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Radial Solutions of Equations and Inequalities Involving the p-Laplacian
WOLFGANG REICHEL
andWOLFGANG WALTER
MathematischesInstitut
I,
Universit&tKarlsruhe, D-76128 Karlsruhe,Germany
(Received31July1996)
Severalproblemsfor the differentialequation
Lu=g(r,u) with
Lpu=r-(rlu’lP-2u’)
are considered.Forot N-1, theoperator
L
isthe radiallysymmetric p-LaplacianinJR".
For variousuniquenessconditions the initial valueproblemwith given datau(ro) uo u’(ro) uandcounterexamplestouniqueness aregiven. Forthe case where g isincreasingin u,asharp comparisontheorem is established; it leadstomaximal solutions, nonuniqueness anduniqueness results,amongothers.Usingtheseresults, astrong comparison principlefor theboundaryvalue problemand a number ofpropertiesofblow-upsolutionsareprovedunder weak assumptions onthenonlinearity g(r, u).
Keywords: p-Laplacian;radial solutions;uniqueness;comparisonprinciple; blow-upsolutions.
AMS1991 SubjectClassification: Primary 34L30, 34C11, 35J60,Secondary35J05
1 INTRODUCTION
Thisworkisdevoted to thestudy ofthe nonlinearsecondorderoperator
Lu r-U(rUlu’lP-2u’)’= lu’l
p-2 (p-1)u" +-u’ (1)
r and to initial andboundary value problems for equationsoftheform
Lpu f (u)
andLpu
g(r,u).
It
is always assumedthat p > 1 ando > 0.For
afunction u dependingN-1 isthe p-Laplacian
ApU
onlyonr
Ix I,
xIR N,
the operatorL
pdiv(IVulP-2Vu)
inIRN;
inparticular,LN2-1u
u’f+ (N 1)u’/r
isthe47
radialLaplacian
(we
usethe same letteruasa functionof x 6..N
and as a functionofrIx[
6IR). In
the linear case p 2we simplywriteL
inplace of L.
With this notation,ot u p-2
Lpu
(p-1)1 L
u, where ot/(p-1).
A
description of the contents of thepaper
follows.In
the theorems the nonlinearityisalways
ofthe formg(r,u), butin this overviewwe formulate someoftheresultsonlyfor thespecialcasef (u).
The firstsignificantnewresultis giveninTheorem 2.
It
statesthatthe initialvalueproblem
Lu f (u), u(ro)
uo,u!(ro)
u0(2)
isuniquelysolvable if
f
ismerelycontinuous, at least in the caseu
0,0. The
consequences
r0 > 0 and also in some cases wherer0 0, u0
can be summed
up
in the statement that the usual assumption thatf
belongs
toC
canoften bereplaced by
continuity off.
Uniquenessfor thegeneralinitialvalueproblem
(3)
isasubtleproblem.Thisbecomesalready(r)u
e-h(r). In
manifest in the simple "p-linear" equationLpu +
k (- 1)thehomogeneouscaseh 0 the initial valueproblemisalways uniquely solvable
(cf. [13]),
whereas in theinhomogeneouscase this is not true, see Section 2.An
extensive listofuniquenessconditions is givenin Section2, togetherwithexamples ofnon-uniqueness.Theorem 3 is a refined version of a comparison theorem forproblem (3),
where g(r,u)
is increasing in u.It
givesriseto maximaland minimal solutions, equippedwith classical properties.Section3contains astrongcomparison theorem fortheboundary valueproblem
withoutthe usualhypothesisofnon-vanishing gradients; e.g., if 1 < p < 2andg(r,u)
islocally
Lipschitzian and (weakly) increasingin u, thenstrong comparison holds.In
Section4blow-up
problems ofthe form(r, u),
(r)
--+ --+R
Lpu
g u o as rare discussed. UsingCorollary
(e)
of Theorem3, it can beshown that the asymptoteof ablow-up
solution of(3)
depends continuously andstrictly Thishas immediateconsequences
ontheuniqueness monotoneonu0andu0.ofradial
blow-up
solutionsofApu f (u)
in aballinIR N.
Theseresults are obtainedunderweak assumptionsonf
andg;inparticular, differentiabilityis notrequired. Both for the strong comparison theorem and theblow-up problemextensiveuse ismade of earlier results on the initial value
problem.
Our
resultsapplyalso to radial and convexCa-solutions
ofMonge-Ampbre
equations detD2u g’(Ixl, u),
since they satisfyutt(u’/r)
N-1(r,
u),i.e.,
LON
g(r,u), u’(0)
0 with g(r,s)
rN-lfi, (r, s).
NOTATION
For
simplicity, we write the odd powerfunction in the form s(q)]slq-ls
[slqsign s (qreal);
ithasthepropertiess(q)t(q) (St)(q), 1Is
(q)(1/s)(q), (--S)
(q)_s(q),
[slq, s(qz) s(q,+q2) Ls(q qlslq_
dds ds
Islq qs(q-1)
The inverse functionofS(q)isS(l/q)
Monotonicity isused in the weak sense, i.e.,
f
is increasing ifu < vimplies
f(u)
<f(v),
andstrictly increasingif u < vimpliesf(u)
<f(v).
For
asolution u in an intervalJ
C [0,cx)
werequirethat u andru
t(p-1)belongtoC
I(j);
thisimpliesthatu"
is continuousaslongasu 0.2
EXISTENCE, UNIQUENESS, CONTINUOUS DEPENDENCE For
the reader’s convenience we state and prove an existence theorem ofPeano
typefor the initial valueproblem(r,u), u(ro)--uo,
u’(ro)
Lpu
g uo.(3)
TheOREM 1(Existence).
Assume
thatg(r,s)
is continuousandboundedin the stripS J
xIR,
whereJ
[0,b]
in thecasero
0andJ
[a,b]inthecase0 <a <
ro <_
b. Then the initial valueproblem(3)
has- under the 0 in the casero
0-asolution existing inJ.
provisionthatuo
COROLLARY Assume
that gis continuousinG,
whereG
isarelatively open subsetof
[0,oe)
xIR,
andthat(ro,uo)
G. Thenproblem(3)
has a local solutionu(r)
in someinterval.It
canbeextended(as
asolution)toamaximal intervalof
existence [0,fl+)
or(fl_, fl+)
with0 <_ fl_ <fl+ <_
oe, wherethe secondcase applies only
if ro
>O;
the extended solutiontends to the boundaryof
Gas r --+fl_ andr --+fl+.
Proof It
followsfrom(3)
thatru’(r)
(p-l)--ru
p-l)p
g(p, u(p)) dp.(3’) Hence
problem(3)
isequivalenttothe fixedpoint equationuSu,
wherefrf { (rO)utO(p-1) frl (p)a
(Su)(r) uo + + 7
g(p, u(p)) dpat.
We apply
Schauder’s fixedpointtheorem in the Banachspace XC(J).
Obviously,
S
mapsX
intoitselfand is continuous inthe maximum norm, i.e.,u
--+ u uniformlyinJ
impliesSu --
Su uniformlyin J. Furthermore, sinceg and the functions(ro/t)
and (p/t) arebounded,[(Su)[
<K
for u 6X
andr 6J. Hence S(X)
is arelatively compact subset ofX,
and Schauder’stheorem shows that a fixedpointexists.Thecorollar3,
is derived in astandard way from Theorem 1.THEOREM 2 (Uniqueness).
Assume
thatG CS
[0,o)
xIR
isrelatively openinS
andg(r,s)
is continuousinG
andlocally Lipschitzianwith respect tos orr.If (ro, uo)
Gandro
>O, Uo O,
thenproblem(3)
hasauniquelocal solution. Theextension
u(r)
remains uniqueaslongasu(r)
O.Proof
If g(r,s)
islocally Lipschitzianin s, notice that aslong
as u#
0the differentialequationcanbe written in the form
u" ,(r,
u,u)
where,(r,
s,s)
is locally Lipschitzian in s,s in G x(IR \ {0}).
Uniqueness then follows form a well known classical theorem.Now
let g be locally Lipschitzianinr.A
solution u satisfies u(r0) #
0;therefore it has an inverse functionr(u)
of classC
2in aneighborhoodofu0.It
followsfromu
r --1,
ur 2+u r ---0
and r >0,where
r’ dr(u)/du,
uu’(r(u))
thatr(u)
isa solutionofthe initial valueproblem(p-
1)r"= r ’2- r’(p+l)
g(r(u),u),r(uo)
ro,r’(uo) 1/Uo
Sincetherighthand side of the differentialequationislocally Lipschitzian inras
long
asIr[
> 0, thetheoremfollows.It
iswell known that existence anduniqueness implycontinuousdepen- denceontheinitialdata.We
formulatethisresult forproblem (3),
usingthe notationu(r;
ro,uo,Uo)
for a solutionof(3).
COROLLARY Let
g be asinTheorem2andletu(r)
u(r; ro,uo,Uo)
beasolutionin acompact interval
I
[a, b],where 0 < a <ro <_
band u56
0in
I.
Then,given e >O,
thereexists 3 > 0such thatfor [ro fo[
< 3,fo
EI, luo ol
< 3,lUo o1
< 3the solutionfi(r) u(r;o, tTo, tT)
existsinI
andisuniquelydetermined, and
lu(r)
fi(r)l < e,lu’(r) fi’(r)l
< eand fitOin I.
For
proof,onechangesg(r, s)
outside aneighbourhoodN
of the solution uin such awaythatgbecomes bounded and continuous inI
xIR;
onemay takeN {(r, s)
r EI, Is u(r)l
_<’}
C G.Thenthesetofall solutions u(r;f0,
iT0,fi),
where the parameters satisfy the above inequalities with 3 1,is arelatively compactsubset ofX
C(I)
(everysolution exists inI).
For
everysequence (r, u, Uo k)
-, (ro,u0,u)
thecorresponding sequence (uk)of solutions has auniformly convergentsubsequencewith limitu, and itfollows from(3 t)
that the sequence ofderivativesconverges uniformlyto u(u(r),t. Let ut(r)) . (0,
rio,tT)
and ) (r0,u0,u).
Then(u(r;.)), u’(r; .))
-,uniformlyinIas)
..
The rest iseasy.In
the next theorem we usethenotationv(a+)
<w(a+) (or
v < w ata+)
if there exists e > 0such that v < w in(a,a+ e). For
v, wC 1,
thisrelationholds if
v(a)
<w(a)
or ifv(a) w(a)
andvt(a)
<wt(a).
THEOREM 3 (Comparison).
Let
I [a,b] andIo
(a, b](0
< a <b).
Assume
v, w C(I)
withVt(p-1) tOt(p-1) C(I0)
satisfyv(a+)
< w(a+),v’(a)
<_wt(a), Lpv-g(r, v)
<Lpw-g(r, w)
inIo,
whereg(r,
s)
isincreasingin s. Thenv
t<_w
inI,
whichimplies v<w inIo.
If
(i) gisstrictlyincreasing ins or(ii)v <w’
ata+
or(iii)thedifferential
inequalityis strict at a
+,
then v < w inIo.
The theorem remains true in the case
I
[b, a](0
< b <a)
is an intervaltotheleft of
aif
theinequalities involving vt,
w are reversed andIo
is the interval [b,a)"
Thedifferential
inequalityandv(a-)
<w(a-), vt(a)
>_wt(a)
implyv > w and v < winIo,
andthe cases(ii), (iii)have tobe changed accordingly.Proof Let
v < w inI [a,c],wherecis maximal.Then[r
a(w
’p-1)vt(p-1))] >_ r[g(r, w)
g(r,v)]
> 0 inI t. (*)
It
follows that w v>_
0inI
whichimpliesthat w v ispositiveand increasingin(a, c].
Thisshowsthat c b.In
eachofthe cases(i)-(iii)the first term in(.)
ispositiveat a+,
whichgivesw > v inI0.
[]Remark
It
isclearthatinthe case ofnonuniqueness of problem(3)
the Comparison Theorem cannothold if in all inequalities of the assumption equalityispermitted.But
it isremarkablethata strictinequalityinoneplace(v
<to ata+)
suffices withoutanyconditions on gexcept monotonicity.COROLLARIES In
the following propositions(a)-(h)
it is always assumed that g(r,s)
is continuous and increasing in s on a setG c S I
xIR
which isrelativelyopen
inS,
andthat u,v,w(withgraphs belongingtoG)
satisfythesmoothness assumptionsof thetheorem;asbefore,I
[a,b]andI0 (a,
b].The initial valueproblem (3a)
istheproblem (3)
withr0 a.Similarpropositionshold also to theleft ofa > 0,where
I
[b,a]
andI0
[b,a); anexplicitformulation isonly giveninthose cases where the necessarychangesare not obvious.(a) Upper
andlowersolutions.Iftosatisfiesthe inequalityL
w > g(r,w)
inI0,then w iscalledanuppersolution
(or
supersolution)tothedifferential equationLu
g(r,u);
it is anupper
solution to the initial valueproblem Theseinequalities implythat(3a)
if, in addition,w(a+)
> uo,wt(a)
> uo.to > u and w > u in I0, where u u(r;a,uo,
Uo). A
lower solution (subsolution)v is definedsimilarly,withinequalitiesreversed.(b)
Maximal and minimal solutions.Problem(3a)
has a maximal solution t7 fi(r;a,u0,Ul) in a maximal interval of existence [a,?)
(? <b)
or [a, b] and a minimal solutionu_ u_(r;
a,u0,u)
in a maximal interval [a,c) (c
<b)
or[a,b]. For
every othersolution u of(3a)
theinequalitiesu_
< u < fi, u < u <fithold in the intervalofexistenceofboth t7 andu.The maximal solution ficanbe obtained as the limit of thesequence ofsolutionsu(r)
u(r;a,uo +
1/
k,Uo),
which isstrictly decreasing (this followsfrom Theorem3). A
similarpropositionholds for the minimal solution.(c)
Comparisonwith maximaland minimal solutions.If
tosatisfies
Lpw
> g(r,
w),w(a) _>
uo,w’ (a)
> u0,’
then w
>_ u__
and w > ut,
whereuu_(r;
a,uo,Uo). In
particular,if
problem(3a)
has a unique solution u u(r;a, uo,Uo),
then w > u, w > ut. In
this case w (withtheabove properties) isalsocalledanupper
solution fortheinitial valueproblem. There areagain corresponding statementsforlower solutions v of
(3a)
and"to
the left".This follows from
(b)
and Theorem 3, applied to w and u(r;a,uo :
1/k, uo).
We
nowdescribe twotechniqueswhichgenerateupperandlowersolutions from a solution. The first oneappliesinthe case whereg(r,s)
isincreasing in r, while the second onerequiressome kindofLipschitz continuityinr.(d)
Shiftof solutions.Assume
that usatisfies
thesmoothnessassumptionsin anintervalI
[a,b](a
>_O)
and u > 0inI0
(a, b]. Then thefunction u(r) := u(r + 3)
isdefined
inI I
3, and(Lu)(r)
>(Lu)(r +3)
for > 0 and(Lua)(r)
<(L)u(r + 3)
for < 0(r
6I0
qh).(4)
(r, u)and
u’
Ifuis asolutionof
Lpu
g > 0 inI,
where g isincreasingin(s
and)r, thenu
is asuper-
or subsolution tothe differentialequationin the case > 0or < 0,resp.
(e)
Supersolutionsbysubstitution.Let (r)
beof
classC
2 andw(r)
u((r)).
Thenw’ u’’
andw" u"
’2+ u’"
with
tp’ tp’(r), u’ u’((r))
Thisimplies( )
Lpw
(p-1)[utb’l
p-2u"cp
’2+ u’cp" + --u’q’
with
or’
ct/
(p1)
and(5)
Dw
"=Lw- (Lu)(qb(r))
(p-1)]u’lp-2
(u,,(lcp, lp_l)_Fu,.dp,,p_2dp,,_Fot,u,(dp’(p-1)
r(r) (6)
Thisfoula will be used in thegenerationof asupersolutionfrom a solution (r, u)"
u of
Lpu
gLw
g(r,w) Dw
g(r,w)
g((r),w). (7)
The same equivalence holds for < (in both places) and for strict inequalities.
(f)
Uniquenessunder the conditionuo(a)
0(a
>0).
Thesolution u(r;a, uo,O) of (3a)
isunique inaneighbourhoodof
aif
g(a,uo)
>O, and,in addition,
(i) g Lip-
(r) for
uniquenesstotheright,(ii) g Lip
+ (r) for
uniquenesstotheleft (a
>0).
A
function(r) belongs
to Lip+ or Lip- if the difference quotient[(r2) aP(rl)]/(r2
rl) is bounded above orbelow, resp. Obviously, increasing or decreasing functions belong to Lip- or Lip+,
resp., and Lip Lip+
fLip-.(g) Uniqueness of solutions with one sign.
We
consider a solution>
0(< O)
and, incasebothinitialvalues u(r;a, uo,Uo) of (3a)
with uo, u0vanish,g(a,
O)
>0(< 0).
The solutionisuniquein aneighbourhoodof
aif furthermore
g(r,s)/s
p-1 isdecreasing (increasing) insfor
s > 0(s < O)if
u >0 (u <
O)
in(a,a+
E].For
uniquenessin anintervaltotheleft of
athepropositionremainsvalid
if
theinequalityfor Uo
isreversed.O. Assume
that g(r,s)
isincreasing(h)
Maximal solutions in thecaseu0in r(e.g., g(r,
s) f (s))
and thatg(r,uo) O for
a < r < b. Then u=- uo
is asolution.
Assume
that thereexists asubsolution whichis >uo
in(a, b].Then,
for
a <ro
< b, the maximal solution iT(r;ro, uo,0)
andno other solution is>uo for
r >ro.
Undertheseassumptions, all solutionsof (3a)
aregivenby
u(r)--uo
in [a, ro], u(r)=-ff(r;ro,uo,O)
in [r0,b] (a
<ro <b).
They
fill
the area between the curves suo
ands fi(r;a, uo,0)
inthe r, s-space. When I isan interval[b, a] tothe
left of
a, then g mustbedecreasing inr,and
ro satisfies
b <ro
<a.EXAMPLE
If g (r,S) >_ Ks
qfors _> 0and 0 < q < p-1,thenthestatement --Oanda > O.For/z
> (q+l)/(p-q-1) in(h)
appliesforu0 u0the function
(r a)/z+l
is asubsolution to therightofa andthe function(a r)/z+l
isasubsolution to the left ofa(incasea >O)
for the initial value 0in asmallone-sidedneighbourhoodofproblem Lpu Ku
quo
u0a.The functions arepositivetotherightor left ofa,resp.
Remarks 1. The statement(f)(i)fails tobetrueunderthe weaker
assump-
tion thatg(r,uo)
ispositive onlyinI0 (a,
b]. Theinitialvalueproblemu" 12,/
u+
r4u(0) u’(0)
0with thesolutions u -r4andu
(1 + ,/)r
4is acounterexample.2.
It
is notclear whether thestatementin(h)
about thecharacterization of the maximal solution as the unique positive solution remains true if the monotonicity ofg(r, s)
inr isreplaced
by alocal Lipschitz condition in r.A
simplecounterexampletothe assertion in(h)
is6r for s > r3
u’=g(r,u),
where g(r,s)=6sir
2 for 0<s<r
30 fors <0.
Solutions are
u(r) .r 3,
0 _< )_<
1", the function g is continuous in [0,o) IR,
but notLipschitzianinr.3. Theexample
u" 12u(1/2)
withthe three solutionsu(r)
r4,
0 and -r4 shows thatunderthe assumptionsin(h)
the solutionsu(r) uo
is in generalnottheminimal solution.Proof (a)-(e)
are simple. (f)(i)We
consider the case a 0 and use the notation vl(r)v2(r)
ifVl/V2
1 as r 0.We
use(e)
with4(r)
r+ e(3 +
r),where,
3 > 0.Let
g(0,uo)
’
> 0.Then,foreveryu’(p-1)
a--i+l"
SinceLu ,,
itsolutionu,
(rau(e-1)) ray,
hence 7follows from
(1)
that (p1)lulp-2u"
--Y--" hencea+l thereisc > 0 such that(p-
1)[ulP-2u>
Y ":,
in [0, c].2(o + 1)
The expression
Dw
in(6)
consistsof three terms,D1,D2,D3
whereD2
0because
4"
0,andD3
> 0becauseq
1+
e > 1 andb(r)
> r. The firsttermallows now the estimateDw>Dw>Vl[(l+e)
p-l] >qpe aslongas q(r)<c.Let -L
< 0 bealowerbound forthe differencequotients ofg(r,s)
in a neighborhood of (0,u0).
Then the fight side of(7)
is bounded above byL((r) r) Le(3 + r)
< 2eL3 ifris restricted to0 < r < 3. Thisshows that for 0 < e < 1the functiontoisanuppersolution in[0, 3]
iftheconstant 3 >0satisfies?,p>_2L3 and 33_<c;
furthermore,w satisfies
w(0) u(eS)
>u(0)
andw’(0) u’(eS)(1
-be) >0
u’(0).
Ifv is another solution, then w > vand, by lettinge --+ 0,u
_>
vin[0, 8].As
before, itfollows by asymmetric argumentthat u v in an interval [0, ].In
the case wherea > 0wehave(p1)lul - " ,
and wemayuseb(r)
r+ e(8 + (r a))
for theproof
which is similar.(f)(ii)
For
uniquenesstothe leftone usesthesametechniquewith(r)
r
e(1 + 8(a r) + (a r)e). One
chooses first 8 > 0 so largethatD1
> 2Le(L
_>0 is now anupperbound for the differencequotientsofg), then solargethatDe + D3
> 0in a small leftneighbourhoodofawhere r -dp(r) < 2e.(g) If
uo #
0 oru
0 thenuhas onesignin(a,a+
e]. If both uo,u0 vanish, it follows fromg(a,0)
0and(3’)
thatuhas onesignin(a,a+
Let
u, v be two solutions onI
[a,a -be]forsufficientlysmall e.Ifuo, u0 do not both vanish, thenu/v
isboundedbelowonI byapositiveconstant.0thenitfollowsfrom
(3")
andthe mean value theorem for Ifu0 u0integralsthat
u(r)
g(Pl,bt(Pl))
1/(p-l)f J(s)
1 dsv(r)
g(P2,v(P2))
1ff J(s)
1 ds --+1 as r-+a,where
J(s) f
(p/s) dpand01, p2 E [a,r].In
case u, v arepositivein (a,a -bel,there exists alarge )0 > 1 with)u > v inI
for all) >_ )0.Let
)* inf{) > 1 )u > v in
I}
andsupposefor contradiction that)* > 1.Then, by assumption,g(r,;*u) < )*P- g(r,
U)
onI and henceLp(L*u)-g(r,)*u)
>L* P-l(Lu-g(r,u))
--0=Lv-g(r, v)
in I.Sinceg(r,
s)
isincreasinginsand)*u > v ata-b,thecomparisontheorem shows that)*u > v in(a,a-
e], contradictingtheminimalityof.*. Hence
)* 1andu > v foranytwosolutionsu, v of
(3a). In
case u, v are negative in (a,a -be], theproofis similar with)* inf{X > 1 )u < v inI}.
Noticethatnowby assumptiong
(r,)*
u) > )*P- g(r,u)
onI.(h)
Ifasolutionu(r)
is > u0inI0,thenus (8
>0)
satisfiesus(a)
> uo,us(a )t
>Uot
0.As
before, this impliesus
> v for 8 > 0 and everysolutionv.
Hence
u > v, i.e., u is the maximal solutiontT(r;a,u0,0) =:
This solutionproduces, accordingto
(d),
asubsolutionv(r) ft(r-(ro-a)).
Hence
tT(r;r0, u0,0)
>v(r)
>uo
forr > r0.Accordingtothereasoning at thebeginningof theproof,
appliedtor0 a,everyother solution > u0equalsthe maximal solution.
A Summary on
UniquenessTHEOREM4 Under each
of
the following conditions, uniquenessfor
theinitialvalueproblem
(a
>O)
Lu
g(r, u),u(a)
uo,u’(a)
u0isguaranteedinaneighbourhood
of
a.It
isassumedthat the functions g(r, s), h (r, s),defined in aneighbourhood U(a,u0)
C [0, o)lR, andk(r),definedinaneigbourhoodU(a)
C [0, cx), are continuous.We
write g(r,s)
6 Lip(s)
if g(r,s)
islocally Lipschitzian ins onU
(a, u0); g(r,s)
6 Lip(r)
is definedanalogously. The spacesof locally q-H61dercontinuous functionsaredenotedbyLipq(s) (0
<q <1).
For
one-sided Lipschitz conditions we use the terms Lip+ or Lip-(see
Corollary(f))
if the differencequotientsare(locally)boundedabove orbelow,resp.
Initial condition validfor Propertiesofg(r,s)
(a)
u
%0 (i) p> g Lip(r)(hencea >O) (ii) p> g Lip(s)
(iii) <p_<2 g(r,s) Lipq(s),O<q_<
(/)
u
0 (i) p> g(a,u0)>0, g incr.s,g Lip-(r)(ii) p> g(a,uo)<O,g incr.s,g6 Lip+(r) (iii) <p<2 g6 Lip(s)
(iv) <p<2 g>_ O, g(r, s) Lipp-l(s) (v) p>2 g(a,Uo) O,g Lip (s) (vi) p>2 g(r,s) h(r, s)p-1
+
k,(r),h,k>O,h6 Lip(s)
(’) Uo,
Uo
]R p> g(r,s) k(r)s(p-I0 ifa 0 (p-linearcase)
u
(3) Uo
u
0 (i) p> [g(r,s)[ _< Kls[p-1(ii) p> g(r,s)s <0for =/=O, g(r, O) O, [g(r,s)[ <K[g(r,s)[
In (/)(iv), (vi)thesigncondition ong(r, s)andh(r, s),k(r) maybe reversed.
Reading guide.Thepropertiesof g as statedapplytotheuniquenesstothe fight;swapLip- and Lip
+
in(fl)(i), (ii)foruniquenessto the left(the
other cases remainunchanged).Remark Thecases(ot)(ii)and
(fl)(iii)
and(v)
haverecentlyappeared
in a paperof Franchi, Lanconelli and Serrin[5]. For
ot 0,DelPino, Manfisevich and Munia[3] have given uniquenessconditions contained in the above list under the overallgrowthcondition[g(r,s)[
<Kls[
p-1.In
order to treat initial valueproblems
where thefight handside vanishes atr aweneed thefollowing:COROLLARY
If
g(r,s) l(r)(r,
s), where(r, s) satisfies (fl)(i),
(ii) or(v), thenthecorrespondinginitialvalueproblemisuniquelysolvabletothe right
of
a (totheleft of
afor
a > 0),if
is continuous in aneighbourhoodof
a,l(r)
>O for
r > a(r
<a)andif
inthecases(/)(i), (ii) isincreasing (decreasing).Remark
In
all other cases afactor(r)
isalready
allowedinthe abovelist.Proof of
Theorem 4. Since we only prove local uniqueness, we may assumeboundednessof g. Theproofs
areonly givenforuniquenessto the fight.Thechangesforuniquenesstothe left in casea > 0 are obvious.(or).
Conditions(i),(ii) give uniqueness byTheorem2.Case
(iii)iseasily reducedtothe case whereu0 0. Theoperator Sin(3it)
hasthen the formF
(Su)(r) A(t; u)( ---)
dtwhere A(t;
u) (a/t)u
p-l)+ ft
a(p/t)
g(p, u(p))dp -->u
(p-l) 0 asa.
We
proceedlike inMcKenna,
Reichel, Walter[9]
andinvestigate the operatorS
on the complete metricspace
C([a,r0])
with the metric d(u,v)
maxlu
(qv(ql.
W.l.o.g. we mayassumeu
> 0 and hence A(t;u)
>Uo p-1/2
> 0 for close to a; otherwise we consider-S.By
the positivityofA(t; u),we obtainthefollowingestimatefor close toa.We
write(Su)
(q)[[U[[
and(Sv)
(q)[[V[[,
where[[.
is theL1/q-norm
on [a,r], U A(t; u);q-3- andV A(t; v);q--r-l"](Su)
(q)-(Sv)(q)l(r) IIUII- IIVIII IIU- VII
fa
rIA(t; u)
A(t;v) [1/q
dt qfa
q<
KL(ro- a) [u(t)
(q)v(t)(q)[
1/qdt<
KL(ro -a)
q+ld(u,
v),where
L
is theq-H61derconstant ofg(r,s)
andK
is aLipschitzconstant forS---r-
nearUo
(p-1. Hence
forr0sufficientlyclose to a, theoperatorS
isa contraction on(C([a,
r0]),d)
and has auniquefixedpoint.(/).
Condition(/)(i)
guarantees uniquenessby Corollary (f)(i)and(ii).For
(/)(ii) oneneedsto observe that the function fi(r)-u(r)
satisfiesLfi (r,
fi) with(r, s)
-g(r, -s); for(/)(i)
isapplicable.Uniqueness under (iii) follows from the observation that s(1/(p-1 is differentiable on
IR
if 1 < p < 2. The proofis then similar to (ot)(iii) by estimating[__lh
K
[a(t; u)-J
a(t; v)p-lJ <[A(t;
u) A(t;v)[,
p-1where
K ((r0 a)
maxIg(r,s)[) (2-p)/(p-1),
and using the Lipschitz continuityofg(r,s)
ins.Conditions(iv)and(vi)are taken fromMcKenna,
Reichel and Walter[9]
and are based on suitable contraction mapping arguments.For
theproof
of(v)
we assume g(a,u0)
> 0 and observe that the expressionA(t;
u)
g(p, u(p)) dpg(trl,
u(tT1))
a+l aa+la _<O" <t
o+l
ispositivefora < < r0 ifr0 iscloseto abythe assumption.
Hence
by(t
+1 aa+l) /t
> a andbythemean-value theorem weget[A
(t;u)(---) A (t; v) (7-)1
<2-p
l
((t-a)
g(a,uo))
p-’-rp 1 ot
+
1 2IA(t; u)
A(t; v)lwhichresults in
( g(__a, uO) )
2-pL (ro a)
p/(p-1) maxlu vl
[(Su)(r) (Sv)(r)l
<\2(or i
a<r<rofora < r < r0andr0sufficientlyclose to a; here
L
istheLipschitzconstant ofg. Again S is a contraction operator on C([a, r0]), equipped with the maximum-norm.Theinvertabilityofthesignconditionimposedon g in(iv), (vi)isevident, since
-S
is a contractionif andonlyifS
isa contraction.(?,).
This conditionwasfoundbyWalter[13]
and isprovedin the context of Sturm-Liouvilleproblems byPrtifer’s transformation.(3).
Under condition(i)itfollowsfrom(3")
that a solution u satisfieslu(r)l
<_K -- far(t a)
dtamaX<r<ro lul
andhence u 0 on a sufficientlysmall interval [a e,a
+
e](a
>0)
or[0, e]
(a 0). For
theproof
of(ii)we defineG(r, s) fg
g(r,r)
dcr,which isnon-positiveby assumption,and find
u’Lu ut(P-1)((p- 1)u" +-u’) (lU IP)
-1---lU
p(G(r, u))’
Gr(r, u),with
,
(p 1)/p. Substituting vlu’l
p weobtainthelinear first order equationa ),
?’
(v’
nt-v) (G(r, u) Gr
(r, u),v(a)
--0,with fi
c/t,.
Solvingthisequationfor v >0andintegratingthe first term by parts, wegetfar( ) tfi
,v(r)
G(t,u(t))’
Gr(t,u(t)
-
dtfa
rtt--1 fa
G(r,
u(r)) &
G(t,u(t))
r--ft-
dt Gr(t,u(t))--r-g
dt.Ifu 0in aneighbourhoodof a, wemaychoose the
sequence rn
--+ asuchthatG(rn,
u(rn)) min[a,r,]
G(t,u(t))
< 0.Then weget rn -1?’V(rn)
<_IG(rn, U(rn))l(--l+6t r dt+(rn-a)K)
< 0 for n large, in contradiction to v >0.Hence
vlu
p-
0 in aneighbourhoodofa. []Proof of
the corollary.We
only indicate where the differences to the originalproofs
are.Suppose ,(r, s)
satisfies(/3)0)
and l(r) is increasing.(r, u), 0 where
We prove
uniqueness to the fight forLpu
g uog(r,
s) l(r),(r, s). Let
usgo backto theproof
ofCorollary 3(f)(i) with a 0 and,(a, u0)
> 0. The estimate forDw
nowbecomesDw
> ypel((r))
aslongas(r)
< c.If
-L
is a lower bound for the difference quotients of,(r, s)
in a neighbourhood of (0, u0), thenwehavetheestimate(noticeq (r)
>r)
g(r,
w)
g((r),w)
<l(dp(r))(,(r, w) ,(gp(r), w))
<l((r))2eLa.
In
order togetDw
>g(r,w) g((r),
w),thefunction/((r)) > 0drops out and theproof
goes as before.For
uniqueness to the left the estimate Dw>_
g(r,w)
g((r),w)
is obtainedby usingthedecreasingcharacter ofl(r)
togetherwith(r)
< r.If,(r, s)
satisfies(fl)(ii),
theproofis obtained by considering solutions v -u ofLpv -l(r),
(r,-v)
where now-,(r,-s)
satisfies(/3)0).
Suppose
now that,(r, s)
satisfies(fl)(v)
with g(a,u0)
> 0. As intheproof
of(v)
thepositivityofA
(t;u) ft
a(p/ t)a
g(p,u(p)dp fora < < r0follows from the positivity
,(a, u0)
andof/(p) forp > a.Hence
theestimate A(t;u) >,(a,
uo)fa (p)o
2
7
l(p) dpholds for a < <
ro
withro
close to a.DenotingI(t) fta(P/t)l(p)dp
weget bythe mean-value theorem
IA(t; u)(’----)-A(t; v)(’--)l
< p l 1(I (t) (a’ uo) )
v-1IA(t; u)-A(t; v)l.
WiththeLipschitz propertyof
,(r, s)
thisresults in2-p
I(Sbl)(r)--(SP)(r)l<((a’blO)) p-I-
2L(ro a)
max[a,r0]I (t)
max[a,r0]lu vl.
Thisgivesthe contractionpropertyfor
S
on[a,r0]forr0 close toa.Remark If,forgiveninitial conditions,g(r,
s)
satisfiesone of theabove uniquenessconditions and is furthermoreincreasingin s, thencomparison between anupperand a lower solution holds even ifequalityispermittedin the initialvalues; cf.Corollary(c)
toTheorem 3.We
furnish ourresults with twoCounterexamples.
For
q > 0theproblem
Lu
u(q) 1,u(O)
1,u’(O)
0hasthe trivial solution u _= 1.
For
1 < p < 2 this is theonly solution by (fl)(iii).For
p > 2 the functionv(r)
1+
er1+ is a subsolution if F > 2/(p2)
and e > 0 is sufficiently small.Hence
the initial value problemhas at least two solutions, since the maximal solutiont7 (r; 0,1,0)
is> lforr>0.Thiscounterexample shows,thatuniquenessmayfail if in
(fl)(i),
(ii)and(v)
onlythe conditiong(a,u0)
> 0, < 0 and 0,resp.,isviolated and if in(fl)(vi) onlythe conditionk(r)
> 0 isdropped.Furthermore it shows that theequivalentof(fl)(iii)
does not hold for p > 2. Finallyit shows,that in(F)
the homogeneityisessential.IftheLipschitz continuityofg(r,
s)
in(fl)(iii), ofh(r, s)
in(fl)(vi)
or the p- 1-H6ldercontinuityofg(r,s)
in(/3)(iv)isdropped, then uniqueness may fail, as shownbytheexample following Corollary(h),
whereZu
u(q)u(a) O, u’(a)
0has nontrivial solutions for 0 < q < p 1totherightand left(ifa >
0).
Thisexamplealso shows that in(8)(i)thegrowth exponentp 1 cannot be decreased and in (8)(ii) uniquenessfails ifthe signconditiong(r,
s)s
< 0 fors5
0isreversed. Notice that(8)(ii) gives uniquenessfora (q)
Lpu
-uu(a) O, u’(a)
O.3
A STRONG COMPARISON PRINCIPLE
For
an interval 1 [a,b] (0
< a <b)
we define11 (a,
b) ifa > 0and
11
[0,b)
ifa 0.We
considerpairs of functions v, w 6C1(I),
ra
v,p- 1),
r u,(p-1) C(11),
whichsatisfya (r,w) in
(a,b), (8)
Lpv-
g(r,v)
>_Lpw-
gv(b)
<to(b)
andv(a)
<w(a)
if a > 0,v’(0) w’(0)
0 if a 0.(9)
If g(r,s)
is (weakly) increasing in s, then the well knowncomparison principlestates that v < w in [a, hi; el.Tolksdoff [11], Walter[12]. Here
weaddress thequestion,under what conditions the weakcomparisonv < to(WCP)
canbestrengthenedtothestrong comparisonv < toorv to(SCP).
Remark
For
a > 0 we want thestrong comparisonv < toto hold on(a,b)
whereasfora 0 it isrequiredtohold on[0,b). Note
thatforot N 1 the interval(a,b)
representsanopenannulusand[0,b)
anopenball inN-space.
We
formulate the correspondingHopf
version(H)
of(SCP)
attheboundary pointsb anda(for
a >0):
v < w in
I1
and v(b)=w(b) impliesv’(b)> w’(b).
v < w in
I1
andv(a)= w(a)
impliesv’(a)
<w’(a). (Ha) In
Walter [12], essentially the following counterexample for p > 2 is given,which shows that(SCP)
and(H)
can fail, even if theincreasingfunction g(r,s)
isLipschitzianas afunction ofs t-l Consider theequationLu
u(q) 1for q > 0.
We
have seen in thecounterexamplesin Section2thatthe initial valueproblemforthe aboveequationwithu0 1,u
0 has two solutions u 1 and iT(r; 0, 1,0)
> 1 for r > 0.By
Corollary3(h),
the maximal solutiont2(r;a,l,0) is > 1 forr > a(a
>0).
Ifwe take v 1 and w(r;
a,1,0),
thisexample
showsthatboth(SCP)
and(Ha)
fail. The followingcondition fromTolksdorf 11 or Walter12]
isknown toguarantee(SCP)
[and(H)]
Case
a >0v’
0orw’ 5
0in(a,b)
[in [a,b]],
g(r,s)
isincreasingandlocally Lipschitzianin s.
The mainweakness of this result is theassumptiononthenon-vanishing ofthe derivatives, which is ingeneralnotcontrollable.Our approachisbased on thefollowing simpleidea: Since we have the weakcomparisonw > v in
I,
thestrong comparisonto > v in11
failsonlyifthereexists atouchingpointr0
I1
withw(ro) v(ro)
andw’(r0) v’(r0).
Ifwefurthermore supposefor contradiction that w v, then wemaytaker0tobe apointof astrict one-sidedlocal zero-minimum of w v.We
determine a continuous function q(r)
which satisfiesa
’ (r,w)
inI1 (8’)
Lev
g(r,v)
> q(r) >Lew
gand considerthe initial valueproblem
Lu
g(r,u)+
q(r),u(ro) v(ro)
w(ro),u’(ro) v’(ro) w’(ro).
(10)
The function v is asupersolutionand the function w is a subsolutionto thisproblem. Assumingthat(10)
has auniquesolution in aneighbourhood U ofr0, we obtainfrom Theorem3,Corollary(c)
that w < u < v, which leads to v w inU,
acontradiction.Summingup,wehaveTIEOrM 5
Suppose
v, w satisfy(8)-(9)
andg(r,s)
iscontinuous in(r,s)
[a,b]IR
and increasingin sIR.
Then(SCP)
holdsif
allproblems(10)
with
ro I1
areuniquelysolvable.In
particular(SCP)
holdsif
thefunction
,
(r,s)
g(r,s) +q (r) satisfiesfor
initialvaluesuo v(ro)
anduo(ro)
auniqueness condition
of
Theorem 4.The assertions
(Ha), (Hb)
areproved
by thesameargumentwhere a strict one-sided zero-minimumof w v atr0 aorr0 b withv’ (r0) w’ (r0)
isled to a contradiction.We
need q to be defined and continuous in[a,a+
]or
[b ,
b], resp.For
illustration, wegivesomeexplicit assumptionswhichimply(SCP)
and(H). We
usethe notationPuLu
g(r,u); naturally, g(r,s)
isincreasing ins.(a)
1 < p <2, g 6 Lip(s)(no
conditiononq).(b)
The p-linearcase, g(r,s) k(r)s (p-l),
k > O. Takeq(r) 0, i.e.,P
v >0 >P
w(for
q -1,wehave acounterexample)(c)
g(r,w(r)) +
q(r)#
0 inI1,g and q Lip(r).(d)
1 < p <2,g(r, w(r)) +
q(r) > 0or < 0inI1,g(r,s)
Lipp-1(s).
(e)
p >2, g(r,w(r)) +
q(r)5
0in11,g 6 Lip(s).(f)
p > 2, g(r,s) h(r, S)
p-1+k(r),h
Lip(s),h andk+q non-negative in11.
(g)
Ifv’ 5
0orw’ 7
0 inI1 (a
>0),
then it suffices that g satisfies(or) (note
that (c)(ii)isthe conditionof Tolksdorfand Walterstatedabove).
4
BLOW-UP SOLUTIONS
Our
nexttheorem deals withblow-up
solutions for theequationLu
g(r,u), u(r) --
cxz as r --+R, (11)
inparticular
Lu f (u). We
introduce anassumption(A)
consistingof five parts:(A1) f (s)
is continuous,nonnegativeandincreasingin[so,cx).
(A2)
Thegeneralized Kellercondition. The functionF(s) fsSo f(t)dt
satisfies
ds
F(s)I/p
< o.(12)
(A3)
g(r,s)
is continuous, nonnegative and increasing in s in the setI
x [so, x), I [a,b]witha > 0.(A4)
There existf(s)
satisfying(A1)(A2)
andpositive constants cl,c:
such that
clf(s)
< g(r,s) <c2f(s)
inI
x(sl,
cxz), where Sl >so.
(A5)
g satisfies a conditionof Lipschitz typeIg(rl,
s)
g(r2,s)l _< Llrl
r2lg(rl,s)
inI
x [so,o).
Remarks 1. Condition
(A2)
has beengivenbyKeller[6]
in the classical case p 2; it is a necessary condition for blow-up. Under more restrictiveassumptions,butforgeneral
N-dimensional domains, theblow-up problemhasrecentlybeen studiedbyBandle andMarcus
1,2],Lazer
andMcKenna
[7,8]
forp 2andbyDiazand Letelier[4]
forgeneral p > 1.McKenna,
Reicheland Walter[9]have treated the radial case forf (u) ]u]
qandgeneralp > 1.
2.
It
followsfrom(A)
that limf(s)/s
p-1 c and limg(r,s)/s
p-1 oe for s cx uniformly inI. For
proofonemayadapt Lemma A
andB
in Bandle,Marcus [2].
3. The functiong(r,
s) h(r)f(s)
satisfies(A)
iff
satisfies(A1) (A2)
andhis continuousandpositiveand
Ih(rl) h(r2)l
<Llrl r21.
4. Condition
(A)
is satisfiedforf(s)
sq and,more general,forf(s)
sq
k(s),
ifkis continuous,positiveandincreasingandq > p 1.It
also holds for g(r,s)
,ksq+
k(r,s)
ifkissuch that(A)
holds andk(r, s)s
-q --+ 0as s ouniformlyinI.
LEMMA If f satisfies (A1) (A2),
thenf(s)
F(s)
--+o as s---o.
Proof In
an intervalJ
[Sl,o)
the function(s) F(s)
lip hasthe following properties:E
cl(J),
>O, 1/r
>O, 1/r
p convexand dsO(s)
<We
havetoprove thatp’ (s)
--, oo ass ---, cxa.Assume
firstthat!/
EC2(j).
Thenconvexityof
7,
pimplies(app)"
> 0 or!/taP" +
(p-1)
’2 >_ 0,whichimplies
By
integration,one obtains1 1
fa
b ds< (p-
1)
(Sl < a < b).(*)
"(b) ’(a) (s)
If
p’
werebounded, thenap
wouldgrowat mostlinearlywiththe effect thatf(1/Tt)ds
x.Hence
sup’
cx.Let M
bepositiveand letaJ
be such that
ds <--1 and
, (a)
>M.
ap(s)
M
Then itfollowsfrom theinequality(.)
that1 1 p-1 1 p-1
< <
’(s) ’(a) M M M
P
in [a,o).M
Thisinequalityshows that
lims ap’(s)
cx.Now
assumethat isonlyof class C
1. We
approximateF pP
by smooth functionsFc,
using the mollifiertechnique:F(s) J’IR F(s + ott)(t)
dt,where
q
>0, suppq
[-1, 1],q
6C(IR)
andfiR
dp(t)dt 1. SinceFbelongstoC differentiationgives
F(s) fiR F’(s +
ott)dp(t) dr.Due
toconvexity,F (s)
isincreasing, and thispropertyis inheritedbyF.
Hence
the inequality(.)
holds for the functions7z(s) := F(s)
1/p.In
the limit asot 0+, we getFa
--+F, F f,
hence7z
--+7z
and(P)’ (pP)’,
whichleads easilyto’.
Thisshows that(.)
holdsunder the assumption of the
Lemma,
whichnow follows as before.The firstpart of theproofwas contributed byProf. M. Plum, which is gratefully acknowledged.
THEorI
6Suppose
that,for
1,2,Ui is asolutionof (11)
in[a,bi
CI (a
>O)
andU (bi) x.If (A)
holdsandul(a+) <
u2(a+)
andu(a)
<u2(a), then bl
>b2.
Proof
Iffollowsfromthecomparisontheorem that theinequalitiesU <u2,u
it
< u2
hold in(a,b2)
and thatbl
>_ b2; furthermore,sinceu2u +
cwouldimply thatg is constant in s, we haveu <
u
at apointro
andthenalso in[ro,
b2).
For
theproof bycontradiction, we assume thata <bl b2
< b,andthathold in[a
bl).
The a > b/pand that strictinequalitiesu
< u2,u < u2proofis based on thefollowingidea.
We
considerthe functionv(r)
Ul(q(r)), where q(r)(1 E)r
and show that for small E > 0 the function v is a subsolution to the differential equation
(11). Because
of the strict inequalities at r a, we(a). Hence
v < u2 andv(b’)
cx where havev(a)
<u2(a), v’(a)
< u2q (b ) bl
and thereforeb2
< b <bl,which isthedesired contradiction.We
want touse(7)
and consider theexpression,, N(r)
}
Dv
(p1)]u] ]p-2
Ul((1 E)
p1) + ot’ul rg)(r)
with
N(r) (1 E)P-I[(1 E)r + bE]
r.For
E small,(1 E)
p 1 pEand(1 E)
p-a 1 (p 1)E,henceN(r) ,
-pEr+ (1
(p1)E)bE
<E(b-
pr) < 0becauser > a > b/p. Thusthe second term ofDv isnegative.
Next
we ispositive,sou has anttispositivefor u large.The derivativeu showthat u
(r(u))
satisfies inverse functionr(u)
withr1/u t.
The functionz(u)
u(withuasindependentvariable andr
r(u))
tt
zt(u
uu
(p-g(r,u)1)Z
p-1 r < (p-c2f(u) 1)Z
p-I’z (uo) ’o,
where u0
ul(a),
u0u(a).
Solving the corresponding initial valueproblem
fory(u),
yt
c2f (u)
(p_ 1)yP_ y(uo)
Uo,
we obtain
/ 1/p
y(u) \p-
,,PC2 (F(u) F(uo)) -+- Uo p)
whichimplies
> z(u),
g(r,u) ot
clf(u)
z
>(p_
1)yp-1
r (p- 1)yp-1 aBy
the lemma, f(u)/yp-1 -+ o as u -+ o,whichimpliesu]t/u
as r
-- hi. Hence
we mayassume(by moving thepointa tothe right,ifnecessary) thatuttispositive andtherefore
Dv
< 0 in[a,bl). Accordingto(7)
wehave toshowthatDv
<g(r,v)
g(cD(r),v).
This isobviouslytrueifg(r,
s)
isdecreasinginr.In
thiscase, which covers thecasewhereg(r,s) f(s),
the theorem isproved.In
thegeneralcase, we take smallandularge,whichimplies(1 )P
1 -p andut/u
ttO,
hence
1
,iP_Zu,,
1(Lu)(4)(r))pe
Dv _<
<--pe(p2 -L(b
a)g(d)(r),1)lul v)
<<g(r,-- v) g(cD(r), v).
It
was usedthat4(r)
r_<
b-aandL(b-a)
< p/3(a
and b canbechosen close tobl).
Theseinequalitiesshow that v is indeed a lower solution.COrOLI.ArY We
consider solutions u(r;
ro, uo,u) of(3)
undertheassump-tion
(A).
(a)
Casero O. Assume
that the maximal solutionti(r; 0,uo,0)
(uo >so)
blowsupatrbo.
Thenthe initial valueproblem(3)
has,for uo
<)<and
Uo O,
aunique solution u(r; 0,,k,0)
whichblows upatbz.
Thefunction bz
is continuous andstrictly decreasing in) (uo,cxz)
andbz
--, 0 as,k--+ c,bx --+
bo
ask --,uo.
(b)
Casero
a >O. Assume
that themaximal solution ti(r;a,uo,u)
(uo
> so, u >_O)
blowsupatbo.
Thenthe solutionu(r;a,,k,IX)
isunique() IX) (uo, Uo),
anditblows upata pointbx.
Thefor
) > uo,lx > uo,function bx,
is continuousandstrictly decreasing in)andIx, andittendsto aask --+ cxzorIx --+ cx andtobo
as(),Ix)
--+ (uo,Uo).
(c)
Uniquenessof
blow-upsolution. Under the assumptionof (a)
theblow-up problem
Lu
g(r,u)
in J(0, R), u’(O) O, u(R)
has
for
givenR (0, bo)
oneandonlyonesolution.If
g(r,uo) O,
g(r,s)
> Ofor
s > uo,r >0andif
the maximal solution iT(r; 0,u0,0)
is u=-
uo, then the blow-up problem hasfor
everyR
> 0aunique solution.
(d)
Thestatementsin(a)-(c)
remain trueif
g(r,s) l(r)(r, s),
where(r, s) satisfies (A)
andthe assumptions in(a)-(c), iscontinuous,increasing and(ro+)
>O.Remark
In
contrast to earlier work [1, 2, 4, 7,8]
on the generalN-
dimensionalblow-up problem,theabove uniquenessresult is obtainedmerely by monotonicity,Keller’s condition and (inthe nonautonomouscase)
bya Lipschitzcondition withrespecttor.Withoutthis last condition(A5),
the theoremfails.For
acounterexample takeablow-up
solution uofLu f (u)
and define gby