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ISSN: 1072-6691. URL: http://ejde.math.txstate.edu or http://ejde.math.unt.edu ftp ejde.math.txstate.edu

EXISTENCE, UNIQUENESS AND SMOOTHNESS OF A SOLUTION FOR 3D NAVIER-STOKES EQUATIONS WITH ANY

SMOOTH INITIAL VELOCITY

ARKADIY TSIONSKIY, MIKHAIL TSIONSKIY

Abstract. Solutions of the Navier-Stokes and Euler equations with initial conditions for 2D and 3D cases were obtained in the form of converging se- ries, by an analytical iterative method using Fourier and Laplace transforms in [28, 29]. There the solutions are infinitely differentiable functions, and for sev- eral combinations of parameters numerical results are presented. This article provides a detailed proof of the existence, uniqueness and smoothness of the solution of the Cauchy problem for the 3D Navier-Stokes equations with any smooth initial velocity. When the viscosity tends to zero, this proof applies also to the Euler equations.

1. Introduction

Many authors have obtained results regarding the Euler and Navier-Stokes equa- tions. Existence and smoothness of solution for the Navier-Stokes equations in two dimensions have been known for a long time. Leray (1934) showed that the Navier- Stokes equations in three dimensional space have a weak solution. Scheffer (1976, 1993) and Shnirelman (1997) obtained weak solution of the Euler equations with compact support in space-time. Caffarelli, Kohn and Nirenberg (1982) improved Scheffer’s results, and Lin (1998) simplified the proof of the results by Leray. Many problems and conjectures about behavior of weak solutions of the Euler and Navier- Stokes equations are described in the books by Ladyzhenskaya (1969), Temam (1977), Constantin (2001), Bertozzi and Majda (2002) or Lemari´e-Rieusset (2002).

The solution of the Cauchy problem for the 3D Navier-Stokes equations is de- scribed in this article. We will consider an initial velocity that is infinitely differ- entiable and decreasing rapidly to zero in infinity. The applied force is assumed to be identically zero. A solution of the problem will be presented in the following stages:

First stage (sections 2, 3). We move the non-linear parts of equations to the right side. Then we solve the system of linear partial differential equations with constant coefficients. We have obtained the solution of this system using Fourier

2000Mathematics Subject Classification. 35Q30, 76D05.

Key words and phrases. 3D Navier-Stokes equations; Fourier transform; Laplace transform;

fixed point principle.

c

2013 Texas State University - San Marcos.

Submitted December 10, 2012. Published April 5, 2013.

1

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transforms for the space coordinates and Laplace transform for time. From the- orems about applications of Fourier and Laplace transforms, for system of linear partial differential equations with constant coefficients, we see that in this case if initial velocity and applied force are smooth enough functions decreasing in infin- ity, then the solution of such system is also a smooth function. Corresponding theorems are presented in Bochner [3], Palamodov [18], Shilov [23], Hormander [9], Mizohata [17], Treves [27]. The result of this stage is an integral equation for the vector-function of velocity.

Second stage (sections 4, 5). We introduce perfect spaces of functions and vector-functions (Gel’fand, Chilov [7]), in which we look for the solution of the problem. We demonstrate the equivalence of solving the Cauchy problem in differ- ential form and in the form of an integral equation.

Third stage (section 6). We divide all parts of the integral equation by an appropriate constant depending on value of initial fluid velocity, and obtain the equivalent integral equation. We also replace the corresponding integration vari- ables in the integral operators. This newly received equivalent integral equation allowed us to analyze the Cauchy problem for the 3D Navier-Stokes equations for any value of initial fluid velocity. According to a priori estimate of the solution of the Cauchy problem for the 3D Navier-Stokes equations [13, 12], the described constant is proportional to max of the norms of the initial velocity in the spaces C2and L2.

Fourth stage(section 6). We use the newly obtained equivalent integral equa- tion to prove the existence and uniqueness of the solution of the Cauchy problem in the time range [0,∞) based on the Caccioppoli-Banach fixed point theorem (Kan- torovich, Akilov [10], Trenogin [26], Rudin [20], Kirk and Sims [11], Granas and Dugundji [8], Ayerbe Toledano, Dominguez Benavides, Lopez Acedo [1]). For this purpose the following three theorems are proven in this article: Theorem 6.1: the integral operator of the problem is a contraction operator; Theorem 6.2: the ex- istence and uniqueness of the solution of the problem is valid for any t ∈ [0,∞);

Theorem 6.3: the solution of the problem depends continuously ont.

Fifth stage(section 6). By using a priori estimate of the solution of the Cauchy problem for the 3D Navier-Stokes equations [13, 12], we show that the energy of the whole process has a finite value for anyt in [0,∞).

2. Mathematical setup

The Navier-Stokes equations describe the motion of a fluid inRN (N = 3). We look for a viscous incompressible fluid filling all of RN here. The Navier-Stokes equations are then given by

∂uk

∂t +

N

X

n=1

un∂uk

∂xn

=ν∆uk− ∂p

∂xk

+fk(x, t) x∈RN, t≥0, 1≤k≤N , (2.1)

div~u=

N

X

n=1

∂un

∂xn

= 0 x∈RN, t≥0, (2.2)

with initial conditions

~u(x,0) =~u0(x) x∈RN. (2.3) Here~u(x, t) = (uk(x, t))∈RN (1≤k≤N) is an unknown velocity vector, N= 3;

p(x, t) is an unknown pressure; ~u0(x) is a given C divergence-free vector field;

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fk(x, t) are components of a given, externally applied forcef~(x, t);ν is a positive coefficient of the viscosity (ifν = 0 then (2.1)–(2.3) are the Euler equations); and

∆ =PN n=1

2

∂x2n is the Laplacian in the space variables. Equation (2.1) is Newton’s law for a fluid element. Equation (2.2) says that the fluid is incompressible. For physically reasonable solutions, we accept

uk(x, t)→0, ∂uk

∂xn →0 as |x| → ∞ 1≤k≤N, 1≤n≤N . (2.4) Hence, we will restrict attention to initial conditions~u0 and forcef~that satisfy

|∂xα~u0(x)| ≤CαK(1 +|x|)−K onRN for anyαand anyK. (2.5) and

|∂xαtβf~(x, t)| ≤CαβK(1 +|x|+t)−K onRN×[0,∞) for anyα, β and anyK.

(2.6) To start the process of solution let us add −PN

n=1un∂u∂xk

n to both sides of the equations (2.1). Then we have

∂uk

∂t =ν∆uk− ∂p

∂xk

+fk(x, t)−

N

X

n=1

un∂uk

∂xn

x∈RN, t≥0, 1≤k≤N, (2.7)

div~u=

N

X

n=1

∂un

∂xn

= 0 x∈RN, t≥0, (2.8)

~

u(x,0) =~u0(x) x∈RN, (2.9) uk(x, t)→0 ∂uk

∂xn

→0 as|x| → ∞ 1≤k≤N, 1≤n≤N, (2.10)

|∂xα~u0(x)| ≤CαK(1 +|x|)−K onRN for anyαand anyK, (2.11)

|∂xαtβf~(x, t)| ≤CαβK(1 +|x|+t)−K onRN×[0,∞) for anyα, β and anyK.

(2.12) Let us denote

k(x, t) =fk(x, t)−

N

X

n=1

un

∂uk

∂xn

1≤k≤N . (2.13)

We can present it in the vector form as

f(x, t) =f(x, t)~ −(~u· ∇)~u . (2.14) 3. Solution of the system (2.7)–(2.14)

Let us assume that all operations below are valid. The validity of these operations will be proved in the next sections. Taking into account our substitution (2.13) we see that (2.7)–(2.9) are in fact system of linear partial differential equations with constant coefficients.

The solution of this system will be presented by the following steps:

First step. We use Fourier transform (7.1) to solve equations (2.7)–(2.14). We obtain:

Uk1, γ2, γ3, t) =F[uk(x1, x2, x3, t)],

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−γs2Uk1, γ2, γ3, t) =F[∂2uk(x1, x2, x3, t)

∂x2s ] (use (2.10)), Uk01, γ2, γ3) =F[u0k(x1, x2, x3)],

P(γ1, γ2, γ3, t) =F[p(x1, x2, x3, t)], F˜k1, γ2, γ3, t) =F[ ˜fk(x1, x2, x3, t)], fork, s= 1,2,3. Then

dU11, γ2, γ3, t)

dt =−ν(γ122232)U11, γ2, γ3, t) +iγ1P(γ1, γ2, γ3, t) + ˜F11, γ2, γ3, t),

(3.1) dU21, γ2, γ3, t)

dt =−ν(γ122232)U21, γ2, γ3, t) +iγ2P(γ1, γ2, γ3, t) + ˜F21, γ2, γ3, t),

(3.2) dU31, γ2, γ3, t)

dt =−ν(γ122232)U31, γ2, γ3, t) +iγ3P(γ1, γ2, γ3, t) + ˜F31, γ2, γ3, t),

(3.3) γ1U11, γ2, γ3, t) +γ2U21, γ2, γ3, t) +γ3U31, γ2, γ3, t) = 0, (3.4) U11, γ2, γ3,0) =U101, γ2, γ3), (3.5) U21, γ2, γ3,0) =U201, γ2, γ3), (3.6) U31, γ2, γ3,0) =U301, γ2, γ3). (3.7) Hence, we have received a system of linear ordinary differential equations with constant coefficients (3.1)-(3.7) according to Fourier transforms. At the same time the initial conditions are set only for Fourier transforms of velocity components U11, γ2, γ3, t), U21, γ2, γ3, t),U31, γ2, γ3, t). Because of that we can eliminate Fourier transform for pressureP(γ1, γ2, γ3, t) from equations (3.1)–(3.3) on the next step of the solution process.

Second step. From here assuming that γ1 6= 0, γ2 6= 0, γ3 6= 0, we eliminate P(γ1, γ2, γ3, t) from equations (3.1)−(3.3) and find

d

dt[U21, γ2, γ3, t)−γ2 γ1

U11, γ2, γ3, t)]

=−ν(γ122232)[U21, γ2, γ3, t)−γ2

γ1

U11, γ2, γ3, t)]

+ [ ˜F21, γ2, γ3, t)−γ2

γ1

11, γ2, γ3, t)],

(3.8)

d

dt[U31, γ2, γ3, t)−γ3 γ1

U11, γ2, γ3, t)]

=−ν(γ122232)[U31, γ2, γ3, t)−γ3

γ1U11, γ2, γ3, t)]

+ [ ˜F31, γ2, γ3, t)−γ3

γ1

11, γ2, γ3, t)],

(3.9)

γ1U11, γ2, γ3, t) +γ2U21, γ2, γ3, t) +γ3U31, γ2, γ3, t) = 0, (3.10) U11, γ2, γ3,0) =U101, γ2, γ3), (3.11) U21, γ2, γ3,0) =U201, γ2, γ3), (3.12)

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U31, γ2, γ3,0) =U301, γ2, γ3). (3.13) Third step. We use Laplace transform (7.2), (7.3) for a system of linear or- dinary differential equations with constant coefficients (3.8)–(3.10) and have as a result the system of linear algebraic equations with constant coefficients:

Uk1, γ2, γ3, η) =L[Uk1, γ2, γ3, t)] k= 1,2,3; (3.14) F˜k1, γ2, γ3, η) =L[ ˜Fk1, γ2, γ3, t)] k= 1,2,3; (3.15) η[U21, γ2, γ3, η)−γ2

γ1U11, γ2, γ3, η)]

−[U21, γ2, γ3,0)−γ2

γ1

U11, γ2, γ3,0)]

=−ν(γ212232)[U21, γ2, γ3, η)−γ2 γ1

U11, γ2, γ3, η)]

+ [ ˜F21, γ2, γ3, η)−γ2

γ1

11, γ2, γ3, η)],

(3.16)

η[U31, γ2, γ3, η)−γ3

γ1

U11, γ2, γ3, η)]

−[U31, γ2, γ3,0)−γ3 γ1

U11, γ2, γ3,0)]

=−ν(γ212232)[U31, γ2, γ3, η)−γ3

γ1U11, γ2, γ3, η)]

+ [ ˜F31, γ2, γ3, η)−γ3

γ1

11, γ2, γ3, η)],

(3.17)

γ1U11, γ2, γ3, η) +γ2U21, γ2, γ3, η) +γ3U31, γ2, γ3, η) = 0, (3.18) U11, γ2, γ3,0) =U101, γ2, γ3), (3.19) U21, γ2, γ3,0) =U201, γ2, γ3), (3.20) U31, γ2, γ3,0) =U301, γ2, γ3). (3.21) Let us rewrite system of equations (3.16)–(3.18) in the form

[η+ν(γ122232)]γ2

γ1

U11, γ2, γ3, η)

−[η+ν(γ122223)]U21, γ2, γ3, η)

= [γ2 γ1

11, γ2, γ3, η)−F˜21, γ2, γ3, η)]

+ [γ2

γ1

U11, γ2, γ3,0)−U21, γ2, γ3,0)],

(3.22)

[η+ν(γ122232)]γ3

γ1U11, γ2, γ3, η)

−[η+ν(γ122223)]U31, γ2, γ3, η)

= [γ3

γ1

11, γ2, γ3, η)−F˜31, γ2, γ3, η)]

+ [γ3 γ1

U11, γ2, γ3,0)−U31, γ2, γ3,0)],

(3.23)

γ1U11, γ2, γ3, η) +γ2U21, γ2, γ3, η) +γ3U31, γ2, γ3, η) = 0 (3.24)

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The determinant of this system is

∆ =

[η+ν(γ122232)]γγ2

1 −[η+ν(γ122232)] 0 [η+ν(γ122232)]γγ3

1 0 −[η+ν(γ212223)]

γ1 γ2 γ3

= [η+ν(γ122232)]2122232)

γ1 6= 0.

(3.25) Consequently the system of equations (3.16)–(3.18) and/or (3.22)–(3.24) has a unique solution. Taking into account formulas (3.19)–(3.21) we can write this so- lution in the form

U11, γ2, γ3, η)

= [(γ2232) ˜F11, γ2, γ3, η)−γ1γ221, γ2, γ3, η)−γ1γ331, γ2, γ3, η)]

122232)[η+ν(γ122232)]

+ U101, γ2, γ3) [η+ν(γ122232)],

(3.26) U21, γ2, γ3, η)

= [(γ3212) ˜F21, γ2, γ3, η)−γ2γ331, γ2, γ3, η)−γ2γ111, γ2, γ3, η)]

122232)[η+ν(γ122232)]

+ U201, γ2, γ3) [η+ν(γ122232)],

(3.27) U31, γ2, γ3, η)

= [(γ1222) ˜F31, γ2, γ3, η)−γ3γ111, γ2, γ3, η)−γ3γ221, γ2, γ3, η)]

122232)[η+ν(γ122232)]

+ U301, γ2, γ3) [η+ν(γ122232)].

(3.28)

Then we use the convolution theorem with the convolution formula (7.4) and inte- gral (7.5) for (3.26)–(3.28) to obtain

U11, γ2, γ3, t)

= Z t

0

e−ν(γ212232)(t−τ)

×[(γ2232) ˜F11, γ2, γ3, τ)−γ1γ221, γ2, γ3, τ)−γ1γ331, γ2, γ3, τ)]

122232) dτ

+e−ν(γ122232)tU101, γ2, γ3),

(3.29)

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U21, γ2, γ3, t)

= Z t

0

e−ν(γ212232)(t−τ)

×[(γ3212) ˜F21, γ2, γ3, τ)−γ2γ331, γ2, γ3, τ)−γ2γ111, γ2, γ3, τ)]

122232) dτ

+e−ν(γ122232)tU201, γ2, γ3),

(3.30) U31, γ2, γ3, t)

= Z t

0

e−ν(γ212232)(t−τ)

×[(γ1222) ˜F31, γ2, γ3, τ)−γ3γ111, γ2, γ3, τ)−γ3γ221, γ2, γ3, τ)]

122232) dτ

+e−ν(γ122232)tU301, γ2, γ3).

(3.31) Using the Fourier inversion formula (7.1) we obtain

u1(x1, x2, x3, t)

= 1

(2π)3/2 Z

−∞

Z

−∞

Z

−∞

hZ t 0

e−ν(γ212223)(t−τ)[(γ2232) ˜F11, γ2, γ3, τ)]

122232) dτ

− Z t

0

e−ν(γ122232)(t−τ)1γ221, γ2, γ3, τ) +γ1γ331, γ2, γ3, τ)]

122232) dτ +e−ν(γ122232)tU101, γ2, γ3)i

e−i(x1γ1+x2γ2+x3γ3)123

= 1

3 Z

−∞

Z

−∞

Z

−∞

2223) (γ122232)

hZ t 0

e−ν(γ212223)(t−τ)

× Z

−∞

Z

−∞

Z

−∞

ei(˜x1γ1x2γ2x3γ3)1(˜x1,x˜2,x˜3, τ)d˜x1d˜x2d˜x3dτi

×e−i(x1γ1+x2γ2+x3γ3)123

− 1 8π3

Z

−∞

Z

−∞

Z

−∞

γ1γ2212223)

hZ t 0

e−ν(γ122223)(t−τ)

× Z

−∞

Z

−∞

Z

−∞

ei(˜x1γ1x2γ2x3γ3)2(˜x1,x˜2,x˜3, τ)d˜x1d˜x2d˜x3dτi

×e−i(x1γ1+x2γ2+x3γ3)123

− 1 8π3

Z

−∞

Z

−∞

Z

−∞

γ1γ3212223)

hZ t 0

e−ν(γ122223)(t−τ)

× Z

−∞

Z

−∞

Z

−∞

ei(˜x1γ1x2γ2x3γ3)3(˜x1,x˜2,x˜3, τ)d˜x1d˜x2d˜x3dτi

×e−i(x1γ1+x2γ2+x3γ3)123 + 1

3 Z

−∞

Z

−∞

Z

−∞

e−ν(γ122232)t

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×hZ

−∞

Z

−∞

Z

−∞

ei(˜x1γ1x2γ2x3γ3)u01(˜x1,x˜2,x˜3)d˜x1d˜x2d˜x3

i

×e−i(x1γ1+x2γ2+x3γ3)123

=S11( ˜f1) +S12( ˜f2) +S13( ˜f3) +B(u01) (3.32) (see Remark 7.1);

u2(x1, x2, x3, t)

= 1

(2π)3/2 Z

−∞

Z

−∞

Z

−∞

hZ t 0

e−ν(γ212223)(t−τ)[(γ3212) ˜F21, γ2, γ3, τ)]

122232) dτ

− Z t

0

e−ν(γ122232)(t−τ)2γ331, γ2, γ3, τ) +γ2γ111, γ2, γ3, τ)]

122232) dτ +e−ν(γ122232)tU201, γ2, γ3)i

e−i(x1γ1+x2γ2+x3γ3)123

=− 1 8π3

Z

−∞

Z

−∞

Z

−∞

γ2γ1122232)

hZ t 0

e−ν(γ122232)(t−τ)

× Z

−∞

Z

−∞

Z

−∞

ei(˜x1γ1x2γ2x3γ3)1(˜x1,x˜2,x˜3, τ)d˜x1d˜x2d˜x3dτi

×e−i(x1γ1+x2γ2+x3γ3)123 + 1

3 Z

−∞

Z

−∞

Z

−∞

3212) (γ212223)

hZ t 0

e−ν(γ122223)(t−τ)

× Z

−∞

Z

−∞

Z

−∞

ei(˜x1γ1x2γ2x3γ3)2(˜x1,x˜2,x˜3, τ)d˜x1d˜x2d˜x3dτi

×e−i(x1γ1+x2γ2+x3γ3)123

− 1 8π3

Z

−∞

Z

−∞

Z

−∞

γ2γ3212223)

hZ t 0

e−ν(γ122223)(t−τ)

× Z

−∞

Z

−∞

Z

−∞

ei(˜x1γ1x2γ2x3γ3)3(˜x1,x˜2,x˜3, τ)d˜x1d˜x2d˜x3dτi

×e−i(x1γ1+x2γ2+x3γ3)123 + 1

3 Z

−∞

Z

−∞

Z

−∞

e−ν(γ122232)t

×hZ

−∞

Z

−∞

Z

−∞

ei(˜x1γ1x2γ2x3γ3)u02(˜x1,x˜2,x˜3)d˜x1d˜x2d˜x3

i

×e−i(x1γ1+x2γ2+x3γ3)123

=S21( ˜f1) +S22( ˜f2) +S23( ˜f3) +B(u02), (3.33) (see Remark 7.1);

u3(x1, x2, x3, t)

= 1

(2π)3/2 Z

−∞

Z

−∞

Z

−∞

hZ t 0

e−ν(γ212223)(t−τ)[(γ1222) ˜F31, γ2, γ3, τ)]

122232) dτ

− Z t

0

e−ν(γ122232)(t−τ)3γ111, γ2, γ3, τ) +γ3γ221, γ2, γ3, τ)]

122232) dτ

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+e−ν(γ122232)tU301, γ2, γ3)i

e−i(x1γ1+x2γ2+x3γ3)123

=− 1 8π3

Z

−∞

Z

−∞

Z

−∞

γ3γ1

122232) hZ t

0

e−ν(γ122232)(t−τ)

× Z

−∞

Z

−∞

Z

−∞

ei(˜x1γ1x2γ2x3γ3)1(˜x1,x˜2,x˜3, τ)d˜x1d˜x2d˜x3dτi

×e−i(x1γ1+x2γ2+x3γ3)123

− 1 8π3

Z

−∞

Z

−∞

Z

−∞

γ3γ2

212223) hZ t

0

e−ν(γ122223)(t−τ)

× Z

−∞

Z

−∞

Z

−∞

ei(˜x1γ1x2γ2x3γ3)2(˜x1,x˜2,x˜3, τ)d˜x1d˜x2d˜x3dτi

×e−i(x1γ1+x2γ2+x3γ3)123

+ 1 8π3

Z

−∞

Z

−∞

Z

−∞

1222) (γ212223)

hZ t 0

e−ν(γ122223)(t−τ)

× Z

−∞

Z

−∞

Z

−∞

ei(˜x1γ1x2γ2x3γ3)3(˜x1,x˜2,x˜3, τ)d˜x1d˜x2d˜x3dτi

×e−i(x1γ1+x2γ2+x3γ3)123

+ 1 8π3

Z

−∞

Z

−∞

Z

−∞

e−ν(γ122232)t

×hZ

−∞

Z

−∞

Z

−∞

ei(˜x1γ1x2γ2x3γ3)u03(˜x1,x˜2,x˜3)d˜x1d˜x2d˜x3

i

×e−i(x1γ1+x2γ2+x3γ3)123

=S31( ˜f1) +S32( ˜f2) +S33( ˜f3) +B(u03), (3.34) (see Remark 7.1).

HereS11(),S12(),S13(),S21(),S22(),S23(),S31(),S32(),S33(),B() are integral operators, and satisfy

S12() =S21(), S13() =S31(), S23() =S32().

From the three expressions above foru1, u2, u3, it follows that the vector~ucan be represented as:

~

u= ¯S¯·f~˜+ ¯B¯·~u0= ¯S¯·f~−S¯¯·(~u· ∇)~u+ ¯B¯·~u0, (3.35) wheref~˜is determined by formula (2.14).

Here ¯S¯and ¯B¯ are the matrix integral operators:

S11 S12 S13

S21 S22 S23

S31 S32 S33

,

B 0 0

0 B 0

0 0 B

.

4. Spaces S andT S~

As in [7, 19], we consider the spaceSof all infinitely differentiable functionsϕ(x) defined inN-dimensional space RN (N = 3), such that these functions tend to 0 as|x| → ∞, as well as their derivatives of any order, more rapidly than any power of 1/|x|.

(10)

To define a topology in the spaceS let us introduce countable system of norms kϕkp= sup

x

|xkDqϕ(x)|,|k| ≤p,|q| ≤p p= 0,1,2, . . . , (4.1) where

|xkDqϕ(x)|=|xk11. . . xkNNq1+···+qNϕ(x)

∂xq11. . . ∂xqNN |, k= (k1, . . . , kN), q= (q1, . . . , qN), xk=xk11. . . xkNN,

Dq = ∂q1+···+qN

∂xq11. . . ∂xqNN, q1, . . . , qN = 0,1,2, . . . .

Note that S is a perfect space (complete countably normed space, in which the bounded sets are compact). The spaceT S~ of vector-functions ϕ~ is a direct sum of N perfect spacesS (N = 3) [26]:

T S~ =S⊕S⊕S.

To define a topology in the spaceT S~ let us introduce countable system of norms kϕk~ p=

N

X

i=1

ikp=

N

X

i=1

sup

x

|xkDqϕi(x)|, |k| ≤p,|q| ≤p , (4.2) N = 3, p= 0,1,2, . . .. The Fourier transform maps the spaceS onto the whole spaceS, and maps the spaceT S~ onto the whole spaceT S~ [23, 7].

5. Equivalence of the Cauchy problem in differential form (2.1)–(2.3) and in integral form

Let us denote solution of (2.1)–(2.3) as{~u(x1, x2, x3, t), p(x1, x2, x3,t)}; in other words let us consider the infinitely differentiable by t ∈ [0,∞) vector-function

~

u(x1, x2, x3, t)∈T S, and infinitely differentiable function~ p(x1, x2, x3, t)∈S, that turn equations (2.1) and (2.2) into identities. Vector-function ~u(x1, x2, x3, t) also satisfies the initial condition (2.3) (~u0(x1, x2, x3)∈T S):~

~

u(x1, x2, x3, t)|t=0=~u0(x1, x2, x3) (5.1) Let us put{~u(x1, x2, x3, t), p(x1, x2, x3, t)} into equations (2.1), (2.2) and apply Fourier and Laplace transforms to the result identities considering initial condition (2.3). After all required operations (as in sections 2 and 3) we receive that vector- function~u(x1, x2, x3, t) satisfies integral equation

~

u= ¯S¯·f~−S¯¯·(~u· ∇)~u+ ¯B¯·~u0 = ¯S¯·~u (5.2) Then the vector-function gradp∈T S~ is defined by equations (2.1) where vector- function~uis defined by (5.2).

Here f~ ∈ T S,~ ~u0 ∈ T S~ and ¯S,¯ B,¯¯ S¯¯ are matrix integral operators. Vector- functions ¯S¯·f~, ¯B¯ ·~u0, ¯S¯·(~u· ∇)~u also belongT S~ since Fourier transform maps perfect spaceT S~ ontoT S.~

Going from the other side, let us assume that~u(x1, x2, x3, t)∈T S~ is continuous int∈[0,∞) solution of integral equation (5.2). Integral-operatorsSij·(~u· ∇)~uare continuous int∈[0,∞) [see (3.32)–(3.34)]. From here we obtain that according to (5.2),

~

u(x1, x2, x3,0) =~u0(x1, x2, x3)

参照

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