volume 7, issue 4, article 152, 2006.
Received 27 March, 2006;
accepted 19 September, 2006.
Communicated by:N.K. Govil
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Journal of Inequalities in Pure and Applied Mathematics
DIFFERENTIAL SUBORDINATIONS AND SUPERORDINATIONS FOR ANALYTIC FUNCTIONS DEFINED BY THE DZIOK-SRIVASTAVA LINEAR OPERATOR
G. MURUGUSUNDARAMOORTHY AND N. MAGESH
School of Science and Humanities Vellore Institute of Technology
Deemed University, Vellore - 632014, India.
EMail:gmsmoorthy@yahoo.com Department of Mathematics Adhiyamaan College of Engineering Hosur - 635109, India.
EMail:nmagi_2000@yahoo.co.in
2000c Victoria University ISSN (electronic): 1443-5756 092-06
Differential Subordinations and Superordinations for Analytic
Functions Defined by the Dziok-Srivastava Linear
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Abstract
In the present investigation, we obtain some subordination and superordination results involving Dziok-Srivastava linear operatorHml [α1]for certain normalized analytic functions in the open unit disk. Our results extend corresponding pre- viously known results.
2000 Mathematics Subject Classification:Primary 30C45; Secondary 30C80.
Key words: Univalent functions, Starlike functions, Convex functions, Differential subordination, Convolution, Dziok-Srivastava linear operator.
Contents
1 Introduction. . . 3 2 Preliminaries . . . 5 3 Main Results . . . 9
References
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1. Introduction
Let H be the class of functions analytic in ∆ := {z : |z| < 1} and H(a, n) be the subclass of H consisting of functions of the form f(z) = a+anzn + an+1zn+1+· · ·. LetAbe the subclass ofHconsisting of functions of the form f(z) = z+a2z2+· · ·. Letp, h∈ H and letφ(r, s, t;z) : C3×∆→ C. Ifp and φ(p(z), zp0(z), z2p00(z);z)are univalent and ifpsatisfies the second order superordination
(1.1) h(z)≺φ(p(z), zp0(z), z2p00(z);z),
thenpis a solution of the differential superordination (1.1). (Iff is subordinate toF, thenF is superordinate tof.) An analytic functionqis called a subordi- nant if q ≺ pfor allpsatisfying (1.1). A univalent subordinantqethat satisfies q ≺ eq for all subordinants q of (1.1) is said to be the best subordinant. Re- cently Miller and Mocanu [14] obtained conditions onh,qandφfor which the following implication holds:
h(z)≺φ(p(z), zp0(z), z2p00(z);z)⇒q(z)≺p(z).
Using the results of Miller and Mocanu [14], Bulboac˘a [5] considered certain classes of first order differential superordinations as well as superordination- preserving integral operators [4]. Ali et al. [1] have used the results of Bulboac˘a [5] and obtained sufficient conditions for certain normalized analytic functions f(z)to satisfy
q1(z)≺ zf0(z)
f(z) ≺q2(z),
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whereq1andq2 are given univalent functions in∆withq1(0) = 1andq2(0) = 1.Shanmugam et al. [19] obtained sufficient conditions for a normalized ana- lytic functionf(z)to satisfy
q1(z)≺ f(z)
zf0(z) ≺q2(z) and q1(z)≺ z2f0(z)
{f(z)}2 ≺q2(z)
whereq1andq2 are given univalent functions in∆withq1(0) = 1andq2(0) = 1.
In [2], for functionsf ∈ Asuch thatδ >0,
<
(zf0(z) f(z)
f(z) z
δ)
>0, z ∈∆,
a class of Bazilevic type functions was considered and certain properties were studied. In this paper motivated by Liu [11], we define a class
B(λ, δ, A, B) :=
(
f ∈ A: (1−λ)
f(z) z
δ
+λzf0(z) f(z)
f(z) z
δ
≺ 1 +Az 1 +Bz
) ,
where δ > 0, λ ≥ 0, −1 ≤ B < A ≤ 1 and studied certain interesting properties based on subordination. Further we obtained a sandwich result for functions in the classB(λ, δ, A, B).
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2. Preliminaries
For our present investigation, we shall need the following definition and results.
Definition 2.1 ([14, Definition 2, p. 817]). Denote byQ, the set of all functions f(z)that are analytic and injective on∆−E(f), where
E(f) =
ζ ∈∂∆ : lim
z→ζf(z) = ∞
and are such thatf0(ζ)6= 0forζ ∈∂∆−E(f).
Lemma 2.1 ([13, Theorem 3.4h, p. 132]). Let q(z) be univalent in the unit disk∆andθandφbe analytic in a domainDcontainingq(∆)withφ(w)6= 0 whenw ∈ q(∆). SetQ(z) = zq0(z)φ(q(z)), h(z) = θ(q(z)) +Q(z). Suppose that
1. Q(z)is starlike univalent in∆, and 2. <n
zh0(z) Q(z)
o
>0forz∈∆.
If
θ(p(z)) +zp0(z)φ(p(z))≺θ(q(z)) +zq0(z)φ(q(z)), thenp(z)≺q(z)andq(z)is the best dominant.
Lemma 2.2 ([19]). Letqbe a convex univalent function in∆andψ, γ ∈Cwith
<
1 + zq00(z) q0(z) + ψ
γ
>0.
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Ifp(z)is analytic in∆and
ψp(z) +γzp0(z)≺ψq(z) +γzq0(z) thenp(z)≺q(z)andq(z)is the best dominant.
Lemma 2.3 ([5]). Letq(z)be convex univalent in the unit disk∆andϑandϕ be analytic in a domainDcontainingq(∆). Suppose that
1. <[ϑ0(q(z))/ϕ(q(z))]>0forz ∈∆, 2. zq0(z)ϕ(q(z))is starlike univalent in∆.
Ifp(z) ∈ H[q(0),1]∩Q, withp(∆) ⊆ D, and ϑ(p(z)) +zp0(z)ϕ(p(z))is univalent in∆, and
(2.1) ϑ(q(z)) +zq0(z)ϕ(q(z))≺ϑ(p(z)) +zp0(z)ϕ(p(z)), thenq(z)≺p(z)andq(z)is the best subordinant.
Lemma 2.4 ([14, Theorem 8, p. 822]). Let q be convex univalent in ∆ and γ ∈C. Further assume that<[γ]>0.Ifp(z)∈ H[q(0),1]∩Q,p(z) +γzp0(z) is univalent in∆, then
q(z) +γzq0(z)≺p(z) +γzp0(z) impliesq(z)≺p(z)andq(z)is the best subordinant.
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For two functionsf(z) = z +P∞
n=2anzn andg(z) = z+P∞
n=2bnzn, the Hadamard product (or convolution) off andg is defined by
(f∗g)(z) :=z+
∞
X
n=2
anbnzn =: (g∗f)(z).
Forαj ∈C (j = 1,2, . . . , l)andβj ∈C\ {0,−1,−2, . . .}(j = 1,2, . . . , m), the generalized hypergeometric function lFm(α1, . . . , αl;β1, . . . , βm;z) is de- fined by the infinite series
lFm(α1, . . . , αl;β1, . . . , βm;z) :=
∞
X
n=0
(α1)n· · ·(αl)n (β1)n· · ·(βm)n
zn n!
(l ≤m+ 1;l, m∈N0 :={0,1,2, . . .}) where(a)nis the Pochhammer symbol defined by
(a)n:= Γ(a+n) Γ(a)
=
( 1, (n= 0);
a(a+ 1)(a+ 2)· · ·(a+n−1), (n∈N:={1,2,3. . .}).
Corresponding to the function
h(α1, . . . , αl;β1, . . . , βm;z) :=zlFm(α1, . . . , αl;β1, . . . , βm;z),
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the Dziok-Srivastava operator [7] (see also [8,20])Hml (α1, . . . , αl;β1, . . . , βm) is defined by the Hadamard product
Hml (α1, . . . , αl;β1, . . . , βm)f(z) (2.2)
:=h(α1, . . . , αl;β1, . . . , βm;z)∗f(z)
=z+
∞
X
n=2
(α1)n−1· · ·(αl)n−1
(β1)n−1· · ·(βm)n−1
anzn (n−1)!. For brevity, we write
Hml [α1]f(z) :=Hml (α1, . . . , αl;β1, . . . , βm)f(z).
It is easy to verify from (2.2) that
(2.3) z(Hml [α1]f(z))0 =α1Hml [α1+ 1]f(z)−(α1−1)Hml [α1]f(z).
Special cases of the Dziok-Srivastava linear operator include the Hohlov lin- ear operator [9], the Carlson-Shaffer linear operatorL(a, c)[6], the Ruscheweyh derivative operatorDn [18], the generalized Bernardi-Libera-Livingston linear integral operator (cf. [3], [10], [12]) and the Srivastava-Owa fractional deriva- tive operators (cf. [16], [17]).
The main object of the present paper is to find sufficient conditions for cer- tain normalized analytic functionsf(z)to satisfy
q1(z)≺
Hml [α1]f(z) z
δ
≺q2(z)
whereq1 andq2are given univalent functions in∆.Also, we obtain the number of known results as special cases.
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3. Main Results
We begin with the following:
Theorem 3.1. Letq(z)be univalent in∆, λ ∈C andα1 >0, δ >0.Suppose q(z)satisfies
(3.1) <
1 + zq00(z) q0(z) + λ
δ
>0.
Iff ∈ Asatisfies the subordination,
(3.2) (1−λα1)
Hml [α1]f(z) z
δ
+λα1
Hml [α1]f(z) z
δ
Hml [α1 + 1]f(z) Hml [α1]f(z)
≺q(z) + λ
δzq0(z), then
Hml [α1]f(z) z
δ
≺q(z)
andq(z)is the best dominant.
Proof. Define the functionp(z)by
(3.3) p(z) :=
Hml [α1]f(z) z
δ
.
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Then
zp0(z) δ :=α1
Hml [α1]f(z) z
δ
Hml [α1+ 1]f(z) Hml [α1]f(z) −1
,
hence the hypothesis (3.2) of Theorem3.1yields the subordination:
p(z) + λzp0(z)
δ ≺q(z) + λzq0(z) δ .
Now Theorem3.1follows by applying Lemma2.2withψ = 1andγ = λδ. Whenl = 2, m = 1, α1 =a, α2 = 1,andβ1 = cin Theorem3.1, we have the following corollary.
Corollary 3.2. Let q(z)be univalent in∆, λ ∈Candα1 >0, δ >0.Suppose q(z)satisfies (3.1). Iff ∈ Aand satisfies the subordination,
(3.4) (1−λa)
L(a, c)f(z) z
δ
+λa
L(a, c)f(z) z
δ
L(a+ 1, c)f(z) L(a, c)f(z)
≺q(z) + λ
δzq0(z), then
L(a, c)f(z) z
δ
≺q(z)
andq(z)is the best dominant.
By takingl = 1, m = 0andα1 = 1in Theorem3.1, we get the following corollary.
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Corollary 3.3. Let q(z)be univalent in∆, λ ∈Candα1 >0, δ >0.Suppose q(z)satisfies (3.1). Iff ∈ Aand satisfies the subordination,
(3.5) (1−λ)
f(z) z
δ
+λ
f(z) z
δ zf0(z)
f(z)
≺q(z) + λ
δzq0(z), then
f(z) z
δ
≺q(z)
andq(z)is the best dominant.
Corollary 3.4. Let−1≤B < A≤1and (3.1) hold. Iff ∈ Aand
(1−λα1)
Hml [α1]f(z) z
δ
+λα1
Hml [α1]f(z) z
δ
Hml [α1+ 1]f(z) Hml [α1]f(z)
≺ λ(A−B)z
δ(1 +Bz)2 + 1 +Az 1 +Bz, then
Hml [α1]f(z) z
δ
≺ 1 +Az 1 +Bz and 1+Az1+Bz is the best dominant.
Theorem 3.5. Letq(z)be univalent in∆,λ, δ ∈C.Supposeq(z)satisfies
(3.6) <
1 + zq00(z)
q0(z) − zq0(z) q(z)
>0.
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Iff ∈ Asatisfies the subordination:
(3.7) 1 +γδα1
Hml [α1+ 1]f(z) Hml [α1]f(z) −1
≺1 +γzq0(z) q(z) , then
Hml [α1]f(z) z
δ
≺q(z)
andq(z)is the best dominant.
Proof. Define the functionp(z)by p(z) =
Hml [α1]f(z) z
δ
.
It is clear that p(0) = 1andp(z)is analytic in∆. By using the identity (2.3), from (3.3) we get,
(3.8) zp0(z)
p(z) =α1δ
Hml [α1+ 1]f(z) Hml [α1]f(z) −1
.
Using (3.8) in (3.7), we see that the subordination becomes 1 +γzp0(z)
p(z) ≺1 +γzq0(z) q(z) . By setting
θ(w) = 1 and ϕ(w) = γ w,
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we observe thatϕandθare analytic inC\ {0}. Also we see that Q(z) :=zq0(z)ϕ(q(z)) = γzq0(z)
q(z) , and
h(z) := ϑ(q(z)) +Q(z) = 1 +γzq0(z) q(z) . It is clear thatQ(z)is starlike univalent in∆and
<zh0(z) Q(z) =<
1 + zq00(z)
q0(z) − zq0(z) q(z)
≥0.
By the hypothesis of Theorem 3.5, the result now follows by an application of Lemma2.1.
Specializing the values ofl = 1, m = 0, α1 = 1 and q(z) = (1−z)1 2b (b ∈ C − {0}), γ = 1b and δ = 1 in Theorem 3.5 above, we have the following corollary as stated in [21].
Corollary 3.6. Letbbe a non zero complex number. Iff ∈ Aand 1 + 1
b
zf0(z) f(z) −1
≺ 1 +z 1−z,
then f(z)
z ≺ 1
(1−z)2b and (1−z)1 2b is the best dominant.
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Choosing the values of l = 1, m = 0, α1 = 1 and q(z) = (1−z)12ab (b ∈ C− {0}), γ = 1b andδ =a 6= 0in Theorem3.5above, we have the following corollary as stated in [15].
Corollary 3.7. Letbbe a non zero complex number. Iff ∈ Aand 1 + 1
b
zf0(z) f(z) −1
≺ 1 +z 1−z,
then
f(z) z
a
≺ 1
(1−z)2ab
wherea6= 0is a complex number and (1−z)12ab is the best dominant.
Similarly for l = 2, m = 1, α1 = 1, α2 = 1, β1 = 1and q(z) = (1−z)1 2b
(b ∈ C− {0}), γ = 1b andδ = 1in Theorem3.5 above, we get the following result as stated in [21].
Corollary 3.8. Letbbe a non zero complex number. Iff ∈ Aand 1 + 1
b
zf00(z) f0(z) −1
≺ 1 +z 1−z, then
f0(z)≺ 1 (1−z)2b and (1−z)1 2b is the best dominant.
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Next, applying Lemma2.3, we have the following theorem.
Theorem 3.9. Let q(z) be convex univalent in ∆, λ ∈ C and 0 < δ < 1.
Supposef ∈ Asatisfies
(3.9) Re
δ λ
>0
and
Hml[α1]f(z) z
δ
∈H[q(0),1]∩Q.Let
(1−λα1)
Hml [α1]f(z) z
δ +λα1
Hml [α1]f(z) z
δ
Hml [α1+ 1]f(z) Hml [α1]f(z)
be univalent in∆.Iff ∈ Asatisfies the superordination,
(3.10) q(z) + λ
δzq0(z)≺(1−λα1)
Hml [α1]f(z) z
δ
+λα1
Hml [α1]f(z) z
δ
Hml [α1+ 1]f(z) Hml [α1]f(z)
then
q(z)≺
Hml [α1]f(z) z
δ
andq(z)is the best subordinant.
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Proof. Define the functionp(z)by
(3.11) p(z) :=
Hml [α1]f(z) z
δ .
Using (3.11), simple computation produces zp0(z)
δ :=α1
Hml [α1]f(z) z
δ
Hml [α1+ 1]f(z) Hml [α1]f(z) −1
, then
q(z) + λ
δzq0(z)≺p(z) + λ
δzp0(z).
By setting ϑ(w) = w and φ(w) = λδ, it is easily observed that ϑ(w) is analytic inC.Also,φ(w)is analytic inC\{0}andφ(w)6= 0,(w∈C\{0}).
Sinceq(z)is a convex univalent function, it follows that
<
ϑ0(q(z)) φ(q(z))
=<
δ λ
>0, z ∈∆, δ, λ∈C, δ, λ6= 0.
Now Theorem3.9follows by applying Lemma2.3.
Concluding the results of differential subordination and superordination, we state the following sandwich result.
Theorem 3.10. Let q1 andq2 be convex univalent in∆, λ∈ Cand0< δ < 1.
Supposeq2satisfies (3.1) andq1 satisfies (3.9). If
Hml [α1]f(z) z
δ
∈ H[q(0),1]∩
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Q,
(1−λα1)
Hml [α1]f(z) z
δ +λα1
Hml [α1]f(z) z
δ
Hml [α1+ 1]f(z) Hml [α1]f(z)
is univalent in∆.Iff ∈ Asatisfies
q1(z) + λ
δzq10(z)≺(1−λα1)
Hml [α1]f(z) z
δ
(3.12)
+λα1
Hml [α1]f(z) z
δ
Hml [α1+ 1]f(z) Hml [α1]f(z)
≺q2(z) + λ
δzq02(z), then
q1(z)≺
Hml [α1]f(z) z
δ
≺q2(z)
andq1, q2are respectively the best subordinant and best dominant.
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Differential Subordinations and Superordinations for Analytic
Functions Defined by the Dziok-Srivastava Linear
Operator
G. Murugusundaramoorthy and N. Magesh
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