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ASYMPTOTICALLY NONEXPANSIVE MAPPINGS AND ASYMPTOTICALLY NONEXPANSIVE SEMIGROUPS

YONGFU SU AND XIAOLONG QIN Received 22 April 2006; Accepted 14 July 2006

Strong convergence theorems are obtained from modified Halpern iterative scheme for asymptotically nonexpansive mappings and asymptotically nonexpansive semigroups, re- spectively. Our results extend and improve the recent ones announced by Nakajo, Taka- hashi, Kim, Xu, and some others.

Copyright © 2006 Y. Su and X. Qin. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

1. Introduction and preliminary

LetH be a real Hilbert space,Ca nonempty closed convex subset ofH, andT:CCa mapping. Recall thatTis nonexpansive if

TxT yxyx,yC, (1.1)

andTis asymptotically nonexpansive if there exists a sequence{kn}of positive real num- bers with limn→∞kn=1 and such that

TnxTnyknxyn1,x,yC. (1.2) A pointxCis a fixed point ofTprovidedTx=x. Denote byF(T) the set of fixed points ofT; that is,F(T)= {xC:Tx=x}. Also, recall that a familyS= {T(s)|0s <∞}of mappings fromCinto itself is called an asymptotically nonexpansive semigroup onCif it satisfies the following conditions:

(i)T(0)x=xfor allxC;

(ii)T(s+t)=T(s)T(t) for alls,t0;

(iii) there exists a positive valued functionL: [0,)[1,) such that lims→∞Ls=1 andT(s)xT(s)yLsxyfor allx,yCands0;

(iv) for allxC,sT(s)xis continuous.

Hindawi Publishing Corporation Fixed Point Theory and Applications Volume 2006, Article ID 96215, Pages1–11 DOI 10.1155/FPTA/2006/96215

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We denote by F(S) the set of all common fixed points ofS, that is,F(S)=

0s<

F(T(s)). It is known thatF(S) is closed and convex. Construction of fixed point of non- expansive mapping is an important subject in the theory of nonexpansive mappings and finds applications in a number of applied areas, in particular, in image recovery and signal processing (see, e.g., [14,15]). However, the sequence{Tnx}n=0of iterates of the map- pingTat a pointxCmay not converge in the weak topology. Thus averaged iterations prevail. In fact, Mann’s iterations do have weak convergence. More precisely, Mann’s iter- ation procedure is a sequence{xn}defined by

xn+1=αnxn+1αnTxn, (1.3) where the initial guessx0Cis chosen arbitrarily.

Reich [9] proved that ifEis a uniformly convex Banach space with a Fr´echet differen- tiable norm and if{αn}is chosen such thatn=1αn(1αn)= ∞, then the sequence{xn} defined by (1.3) converges weakly to a fixed point ofT. However we note that Mann’s iterations have only weak convergence even in a Hilbert space [1].

Recently many authors want to modify the Mann iteration method (1.3) so that strong convergence is guaranteed have recently been made. Nakajo and Takahashi [8] proposed the following modification of the Mann iteration (1.3) for a single nonexpansive mapping Tin a Hilbert space:

x0C arbitrarily, yn=αnxn+1αn

Txn, Cn=

zC:ynzxnz, Qn=

zC: x0xn,xnz0, xn+1=PCnQnx0,

(1.4)

wherePK denotes the metric projection fromHonto a closed convex subsetK ofHand proved that sequence{xn}converges strongly toPF(T)x0.

They also proposed the following iteration process for a nonexpansive semigroupS= {T(s)|0s <∞}in a Hilbert spaceH:

x0C arbitrarily, yn=αnxn+1αn1

tn

tn

0 T(s)xnds, Cn=

zC:ynzxnz, Qn=

zC: x0xn,xnz0, xn+1=PCnQnx0.

(1.5)

They proved that if the sequence{αn}is bounded from one and if{tn}is a positive real divergent sequence, then the sequence{xn}generated by (1.5) converges strongly to PF(S)x0.

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Halpern [3] firstly studied iteration scheme as follows:

xn+1=αnu+1αn

Txn, n0, (1.6)

whereu,x0Care arbitrary (but fixed) and{αn} ⊂(0, 1). He pointed out that the con- ditions limn→∞αn=0 andn=1αn= ∞are necessary in the sense that if the iteration scheme (1.6) converges to a fixed point ofT, then these conditions must be satisfied. Ten years later, Lions [6] investigated the general case in Hilbert space under the conditions

nlim→∞αn=0, n=1

αn= ∞, lim

n→∞

αnαn+1

α2n+1

=0 (1.7)

on the parameters. However, Lions’ conditions on the parameters were more restric- tive and did not include the natural candidate{αn=1/n}. Reich [10] gave the iteration scheme (1.6) in the case whenEis uniformly smooth andαn=nδwith 0< δ <1.

Wittmann [13] studied the iteration scheme (1.6) in the case whenEis a Hilbert space and{αn}satisfies

nlim→∞αn=0, n=1

αn= ∞, n=1

αn+1αn<. (1.8)

Reich [11] obtained a strong convergence of the iterates (1.6) with two necessary and decreasing conditions on parameters for convergence in the case whenEis uniformly smooth with a weakly continuous duality mapping.

Recently, Martinez-Yanes and Xu [7] adapted the iteration (1.6) in Hilbert space as follows:

x0C arbitrarily, yn=αnx0+1αn

Txn, Cn=

zC:ynz2xnz2+αnx02+ 2 xnx0,z, Qn=

zC: x0xn,xnz0, xn+1=PCnQnx0.

(1.9)

More precisely, they prove the following theorem.

Theorem 1.1 (Martinez-Yanes and Xu [7]). LetHbe a real Hilbert space,Ca closed convex subset of H, and T:CC a nonexpansive mapping such thatF(T)= ∅. Assume that {αn} ⊂(0, 1) is such that limn→∞αn=0. Then the sequence{xn}defined by (1.9) converges strongly toPF(T)x0.

The purpose of this paper is to employ Nakajo and Takahashi’s [8] idea to modify pro- cess (1.6) for asymptotically nonexpansive mappings and asymptotically nonexpansive semigroup to have strong convergence theorem in Hilbert space.

In the sequel, we need the following lemmas for the proof of our main results.

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Lemma 1.2. LetKbe a closed convex subset of real Hilbert spaceHand letPKbe the metric projection fromH ontoK (i.e., forxH,Pk is the only point inKsuch thatxPkx = inf{xz:zK}). GivenxHandzK. Thenz=PKxif and only if there holds the relations

xz,yz0 yK. (1.10)

Lemma 1.3 (Lin et al. [5]). LetTbe an asymptotically nonexpansive mapping defined on a bounded closed convex subsetCof a Hilbert spaceH. Assume that{xn}is a sequence inC with the properties (i)xnpand (ii)Txnxn0. ThenpF(T).

Lemma 1.4 (Kim and Xu [4]). LetCbe a nonexpansive bounded closed convex subset ofH and letS= {T(t) : 0t <∞}be an asymptotically nonexpansive semigroup onC. Then it holds that

lim sup

s→∞ lim sup

n→∞ sup

xC

T(s) 1

t t

0T(u)xndu

1 t

t

0T(u)xndu=0. (1.11) Lemma 1.5. LetCbe a nonexpansive bounded closed convex subset ofHand letS= {T(s) : 0s <∞}be an asymptotically nonexpansive semigroup onC. If {xn} is a sequence in Csatisfying the properties (i)xnz; (ii) lim sups→∞lim supn→∞T(s)xnxn =0, then zF(S).

Proof. This lemma is the continuous version of [12, Lemma 2.3]. The proof given in [12]

is easily extended to the continuous case.

2. Main results

In this section we propose a modification of the Halpern iteration method to have strong convergence for asymptotically nonexpansive mappings and asymptotically nonexpan- sive semigroup in Hilbert space.

Theorem 2.1. LetCbe a bounded closed convex subset of a Hilbert spaceHand letT:C Cbe an asymptotically nonexpansive mapping with sequence {kn}. Assume that{αn}n=0

and{βn}n=0 are sequences in (0, 1) such that limn→∞αn=0, limn→∞βn=1, andM is an appropriate constant such thatMx0v2, for allvC. Define a sequence{xn}inCby the following algorithm:

x0C chosen arbitrarily, zn=βnxn+1βn

Tnxn, yn=αnx0+1αn

Tnzn, Cn=

vC:ynv2xnv2+zn2xn2+ 2 xnzn,v+αnM, Qn=

vC: x0xn,xnv0, xn+1=PCnQnx0.

(2.1)

Then{xn}converges toPF(T)x0, providedk2n(1αn)10.

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Proof. From [2] we know thatThas a fixed point inC. That is,F(T)= ∅. It is obviously that Cn is closed andQn is closed and convex for eachn0. Next observe that C is convex. Forv1,v2Cnandt(0, 1), puttingv=tv1+ (1t)v2. It is sufficient to show thatvCn. Indeed, the defining inequality inCnis equivalent to the inequality

2 znyn,vzn2yn2+αnM. (2.2) Therefore, we have

2 znyn,v=2 znyn,tv1+ (1t)v2

=2t znyn,v1

+ 2(1t) znyn,v2

zn2yn2+αnM,

(2.3)

which implies thatCis convex. Next, we show thatF(T)Cnfor alln. Indeed, for each pF(T),

ynp2=αnx0p+1αnTnznp2

αnx0p2+1αnk2nznp2

xnp2xnp2+αnx0p2+1αn

k2nznp2

xnp2+znp2xnp2+αnx0p2

xnp2+zn2xn2+ 2 xnzn,p+αnM.

(2.4)

Therefore,pCnfor eachn1, which implies thatF(T)Cn. Next we show that

F(T)Qn n0. (2.5)

We prove this by induction. Forn=0, we haveF(T)C=Q0. Assume thatF(T)Qn. Sincexn+1is the projection ofx0ontoCnQn, byLemma 1.2we have

x0xn+1,xn+1z0 zCnQn. (2.6) AsF(T)CnQnby the induction assumptions, the last inequality holds, in particu- lar, for allzF(T). This together with the definition ofQn+1implies thatF(T)Qn+1. Hence (2.5) holds for alln0. In order to prove limn→∞xn+1xn =0, from the def- inition ofQnwe havexn=PQnx0which together with the fact thatxn+1CnQnQn

implies that

x0xnx0xn+1. (2.7) This shows that the sequence{xnx0}is nondecreasing. SinceCis bounded. We ob- tain that limn→∞xnx0exists. Notice again thatxn=PQnx0andxn+1Qnwhich give

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xn+1xn,xnx00. Therefore, we have xn+1xn2=xn+1x0

xnx02

xn+1x02xnx022 xn+1xn,xnx0

xn+1x02xnx02.

(2.8)

It follows that

nlim→∞xnxn+1=0. (2.9)

On the other hand, It follows fromxn+1Cnthat

ynxn+12xnxn+12+zn2xn2+ 2 xnzn,xn+1

+αnM. (2.10) It follows from (2.1) and limn→∞βn=1 that

znxn=

1βnxnTnxn−→0. (2.11) Next, we consider

zn2xn2+ 2 xnzn,xn+1

=zn2+xn22 zn,xn+ 2 xnzn,xn+1

2xn2+ 2 zn,xn

=znxn2+ 2 xnzn,xn+1

2xn2+ 2 zn,xn

=znxn2+ 2 zn,xnxn+1

2xn2+ 2 xn,xn+1 .

(2.12)

Therefore, it follows from (2.9) and (2.11) that

zn2xn2+ 2 xnzn,xn+1

−→0. (2.13)

Furthermore, from (2.9), (2.13), and limn→∞αn=0, we obtain

nlim→∞ynxn+1=0. (2.14) On the other hand, we consider

ynTnxnynTnzn+TnznTnxn

αnx0Tnzn+knznxn

=αnx0Tnzn+kn1βnxnTnxn.

(2.15)

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Therefore, it follows that

xnTnxnxnxn+1+xn+1yn+ynTnxn

xnxn+1+xn+1yn+αnx0Tnzn +kn

1βnxnTnxn.

(2.16)

That is,

1kn1βnxnTnxnxnxn+1+xn+1yn+αnx0Tnzn. (2.17) It follows from limn→∞βn=1, limn→∞αn=0, (2.9), and (2.14) that

nlim→∞xnTnxn−→0. (2.18) Puttingk=sup{kn:n1}<, we obtain

TxnxnTxnTn+1xn+Tn+1xnTn+1xn+1 +Tn+1xn+1xn+1+xn+1xn

kxnTnxn+1 +kxnxn+1 +Tn+1xn+1xn+1,

(2.19)

which implies that

Txnxn−→0. (2.20)

Assume that {xni} is a subsequence of{xn}such thatxnix. By Lemma 1.3we have

xF(T). Next we show thatx=PF(T)x0and the convergence is strong. Putx=PF(T)x0

and consider the sequence{x0xni}. Then we havex0xnix0xand by the weak lower semicontinuity of the norm and by the fact thatx0xn+1x0xfor alln0 which is implied by the fact thatxn+1=PCnQnx0, we have

x0xx0xlim inf

i→∞

x0xnilim sup

i→∞

x0xnix0x. (2.21)

This gives

x0x=x0x, x0xni−→x0x. (2.22) It follows thatx0xnix0x; hence,xnix. Since{xni}is an arbitrary subsequence of {xn}, we conclude thatxnx. The proof is completed.

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Theorem 2.2. LetCbe a nonempty bounded closed convex subset ofHand letS= {T(s) : 0s <∞}be an asymptotically nonexpansive semigroup onC. Assume that{αn}n=0and {βn}n=0are sequences in (0, 1) such that limn→∞αn=0 and limn→∞βn=1.{tn}is a positive real divergent sequence andM is an appropriate constant such that Mx0vfor all vC. Define a sequence{xn}inCby the following algorithm:

x0C chosen arbitrarily, zn=βnxn+1βn1

tn tn

0 T(s)xnds,

yn=αnx0+1αn1 tn

tn

0 T(s)znds, Cn=

vC:ynv2αnxnv2+zn2xn2+ 2 xnzn,v+αnM, Qn=

vC: x0xn,xnz0, xn+1=PCnQnx0.

(2.23) Then{xn}converges toPF(S)x0, provided ((1/tn)0tnLsdt)2(1αn)10.

Proof. We only conclude the difference. First we showF(S)Cn. It follows fromC is bounded, we obtain thatF(S)= ∅(see [12]). TakingpF(S), we have

ynp2αnx0p2+1αn1 tn

tn

0 T(s)zndsp

2

αnx0p2+1αn

1 tn

tn

0

T(s)znpds 2

αnx0p2+1αn1 tn

tn

0 Lsds 2

znp2

=xnp2+znp2xnp2+αnx0p2

xnp2+zn2xn2+ 2 xnzn,p+αnM.

(2.24)

It follows thatF(S)Cnfor eachn0. From the proof ofTheorem 2.1we have the se- quence{xn}is well defined andF(S)CnQnfor eachn0. Similarly to the argument ofTheorem 2.1and noticingq=PF(S)x0, we havexn+1x0qx0for eachn0 andxn+1xn0. Next, we assume that a subsequence{xni}of{xn}converges weakly

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toq. It follows that

T(s)xnxn

T(s)xnT(s) 1

tn

tn

0 T(s)xnds +T(s)

1 tn

tn

0 T(s)xnds

1 tn

tn

0 T(s)xnds +1

tn tn

0 T(s)xndsxn

21 tn

tn

0 T(s)xndsxn

+T(s)

1 tn

tn

0 T(s)xnds

1 tn

tn

0 T(s)xnds,

(2.25)

for eachn0. It follows from (2.23) that yn 1

tn

tn

0 T(s)zndsαn

x0 1 tn

tn

0 T(s)znds. (2.26) Therefore, we obtain

yn 1 tn

tn

0 T(s)znds−→0. (2.27) Next, we consider the first term on the right-hand side of (2.25)

1 tn

tn

0 T(s)xndsxn

xnxn+1+xn+1yn+yn 1 tn

tn

0 T(s)xnds. (2.28) Sincexn+1Cn, we have

ynxn+12αnxnxn+12+zn2xn2+ 2 xnzn,xn+1

+αnM. (2.29) Similar to the proof ofTheorem 2.1, we have

nlim→∞ynxn+1=0, (2.30) and hence

yn 1 tn

tn

0 T(s)xnds

yn1

tn

tn

0 T(s)znds+1 tn

tn

0 T(s)znds 1 tn

tn

0 T(s)xnds

yn1

tn tn

0 T(s)znds+ 1 tn

tn

0

T(s)znT(s)xnds

yn1

tn tn

0 T(s)znds+ 1

tn tn

0 Lsdsznxn2.

(2.31)

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Since limn→∞βn=1, we have znxn=

1βnxn 1 tn

tn

0 T(s)xnds−→0. (2.32) It follows from (2.27) and (2.32) that

yn 1 tn

tn

0 T(s)xnds−→0. (2.33) It follows from (2.30) and (2.33) that

xn 1 tn

tn

0 T(s)xnds−→0. (2.34)

On the other hand, by usingLemma 1.4we obtain lim sup

s→∞ lim sup

n→∞

T(s) 1

tn

tn

0 T(s)xnds

1 tn

tn

0 T(s)xnds=0. (2.35) It follows from (2.34) and (2.35) that

lim sup

s→∞ lim sup

n→∞

T(s)xnxn=0. (2.36)

Assume that a{xni}is a subsequence of{xn} such that{xni}qC, thenqF(S) (byLemma 1.5). Next we show thatq=ΠF(S)x0and the convergence is strong. Putq= ΠF(S)x0, fromxn+1=ΠCnQnx0andqF(S)CnQn, we havexn+1x0qx0. On the other hand, from weakly lower semicontinuity of the norm, we obtain

qx0x0qlim inf

i→∞ x0xni

lim sup

i→∞

x0xni

qx0.

(2.37)

It follows from definition ofΠF(S)x0that we obtainq=ΠF(S)x0and hence

qx0=qx0. (2.38)

It follows thatxniq. Since{xni}is an arbitrarily weakly convergent sequence of{xn}, we can conclude that{xn}converges strongly to one point ofΠF(S)x0. This completes the

proof.

References

[1] A. Genel and J. Lindenstrauss, An example concerning fixed points, Israel Journal of Mathematics 22 (1975), no. 1, 81–86.

[2] K. Goebel and W. A. Kirk, A fixed point theorem for asymptotically nonexpansive mappings, Pro- ceedings of the American Mathematical Society 35 (1972), no. 1, 171–174.

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