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Explicit Exponential Decay Bounds in Quasilinear Parabolic Problems
G.A.PHILIPPINa.,andS.VERNIER PIROb
aDpartementdemathmatiques etdestatistique, Universit Laval, Quebec, Canada, G1K 7P4,"bDipartimentodi matematica,
Universit&diCagliari, 09124 Cagliari,Italy
(Received2March 1997; Revised 3September1997)
Thispaper dealswith classical solutionsu(x, t)ofsomeinitialboundaryvalueproblems involvingthequasilinear parabolicequation
g(k(t)lVul2)ZXu
+f(u) ut, xEf, >O,wheref,g,karegivenfunctions.Inthe case of onespace variable,i.e.whenf :=(-L, L),
weestablishamaximumprinciple fortheauxiliaryfunction
(t)
ao g()d+cu +2 f(s)dswherecis anarbitrary nonnegativeparameter.Insome casesthis maximumprinciple may be used to deriveexplicit exponential decayboundsforluland
luxl.
Someextensions inN space dimensions are indicated. This work may be considered as a continuation of previous works byPayneand Philippin (MathematicalModelsand MethodsinApplied Sciences, 5(1995),95-110;Decayboundsinquasilinear parabolicproblems, In:Nonlinear ProblemsinAppliedMathematics, Ed.by T.S. Angell, L. Pamela, Cook,R.E., SIAM, 1997).Keywords: Maximumprinciples for quasilinear parabolic equations AMSClassification." 35K55,35K60,35K20
Correspondingauthor.
1 INTRODUCTION
Usingamaximumprincipleapproach
Payne
and Philippin[8]
derived pointwise decay bounds for solutions ofsome initial boundary value problems involving the parabolic differential equationAu +f(u)=
ut,xE9t,
>
0, where ft is abounded convexdomain in 1Ru.
Thispaper deals with classical solutionsu(x, t)
of some initial boundary value problems involving the quasilinear parabolic equationg(k(t)lVul2)Au + f(u)
-u,, x 2,>
0,wheref,g,kare givenfunctions. In Section 2 we considerthe case of onespacevariable x E
(-L, L).
Undercertainhypotheses weestablish amaximum principle forthe auxiliaryfunctiong() d
/cu2/2f(s)
dsJO
(2)
where cis anarbitrary nonnegative parameter.
When
f
is zero and k is an exponential function we compute in Section 3.1 acritical value c0 that depends on the boundary condi- tionsandon g in suchaway that for0_<
c<
c0, takesits maximum value initially.Thisfact leadstoexplicit exponentialdecaybounds foru]
and]Ux].
When
f
is not zero and k 1, we show under certain assumptions thatiftheinitialdatau(x, 0)
isnonnegative and smallenoughin some sensethatwillbe made precisein Section3.2, thesolutionu(x, t)
cannot blow upin finite time. Dependingonfwe
thendeterminec <
c0 such that for 0_<
c<
c, takes its maximum value initially. This leads againtoexplicit exponentialdecaybounds foru(>_0)
and]u].
In Section4, the results ofSections2and 3.1 areextendedin
u
inthecaseofthe parabolic equation
g(k(t)lul2)/ku-
ut,x Q,>
0. We referto[9] for a similarinvestigation involvingtheparabolic equation(g(lul2)7u)-
ut,x, >
O.For maximum principle results related to parabolic partial differ- ential equationswerefer to[10-14].
2 MAXIMUM PRINCIPLE FOR
(X, t)
Inthis section we establishthe following result.THEOP,EM Let
u(x, t)
be the solutionof
the initial boundary valueproblem
g(kux)Uxx
2+ f(u)
ut, xE(-L,L),
E(0, T), (3)
u(+L, t)
0,[0, T], (4)1
u(x, o) h(x),
xwith
h(+L)
O, h O. Let(x, t)
bedefined
onu(x, t)
bywherec isanarbitrarynonnegativeparameterandwith
F(s) f()
d,(6)
(7)
G(cr) g() d. (S)
Assume that thegiven
functions
g C2,
k C arestrictlypositive and satisfy the inequality(2ck k’)[crg(a) G(cr)] >
0,(0, T),
cr>
0,(9)
andthat the given
function f
ECsatisfies
the inequalitysf(s) 2F(s) >_
0, s. (10)
We then conclude that b takes its maximum value eitherat an interior critical point
(2, {) of
u,orinitially. Inother words wehave{
),
withUx(,
-{ 0 (i),(x, t) <_
maxmax[_c,/]
(x, O)
(ii).(11)
Fortheproofof Theorem wecompute
ffx 2e2at
{UxUxxg(kux)+
2 a UUx+f(U)Ux}
2eZatux(U + ou), (12)
dxx 2e
2ct{2k UxUxx
2 2gt +
gUxx
2+
g UxUxxx+
au2x+
oz UUxx 4-f Ux
2 4-fUxx}
2 2
+fUxx},
2e2at{gUxx
4- UxUxt 4-oux4-oUUxx(13)
’t-
e2t k’Igku2x G(ku2x)] +
2gUxUxt+ 2auut + 2fur
+2a
+2F(u) (14)
Combining
(13)
and(14)
weobtainaftersome reduction gbxxt e2t{ (2ak- k’)[gk Ux-
2G(k Ux)]
2+
2gUxx
22f
22auf- 2o2u
2-4aF(u)}.
From
(12)
wecomputegUxx
1/2 u- xe
-2t(f + au). (16)
Inserting
(16)
into(15)
weobtainthe parabolicdifferentialinequality gbxx+ u-2c(x, t)’x ’t
e2’t{ (2ok- -k’)[gku
x-2G(ku2x)]+2a[uf 2F(u)] }
_>0,(17)
wherethe last inequalityin
(17)
follows from(9)
and(10).
In (17), c(x,t)
isregularthroughout (-L,
L)
(0, T). Itthen followsfrom Nirenberg’s maximumprinciple[6,10]that takesits maximumvalue(i)at a criticalpoint
(2, )
of u, or(ii)initially, or(iii)at aboundarypoint(, )
with2 +L,
"
E(0, T].
TheconclusionofTheorem willfollowif we canshowthat(iii)implies(i)or(ii).If fact
(12)
andtheboundaryconditions(4)1,
implyx(+L, t)-0.
It then follows from Friedman’s maximum principle[3,10]that qcantakeitsmaximumvalueat aboundarypoint(2, )
with2 +Lonly if isidenticallyconstantin(-L, L)
x(0, ),
inwhich casethetwopossibilities(i)and(ii)holdin
(11).
Thisachieves the proofofTheorem 1.Itisworthyto notethat canbeconstant only forsomeparticular choice ofthe data inproblem
(3), (4)1, (5).
In fact const, implies equalityin(17),
i.e. alsoin(9)
andin(10).
Thisimplies then thatf(u) Au, A
const.,(18)
andthat
either
k(t)
e2at or g const.(19)
Moreover ff)=const, implies 6x-Ux(Ut-+-aU)=_O from which we concludeeither
ux=O
orut+au=-O. (20)
Thefirstequationin
(20),
togetherwith(3)
and(18),
leadstou(x,t)
=eat, (21)
which isimpossiblein viewof
(4)1.
Thesecond equationin(20)
leadstou(x, t) h(x)e -t, (22)
whichsolves
(3)
onlyif wehaveg(h’:Z)h" + (A + a)h
O, x(-L, L). (23)
Toconcludethis section we notethat Theorem remainstrue even if we replace(4)1
byanyoneof the following pairsofboundaryconditions:(-c, t) x(C, t)
0,Ux(-C, t) .(c, t) o, .x(-C, t) ,,x(I, t) o.
(4)2
(4)3
(4)4
Moreoverifboth inequalities
(9)
and(10)
inTheorem arereversedwe then conclude that takesits minimumvalueeitherat a criticalpoint of u,orinitially.3 ELIMINATION OF THE FIRST POSSIBILITY (i) IN (11)
We note that the realizationof(ii) in
(11)
leads to lower exponential decaybounds for bothlul
andluxl.
Inthis section weimposerestrictions on the parameter c_>
0 so that the first possibility (i) in(11)
cannotoccur.Weshall investigatetwoparticularcases.
3.1 First
Case:f (u)"-
0,k(t)
e2#t,
I OWe consider the parabolic problem
(3),
(4)k, k-1,2,3 or 4, and(5)
with the particular choices
f(u)
O,k(t)
e2t,
# const._<
c. We assume(9)
sothat theconclusion(11)
of Theorem holds.Notethatif#"-c, assumption
(9)
is satisfied for any arbitrary functiong>
0. If#
<
c,(9)
is satisfied ifandonlyifg’ >
0.Suppose
thatwehavethefirstpossibility(i)in(11),
i.e.(x, t) <_ cu2(, )e
2cu2e 2", (27)
with
uI
maxuZ(x, ). (28)
Wecan rewrite
(27)
evaluatedat ase-2’G(e2UUx )2 <
c(u2rvi u2(x, -)). (29)
Making use of the mean value theorem we may bound the left hand sideof
(29)
as follows:2(X,
-)gmin_< e-21-{G(e2U-iU2x),
b/x
(30)
wheregmin
>
0istheminimumvalue ofg.From(29)
and(30)
weobtain the inequality2(X,/)groin _< Ce(U U2(X,/)),
/x
(3)
that may berewritten as
(32)
Integrating
(32)
from thecriticalpoint2tothenearest zeroI-L, L]
of
u(x, ),
weobtain7r2gmin
(33)
c
> co
41- l
2"Since
12 1
isunknown,weneedanupper bound forthisquantityin(33).
ObviouslywemayuseL if we have
(4)1
12 l < A
:= 2L if wehave(4),
k 2,3 or4,(34)
ifweassume theexistenceof
[-L, L]
when wehave theboundaryconditions
(4)4.
This willbe thecasee.g.iftheinitialdatah(x)
havezero meanvalue,i.e. if wehavec
h(x)
dx O.(35)
L
Infactwiththe auxiliaryfunctionp(r)definedby 1/2
fO
p(cr) 0"- g()-l/2
d,(36)
wehave
dfC u(x, t)
dxfc ut(x, t)
dxg(e2"tU2x)Uxx
dxdt L -L L
fL(p(e2lZtU2x)Ux)xdx
Lp(e21tUx)UXl_L2
L O.(37)
Itthenfollows from
(35)
and(37)
thatu(x, t)
dxh(x)
dx 0,L L
vt e [o, r], (38)
i.e. the zero mean value property of
u(x, t)
is inherited from thezero mean value property of the initial data if we have the boundary conditions(4)4.
Butthisimplies theexistenceof EI-L, L]
such thatu(L t)
0.We conclude from the above investigation that, for 0
<_
a<_
ao, the first possibility(i) in(11)
cannothold, sothat[u
and[Ux[
must decayexponentially. This showsinfact that
u(x, t)
cannot blow up andwill existfor all>
0. These resultsaresummarized next.THEOREM 2 Let
u(x, t)
be thesolutionof
the parabolicproblem(3), (4)k
k 1,2, 3,or4, and(5). If
wehave(4)4
werequirethat theinitialdatah(x)
satisfy the
further
condition(35).
Assumeeither#-a
<
ao,(39)
OF
#
<
a< ao
andg’
>_O,(40)
with
7l’2gmin
a0:= 4A2
(41)
where
A
isdefined
in(34).
Then we may take T-oc in(3)
and(4).
Moreover the
function
bdefined
as(x, t)"- e:t{e-2UtG(e2’tUx) + au2}, (42)
takes its maximum value initially. The resulting inequality
(11)
withc
co
takes theform
e-2’tG(e2UtU2x) + cou
:<_ H2e -2"t, V# <_
co,(43)
with
H2 max
{G(h ’) + c0h2}. (44)
Wenotethat the quantitiesCoandH2areexplicitelycomputablein termsof theinitial andboundary data.
A
weakerbutmorepracticalversionof(43)
is2
(X, t)
-}- O0u2 __ H2e
-2ctgminUx
(45)
Integrating
(45)
over(-L, L)
we obtain2
(X, t)dx + co
u2dx_< 2LH2e-2’. (46)
gmin
Ux
L L
Moreover depending of the boundary conditions
(4), u(x,t)
is admissible for the variational characterization of the first or second eigenvalue of a vibrating string oflength 2L with fixed or free ends.Wehave actually
gmin
Ux(X
2t)
dx>_ co
dx,L L
(47)
valid in all cases considered in Theorem 2. From
(46)
and(47)
weobtain the following decay bound for
f_L
u2dx:L
U2(
x,t)
dx< LcIH2e -2t.
L
(48)
We shall now derive a pointwise lower bound for[u(x,t)[
that isproportional to the distance
Ix- 1
from x to the nearest zero ofu(x, t).
Tothis endwe rewrite(45)
asv/(ga/oo)e-2Co
t-u2(49)
Integrating
(49)
for fixed from x toX we obtain\He--otj ao
v/(n2/oo)e-2oo, 2 V
gmin(so)
or
lu(x,t)l
H__Ix- 1 e-’,
x(-t,t), >
O.(51)
Ofcourse we can substitute by
+L
or -L if wehave theboundary conditions(4)k, k 1,2,3.3.2 SecondCase:
f (u) O, k(t)
Inthis section we considerthe parabolicproblem
(3),
(4)k,k 1,2, 3or 4, and(5)
withthe particularchoicek(t)=
1,f(u)
O. Itiswell known that thesolutionu(x, t)
ofthisproblem maynot existfor alltime.Infactu(x, t)
may blow upat sometimet*whichmay befinite or infinite[1,3].Howeverifblow-up does occurat
t*,
then u(x,t)
will exist on the time interval(0, t*).
We want to establish conditions involving the data sufficient to prevent blow-up of u(x,
t)
and even sufficient to guarantee its expo- nentialdecay. Tothis endwefirst establishthe following comparison result.LEMMA Let
u(x, t)
be thesolutionof
the parabolicproblem(3), (4)
k 1,2,3, or4, and(5)
withh(x)>
0 andk(t)=
1.Assumemoreover the followingconditionsonf
and g:sf’(s) >_ f(s) >
0, s>
0,f(0)
-0,(52) 71"2gmin
f(UM) <
S0 :=(53)
#’-- UM 4A2
g’(cr) >
0, cr>_
0,(54)
where
u2
has beendefined
in(28).
Wethen have thefollowing boundsfor
u(x,
t):
O<-u(x’t)<-Uexp{(f(uM)
uMc)t} (55)
with
U max 2
+__G(h,2). (56)
(-L,L) O0
Wenotethatcondition
(52)
impliescondition(10)
andthe factthat theratiof(s)/s
is anondecreasingfunction ofs.The lowerbound in
(55)
follows from Nirenberg’s and Friedman’s maximumprinciples[3,6,10]. To establishthe upper boundin(55)
we introduce anauxiliaryfunctionv(x, t)
defined asu(x, t) v(x, t)e "t, (57)
with#
"--f(UM)/U
M.Inserting(57)
into(3)
weobtainet[g(e2tV2x)Vxx vt] u(# -f(--) >_
O,(58)
where the above inequality results from the definition of# together with the monotonicity of
f(s)/s.
The auxiliary functionv(x, t)
then satisfies2/zt 2
g(e Vx)Vxx
Vt>_
O, x E(-L,L), tE(0, T), (59)
v(x, O) h(x),
x(-L, L). (60)
Moreover
v(x, t)
satisfies thesame boundary conditions(4)
asu(x,t).
Let
w(x, t)
satisfyg(e2’tW2x)Wxx
wt O, x(-L, L), (0, T), (61)
w(x,O)=h(x), x(-L,L), (62)
withthesameboundaryconditions asuand v.From
(59)
and(61)
we have2
g(e2"’Wx)Wxx (v w), >
O.g(e2U’Vx)Vxx (63)
Using the mean value theoremwemay rewrite the first two termsin
(63)
as follows:(64)
for some intermediate value
.
We conclude from(63)
and(64)
that the function "-v-w satisfies a parabolic inequality of the follow- ing form:g(e2#t Vx)xx
2+ C(x, t)x
ot>_ O,
xE(-L, L), (0, T), (65)
where
C(x, t)
is regular throughout(-L, L) (0, T).
Sinceo(x, 0)-
0 andsinceo satisfieszero Dirichlet orNeumannboundary conditions, itfollows that(66)
From(57)
and(66)
weobtain0
< u(x, t) <_ eUtw(x, t). (67)
Finallysince we assume
(53)
and(54)
wemayuse(43)
toboundw(x, t).
Dropping thefirst term in
(43)
we obtainO0
W2 HZe -2t, (68)
where H2 is defined in
(44).
The desired inequality(55)
follows now from(67)
and(68).
Lemma isthemain tool inthederivationof the following result.
THEOREM 3 Let
u(x, t)
be thesolutionof
problem(3),
(4)k,k 1,2, 3or4, and
(5)
withh(x) >_
O, andk(t)=
1. Assume(52)-(54).
Moreoverassumethat thedatainproblem
(3)-(5)
are smallenough in thefollow-
ing sense:
f(U) 7r2gmin
---U-- < co 4A---2-, (69)
where Uis
defined
in(56).
Thenu(x, t)
existsfor
alltime>
0(i.e. wemay take T=c inproblem
(3)-(5)).
Moreoverwehavemax
f(u(x, t))
<
so, Vt>
0.(70)
(-L,L)
U(X, t)
For the proofof Theorem 3 we assume that
(70)
is not valid and show that this invalidity is self-contradictory. From the definition of UwehaveU_> max
h(x). (71)
(-L,L)
Since
f(s)/s
isnondecreasing,(71)
and(69)
implyf(h) < f(
-’<
s0.(72)
h U
If
(70)
i violated, thereexists in viewof(72)
afirst time 7-forwhichwehave
max
’’u---t]( co. (73)
(-L,L) U
With
f(UM)/U
M<__
max(_L,L)(f(u)/u),
weobtainf(UM) _<
SO.
(74)
UM From
(55)
and(74)
weobtainu(x,t) <_ U,
x E(-L,L),
O<_ <_
7-,(75)
and weconclude that
maxf(U(x, 7-)) <f(U)<
co,(76)
(-,)
u(x, -)
Uso that
(70)
cannot actually be violated in a finite time7-. Thisestab- lishes(70)
with7--.
Weare nowpreparedto establishthe following result:
THEOREM 4 Let
u(x, t)
be thesolutionof
theparabolicproblem(3),
(4)k, k- 1,2or3, and(5)
withh(x) >_
O,k(t)
1.Assume(52)-(54).
Moreover assumethat the datainproblem(3)-(5)
aresmallenoughinthesense thatthereexists a constant
c >
0such that the inequalityU(U) <
a0 al(77)
U
is satisfied, where U is
defined
in(56).
Then we conclude that thefirst
possibility(i) in
(11)
cannotholdVc,
0<_
c<_ c.
Weare then ledto thefollowingdecaybound
for uZand
u2.x.G(u2x) +
OelU2-k-2F(u) _< 7-2e-2a’t,
x E(-L, L), >
0(78)
(validfor
alltime> O)
with7-g2 max
{G(h ’z) + alh
2+ 2F(h)}. (79)
(-L,L)
Before proving Theorem 4weshow that therealization of(i)in
(11)
with
c--c
implies the inequalityf(UM)
_>
oe0 o1.(80)
btM
Infact therealizationof(i)in
(11)
withc"-c implies the inequality u22F(u)
e2c’’{G(u2x(X, t)) +
c,+ } _< [cu + 2F(uM)]e 2’, (8)
where
u
is defined in(28).
Evaluatedat t-,
weobtainG(u2x(X, )) _< c [u U2(X, -)] + 2IF(urn)- F(u(x, ))]. (82)
Using the generalized mean value theorem and the monotonicity of
f(s)/s
we mayrewrite the last termin(82)
as follows:F(UM) F(u(x,-{)) [u u2(x, -)]
F(UM) F(u(x,-{))
u u2(x,-{)
[U2M ue(x, -)] 12f(UM)[U h u2(x, [)], (83)
2
UMwhere is someintermediatevalue ofu.Moreoverthe left handsideof
(82)
may be bounded as follows:<_
groin
Ux (84)
withgmin-g(0). From
(82)-(84)
we obtain the inequality(
gminUx(X )
Cel nt-[U2M U2(X, -)],
UM ,/
(85)
that may be rewritten as
V/u2
Mu2(
x,)
min o1 -{- btM(86)
Inte.grating
(86)
from the critical point to the nearest end +L of theinterval(-L, L)
withu(, t)
0, we obtain(80).
Fortheproofof Theorem 4wenotethat the assumption
(77)
implies(69),
sothatconclusion(70)
of Theorem3holds.Inparticularwehaveand
(55)
leads tof(UM) <_
C0, Vt
>
0,(87)
b/M
/’/M
U, (88)
from which we obtain using the monotonicity of
f(s)/s
and assump- tion(77)
f(UM) < f(U)
<
c0 c,(89)
UM U
in contradiction to
(80),
so that (i) in(11)
cannot hold. The inequality(78)
follows now from (ii) in(11).
This achieves the proof ofTheorem4.As
anexample, letu(x, t)
be thesolutionof the following parabolic differential equation:Uxx
V/1 + Uax +
u + ut,xe ,
,t>0,(90)
withtheboundaryconditions
u
,t
-u ,t -0,(91)
andwiththeinitialcondition
u(x, O)
acosx, a const.>
0.(92)
With e const.
_>
0, the functionf(s)’-s
+ satisfies(52).
With g(e):=(1 + or) /2,
condition(54)
is satisfied. Sinceg(s)isincreasingwe havegmin-1. From(56)
withc0- andh(x)-a
cos x wecompute/ fo /1/2/aZ
sinxU max 2COS2X nt- d
[(1
nt-a2)
3/2(-Tr/2jr/2)
(93)
FromTheorem 3weconclude thatu(x, t)
existsfor alltime>
0if(69)
is satisfied, i.e. if we have 0
<
a< V/(5/2)
)/3- 0.917. FromTheorem 4 we have the decay estimate
(78)
withc--1-{2/
3[(1 + a2)
3/21]}
e/2>
0.4 EXTENSION TO THE N-DIMENSIONAL CASE
The results ofSections2 and 3.1 may be extended in caseofNspace variables
X’--(X,...,Xu),
N>2. In this section we establish the followingmaximumprincipleanalogoustoTheorem 1.THEOREM 5 Let f be a bounded convex domain in ]RNwith a C2+ boundary 0. Let u(x, t) be the solution
of
the initial boundary value problemg(k(t)lVul2)/ku-
ut, xE f, E(0, T), (94)
u(x,t)=0,
xE0f,tE(0, T), (95)
u(x, 0) h(x),
x, (96)
wheregandkaregiven positivefunctions,g C
2,
k C1.
LetI,(x, t)
bedeft’ned
onu(x, t)
byG(k(t)[Vu[2) )e2t
(x, t)
:-+ (97)
with
G(r) g() d. (98)
In
(97),
a is an arbitrarynonnegative parameter, and isaconstant to bechosenin(0, 1)
as indicatedbelow. We distinguish two cases.If g’(cr) >_
O, we assume2ak-
k’ >
0,(99)
andweassumethattwo constants
A >
0and(0, 1)
canbedetermined such thatg(r) A(A,N,)crg’(cr) >_
O, cr>_
O,( oo)
with
A
(A, N,/3)
:-- max{ AN,
ANq--A-1 -/3
-2/ (101)
If g’(cr) <_
O, weassumek’(z) >_o, (102)
andweassumethat (0,
1)
canbe determinedsuch thatcrg(r) -/3G(r) >_
O, r>_
O,( o3)
g(cr) + B(N, )crg’(r) >_
O, cr>_
O,(104)
with
{ 1}
B(N, 3)
max N-l,1-/3 (105)
We then conclude that
,I:,(x, t)
takes its maximum value either at an interiorcritical point(, ) of
u, or initially. Inother words we have(x, t) <
max{ max (’ ) (x, 0)
withVu(, -)
0 (ii).(i),(106)
Wenotethe presence ofa
factor/3
inthedecayexponent of(x, t).
Thisfactor makes Theorem 5 lesssharpthan Theorem corresponding totheone-dimensional case.
The existence of a classical solution of
(94)-(96)
will not be investigated inthispaper.Wereferto[1,5]
for suchexistenceresults.For the proof of Theorem 5 we proceed in two steps. We first construct aparabolic inequality of the following type:
C
g(k(t)lVul2)m
/IVu[-2e(x, t). V ,t
0,(107)
where thevectorfield
c(x, t)
isregular
throughoutf x(0, T).
Using the following notations"u,i’-Ou/Oxi,
i-1,...,N,U,ik’--02u/OxiOxk,
i,k-1,...,
N, u,t-Ou/Ot,
u,iv,i-Ni=
u,il,iu. ,
etc.,wecompute,- [gklul G(k(t)lul=)] + 2uu + 2gusus
1G(klVul2)/ou
2}e 2c/t, (108)
+2
,1 2{gu,ikU,i
/OUU,k}e 2ct, (109)
A 2{2g’ku,i
u,ku,ieU,e+ gu,i(Au),
/ gU,ik U,ik /
CeIXTu[
2/cuAu}e2t.
Moreoverdifferentiating
(94)
weobtaingbl,i( mbl),
--2kg’
lA,iktl,ibl,kmld
/bl,tklA,k.(110)
(111)
Combining
(108), (110),
and(111),
weobtainaftersome reduction garb-b,t { 4ggk[u,i
U,kU,ieu,e
u,i u,iu, Au] + 2g2
u,i u,i/2o
T [gklVulZ fla(klVul2)]
}
k2
[gklVul
2G(NlVul2)] 2, 2 u e2t.
In contrast to the one-dimensional case the quantity U,ikU,kU,ieU,e--
U,ikU,iU,kAU
is not identically zero. Depending on the sign ofg’,
it seems convenient to substitute an upper boundor alower bound for U,ik U,iU,k,/U.If
g’_>
0, we use the arithmetic-geometric mean inequality in the following form:(113)
where
A
is an arbitrary positive constant. Combining(112)
and(113)
weobtain
gAD b,t >_ {4gg’ku,ikU,kU,ieu,e + 2gig NAg’klVul 2]
U,ikIA,ik2A-l ggtk[Vul-2(U,ikU,iU,k) 2-1- [gklVul2-flG(klVul2)]
k’
2) }
k2 [gklVul
2G(klVu 2o2flu
2 e2aflt. (ll4)
Since g
NAg’k]7u]
2>
0byassumption(100)
wemayusetheCauchy- Schwarz inequality[Vll[2U,ik
bl,ik IA,ik1d,kU,ig b/,g.(115)
Wethen obtaingAd9
rb,t >_ {2g[Vul-2[g + (2 AN)g’klVul 2]
bl,ikbl,kU,igU,g2A-lgg’klVul-2(U,ikU,iU,k)
2+ [gklVu[
2flG(klVul2)]
k’
2) }
k2 [gklgul
2G(klVu 2oe2flu
2 e2flt(116)
Wenowmakeuseof
(109)
torepresent1.l,ikU,iasfollows:gU,ikU,i --OUU,k
-+-
k 1,...,N,(117)
wheredots stand foratermcontaining
,.
From(117)
wecomputeg2 g2(u,ik
U,ikU,kU,iU,k)
U,igu,g2ce2 c217ul4u Iul2u
22--
/...(119)
|8)Inserting
(118)
and(119)
into(116)
weobtainaftersomereduction gaff)ff),t +
>_ {2g-lo2u2[g + (2-N)-/ -1)g’klul2]/ [gklul2-G(klVul2)]
}
k- [gklVul
2
a(klVul2)] 2a2/3u
2 e2t. (120)
Using
(100)
weobtaing-c2u2[g
/(2-
g&-,-)g’klu[ 2] >_/o2u . (121)
Combining
(120)
and(121)
we areledtothedesiredinequality gaff)if),, +... _> k-2(2k- k’)[gklul
2a(klul2)]e2’ >_ o.
If
g’ <_
0,we usethe inequality2 AuU,ik tt,iU,k N
1) V ul 2u,ik
U,ik-+-IVul-2(U,ikU,iU,k)
2+ (N
u,iku,,
u,ieu,e,
(122)
(123)
derived in
[7].
Combining(112)
and(123)
weobtainif),, >_ 12(3-N)gg’ku,iu,lcu,ieu,e + 2g[g + (N-
gaff)
1)g’kl7ul2]u,i
u,i2gg’klVul-2(u,i&u,iu,k)
2+ [gklul
2/a(klVul2)]
kt
2) }
k2 [gklul2 G(klul -,22u
2 e2’>_ {
2 3N)
ggku,izcu,:
u,ieu,e +
2gig+ N-1) g’
kVul2
u,ik u,i2gg’klVul-2(u,iku,iu,k)
22o2/3u2}e 2/t, (124)
wherethe last inequalityin
(124)
followsfrom assumptions(102)
and(103).
Nowsince g+ (N- 1)g’k[Vul
2>_
0by assumption(104)
wemayuse
(115).
Moreover inserting(118)
and(119)
we obtain after some reductiongA ,t +"" >_ {2c2u2g-[g + g’k[u[ 2] 2oz2/u2} e2c/3’ _>
0,(125)
where the last inequality follows from
(104).
The inequality(125)
is again of thedesiredtype.Itfollows from Nirenberg’smaximumprinciple
[6,10]
that takesits maximumvalue(i)at aninterior criticalpoint(, -)
of u,or(ii)initially, or(iii)at aboundary point(i, )
with i 0f. The second step of the proof of Theorem 5 consists in showing that the later possibility (iii)cannothold.Tothisendwecompute the outward normal derivative of q,onOft. Using(94)
rewritten innormalcoordinates weobtain0
On 2eZtUnUnng -2(N- 1)eZt gKIVul
2<
0 on0f,(126)
where
K(_> 0)
is the average curvature of Oft. Let(i, )
be apoint at which takes its maximumvaluewith: OFt.
Friedman’s boundarylemma
[3,10]
implies that -const. in f x[0, ],
so that we mustactually have
O/On-O
on 0f. Since we haveIVul>
0 on 0f, weconclude then that the averagecurvatureKvanishesidenticallyon
OFt,
which isclearly impossible.Thisachievestheproofof Theorem 5.
Nowwewant toselectc
_>
0insuchaway that thefirstpossibility(i) in(106)
cannotoccur.Tothis endweproceedas in Section3.1. Inthe particularcaseofk(t)=
1,thisleadsto the following result.THEOREM 6 Letf beaboundedconvex domainin
RNwhose
boundary isC +.
Letdbe theradiusof
thegreatestballcontainedinFt.
Letu(x, t)
be thesolution
of
the parabolic problem(94)-(96)
withk(t)=_1.Assume that thehypothesesof
Theorem 5aresatisfied.
We then conclude thatif
7r2gmin
0_<c<c0"=
4d
(127)
the
first
possibility (i) in(106)
cannotoccur. Withcco
we are thenledto the following decay bound
for
G(IVul 2) +
c0u2< HZe -2t, (128)
with
H2 :-
max{G(lVh[ ) + aoh2}. (129)
WenotethatinthecontextofTheorem 6, the quantity
(130)
satisfiesthe parabolic inequality
gA ,t
nt--1V. .
0,(131)
where the vector field
.
is regular throughout f x(0, oo).
Moreoverwehave
-2(N- 1)KuZn <
0 on 0f.(132) On
It then follows from
(131)
and(132)
thatb
takes its maximumvalue initially.Thisshows thatifg <
0,wehavegmin
g(max), (133)
with)max
max]Vh[ 2.
As
a first example consider g(0-):=(1+0") 1/2.
Sinceg’(0")-
1/2(1 + 0")-1/2 _>
0,wehavetodeterminethe(greatest)/3E(0, 1)
such that(100)
is satisfied, i.e. such thatA(A,N,/3) <
2, where A is defined in(101).
This condition is satisfied only for N<
4. We are then led to/3=
2x/- >
0ifN=2 orN--3.As
a second example, consider g(0")’=(1+0")-,
O<_e<E’--min{1/2, 1/(N- 1)}.
Sinceg’--e(1 +0-)-1-<
0, we have to determine the(greatest)/3E(0, 1)
such that(103)
and(104)
areboth satisfied. This willbe thecasefor/3-
-e.Werefer to
[9]
forsimilarresults involvingsolutionsof the parabolic differentialequation(g(lVul2)u,i),i
u,t.(134)
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