3.1also implies a couple of immediate consequences.

Corollary 3.2. IfB1=0, then, for eachA,πn(A,β)=πn(A,B2).

Corollary 3.3. IfB2=0, then, for eachA,πn(A,β)=πn1(A,B1).

The dual ofTheorem 3.1and its corollaries say that if we assume thatα:A1A2 is the zero map, then for eachB,πn(α,B)=πn1(A2,B)πn(A1,B) forn1. Specifically, if A2=0, thenπn(α,B)=πn(A1,B), and ifA1=0, thenπn(α,B)=πn1(A2,B). Notice that asA2=0, one sees from diagram (2.14) inTheorem 2.6thatπn(α,B)=πn(kerα,η,B);

however, the isomorphism fails whenA1=0. As an example, consider theΛ-mapα: 0 Z, whereΛis the integral group ring of the finite cyclic groupCkwith generatorτandZ is regarded as a trivialCk-module. Then,

πn(α,Z)=πn1(Z,Z)=

Z/k, fornodd,

0, forneven. (3.14)

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(See [3, Theorem 3.1].) On the other hand, the well-known projective resolution ofZ, thus,

··· ρ ZCk σ

ZCk ρ

ZCk Z

ICk Z ICk

(3.15) where the maps,ρ,σare the augmentation ofZCk, multiplication byτ1, and multi- plication byτk1+···+τ+ 1, respectively, gives us that

πnkerα,η,Z=πnZ,Z)=πnICk,Z=

πICk,Z

, forneven πICk,ICk

, fornodd =0, (3.16) because all the maps in HomΛ(ICk,Z) and HomΛ(ICk,ICk) arep-nullhomotopic.

Similarly, asB1=0,πn(A,β)=πn(A, coker{ι,β}); however, this position alters when B2=0; consider theΛ-mapβ:Q/Z0, where, again,Λis the integral group ring of the finite cyclic groupCkandQ/Zis regarded as a trivialCk-module. Then,

πn(Q/Z,β)=πn1(Q/Z,Q/Z)=

Z/k, fornodd,

0, forneven. (3.17)

(See [3, Theorem 2.6].) Forπn(A, coker{ι,β}), we adopt the injective resolution ofQ/Z: Q/Z Δ (Q/Z)k ρ

(Q/Z)k σ (Q/Z)k ρ

···

I(Q/Z)k Q/Z I(Q/Z)k

(3.18) whereΔ=is the diagonal map, and obtain that

πn

Q/Z, coker{ι,β}=πn

Q/ZQ/Z=πn

Q/Z,I(Q/Z)k

=

πQ/Z,I(Q/Z)k, forneven

πI(Q/Z)k,I(Q/Z)k, fornodd =0, (3.19) again because all the maps in HomΛ(Q/Z,I(Q/Z)k) and HomΛ(I(Q/Z)k,I(Q/Z)k) are i-nullhomotopic.

Therefore, as one may expect, the classic fibration/cofibration does not hold for arbi- trary maps in module theory. The same phenomena arise again even when we generalize B1andB2, respectively, to injective modules.

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Theorem 3.4. Letβ:B1B2be arbitrary. Then, for eachA,

(i) ifB1is injective, thenπn(A,β)=πn(A,B2)=πn(A, coker{ι,β});

(ii) ifB2is injective, thenπn(A,β)=πn1(A,B1).

Proof. The first halves of both parts of the theorem, namely,πn(A,β)=πn(A,B2) when B1 is injective andπn(A,β)=πn1(A,B1) whenB2 is injective, come directly from the (injective) homotopy exact sequence of the mapβ:B1B2, thus,

··· πn A,B1

β

πn A,B2

J

πn(A,β) πn1

A,B1

β

πn1

A,B2

J

···

(3.20) To prove thatπn(A,β)=πn(A, coker{ι,β}) whenB1is injective, one considers diagram (2.11), but nowCB1=B1. Thus,

Σn1A ιn1

ρ

n1A n

σ

ΣnA ιn

σ

nA B1

{ι,β}

B1B2 κ

coker{ι,β}

(3.21)

SinceB1 is injective, the short exact sequence B1 {ι,β}

B1B2 κ

coker{ι,β} splits.

Thus there exists a mapν: coker{ι,β} →B1B2 such that κν=1coker{ι,β}. Applying Theorem 2.5, we defineχ:πn(A,β)πn(A, coker{ι,β}) byχ(σ)=[σ] and show thatχ is an isomorphism.

First, ifσ=0 in πn(A,β), then there is θ:nAB1B2 such thatσ=κθ ιn, which also means thatχ(σ)=[σ]=0 inπn(A, coker{ι,β}). Soχis well defined. To show that χis monomorphic, suppose given σπn(A,β) such thatχ(σ)=[σ]=0, thenσ=ωιnfor someω:nAcoker{ι,β}. Thus,σ=ωιn=1coker{ι,β}ωιn= κνωιn, which forcesσ=0. Thus,χis monomorphic. Finally, the fact that every σnAcoker{ι,β}yields a commutative diagram

Σn1A ιn1

0

n1A n

νσn

ΣnA

σ

B1 {ι,β}

B1B2 κ coker{ι,β}

(3.22)

allows us to conclude thatχis epimorphic.

Examining the connection betweenπn(A,β) andπn(A, coker{ι,β}), even for the rather simple case thatB2is injective, we find that, for a mapσnAcoker{ι,β}to be re- lated to an element inπn(A,β),σought to be “reversible” in a diagram such as (2.11), that is, σ must guarantee the existence of a pair (ρ,σ), or equivalently, σ is the in- duced map of (ρ,σ). Conversely, for a pair (ρ,σ) :ιn1→ {ι,β} to be related to an el- ement inπn(A, coker{ι,β}), the reversibleσ ought to, simultaneously, factor through not onlyιn but also κ as (ρ,σ) is i-nullhomotopic. These lead precisely to our group

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