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Approximation of Solutions for Second-Order m-Point Nonlocal Boundary Value Problems via the Method of Generalized Quasilinearization

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Volume 2011, Article ID 929061,17pages doi:10.1155/2011/929061

Research Article

Approximation of Solutions for Second-Order m-Point Nonlocal Boundary Value Problems via the Method of Generalized Quasilinearization

Ahmed Alsaedi

Department of Mathematics, Faculty of Science, King Abdulaziz University, P.O. Box 80203, Jeddah 21589, Saudi Arabia

Correspondence should be addressed to Ahmed Alsaedi,[email protected] Received 11 May 2010; Revised 29 July 2010; Accepted 2 October 2010

Academic Editor: Gennaro Infante

Copyrightq2011 Ahmed Alsaedi. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

We discuss the existence and uniqueness of the solutions of a second-orderm-point nonlocal boundary value problem by applying a generalized quasilinearization technique. A monotone sequence of solutions converging uniformly and quadratically to a unique solution of the problem is presented.

1. Introduction

The monotone iterative technique coupled with the method of upper and lower solutions 1–7manifests itself as an effective and flexible mechanism that offers theoretical as well as constructive existence results in a closed set, generated by the lower and upper solutions. In general, the convergence of the sequence of approximate solutions given by the monotone iterative technique is at most linear 8, 9. To obtain a sequence of approximate solutions converging quadratically, we use the method of quasilinearization10. This method has been developed for a variety of problems11–20. In view of its diverse applications, this approach is quite an elegant and easier for application algorithms.

The subject of multipoint nonlocal boundary conditions, initiated by Bicadze and Samarski˘ı 21, has been addressed by many authors, for instance,22–32. The multipoint boundary conditions appear in certain problems of thermodynamics, elasticity and wave propagation, see 23and the references therein. The multipoint boundary conditions may be understood in the sense that the controllers at the endpoints dissipate or add energy according to censors located at intermediate positions.

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In this paper, we develop the method of generalized quasilinearization to obtain a sequence of approximate solutions converging monotonically and quadratically to a unique solution of the following second-orderm−point nonlocal boundary value problem

−xt f

t, xt, xt

, t∈0,1, 1.1

px0qx0 m−2

i1

τix ηi

, px1 qx1 m−2

i1

σix ηi

, ηi∈0,1, 1.2

wheref:0,1×R×R → Ris continuous andτi, σi i1,2, . . . , m−2are nonnegative real constants such thatm−2

i1 τi<1,m−2

i1 σi<1,andp, q >0 withp >1.

Here we remark that26studies1.1with the boundary conditions of the form

δx0γx0 0, x1 m−2

i1

αix ηi

, ηi∈0,1. 1.3

A perturbed integral equation equivalent to the problem1.1and1.3considered in26is

xt 1

0

kt, sf

s, xs, xs ds

m−2

i1

αix ηi

t2, 1.4

where

kt, s 1 δγ

⎧⎨

γδt

1−s, 0≤t≤s, δγs

1−t, st≤1. 1.5

It can readily be verified that the solution given by1.4does not satisfy1.1. On the other hand, by Green’s function method, a unique solution of the problem1.1and1.3is

xt 1

0

kt, sf

s, xs, xs ds

m−2

i1

αix ηi

γδt

δγ, 1.6

wherekt, sis given by1.5. Thus,1.6represents the correct form of the solution for the problem1.1and1.3.

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2. Preliminaries

ForxC10,1,we definex1xx,wherexmax{|xt|:t∈0,1}.It can easily be verified that the homogeneous problem associated with1.1-1.2 has only the trivial solution. Therefore, by Green’s function method, the solution of1.1-1.2can be written as

xt 1

0

Gt, sf

s, xs, xs ds

m−2

i1

τix ηi

−t

2qp qp p

2qp

m−2

i1

σix ηi

t

2qp q

p 2qp

,

2.1

whereGt, sis the Green’s function and is given by

Gt, s 1

p p2q

⎧⎨

qpt

qp1s

, 0≤t≤s, qps

qp1t

, s≤t≤1. 2.2

Note thatGt, s>0 on0,1×0,1.

We say thatαC20,1is a lower solution of the boundary value problem1.1and 1.2if

−αt≤f

t, αt, αt

, t∈0,1, pα00≤m−2

i1

τiα ηi

, pα1 qα1≤m−2

i1

σiα ηi

,

2.3

andβC20,1is an upper solution of1.1and1.2if

−βt≥f

t, βt, βt

, t∈0,1, pβ00≥m−2

i1

τiβ ηi

, pβ1 qβ1≥m−2

i1

σiβ ηi

. 2.4

Definition 2.1. A continuous functionh:0,∞ → 0,∞is called a Nagumo function if

λ

sds

hs ∞, 2.5

forλ ≥ 0. We say thatfC0,1 × R × Rsatisfies a Nagumo condition on0,1relative to α, βif for every t ∈ 0,1 andx ∈ mint∈0,1αt,maxt∈0,1βt, there exists a Nagumo functionhsuch that|ft, x, x| ≤h|x|.

We need the following result33to establish the main result.

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Theorem 2.2. Letf : 0,1×R2 → Rbe a continuous function satisfying the Nagumo condition onE{t, x, y∈0,1×R2 :αxβ}whereα, β:0,1 → Rare continuous functions such thatαtβtfor allt ∈ 0,1.Then there exists a constantM >0 (depending only onα, β,the Nagumo functionh) such that every solutionxof 1.1-1.2withαtxtβt,t ∈ 0,1 satisfies|x| ≤M.

If α, βC20,1 are assumed to be lower and upper solutions of 1.1-1.2, respectively, in the statement of Theorem 2.2, then there exists a solution,xtof 1.1and 1.2such thatαtxtβt,t∈0,1.

Theorem 2.3. Assume thatα, βC20,1are, respectively, lower and upper solutions of1.1-1.2.

Ifft, x, yC0,1×R×Ris decreasing inxfor eacht, y∈0,1×R,thenαβon0,1.

Proof. Let us define ut αtβt so that uC20,1 and satisfies the boundary conditions

pu0qu0≤m−2

i1

τiu ηi

, pu1 qu1≤m−2

i1

σiu ηi

. 2.6

For the sake of contradiction, letuhave a positive maximum at somet0∈0,1. Ift0 ∈0,1, then ut0 0 and ut0 ≤ 0.On the other hand, in view of the decreasing property of ft, x, yinx,we have

ut0 αt0βt0≥ −f

t0, αt0, αt0 f

t0, βt0, βt0

>0, 2.7 which is a contradiction. If we suppose that uhas a positive maximum at t0 0, then it follows from the first of boundary conditions2.6that

pu0qu0≤m−2

i1

τiu ηi

u0, 2.8

which implies thatp−1u0≤ qu0.Now asp > 1,q > 0,u0 > 0,u0≤ 0,therefore we obtain a contradiction. We have a similar contradiction att0 1.Thus, we conclude that αtβt,t∈0,1.

3. Main Results

Theorem 3.1. Assume that

A1the functions α, βC20,1are, respectively, lower and upper solutions of 1.1-1.2 such thatαβon0,1;

A2the function fC20,1 × R × R satisfies a Nagumo condition relative to α, β

and fx0 on 0,1 × mint∈0,1αt,maxt∈0,1βt × −M, M, where M is a

positive constant depending on α, β, and the Nagumo function h. Further, there exists a function φC20,1×R2 such that Ψf φ0 withΨφ ≥ 0 on 0,1× mint∈0,1αt,maxt∈0,1βt×−M, M,where

Ψ

xy2 2

∂x2 2 xy

xy 2

∂x∂x

xy2 2

∂x2. 3.1

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Then, there exists a monotone sequencen} of approximate solutions converging uniformly to a unique solution of the problems1.1-1.2.

Proof. For y ∈ R, we define ωy max{−M,min{y, M}} and consider the following modifiedm-point BVP

−xt f

t, xt, ω xt

, t∈0,1, px0qx0 m−2

i1

τix ηi

, px1 qx1 m−2

i1

σix ηi

.

3.2

We note thatα, βare, respectively, lower and upper solutions of3.2and for everyt, x ∈ 0,1×mint∈0,1αt,maxt∈0,1βt,we have

f

xhx, 3.3

whereh· hω·.As

0

sds hs

M

0

sds

hs

M

sds

hM ∞, 3.4

soh is a Nagumo function. Furthermore, there exists a constantNdepending on α, β, and Nagumo functionhsuch that

M

0

sds hs

N

0

sds hs >

max

βt:t∈0,1

−min{αt:t∈0,1}

, 3.5

whereM >max{N,α}. Thus, any solutionxof3.2withαtxtβt,t∈0,1 satisfies|x| ≤Mon0,1and hence it is a solution of1.1-1.2.

Let us define a functionF:0,1×R2 → Rby F

t, x, x f

t, x, x φ

t, x, xω x

. 3.6

In view of the assumptionA2,it follows thatFC20,1×R2and satisfiesΨF≥0 on 0,1×mint∈0,1αt,maxt∈0,1βt×−M, M.Therefore, by Taylor’s theorem, we obtain

f t, x, ω

x

f t, y, ω

y Fx

t, y, ω

y

xy Fx

t, y, ω

y

ω x

ω y

φt, x,0−φ t, y,0

f t, y, ω

y

Fx

t, y, ω y

φx

t, β,0 xy Fx

t, y, ω

y

ω x

ω y

.

3.7

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We set

H

t, x, x;y, y f

t, y, ω y

Fx

t, y, ω y

φx

t, β,0 xy Fx

t, y, ω

y

ω x

ω y

, 3.8

and observe that

f t, x, ω

x

H

t, x, x;y, y , f

t, x, ω x

H

t, x, x;x, x

. 3.9

By the mean value theorem, we can findαc1yandαc2yc1, c2depend ony, y, resp., such that

f t, y, ω

y

f

t, αt, αt

fxt, c1, c2

yαt

fxt, c1, c2 ω

y

αt

. 3.10

Letting

H1

t, x, x;y, y f

t, αt, αt

fxt, c1, c2x−αt fxt, c1, c2 ω

x

αt 3.11,

we note that

f t, y, ω

y H1

t, y, y;y, y , f

t, αt, αt H1

t, αt, αt;y, y

. 3.12

Let us defineHas

H

⎧⎨

H

t, x, x;y, y

, forxy, H1

t, x, x;y, y

, forxy. 3.13

ClearlyHis continuous and bounded on0,1×mint∈0,1αt,maxt∈0,1βt×Rand satisfies a Nagumo condition relative toα, β. For everyαtyβtandy ∈R, we consider the m-point BVP

−xH

t, x, x;y, y

, t∈0,1, px0qx0 m−2

i1

τix ηi

, px1 qx1 m−2

i1

σix ηi

.

3.14

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Using3.9,3.12and3.13, we have

H

t, αt, αt;y, y H1

t, αt, αt;y, y f

t, αt, αt

≥ −αt,

pα00≤m−2

i1

τiα ηi

, pα1 qα1≤m−2

i1

σiα ηi

, H

t, βt, βt;y, y H

t, βt, βt;y, y

f

t, βt, βt

≤ −βt,

pβ00≥m−2

i1

τiβ ηi

, pβ1 qβ1≥m−2

i1

σiβ ηi

.

3.15

Thus,α, βare lower and upper solutions of3.14, respectively. SinceHsatisfies a Nagumo condition, there exists a constantM1 > max{α}depending onα, βand a Nagumo functionsuch that any solutionxof3.14withαtxtβtsatisfies|x|< M1on0,1.

Now, we chooseα0αand consider the problem

−xH

t, x, x;α0, α0

, t∈0,1, px0qx0 m−2

i1

τix ηi

, px1 qx1 m−2

i1

σix ηi

.

3.16

UsingA1,3.9,3.12and3.13, we obtain

H

t, α0, α0;α0, α0

f

t, α0, α0

≥ −α0t,

00−00≤m−2

i1

τiα0

ηi

, 01 01≤m−2

i1

σiα0

ηi

,

H

t, βt, βt;α0, α0 H

t, βt, βt;α0, α0

f

t, βt, βt

≤ −βt,

pβ00≥m−2

i1

τiβ ηi

, pβ1 qβ1≥m−2

i1

σiβ ηi

,

3.17

which imply thatα0 andβare lower and upper solutions of3.16. Hence by Theorems2.2 and2.3, there exists a unique solutionα1of3.16such that

α0α1βt, α1M1, t∈0,1. 3.18

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Note that the uniqueness of the solution follows by Theorem 2.3. Using 3.9 and 3.13 together with the fact thatα1is solution of3.16, we find thatα1is a lower solution of3.2, that is,

−α1 H

t, α1, α1;α0, α0

f

t, α1, ω α1

, t∈0,1, 10−10 m−2

i1

τiα1

ηi

, 11 11 m−2

i1

σiα1

ηi

.

3.19

In a similar manner, it can be shown by usingA1,3.12,3.13, and3.19thatα1andβare lower and upper solutions of the followingm-point BVP

−xH

t, x, x;α1, α1

, t∈0,1, px0qx0 m−2

i1

τix ηi

, px1 qx1 m−2

i1

σix ηi

.

3.20

Again, by Theorems2.2and2.3, there exists a unique solutionα2of3.20such that

α1t≤α2t≤βt, α2t≤M1, t∈0,1. 3.21 Continuing this process successively, we obtain a bounded monotone sequence {αn} of solutions satisfying

α1t≤α2t≤α3t≤ · · · ≤αnt≤βt, t∈0,1, 3.22 whereαnis a solution of the problem

−xH

t, x, x;αn−1, αn−1

, t∈0,1, px0qx0 m−2

i1

τix ηi

, px1 qx1 m−2

i1

σix ηi

,

3.23

and is given by

xt 1

0

Gt, sH

s, αn, αn;αn−1, αn−1 ds

m−2

i1

τix ηi

−t

2qp qp p

2qp

m−2

i1

σix ηi

t

2qp q

p 2qp

.

3.24

Since H is bounded on 0,1 × mint∈0,1αt, maxt∈0,1βt × R × mint∈0,1αt, maxt∈0,1βt × R, therefore it follows that the sequences {αjn }j 0,1 are uniformly bounded and equicontinuous on 0,1. Hence, by Ascoli-Arzela theorem, there exist the subsequences and a function xC10,1 such thatαjnxj uniformly on 0,1 as

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n → ∞.Taking the limitn → ∞,we find thatHt, α n, αn;αn−1, αn−1ft, x, ωxwhich consequently yields

xt 1

0

Gt, sf

s, xs, ω xs

ds m−2

i1

τix ηi

−t

2qp qp p

2qp

m−2

i1

σix ηi

t

2qp q

p 2qp

.

3.25

This proves thatxis a solution of3.2.

Theorem 3.2. Assume thatA1andA2hold. Further, one assumes that

A3the functionFC20,1×R×Rsatisfiesy∂/∂xFt, x, y my20 for|y| ≥ M,wherem max{|Fxxt, x, y|:t, x, y∈0,1×mint∈0,1αt,maxt∈0,1βt×

−M, M},andFfφ.

Then, the convergence of the sequencen} of approximate solutions (obtained in Theorem 3.1) is quadratic.

Proof. Let us seten1t xtαn1t≥0 so thaten1satisfies the boundary conditions

pen10−qen10 m−2

i1

τien1 ηi

, pen11 qen11 m−2

i1

σien1 ηi

. 3.26

In view of the assumption A3,for every t, x ∈ 0,1×mint∈0,1αt,maxt∈0,1βt,it follows that

Fxt, x, M 2mM≤0, Fxt, x,−M−2mM≥0. 3.27 Now, by Taylor’s theorem, we have

−en1t F

t, x, x

φt, x,0

f

t, αn, ω αn

Fx

t, α, ω αn

αn1αn

φx

t, β,0

αn1αn Fx

t, αn, ω αn

ω αn1

ω αn Fx

t, αn, ω αn

x−αn1 Fx

t, αn, ω αn

xω αn1 1

2

x−αn2Fxxt, z1, z2 2x−αn xω

αn

Fxxt, z1, z2

xω αn2

Fxxt, z1, z2

φt, x,0−φt, αn,0−φx

t, β,0

αn1αn

Fx

t, αn, ω αn

xω αn1

M2

2

|x−αn|xω

αn2ρ1x−αn2, 3.28

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where αnz1x, ωαnz2x, αnξβ, M2 max{|Fxx|,|Fxx |,|Fxx|} on 0,1 ×mint∈0,1αt, maxt∈0,1βt ×−M, M and ρ1 ρmax{φxxt, x,0 : t, x,0 ∈ 0,1×mint∈0,1αt, maxt∈0,1βt}withρ >1 satisfyingβαnρxαnon0,1.Also, in view of3.13, we have

−en1t f t, x, x

H

t, αn1, αn1;αn, αn

f t, x, x

f

t, αn1, ω αn1 fxt, c3, c4en1fxt, c3, c4

xω αn1

≥ −γen1fxt, c3, c4 xω

αn1 ,

3.29

where αn1c3x, ωαn1c4x and γ max{|fxt, x, y| : t, x, y ∈ 0,1× mint∈0,1αt, maxt∈0,1βt×−M, M}.

Now we show thatωαn1t αn1t.By the mean value theorem, for everyy1

−M, Mandωαn1t≤c5y1,we obtain Fx

t, αnt, y1

Fx

t, αnt, ω

αn1t

Fxxt, αnt, c5 y1ω

αn1t

. 3.30

Letαn1> Mfor somet∈0,1.Thenωαn1t Mand3.30becomes Fx

t, αnt, y1

Fxt, αnt, M Fxxt, αnt, c5

y1M

Fxt, αnt, M−m

y1M

. 3.31

In particular, takingy1−Mand using3.27, we have

Fxt, αnt,−M≤Fxt, αnt, M 2mM≤0, 3.32 which contradicts thatFxt, αnt,−M ≥ 2mM > 0.Similarly, lettingαn1 < −Mfor some t∈0,1,we get a contradiction. Thus, it follows that|αn1t| ≤Mfor everyt∈0,1, which implies thatωαn1t αn1tand consequently,3.28and3.29take the form

−en1 t≤Fx

t, αn, ω αnt

en1t M3en21, 3.33 whereM3ρ1 M2/2and

−en1 t≥ −γen1t fxt, c3, c4en1t. 3.34 Now, by a comparison principle, we can obtainen1t≤rton0,1, wherertis a solution of the problem

−rt Fx

t, αn, ω αnt

rt M3en21, pr0qr0 m−2

i1

τien1 ηi

, pr1 qr1 m−2

i1

σien1 ηi

.

3.35

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SinceFx is continuous and bounded on0,1×mint∈0,1αt,maxt∈0,1βt×R, there exist ζ2, ζ1>0independent ofnsuch that−ζ1Fxζ2on0,1×mint∈0,1αt,maxt∈0,1βt×

−M, M.Sinceζ2Fxt, αn, ωαn≥0 on0,1,so we can rewrite3.35as rt ζ2rt

ζ2Fx

t, αn, ω αn

rt−M3en21 pr0qr0 m−2

i1

τien1 ηi

, pr1 qr1 m−2

i1

σien1 ηi

,

3.36

whose solution is given by

rt 1

0

Gζ2t, s ζ2Fx

t, αn, ω αn

rs−M3en21 ds

m−2

i1

τien1 ηi

−t

2qp qp p

2qp

m−2

i1

σien1 ηi

t

2qp q

p 2qp

3.37 where

Gζ2t, s −1 ζ2

pqζ2

/pe−ζ2

⎧⎪

⎪⎪

⎪⎨

⎪⎪

⎪⎪

1−2q p e−ζ21−s

2q pe−ζ2t

, 0≤t≤s,

e−ζ2t−s2q p e−ζ21−s

2q pe−ζ2s

, s≤t≤1, 3.38

Introducing the integrating factorμt e0tFxs,αns,ωαnsdssuch thate−ζ1t< μeζ2t,3.34 takes the form

rtμt

−M3en21μt. 3.39

Integrating3.39from 0 totand usingr0≥−1/qm−2

i1 τien1ηi,we obtain rtμt≥ −1

q

m−2

i1

τien1 ηi

M3en21 t

0

μsds, 3.40

which can alternatively be written as

rt≥ −1 qeζ1t

m−2

i1

τien1 ηi

M3

ζ2eζ1ten21 eζ2−1

≥ −1 q

m−2

i1

τien1M3

ζ2 en21 eζ2−1

−ρ1en1ρ2en21,

3.41

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whereρ1 1/qm−2

i1 τi,ρ2 M32eζ2−1. Using the fact thatGζ2t, s≤0 together with 3.41yields

Gζ2t, sζ2Fxrt≤Gζ2t, sζ2Fx

ρ1en1ρ2en21

Gζ2t, sζ2ζ1

ρ1en1ρ2en21 ,

3.42

which, on substituting in3.37, yields

en1rt≤ 1

0

Gζ2t, sζ2ζ1

ρ1en1ρ2en21

M3en21 ds

m−2

i1

τien1 ηi

−t

2qp qp p

2qp

m−2

i1

σien1 ηi

t

2qp q

p 2qp

1

0

Gζ2t, sζ2ζ1

ρ1en1ds 1

0

Gζ2t, sρ2ζ2ζ1 M3

en21

ds

m−2

i1

τim−2

i1

σi

pq p

2qp

en1 ηi

B m−2

i1

τim−2

i1

σi

pq p

2qp

en1Aen21,

3.43 where

A

ρ2ζ2ζ1 M3

max 1

0

Gζ2t, sds, B ζ2ζ1ρ1max 1

0

Gζ2t, sds. 3.44

Taking the maximum over0,1and then solving3.43foren1,we obtain

en1A

1−Bm−2

i1 τim−2

i1 σi

pq/p

2qpen21. 3.45 Also, it follows from3.33that

en1 μt

≥ −M3en21μt≥ −M3eζ2ten21, t∈0,1. 3.46

Integrating3.46from 0 totand usingvn1 0≥−1/qm−2

i1 τien1ηi from the boundary conditionpen10−qen10 m−2

i1 τien1ηi,we obtain en1 tμt≥ −1

q

m−2

i1

τien1 ηi

M3

eζ2t−1

ζ2 en21, 3.47

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which, in view of the facte−ζ1t< μeζ2tand3.45, yields

en1t≥eζ1t

⎢⎣ −1

q

m−2

i1

τi

⎛⎜⎝ A 1−Bm−2

i1 τim−2

i1 σi

pq /p

2qp

⎟⎠

M3

eζ2t−1 ζ2

$

en21≥ −δ1en21,

3.48

where

δ1max

⎧⎪

⎪⎩eζ1t

⎢⎣ 1

q

m−2

i1

τi

⎛⎜⎝ A 1−Bm−2

i1 τim−2

i1 σi

pq /p

2qp

⎟⎠

M3

eζ2t−1 ζ2

$

, t∈0,1

% .

3.49

Asen1C10,1, there existst∈0,1such that en1

t

en11−en10≤en11

≤ 1 p

m−2

i1

σien1 ηi

q

pen11≤ 1 p

m−2

i1

σien1 p en21

⎢⎣ A p

1−Bm−2

i1 σim−2

i1 τi

pq /p

2qp

m−2

i1

σi p

⎥⎦en21.

3.50

Integrating3.46fromttott≤tand using3.50, we have

en1t≤eζ1t

⎢⎣ eζ2tAm−2

i1 σi

p

1−Bm−2

i1 σim−2

i1 τi

pq /p

2qp

p M3

eζ2teζ2t ζ2

⎥⎦en21.

3.51

Using3.45in3.34, we obtain en11t

γAμ1t

1−Bm−2

i1 σim−2

i1 τi

pq /p

2qpen21, 3.52

(14)

whereμ1t e0tfxs,c3,c4ds. Sincefx is bounded on0,1×mint∈0,1αt, maxt∈0,1βt×

−M, M,we can chooseζ3, ζ4 > 0 such that −ζ3fxt,c3,c4ζ4 on0,1×mint∈0,1αt, maxt∈0,1βt×−M, Mande−ζ3t< μ1t≤eζ4tso that3.52takes the form

en11t

γAeζ4t

1−Bm−2

i1 σim−2

i1 τi

pq /p

2qpen21. 3.53

Integrating3.53fromttott≥t, and using3.51, we find that

en1t≤ 1 μ1t

⎢⎣en1 t

μ1

t

γA

eζ4teζ4t L2

1−Bm−2

i1 σim−2

i1 τi

pq /p

2qpen21

⎥⎦

eζ3t

⎢⎣ Aeζ4tm−2

i1 σi

p

1−Bm−2

i1 σim−2

i1 τi

pq /p

2qpqδeζ4t p

γA

eζ4teζ4t ζ4

1−Bm−2

i1 σim−2

i1 τi

pq /p

2qp

⎥⎦en21.

3.54

Letting

δ2max

⎧⎪

⎪⎩max

⎧⎪

⎪⎩eζ1t

⎢⎣ eζ2tAm−2

i1 σi

p

1−Bm−2

i1 σim−2

i1 τi

pq /p

2qp

p M3

eζ2teζ2t ζ2

⎥⎦, t∈ 0, t⎫

⎪⎬

⎪⎭,

max

⎧⎪

⎪⎩eζ3t

⎢⎣ Aeζ4tm−2

i1 σi

p

1−Bm−2

i1 σim−2

i1 τi

pq /p

2qpqδeζ4t p

γA

eζ4teζ4t ζ4

1−Bm−2

i1 σim−2

i1 τi

pq /p

2qp

⎥⎦, t∈ t,1%%

,

3.55

(15)

it follows from3.51and3.54that

en1t≤δ2en21. 3.56

Hence, from3.48and3.56, it follows that

,,en1,,≤δ3en21, 3.57

whereδ3max{δ1, δ2}.From3.45and3.57with

Q A

1−Bm−2

i1 σim−2

i1 τi

pq /p

2q3, 3.58

we obtain

en11en1,,vn1,,≤Qen21. 3.59

This proves the quadratic convergence inC1norm.

Example 3.3. Consider the boundary value problem

−x− 1

720tex− 1

35x−1− tx2 16

1 x2, t∈0,1, 5

4x0−11

20x0 1 7x

3 4

1

9x 4

5

, 5

4x1 11

20x1 1 3x

3 4

.

3.60

Letαt 0 andβt 1tbe, respectively, lower and upper solutions of3.60. Clearlyαt andβtare not the solutions of 3.60andαt < βt, t ∈ 0,1.Also, the assumptions of Theorem 3.1are satisfied. Thus, the conclusion ofTheorem 3.1applies to the problem3.60.

Acknowledgment

The author is grateful to the referees and professor G. Infante for their valuable suggestions and comments that led to the improvement of the original paper.

参照

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