Serially Correlated Errors (Time Series Data):
• Suppose that u
1, u
2, · · · , u
nare serially correlated.
Consider the case where the subscript represents time.
Remember that β
GM M∼ N (
β, σ
2(X
0Z(Z
0Ω Z)
−1Z
0X)
−1) , We need to consider evaluation of σ
2Z
0Ω Z = V(u
∗), i.e.,
V(u
∗) = V(Z
0u) = V(
∑
n i=1z
0iu
i) = V(
∑
n i=1v
i)
= E ( (
∑
n i=1v
i)(
∑
n i=1v
i)
0)
= E ( (
∑
n i=1v
i)(
∑
n j=1v
j)
0)
= E(
∑
n i=1∑
n j=1v
iv
0j) =
∑
n i=1∑
n j=1E(v
iv
0j) where v
i= z
0iu
iis a r × 1 vector.
145
Define Γ
τ= E(v
iv
0i−τ).
Γ
0= E(v
iv
0i) represents the r × r variance-covariance matrix of v
i. Γ
−τ= E(v
i−τv
0i) = E((v
iv
0i−τ)
0) = (
E(v
iv
0i−τ) )
0= Γ
0τ. V(u
∗) =
∑
n i=1∑
n j=1E(v
iv
0j)
= E(v
1v
01) + E(v
1v
02) + E(v
1v
03) + · · · + E(v
1v
0n) + E(v
2v
01) + E(v
2v
02) + E(v
2v
03) + · · · + E(v
2v
0n) + E(v
3v
01) + E(v
3v
02) + E(v
3v
03) + · · · + E(v
3v
0n)
...
+ E(v
nv
01) + E(v
nv
02) + E(v
nv
03) + · · · + E(v
nv
0n)
= Γ
0+ Γ
−1+ Γ
−2+ · · · + Γ
1−n+ Γ
1+ Γ
0+ Γ
−1+ · · · + Γ
2−n146
+ Γ
2+ Γ
1+ Γ
0+ · · · + Γ
3−n...
+ Γ
n−1+ Γ
n−2+ Γ
n−3+ · · · + Γ
0= Γ
0+ Γ
01+ Γ
02+ · · · + Γ
0n−1+ Γ
1+ Γ
0+ Γ
01+ · · · + Γ
0n−2+ Γ
2+ Γ
1+ Γ
0+ · · · + Γ
0n−3...
+ Γ
n−1+ Γ
n−2+ Γ
n−3+ · · · + Γ
0= n Γ
0+ (n − 1)( Γ
1+ Γ
01) + (n − 2)( Γ
2+ Γ
02) + · · · + ( Γ
n−1+ Γ
0n−1)
= n Γ
0+
n−1
∑
i=1
(n − i)( Γ
i+ Γ
0i)
147
= n ( Γ
0+
n−1
∑
i=1
(1 − i
n )( Γ
i+ Γ
0i) )
≈ n ( Γ
0+
∑
qi=1