WEIGHTED COMPOSITION OPERATORS BETWEEN DIFFERENTIABLE FUNCTION ALGEBRAS
S.AMIRI,A. GOLBAHARAN ANDH.MAHYAR
FACULTY OF MATHEMATICAL SCIENCES ANDCOMPUTER, KHARAZMI UNIVERSITY
1. INTRODUCTION
Let
C(X)
be the Banachalgebra
of all continuouscomplex‐valued
functionson a com‐pact
Hausdorffspace X with the uniformnorm,\displaystyle \Vert f\Vert_{X}=\sup_{x\in X}|f(x)|, f\in C(X)
.A Banach function
algebra
isasubalgebra
BofC(X)
whichseparates
thepoints
ofX,
containsthe constantsand is
complete
underanalgebra
norm. If thealgebra
norm onBis
equivalent
to the uniform norm, then thesubalgebra
B is called auniformalgebra.
A function
algebra
B on acompact
Hausdorff space X is natural if every nonzerocomplex homomorphism
on B is an evaluationhomomorphism
at anypoint
of X[7,
4.1.3].
For each x \in X, the evaluation map$\delta$_{x}
is definedby
$\delta$_{x}(f)
=f(x)
for everyfunction
f\in B
. Inthecase where B isa Banach functionalgebra
on X, we say that B
isnatural if its maximal ideal space
\mathcal{M}(B)
coincides with X.Let A and B be linear spaces of functionson setsX and Y,
respectively.
Let ube acomplex‐valued
function on Y, and $\varphi$ be a map from Y to X. A linearoperator
uC_{ $\varphi$},
defined
by
uC_{ $\varphi$}f=u(f\circ $\varphi$) , f\in A
iscalled a
weighted
composition operator
from A to B, wheneveru(f\mathrm{o} $\varphi$)
\in B for eachf\in A
. TheoperatoruC_{ $\varphi$}
canberegarded
as ageneralization
ofamultiplication
operator
and a
composition operator.
Inthe case whereu= 1, theoperator
uC_{ $\varphi$}
reduces to the2010MathematicsSubjectClassification. 46\mathrm{J}15, 47\mathrm{B}38,47\mathrm{B}06.
Keywords andphrases. Continuouslydifferentiable functionalgebras; weightedcomposition operators;
composition
operatorC_{ $\varphi$}
. In the case where X = Y and$\varphi$(x)
= x, it reduces to themultiplication
operatorM_{\mathrm{u}}.
Using
the closedgraph theorem,
everyweighted
composition operator
from aBanachfunction
algebra
to another isautomatically
continuous and therefore a bounded linearoperator
between them.A
complex‐valued
functionf
defined on aperfect
compact
plane
set X iscomplex‐
differentiableon X ifat eachpoint z_{0}\in X
the limitf'(z_{0})=z\displaystyle \rightarrow z\lim_{z\in X^{0}}\frac{f(z)-f(z_{0})}{z-z_{0}},
exists. The n‐th
complex‐derivative
off
is denotedby
f^{(n)}.
Suppose
thatD^{n}(X)
isthealgebra
ofn‐timescontinuously complex‐differentiable
func‐tionson a
perfect
compactplane
set X. Thisalgebra
with thenorm\displaystyle \Vert f\Vert_{n}=\sum_{k=0}^{n}\frac{\Vert f^{(k)}\Vert_{X}}{k!} (f\in D^{n}(X))
,is a normed function
algebra
on X which is notnecessarily complete,
even for afairly
nice X. For
example,
Bland and Feinstein in[4,
Theorem2.3]
showed that ifacompact,
perfect plane
setX hasinfinitely
manycomponents
then thealgebra
D^{n}(X)
isincomplete.
By
standardmethods,
thecompleteness
ofD^{1}(X)
implies
thecompleteness
ofD^{n}(X)
foreachn\in \mathrm{N}. As Bland and Feinstein showed in
[4,
Theorem2.5],
there existsanexample
ofaset X which is the
image
ofa rectifiable Jordan arc intheplane
andyet
D^{1}(X)
isincomplete.
Therefor,
thecompleteness
ofD^{1}(X)
isfar frombeing
atopological
property
ofX. To
provide
a sufficient condition for thecompleteness
ofD^{1}(X)
, let us recall the
definition of
pointwise regularity
and uniformregularity
forcompact
plane
sets.Definition 1.1. Let X beacompact
plane
setwithmorethanonepoint.
(i)
X is calledpointwise
regular
if for each z_{0} \in X there exists aconstant c_{z_{0}} suchthat,
foreveryz\in X there existsarectifiablepath
$\gamma$:[a, b]\rightarrow X
with$\gamma$(a)=z_{0},
$\gamma$(b)=z
and| $\gamma$|\leq c_{z_{0}}|z-z_{0}|
where| $\gamma$|
is thelength
of thepath
$\gamma$.(ii)
X is calleduniformly regular
if there exists aconstantcsuch that for allz,w\in X,
there exists a rectifiable
path
$\gamma$ :[a, b]
\rightarrow X with$\gamma$(a)
=z,
$\gamma$(b)
= w andClearly
allpointwise
anduniformly regular
sets areperfect
andpath‐connected.
Wenote thateveryconvex
compact
plane
set isobviously uniformly regular.
There arealsonon‐convex
uniformly regular
sets, like the Swiss cheese defined in[14].
Clearly
therearepointwise
regular
sets which are notuniformly regular.
Forexample,
the union of twoclosed discs
tangent
fromoutside isapointwise
regular
setwhich isnotuniformly regular.
It is also
interesting
to notethat if theboundary
ofacompactplane
setX satisfiesoneofthese two
regularity
conditions then it satisfies the samecondition(of
coursethis is not anecessarycondition),
see[4,
Theorem3.5].
We now
provide
sufficient conditions for thecompleteness
ofD^{1}(X)
. Dales and Daviein
[8,
Theorem1.6]
showed that when X is afinite union ofuniformly regular
sets,
foreach
z_{0}\in X
there exists aconstantc_{z\mathrm{o}} such that for allf\in D^{1}(X)
and eachz\in X,
(1.1)
|f(z)-f(z_{0})|\leq c_{z0}|z-z_{0}|(\Vert f\Vert_{X}+\Vert f'\Vert_{X})
.Using
thisinequality, they
obtained thefollowing
result.Theorem 1.2.
[8,
Theorem1.6]
If
X is acompact
plane
set which is afinite
unionof
uniformly regular
sets,
thenD^{n}(X)
is a Banachfunction algebra
on X.Later in
[11],
it was shown that the condition(1.1)
is still valid when X is a finiteunionof
pointwise
regular
sets. Infact,
in[11],
itwas shownthat the condition(1.1)
isanecessary andsufficient condition for the
completeness
ofD^{1}(X)
.Theorem 1.3.
[11]
Let X be acompact
plane
set. ThenD^{1}(X)
iscomplete
if
andonly if
for
eachz_{0}\in X
there exists a constant c_{z0} such thatfor
allf\in D^{1}(X)
and eachz\in X,
|f(z)-f(z_{0})|\leq c_{z_{0}}|z-z_{0}|(\Vert f\Vert_{X}+\Vert f'\Vert_{X})
.Asaconsequence of the above
theorem,
thefollowing
result wasalso established.Theorem 1.4.
[11]
If
X is afinite
unionof
pointwise
regular
sets,
thenD^{n}(X)
is aBanach
function algebra
on X.In
general,
it is not known whether or not the converse of this theorem holds true.However,
as it wasproved
in[9],
there areseveral classes ofconnected,
compact plane
X. For
example,
this istrue for allrectifiably connected, polynomially
convex,compact
plane
setswithempty interior,
for allstar‐shaped,
compact
plane
sets, and for all Jordanarcs in\mathbb{C}. NotethatinTheorem
1.3,
X need notbe connected.As it was shown in
[8],
thealgebra
D^{n}(X)
is natural when X isuniformly regular.
However,
asmentioned in[12],
one can show that thealgebra
D^{n}(X)
is natural for everyperfect
compact
plane
set X(see
also[9,
Theorem4.1]).
In this
article,
we discuss the boundedness andcompactness
ofweighted
composition
operators
acting
onalgebras
D^{n}(X)
whenperfect
compact
plane
setsXsatisfy
the con‐dition
(1.1).
Inthecase that u=1, wegive
anecessary and sufficient condition for thecomposition
operators
between two Banachalgebras
D^{n}(X)
andD^{m}(Y)
to be boundedand
compact.
As aconsequence, westatecertain results about powercompact
andqua‐sicompact
composition
operators
on thesealgebras.
Thenusing
theseresults, by giving
examples
we show that there existquasicompact
or Rieszoperators
on thesealgebras
which arenot power
compact.
2. BOUNDEDNESS AND COMPACTNESS OF
uC_{ $\varphi$}
OND^{n}(X)
It is known that if u, $\varphi$ \in
D^{n}(X)
, thenuC_{ $\varphi$}
is aweighted
composition operator
on
D^{n}(X)
.Conversely,
ifuC_{ $\varphi$}
is aweighted
composition
operator onD^{n}(X)
, then
u,
u $\varphi$\in D^{n}(X)
sinceD^{n}(X)
contains theconstant functionsand the coordinate functionz.
Although,
$\varphi$ does notnecessarily belong
toD^{n}(X)
as it may not be evencontinuouson X. The
following
theoremgives
anecessary and sufficient condition on u and $\varphi$foruC_{ $\varphi$}
tobe aweighted
composition operator
onD^{1}(X)
.Theorem 2.1.
[2,
Theorem2.1]
Let X be aperfect
compact
plane
set. Letube acomplex‐
valued
function
onX, and $\varphi$be aself‐map of
X notnecessarily
continuous. ThenuC_{ $\varphi$}
isa
weighted
composition operator
onD^{1}(X)
if
andonly if
u and u $\varphi$belong
toD^{1}(X)
.In
general,
foraconstantself‐map
$\varphi$of X,theweighted
composition operator
uC_{ $\varphi$}
on anormed function
algebra
B onX isarankoneoperator,
soit iscompact.
Wenowgive
asufficient condition for
compactness
ofuC_{ $\varphi$}
onD^{n}(X)
for those $\varphi$which arenot constantself‐maps
of X.Theorem 2.2.
[2,
Theorem2.2]
Let X be aperfect
compact
plane
setsatisfying
the condition(1.1).
Letu,$\varphi$\in D^{n}(X)
.If
$\varphi$(\mathrm{c}\mathrm{o}\mathrm{z}(u))
\subseteqintX,
then theweighted
composition
operator
uC_{ $\varphi$}
iscompact
onD^{n}(X)_{2}
where\mathrm{c}\mathrm{o}\mathrm{z}(u)=\{z\in X : u(z)\neq 0\}.
The condition
$\varphi$(\mathrm{c}\mathrm{o}\mathrm{z}(u))\subseteq
intX is alsonecessaryforcompactness
ofweighted
compo‐sitionoperators
uC_{ $\varphi$}
onalgebras
D^{n}(X)
for certaincompactplane
setsX. This is indeedthe motivation forthe
following
definition.Definition 2.3. A
plane
setX has an internal circulartangent
at$\zeta$\in\partial X
if there existsanopendisc U such that
$\zeta$\in\partial U
and\overline{U}\backslash \{ $\zeta$\}\subseteq
intX. Aplane
set X isstrongly
accessible from the interior if it has aninternal circulartangent
at eachpoint
of itsboundary.
A
compact
plane
setXissaidtohaveapeak boundary
withrespecttoasetB\subseteq C(X)
if for each
$\zeta$\in\partial X
there existsanon‐constantfunction h\in Bsuch that\Vert h\Vert_{X}=h( $\zeta$)=1.
The closed unit disc
\overline{\mathrm{D}}=\{z\in \mathbb{C} : |z| \leq 1\}
and\displaystyle \overline{ $\Delta$}(z_{0}, r)\backslash \bigcup_{k=1}^{n} $\Delta$(z_{k}, r_{k})
where closed discs\overline{ $\Delta$}(z_{k}, r_{k})
aremutually disjoint
in$\Delta$(z_{0}, r)=\{z\in \mathbb{C} : |z-z_{0}| <r\}
areexamples
ofplane
sets which arestrongly
accessible from the interior.Moreover,
if X is acompact
plane
set such that\mathbb{C}\backslash X
isstrongly
accessible from theinterior,
then X has apeak
boundary
withrespect
to every subset ofC(X)
which contains the rational functions withpoles
off X, inparticular,
withrespect
toD^{n}(X)
. To seethis,
take$\zeta$\in\partial X
. Thenthere exists a disc
D=D(z_{0}, r)
such that$\zeta$\in\partial D
and\overline{D}\backslash \{ $\zeta$\}
\subseteq \mathbb{C}\backslash X
. The functionh(z)=\displaystyle \frac{ $\zeta$-z_{0}}{z-z_{0}}
satisfies the conditions in the definition of thepeak boundary
(see [3,
15Theorem 2.4.
[2,
Theorem2.5]
Let X be aperfect
compact
plane
set with connectedinterior
satisfy
the condition(1.1),
bestrongly
accessiblefrom
the intenor and have apeak boundary
withrespect
toD^{n}(X)
. Letacomplex
function
u and aself‐map
$\varphi$of
X bein
D^{n}(X)
.If
theweighted
composition operator
uC_{ $\varphi$}
onD^{n}(X)
iscompact,
then either $\varphi$is constant or
$\varphi$(\mathrm{c}\mathrm{o}\mathrm{z}(u))\subseteq
intX.In thecase where u=1, the
weighted
composition
operatoruC_{ $\varphi$}
reduces to thecom‐position operators
C_{ $\varphi$}
. Thefollowing corollary
can be concludedimmediately
from theabove theorems for
composition operators
C_{ $\varphi$}
onD^{n}(X)
.Corollary
2.5.[2,
Corollary
2.6]
Let X be aperfect
compact
plane
setsatisfying
the condition(1.1).
Let aself‐map
$\varphi$of
X be inD^{n}(X)
.(i)
If
either $\varphi$ is constant or$\varphi$(X)\subseteq \mathrm{i}\mathrm{n}\mathrm{t}X_{f}
ThenC_{ $\varphi$}
iscompact
onD^{n}(X)
.(ii)
Let X bestrongly
accessiblefrom
theinterior,
have apeak boundary
withrespect
toD^{n}(X)
and let intX be connected.If
C_{ $\varphi$}
iscompact
onD^{n}(X)
, then either $\varphi$is constant or
$\varphi$(X)\subseteq
intX.Corollary
2.6. LetC_{ $\varphi$}
be acomposition operator
onD^{n}(\mathrm{D})
inducedby
aself‐map
$\varphi$of
D. Then
C_{ $\varphi$}
iscompact
if
andonly
if
either $\varphi$ is constant or$\varphi$(\overline{\mathrm{D}})\subseteq \mathrm{D}.
3. COMPOSITION OPERATORS BETWEEN THEALGEBRAS
D^{n}(X)
ANDD^{m}(Y)
In thissection,
we discuss thecomposition
operators between thealgebras
of continu‐ously complex
differentiable functions.Let
X,
Y be twoperfect
compact
plane
sets and n,m be twopositive
integers
withm \leq n. Then for a map $\varphi$ : \mathrm{Y} \rightarrow
X,
C_{ $\varphi$}
is acomposition
operator fromD^{n}(X)
intoD^{m}(Y)
if andonly
if $\varphi$ \inD^{m}(Y)
. If X satisfies the condition(1.1)
and m < n, then
by using
the Arzela‐AscoliTheorem,
one can show that the condition $\varphi$ \inD^{m}(Y)
is asufficient condition for
compactness
ofcomposition
operator
C_{ $\varphi$}
. But in thecasen=m,by
Corollary
2.5,
this condition is not sufficient forcompactness
ofC_{ $\varphi$}
.Thus,
we havethe
following
results forcomposition
operators.
Theorem 3.1. Let
X,
Y be twoperfect
compact
plane
setssatisfying
the condition(1.1)
andn,m betwo
positive integers
withm<n. Then thefollowing
conditionsareequivalent.
(i) $\varphi$\in D^{m}(Y)
.(ii)
C_{ $\varphi$}
is a boundedoperator
from
D^{n}(X)
intoD^{m}(Y)
.(iii) C_{ $\varphi$}
is acompact operator
from
D^{n}(X)
intoD^{m}(Y)
.Theorem 3.2. Let
X,
Y betwoperfect
compact
plane
setssatisfying
the condition(1.1),
n be a
positive integer
and the map $\varphi$ : Y\rightarrow X be inD^{n}(Y)
.(i)
If
either $\varphi$ is constantor$\varphi$(Y)\subseteq
intX,
thenC_{ $\varphi$}
is acompact
operatorfrom
D^{n}(X)
into
D^{n}(Y)
.(ii)
Let X have apeak boundary
withrespect
toD^{n}(X)
and let Y bestrongly
accessiblefrom
the interior. Assume that intX is connected.If
C_{ $\varphi$}
is acompact operator
For thecase n<m, we need the
following
formula forhigher
derivatives ofcomposite
functions which is known asFaà di Brunos formula
[1,
page823].
Let
f
: X\rightarrow \mathbb{C} and $\varphi$: Y\rightarrow X ben‐timescontinuously
differentiable functions. Then(f\displaystyle \circ $\varphi$)^{(n)}=\sum_{j=1}^{n}(f^{(j)}\circ $\varphi$)\cdot$\psi$_{j,n},
where
$\psi$_{j,n}=\displaystyle \sum_{a}(\frac{n.!}{a_{1}!a_{2}!\cdot\cdot a_{n}!}\prod_{\mathrm{i}=1}^{n}(\frac{$\varphi$^{(i)}}{i!})^{a_{i}})
,thesum
\displaystyle \sum_{a}
is takenoverallnon‐negative integers
a_{1}, a_{2},...,a_{n}
satisfying
a_{1}+a_{2}+\cdots+a_{ $\eta$}
=j
anda_{1}+2a_{2}+\cdots+na_{n}=n
. Forexample,
$\psi$_{1,n}=$\varphi$^{(n)}
and$\psi$_{n,n}=($\varphi$')^{n}.
Theorem 3.3. Let
X,
Y be twoperfect
compact
plane
sets. Let n,m be twopositive
integers
withn<m.If
$\varphi$\in D^{m}(Y)
and$\varphi$(Y)
\subseteqintX,
thenC_{ $\varphi$}
is acompact operator
from
D^{n}(X)
intoD^{m}(Y)
.Pro0f
. First we show thatC_{ $\varphi$}
is a boundedoperator
fromD^{n}(X)
intoD^{m}(Y)
. Letf\in
D^{n}(X)
. Thenf
isanalytic
and soinfinitely
differentiable in intX. Inparticular,
f
ism‐times
continuously
differentiable on thecompact
subset$\varphi$(Y)
\subseteq intX.Thus,
using
Faà di Brunos
formulas,
C_{ $\varphi$}(f) =f\mathrm{o} $\varphi$\in D^{m}(Y)
. HenceC_{ $\varphi$}
is acomposition
operator
from
D^{n}(X)
intoD^{m}(Y)
.We now prove the compactness of
C_{ $\varphi$}
. To dothis,
let\{f_{k}\}
be a bounded sequencein
D^{n}(X)
with\Vert f_{k}\Vert_{n}=
\displaystyle \sum_{r=0}^{n}\frac{\Vert f_{k}^{(r)}\Vert_{\mathrm{X}}}{r!}
\leq 1. Then\{f_{k}\}
is auniformly
bounded sequenceof
analytic
functions in intX. Thus it isa normalfamily
inthe senseof Montel andby
using
asubsequence
ifnecessary, wemay assume that there existsa functionf analytic
in intX with
f_{k}\rightarrow f uniformly
oncompact
subsets of intX.Also, by
[6,
VII,
Theorem2.1],
f_{k}^{(r)}
\rightarrow f^{(r)}
uniformly
oncompact
subsets of intX for eachr\geq 0
.By
assumption,
$\varphi$(Y)
\subseteqintX,
so one can define a function F on Yby
F(y)
=f( $\varphi$(y))
. Since
f
is ananalytic
function inintX,
it isinfinitely
differentiable function onintX,
inparticular,
itism‐times
continuously
differentiableonintX.Also,
notethat$\varphi$\in D^{m}(Y)
and thereforeas k\rightarrow\infty.
\displaystyle \Vert C_{ $\varphi$}(f_{k})-F\Vert_{m}=\sum_{r=0}^{m}\frac{\Vert(f_{k}\circ $\varphi$-F)^{(r)}\Vert_{Y}}{r!}=\sum_{r=0}^{m}\frac{\Vert((f_{k}-f)\circ $\varphi$)^{(r)}\Vert_{Y}}{r!}
\displaystyle \leq\Vert(f_{k}-f)\circ $\varphi$\Vert_{\mathrm{y}}+\sum_{r=1}^{m}\frac{1}{r!}\sum_{j=1}^{r}\Vert(f_{k}-f)^{(j)}0 $\varphi$\Vert_{\mathrm{y}}
.\Vert$\psi$_{j,r}\Vert_{\mathrm{y}}
\displaystyle \leq\Vert f_{k}-f\Vert_{ $\varphi$(Y)}+\sum_{r=1}^{m}\frac{1}{r!}\sum_{j=1}^{r}\Vert f_{k}^{(j)}-f^{(j)}\Vert_{ $\varphi$(Y)}
.\Vert$\psi$_{j,r}\Vert_{\mathrm{y}}.
Therefore,
\Vert C_{ $\varphi$}(f_{k})-F\Vert_{m}\rightarrow 0
as k\rightarrow\infty, since$\varphi$(Y)
is acompact
subset of intX andf_{k}^{(r)}\rightarrow f^{(r)}
uniformly
on$\varphi$(Y)
for eachr\geq 0. \squareUsing
thesamearguments
asintheproof
of the above theoremweobtain thefollowing
result.
Theorem 3.4. Let m be a
positive integer
andX,
Y be twoperfect
compact
plane
sets.If
$\varphi$\in D^{m}(Y)
and$\varphi$(Y)\subseteq
intX,
thenC_{ $\varphi$}
is acompact operator
from
A(X)
intoD^{m}(Y)
.As
usual,
A(X)
denotes theuniform algebra of
all continuousfunctions
on acompact
plane
setX which areanalytic
on intX.To provethe next
theorem,
werequire
thefollowing
lemma duetoJulia[5,
Chapter
IofPart
Sìx].
Lemma 3.5. Let
\overline{\mathrm{D}}
be the closed unit disc in \mathbb{C} and let h be acontinuously differentiable
function
on\overline{\mathrm{D}}
.If
h( $\zeta$)=\Vert h\Vert_{\overline{\mathrm{D}}}
for
some$\zeta$\in\overline{\mathrm{D}}
, then either h is constant or
h'( $\zeta$)\neq 0.
For
convenience,
for eachz_{0}\in X
and eachfunctionf
: X\rightarrow \mathbb{C}we definep_{z_{0}}(f):=z\displaystyle \neq zz\in X\sup_{0}\frac{|f(z)-f(z_{0})|}{|z-z_{0}|}.
Then when X satisfies the condition
(1.1),
for each z_{0} \in X there exists a constant c_{z0}such that
(3.1)
p_{z0}(f)\leq c_{z0}(\Vert f\Vert_{X}+\Vert f'\Vert_{X}) (f\in D^{1}(X))
.Theorem 3.6. Letn,m be two
positive
integers
andX,
Y be twoperfect
compact
plane
setssatisfying
the condition(1.
1)
such that X hasapeak
boundary
withrespect
toD^{n+1}(X)
and intX is connected. Let Y be
strongly
accessiblefrom
the interior.If
n<m, then the(i) $\varphi$\in D^{m}(Y)
and either $\varphi$ is constantor$\varphi$(Y)\subseteq
intX.(ii)
C_{ $\varphi$}
isa boundedoperator
from
D^{n}(X)
intoD^{m}(Y)
.(iii) C_{ $\varphi$}
is acompact operator
from
D^{n}(X)
intoD^{m}(Y)
.Proof.
(\mathrm{i})\rightarrow(\mathrm{i}\mathrm{i}\mathrm{i})
has beenproved
inTheorem 3.3.(\mathrm{i}\mathrm{i}\mathrm{i})\rightarrow(\mathrm{i}\mathrm{i})
isobvious.(\mathrm{i}\mathrm{i})\rightarrow(\mathrm{i})
. We knowthat$\varphi$\in D^{m}(Y)
, since
D^{n}(X)
contains the coordinate function z.Assume that
$\varphi$( $\zeta$)
\in\partial X for spme$\zeta$
\in Y. Thenby
openmapping
theorem foranalytic
functionswehave that
$\zeta$\in\partial Y
. Since X hasapeak boundary
withrespect
toD^{n+1}(X)
,
there existsanon‐constant function
h\in D^{n+1}(X)
such thath( $\varphi$( $\zeta$))=\Vert h\Vert_{X}=1
. Letf_{k}(z)=\displaystyle \frac{h^{k}.(z.)}{k(k-1)\cdot(k-n)}, (z\in X, k>n)
.Then
\{f_{k}\}
is a bounded sequence inD^{n}(X)
andf_{k}^{(r)}
\rightarrow 0uniformly
on X for eachr=0,
1, 2,
...,n. Therefore
\Vert f_{k}\Vert_{n}\rightarrow 0
andhence, by
boundedness ofC_{ $\varphi$},
\Vert f_{k}\circ $\varphi$\Vert_{m}=\Vert C_{ $\varphi$}(f_{k})\Vert_{m}\rightarrow 0
as k\rightarrow\infty.Thus
\Vert(f_{k}\circ $\varphi$)^{(r)}\Vert_{Y}\rightarrow 0
for each r=0,1, 2,
...,m and
consequently, using
theinequality
(3.1),
p_{ $\zeta$}((f_{k}\mathrm{o} $\varphi$)^{(r)})\rightarrow 0
for each r=0,1, 2,
...,m-1. In
particular,
(3.2)
p_{ $\zeta$}((f_{k}\circ $\varphi$)^{(n)})\rightarrow 0
as k\rightarrow\infty.Also
by
(3.1),
it follows from theuniformly
convergencef_{k}^{(r)}
\rightarrow 0 on X for each r =0,
1, 2,
...,n, that
(3.3)
p_{ $\varphi$( $\zeta$)}(f_{k}^{(r)})\rightarrow 0
as k\rightarrow\infty(r=0,1,2, \ldots,n-1)
.Using
Faà di Brunosformula,
p_{ $\zeta$}((f_{k}^{(n)}\displaystyle \circ $\varphi$)($\varphi$')^{n})\leq p_{ $\zeta$}((f_{k}\circ $\varphi$)^{(n)})+\sum_{j=1}^{n-1}p_{ $\zeta$}((f_{k}^{(j)}\circ $\varphi$) . $\psi$_{j,n})
\displaystyle \leq p_{ $\zeta$}((f_{k}\circ $\varphi$)^{(n)})+\sum_{j=1}^{n-1}\Vert f_{k}^{(j)}\circ $\varphi$\Vert_{Y}p_{ $\zeta$}($\psi$_{j,n})+\sum_{j=1}^{n-1}p_{ $\zeta$}(f_{k}^{(j)}\circ $\varphi$)\Vert$\psi$_{j,n}\Vert_{Y}.
\displaystyle \leq p_{ $\zeta$}((f_{k}\circ $\varphi$)^{(n)})+\sum_{j=1}^{n-1}\Vert f_{k}^{(j)}\Vert_{X}p_{ $\zeta$}($\psi$_{j,n})+\sum_{j=1}^{n-1}p_{ $\varphi$( $\zeta$)}(f_{k}^{(j)})p_{ $\zeta$}( $\varphi$)\Vert$\psi$_{j,n}\Vert_{Y}.
This
inequality, along
with the limits(3.2), (3.3)
and theproperty
of\{f_{k}\}
imply
that(3.4)
p_{ $\zeta$}((f_{k}^{(n)}\circ $\varphi$)($\varphi$')^{n})\rightarrow 0
as k\rightarrow\infty.By
thedefinition off_{k}^{(n)},
(3.5)
\displaystyle \frac{1}{k-n}p_{ $\zeta$}(((h\mathrm{o} $\varphi$)')^{n}(h\mathrm{o} $\varphi$)^{k-n})\leq p_{ $\zeta$}((f_{k}^{(n)}\mathrm{o} $\varphi$)($\varphi$')^{n})+\frac{P(k).p_{ $\zeta$}.( $\psi$)}{k(k-1)\cdot(k-n)},
where the function$\psi$
is a combination of$\varphi$',
h and the derivatives of h, andP(k)
is apolynomial
intermsof k withdegree
less thann+1. Hence\displaystyle \frac{P(k)}{k(k-1)\cdots(k-n)}\rightarrow 0
as k\rightarrow\infty.Using
this limittogether
with the limit(3.4)
and theinequality
(3.5),
weobtain(3.6)
\displaystyle \frac{1}{k-n}p_{ $\zeta$}(((h\circ $\varphi$)')^{n}\cdot(h\circ $\varphi$)^{k-n})\rightarrow 0
as k\rightarrow\infty.Onthe other
hand,
wehave\displaystyle \sup|(h\circ $\varphi$)'(z)|^{n}\frac{|h^{k-n}( $\varphi$(z))-h^{k-n}( $\varphi$( $\zeta$))|}{(k-n)|z- $\zeta$|}
z\in\overline{U}z\neq $\zeta$
\displaystyle \leq\frac{1}{k-n}\{p_{ $\zeta$}(((h\circ $\varphi$)')^{n}\cdot(h\circ $\varphi$)^{k-n})+p_{ $\zeta$}(((h\circ $\varphi$)')^{n})\Vert h\Vert_{X}^{k-n}\}.
Using
(3.6)
and the fact that\Vert h\Vert_{X}=1
, one canconcludefrom the aboveinequality
that\displaystyle \sup|(h\circ $\varphi$)'(z)|^{n}\frac{|h^{k-n}( $\varphi$(z))-h^{k-n}( $\varphi$( $\zeta$))|}{(k-n)|z- $\zeta$|}\rightarrow 0
, as k\rightarrow\infty.z\in\overline{U}z\neq $\zeta$
Let $\epsilon$>0. Then
|(h\displaystyle \circ $\varphi$)'(z)|^{n}\frac{|h^{k-n}( $\varphi$(z))-h^{k-n}( $\varphi$( $\zeta$))|}{(k-n)|z- $\zeta$|}< $\epsilon$,
forsome
positive
integer
k>nand for allz\in\overline{U}
withz\neq $\zeta$
.Taking
limitasz\rightarrow $\zeta$
,we
get
|(h\mathrm{o} $\varphi$)'( $\zeta$)|^{n+1}\leq e
, for each $\epsilon$>0, sinceh( $\varphi$( $\zeta$))=1
.Consequently,
|(h\mathrm{o} $\varphi$)'( $\zeta$)|^{n+1}=0,
hence,
(h\mathrm{o} $\varphi$)'( $\zeta$)=0
.By
Julias Lemma3.5,
h\mathrm{o} $\varphi$
is constanton U.Using
theidentity
theorem
[6,
IV,
Theorem3.7],
theanalytic
functionh\mathrm{o} $\varphi$
isconstantonthe connectedsetintX. The
hypothesis,
X isstrongly
accessiblefrom theinterior, implies
that X has denseinterior,
soh\mathrm{o} $\varphi$
is constant on X. But h is notconstant,
thus $\varphi$must beconstant. \squareThe
assumption,
X has apeak boundary
withrespect
toD^{n+1}(X)
, inTheorem 3.6 isa mild
restriction,
sinceD^{n+1}(X)
contains all rational functions withpoles
off X. Inparticular,
whenX=\mathrm{Y}=\overline{\mathrm{D}}
wehave thefollowing
result.Theorem3.7. Letn,m betwo
positive integers
withn<m, then thefollowing
conditionsare
equivalent.
(i)
$\varphi$\in D^{m}(\overline{\mathrm{D}})
and either$\varphi$\dot{u}
constant or$\varphi$(\overline{\mathrm{D}})
\underline{\subseteq} D.(iii) C_{ $\varphi$}
is acompact operator
from
D^{n}(\mathrm{I}\mathrm{D})
intoD^{m}(\overline{\mathrm{D}})
.In thecasethat the
underlying
set X hasempty
interior,
the situation isdifferent. Forexample,
asKamowitzmentioned in[13],
wehave thefollowing
resultwhen X is the unitinterval
[0
,1]
. Asusual,
inthis case, we denoteD^{n}(X)
by
C^{n}([0,1
Theorem 3.8. A non‐zero
composition operator
C_{ $\varphi$}
onC^{n}([0,1])
iscompact
if
andonly
if
$\varphi$ is a constactfunction.
Thus everynon‐zero compact
endomorphism
TonC^{n}([0,1])
has the formTf=f(z_{0})1
forsome z_{0}\in
[0
,1].
4. QUASICOMPACT, RIESZ AND POWER COMPACT OPERATORS ON
D^{n}(X)
Using
the result of theprevious section,
we will prove some results aboutquasicom‐
pactness,
Riesz and powercompactness
ofC_{ $\varphi$}
onD^{n}(X)
. Forconvenience,
wefirst recalltheir definitions.
Let E be an infinite dimensional Banach space. We denote the Banach
algebra
ofbounded linear
operators
on Eby
\mathcal{B}(E)
and the Banachalgebra
ofcompact
linear oper‐ atorson Eby
\mathcal{K}(E)
. Then\mathcal{K}(E)
is aclosed ideal in\mathcal{B}(E)
. Theoperator
T\in \mathcal{B}(E)
is aFredholm
operator
if T hasfinite‐dimensionalkernel and cokernel. WhenE isan infinitedimensional Banach space,
by
AtkinsonTheorem,
T\in\mathcal{B}(E)
is Fredholm if andonly
ifT+\mathcal{K}(E)
isinvertible in the Calkinalgebra
\mathcal{B}(E)/\mathcal{K}(E)
. The essentialspectrum
$\sigma$_{e}(T)
ofan
operator
T\in \mathcal{B}(E)
isthesetofcomplex
numbers $\lambda$,such that $\lambda$ I-T isnotFredholm.This is also
equal
to thespectrum
ofT+\mathcal{K}(E)
in the Calkinalgebra
\mathcal{B}(E)/\mathcal{K}(E)
. Theessential
spectral
radiusr_{e}(T)
ofT\in \mathcal{B}(E)
isthespectral
radiusofT+\mathcal{K}(E)
intheCalkinalgebra
\mathcal{B}(E)/\mathcal{K}(E)
, that isr_{e}(T)=\displaystyle \lim_{n\rightarrow\infty}\Vert T^{n}+\mathcal{K}(E)\Vert^{\frac{1}{n}}.
Anoperator
T\in \mathcal{B}(E)
iscalledquasicompact
ifr_{e}(T)<1
. Thisholds if andonly
if thereisanatural number n such that the distance from T^{m}to
\mathcal{K}(E)
,\Vert T^{n}+\mathcal{K}(E)\Vert
isstrictly
less than 1. Anoperator
T\in \mathcal{B}(E)
is called Riesz if $\lambda$ I-T is Fredholm for allnon‐zerocomplex
numbers $\lambda$. Thus T is Riesz if andonly
ifr_{e}(T)
= 0.Also,
anoperator
T ispower
compact
ifT^{N}
iscompact
for somepositive integer
N.Obviously,
every powerFeinstein and Kamowitz
proved
in[10,
Theorem 1.2(iii)]
that if $\varphi$ induces a qua‐sicompact
endomorphism
of a unital commutativesemi‐simple
Banachalgebra
B withconnected maximal ideal
(character)
space X, then\cap$\varphi$_{n}(X)
=\{x_{0}\}
forsome x_{0} \inX,
where $\varphi$_{n} denotes the n‐th iterate of $\varphi$.
By using
this relation\mathrm{a}\acute{\mathrm{n}}\mathrm{d}
the obtained condi‐tion for
compactness
ofcomposition operators
onalgebras
D^{n}(X)
, we have thefollowing
result.
Theorem 4.1.
[2,
Theorem2.7]
Let X be aperfect
compact
plane
setsatisfying
the condition(1.1).
Letaself‐map
$\varphi$of
X be inD^{n}(X)
.(i) If\cap$\varphi$_{n}(X)=\{z_{0}\}
for
some z_{0}\inintX,
thenC_{ $\varphi$}
ispowercompact
onD^{n}(X)
.(ii)
Let X bestrongly
accessiblefrom
theinterior,
have apeak boundaw
withrespect
toD^{n}(X)
and let intX be connected.If
$\varphi$\dot{u}
non‐constant andC_{ $\varphi$}
ispowercompact
on
D^{n}(X)
,then\cap$\varphi$_{n}(X)=\{z_{0}\}
for
some z_{0}\in intX.Using
thesameargument
asintheproof
of[10,
Lemma2.1],
one canobtain thefollowing
Theorem.
Theorem 4.2. Let X be aconnected
perfect
compact
plane
set,
$\varphi$ beaself‐map of
X withfixed
point
z_{0}.If
C_{ $\varphi$}
isaquasicompact composition operator
onD^{n}(X)
, then
|$\varphi$'(z_{0})|<1.
Itwasalso shown in
[10,
Theorem3.2]
thatifT=C_{ $\varphi$}
actsonC^{1}([0,1 \mathrm{s}\mathrm{n}\mathrm{d}\cap$\varphi$_{n}([0,1])=
\{x_{0}\}
for some x_{0}\in[0
,1]
, thenr_{e}(T)=
|$\varphi$'(x_{0})|
.By
thefollowing example
we show thatthis isnot, in
general,
trueforD^{1}(X)
.Example
4.3. Let$\varphi$(z)=\displaystyle \frac{1-z}{2}
for everyz\in\overline{\mathrm{D}}
. Notethatz_{0}=\displaystyle \frac{1}{3}
is the fixedpoint
of $\varphi$in \mathrm{D}and
|$\varphi$'(z_{0})|=\displaystyle \frac{1}{2}
. On the otherhand,
$\varphi$(-1)=1
, so
$\varphi$(\overline{\mathrm{D}})\not\leqq \mathrm{D}
and thecomposition
operator
C_{ $\varphi$}
onD^{1}(\mathrm{D})
is notcompact.
However,
|$\varphi$_{2}(z)|
\leq\displaystyle \frac{1}{2}
< 1 for allz\in\overline{\mathrm{D}}
.Hence,
C_{ $\varphi$}
ispowercompactonD^{1}(\overline{\mathrm{D}})
and then\cap$\varphi$_{n}(\overline{\mathrm{D}})=\{z_{0}\}
andr_{e}(C_{ $\varphi$})=0.
A
question
which may be asked is whether everyquasicompact
or Rieszoperator
onD^{n}(X)
isnecessarily
powercompact.
As provenby
FeinsteinandKamowitz,
there existsa
quasicompact operator
onC^{1}([0,1])
which isnotRiesz and there exists aRieszoperator
on
C^{1}([0,1])
which is not powercompact
[10,
Corollary
3.3].
Example
4.4. Let$\varphi$(x)
=\displaystyle \frac{x+x^{2}}{3}
. Then\cap$\varphi$_{n}([0,1])
=\{0\}
andr_{e}(C_{ $\varphi$})
=|$\varphi$'(0)|
=\displaystyle \frac{1}{3}.
Let now
$\varphi$(x)
=\displaystyle \frac{x^{2}}{2}
. Then
\cap$\varphi$_{n}([0,1])
=\{0\}
andr_{e}(C_{ $\varphi$})
=|$\varphi$'(0)|
= 0.Therefore,
C_{ $\varphi$}
isaRiesz operator onC^{1}([0,1])
which isnot powercompact
since non‐iterate of $\varphi$ is constant.The
following example
shows that there exists aquasicompact operator
onD^{n}(X)
which isnot
necessarily
powercompact.
Example
4.5.[2,
Example
2.9]
Let c>1 and$\varphi$(z)=\displaystyle \frac{z+(c-1)}{c}
foreveryz\in\overline{\mathrm{D}}
. ThenC_{ $\varphi$}
isa
composition
operatoronD^{n}(\overline{\mathrm{D}})
andr_{e}(C_{ $\varphi$})<1
. HenceC_{ $\varphi$}
is aquasicompact operator
on
D^{n}(\overline{\mathrm{D}})
which is not powercompact
since\cap$\varphi$_{m}(\overline{\mathrm{D}})=\{1\}\not\subset \mathrm{D}.
However,
as shownby
Feinstein andKamowitz,
if Dales‐Daviealgebra
D(X, M)
is anatural Banach function
algebra
on a connectedperfect
compact
plane
set X with anon‐analytic weight
sequence M ={Mn},
thenevery
quasicompact
endomorphism
ofD(X, M)
inducedby
ananalytic
self‐map
of X ispowercompact[10,
Theorem2.2].
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485‐497.DEPARTMENTOFMATHEMATICS,FACULTYOFMATHEMATICALSCIENCESANDCOMPUTER, KHARAZMI
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