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PII. S0161171202004507 http://ijmms.hindawi.com

© Hindawi Publishing Corp.

ON THE SOLVABILITY OF A CLASS OF SINGULAR PARABOLIC EQUATIONS WITH NONLOCAL BOUNDARY CONDITIONS

IN NONCLASSICAL FUNCTION SPACES

ABDELFATAH BOUZIANI Received 11 January 2000

The aim of this paper is to prove the existence, uniqueness, and continuous dependence upon the data of a generalized solution for certain singular parabolic equations with initial and nonlocal boundary conditions. The proof is based on an a priori estimate established in nonclassical function spaces, and on the density of the range of the operator corresponding to the abstract formulation of the considered problem.

2000 Mathematics Subject Classification: 35K20, 35B30, 35D05, 46E40, 46E99.

1. Introduction. This paper is devoted to the solvability of a certain singular para- bolic problem with a nonlocal boundary condition. It can be a part in the contribution of the development of the a priori estimates method for solving such problems. The questions related to these problems are so miscellaneous that the elaboration of a gen- eral theory is still premature. Therefore, the investigation of these problems requires at every time a separate study.

This work can be considered as a continuation of the results of Yurchuk [12], Benuar and Yurchuk [1], Bouziani [2,3,5,4,6], Bouziani and Benouar [7,8], and Mesloub and Bouziani [9], in so far as, on the one hand, the studied equation is parabolic and, on the other hand, the boundary condition is of integral type.

The remainder of the paper is divided into four sections. InSection 2, we give the statement of the problem. Then inSection 3, we first introduce the appropriate func- tion spaces needed in our investigation, the abstract formulation of the problem and the sense of the generalized solution are presented inSection 3.2, and some proper- ties of special smoothing operators are considered inSection 3.3. The uniqueness and the continuous dependence upon the data of a solution are established inSection 4.

InSection 5, the existence of the generalized solution is proved.

2. Statement of the problem. In the rectangleQ=(0, b)×(0, T ), we consider the singular parabolic equation

z=∂z

∂t−a(t) x

∂x

x∂z

∂x

=f (x, t), (2.1)

wherebandTare fixed but arbitrary positive numbers, anda(t)is a known function satisfying the following assumption.

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Assumption2.1. Fort∈[0, T ], we assume that

c0≤a(t)≤c1, a(t)≤c2. (2.2) InAssumption 2.1, and throughout, we suppose thatci(wherei=0, . . . ,4)are positive constants.

We pose the following problem for (2.1): given the dataf,Φ,µ, andM, find a function z=z(x, t)subject to the initial condition

z=z(x,0)=Φ(x), for 0≤x≤b, (2.3) the Dirichlet condition

z(b, t)=µ(t), for 0≤t≤T , Φ(b)=µ(0), (2.4) and the weighted integral condition

b

0x2z(x, t)dx=M(t) for 0≤x≤b, b

0x2Φ(x)dx=M(0). (2.5) We transform problem (2.1), (2.3), (2.4), and (2.5) with inhomogeneous boundary conditions into a problem with homogeneous boundary conditions. For this, we put z(x, t)=u(x, t)+ζ(x, t), where

ζ(x, t)=x

bµ(t)+12 b4(b−x)

M(t)−b3 4µ(t)

. (2.6)

Then, problem (2.1), (2.3), (2.4), and (2.5) can be transformed as follows: find a function u=u(x, t)satisfying

u=∂u

∂t −a(t) x

∂x

x∂u

∂x

=f (x, t)−ζ=f (x, t), (2.7) u=u(x,0)=Φ(x)−ζ=ϕ(x), (2.8)

u(b, t)=0, b

0

x2u(x, t)dx=0. (2.9)

3. Preliminaries

3.1. Function spaces. We first introduce appropriate function spaces. We denote byC0(0, b)the vector space of continuous functions with compact support in(0, b).

Since such functions are Lebesgue integrable with respect todx, we can define on C0(0, b)the bilinear form((·,·))xgiven by

(u, w)

x= b

0x(ξu)·x(ξw)dx, (3.1) wherexg=b

xg(ξ, t)dξ. We recall that((·,·))x is a scalar product onC0(0, b)for whichC0(0, b)is not complete. Thus we are led to introduce its completion.

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Definition3.1. We denote byB2,x1,(0, b)a completion ofC0(0, b) for the scalar product defined by (3.1), calledthe space of square integrable weighted primitive func- tions on(0, b)(orthe weighted Bouziani space).

Remark3.2. Ifx=1, then the spaceB2,x1,(0, b)is identified with the spaceB21,(0, b), first introduced in [2,5].

Definition3.3. We denote by B2,ρ1 (0, b)a completion of C0(0, b)for the scalar product defined by

(u, w)

ρ= T

0 t ρ(τ)u

·t ρ(τ)w

dt, (3.2)

wheretg=t

0g(x, τ)dτandρ(t)=ect.

Now, we generalize Definitions3.1and3.3of weighted Bouziani spacesB2,x1,(0, b) andB12,ρ(0, T ).

Definition3.4. Let(0, b)(resp.,(0, T )) be an open interval inR, letσ (x)(resp., ρ(t)) be a continuous function from(0, b)toR+ (resp., from(0, T )toR+), letmbe a non-negative integer and let 1≤p≤ ∞. Then we defineBm,p,σ(0, b)(resp.,Bp,ρm (0, T )) to be the completion of the spaceC0(0, b)(resp.,C0(0, T )) for the norm

uBm,∗p,σ(0,b)= b

0

xm(σ u)p

dx 1/p

, (3.3)

respectively,

uBp,ρm(0,T )=T 0

mt (ρu)p

dt 1/p

, (3.4)

and forp=2, we define a scalar product by (u, w)Bm,∗

2,σ(0,b)=

xm(σ u),xm(σ w)

L2(0,b), (3.5)

respectively,

(u, w)Bm

2,ρ(0,T )=

mt (ρu),mt (ρw)

L2(0,T ). (3.6)

Remark3.5. The spacesB0,∗2,σ(0, b)andB02,ρ(0, T )coincide (with equality of norm of graphs) with the spacesL2x(0, b)andL2ρ(0, T ), respectively; that is, by the norms of functionsufromL2x(0, b)andL2ρ(0, T )we understand the nonnegative numbers:

uL2x(0,b)= {b

0(xu)2dx}1/2anduL2ρ(0,T )= {T

0(ρ(t)u)2dt}1/2, respectively.

In this paper, we also use other weighted spaces such asL2σ(0, b), L2s(0, b), and L2r(0, T ), whereσ (x)=x2, s(x)=√

x, andr (t)= ρ(t)=ect/2, which are Hilbert spaces of (classes of) weighted square integrable functions with finite norms:

uL2σ(0,b)= b

0(σ u)2dx 1/2

, uL2s(0,b)=

b

0(su)2dx 1/2

, uL2r(0,T )=

T

0(r u)2dt 1/2

.

(3.7)

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LetHs1(0, b)= {u/u∈L2s(0, b), ∂u/∂x∈L2s(0, b),b

0x2u(x, t)dx=0}, which is the Hilbert space for the norm

uHs1(0,b)=

u2L2 s(0,b)+

∂u

∂x 2L2

s(0,b)

1/2

. (3.8)

LetHbe a Hilbert space with a norm·H. We denote byL2(0, T;H)(resp.,L2r(0, T;H)) the set of all measurable abstract functionsu(·, t)from(0, T )intoHsuch that

uL2(0,T;H)= T

0

u(·, t)2Hdt 1/2

<∞, (3.9)

respectively,

uL2r(0,T;H)=T 0

ect/2u(·, t)H2

dt 1/2

<∞. (3.10)

LetC(0, T;H)be the set of all continuous functionsu(·, t):(0, T )→Hwith uC(0,T;H)= sup

0≤τ≤T

u(·, τ)H<∞. (3.11)

We writeB2,ρ1 (0, T;H)for the space of functions from(0, T )intoHwhich are weighted Bouziani space for the measuredt. It is a Hilbert space for the norm

uB2,ρ1 (0,T;H)= T

0

t

eu(·, τ)H2

dt 1/2

. (3.12)

The following inequalities are well known and are frequently used in this paper. We list them here for convenience.

Lemma3.6. Forx∈(0, b), the following inequalities hold:

u2L2

x(0,b)≤bu2L2

s(0,b), (3.13)

u2B1,∗

2 (0,b)4u2L2 x(0,b), u2B1,∗

2,x(0,b)≤b2 2u2L2

x(0,b).

(3.14)

We are now in a position to give the abstract formulation corresponding to the problem (2.7), (2.8), and (2.9).

3.2. Abstract formulation. We consider problem (2.7), (2.8), and (2.9) as the solu- tion of the abstract equation

Lu=(f , ϕ), (3.15)

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whereLis the operator which mapsu(x, t)to the pair of elementsᏸuandu, so that

Lu=(u, u). (3.16)

We considerLas an unbounded operator with domainD(L)consisting of all func- tions u belonging toL2(0, T;B2,x1,∗(0, b))for which ∂u/∂t, (1/x)(∂u/∂x), ∂2u/∂x2 L2(0, T;B2,x1,∗(0, b))and satisfying conditions (2.9). We completeD(L)in the norm

uB= ∂u

∂t 2

L2(0,T;B1,∗2,x(0,b))+u2C(0,T;H1 s(0,b))

1/2

; (3.17)

this yields a Banach spaceB. The elements of Bare continuous functions on [0, T ] with values inHs1(0, b). Hence onB, the following mapping is defined and continuous:

:Buu=u(x,0)∈Hs1(0, b). (3.18) We writeFfor the Hilbert spaceL2(0, T;L2s(0, b))×Hs1(0, b)consisting of all elements (f , ϕ)for which the norm

(f , ϕ)F=

f2L2(0,T;L2s(0,b))2H1 s(0,b)

1/2

(3.19) is finite. We consider the operatorL with the above domain as a mapping from B intoF.

Now, we can introduce the concept of a generalized solution of problem (2.7), (2.8), and (2.9). Let ¯Lbe the closure of the operatorL.

Definition3.7. A solution of the operator equation

Lu¯ =(f , ϕ), (f , ϕ)∈F , (3.20) is calleda generalized solutionof problem (2.7), (2.8), and (2.9).

To prove the solvability of problem (2.7), (2.8), and (2.9) in the sense ofDefinition 3.7, we establish the a priori estimate

uB≤cLuF, u∈D(L). (3.21) It follows from (3.21) that there is a bounded inverseL1on the rangeR(L)ofL.

However, since we have no information concerningR(L)except that R(L)⊂F, we must extendL, so that an a priori estimate like (3.21) holds for the extension. For this, we prove thatLadmits a closure. Thus we extend (3.21) tou∈D(¯L)by passing to the limit. It follows that the closure procedure forLreduces to the closure of the rangeR(L)inF, so thatR(L)=R(¯L), and a bounded inverse ¯L−1exists onR(¯L), so the uniqueness of a generalized solution. For existence, it remains to prove thatR(L) does not have an orthogonal complement inF.

3.3. Smoothing operators. We consider the operators defined by the relations ρε−1

v=1 εt

e(1/ε)(τ−t)v

, ε >0, ρ−1ε

v= −1 εt

e(1/ε)(t−τ)v

, ε >0,

(3.22)

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wheretg=T

t g(x, τ)dτ. These operators, first proposed by Yurchuk in abstract form in [11], are used as smoothing operators with respect tot[12]. They furnish the solutions of the problems

ε∂ ρε1

v

∂t +

ρ−1ε

v=v, ρ−1ε

v(x,0)=0,

−ε∂ ρε1

v

∂t +

ρ−1ε v=v,

ρ−1ε v(x, T )=0,

(3.23)

respectively. These operators have, for all v L2(0, T , L2(0, b)), the following properties:

(P1) the functions ε1)v and ε1)v H1(0, T ), with ε1)v(x,0) = 0, and ε1)v(x, T )=0;

(P2) the operators−1ε )are conjugate to−1ε ), that is,

Q

ρε1

v·ω dx dt=

Q ρε1

ω dx dt, ∀ω∈L2(0, T ); (3.24) (P3) ε1)(∂v/∂τ)=(∂/∂t)(ρε1)v+(1/ε)et/ε·v(x,0);

(P4) T

0ε1)vL2(0,b)dt≤T

0vL2(0,b)dt andT

0 ε1)v−vL2(0,b)dt→0, when ε→0;

(P5) T

0ε−1)vL2(0,b)dt≤T

0 vL2(0,b)dtandT

0−1ε )v−vL2(0,b)dt→0, when ε→0;

(P6) ifA(t)v=a(t)(∂/∂x)(x(∂v/∂x))then A(t)

ρε1 v=

ρε1

A(τ)v+ε ρε1

A(τ) ρε1

v, (3.25)

whereA(t)v=a(t)(∂/∂x)(x(∂u/∂x)).

For the proof of these properties, see, for instance, [4].

4. Uniqueness and continuous dependence. In this section, we first establish an a priori estimate. The uniqueness and the continuous dependence of the solution upon the data then are direct corollary of it.

Theorem4.1. UnderAssumption 2.1, the solution of problem (2.7), (2.8), and (2.9) satisfies the following a priori estimate:

uB≤cLuF, (4.1)

wherecis a positive constant independent ofu.

Proof. We consider the scalar product inL2(0, τ;B1,∗2,x(0, b)∩L2s(0, b)), with 0≤ τ≤T, of (2.7) and∂u/∂t, yields

τ 0

∂u(·, t)

∂t 2B1,∗

2,x(0,b)

dt− τ

0

a(t) x

∂x

x∂u(·, t)

∂x

,∂u(·, t)

∂t

B1,∗2,x(0,b)

dt

+ τ

0

∂u(·, t)

∂t 2L2

s(0,b)

dt− τ

0

a(t) x

∂x

x∂u(·, t)

∂x

,∂u(·, t)

∂t

L2s(0,b)

dt

= τ

0

f (·, t),∂u(·, t)

∂t

B1,∗2,x(0,b)

dt+ τ

0

f (·, t),∂u(·, t)

∂t

L2s(0,b)

dt.

(4.2)

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The standard integration by parts of the second and last terms on the left-hand side of (4.2) leads to

τ

0

a(t) x

∂x

x∂u(·, t)

∂x

,∂u(·, t)

∂t

B1,∗2,x(0,b)

dt= τ

0

b 0

a(t)x∂u

∂xx

ξ∂u

∂t

dx dt,

τ

0

a(t) x

∂x

x∂u(·, t)

∂x

,∂u(·, t)

∂t

L2s(0,b)

dt=1 2

b 0a(τ)x

∂u(x, τ)

∂x 2

dx

1 2

b 0a(0)x

dx

2

dx

1 2

τ 0

b 0

a(t)x ∂u

∂x 2

dx dt.

(4.3)

Substituting (4.3) into (4.2), we get τ

0

∂u(·, t)

∂t 2B1,∗

2,x(0,b)

dt+ τ

0

∂u(·, t)

∂t 2L2

s(0,b)

dt+1 2

b 0

a(τ)x

∂u(x, τ)

∂x 2

dx

= τ

0

f ,∂u

∂t

B2,x1,∗(0,b)

dt+ τ

0

f (·, t),∂u(·, t)

∂t

L2s(0,b)

dt+1 2

b 0

a(0)x

dx 2

dx

+1 2

τ 0

b 0

a(t)x ∂u

∂x 2

dx dt− τ

0

b 0

a(t)x∂u

∂xx

ξ∂u

∂t

dx dt.

(4.4)

In light of the Cauchy inequality and inequality (3.13), the first two terms and the last term in the right-hand side of (4.4) are then majorized as follows:

τ 0

f (·, t),∂u(·, t)

∂t

B2,x1,∗(0,b)dt

≤ε1

2 τ

0f (·, t)2B1,∗

2,x(0,b)dt+ 1 2ε1

τ 0

∂u(·, t)

∂t 2B1,∗

2,x(0,b)

dt,

τ 0

f (·, t),∂u(·, t)

∂t

L2s(0,b)

dt

≤ε2

2 τ

0f (·, t)2L2

s(0,b)dt+ 1 2ε2

τ 0

∂u(·, t)

∂t 2L2

s(0,b)

dt,

τ

0

b 0

a(t)x∂u

∂xx

ξ∂u

∂t

dx dt

≤bε3

2 τ

0

a2(t) ∂u(·, t)

∂x 2L2

s(0,b)

dt+ 1 2ε3

τ 0

∂u(·, t)

∂t 2B1,∗

2,x(0,b)

dt.

(4.5)

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Combining the inequalities (4.5) with (4.4), choosingε1=3/2,ε2=3/4, andε3=3/2, and usingAssumption 2.1, we obtain

1 3

τ 0

∂u(·, t)

∂t 2B1,∗

2,x(0,b)+ ∂u(·, t)

∂t 2L2

s(0,b)

dt+c0

2

∂u(·, τ)

∂x 2L2

s(0,b)

3 4

τ

0f (·, t)2B1,∗

2,x(0,b)dt+3 8

τ

0f (·, t)2L2

s(0,b)dt+c1

2

dx 2L2

s(0,b)

+3bc12 4

τ 0

∂u(·, t)

∂x 2L2

s(0,b)

dt.

(4.6)

Observing that 1

3u(·, τ)2L2 s(0,b)1

3ϕ2L2 s(0,b)+1

3 τ

0u(·, t)2L2

s(0,b)dt+1 3

τ 0

∂u(·, t)

∂t 2L2

s(0,b)

dt, (4.7) it follows by using (3.13) and (3.14) that

τ 0

∂u(·, t)

∂t 2B1,∗

2,x(0,b)

dt+u(·, τ)2H1 s(0,b)

≤c3

τ

0f (·, t)2L2

s(0,b)dt+ϕ2H1 s(0,b)

+c4

τ

0u(·, t)2H1 s(0,b)dt,

(4.8)

where

c3=max c1/2,3

1+b3 /8 min

1/3, c0/2 , c4=max

1/3,3bc21/4 min

1/3, c0/2 . (4.9) We eliminate the last term on the right-hand side of (4.8). To do that we use [3, Lemma 3.1] to obtain

τ 0

∂u(·, t)

∂t 2B1,∗

2,x(0,b)

dt+u(·, τ)2H1

s(0,b)

≤c3exp

c4TT

0 −f (·, t)2L2

s(0,b)dt+ϕ2H1 s(0,b)

.

(4.10)

Since the right-hand side here does not depend onτ; we take the upper bound of the left-hand side onτ from 0 toT; hence (4.1) holds withc=c1/23 exp(c4T /2), and this provesTheorem 4.1.

We show that the operator L admits a closure, that is, the closure of the graph G(L)⊂B×F ofLis a graphG(¯L)=G(L)of operator ¯L.

Proposition4.2. The operatorL:B→Fwith domainD(L)has a closure.

Proof. For the proof, the reader should refer to [10].

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We extend the a priori estimate (4.1) tou∈D(¯L)by passing to the limit, that is, uB≤c¯LuF, ∀u∈D¯L

. (4.11)

From (4.11) we conclude the following corollaries.

Corollary 4.3. Let the conditions of Theorem 4.1be satisfied. If problem (2.7), (2.8), and (2.9), has a generalized solution, then this solution is unique and depends continuously on(f , ϕ).

Corollary4.4. The rangeR(L)¯ of¯Lis closed inFandR(¯L)=R(L), whereR(L)is the range ofL.

5. The existence of the solution. Now we want to prove the solvability of our prob- lem. Our existence theorem reads as follows.

Theorem5.1. There exists a functionu∈C(0, T;Hs1(0, b))with∂u/∂t∈L2(0, T; B2,x1,(0, b))which solves problem (2.7), (2.8), and (2.9) in the sense ofDefinition 3.7, for arbitraryf∈L2(0, T;L2s(0, b))andϕ∈Hs1(0, b).

Proof. Corollary 4.4shows that, to prove that (2.7), (2.8), and (2.9) has a general- ized solution for each(f , ϕ)∈F, it is sufficient to show thatR(L)is dense inF. For this we need the following proposition.

Proposition5.2. If T

0

u(·, t), ω(·, t)

L2s(0,b)dt=0, (5.1)

for some functionω∈L2(0, T;L2s(0, b))and allu∈D0(L)= {u/u∈D(L):u=0}, thenω≡0almost everywhere inQ.

Proof of the proposition. Equation (5.1) may be written in the form T

0

∂u(·, t)

∂t , ω(·, t)

L2s(0,b)

dt= T

0

A(t)u, ω(·, t)

L2(0,b)dt. (5.2) Substitute in (5.2)uby the smooth functionρε1u, hence by property (P3) it follows that

T 0

ρε1∂u

∂τ, ω(·, t)

L2s(0,b)

dt= T

0

A(t)ρε1u, ω(·, t)

L2(0,b)dt. (5.3) Applying property (P6) to the right-hand side of (5.3), we get

T 0

ρε1∂u

∂τ, ω(·, t)

L2s(0,b)

dt= T

0

ρε1A(t)u+ερε1A(t)ρε1u, ω(·, t)

L2(0,b)dt.

(5.4) According to property (P2), it follows that

T 0

∂u(·, t)

∂t , ρε1

ω

L2s(0,b)

dt= T

0

A(t)u+εA(t)ρε1u, ρε1

ω

L2(0,b)dt. (5.5)

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The standard integration by parts with respect totof the left-hand side of (5.5) leads to T

0

u(·, t),∂ ρε1

ω

∂t

L2s(0,b)

dt= T

0

A(t)u+εA(t)ρ−1ε u, ρ−1ε

ω

L2(0,b)dt. (5.6) The operatorA(t) with boundary conditions (2.9) has, onL2(0, b), a continuous in- verse. Hence, it is easy to see that

T 0

u(·, t),∂ ρε−1ω

∂t

L2s(0,b)dt

= T

0

A(t)u+εA(t)ρ−1ε A−1(t)A(t)u, ρε−1

ω

L2(0,b)dt

= T

0

A(t)u+εΛε(t)A(t)u, ρε1

ω

L2(0,b)dt

= T

0

A(t)u, I+εΛε

ρ−1ε ω

L2(0,b)dt.

(5.7)

The calculations ofA1(t), Λε(t), andΛε(t)are straightforward but somewhat te- dious. We only give their definitions

A1(t)g= 1 a(t)

b x

ξ

b

ξ g(η, t)dη+ 1 a(t)logx

b b

0g(x, t)dx, Λε(t)g=a(t)ρε1 1

a(τ)g(x, τ), Λε(t)

ρ−1ε ω= 1 a(t)

ρε−1a(τ)

ρε−1ω.

(5.8)

The left-hand side of (5.7) shows that the mappingT

0(A(t)u, Kε(t)(ρε1)ω)L2(0,b)dt is a continuous linear functional ofu, where

Kε(t)

ρε−1ω=

I+εΛε(t)

ρ−1ε ω, (5.9)

if the functionKεhas the following properties:

∂Kε

∂x ∈L2

0, T;L2(0, b) ,

∂x

x∂Kε

∂x

∈L2

0, T;L2(0, b)

, (5.10)

and satisfies

Kεx

=0=Kεx

=b=0. (5.11)

Therefore, we conclude from (5.9) and (5.11) that

I+ε 1 a(t)

ρ−1ε

a(τ) ρ−1ε

ω|x=0=0. (5.12) For each fixedx∈[0, b]and sufficiently smallε, the operator

I+ε 1

a(t) ρε1

a(τ) ρε1

(5.13)

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has a continuous inverse operator onL2(0, T ). Thus from (5.12) we obtain

ω|x=0=ω|x=b=0. (5.14)

We set

ω(x, t)=x3v−3x

ξ2v

. (5.15)

From (5.14) and (5.15), we conclude that b

0x2v(x, t)dx=0, v(b, t)=0. (5.16) If we substitute (5.15) into (5.2), we obtain

T 0

∂u(·, t)

∂t , x4v(·, t)−3xx

ξ2v(·, t)

L2(0,b)

dt

= T

0

A(t)u, x3v(·, t)−3x

ξ2v(·, t)

L2(0,b)dt.

(5.17)

Now we put

u= t ev

= t

0

ev(x, τ)dτ (5.18)

in (5.17), wherecis a constant such that

cc0−c236b2c120, (5.19) and integrating by parts by taking into account (5.16), we get

T 0

∂u(·, t)

∂t , x4v(·, t)−3xx

ξ2v(·, t)

L2(0,b)

dt

= T

0

b

0ectx4v2dx dt+3 2

T 0

b 0ect

x(ξv)2

dx dt, T

0

A(t)u, x3v(·, t)−3x

ξ2v(·, t)

L2(0,b)dt

= −1 2

b

0ecTa(T )x4 T

ectv

∂x 2

dx

1 2

T 0

b 0

e−ctx4

ca(t)−a(t)t

ev

∂x 2

dx dt

6 T

0

b

0x3a(t)v t

ev

∂x

dx dt.

(5.20)

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Substituting (5.20) into (5.17), yields T

0

b 0

ectx4v2dx dt+3 2

T 0

b 0

ect

x(ξv)2

dx dt

= −1 2

b

0ecTa(T )x4 T

ectv

∂x 2

dx

1 2

T 0

b 0

e−ctx4

ca(t)−a(t)t ev

∂x 2

dx dt

6 T

0

b 0

x3a(t)v t

ev

∂x

dx dt.

(5.21)

The application of the Cauchy inequality to the last term of the above equality gives T

0

b

0ectx4v2dx dt+ T

0

b 0ect

x(ξv)2

dx dt

≤ −1 2

b 0

e−cTa(T )x4 T

ectv

∂x 2

dx

T

0

b 0

e−ctx4

ca(t)−a(t)−36x2a2(t)∂t

ev

∂x 2

dx dt.

(5.22)

According toAssumption 2.1and inequality (5.19), we get v2L2

r(0,T;L2σ(0,b))+v2L2

r(0,T;B1,∗2,x(0,b))

≤ −

cc0−c236b2c12 v2B1

2,ρ(0,T;L2σ(0,b))0,

(5.23)

and thusv≡0, henceω≡0 almost everywhere inQ. This provesProposition 5.2.

Returning to the proof ofTheorem 5.1. SinceF is a Hilbert space, the density of R(L)inFis equivalent to the property that orthogonality of a vectorW=(ω, ω0)∈F to the rangeR(L), that is, the identity

T 0

u(·, t), ω(·, t)

L2s(0,b)dt+ u, ω0

Hs1(0,b)=0, ∀u∈D(L), (5.24) impliesW≡0. In particular, ifu∈D0(L)then conclude byProposition 5.2thatω≡0.

Thus (5.24) implies that

u, ω0

H1s(0,b)=0, u∈D(L). (5.25)

Now since R() is dense inHs1(0, b), it follows thatω00. Hence R(L)=F. This completes the proof ofTheorem 5.1.

Acknowledgment. This work was supported by “Le Centre Universitaire Larbi Ben M’hidi de Oum El Bouaghi.”

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References

[1] N. I. Benuar and N. I. Yurchuk,A mixed problem with an integral condition for parabolic equations with a Bessel operator, Differentsial nye Uravneniya27(1991), no. 12, 2094–2098.

[2] A. Bouziani,Mixed problem with boundary integral conditions for a certain parabolic equation, J. Appl. Math. Stochastic Anal.9(1996), no. 3, 323–330.

[3] , Solution forte d’un problème mixte avec condition intégrale pour une classe d’équations paraboliques, Maghreb Math. Rev.6(1997), no. 1, 1–17 (French).

[4] ,On a third order parabolic equation with a nonlocal boundary condition, J. Appl.

Math. Stochastic Anal.13(2000), no. 2, 181–195.

[5] ,On a class of nonclassical hyperbolic equations with nonlocal conditions, to appear in J. Appl. Math. Stochastic Anal., 2002.

[6] ,On the quasi-static flexure of a thermoelastic rod, to appear in Commun. Appl.

Anal., 2002.

[7] A. Bouziani and N. E. Benouar,Problème mixte avec conditions intégrales pour une classe d’équations paraboliques, C. R. Acad. Sci. Paris Sér. I Math.321(1995), no. 9, 1177–

1182 (French).

[8] ,Mixed problem with integral conditions for a third order parabolic equation, Kobe J. Math.15(1998), no. 1, 47–58.

[9] S. Mesloub and A. Bouziani,Problème mixte avec conditions aux limites intégrales pour une classe d’équations paraboliques bidimensionnelles, Acad. Roy. Belg. Bull. Cl. Sci.

(6)9(1998), no. 1-6, 61–72.

[10] ,On a class of singular hyperbolic equation with a weighted integral condition, Int.

J. Math. Math. Sci.22(1999), no. 3, 511–519.

[11] N. I. Yurchuk,Solvability of boundary value problems for certain operator-differential equations, Differensial’nye Uravneniya13(1977), no. 4, 626–636.

[12] ,A mixed problem with an integral condition for some parabolic equations, Differ- entsial nye Uravneniya22(1986), no. 12, 2117–2126.

Abdelfatah Bouziani: Département de Mathématiques, Centre Universitaire Larbi Ben M’hidi-Oum El Bouagui, B.P.565, 04000, Algeria

Current address:Mathematical Division, The Abdus Salam International Centre for Theoretical Physics (ICTP), Strada Costiera11,34100Trieste, Italy

E-mail address:[email protected]

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Mathematical Problems in Engineering

Special Issue on

Modeling Experimental Nonlinear Dynamics and Chaotic Scenarios

Call for Papers

Thinking about nonlinearity in engineering areas, up to the 70s, was focused on intentionally built nonlinear parts in order to improve the operational characteristics of a device or system. Keying, saturation, hysteretic phenomena, and dead zones were added to existing devices increasing their behavior diversity and precision. In this context, an intrinsic nonlinearity was treated just as a linear approximation, around equilibrium points.

Inspired on the rediscovering of the richness of nonlinear and chaotic phenomena, engineers started using analytical tools from “Qualitative Theory of Di

erential Equations,”

allowing more precise analysis and synthesis, in order to produce new vital products and services. Bifurcation theory, dynamical systems and chaos started to be part of the mandatory set of tools for design engineers.

This proposed special edition of the Mathematical Prob-

lems in Engineering aims to provide a picture of the impor-

tance of the bifurcation theory, relating it with nonlinear and chaotic dynamics for natural and engineered systems.

Ideas of how this dynamics can be captured through precisely tailored real and numerical experiments and understanding by the combination of specific tools that associate dynamical system theory and geometric tools in a very clever, sophis- ticated, and at the same time simple and unique analytical environment are the subject of this issue, allowing new methods to design high-precision devices and equipment.

Authors should follow the Mathematical Problems in Engineering manuscript format described at

http://www .hindawi.com/journals/mpe/. Prospective authors should

submit an electronic copy of their complete manuscript through the journal Manuscript Tracking System at

http://

mts.hindawi.com/

according to the following timetable:

Manuscript Due December 1, 2008 First Round of Reviews March 1, 2009 Publication Date June 1, 2009

Guest Editors

José Roberto Castilho Piqueira,

Telecommunication and Control Engineering Department, Polytechnic School, The University of São Paulo, 05508-970 São Paulo, Brazil;

[email protected]

Elbert E. Neher Macau,

Laboratório Associado de Matemática Aplicada e Computação (LAC), Instituto Nacional de Pesquisas Espaciais (INPE), São Josè dos Campos, 12227-010 São Paulo, Brazil ; [email protected]

Celso Grebogi,

Center for Applied Dynamics Research, King’s College, University of Aberdeen, Aberdeen AB24 3UE, UK; [email protected]

Hindawi Publishing Corporation http://www.hindawi.com

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